The solubility of the solute in the solvent depends on intermolecular interactions.
How does the nature of the solvent affect its ability to dissolve a solute?The nature of the solute and the solvent alone determines how soluble they are in a solvent. In a polar solvent, a polar solute dissolves. In a non-polar solvent, a polar solute is poorly soluble. In a non-polar solvent, a non-polar solute dissolves.
Since the question is incomplete, we can not see what the solute or the solvent ought to have been. However, we must know that the solubility of the solute in the solvent must depend on intermolecular interactions between the both.
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which of the following processes produces the most atp? view available hint(s)for part c which of the following processes produces the most atp? a. glycolysis krebs b. cycle and oxidative c. phosphorylation d. hydrolysis of creatine phosphate
The highest levels of atp are produced through the glycolysis Krebs (a) process.
What is phosphorylation with ATP?By means of chemiosmosis, oxidative phosphorylation generates ATP using energy from the movement of electrons in an electron transport system. Only one proton (H+) and one electron are present in a hydrogen atom. Potential energy, or stored energy, is available to do work in electrons. A glucose molecule needs two ATP molecules to be completely phosphorylated. When glucose is phosphorylated to fructose 1,6-diphosphate in glycolysis, two molecules of ATP are used up.
What process is phosphorylation?A biological process called phosphorylation involves the addition of phosphate to an organic molecule. For two examples, adding phosphate to glucose will result in glucose monophosphate or adding it to adenosine diphosphate (ADP) will result in adenosine triphosphate (ATP).
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if a solution is able to conduct electricity, which of the following compounds must be dissolved in it?
If a solution is able to conduct electricity,ionic compounds must be dissolved in it as it will generate ions.
What are ions?
An ion is defined as an atom or a molecule which has a net electrical charge. There are 2 types of ions :1) cation 2) anion . The cation is the positively charged ion and anion is the negatively charged ion . As they are oppositely charged they attract each resulting in the formation of ionic bond.
Ions consisting of single atom are mono-atomic ions while which consists of two or more ions are called as poly-atomic ions . They are created by chemical interactions . They are very reactive in their gaseous state and rapidly react with oppositely charged ions resulting in neutral molecules.
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What is the molar concentration of a solution prepared by diluting 10. 0 ml of the solution in question #1 to a total volume of 50. 00 ml?.
The molar concentration of the solution prepared by diluting it from 10 ml to 50 ml is 0.0004000 mol/L.
In order to calculate the molar concentration of the diluted solution, firstly we need to know the molar concentration of the original solution and its dilution factor. The dilution factor is the ratio of the final volume to the initial volume. The dilution factor can be calculated here :
dilution factor = final volume / initial volume
dilution factor = 50.00 ml / 10.0 ml
dilution factor = 5.00
The molar concentration of the diluted solution can be calculated by using the formual M1V1 = M2V2
Here M1 is the initial molar concentration, V1 is the initial volume of the solution, M2 is the final molar concentration, and V2 is the final volume.
Putting the values we have in the equation M1V1 = M2V2.
M1 = the molar concentration of the original solution is unknown.
V1 = 10.0 ml
M2 = the molar concentration of the diluted solution is unknown.
V2 = 50.00 ml
Using this formula and solving for M2, we get:
M2 = M1V1 / V2
Since, we do not know the initial molar concentration, M2 can not be calculated directly. But, we do know that the number of moles of solute is the same before and after the dilution. Therefore, we can use the following equation:
n = M1V1 = M2V2, where n is the number of moles of solute.
n = M1V1
M1 = n / V1
after putting in the given values :
n = M1V1
M1 = n / V1 = (10.0 ml / 1000.0 ml/L) x (0.2000 mol/L)
M1 = 0.002000 mol
Since we know the initial molar concentration now, we can use the formula M2 = M1V1 / V2 to find the molar concentration of the diluted solution,
M2 = M1V1 / V2 = (0.002000 mol/L) x (10.0 ml / 50.00 ml)
M2 = 0.0004000 mol/L
Hence, the molar concentration of the solution diluted from 10 ml to 50 ml is calculated out to be 0.0004000 mol/L.
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which of the following equations is used in this experiment's calculations to find the molar volume of an ideal gas? group of answer choices
PV = nRT is the equation used in this experiment's calculations to find the molar volume of an ideal gas.
What is ideal gas?Ideal gas is a theoretical gas composed of a set of randomly-moving, non-interacting point particles that obey certain mathematical equations. It is assumed that the particles of an ideal gas have no volume, no inter-particle forces, and that the pressure, volume, and temperature are related by the ideal gas law. Ideal gas behaviour is an approximation of the behaviour of real gases under many conditions, and is widely used in the field of thermodynamics and statistical mechanics.
This equation states that the product of pressure and volume is equal to the number of moles of the gas multiplied by the gas constant and the temperature of the gas.
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Complete Question
which of the following equations is used in this experiment's calculations to find the molar volume of an ideal gas? group of answer choices
A) PV = nRT
B) V = nRT/P
C) Both A and B
D) None to these
The periodic table entry for Silicon is shown below. Assuming the atom is neutral, can you make the assumption that there are 14 neutrons in all Si atoms?
1- For an element, how does Avogadro’s number connect the atomic and macroscopic scales?
It describes the number of grams in 1 mole of an element.
It describes the number of atoms in 1 gram of an element.
It describes the number of atoms in 1 mole of an element.
It describes the number of moles in 1 gram of an element.
2- The atomic mass of the element platinum (Pt) is 195.08 amu. How many atoms of platinum are in 195.08 grams?
6.022×1023 atoms
1.175×1026 atoms
1.951×1025 atoms
3.087×1021 atoms
3- The atomic mass of copper (Cu) is 63.546 amu, the atomic mass of sulfur (S) is 32.065, and the atomic mass of oxygen (O) is 15.999 amu. Which molar mass is correct for copper sulfate (CuSO4)?
159.607 g/mol
225.802 g/mol
111.610 g/mol
446.440 g/mol
Answer:
1. It describes the number of atoms in 1 mole of an element.
2. 195.08 g Pt / 195.08 g/mol = 1 mol Pt
1 mol Pt x 6.022 x 10^23 atoms/mol = 6.022 x 10^23 atoms
The correct answer is: 6.022×10^23 atoms
3. Cu: 63.546 g/mol
S: 32.065 g/mol
O (4 atoms): 4 x 15.999 g/mol = 63.996 g/mol
Molar mass of CuSO4 = 63.546 + 32.065 + 63.996 = 159.607 g/mol
The correct answer is: 159.607 g/mol
At what temperature would the reaction proceed with a rate four times faster than at 460 k?.
The reaction would proceed with a rate four times faster than at 460 K at a temperature of 1840 K (1567°C).
What is temperature?Temperature is a measure of the amount of thermal energy present in a system. It is expressed in units of energy, usually degrees Celsius (°C) or degrees Fahrenheit (°F). Temperature is an important physical property of matter as it is directly related to the average kinetic energy of the particles that make up the system. Temperature can be affected by a variety of factors, including pressure, concentration, type of material, and radiation.
The rate of a reaction is typically proportional to the temperature, so the rate at a temperature four times higher than 460 K would be four times faster. Therefore, the reaction would proceed with a rate four times faster than at 460 K at a temperature of 1840 K (1567°C).
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25.0 mL of a 0.2450 M NH4Cl solution is added to 55.5 mL of 0.1655 M FeCl3. What is the concentration of chloride ion in the final solution?
Keep in mind that concentration (mol/L) = (# of moles) / (volume (L) )
Find the volume in litres is easy: 25.0mL + 55.5mL = 80.5 mL = 0.0805 L
Now we have to find the number of moles of Chlorine (Cl) moles of Cl in 25.0mL of NH4Cl = (25.0mL)(1 L/1000mL)(0.2450mol NH4Cl/1L)(1 mol Cl/1 mol NH4Cl) = 0.006125 mol
Cl moles of Cl in FeCl3= (55.5mL)(1 L/1000mL)(0.1655mol FeCl3/1 L)(3 mol Cl/ 1 mol FeCl3) = 0.02755575 mol Cl
Total moles Cl = 0.006125 + 0.02755575 = 0.03368075 mol Cl
Concentration = (0.03368075/0.0805) = 0.418 mol/L Cl
What is concentration of solutions?
The amount of solute that has been dissolved in a specific volume of solvent or solution is measured by the solution's concentration. A solution that contains a significant amount of dissolved solute is said to be concentrated. A solution is said to be dilute if it only contains a small amount of dissolved solute.
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Consider the following mechanism.
O3 → O2 + O (slow) O3 + O → 2O2 (fast)
a. Write the overall balanced chemical equation.
b. Identify any intermediates within the mechanism.
c. What is the order with respect to each reactant?
d. Write the rate law for the overall reaction.
Answer:
a. The overall balanced chemical equation for the reaction is: 3O3 → 3O2 + O b. The intermediate in the mechanism is O3. c. The order of the reaction is first order with respect to O3 and second order with respect to O. d. The rate law for the overall reaction is rate = k[O3]^1[O]^2.
18.8% Na, 29.0% Cl, 52.3% O empirical formula
Answer:
NaClO4
Explanation:
The empirical formula for a compound with 18.8% Na, 29.0% Cl, and 52.3% O is NaClO4. This means that the compound contains one atom of sodium, one atom of chlorine, and four atoms of oxygen.
Question 1: A solution of phosphoric acid (H3PO4) with a known concentration of 0.250 M H3PO4 is titrated with a 0.800 M NaOH solution. How many mL of NaOH are required to reach the third equivalence point with a starting volume of 72.0 mL H3PO4 according to the following balanced chemical equation:
H3PO4 + 3NaOH -> Na3PO4 + 3H2O
Question 2: A solution of oxalic acid dihydrate (H2C2O4•2H2O) with a known concentration of 0.400 M H2C2O4•2H2O is titrated with a 0.333 M NaOH solution. How many L NaOH are required to reach the second equivalence point with a starting volume of 65.0 mL H2C2O4•2H2O, according to the following balanced chemical equation:
H2C2O4•2H2O + 2NaOH -> Na2C2O4 + 4H2O
The volume of 0.800 M NaOH solution required to reach the third equivalence point is 67.5 mL
The volume of 0.333 M NaOH solution required to reach the second equivalence point is 156 mL
Stoichiometry: Calculating the volume required to reach equivalence pointFrom the question, we are to determine the volume of NaOH required to reach third equivalence point
Question 1:
The third equivalence point is reached when all three hydrogen ions (H+) in phosphoric acid have reacted with hydroxide ions (OH-) from the sodium hydroxide solution.
From the given balanced equation,
Each molecule of phosphoric acid reacts with three molecules of sodium hydroxide, we can calculate the number of moles of sodium hydroxide required to reach the third equivalence point as follows:
Number of moles =Concentration × Volume
Number of moles of H3PO4 = 0.250 M x 0.0720 L = 0.0180 mol
Number of moles of NaOH required = 3 x 0.0180 mol = 0.0540 mol
Now, we can calculate the volume of the 0.800 M NaOH solution required to supply 0.0540 mol of NaOH:
Volume of NaOH = 0.0540 mol / 0.800 M = 0.0675 L = 67.5 mL
Hence, 67.5 mL of the 0.800 M NaOH solution is required.
Question 2:
The second equivalence point is reached when all the hydrogen ions (H+) in two molecules of oxalic acid dihydrate have reacted with two molecules of hydroxide ions (OH-) from the sodium hydroxide solution. Since each molecule of oxalic acid dihydrate reacts with two molecules of sodium hydroxide, we can calculate the number of moles of sodium hydroxide required to reach the second equivalence point as follows:
Number of moles of H2C2O4•2H2O = 0.400 M x 0.0650 L = 0.0260 mol
Number of moles of NaOH required = 2 x 0.0260 mol = 0.0520 mol
Now, we can calculate the volume of the 0.333 M NaOH solution required to supply 0.0520 mol of NaOH:
Volume of NaOH = 0.0520 mol / 0.333 M = 0.156 L = 156 mL
Hence, 156 mL of the 0.333 M NaOH solution is required
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A 0.52 kg bird flying at an altitude of 550 meters.
The bird's potential energy is 2,802.8 J.
The potential energy of an object is the energy it has due to its position in a gravitational field. The formula for potential energy is as follows:
PE = m × g × h
Where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.
In this case, the mass of the bird is 0.52 kg, the acceleration due to gravity is 9.8 m/s², and the height is 550 meters. Plugging these values into the formula, we get:
PE = 0.52 kg × 9.8 m/s² × 550 m
PE = 2,802.8 J
Therefore, the potential energy of the bird is 2,802.8 joules.
Your question seems incomplete. The completed version should be as follows:
A 0.52 kg bird flying at an altitude of 550 meters. What is the bird's potential energy?
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Which technique uses a porous barrier to separate a solid from a liquid?
Answer:
Filtration
Explanation:
FILTRATION = A technique that uses a porous barrier to separate a solid from a liquid.
What is the percent by mass of hydrogen in NH3 ? (NH3 = 17.0 grams/mol) 17.6% 82.4% 21.4% 5.9%
The percent by mass of hydrogen in NH3 is 82.4%.
How many moles of hydrogen are present in 34 grams of NH3?To find out the number of moles of hydrogen in 34 grams of NH3, first we need to find the number of moles of NH3 which can be calculated by dividing 34 grams by the molar mass of NH3 (17.0 grams/mol). Therefore, the number of moles of NH3 is 2 moles. As NH3 contains 3 moles of hydrogen per mole, the number of moles of hydrogen in 34 grams of NH3 is 2 x 3 = 6 moles.
Molecular mass of NH3 = 1 x atomic mass of N + 3 x atomic mass of H
= 1 x 14.01 + 3 x 1.01
= 17.03 g/mol
Mass percent of hydrogen in NH3 = (3 x atomic mass of H) / molecular mass of NH3 x 100%
= (3 x 1.01 g/mol) / 17.03 g/mol x 100%
= 82.4%
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For a helium atom in a one-dimensional box calculate the value of the quantum number of the energy level for which the energy is equal to 3/2kT at 25 degrees C (a) for a box 1 nm long, (b) for a box 10^-6 m long, and (c) for a box 10^-2 m long.Please show answer with steps!
As the quantum numbers depend on the number of energy levels in an atom there are 2 quantum numbers for helium owing to it's 2 electrons.
What is an energy level?Electrons present in an atom revolve in different orbits which are stationary states and are also called as energy levels. The energy levels are numbered as integers which are also called as principal quantum numbers.
Energy of the stationary state is given as E= -R
1/n² where R
is the Rydberg's constant. When an electron is excited, and it moves from lower to higher energy levels there is absorption of energy, while when it moves from higher energy level to lower energy level it radiates or gives out energy in the form of radiation.
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Define class A burette a
A Class A burette is a type of laboratory glassware used for precise volumetric measurements of liquids.
What is a class A burette ?This burette is a graded glass tube with a glass tip at one end. It is utilized to dispense liquids in predetermined quantities. Most experiments requiring titration use a burette.
It is typically made of borosilicate glass and has a long, narrow, cylindrical shape with a stopcock at the bottom for dispensing the liquid. The burette is usually graduated in milliliters (mL) with the smallest graduation being 0.1 mL.
Class A burettes are manufactured and tested according to strict standards set by organizations such as the National Institute of Standards and Technology (NIST) in the United States, and the International Organization for Standardization (ISO) globally.
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Cite the evidence that indicates that both physical and chemical changes occur when a copper wire is heated in a Bunsen burner flame. (More than one answer may be correct.) The original appearance was not restored when the wire cooled, instead a new substance appears. No change in the composition of the copper wire could be detected The original appearance was restored when the wire cooled. The wire changed color during the heating
Answer:
When a copper wire is heated in a Bunsen burner flame, the copper's color changes to become a glowing red. It won't be restored to its original appearance after cooling. Instead, it becomes a black material called copper (II) oxide, which is 79.9% copper and 20.1% oxygen (was 100% copper before it was burned). This chemical change occurred as the oxygen in the air combined with the copper during the heating process.
Explanation:
The evidence that indicates that both physical and chemical changes occur when a copper wire is heated in a Bunsen burner flame are:
The original appearance was not restored when the wire cooled, instead a new substance appears.
The wire changed color during the heating.
What is a physical change ?A physical change is a type of change in which the form, shape, size, or state of matter of a substance is altered, but the substance itself remains the same chemically. In other words, the composition of the substance does not change.
Examples of physical changes include changes of state (such as melting, freezing, or vaporization), changes in shape or size (such as crushing or cutting), and changes in appearance (such as changing color or texture).
A chemical change involves breaking or making of chemical bonds. This include formation of a new compounds and some color changes. Therefore,
The original appearance was not restored when the wire cooled, instead a new substance appears, states a physical change and
The wire changed color during the heating indicates a chemical change.
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What is the volume in liters of 5.50 moles of CO2 at standard
temperature and pressure (STP)?
The volume of 5.50 moles of CO2 at STP is 120.02 liters.
What is standard temperature and pressure?To calculate the volume of 5.50 moles of CO2 at standard temperature and pressure (STP), we need to use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (0 degrees Celsius). The gas constant is 0.08206 L•atm/mol•K.
So we can plug in the values and solve for V:
V = nRT/P = (5.50 mol)(0.08206 L•atm/mol•K)(273.15 K)/(1 atm) = 120.02 L
Therefore, the volume of 5.50 moles of CO2 at STP is 120.02 liters.
Standard temperature and pressure (STP) is a set of standard conditions used for measuring and comparing the properties of gases. STP is defined as a temperature of 273.15 Kelvin (0 degrees Celsius) and a pressure of 1 atmosphere (atm). These standard conditions allow scientists to compare the behavior of gases under the same set of conditions, making it easier to compare and contrast the properties of different gases.
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The number of moles is 123.2 moles
How can you find the volume form moles?To find the volume of a substance from its number of moles, you will need to know its molar volume, which is the volume occupied by one mole of a substance. The molar volume can vary depending on the temperature and pressure, so you will need to specify these conditions.
The formula to calculate the volume of a substance from its number of moles is:
Volume = Number of moles x Molar volume
We know that;
1 mole occupies 22.4 L
5.5 moles occupies 5.5 moles * 22.4 L/1 mole
= 123.2 moles
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How to find answers for a-e
The balanced equation for the given reaction is Cu[tex]_2[/tex]SO[tex]_4[/tex] + Ba(NO[tex]_3[/tex])[tex]_2[/tex] →2CuNO[tex]_3[/tex]+ BaSO[tex]_4[/tex]. The precipitates that result from it are these insoluble salts.
What is precipitation reaction?Chemical reactions known as precipitation reactions take place in aqueous solutions to produce precipitates. Moreover, chemical changes that occur inside the substances are a part of chemical processes. Hence, under some circumstances, it creates an entirely novel element.
It denotes a chemical process in which two ions combine to generate insoluble salts in aqueous solutions. The precipitates that result from it are these insoluble salts. Single displacement reactions and double displacement reactions are also possible.
a)The balanced equation for the given reaction is
Cu[tex]_2[/tex]SO[tex]_4[/tex] + Ba(NO[tex]_3[/tex])[tex]_2[/tex] →2CuNO[tex]_3[/tex]+ BaSO[tex]_4[/tex]
b) moles of Ba(NO[tex]_3[/tex])[tex]_2[/tex] = 0.02×0.2=0.04moles
The mole ratio between Ba(NO[tex]_3[/tex])[tex]_2[/tex] and BaSO[tex]_4[/tex] is 1:1
moles of BaSO[tex]_4[/tex]= 0.04moles
Therefore, the balanced equation for the given reaction is
Cu[tex]_2[/tex]SO[tex]_4[/tex] + Ba(NO[tex]_3[/tex])[tex]_2[/tex] →2CuNO[tex]_3[/tex]+ BaSO[tex]_4[/tex]
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What is the density of a liquid with a mass of 17.4 g and a volume of 20 mL? Where would this liquid be in the column?
The density of the liquid is 0.87 g/mL. This liquid would be located in the "less dense than water" column since the density is less than 1 g/mL.
What is density?Density is a measure of mass per unit volume. It is used to measure the concentration of matter in a given space. The SI unit of density is kg/m3, although other units such as g/cm3 may also be used. The density of an object can be determined by dividing its mass by its volume. Density is an important physical property that affects how materials interact with each other, as well as how they interact with light and sound. For example, a denser material will be more likely to sink in a liquid. Additionally, higher density materials will generally be more durable than lower density materials. Density is also an important factor in understanding the behavior of fluids and gases.
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1. Calcutate the mass of Sliver deposited
at the Cathode during the electrysis of
Nitrate (AgNO3) Solution, H,
bliver
CL use of
of
Current
DIO
The mass of sliver deposited at the cathode during the electrolysis of Nitrate (AgNO₃) solution is 0.0011 gram.
What is electrolysis ?
The term electrolysis is defined as a chemical reaction that happens when an electric current is pass over through a substance. The substance gets or loses an electron during chemical reaction.
Given:
Current = 0.10 ampere
Tome = 10 second
Molar mass of Ag = 108 g mol−1
1 Faraday = 96500 C
Q = i × t
=0.1 × 10 × 60
= 60 Coulombs
Weight of the substance deposited = ZQ
Z=M/nF
n-factor of AgNO3 = 1
Z = 108 / 1 × 96500
= 0.0011 gram
Thus, 0.0011 gram is the mass of Sliver deposited at the Cathode during the electrolysis of Nitrate (AgNO₃) Solution.
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Your question is incomplete, most probably your question was
Calculate the mass of Sliver deposited at the Cathode during the electrolysis of Nitrate (AgNO3) Solution,use a current of 0.10 ampere for 10 minutes.
How many molecules are in 0.0023 moles of CO2?
Taking into account the definition of Avogadro's Number, 1.38529×10²¹ molecules in 0.0023 mole of CO₂ .
Definition of Avogadro's NumberAvogadro's number is defined as the number of particles (atoms, molecules, ions, electrons) in 12 grams of carbon-12, that is, in one mole of the substance or compound.
Its value is 6.023×10²³ particles per mole and it applies to any substance.
Molecules of CO₂ in this caseConsidering the definition of Avogadro's number, you can apply the following rule of three: If 1 mole of CO₂ contains 6.023×10²³ molecules, 0.0023 mole of CO₂ contains how many molecules?
amount of molecules of CO₂= (0.0023 moles × 6.023×10²³ molecules)÷ 1 mole
amount of molecules of CO₂= 1.38529×10²¹ molecules
Finally, there are 1.38529×10²¹ molecules.
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How many molecules are in 38.8g of C4H8O2?
Answer:
14
Explanation:
What is the molarity of ions in a 0.611 M solution of Li₂SO assuming
the compound dissociates completely?
The compound Li₂SO₄ on dissociation gives two moles of Li+ ions and one mole of SO₄ ²⁻ ions. Then the molarity of SO₄ ²⁻ is 0.611 M itself and the molarity of Li+ ions is 1.22 M.
What is molarity ?Molarity of a solution is the ratio of number of moles of solutes in that solution to the volume of solution in liters. It is a colligative property and depends on the amount of solute and solvent.
Molarity = n/V in L.
Given that, the molarity of Li₂SO₄ solution is 0.611 M. The complete dissociation of this compound is written as follows:
[tex]\rm Li_{2}SO_{4} \rightarrow 2 Li^{+} +SO_{4}^{2-}[/tex]
Here, the ionization of the compound produces 2 moles of Li+ and one mole of sulphate ions. Then, the molarity of the sulphate ions is the same as the whole solution that is 0.611 M.
Then molarity of the Li+ ions in the solution will be 1.22 M.
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GEOLOGY
1. If a rock begins with 4000 atoms of a radioactive isotope, how many would remain
A .after one half-life?
B. after two half-lives?
C. after three half-lives?
D. after four half-lives?
2. If an isotope has a half-life of twenty million years, and there is 25% of the isotope remaining in a rock, how old is the rock?
A. 10 million years
B. 20 million years
C. 40 million years
D. 60 million years
3. A scientist radiometrically dates 3 different rocks using 3 separate decay series.
Rock A is dated using isotope A (half-life = 50 years)
Rock B is dated using isotope B (half-life = 100 years),
Rock C is dated using isotope C (half-life = 1000 years).
If each rock contains 50% of their measured radioactive element and 50% of its corresponding daughter element, which rock is oldest?
A. Rock A
B. Rock B
C. Rock C
D. Impossible to tell
4. An ArcheologistLinks to an external site. finds some cotton cloth at a burial site and wants to determine the age of the remains. Which isotopic system should they use?
A. Carbon-14
B. Uranium
. Potassium-Argon
5. The Archeologist determines that there is 16.7% of the parent isotope remaining in the cloth sample. How old is the burial site? Hint: you can find the length of the half-life in the reading above.
A. 13,559 years
B. 14,798 years
C. 16,743 years
D. 1.66 billion years
E. 1.81 billion years
F. 2.05 billion
6. A geologist is trying to date a sequence of sedimentary rocks with abundant fossils and sandstones. Within the sequence is a distinctive clay layer that, under closer inspection, turns out to be fine-grained volcanic ash. Which of the following is the best way to obtain an absolute date for the sequence of rocks?
A. Carbon date the fossils
B. Potassium-Argon date the sands
C. Uranium date the Zircons in the ash
D. Identify the index fossils
7. The geologist determines there is 78.3% of the parent remaining in the sample that they examine. How old is the sequence of rocks? Hint: you can find the length of the half-life in the reading above.
A. 187.5 million years
B. 247.8 million years
C. 390.7 million years
D. 2.504 billion years
E. 1.588 billion years
F. 1.202 billion years
A rock that begins with 4000 atoms of a radioactive isotope would have the following remain;
A. After one half-life, 2000 atoms would remain.
B. After two half-lives, 1000 atoms would remain.
C. After three half-lives, 500 atoms would remain.
D. After four half-lives, 250 atoms would remain.
If an isotope has a half-life of twenty million years, and there is 25% of the isotope remaining in a rock, how old is the rock?If 25% of the isotope remains, that means 75% has decayed. Since each half-life represents 20 million years, two half-lives (40 million years) would result in 25% of the original isotope remaining, and therefore four half-lives (80 million years) would result in 6.25% of the original isotope remaining. Therefore, the rock must be older than 40 million years but younger than 80 million years. Since the answer choices only include 40 million years and 60 million years, the closest answer is C, 40 million years.
Each rock has decayed 50% of its radioactive element, which means they have all undergone the same amount of decay. However, since each isotope has a different half-life, the amount of time it takes to undergo 50% decay will be different. The rock dated with isotope C has the longest half-life, and therefore has undergone the least amount of decay and must be the oldest.
Carbon-14 dating is the best choice for dating organic materials, such as cotton cloth.
Using the half-life of Carbon-14 (5730 years), we can calculate the age of the burial site using the formula t = (ln(0.167) / ln(0.5)) x 5730. This results in an age of approximately 14,798 years.
The best way to obtain an absolute date for the sequence of rocks would be to date the volcanic ash layer using a radiometric dating method such as Uranium dating, which would provide an age for the time at which the ash was deposited. This age could then be used to bracket the ages of the sedimentary rocks above and below the ash layer.
Conclusively, Using the half-life of the parent isotope, we can calculate the age of the sequence of rocks using the formula t = (ln(0.783) / ln(0.5)) x length of the half-life. Since we don't know the specific isotope being used, we can't calculate the exact age, but the closest answer choice is E, 1.588 billion years.
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Carbonyl fluoride, cof2 , is an important intermediate used in the production of fluorine-containing compounds. For instance, it is used to make the refrigerant carbon tetrafluoride, cf4 via the reaction.
The concentration of carbonyl fluoride (COF2) remains at equilibrium is 0.33M if only COF2 is present initially at a concentration of 2.00 M.
The reaction given is an equilibrium reaction, and so the reaction can be expressed in terms of the equilibrium constant (Kc).
The equilibrium constant (Kc) for the reaction is given as = 5.10.
[tex]2COF2(g) ,--- > CO2(g)+CF4(g)[/tex]
For an equilibrium reaction, the equilibrium concentration of the reactants can be determined using the following equation:
[tex]Kc = [CO2][CF4]/[COF2]^2[/tex] Where [CO2], [CF4], and [COF2] are the equilibrium concentrations of the respective species.
Rearranging the equation gives us the following expression:
[tex][COF2]^2 = [CO2][CF4]/Kc[/tex]
ICE chart is :
[tex]2COF2(g) < -- > CO2(g) + CF(g)[/tex]
I 2 0 0
C -2x +x +x
----------------------------------------------------------
E 2-2x x x
Plugging in the values given, we can calculate the equilibrium concentration of COF2:
[tex]Kc = (x)(x)/(2-2x)^2[/tex]
[tex]6.40 = x^2/(2-2x)^2[/tex]
Taking the square root of both sides, we can calculate the equilibrium concentration of COF2:
x = 0.835M
[COF2] = 2-2x =2 -2(0.835) = 0.33M
Therefore, if only COF2 is present initially at a concentration of 2.00 M, the concentration of COF2 at equilibrium will be 0.33 M.
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complete question: Carbonyl fluoride, COF2 , is an important intermediate used in the production of fluorine-containing compounds. For instance, it is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction 2COF2(g)⇌CO2(g)+CF4(g), Kc = 6.40 . If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2 remains at equilibrium?
the angle between the bonds between the carbon atom and hydrogen atoms located at vertices and___, is given by the expression
Answer:
if u are talking Abt H2O then the shape is vent shaped and angle between both oxygen atoms is 104.5°
Explanation:
I hope the image helps
What mass (in grams) of aluminum chloride has the same number of aluminum atoms as
3.19g of aluminum oxide?
The mass (in grams) of aluminum chloride that has the same number of aluminum atoms as 3.19 g of aluminum oxide is 8.36 g
How do I determine mass of aluminum oxide?First, we shall determine the mass of aluminum, Al present in 3.19 g of aluminum oxide, Al₂O₃. Details below:
1 mole of Al₂O₃ = (27 × 2) + (16 × 3) = 102 gMass of Al in 1 mole of Al₂O₃ = 2Al = 2 × 27 = 54 gMass of Al in 3.19 g of Al₂O₃ =?102 g of Al₂O₃ contains 54 g of Al
Therefore,
3.19 g of Al₂O₃ will contain = (3.19 × 54) / 102 = 1.69 g of Al
Next, we shall determine the number of atoms in 1.69 g of Al. Details below:
From Avogadro's hypothesis,
1 mole of Al = 6.02×10²³ atoms
But
1 mole of Al = 27 g
Thus,
27 g of Al = 6.02×10²³ atoms
Therefore,
1.69 g of Al = (1.69 × 6.02×10²³) / 27
1.69 g of Al = 3.772×10²² atoms
Finally, we shall determine the mass of aluminum chloride, AlCl₃. Details below:
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of AlCl₃
But
1 mole of AlCl₃ = 133.5 g
Thus,
6.02×10²³ atoms = 133.5 g of AlCl₃
Therefore,
3.772×10²² atoms = (3.772×10²² × 133.5) / 6.02×10²³
3.772×10²² atoms = 8.36 g
Thus, the mass of aluminum chloride, AlCl₃, is 8.36 g
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Wind has less energy as it slows, and _____ of sediment occurs.
As the wind slows, silt is deposited because the wind has less energy.
When a stream slows down, what happens to the sediment?Deposition in rivers and streams. A stream or river begins to deposit silt when it begins to slow down. In steep terrain, larger sediments fall, but smaller sediments can still be carried. As the slope gets less steep, smaller sediments are dropped.
What transpires to sediments as wind speed decreases?Sediment that has been eroded is deposited in a new location when the speed of the wind or water slows. Fertile land is produced as a result of the sedimentation process.
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The relation between the volume of titanium and iron in a bicycle weighing 5 kg, if
titanium has a density of 4.5g/cm³ and iron has a density of 7.87 g/cm 3 (ignore
other materials). Write a constraint equation, determine two solutions, and graph
the equation and mark your solutions.
please help
The solutions for both are:
V_titanium = (1/4) V_total ≈ 0.188 cm³
And
V_iron = (3/4) V_total ≈ 0.565 cm³
We have a line in the V_titanium-V_iron plane with slope -4.5/7.87 and y-intercept 5/7.87. The two solutions above correspond to the points where this line intersects the line V_titanium = 0 and V_iron = 0, respectively.
Calculating the volumes of Titanium and IronThe volume of titanium and iron in a bicycle can be related using the following constraint equation:
V_titanium * 4.5 + V_iron * 7.87 = M_total / 1000
where V_titanium and V_iron are the volumes of titanium and iron in cubic centimeters (cm³), M_total is the total mass of the bicycle in grams (g), and we divide by 1000 to convert the mass to kilograms.
We are given that the bicycle weighs 5 kg or 5000 g, so we can substitute M_total = 5000 into the equation:
V_titanium * 4.5 + V_iron * 7.87 = 5000 / 1000
4.5 V_titanium + 7.87 V_iron = 5
This is a linear equation in two variables, V_titanium and V_iron. To find two solutions, we need one additional equation that relates V_titanium and V_iron. One possibility is to assume that the bicycle contains a fixed ratio of titanium to iron, say 1:3. Then we can write:
V_titanium = (1/4) V_total
V_iron = (3/4) V_total
where V_total is the total volume of the bicycle, which is the sum of the volumes of titanium and iron:
V_total = V_titanium + V_iron
Substituting these expressions into the constraint equation and simplifying, we get:
(4.5/4) V_total + (7.87/4) V_total = 5/2
3.31 V_total = 5/2
V_total = (5/2) / 3.31
V_total ≈ 0.753 cm³
Using the ratios above, we can then calculate the volumes of titanium and iron:
V_titanium = (1/4) V_total ≈ 0.188 cm³
V_iron = (3/4) V_total ≈ 0.565 cm³
These are the two solutions for the volumes of titanium and iron in the bicycle, assuming a fixed ratio of 1:3.
To graph the constraint equation, we can solve for V_iron as a function of V_titanium:
V_iron = (5 - 4.5 V_titanium) / 7.87
This gives us a line in the V_titanium-V_iron plane with slope -4.5/7.87 and y-intercept 5/7.87. The two solutions above correspond to the points where this line intersects the line V_titanium = 0 and V_iron = 0, respectively.
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