Answer:
what is the question? probably describe the polynomial. okay. the polynomial 10v^2 + 50 is a quadratic (it is to the 2nd power) and a binomial (has 2 terms).
The diagonals of a rectangle measure x+5 feet and 2x+1 feet what is the value of x?
The value of x is 4.
Given that diagonals of a rectangle measure x+5 feet and 2x+1 feet as shown in the attached figure.
The diagonal of a rectangle is a line or straight line that connects the opposite corners or vertices of the rectangle.
In the given figure ABCD is a rectangle.
OA=2x+1 and OD=x+5 [Given]
AC and BD are diagonals of a rectangle.
As we know that the diagonals of a rectangle are always equal.
So, AC = BD
We can also write it as,
2×OA=2×OD
2×(2x+1) =2×(x+5)
Apply the distributive property a(b+c)=ab+ac, we get
4x+2=2x+10
Subtract 2x from both sides, we get
4x+2-2x=2x+10-2x
2x+2=10
Subtract 2 from both sides, we get
2x+2-2=10-2
2x=8
Divide both sides by 2, we get
2x/x=8/2
x=4
Hence, the value of x=4 when diagonals of a rectangle measure x+5 feet and 2x+1 feet.
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can someone please help me with 17a
Answer:
r=8.74038744 m
and surface area=1303.76211 m2
Step-by-step explanation:
Given that SQ⎯⎯⎯⎯⎯ bisects ∠PSR and PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯, which of the following triangle congruence statements can be used to prove that ∠P≅∠R?
The figure shows two triangles P S Q and R S Q with a common side S Q.
The congruency proof that can be used to show that ∠P≅∠R is as given in the steps below.
How to prove Triangle Congruence?
From the figure as seen online, we can see that;
The figure shows the same triangles PQS and RQS as in the beginning of the task. Angles SPQ and SRQ are highlighted in red.
Thus, the 2 column proof to show that ∠P≅∠R is;
Statement 1; ∠SPQ≅∠SRQ
Reason 1; Given
Statement 2; SQ bisects ∠PSR
Reason 2; Given
Statement 3; ∠PSQ≅∠QSR
Reason 3; Definition of angle bisector
Statement 4; SQ ≅ SQ
Reason 4; Reflexive Property of Congruence
Statement 5; △PQS≅△RQS
Reason 5; Angle - Angle Side (AAS) Congruency Postulate
Statement 6; PS ≅ SR
Reason 6; CPCTC (Corresponding parts of congruent triangles are congruent)
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What is the total probability of rolling a single die twice, and having it land on 3 the
first roll, and a number greater than 3 the second roll?
er:
Answer:
0,5*0,5=0,25
Step-by-step explanation:
assuming a die of 6 faces
25
0,5 for < 4; 0,5 for < 3
Answer the question please!!!!!!
[tex]Simplify \: \: \\ ( \: a \: ) \: 287 \: \times \: 90 \\ ( \: b \: ) \: 105 \: \times 95[/tex]
Answer:
a) 25830
b)9975
Step-by-step explanation:
a) 287
x 90
25830
b) 105
x 95
9975
Function the graphic below:
The graph is a decreasing exponential graph.
How to illustrate the information?Part A: The given graph is decreasing the exponential graph since the graph is decreasing rapidly as the value of x is increasing and the value of y is decreasing rapidly.
Part B: The graph shown here is maybe the case of any electric appliance which is of cheap quality. The time when it is brought then its performance and its life is awesome after that its life is decreasing rapidly.
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Complete question:
Describe a relationship that can be modeled by the function represented by the graph, and explain how the function models the relationship. Identify and interpret the key features of the function in the context of the situation you described in part A.
I WILL GIVE BRAINLIEST!!!!
2 step equation:
4x + 3 = 19
2 step equation w/ fractions:
(4/3)x + 5 = 17
Distributive Property:
4x(6 - 2) - 10 = 20
Decimals:
4.3x + 0.7 = 5
Real world equation:
Sharon's restaurant is bringing in money from customers, and she needs to know how much she needs to pay off the bill for the electricity to run the place. To turn the electricity on, she has to pay $25. For every hour that the electricity is on for, she has to pay $4. How many hours can she have the electricity on for if she makes $49 profit?
i really need some help solving these
The answers to the questions are:
1. x = 4
2. x = 1.5
3. x = 1.875
4. x = 1
2 step equation:1. 4x + 3 = 19
4x = 19 - 3
4x = 16
divide by 4
x = 4
2 step equation w/ fractions:(4/3)x + 5 = 17
= 1.33x + 5 = 7
Take like terms
1.33x = 7-5
1.33x = 2
divide through by 1.33x to get 2
x = 2/1.33
x = 1.5
3. Distributive Property:4x(6 - 2) - 10 = 20
Multiply and open the bracket
24x - 8x - 10 = 20
Take like terms
16x = 20+10
16x = 30
x = 30/16
= 1.875
4. Decimals:4.3x + 0.7 = 5
4.3x = 5 - 0.7
4.3x = 4.3
x = 1
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PLEASE ANSWER QUICKLY
By applying the definition of product between two square matrices, we find that [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right][/tex] is equal to the matrix [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right][/tex]. (Correct choice: D)
What is the product of two square matrices
In this question we must use the definition of product between two square matrices to determine the resulting construction:
[tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right][/tex]
[tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right][/tex]
By applying the definition of product between two square matrices, we find that [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}1&2\\3&6\end{array}\right] \cdot \left[\begin{array}{cc}1&2\\3&6\end{array}\right][/tex] is equal to the matrix [tex]\vec A \,\cdot \,\vec A = \left[\begin{array}{cc}7&14\\21&42\end{array}\right][/tex].
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A teacher knows that 80% of her students will score no more than 5 points above or below the class average, 85%, on the test. Which inequality represents the test scores of 80% of her students?
Answer:
[tex]|x-85| \leq 5[/tex]
Step-by-step explanation:
|x-85| represents the 'distance' of the test score than 85, and this distance must be less than or equal to 5.
Type SSS, SAS, ASA, SAA, or HL to
justify why the two larger triangles are
congruent.
A
B
F
D
C
E AC = BC
ZAZB
Answer:
ASA
Step-by-step explanation:
If my savings of $x grows 10% each year. how much will I have in: 2 years
The amount I'll have in two years at the growth rate described is; $1.21x.
How much will I have in 2 years?Since it follows that the savings grow by 10% each year, it can be concluded that the growth factor is; 110% = 1.1
Hence, in two years, we have;
= $x × (1.1)²
= $1.21x.
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Answer:
1.21x
Step-by-step explanation:
on rsm it says its correct
PLEASE HELPPPPPPPPPPPPPPPPPPPPPPP
Answer:
x intercepts: (1,0), (-3,0)
the roots are 1 and -3
Step-by-step explanation:
Using the Quadratic Formula:
x=−b±sqrt(b2−4ac)/2a
Substitute:
x= -8±sqrt(8^2-4(4)(-12))/2(4)
x=-8±sqrt((64- -192))/8
x=-8±sqrt(256)/8
Solve two equations (±)
x=-8±16/8
x=8/8 and x=-24/8
x=1 and x=-3
Answer:
x = -3
x = 1
Step-by-step explanation:
Hello!
We can solve the quadratic by Factoring the Equation and using the Zero Product Property.
Factor[tex]y = 4x^2 + 8x - 12[/tex][tex]y = 4(x^2 + 2x - 3)[/tex]
We want to find two numbers that multiply out to -3, but add up to 2. The numbers that work are -1 and 3. We can expand 2x to -x and 3x and factor by grouping.
[tex]y = 4(x^2 -x + 3x - 3)[/tex][tex]y = 4(x(x - 1) + 3(x - 1))[/tex][tex]y = 4(x + 3)(x - 1)[/tex]Solve for x
Set each factor to 0 and solve for x in both.
[tex]0 = 4(x + 3)(x - 1)[/tex][tex]0 = (x + 3), x = -3[/tex][tex]0 = (x - 1), x = 1[/tex]Therefore, the x-interecpts are -3 and 1.
Consider the function f(x) = one-third(6)x. what is the value of the growth factor of the function?
6 is the growth factor in the function f(x) = (1/3)(6ˣ).
The rate at which a quantity multiplies itself over the independent factor, to increase the value of the function exponentially is known as its growth factor.
In the question, we are given a function f(x) = (1/3)(6ˣ) and are asked to identify the growth factor of the function.
We know that the rate at which a quantity multiplies itself over the independent factor, to increase the value of the function exponentially is known as its growth factor.
In the given function, f(x) = (1/3)(6ˣ), (1/3) remains unaffected with the change in the independent factor x, but 6 is exponentially increasing with x.
Thus, 6 is the growth factor in the function f(x) = (1/3)(6ˣ).
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The lifetime of a certain type of battery is normally distributed with mean value 13 hours and standard deviation 1 hour. There are nine batteries in a package. What lifetime value (in hours) is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages
The lifetime of the batteries in a package is 14.31 hours which exceeds that value for only 5% of all packages.
Give sample mean of 13 hours and standard deviation of 1 hour and sample size is 9.
We have to apply t test in this because the value of n which is sample size is less than 30.
We have been given the p value of the required mean so we have to find the t value for this with degree of freedom (9-1)=8
t value=2.306.
We know that
t=X bar-μ/s/[tex]\sqrt{n}[/tex]
s/[tex]\sqrt{n}[/tex]=1/[tex]\sqrt{3}[/tex]=0.57
Put all the values in the above formula to calculate required mean.
2.306=X bar-13/0.57
X bar=1.31442+13
=14.31442
after rounding off we get
X bar=14.31
Hence the lifetime of the batteries is 14.31 for which the percentage exceeds 5%.
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The official height to width ratio of the United States flag is 1:1.9 If a United States flag is 6 feet high, how wide is it?
Answer:
11.4 feet
Step-by-step explanation:
1/1.9 = h/w (h= height, w=width)
Solving for w, gives you the formula
w = (1.9)h
This means the width is 1.9 times the height.
Use the formula to find the width where the height is 6 feet.
h = 6
w = (1.9)(6) = 11.4
The width is 11.4 feet.
Line segment Z E is the angle bisector of AngleYEX and the perpendicular bisector of Line segment G F. Line segment G X is the angle bisector of AngleYGZ and the perpendicular bisector of Line segment E F. Line segment F Y is the angle bisector of AngleZFX and the perpendicular bisector of Line segment E G. Point A is the intersection of Line segment E Z, Line segment G X, and Line segment F Y.
Triangle G E F has angles with different measures. Point A is at the center. Lines are drawn from the points of the triangle to point A. Lines are drawn from point A to the sides of the triangle to form right angles and line segments A X, A Z, and A Y.
Which must be true?
Point A is the center of the circle that passes through points E, F, and G but is not the center of the circle that passes through points X, Y, and Z.
Point A is the center of the circle that passes through points X, Y, and Z but is not the center of the circle that passes through points E, F, and G.
Point A is the center of the circle that passes through points E, F, and G and the center of the circle that passes through points X, Y, and Z.
Point A is not necessarily the center of the circle that passes through points E, F, and G or the center of the circle that passes through points X, Y, and Z
The correct option that depicts the centroid of the triangle is; C. Point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.
How to interpret the segments formed from Triangle Centroid?The center of inscribed circle into the triangle is the point where the angle bisectors of the triangle meet.
The center of the circumscribed circle over the triangle is the point where the perpendicular bisectors of the sides meet.
Line segments ZE, FY and GX are both angle bisectors and perpendicular bisectors of the sides. Thus, the point of intersection of line segments ZE, FY and GX is the center of inscribed circle into the triangle and the center of the circumscribed circle over the triangle.
Inscribed circle passes through the points X, Y and Z. Circumscribed circle passes through the points E, F and G. So, point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.
Thus, the correct option is option C. Point A is the center of the circle that passes that passes through the points E, F and G and is the center of the circle that passes through the points X, Y and Z.
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A star is estimated to be 150,000,000,000,000 km away from Earth. Write this distance in scientific notation. [?] × 10 km
Answer:
[tex](1*10^{15} )(5*10^{14})[/tex] or 1.5×10^14
Step-by-step explanation:
The answer is [tex](1*10^{15} )(5*10^{14})[/tex] or 1.5×10^14.
Hope this helps!
Can someone please help me on this?
Answer:
[tex]\frac{9\pi }{4}[/tex] inches
Step-by-step explanation:
I suppose they are asking you for the length of the red part.
18[tex]\pi \\[/tex] * [tex]\frac{45}{360}[/tex] = [tex]\frac{9\pi }{4}[/tex] inches
Answer:
L = 7.07 in
Step-by-step explanation:
L = arc lenght
[tex]L=\frac{\pi (45)(9)}{180} =2.25\pi =7.07in.[/tex]
Hope this helps
question 12 please, i cannot find the central angle.
Answer:
Below.
Step-by-step explanation:
12. That is a semicircle
The central angle is 180 degrees.
Total area=
Help me please, thankss
The Area of given figure is 341.6 square.
According to the statement
we have to find the total area of given figure.
Here a= 10 and h= 11
So, we use the formula is A = a(a + √((a)^2 + 4(h)^2))
where the a represent the base of given solid or sides of the equilateral triangle
And h represent the slant height of the solid.
So, Substitute the values in above formula then
A = 10(10 + √((10)^2 + 4(11)^2))
A = 10(10 + √((100 + 4(121))
A = 10(10 + √(100 + 484)
A = 10(10 + √(584)
A = 10(10 + 24.16)
A = 10(34.16)
A= 341.6
So, The Area of given figure is 341.6 square.
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The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s in the $n^{\rm{th}}$ block. What is the sum of the first $1234$ terms of this sequence
Consider the lengths of consecutive 1-2 blocks.
block 1 - 1, 2 - length 2
block 2 - 1, 2, 2 - length 3
block 3 - 1, 2, 2, 2 - length 4
block 4 - 1, 2, 2, 2, 2 - length 5
and so on.
Recall the formula for the sum of consecutive positive integers,
[tex]\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2[/tex]
Now,
[tex]1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016[/tex]
which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.
In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of
[tex]\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224[/tex]
numbers, and their sum is
[tex]\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400[/tex]
This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of [tex]1+9\times2=19[/tex].
So, the sum of the first 1234 terms in the sequence is 2419.
Determine the slope of the line
Answer:1+1
Step-by-step explanation:
I need help with these questions because I don't understand it.
Evaluating the given expressions and inequalities, we have;
[tex]11) \: \frac{x}{4} \cdot \left(2 + y - x \right) = 4[/tex]
12) (8•a - 5•b) - 2•(a + b) = 4
[tex] 13) \: \frac{p \cdot (p + {a}^{2} )}{6} = 55 [/tex]
[tex] 14) \: 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = 12 [/tex]
[tex] 16) \: x \geq 11\frac{2}{3} [/tex]
17) k > 9
18) v > 9
20) m ≤ 16
Which method can be used to evaluate the expressions and inequalities?The given expressions are;
[tex]11) \: \frac{x}{4} \cdot \left(2 + y - x \right)[/tex]
Where x = 4, and y = 6, we have;
[tex]\frac{x}{4} \cdot \left(2 + y - x \right) = \frac{4}{4} \cdot \left(2 + 6 - 4 \right) = 4[/tex]
Therefore;
[tex]\frac{x}{4} \cdot \left(2 + y - x \right) = 4[/tex]
12) (8•a - 5•b) - 2•(a + b)
Where a = 3 and b = 2, we have;
(8•a - 5•b) - 2•(a + b) = (8×3 - 5×2) - 2•(3 + 2) = 4
Therefore;
(8•a - 5•b) - 2•(a + b) = 4[tex]13) \: \mathbf{\frac{p \cdot (p + {a}^{2} )}{6}} [/tex]
Where a = 7, and p = 6, we have;
[tex] \frac{p \cdot (p + {a}^{2} )}{6} = \mathbf{ \frac{6 \times (6 + {7}^{2} )}{6}} = 55 [/tex]
Therefore;
[tex] \frac{p \cdot (p + {a}^{2} )}{6} = 55 [/tex]
[tex]14) \: \mathbf{3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} } [/tex]
Where m = 5, and n = 6, we have;
[tex] 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = \mathbf{3\times 5 - \frac{2\times 5}{2} +\frac{6}{3} }= 12 [/tex]
Therefore;
[tex] 3\cdot m - \frac{2\cdot m}{2} +\frac{n}{3} = 12 [/tex]
[tex]16) \: \mathbf{1 \frac{1}{6} }\leq \frac{x}{10} [/tex]
Which gives;
[tex] \frac{7}{6} \times 10 \leq x [/tex]
[tex] \mathbf{ \frac{35}{3} }\leq x [/tex]
[tex] x \geq 11\frac{2}{3} [/tex]
17) 20 < k + 11
Therefore;
k > 20 - 11 = 9
k > 918) 6•v > 54
v > 54 ÷ 6 = 9
Therefore;
v > 9[tex]20) \: 8 \geq \mathbf{ \frac{m}{2}} [/tex]
Therefore;
2 × 8 = 16 ≥ m
Which gives;
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5.
MATHEMATICS Year'
A square is folded into half to form a rectangle as shown below. The perimeter of the rectangle is 36 cm.
Calculate the area of the square.
Answer: 144 [tex]cm^{2}[/tex]
Step-by-step explanation:
The rectangle's length is twice as long as it's width as the square is folded in half. Let's say that the width's length is x, we get the equation
x + 2x + x + 2x = 36
6x = 36
x = 6 cm
The length of the rectangle is the length of the square which is 2x = 2 * 6 = 12 cm
So the area of the square is 12 * 12 = 144 [tex]cm^{2}[/tex]
Below is the market for funnel cakes at a small community fair.
a) what is the equilibrium price and quantity of the funnel cakes?
b) What is the total consumer spending on funnel cakes at the equilibrium point?
c) Calculate the producer surplus and consumer surplus at equilibrium. Show your work.
d) What would be the result if the suppliers charged $6? Explain.
e) Cheese pretzels are substitute good for funnel cakes at the same fair. Draw a correctly labeled graph of the market for cheese pretzels. Shade the area of consumer surplus.
f) A large number of new guests enter the fair. Illustrate the effect of this change on the same graph from part E.
g) does the consumer surplus increase, decrease, or stay the same as a result of the change from part F? Explain.
h) A new cheese pretzel stand opens at the same fair. On a new graph, illustrate the market for cheese pretzels at this fair before and after the new stand opened.
i) if the large number of new guests entering the fair happened at the same time that the new cheese pretzel stand open how would the equilibrium price and quantity for cheese pretzels change? Explain.
From the graph given, the equilibrium price and quantities are given respectively as;
Price = $5Quantity = 6 units of funnel cakes.What is the total consumer spending on funnel cakes at the equilibrium point?The total consumer spending(TCS) is achieved by finding the product of the price and the quantities at the equilibrium point.
Hence,
TCS = 5 * 6
= 60
A) The producer surplus is the area of the triangle shaded yellow in the attached image.
Recall that he area of triangle is:
1/2 b * h
b = 4
h = 6
Hence Area of the RA-Triangle (Producer Surplus) =
1/2 * 4 * 6
= 12
B) The Consumer surplus is the area of the triangle shaded Green in the attached image.
Recall that the area of triangle is:
1/2 b * h
b = 4
h = 6
Hence Area of the RA-Triangle (Consumer Surplus) =
1/2 * 4 * 6
= 12
What would be the result if the suppliers charged $6?
If the suppliers charged $6, then the quantity demanded would drop to 4 units of funnel cakes. It is demonstrated graphically. Recall that the law of demand and supply indicates that when prices goes up, demand comes down and vice versa.
Graph II illustrates what would happen if a large number of guests entered the fair. It would result to a right-ward shift in the demand curve.
Does the consumer surplus increase, decrease, or stay the same as a result of the change from part F?Yes, there is an increase in the consumer surplus. Now there are more consumers hence the total amount they are willing to pay as an aggregate sum has increased from what was.
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The population parameters that describe the y-intercept and slope of the line relating y and x, respectively, are _____. Group of answer choices B0 and B1 y and x a and b a and B
B0 AND B1 are the parameters which describes the intercept and slope of the lines.
According to statement
we have to find the parameters which describes the intercept and slopes.
Simple linear regression is a model that estimates the relationship between one independent variable and one dependent variable using a straight line. Both variables should be quantitative.
So, B0 AND B1 are the parameters which describes the intercept and slope of the lines.
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What is the perimeter of a regular heptagon with a side length of 8 units? 48 units 56 units 72 units 32 units
Answer:
The answer to your question is P=56
Step-by-step explanation:
P=7a=7·8=56
I hope this helps and have a good day!
Find the equation of the line through point (−1,4) and parallel to 5x+y=4. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).
The equation of the parallel line is y = -5x - 1
How to determine the line equation?The equation is given as:
5x + y = 4
Make y the subject
y = -5x + 4
The slope of the above equation is
m = -5
Parallel lines have equal slope.
This means that the slope of the new line is 5
The equation is then calculated as:
y = m(x - x1) + y1
So, we have:
y = -5(x + 1) + 4
Expand
y = -5x - 5 + 4
Evaluate
y = -5x - 1
Hence, the equation of the parallel line is y = -5x - 1
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Find the equation of the line with slope = 6 and passing through (2,20). write your equation in the form y = mx + b.
Answer:
y = 6x + 8
Step-by-step explanation:
y = mx + b
20 = 6(2) + b
b = 8
y = 6x + 8
The Bay announced it would open a 9000-plus square metre freestanding store in the new West Grand Promenade. This would be the largest store on the promenade, with other smaller stores selling food, tires, and shoes. How else can this particular Bay store be described
This Bay store can also be described as a big box retailer store.
Big Box Retailer
A big box retailer is a physically enormous retail store that is typically a component of a chain of stores (also known as a hyper store, supercenter, superstore, or megastore). By extension, the phrase, big box retailer can also refer to the business that runs the store.
The Bay Store as a Big Box
There are numerous retail chains that only operate in Canada, aside from the large American big box retailer stores like Walmart Canada and the formerly-existent Target Canada. These include places like Hudson's Bay by Home Outfitters, Loblaws by Real Canadian Superstore, Rona, Winners by HomeSense, Canadian Tire by Mark's & Sport Chek, Shoppers Drug Mart, Chapters by Indigo Books and Music, Sobeys, and several others.
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