44. Calculate the mass of 0.00456 moles of (NH4)2SO4A) 132 g B) 3.45 x 10-5 g C) 114 g D) 0.603 g E) 0.520 g

Answers

Answer 1

A) 132 g

Explanation:

The molar mass of (NH4)2SO4 can be calculated as follows:

Molar mass of NH4 = 14.01 g/mol

Molar mass of SO4 = 96.06 g/mol

Molar mass of (NH4)2SO4 = (2 x 14.01 g/mol) + (1 x 32.07 g/mol) + (4 x 16.00 g/mol) = 132.14 g/mol

Therefore, the mass of 0.00456 moles of (NH4)2SO4 is:

Mass = 0.00456 moles x 132.14 g/mol = 0.603 g

The correct answer is D) 0.603 g.

Explanation:

The molar mass of (NH4)2SO4 is the sum of the molar masses of its constituent elements. We can calculate the molar mass of each element by looking up their atomic masses on the periodic table. The molar mass of NH4 is (1 x 14.01 g/mol) + (4 x 1.01 g/mol) = 18.05 g/mol, and the molar mass of SO4 is (1 x 32.07 g/mol) + (4 x 16.00 g/mol) = 96.06 g/mol.

To calculate the molar mass of (NH4)2SO4, we need to multiply the molar mass of NH4 by 2 (since there are 2 NH4 groups in the compound) and add it to the molar mass of SO4. This gives us:

Molar mass of (NH4)2SO4 = (2 x 18.05 g/mol) + 96.06 g/mol = 132.14 g/mol

Now we can use this molar mass to calculate the mass of 0.00456 moles of (NH4)2SO4:

Mass = 0.00456 moles x 132.14 g/mol = 0.603 g

Therefore, the correct answer is D) 0.603 g.

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Related Questions

CO2 in beer is increased after fermentation by two different methods, what are they

Answers

The two main methods used to increase CO2 levels in beer after fermentation are natural carbonation and forced carbonation.

Natural carbonation involves adding a small amount of sugar to the beer before bottling or kegging. The residual yeast in the beer will consume the sugar, producing CO2 as a byproduct, which will dissolve into the beer, naturally carbonating it. This process can take anywhere from a few days to a few weeks, depending on the beer style and temperature.

Forced carbonation, on the other hand, involves using a CO2 tank to directly inject carbon dioxide into the beer. The beer is placed in a closed vessel and pressurized with CO2 until the desired level of carbonation is reached. This method is much quicker and more precise than natural carbonation, but it requires specialized equipment and can be more expensive.

Both methods have their advantages and disadvantages, and many breweries use a combination of both to achieve the desired level of carbonation for their beers. The level of carbonation can greatly affect the taste and mouthfeel of the beer, so it is an important consideration for brewers to get right.

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6.8. Compared to glass, plastic sheet substitutes are generally less A. durable.
C. transparent.
B. fire-resistant.
D. expensive.

Answers

Compared to glass, plastic sheet substitutes are generally less durable.

Glass is a very strong and durable material that is much more resistant to scratches and other types of wear and tear than plastic. Plastic sheets are often used as a substitute for glass because they are often cheaper and lighter, but they are not as strong or as durable.Plastic sheeting is generally not as durable as glass, as it is more prone to cracking, scratching, and other damage. Plastic can also be affected by extreme temperatures, whereas glass is more heat-resistant. Additionally, plastic is much more susceptible to UV radiation damage, which can cause it to become brittle and break over time. Glass, on the other hand, is highly durable and can withstand extreme temperatures and pressure without cracking or breaking.

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Compound 1 is a stronger acid than Compound 2 because the anion of Compound 1 is better stabilized by:A. resonance effect.B. dehydrationC. an inductive effectD. hydrogen bonding between OH and CO2-

Answers

Compound 1 is a stronger acid than Compound 2 because the anion of Compound 1 is better stabilized by Option A. resonance effect. This allows for the distribution of the negative charge over a larger area, making the anion more stable and the acid stronger.

This means that the negative charge on the anion of Compound 1 is spread out over multiple atoms, making it more stable and less likely to react with other molecules. In contrast, Compound 2 does not have this stabilization effect, making it a weaker acid. Dehydration, inductive effects, and hydrogen bonding do not play significant roles in determining the acidity of these compounds. Hence, the correct answer is A. Compound 1 is a stronger acid because the anion of Compound 1 is better stabilized by the resonance effect.

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Question 12
The only criteria gas that is colored is:
a. Nitrogen dioxide
b. Carbon monoxide
c. Ozone d. Sulfur dioxide

Answers

The only gas among the given options that is colored is nitrogen dioxide. It is a reddish-brown gas that has a pungent odor. Nitrogen dioxide is formed due to the combustion of fossil fuels, and it is a significant air pollutant.

It is harmful to human health as it can cause respiratory problems and aggravate asthma.

The other gases in the options, carbon monoxide, ozone, and sulfur dioxide, are colorless gases.

Criteria, in this context, refers to the specific characteristics that differentiate nitrogen dioxide from the other gases in the options. One such criterion is its characteristic color. It is essential to understand the criteria that differentiate different substances to identify and classify them correctly.

In conclusion, the only gas among the options that is colored is nitrogen dioxide. It is a harmful air pollutant and is formed due to the combustion of fossil fuels. Understanding the criteria that differentiate different substances, such as color, is crucial for correct identification and classification.

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How do you convert an alcohol into an alkyl halide with an ester as an intermediate?

Answers

By following below  steps, you can successfully convert an alcohol into an alkyl halide using an ester as an intermediate.

To convert an alcohol into an alkyl halide with an ester as an intermediate, follow these steps:
Step 1: Convert the alcohol into an ester
- To do this, you can perform a Fischer esterification reaction. Add the alcohol to a carboxylic acid in the presence of a strong acid catalyst (e.g., concentrated sulfuric acid) and heat the mixture. This will cause the alcohol and carboxylic acid to react, forming an ester and water as a byproduct.
Step 2: Convert the ester into an alkyl halide
- To convert the ester into an alkyl halide, you can perform a nucleophilic substitution reaction. Add the ester to a solution containing a halide anion (e.g., sodium bromide or potassium iodide) and a strong acid (e.g., concentrated hydrochloric acid). The halide anion will act as a nucleophile and displace the ester's alkoxy group, leading to the formation of an alkyl halide and a carboxylate salt as a byproduct.

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suppose we were able to measure the amount of oxygen gas formed in units of moles/l, and the rate of formation of oxygen was found to be 0.0125 m/s. using the rate law for this reaction and the units associated with each variable, show what the derived units for the rate law constant would be. what would be the rate of decomposition of the hydrogen peroxide? explain your answer.

Answers

The derived units for the rate constant k depend on the order of the reaction with respect to hydrogen peroxide, n. For a first-order reaction (n=1), the units of k would be s^-1, for a second-order reaction (n=2), the units of k would be L/mol/s, and for a zero-order reaction (n=0), the units of k would be mol/L/s.

The decomposition of hydrogen peroxide can be represented by the following balanced chemical equation:

2 H2O2 (aq) → 2 H2O (l) + O2 (g)

The rate law for this reaction can be expressed as:

Rate = k [H2O2]^n

where k is the rate constant and n is the order of the reaction with respect to hydrogen peroxide.

If we measure the rate of formation of oxygen gas in units of moles per liter per second (mol/L/s), we can use the stoichiometry of the reaction to determine the rate of decomposition of hydrogen peroxide.

Since the reaction produces 1 mole of oxygen gas for every 2 moles of hydrogen peroxide decomposed, the rate of decomposition of hydrogen peroxide can be calculated as follows:

Rate of decomposition of H2O2 = (1/2) x rate of formation of O2

= (1/2) x 0.0125 mol/L/s

= 0.00625 mol/L/s

Therefore, the rate of decomposition of hydrogen peroxide is 0.00625 mol/L/s.

To determine the units of the rate constant k, we can rearrange the rate law equation to solve for k:

k = Rate / [H2O2]^n

Substituting the units of the variables, we get:

k = (mol/L/s) / (mol/L)^n

= mol^(1-n) / L^(n-1) s

Note that the rate law and rate constant depend on the specific conditions of the reaction, such as temperature, pressure, and catalysts.

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Question 9
The factor used to determine the bromine residual with the chlorine test kit (DPD):
a. multiply chlorine residual by 2.25
b. multiply chlorine residual by 4
c. divide chlorine residual by 4
d. divide chlorine residual by 2.5

Answers

The factor used to determine the bromine residual with the chlorine test kit (DPD) is to multiply the a. chlorine residual by 2.25.

To calculate the bromine residual in a water sample using the DPD chlorine test kit, you first need to measure the chlorine residual. Once you have obtained the chlorine residual, you can use the conversion factor of 2.25 to convert the chlorine residual to bromine residual. This is done because bromine has a different molecular weight and reactivity compared to chlorine, and the conversion factor helps to account for these differences.

By using this factor, you can accurately determine the bromine residual in your sample, which is essential for maintaining water quality and ensuring that the water is safe for use. The factor used to determine the bromine residual with the chlorine test kit (DPD) is to multiply the a. chlorine residual by 2.25.

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given the reaction 2hgo(s) → 2hg(l) o2(g), what weight of elemental mercury will be obtained by the decomposition of 94.5 g of hgo?

Answers

87.457 g of elemental mercury will be obtained from the decomposition of 94.5 g of HgO.

To calculate the weight of elemental mercury obtained from the decomposition of 94.5 g of HgO, you'll need to use stoichiometry and the balanced equation: 2HgO(s) → 2Hg(l) + O2(g).

First, determine the molar mass of HgO (mercuric oxide): Hg (200.59 g/mol) + O (16.00 g/mol) = 216.59 g/mol.

Next, convert the given mass of HgO (94.5 g) to moles:
94.5 g HgO × (1 mol HgO / 216.59 g HgO) = 0.436 moles HgO.

Now, use the stoichiometry from the balanced equation to convert moles of HgO to moles of Hg:
0.436 moles HgO × (2 moles Hg / 2 moles HgO) = 0.436 moles Hg.

Finally, convert moles of Hg to mass:
0.436 moles Hg × (200.59 g Hg / 1 mol Hg) = 87.457 g Hg.

Thus, 87.457 g of elemental mercury will be obtained from the decomposition of 94.5 g of HgO.

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To find the weight of elemental mercury obtained by the decomposition of 94.5 g of HgO, you can follow these steps:

Step 1: Determine the balanced chemical equation.
The balanced equation is already given: 2HgO(s) → 2Hg(l) + O2(g).

Step 2: Calculate the molar mass of HgO and Hg.
Molar mass of HgO = (1 x Hg) + (1 x O) = (1 x 200.59) + (1 x 16.00) = 216.59 g/mol
Molar mass of Hg = 200.59 g/mol

Step 3: Determine the moles of HgO in the given mass.
Moles of HgO = mass of HgO / molar mass of HgO = 94.5 g / 216.59 g/mol = 0.436 moles

Step 4: Use the stoichiometry of the balanced equation to determine the moles of Hg produced.
From the equation, 2 moles of HgO produce 2 moles of Hg, so the mole ratio is 1:1. Therefore, 0.436 moles of HgO will produce 0.436 moles of Hg.

Step 5: Convert moles of Hg to mass.
Mass of Hg = moles of Hg x molar mass of Hg = 0.436 moles x 200.59 g/mol = 87.457 g

So, the weight of elemental mercury obtained by the decomposition of 94.5 g of HgO is approximately 87.457 g.

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Question 28
Diatomaceous earth filters:
a. Should be supplemented by a chlorination system
b. Should be integrated into a rapid sand filtration system
c. Can be used for a public water treatment system
d. Cane be used in a public sewer treatment system

Answers

Diatomaceous earth filters c. Can be used for a public water treatment system.

Diatomaceous earth filters are effective in removing particles and impurities from water. While they can be used as part of a public water treatment system, they may be combined with other methods, such as a chlorination system for disinfection or a sand filtration system for further filtration. However, diatomaceous earth filters are not typically used in public sewer treatment systems.

Diatomaceous earth filters are not typically used in public sewer treatment systems as they are designed to remove particles from water, and not sewage. In sewer treatment systems, other types of filtration and treatment methods are typically used, such as activated sludge processes, sedimentation tanks, and anaerobic digestion systems.

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Which one of the following is an example of a balanced chemical reaction?A) HCl + KMnO4 ® Cl2 + MnO2 + H2O + KClB) HCl + KMnO4 ® Cl2 + MnO2 + 2H2O + KClC) 2HCl + 2KMnO4 ® Cl2 + MnO2 + 2H2O + 2KClD) 6HCl + 2KMnO4 ® 2Cl2 + 2MnO2 + 4H2O + 2KClE) 8HCl + 2KMnO4 ® 3Cl2 + 2MnO2 + 4H2O + 2KCl

Answers

The correct answer is C) 2HCl + 2KMnO4 ® Cl2 + MnO2 + 2H2O + 2KCl. This is because the equation has the same number of atoms of each element on both the reactant and product side, making it a balanced chemical reaction.

The correct option for a balanced chemical reaction is:

D) 6HCl + 2KMnO4 ® 2Cl2 + 2MnO2 + 4H2O + 2KCl
1. Write down the unbalanced reaction: HCl + KMnO4 → Cl2 + MnO2 + H2O + KCl
2. Balance the elements one by one, starting with those that appear in fewer compounds. In this case, start with Mn:
  HCl + KMnO4 → Cl2 + 2MnO2 + H2O + KCl
3. Balance the potassium (K):
  HCl + 2KMnO4 → Cl2 + 2MnO2 + H2O + 2KCl
4. Balance the chlorine (Cl):
  6HCl + 2KMnO4 → 3Cl2 + 2MnO2 + H2O + 2KCl
5. Finally, balance the hydrogen (H) and oxygen (O):
  6HCl + 2KMnO4 → 2Cl2 + 2MnO2 + 4H2O + 2KCl

Now the reactant for the chemical reaction is balanced.

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Due to the rules for electrolyte solutions, when sodium leaves a cell this enters

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Due to the rules for electrolyte solutions, when sodium leaves a cell it enters the extracellular fluid and creates a concentration gradient that drives the movement of other ions, such as potassium, into the cell to maintain the balance of electrolytes.

The process that occurs when sodium leaves a cell in an electrolyte solution. When sodium (Na+) leaves a cell in an electrolyte solution, potassium (K+) ions enter the cell. This process is known as the sodium-potassium pump, which is an essential mechanism for maintaining cell membrane potential and proper electrolyte balance. The sodium-potassium pump works by actively transporting 3 sodium ions out of the cell while bringing 2 potassium ions into the cell, ensuring a proper balance of ions inside and outside the cell. This movement of ions is crucial for proper cellular function and is regulated by specialized channels and transporters within the cell membrane.

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complete question:

Due to the rules for electrolyte solutions, when sodium leaves a cell this enters. what will happen?

#27. When two amino acids are joined via a peptide bond, what is the mass of the byproduct of the reaction?

Answers

When two amino acids join via a peptide bond, the mass of the byproduct, which is a water molecule, is approximately 18 atomic mass units.

When two amino acids are joined via a peptide bond, a byproduct is formed as a result of the reaction. This process, called dehydration synthesis, involves the removal of a water molecule (H2O) as the amino acids form the peptide bond.

To create a peptide bond, the carboxyl group (COOH) of one amino acid reacts with the amino group (NH2) of another amino acid. During this reaction, the carboxyl group loses a hydroxyl group (OH) while the amino group loses a hydrogen atom (H). The two amino acids are then linked by the peptide bond, and the released hydroxyl group and hydrogen atom combine to form a water molecule.

The mass of the byproduct, which is a water molecule, can be calculated by adding the atomic masses of its constituent atoms.

A water molecule consists of one oxygen atom and two hydrogen atoms. The atomic mass of oxygen is approximately 16 atomic mass units (amu), and the atomic mass of hydrogen is approximately 1 amu. Therefore, the total mass of a water molecule is:

1 oxygen atom × 16 amu/oxygen atom + 2 hydrogen atoms × 1 amu/hydrogen atom = 16 amu + 2 amu = 18 amu.

In summary, when two amino acids join via a peptide bond, the mass of the byproduct, which is a water molecule, is approximately 18 atomic mass units.

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how much heat in joules is needed to heat up 57.1 grams of ice at 0 celsius to 66 oc? use the formula sheet for any information you might need g

Answers

The amount of heat in joules needed to heat up 57.1 grams of ice at 0 Celsius to 66 Celsius is 34857 J.

To calculate the amount of heat in joules needed to heat up 57.1 grams of ice at 0 Celsius to 66 Celsius, we can use the following formula:

q = m x c x ΔT

Where:
q = amount of heat (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)

First, we need to calculate the amount of heat needed to melt the ice:

q1 = m x ΔHf

Where:
ΔHf = heat of fusion of ice (334 J/g)

q1 = 57.1 g x 334 J/g = 19039.4 J

Next, we need to calculate the amount of heat needed to raise the temperature of the water from 0°C to 66°C:

q2 = m x c x ΔT

Where:
c = specific heat capacity of water (4.184 J/g°C)

ΔT = 66°C - 0°C = 66°C

q2 = 57.1 g x 4.184 J/g°C x 66°C = 15817.6 J

Finally, we add the two amounts of heat together to get the total amount of heat needed:

q = q1 + q2
q = 19039.4 J + 15817.6 J
q = 34857 J

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When the [HA] increases pH goes down along with percent ionization

Answers

When the concentration of the acidic form of a compound ([HA]) increases, the pH of the solution decreases, and the percent ionization of the compound also decreases.

The pH is a measure of the acidity or alkalinity of a solution and is defined as the negative logarithm (base 10) of the hydrogen ion concentration ([H+]). As [HA] increases, the concentration of hydrogen ions in the solution also increases, resulting in a decrease in pH.

The percent ionization of a compound is the proportion of the compound that exists in the ionized form compared to the total concentration of the compound. When [HA] increases, more of the compound exists in the non-ionized form, leading to a decrease in the percent ionization.

Therefore, as the concentration of the acidic form ([HA]) increases, the pH decreases due to the increased concentration of hydrogen ions, and the percent ionization decreases because more of the compound remains in the non-ionized form.

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Question 19
Homes containing garbage disposals should have a septic tank capacity increased by what % in order to accommodate the increased organic loading?
a. 10%
b. 100%
c. 50%
d. does not matter

Answers

The correct answer is c. 50%. Homes with Garbage disposals generate more organic waste, which can overload the septic system. Increasing the septic tank capacity by 50% can help accommodate this increased loading.

This situation was what drove Hand in Hand India (HiH India), a pan-Indian non-profit organisation that promotes sustainable development, to engage with Karaikal’s locals in changing mindsets, driving behavioural change in their waste management approach.

“Smaller towns like Karaikal lack the adequate infrastructure to process its solid waste. Along with a lack of awareness among residents, it created a huge environmental problem”, reports Amuda Shekharan from HIHI.

“As every household is generating rubbish, the success of any waste management program would depend on the behavioural and mindset change in the community.”

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Chlorine gas reacts with phosphorus to produce phosphorus pentachloride. How manygrams of PCl5 are produced from 3.5 g of Cl2 and excess P?5Cl2(g) + 2P(s) = 2PCl5(s)A) 1.4 g B) 4.1 g C) 8.2 g D) 0.020 g E) 730 g

Answers

4.1 g grams of PCl5 are produced from 3.5 g of Chlorine gas and excess P.

To solve this problem, we need to use stoichiometry to determine the amount of PCl5 produced from the given amount of Cl2.
First, we need to balance the chemical equation:
5Cl2(g) + 2P(s) → 2PCl5(s)
This tells us that 5 moles of Cl2 react with 2 moles of P to produce 2 moles of PCl5.
Next, we need to convert the given mass of Cl2 to moles:
3.5 g Cl2 ÷ 70.9 g/mol Chlorine gas= 0.0494 mol Cl2
Now we can use the mole ratios from the balanced equation to find the moles of PCl5 produced:
0.0494 mol Cl2 × (2 mol PCl5 ÷ 5 mol Cl2) = 0.0198 mol PCl5
Finally, we can convert the moles of PCl5 to grams:
0.0198 mol PCl5 × 208.2 g/mol PCl5 = 4.12 g PCl5
Therefore, the answer is B) 4.1 g.

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addition of a sample of compound A to compound X does not lower the melting point of X, X must be identical to A?

Answers

The addition of a sample of compound A to compound X not lowering the melting point of X does not necessarily mean that X is identical to A.

What are the factors affecting melting point?


The answer is yes, if the addition of compound A to compound X does not lower the melting point of X, it suggests that both compounds are identical. This observation is based on the principle that when two different compounds are mixed, their melting point usually decreases due to impurities or differing molecular interactions. However, if the melting points remain the same, it indicates that the compounds are likely the same. It could simply mean that the two compounds do not have a significant effect on each other's melting points. Other factors, such as the amount and nature of impurities in each compound, could also influence their melting points. Therefore, additional testing and analysis would be necessary to determine if X is indeed identical to A.

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In the reaction N2 + 3H2 → 2NH3, the rate of formation of ammonia at a given moment is
0.060 mol/s. What is the rate of reaction of hydrogen gas at the same moment?
A) -0.060 mol/s
B) 0.090 mol/s
C) -0.090 mol/s
D) 0.040 mol/s
E) -0.040 mol/s

Answers

Option A) -0.060 mol/s is the rate of reaction of hydrogen gas at the same moment. To be able to predict how much reactant will be used in a reaction, how much product you will get.

The rate of formation of ammonia (NH₃) in the reaction N2 + 3H₂ ⇔ 2NH₃ is given as 0.060 mol/s. To find the rate of reaction of hydrogen gas (H₂) at the same moment, we need to consider the stoichiometry of the reaction.
For every 2 moles of NH₃ produced, 3 moles of H₂ are consumed. So the rate of reaction of H₂ can be calculated using the ratio:

Stoichiometry (reaction stoichiometry) is widely used to balance chemical equations. For instance, in an exothermic reaction, the diatomic gases hydrogen and oxygen can combine to form the liquid water.

Stoichiometry is still useful in many areas of life, including determining how much fertiliser to use in farming, determining how quickly you must travel to get someplace in a specific length of time, and even performing basic unit conversions between Celsius and Fahrenheit may be left over, you must comprehend the fundamental chemistry concept of stoichiometry.
Rate of H₂ / Rate of NH₃ = -3 / 2
Now, plug in the given rate of NH3 formation:
Rate of H₂ / 0.060 mol/s = -3 / 2
Rate of H₂ = (0.060 mol/s) × (-3 / 2)
Rate of H₂ = -0.090 mol/s
So, the correct answer is C) -0.090 mol/s.

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What is the coefficient for O2 when the following combustion reaction of a hydrocarbonis balanced?___ C7H14 + ___ O2 = ___ CO2 + ___ H2OA) 42 B) 21 C) 11 D) 10 E) none of these

Answers

The coefficient for O2 is therefore 21, which is option B.

To balance the combustion reaction of a hydrocarbon, we need to ensure that the number of atoms of each element is equal on both sides of the equation.

For this particular equation, we have 7 carbon atoms and 14 hydrogen atoms on the left-hand side, and we need to balance this with 7 carbon dioxide molecules and 7 water molecules on the right-hand side.

To balance the oxygen atoms, we need to add an appropriate coefficient to the oxygen molecule. We can start by balancing the carbon atoms first. We need 7 carbon dioxide molecules to balance the 7 carbon atoms on the left-hand side, so we write:

C7H14 + ___ O2 → 7 CO2 + ___ H2O

Next, we balance the hydrogen atoms. We need 14 water molecules to balance the 14 hydrogen atoms on the left-hand side, so we write:

C7H14 + ___ O2 → 7 CO2 + 14 H2O

Now, we can balance the oxygen atoms. On the left-hand side, we have ___ O2 molecules, and on the right-hand side, we have 7 x 2 + 14 = 28 oxygen atoms. Therefore, we need 14 O2 molecules on the left-hand side to balance the equation:

C7H14 + 21 O2 → 7 CO2 + 14 H2O

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Question 103
To prepare a solution of 100 mg per liter available chlorine, __ of 5.25 percent bleach with one gallon of water should be used.
a. 0.5 oz
b. 1.0 oz
c. 0.33 oz
d. 0.25 oz

Answers

To prepare a solution of 100 mg per liter of available chlorine, 0.33 oz of 5.25 percent bleach with one gallon of water should be used.

The concentration of available chlorine in household bleach is typically expressed as a percentage, which represents the amount of sodium hypochlorite in the bleach. For example, 5.25 percent bleach contains 52,500 mg of sodium hypochlorite per liter of solution. To calculate the amount of bleach needed to prepare a solution with a desired concentration of available chlorine, the following formula can be used: (amount of bleach in oz) = (desired concentration of available chlorine in mg/L) x (volume of water in liters) x (100) / (% of available chlorine in the bleach) In this case, the desired concentration of available chlorine is 100 mg/L, the volume of water is one gallon (which is approximately 3.785 L), and the percentage of available chlorine in the bleach is 5.25 percent. Plugging these values into the formula yields: (amount of bleach in oz) = (100 mg/L) x (3.785 L) x (100) / (5.25%) = 0.33 oz

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If a buffer solution is 0.110 M in a weak acid ( Ka=8.1×10−5) and 0.510 M in its conjugate base, what is the pH? Enough of a monoprotic weak acid is dissolved in water to produce a 0.0154 M solution. The pH of the resulting solution is 2.47 . Calculate the Ka for the acid.

Answers

A monoprotic weak acid is dissolved in water to produce a 0.0154 M solution. The pH of the resulting solution is 2.47 .  2.6 x 10⁻⁴ is the Ka for the acid.

For the first question, we can use the Henderson-Hasselbalch equation:

[tex]pH=pKa+log\frac{[base]}{[acid]}[/tex]
Where pKa is the dissociation constant of the weak acid and [base] and [acid] are the concentrations of the conjugate base and weak acid, respectively.
Plugging in the values given, we get:
pH = 4.09 + log(0.510/0.110)
pH = 4.74
Therefore, the pH of the buffer solution is 4.74.
For the second question, we can use the equation for the dissociation constant of a weak acid:
[tex]Ka=\frac{[H+][A-]}{[HA]}[/tex]
Where [H+], [A-], and [HA] are the concentrations of hydronium ions, conjugate base, and weak acid, respectively.
We are given the pH, which can be used to find [H+]:

[tex]pH=-log[H+][/tex]
2.47 = -log[H+]
[H+] = 2.0 x 10⁻³ M
We are also given the concentration of the weak acid, [HA], which is 0.0154 M.
Using the fact that the weak acid is monoprotic and therefore that [H+] = [A-], we can find [A-]:
[A-] = 2.0 x 10⁻³ M
Now we can plug in these values to find Ka:
Ka = (2.0 x 10⁻³)² / 0.0154
Ka = 2.6 x 10⁻⁴
Therefore, the Ka for the acid is 2.6 x 10⁻⁴.

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Ammonia reacts with hydrochloric acid to produce ammonium chloride. Identify thebalanced reaction that describes this process.A) NH4+ + HCl ® NH4Cl + H D) NH4+ + 2HCl ® NH4Cl2B) NH3 + HCl ® NH4Cl E) NH3 + 2HCl ® NH4Cl2C) NH3 + 2HCl ® NH4Cl + HAns: B Category: Medium Section

Answers

Answer:

Explanation:

 the correct answer is B :

NH3 + HCL ---> NH4Cl

The number of atoms on the reactant side should be equal to the number of atoms on the product side.

at a certain temperature the vapor pressure of pure thiophene is measured to be . suppose a solution is prepared by mixing of thiophene and of acetyl bromide . calculate the partial pressure of thiophene vapor above this solution. round your answer to significant digits.

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The partial pressure of thiophene vapor  this solution is 0.080 atm. According to Raoult's law, a solvent's partial vapour pressure in a solution (or mixture) is equal to or the same as the pure solvent's vapour pressure times the mole fraction present in the solution.

To answer this question, we need to use Raoult's Law, which states that the partial pressure of a component in a solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the solution.
First, we need to calculate the mole fraction of thiophene in the solution. We are given that the solution is prepared by mixing 0.8 moles of thiophene and 0.2 moles of acetyl bromide. The total moles of the solution is therefore:
0.8 + 0.2 = 1.0 moles
The mole fraction of thiophene is:
0.8/1.0 = 0.8
Now we can use Raoult's Law to calculate the partial pressure of thiophene vapor above the solution. We are given that the vapor pressure of pure thiophene is 0.10 atm at the temperature in question. Therefore, the partial pressure of thiophene vapor above the solution is:
0.10 atm x 0.8 = 0.080 atm
Rounding to significant digits, the partial pressure of thiophene vapor above the solution is 0.080 atm.

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Sometimes two or three pairs of electrons may be shared to give __________ covalent bonds.
(double/triple, coordinate covalent bond, energy, bond dissociation energy, resonance structure)

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Sometimes two or three pairs of electrons may be shared to give double or triple covalent bonds.

A double covalent bond occurs when two pairs of electrons are shared between two atoms, while a triple covalent bond is formed when three pairs of electrons are shared. These bonds are stronger than single covalent bonds and result in shorter bond lengths. In some cases, a coordinate covalent bond can form when one atom donates both electrons for a shared pair, often occurring between a Lewis base and a Lewis acid. This type of bond is still considered a covalent bond, as the electrons are shared between the atoms.

Bond dissociation energy refers to the energy required to break a covalent bond, with double and triple covalent bonds generally having higher bond dissociation energies than single bonds, this is because more energy is needed to break the stronger, shorter bonds. Resonance structures are used to represent molecules where the electron distribution cannot be accurately depicted by a single Lewis structure. In such cases, multiple structures are used to show the various possible arrangements of electrons, indicating that the actual electron distribution is an average of these structures. Sometimes two or three pairs of electrons may be shared to give double or triple covalent bonds.

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What is the term for the minimum amount of energy to remove an electron from a neutral atom in the gaseous state?

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The term for the minimum amount of energy required to remove an electron from a neutral atom in the gaseous state is called ionization energy.

Ionization energy is an essential concept in chemistry and is often used to compare and contrast elements based on their reactivity. In general, ionization energy increases from left to right across a period and decreases from top to bottom within a group in the periodic table. This trend occurs because the nuclear charge and electron shielding play a significant role in determining the ease of removing an electron from an atom. Elements with high ionization energies, such as noble gases, are less reactive, while elements with low ionization energies, like alkali metals, are more reactive.

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Modeling Energy Changes
Student Guide

Answer in a copy and paste format, or using photos of what was said please.
Anyone who can do this will receive brainliest ofc!

Answers

In terms of the energy change in the reaction, the negative value indicates that the reaction is exothermic as the reaction releases 1560.74 kJ of energy for every mole of C2H6 that reacts with 7/2 moles of O2.

What is a model of chemical energy changes?

The model of chemical energy changes is given below:

Balanced chemical equation:

C2H6 + 7/2 O2 → 2CO2 + 3H2O

Now, to calculate the energy change in the reaction, we will use a table of enthalpy values. The enthalpy change for each of the reactants and products is given in the table below:

Reactants:

C2H6: -84.68 kJ/mol

O2: 0 kJ/mol

Products:

CO2: -393.51 kJ/mol

H2O: -285.83 kJ/mol

The energy change in the reaction can be calculated using the formula:

ΔH = ∑(products) - ∑(reactants)

ΔH = [2(-393.51 kJ/mol) + 3(-285.83 kJ/mol)] - [-84.68 kJ/mol + 7/2(0 kJ/mol)]

ΔH = -1560.74 kJ/mol

Therefore, the energy change in the reaction is -1560.74 kJ/mol.

To create a model of the energy change in the reaction, we can use an energy level diagram. In this diagram, the energy of the reactants is shown on the left, the energy of the products is shown on the right, and the activation energy is shown as a barrier between them.

The energy level diagram for this reaction is shown below:

Reactants (C2H6 + 7/2 O2)

                |

                |

       Activation energy

                |

                |

Products (2CO2 + 3H2O)

As shown in the diagram, the reactants have a higher energy level than the products, and the activation energy is required to get the reaction started.

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if 30 ml of a stock solution of bacl2 can be mixed with water to prepare 150 ml of 0.3 mgml solution, what is the concentration of bacl2 in the stock solution in mgml? do not include units in your answer.

Answers

Answer:

310

Explanation:

If the rate law of a chemical reaction is k[NH4+]2[NO2-], what is the order of the reaction?

Answers

The order of a chemical reaction is determined by the rate law equation. We have two molecules of NH4+ and one molecule of NO2- involved in the rate-determining step. When we add the exponents of these molecules, we get 2 + 1 = 3.

Therefore, the overall order of the reaction would be second order.

The rate law is k[NH4+]2[NO2-]. The exponents (2 and 1) represent the order of the reactants NH4+ and NO2- respectively.

We must understand what the term "order" means in chemistry. The order of a reaction represents the number of molecules or atoms of a reactant that are involved in the rate-determining step of the reaction. The rate-determining step is the slowest step of the reaction that controls the overall reaction rate.

Therefore, the overall order of the reaction is third order. However, the rate law only shows the concentration dependence of the reaction, which means that we only consider the exponents of the reactants in the rate law equation. The order of the reaction is second order.

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The dry and wet bulb temperatures of atmospheric air at 98 kPa are 28 0C and 15 0C, respectively. Determine (1) The specific humidity kg H2O/kg dry air (2) The relative humidity % (3) The enthalpy of the air kJ/kg dry air

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The specific humidity of the air is 0.0085 kg H2O/kg dry air, the relative humidity is 34%, and the enthalpy of the air is 80 kJ/kg dry air. respectively.

To determine the specific humidity, relative humidity, and enthalpy of the air, we need to use the psychrometric chart. The psychrometric chart is a graphical representation of the thermodynamic properties of moist air and is used to determine various properties of moist air.

To determine the specific humidity of the air, we need to find the point on the psychrometric chart corresponding to the dry bulb temperature of 28°C and the wet bulb temperature of 15°C. From the chart, we find that the specific humidity of the air is approximately 0.0085 kg H2O/kg dry air.

To determine the relative humidity of the air, we need to find the ratio of the actual vapor pressure to the saturation vapor pressure at the dry bulb temperature of 28°C. From the psychrometric chart, we find that the saturation vapor pressure at 28°C is approximately 3.5 kPa, and the actual vapor pressure is approximately 1.2 kPa. Therefore, the relative humidity of the air is approximately 34%.

To determine the enthalpy of the air, we need to find the point on the psychrometric chart corresponding to the dry bulb temperature of 28°C and the specific humidity of 0.0085 kg H2O/kg dry air. From the chart, we find that the enthalpy of the air is approximately 80 kJ/kg dry air.

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13. Is a flammable gas produced by landfillsa. Carbon dioxideb. Carbon monoxidec. Methaned. Radone. Sulfur dioxide

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(c) Methane is a flammable gas produced by landfills.

Landfills are sites where waste materials are disposed of, and as these materials decompose, they generate various types of gases. Among these gases, methane is the most significant due to its flammability and contribution to climate change.

Methane is created through the anaerobic decomposition of organic materials, such as food waste, paper, and yard waste, by microorganisms in the absence of oxygen. This gas is a potent greenhouse gas, approximately 25 times more effective at trapping heat in the Earth's atmosphere than carbon dioxide.

As a result, methane emissions from landfills contribute to global warming and can pose risks for explosions or fires if not properly managed. To mitigate these risks, landfill gas recovery systems can be installed to capture methane and either convert it into electricity or burn it off in a controlled manner, reducing its environmental impact.

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