The distance the block will move to have a kinetic energy of 57 J is 8.14 meters.
What is work?The work is defined as the amount of energy. The work in physics is the product of the force and the displacement.
Given that a 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. The total kinetic energy possessed by the block is 57 J.
The distance will be calculated as:-
W = F x D
W = 7 x 2
W = 14 J
The distance is,
W₁ / W₁ = D₂ / D₁
14 / 57 = 2 / D₂
D₂ = ( 57 x 2 ) / 14
D₂ = 8.14 meters
Therefore, the distance the block will move to have a kinetic energy of 57 J is 8.14 meters.
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a)write an equation for the magnitude of this systems acceleration. use the variables from the problem statement together with g for acceleration from gravity in order to write you equation.b) calculate the magnitude of the systems acceleration in m/s^2
The equation for the magnitude of the system's acceleration is a = g + (2M/m), where g is the acceleration due to gravity and M and m are the masses of the two objects.
What is acceleration ?Acceleration is the rate of change of velocity in an object over time. It is the rate of change of the speed of an object, and is defined as the change in velocity divided by the change in time. In other words, it is the rate at which an object's speed changes. Acceleration can be caused by a change in the speed of an object, or by a change in its direction. It is usually measured in meters per second squared (m/s2). Acceleration can be either positive or negative, depending on the direction of the change in velocity.
a = g + (2M/m)
a = 9.81 m/s^2 + (2(8 kg)/(3 kg)) = 13.87 m/s^2
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A ball falls from a shelf. Assuming there is no friction, why is the conservation of mechanical energy independent of mass?.
The conservation of mechanical energy is independent of mass because the energy is proportional to both mass and velocity, and any changes in one factor are balanced out by changes in the other factor.
The conservation of mechanical energy is a fundamental principle in physics that states that the total amount of mechanical energy in a closed system remains constant over time, provided that no external forces act on the system.
When a ball falls from a shelf, its potential energy (due to its position above the ground) is converted into kinetic energy (due to its motion as it falls). The total amount of mechanical energy in the system (the ball and the Earth) is conserved, even though the mass of the ball is different from the mass of Earth.
This is because the potential energy of the ball is proportional to its mass and height above the ground, while the kinetic energy of the ball is proportional to its mass and velocity. As the ball falls, its potential energy decreases, while its kinetic energy increases by an equal amount, such that the total mechanical energy of the system (ball and Earth) remains constant.
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Answer: Mass is eliminated when equating gravitational potential energy with kinetic energy.
Explanation:
how many pattern block hexagons would 2 trapezoids create
To make two hexagons out of pattern blocks, you need 12 trapezoids.
Explain about the term hexagons?A closed, two-dimensional polygon containing six sides is what is known as a hexagon. Six vertices and six angles make up a hexagon.
You need to utilize a total of 12 trapezoids to make two hexagons using pattern blocks. You will also need 2 hexagons to employ all twelve trapezoids because each hexagon has six trapezoids in it. Trapezoids can be arranged in a pattern with two triangles, 2 parallelograms, 2 rhombuses, and 2 trapezoids to create the two hexagons. These 12 trapezoids can be used to form two full hexagons.Thus,
You need 12 trapezoids to build two hexagons out of pattern blocks.Six trapezoids form each hexagon.Since you require two hexagons, a total of 12 trapezoids are required.To know more about the hexagons, here
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A ball with mass m is suspended from a roof with a rope of length L. The ball spins in a circle making a constant angle θ with the vertical as shown. Write an expression for the speed v of the ball in terms of m, L, θ, and g.
The speed v of the ball can be determined using the centripetal force equation Fc = mv^2/r.
The centripetal force is provided by the tension in the rope and the weight of the ball. We can write the equation as:
Tcosθ - mg = mv^2/L
From this equation, we can solve for the speed v: v = sqrt((Tcosθ - mg)L/m).
We can also express the tension T in terms of the angle θ and the length L using the equation Tsinθ = mv^2/L.
Substituting this into the previous equation gives us: v = sqrt((Lsinθcosθ - mgL)/m)
This is the expression for the speed v of the ball in terms of m, L, θ, and g.
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A fishing bont weighing 196,200 N is towed by a much larger ship. The tow cable in linearly elastic and elongates 0.03 m for each 500 N of tension in it. The wave and viscous drage on the fishing boat can be used to be linearly proportional to its velocity, and equal to 10,000 N/m. At time to the large tow ship starts moving with constant velocity, V = 3 m/s. There is no initial slack in the cable ) Propee a model of this system consisting of ideal lumped elements. (Mn, springs, dampers) Do this carefully; the rest of the problem depends on its accuracy. b) Find an expression for the fishing boat velocity was a function of time. Plot the velocity of both boat on the same graph c) What is the maximum force in the cable and at what time does it occur? d) What is the elongation of the tow cable due to the drag of the fishing boat at t=0 e) It is desired to change the stiffness of the cable to that the fishing boat will approach the velocity of the tow ship as fast as posible without cecillating What should the cable stiffness be in this case?
The spring, damper, and mass make up this system's model. The linear elasticity of the tow cable is represented by the spring.
The fishing boat's viscous drag and wave are represented by the damper. The fishing boat itself is represented by the mass.
b) The following expression can be used to represent the fishing boat's velocity over time:
V(t) = V₀ + [Ft - (10,000/m) ×Vt]/M,
where V₀ is the fishing boat's initial velocity, Ft is the cable force, and M is the boat's mass.
c) When the fishing boat's velocity equals the tow ship's velocity, the cable experiences its maximum force.
This occurs at t=0, and the force in the cable is 196,200 N.
d) The fishing boat's drag causes the tow cable to elongate by 0.03 m at t=0.
e) The stiffness of the cable should be 196,200 N/0.03 m to ensure that the fishing boat reaches the tow ship's velocity as quickly as possible without oscillating.
How does velocity work?The rate of change in an object's position in a particular direction is measured by its velocity. Because it is a vector quantity, it has a magnitude (also known as speed) and a direction. Using the derivative of the object's position over time, velocity can be determined. The calculation of a particle's or object's motion over time frequently makes use of velocity.
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How can motion be measured?
Motion can be measured in several ways, depending on the context and the specific parameters that need to be quantified.
What is Motion?
Motion is a fundamental concept in physics and is described by the laws of motion formulated by Sir Isaac Newton. These laws state that an object at rest tends to remain at rest and an object in motion tends to remain in motion with the same velocity . The study of motion is important in many fields, including physics, engineering, and astronomy.
Motion can be measured in several ways, depending on the context and the specific parameters that need to be quantified. Some common methods of measuring motion include:
Displacement: Displacement is the change in position of an object over a certain period of time. It can be measured using a ruler, tape measure, or other distance-measuring tools.
Speed: Speed is the rate at which an object moves, and it can be measured using a stopwatch or other timing device to determine the time it takes for an object to travel a certain distance.
Velocity: Velocity is similar to speed, but it takes into account both the speed and direction of motion. It can be measured using a velocity sensor or other motion-tracking tools.
Acceleration: Acceleration is the rate at which an object's speed or velocity changes over time, and it can be measured using an accelerometer or other motion-tracking tools.
Gyroscopic sensors: Gyroscopic sensors can be used to measure the rotational motion of an object, such as the rotation of a wheel or the movement of a drone.
Video analysis: Video analysis software can be used to track the movement of an object or a person, using visual markers or other reference points to determine motion.
Inertial measurement units (IMUs): IMUs are electronic sensors that can measure motion, acceleration, and rotation in three-dimensional space, and are commonly used in robotics, virtual reality, and other applications.
These are just a few examples of methods used to measure motion, and there are many other tools and techniques that can be used depending on the specific context and requirements.
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The Origin of Magma Draw arrows on simplified Pressure/Temperature (P/T) diagrams according to the scenarios below. Be sure to start your arrow at the red dot and draw it in the direction the dot would move in each scenario. 1. An area of solid rock in the subsurface is heated quickly in place and starts to melt. Indicate the direction the dot would move in P/T space. 2. An area of solid rock undergoes increases in pressure and temperature as it is buried in the subsurface, following parallel to the liquid/solid line for this exercise. Indicate the direction the dot would move in P/T space. Temperature (°C) Temperature (°C) 1. Low High Low 2. High Pinbr 3. An area of solid rock deep in the subsurface quickly rises to a lower depth/pressure and melts. Indicate the direction the dot would move in P/T space. At which type of plate boundary does this type of melting occur? 4. Magma erupts at the surface and then rapidly cools to a solid. Indicate the direction the dot would move in P/T space. Temperature (°C) Temperature (°C) Low 3. High Low 4. High 5. If water is added to the system, which way does the liquid/solid line move? Draw in the new solidus line. At which type of plate boundary does this type of melting occur? 6. Dotted line is the liquid/solid line of a wet system. If water is added to a portion of dry rock (dot), will it melt in place? Label the dot 'Melt' or 'No Melt' to indicate your answer. Temperature (C) Temperature (°C) 5. Low High Low High 6. Pressure (bars x 1,000) Depth (km) Pressure (bars x 1,000) Depth (km) Examine the pressure-temperature (P-T) diagram below and locate point X. This point represents a piece of peridotite (the type of rock that exists in the mantle) buried 80 km underground. Ocean 0 0 500 TEMPERATURE IN DEGREES CELSIUS (°C) 1000 1500 2000 2500 Crust 10,000 Lithosphere 50 100% LIQUID MAGMA 20,000 Lithospheric Mantle 100- 30,000 Decompression 40,000 DEPTH IN KILOMETERS (km) Continental geothermal gradient Oceanic geothermal gradient 150- Peridotite solidus PRESSURE IN ATMOSPHERES (atm) 50,000 60.000 Asthenospheric Mantle 200- 100% SOLID PERIDOTITE ROCK PARTIAL MELTING OF PERIDOTITE ! (Solid + Liquid) 1 70,000 250 80,000 Heating Melting 1 1 90,000 300 A. Earth's Mechanical Layers B. Pressure-Temperature Diagram 0 25% 50% 75% 100% 1. According to the continental geothermal gradient, rocks buried 80 km beneath a continent would normally be heated to what temperature? 2. According to the oceanic geothermal gradient, rocks buried 80 km beneath an ocean basin would normally be heated to what temperature? 3. Is the mantle rock at point X a mass of solid, a mixture of solid and liquid, or a mass of liquid? How do you know? 4. What would happen to the mass of mantle at point X if it were heated to 1750 °C? 5. What would happen to the mass of mantle at point X if it were heated to 2250 °C? 6. At its current depth, the mantle at point X is under about 25,000 atm of pressure. a. At what depth and pressure will this rock begin to melt if it is uplifted closer to Earth's surface and its temperature remains the same? Depth: Pressure: b. What is the name applied to this kind of melting? At which plate boundary setting does the uplifting of mantle rock cause melting in this way? 7. Based on your answers above, what are two environmental changes that can cause the mantle at point X to begin partial melting?
Two environmental changes that can cause the mantle at point X to begin partial melting are heat and pressure reduction.
What is the pressure reduction?Pressure reduction is a process that occurs when the pressure of an object or material is decreased. This can be done in a variety of ways, such as by using a pressure-reducing valve, increasing the area of a pipe, or using a compressor to reduce the pressure of a gas or liquid.
1. Low High Low
2. High Pinbr
3. Low High Low
4. High Low
5. The liquid/solid line would move to the right, indicating an increase in solidus temperature. This type of melting occurs at subduction zones.
6. No Melt
1. According to the continental geothermal gradient, rocks buried 80 km beneath a continent would normally be heated to about 1400 °C.
2. According to the oceanic geothermal gradient, rocks buried 80 km beneath an ocean basin would normally be heated to about 1000 °C.
3. The mantle rock at point X is a mass of solid, as indicated by the fact that it is below the solidus line.
4. If heated to 1750 °C, the mass of mantle at point X would remain a solid.
5. If heated to 2250 °C, the mass of mantle at point X would begin to partially melt.
6. a. At its current temperature, the mantle at point X will begin to melt at a depth of about 50 km and a pressure of about 10,000 atm.
b. The name applied to this kind of melting is decompression
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What chemical did Dr Julian first synthesize that changed the world and why was this considered such an important discovery?
Answer:
Julian (1899-1975) first synthesized the drug physostigmine, previously only available from its natural source, the Calabar bean. His pioneering research led to the process that made physostigmine readily available for the treatment of glaucoma.
Answer:
Julian (1899-1975) first synthesized the drug physostigmine, previously only available from its natural source, the Calabar bean. His pioneering research led to the process that made physostigmine readily available for the treatment of glaucoma.
Compare the normal force that the seat exerts on you to the force that earth exerts on you when you are passing the bottom of the loop.
A) At the bottom, normal force is minimum so, Nbottom = mvb²/R - mg
B) At the top, normal force is maximum so, Ntop = mvt²/R + mg
A) When you are passing the bottom of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the bottom of the loop, the net force on you is equal to the force of gravity, and it acts towards the centre of the loop, providing the centripetal force required to keep you moving in a circular path.
The normal force, N, is the force exerted by the seat on you, perpendicular to the surface of the seat. Gravity's energy, mg, operates vertically downward. Therefore, we write,
Nbottom + mg = Fnet = mvb²/R
where,
R is radius of the loop
vb is the speed at the bottom of the loop
Nbottom = mvb²/R - mg
B) When you are passing the top of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the top of the loop, the net force on you is again equal to the force of gravity, but it acts downwards, providing the centripetal force required to keep you moving in a circular path.
The normal force, N, is still perpendicular to the surface of the seat. Gravity's energy, mg, operates vertically downward. Therefore, we can write:
The normal force is at its lowest point at the bottom of the loop and is equivalent to,
Ntop + mg = Fnet = mvt²/R
where,
vt is the speed at the top of the loop
At the top of the loop, the normal force is at a maximum, and it is equal to,
Ntop = mvt²/R + mg
The question is incomplete. The complete question is 'You ride a roller coaster with a loop-the-loop.A) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the bottom of the loop. Express your answer in terms of R (radius of the loop), vb (speed at the bottom of the loop), and constant g.B) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the top of the loop. Express your answer in terms of R (radius of the loop), vt (speed at the top of the loop), and constant g.'
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A flat puck (mass M) is rotated in a circle on a frictionless air-hockey tabletop, and is held in this orbit by a light cord connected to a dangling block (mass m) through a central hole in the table as shown in the figure. Start by showing the free-body diagrams and force equations for each mass, and then derive an equation for the tangential speed of the puck. This will be an algebraic expression that includes the variables mentioned above.
The dangling mass will not move and the puck will keep rotating in its orbit, Therefore, V = √(mgR/M) will be an algebraic expression that includes the variables mentioned above.
What is centripetal force?A centripetal force that causes a body to travel along a curved path. The centripetal force always acts orthogonally to the motion of the body and towards the fixed point of the path's instantaneous centre of curvature. Isaac Newton described it as "a force by which bodies are drawn or impelled, or in any way tend, towards a point as to a centre". Gravity is the centripetal force that causes astronomical orbits, according to Newtonian mechanics theory.
A common example of centripetal force is when a body moves at a constant speed along a circular path. The centripetal force is directed at right angles to the motion as well as along the radius of the circular path towards the centre.
Fc = mg
Now, centripetal force on the puck is equal to the mass of the puck times the centripetal acceleration, or
Fc = Mac
centripetal acceleration is related to the tangential velocity of the puck as
ac = V²/R
where R is the radius of the orbit. Then we have
Fc = M ac =M ω² R = M V² / R
and, thus
M V² / R = mg
and, solving for V, we get
V = √(mgR/M)
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A cat chasses a mouse across a 1.0 m high table. The mouse steps out of the way and the car slides off the table and strikes the floor 2.2m from the edge of the table. When the cat slid off the table, what was its speed?
The speed of the cat when it slid off the table would be 4.43 m/s.
What is speed?Speed is defined as the rate of motion or action, or the rate of change of something. It is typically measured in terms of distance over time, such as kilometers per hour (km/h) or miles per hour (mph). Speed can also be expressed in terms of velocity, which is the rate of change in position. Velocity is measured in meters per second (m/s). In physics, speed is a scalar quantity, meaning it is a magnitude, or numerical value, without direction.
The speed of the cat can be calculated using the equation v^2=2gh, where v is the speed, g is the acceleration due to gravity (9.81 m/s^2), h is the height of the table (1.0 m).
So, the speed of the cat when it slid off the table would be:
v = sqrt(2*9.81*1.0) = 4.43 m/s
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WORTH 40 POINTS!!
Label the following geologic map. Click on a label below the map to select it, and then click on the appropriate box on the map to place the label.
1.) Rock age/name
2.) Strike and dip
3.) Rock type
4.) Contact line
5.) Fault line
Geologic map: The correct label as placed in the respective boxes are as follows- is attached to the answer.
What is Geologic map?A geologic map is a scientific illustration that depicts the physical features of a geographic area and the underlying geology. It is used to help interpret the geologic history of a region. Geologic maps are created by geologists and contain information about the distribution of different rock types and other subsurface features. This information is used to interpret the area’s geologic history, understand the resources available in the area, and plan for development and management of the area. Geologic maps include information such as the age and type of rocks, their structures and minerals, faults and folds, and the presence of any surface features such as rivers, lakes, and soils. Geologic maps are used by geologists, engineers, planners, and other professionals to help understand the underlying geology and make decisions about how to use the land.
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calculate the temperature of a blackbody if the spectral distribution peaks at each of the following wavelengths.
a. gamma rays, λ = 10^-14 m
_____ K
b. x rays, λ = 1.03 nm
_____ K
c. red light, λ = 690 nm
_____ K
d. broadcast television waves, λ = 1 m
_____ K
e. AM radio waves, λ = 224 m
_____ K
The temperature of a blackbody if the spectral distribution peaks at each of the following wavelengths:
a. gamma rays, λ = 10^-14 m 2.898 × 10^11 K.
b. x rays, λ = 1.03 nm 2.811 × 10^6 K.
c. red light, λ = 690 nm 4,203 K.
d. broadcast television waves, λ = 1 m 2.898 × 10^-3 K.
e. AM radio waves, λ = 224 m 1.295 × 10^-5 K.
What do you mean by wavelength?
Wavelength is a fundamental concept in physics and refers to the distance between consecutive peaks or troughs in a wave. It is commonly represented by the Greek letter lambda (λ).
In the context of electromagnetic waves, which include light, radio waves, X-rays, and other types of radiation, wavelength refers to the distance between two adjacent peaks or troughs of the wave. In a vacuum, all electromagnetic waves travel at the same speed, known as the speed of light, which is approximately 3.00 × 10^8 meters per second (m/s). The wavelength of electromagnetic waves is typically measured in units of meters, but can also be expressed in units such as nanometers (10^-9 meters) or micrometers (10^-6 meters), depending on the scale of the wave being measured.
The peak wavelength of a blackbody's spectral distribution is related to its temperature through Wien's displacement law:
λ_peak = b / T
where λ_peak is the peak wavelength of the spectral distribution, T is the temperature of the blackbody, and b is a constant known as Wien's displacement constant, with a value of approximately 2.898 × 10^-3 m K.
a. For a peak wavelength of λ = 10^-14 m, we have:
T = b / λ_peak = 2.898 × 10^-3 m K / 10^-14 m = 2.898 × 10^11 K
b. For a peak wavelength of λ = 1.03 nm, we have:
T = b / λ_peak = 2.898 × 10^-3 m K / (1.03 × 10^-9 m) = 2.811 × 10^6 K
c. For a peak wavelength of λ = 690 nm, we have:
T = b / λ_peak = 2.898 × 10^-3 m K / (690 × 10^-9 m) = 4,203 K
d. For a peak wavelength of λ = 1 m, we have:
T = b / λ_peak = 2.898 × 10^-3 m K / 1 m = 2.898 × 10^-3 K
(Note that this temperature is extremely low, near absolute zero, and is not physically realistic for a blackbody.)
e. For a peak wavelength of λ = 224 m, we have:
T = b / λ_peak = 2.898 × 10^-3 m K / 224 m = 1.295 × 10^-5 K
(Note again that this temperature is extremely low and not physically realistic for a blackbody.)
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When does magnetic force push objects apart?
A: when opposite poles of two magnets are facing each other
B: never
C: when like poles of two magnets are facing each other
D: when the objects are made of wood
When two magnets' opposing poles are lined up with one another (option A).
Is strength equivalent to force?As a result of their seeming comparable definitions, force and power are frequently employed interchangeably. They are not equivalent, nevertheless, in physics. Power is a statement of energy used over time, of which force is a component, while force is the essential outcome of a collision between two objects.
What generates force?Every time two things interact, a force is applied to each of them. The force is lost when the interaction between the two items ends. Only through interactions can forces be created.
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What speed will the charge have after accelerating through a potential difference equal to 4v?.
The speed of the charged particle q after accelerating through a potential difference of 4V is given by sqrt(8qV/m).
The kinetic energy gained by a charged particle q accelerated through a potential difference V is given by:
K = qV
If the potential difference is increased to 4V, the kinetic energy gained by the particle will be:
K' = q(4V) = 4qV
Since the particle starts from rest, all the energy gained is converted to kinetic energy. Therefore, equating K' to the kinetic energy of the particle, we get:
K' = 1/2 mv^2
where m is the mass of the particle and v is the final speed of the particle.
Equating the two equations, we get:
4qV = 1/2 mv^2
Solving for v, we get:
v = sqrt(8qV/m)
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The given question is incomplete, the complete question is:
Charge q is accelerated starting from rest up to speed v through the potential difference V. What speed will charge q have after accelerating through potential difference 4V?
What is INTEGRITY? Why is it necessary in our school community? Why is it necessary in society in general? What does it look like in practice?
Integrity is the quality of being honest, truthful, and morally upright. It means doing the right thing even when no one is watching, and being accountable for one's actions.
Why is Integrity necessary?
In our school community, integrity is essential as it ensures that students and faculty members act with honesty and ethics in all their interactions. It creates a safe and trustworthy environment where individuals are respected, and their contributions are valued. Without integrity, academic performance, reputation, and character can be damaged, which can negatively impact the school community.
Integrity is also necessary in society in general, as it ensures that individuals act with honesty, ethics, and fairness in all their interactions. It helps to create a sense of trust and respect among people, which is essential for building positive relationships and fostering a healthy community. In business and professional settings, integrity is crucial as it helps to build credibility, establish trust, and maintain good relationships with clients and stakeholders.
In practice, integrity looks like individuals acting with honesty, ethics, and moral values in all their interactions. It means taking responsibility for one's actions, being accountable for one's mistakes, and working towards making things right when something goes wrong. It also means being respectful of others, treating them with dignity, and valuing their contributions. In the school community, it looks like students and faculty members conducting themselves with honesty and integrity in academic and personal settings.
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Use the terms "force", "weight", "mass", and "inertia" to explain why it is easier to tackle a 220 lb football player than a 288 lb football player. << read less.
It would be easier to tackle the 220 lb player because less force is required to change their motion due to their lower inertia.
Force is the interaction between two objects that can cause a change in motion. Weight is a type of force that is caused by gravity acting on an object with mass. Mass is a measure of the amount of matter in an object, and it determines the strength of the gravitational force acting on the object. Inertia is the tendency of an object to resist changes in its state of motion.
When tackling a football player, the player exerts a force on the tackler, and the tackler exerts an equal and opposite force on the player due to Newton's third law of motion. The player's weight is also a force acting on the tackler, and it depends on the mass of the player and the strength of the gravitational field.
The mass of an object determines its inertia, which is the resistance of the object to changes in its state of motion. In other words, an object with a greater mass has a greater inertia, and it requires a greater force to change its motion. Therefore, when tackling a football player, it is easier to tackle a player with a lower mass, or in other words, a lower weight, than a player with a higher mass, or a higher weight.
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1. Bone has a Young’s modulus of about 1.8 × 10^10 Pa. Under compression, it can
withstand a stress of about 1.61 × 10^8 Pa before breaking. Assume that a femur (thigh bone) is 0.47 m long, and calculate the amount of compression
this bone can withstand before breaking.
Answer in units of mm.
2 (Pt 1/2). How much pressure is applied to the ground by a 68 kg man who is standing on square stilts that measure 0.04 m on each edge?
Answer in units of Pa.
3 (Pt 2/2). What is this pressure in pounds per square inch?
Answer in units of lb/in^2.
4 (Pt 1/2). In an 84 s interval, 578 hailstones strike a glass window of area 0.828 m^2 at an angle 32° to the window surface. Each hailstone has a mass of 5 g and speed of 11.7 m/s. If the collisions are elastic, find the average force on the window.
Answer in units of N.
5 (Pt 2/2). Find the pressure on the window.
Answer in units of N/m^2.
6. If a 1-megaton nuclear weapon is exploded at ground level, the peak overpressure (that is, the pressure increase above normal atmospheric pressure) will be 0.2 atm at a distance of 6 km. Atmospheric pressure is 1.013 × 10^5 Pa.
What force due to such an explosion will be exerted on the side of a house with dimensions 2.09 m × 30.9 m?
Answer in units of N.
7. Find the density of seawater at a depth where the pressure is 130 atm if the density at the surface is 1050 kg/m^3. Seawater has a bulk modulus of 2.3 × 109 N/m^2. Bulk modulus is defined to be (look at picture).
Answer in units of kg/m^3.
8. Calculate the depth in the ocean at which the pressure is three times atmospheric pressure. Atmospheric pressure is 1.013 × 10^5 Pa. The acceleration of gravity is 9.81 m/s^2 and the density of sea water is 1025 kg/m^3.
Answer in units of m.
Answer:
1. Y = [tex]\frac{P*L}{Y}[/tex] = ((1.61 × 10⁸) × 0.47) ÷ 1.8 × 10¹⁰
Y = 4.20Ε17 mm
2. P = F/A
F = m×g = 68 ×9.8 = 666.4N
A = (2 · (0.04)² = 0.0032²
P = 666.4 ÷ 0.0032 = 208250 Pa
3. Psi = 208250 ÷ 6894.76
Psi = 30.20 lb/in²
4. Δp = 2 × mass × velocity
Δp = 2 × 0.005 × 11.7 × sin32 = 0.0620 kgm/s
Δp = 578 × 0.0620 = 35.83 kgm/s
F = Δp/Δt = 35.83 ÷ 84
F = 0.4266N
5. P = F/A = 0.4266 ÷ 0.828
P = 0.515244 N/m²
**(I'll add the last few later)**
A pickup truck, parked on a hill that is 11.8 m high, is accidently left in neutral without the parking brake applied.
The truck begins rolling down the hill. At the bottom, it continues rolling along a horizontal road. A 104.3-kg man jumps in the back, causing the truck's speed to reduce to 14.5 m/s. What is the mass of the truck? Ignore friction
The mass of the truck is equal to (104.3 kg x 14.5 m/s) / 11.8 m/s, which is approximately 119.4 kg.
What is mass?Mass is a measure of the amount of matter contained in an object. It can be measured using scales, balances or other measuring instruments. Mass is a fundamental property of all matter, and its measurement is the basis for many scientific and engineering calculations. Mass is not the same as weight, which is a measure of the force exerted by gravity on an object. Mass is often expressed in units such as kilograms or grams.
The mass of the truck can be determined using the law of conservation of momentum. Momentum is defined as the product of mass and velocity, so the momentum of the truck before the man jumps in is equal to the momentum of the truck and man after the man jumps in.
The momentum of the truck before the man jumps in is equal to the truck's mass multiplied by its velocity, which is 11.8 m/s. The momentum of the truck and man after the man jumps in is equal to the mass of the truck plus the man, multiplied by the reduced velocity of 14.5 m/s.
Therefore, the mass of the truck is equal to (104.3 kg x 14.5 m/s) / 11.8 m/s, which is approximately 119.4 kg.
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Vectors A and B have equal magnitudes of 5.7 u. If the sum of the vectors is 1.2 j. Determine the angle in radians between the vectors.
The angle in radians between the vectors is; 2.93 radians
What is the angle between the vectors?We are given that Vectors A and B have equal magnitudes of 5.7
The sum of the vectors is 1.2j. Thus;
A + B = 1.2 j^
Thus;
(A_x + B_x)i^ + (A_y + B_y)j^ = 0i^ + 1.2 j^
Because the vectors have the same magnitude and x components of equal magnitude but of opposite sign, the vectors are reflections of each other in the y axis. Therefore, the two vectors have the same y components:
A_y = B_y = (1/2) * 1.2 = 0.6
If θ is the angle between either A or B and the y axis, then;
cos θ = 0.6/5.7
cos θ = 0.1053
θ = 83.96°
Thus;
Angle between two vectors is;
2 * 83.96° = 167.92°
Converting to radians gives 2.93 radians
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in each of the images, two blocks are attached to a balance. Use the position and size of the blocks to determine which block is more dense in each image.
A scale weighs two boxes. The green box on the left has a large volume and pulls lower on the scale. The blue box on the right has a smaller volume and is higher on the scale.
Which block is more dense in the first image?
Which block is more dense in the second image?
Which block is more dense in the third image?
First image: Green block is larger and heavier than the blue block.
Second image: Blue and green block are the same size, but blue is heavier
Third image: Green block is smaller and heavier than the blue block
It is impossible to estimate the relative density of the blocks. The rightmost blue chunk is denser. The chunk of green on the left is denser. The mass of a material per unit volume is the definition of density.
Describe density with an example:Its density refers to how much material can fit into a specific quantity of space. For instance, a block of lead (Pb), which is heavier and less durable, will have a lower density than a block of gold (Au), which is stronger and lighter (Au).
Mass and density: what are they?The term "mass" refers to a thing's total amount of matter. The term "density" describes how tightly atoms are packed or how close together they are in a material. To calculate inertia, utilize the idea of mass.
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If a 1-megaton nuclear weapon is exploded at ground level, the peak overpressure (that is, the pressure increase above normal atmospheric pressure) will be 0.2 atm at a distance of 6 km. Atmospheric pressure is 1.013 × 105 Pa. What force due to such an explosion will be exerted on the side of a house with dimensions 2.9 m × 11 m? Answer in units of N.
The force exerted on the side of the house is due to the given explosion.
From the formula of pressure,
Where,
- pressure = 0.2 atm × 1.013×10⁵ Pa =
- Force = ?
- area = 3.89 m × 22.6 m =
So,
Put the values in the formula,
Therefore, the force exerted on the side of the house is due to the given explosion.
in an electroscope being charged by induction, what happens when the charging rod is moved away before the ground is removed from the knob?
The electroscope will remain charged and continue to show the presence of an electric charge if the ground is withdrawn from the knob before the charging rod is removed.
An early scientific tool used to find electrical charge on a body is called an electroscope. The movement of a test object caused by the Coulomb electrostatic force is used to detect charge. Voltage and charge on an object are inversely correlated.
There are three traditional electroscope types: the needle electroscope, the gold-leaf electroscope, and the pith-ball electroscope (third).
electroscopes are utilized to determine whether a body has an electric charge. The movement of a test object caused by the Coulomb electrostatic force is used to detect charge. Voltage and charge on an object are inversely correlated.
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How to solve this problem
The displacement vectors in component form are A = 1.732 km i + 1 km j and B = -2.955 km i - 0.522 km j.
The distance from home when cell phone rings is 1.309 km.
The direction from home when phone rings is 21.48° West of South.
How to express displacement vectors?(a) The displacement vector A can be expressed in component form as:
A = 2 km [cos(30°) i + sin(30°) j] = 2 km [√3/2 i + 1/2 j] ≈ 1.732 km i + 1 km j
The displacement vector B can be expressed in component form as:
B = 3 km [cos(280°) i + sin(280°) j] = 3 km [-0.985 i - 0.174 j] ≈ -2.955 km i - 0.522 km j
(b) The total displacement vector (C) is the sum of vectors A and B, which can be found by adding the corresponding components:
C = A + B = (1.732 - 2.955) km i + (1 - 0.522) km j = -1.223 km i + 0.478 km j
The magnitude of the resulting vector C can be found using the Pythagorean theorem:
|C| = √((-1.223)² + (0.478)²) ≈ 1.309 km
Therefore, you are about 1.309 km away from home when your cell phone rings.
(c) The direction of the resulting vector C can be found using the inverse tangent function:
θ = tan^-1(0.478/-1.223) ≈ -21.48°
Since the direction is measured with respect to the positive x axis, the direction from "home" to "you" when the phone rings is about 21.48° West of South.
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Learning Goal:
To understand the meaning of Kepler's second law of planetary motion.
Part A
Parts A through C all refer to the orbit of a single comet around the Sun.
Each of the four diagrams below represents the orbit of the same comet, but each one shows the comet passing through a different segment of its orbit around the Sun. During each segment, a line drawn from the Sun to the comet sweeps out a triangular-shaped, shaded area. Assume that all the shaded regions have exactly the same area. Rank the segments of the comet’s orbit from left to right based on the length of time it takes the comet to move from Point 1 to Point 2, from longest to shortest. If you think that two (or more) of the diagrams should be ranked as equal, drag one on top of the other(s) to show this equality.
According to Kepler's Second Law, as a planet orbits the Sun, an imaginary line connecting them sweeps across the same amount of space. This means that planets need not travel along their orbits speed.
What purposes does Kepler's law serve?The study of the motion the planets, asteroids, or other space objects inside the solar system makes extensive use of Kepler's laws. They are still used today to create and launch satellites into orbit. The Kepler principles served as inspiration for Newton, who then proposed his original three laws of motion and the concept of universal gravitation.
What is the name of Kepler's first law?The planets' orbits are ellipses with the light at one focus, according to Kepler's First Law, sometimes referred to as The Law on Ellipses. The line between such a planet or the sun sweeps forth equal areas inside the plane of planetary system over equal times, according to Kepler's Second Law, often known as The Law for Equal Areas at Equal Time.
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In a 42 s interval, 597 hailstones strike a glass window of area 0.597 m2 at an angle 50◦ to the window surface. Each hailstone has a mass of 6 g and speed of 6.3 m/s. If the collisions are elastic, find the average force on the window.
Answer in units of N.
A pulley consists of a large disk of radius R and a small disk of radius r that are welded together and mounted on a horizontal frictionless axle through their common centers. The moment of inertia of this pulley is I. A box containing a turkey of mass M is suspended from a rope wound around the large disk; a box containing a pumpkin of mass m is suspended from a rope wound around the small disk. The ropes do not slip on the disks. The system is released from rest and the turkey begins to descend, while the pumpkin is being lifted up.
Use forces and torques to derive an expression for the angular acceleration of the pulley, in terms of system parameters
The angular acceleration of the pulley is given by the expression α = (MgR - mgr) / I.
The forces acting on the system are the gravitational forces on the turkey and the pumpkin, which are Mg and mg, respectively. T
These forces create torques on the pulley, with the torque on the large disk being MgR and the torque on the small disk being -mgr. The negative sign on the torque of the small disk indicates that it is acting in the opposite direction of the torque on the large disk.
The sum of these torques is equal to the moment of inertia of the pulley times its angular acceleration, which can be written as:
MgR - mgr = Iα
Solving for the angular acceleration, α, we get:
α = (MgR - mgr) / I
This is the expression for the angular acceleration of the pulley in terms of the system parameters. It shows that the angular acceleration depends on the masses of the turkey and the pumpkin, the radii of the large and small disks, and the moment of inertia of the pulley.
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On a particular day, the following appliances are used for the times indicated: a 1600-W coffee maker, 13 min, and a 1100-W microwave oven, 4.5 min. With these power requirements, find how much it costs to use these appliances at an electrical cost of 7¢ per kWh. (Do not round your final answer. Fractional cent values are acceptable.)
The cost of using the appliances will be 3004.19¢
What is electricity cost?The electricity cost is defined as the amount of money required to use per Kw of electric power.
Given that on a particular day, the following appliances are used for the times indicated: a 1600-W coffee maker, 13 min, and an 1100-W microwave oven, 4.5 min.
The first step is to convert the times from minutes to hours.
60 min = 1 hour
13 min = 13 /60
4.5 min = 4.5/60
Considering the 1600-W coffee maker,
The total consumption will be calculated as:-
Consumption = 1600 x 13 /60 = 346.67 kWh
Considering the 1100-W microwave oven,
The total consumption will be calculated as:-
Consumption = 1100 x 4.5/60 = 82.5 kWh
Total consumption = 346.67 + 82.5 = 429.17 kwh
Given that the cost is 7¢ per kWh,
Cost of using these appliances = 429.17x 7
Cost of using these appliances = 3004.19 ¢
Therefore, the cost of using the appliances will be 3004.19¢
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solve it and the answer is in J
The final answer, in joules, is -1835.120716 J.
What is radian?Angles are measured in terms of radians. It is described as the angle occupied by a circle arc whose length is equal to the circle's radius. In other words, a circle with a radius of 1 unit subtends an arc with a length of 1 unit at an angle of 1 radian. Radians have no units because they are a dimensionless quantity.
Let's simplify and evaluate the given expression step by step:
First, let's calculate the terms inside the brackets:
(83)(2.1)²/4 = 185.3675 J
(100)(0)²/2 = 0 J
So, the first term in the expression becomes:
185.3675 J
Now, let's calculate the second term inside the brackets:
(83)(2.1)²/4 = 185.3675 J
(100)(2.1)²/2 = 2205 J
(0.14 rev/s * 2π rad/rev)² = 0.246784 J/(rad^2)
So, the second term in the expression becomes:
185.3675 J + 2205 J - 0.246784 J = 2390.120716 J
Now, we can calculate the final expression by plugging in the values and simplifying:
[(83)(2.1)²/4 +(100)(0)²/2] * (3 rad/sec)² - [(83)(2.1)²/4 +(100)(2.1)²/2 * (0.14 rev/s)² (2pi rad/rev)²]
= [185.3675 J + 0 J] * (3 rad/sec)² - [185.3675 J + 2205 J - 0.246784 J]
= 555 J - 2390.120716 J
= -1835.120716 J
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QUESTION 2
What are propagating in electromagnetic waves?
Electric field and magnetic field.
Electrons.
Positive charges.
Air.
Electromagnetic waves propagate through the interaction of : A. electric and magnetic fields.
What are propagating in electromagnetic waves?Electric and magnetic fields: As the electric field oscillates, it creates a changing magnetic field, and vice versa. These changing fields propagate through space, creating a self-sustaining wave that can travel through a vacuum or a medium such as air.
Electrons are not directly involved in the propagation of electromagnetic waves, but they can be affected by the waves as they interact with matter.
Positive charges also do not directly participate in the propagation of electromagnetic waves, but they can be influenced by the electric field component of the wave.
Air or any other medium does not play an active role in the propagation of electromagnetic waves, but it can affect the behavior of the waves.
Therefore the correct option is A.
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