The values of each type of energy the object has the child has both KE and GPE.
What is energy?Energy is the capacity to do work or cause change. It is the ability to cause motion, create light and heat, and cause chemical reactions. Energy exists in many forms, such as mechanical, electrical, thermal, chemical, kinetic, and potential, and can be converted from one form to another. It is a fundamental part of physical and chemical processes, as well as biological processes.
Kinetic Energy (KE):
KE = 0.5•m•v2
KE = 0.5•15kg•(3m/s)2
KE = 22.5 J
Gravitational Potential Energy (GPE):
GPE = m•g•h
GPE = 15kg•9.8m/s2•2.5m
GPE = 367.5 J
Therefore, the child has both KE and GPE.
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_____ is a buildup of fluid within the eye.
a. macular
b. degeneration
c. cataracts
d. glaucoma
e. osteoporosis
Glaucoma Is a buildup of fluid within the eye.
The optic nerve, which is necessary for clear vision, is harmed by a group of eye conditions collectively referred to as glaucoma. This injury typically happens as a result of an excessively high amount of pressure in your eye. Glaucoma is one of the leading causes of blindness in persons over 60. Glaucoma frequently results from high intraocular pressure. Diabetes, however, can also increase your risk of developing glaucoma. We'll go into more detail about the connection between diabetes and glaucoma in this piece. We'll also talk about some preventative steps you may take to help keep your eyes healthy. Loss of side or peripheral vision: Often, this is the first glaucoma symptom.
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A hydrogen bond can occur between:
A. Two hydrogen atoms on different molecules.
B. Two oxygen atom surrounded by hydrogens.
C. The two hydrogen atoms on a water molecule.
D. A hydrogen from one molecule and an oxygen from another molecule.
A hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D
What is the hydrogen bond?The hydrogen bond is one that is responsible for association in molecules. It occurs when hydrogen is covalently bonded to a highly electronegative element such as oxygen, nitrogen or Sulphur.
Thus, a hydrogen bond occurs between a hydrogen from one molecule and an oxygen from another molecule. Option D
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potassium iodide lead (II) nitrtate -- lead (II) iodide potassium nitrtate , write as a balanced equation
For Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium Nitrate , The balanced equation is [tex]Pb(NO_{3})_{2}[/tex] + 2KI -----> [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]
We must first convert from a word equation to a symbol equation:
Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium
Nitrate
The lead (II) ion is represented as [tex]Pb^{2+}[/tex] and nitrate ion as [tex]NO_{3} ^{-}[/tex]
We need two nitrate ions per lead (II) ion, so lead (II) nitrate is [tex]Pb(NO_{3})_{2}[/tex]
The potassium iodide is simply KI
In lead (II) iodide, the charges balance in a 1:2 ratio, so it is [tex]PbI_{2}[/tex]
And, potassium nitrate is simply [tex]KNO_{3}[/tex]
So, The symbol equation is as follows:
[tex]Pb(NO_{3})_{2}[/tex] + KI -----> [tex]PbI_{2}[/tex] + [tex]KNO_{3}[/tex]
Now, increase the number of nitrate ions on the right hand side of the equation as:
[tex]Pb(NO_{3})_{2}[/tex] + KI -----> [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]
Now, balance the potassium ions on each side of the equation as:
[tex]Pb(NO_{3})_{2}[/tex] + 2KI -----> [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]
Hence, the balanced equation is ;
[tex]Pb(NO_{3})_{2}[/tex] + 2KI -----> [tex]PbI_{2}[/tex] + 2 [tex]KNO_{3}[/tex]
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Comparison of IR of starting materials (given in the lecture) to IR of product What indicates the purity of the product on the IR spectrum of product
The Old Way
If the peaks matched those of known impurities, they could use the intensities to calculate the purity of the ester.
What is IR Spectrum ?IR-spectroscopy is perhaps the most frequently used technique in the organic chemistry labs at PSU. It is routinely used to identify products and to verify that an experiment has succeeded.
An IR -spectrum routinely shows peaks from the range of 3600 to 500 cm-1. IR -frequencies correspond to the frequencies of molecular vibrations. The IR spectrum can be used to show that there is not any starting material left by the loos of the alkene bond(C=C) between 1500cm^-1 and 1800cm^1 from 1-hexene and the addition of a hydroxyl group(-OH) of 2-Hexanol between 3000cm^-1 and 3300cm^-1.Learn more about IR Spectrum here:
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HI. I need some help in understanding EXTRACTION OF METAL, so do we use ELECTROLYSIS as separating method of a molten solution of there ion to extract them from the solution ,or NOT
Yes, Electrolysis is used as a separating method of a molten solution of their ion to extract them from the solution.
What is Electrolysis?A non-spontaneous chemical reaction can be sped up using a process called electrolysis that uses direct electric current. As a step in the electrolytic cell-based separation of elements from naturally existing sources like ores, electrolysis is significant from a commercial standpoint.
The electric current used to trigger an artificial reaction Numerous elements were discovered and are still produced in today's industry by the electrolysis method, which can be used to separate a substance into its original components or elements.
Uses for electrolysis include
The removal of metals from their ores using this process.It is employed in the refinement of several metals, including copper and zinc.Chlorine is produced by the process of electrolysis.Many items we use every day are electroplated using electrolysis.To know more about electrolysis refer to: https://brainly.com/question/12054569
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I NEED HELP ASAPPPP
Once extracted and purified, 20.0 grams of a pure sample of
substance X is thermally decomposed at 840oC. The two products of this reaction are calcium oxide and carbon dioxide gas. Write a balanced chemical equation and calculate the mass of calcium oxide produced. Show your process.
BALANCED CHEMICAL EQUATION:
PROCESS:
Answer:
11.2 grams CaO
Explanation:
It appears that substance X may be calcium carbonate: CaCO3
CaCO3 can be thermally decomposed to CO2 and CaO in the following balanced reaction:
CaCO3(s) ⇒ CaO(s) + CO2(g) (with applied heat, 840°C)
The molar ratio between the product, CaO, and the reactant, CaCO3, is 1:1. If we start with 1 mole CaCO3, we should produce 1 mole of CaO.
We have 20.0 grams of substance X, which we'll label CaCO3. Calculate the moles of CaCO3 by using its molar mass of 100.1 grams/mole.
20.0 grams/(100.1 grams/mole) = 0.1998 or 0.200 moles of CaCO3.
This should produce, with a molar ratio of 1 to 1, 0.200 moles of CaO
Convert this to grams CaO by multiply by it's molar mass of 56.1 g/mole:
(0.200 moles)*(56.1 g/mole) = 11.2 grams CaO. Any less, then blame it on your lab partner. But don't try taking credit if you have more than 11.2 grams. Scraping debri off the counter into the beaker doesn't count.
Describe any five uses of non-metals.
HYDROGEN: USED AS ROCKET FUEL.
CHLORINE: USED TO PURIFY WATER.
GRAPHITE: USED IN PENCILS TO WRITE.
HELIUM: USED IN BALOONS TO MAKE THEM FLOAT INTO THE AIR.
PHOSPHOROUS: USED FOR IGNITION, SUCH AS FIREWORKS.
Cesium-137 has a half life of 30.0 years. If initially there are 8.0 kg of cesium-137 present in a sample, how many kg will remain after 60.0 years
Mass after 60 years:
2 kg of cesium-137 will remain after 60.0 years.
What is Half-life?
The duration needed for a quantity to decrease to half of its initial value is known as the half-life.
Given:
N0 = is the initial amount of cesium-137 = 8.0 Kg
N = is the amount remaining after a time = Unknown
t = Duration of cesium-137 decay in 8.0 Kg = 60 years
t1/2 = half-life of cesium-137 = 30.0 years
Formula = N/No = (1/2)^t/t1/2
After putting the value:
N/8= (1/2)^60/30
N/8= (1/2)^2
N/8= 1/4
4N= 8
N= 8/4
N= 2 Kg
As a result, 2 Kg of cesium-137 will be present after 60 years.
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Monosaccharides are the smallest building blocks of sugars and have similar chemical compositions. Considering that simple sugars are a component of carbohydrates, what is the general chemical composition of monosaccharides
Answer:
See below
Explanation:
Monosaccharides:They are the simplest sugars.They can not be hydrolyzed.They are sweet in taste.They are soluble in water.They have the general formula of [tex]C_n(H_2O)_n[/tex]Chemical composition:They are composed of:CarbonHydrogenOxygen[tex]\rule[225]{225}{2}[/tex]
What property should a radioisotope used for dating have?
OA. It must be an isotope not commonly found in the fossil.
OB. Its half-life should be similar to the age of the fossil.
OC. It must have a half-life much longer than the fossil age.
OD. It must decay to a stable isotope of the same element.
The property a radioisotope used for dating should have is Its half-life should be similar to the age of the fossil and is denoted as option B.
What is a Radioisotope?This is an element which is unstable and releases radiation to achieve its stability.
The half-life of the element used in dating should be similar to that of the fossil for easy comparisons and accuracy.
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Answer:
b, half life should be similar to the fossil
Explanation:
(RLLY NEED HELP) What is caused by friction between two objects?
Static electricity
Dry air
A circuit
Moist air
Please Help! Is it possible to have two other resonance structures with the double bond being connected to the chlorine.
It is possible for two other resonance structures to be connected but results in positive formal charge which isn't suited for a very electronegative atom such as chlorine.
What is a Lewis structure?This is a type of diagram which depicts the bonding between atoms and lone pairs which are present in the molecule.
Adding two other resonance structures will also result in the poor overlap between the p-orbitals.
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What is the energy change when 100g of Benzene boils at 80.1°C?
The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.
What is Enthalpy of Vaporization ?The amount of enthalpy or energy that must be added to a liquid substance into gas substance is called Enthalpy of Vaporization. It is also known as Latent heat of vaporization.
How to find the energy change from enthalpy of vaporization ?To calculate the energy use this expression:
[tex]Q = n \Delta H_{\text{vapo.}[/tex]
where,
Q = Energy change
n = number of moles
[tex]\Delta H_{\text{Vapo.}}[/tex] = Molar enthalpy of vaporization
Now find the number of moles
Number of moles (n) = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{100\ g }{78\ g/mol}[/tex]
= 1.28 mol
Now put the values in above formula we get
[tex]Q = n \Delta H_{\text{vapo.}[/tex]
= 1.28 mol × 30.8 kJ/mol
= 39.42 kJ
Thus from the above conclusion we can say that The enthalpy of vaporization for Benzene is 30.8 kJ/mol. 39.42 kJ is the energy change when 100g of Benzene boils at 80.1 degrees Celsius.
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Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The enthalpy of vaporization for Benzene is 30.8 kJ/mol. What is the energy change when 100g of Benzene boils at 80.1 degrees Celsius?
Determine the molar mass of a 0.314-gram sample of gas having a volume of 1.6 l at 287 k and 0.92 atm. show your work.
As per Ideal gas equation, molar mass of the gas is 5.032 g/mo
We’ll begin by calculating the number of mole of the gas. This can be obtained as follow:
Volume (V) = 1.6 L
Temperature (T) = 287 K
Pressure (P) = 0.92 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Number of mole (n) =?
According to Ideal gas equation , PV = nRT
0.92 × 1.6 = n × 0.0821 × 287
1.472 = n × 23.5627
Divide by 23.5627
n = 1.176 / 23.5627
n = 0.0624 mole
Finally, we shall determine the molar mass of the gas. This can be obtained as follow:
Mass of gas = 0.314 g
Number of mole = 0.0624 mole
Mole = [tex]\frac{mass}{molar mass}[/tex]
0.0624 = [tex]\frac{0.314}{molar mass}[/tex]
Cross multiply
0.0624 × molar mass of gas = 0.314
Divide by 0.0624
Molar mass of gas = [tex]\frac{0.314}{0.0624}[/tex]
Molar mass of gas = 5.032 g/mo
Therefore the Molar mass of gas is 5.032 g/mo
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A mixture of water and acetone boils at 1.25 atm will boil at 348.15K. Given the vapor pressure of acetone (1.58 atm) and water(0.312 atm), what is the composition of the solution in terms of mole fraction of each chemical present
A mixture of water and acetone boils at 1.25 atm will boil at 348.15K. Given the vapor pressure of acetone (1.58 atm) and water(0.312 atm). 5.06 is the composition of the solution in terms of mole fraction of each chemical present.
What is Raoult's Law ?Raoult's Law is a nonvolatile solute lowers the vapour pressure of the solvent.
It is expressed as:
[tex]P_{\text{soln}} = x_{\text{solvent}} P_{\text{solvent}}[/tex]
where,
[tex]P_{\text{sol}[/tex] = vapor pressure of the solution
[tex]x_{\text{solvent}}[/tex] = mole fraction of the solvent
[tex]P_{\text{solvent}}[/tex] = vapor pressure of the pure solvent
Now put the values in above expression, we get
[tex]P_{\text{soln}} = x_{\text{solvent}} P_{\text{solvent}}[/tex]
[tex]x_{\text{solvent}} = \frac{P_{\text{soln}}}{P_{\text{solvent}}}[/tex]
[tex]= \frac{1.58}{0.312}[/tex]
= 5.06
Thus from the above conclusion we can say that A mixture of water and acetone boils at 1.25 atm will boil at 348.15K. Given the vapor pressure of acetone (1.58 atm) and water(0.312 atm). 5.06 is the composition of the solution in terms of mole fraction of each chemical present.
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Consider the reaction. At 298 K, the equilibrium concentration of O2 is 1.6 x 10-2 M, and the equilibrium concentration of O3 is 2.86 x 10-28 M. What is the equilibrium constant of the reaction at this temperature
The value of the equilibrium constant is 1.99 × [tex]10^-^5^0[/tex] .
Given:
Concentration of [tex]O_2 = 1.6[/tex] × [tex]10^-^2 M\\[/tex]
Concentration of [tex]O_3 = 2.86[/tex] × [tex]10^-^2^8 M[/tex]
A chemical reaction known as an equilibrium reaction occurs when the reactants remain in a stable condition both during and after the reaction.
The given balanced equilibrium reaction is,
[tex]3O_2 (g) = 2O_3 (g)[/tex]
The expression for equilibrium constant will be,
[tex]K_c = \frac{[O_3] ^2}{[O_2]^3}[/tex]
Now put all the given values in this formula, and we get
[tex]K_c = \frac{(2.86 * 10^-^2^8] ^2}{[1.6 * 10 ^-^2]^3}[/tex]
[tex]K_c = 1.99[/tex] × [tex]10^-^5^0[/tex]
Therefore, the value of the equilibrium constant is 1.99 × [tex]10^-^5^0[/tex] .
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Help me ASAP please!!!
The concentration of the sodium hydroxide will be 0.016 M
Stoichiometric problemFirst, the concentration of the diluted nitric acid needs to be found.
m1 = 2.0 M, v1 = 100 mL, v2 = 300.0 mL
m2 = 2 x 100/300 = 0.6667 M
The equation of the reaction goes thus: [tex]HNO_3 + NaOH = NaNO_3 + H_2O[/tex]
The mole ratio is 1:1.
Mole of 0.6667 M, 7.05 mL HNO3 = 0.6667 x 0.00705 = 0.0047 mol
Equivalent mole of NaOH = 0.0047 mol
Molarity of 0.0047 mol, 30.0 mL NaOH = 0.0047/0.3 = 0.016 M
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Part C Compare your proposed process for the synthesis of ammonia from part E of task 2 with the Haber process. Describe at least two similarities and two differences between the processes.
On comparing the proposed processes of ammonia synthesis by dry distillation and Haber process,
The similarities found are both process use natural raw material and The differences between them are Haber process use catalyst (iron) while there is no catalyst in the proposed processDry distillation processAmmonia was mainly produced by the method of dry distillation pf animal waste It can also be prepared from the waste of vegetables which are rich in ammoniaIn this process the nitrites, nitrous acids and hydrogen were reduced to give the nitrogen as a product.Haber process This process involves the reaction between molecules of nitrogen and hydrogen in gaseous phase.The raw materials, nitrogen is obtained from air and the hydrogen is from Water and methane gas.Chemical reaction involved in this process is, N2 + 3H2 ↔ 2NH3The catalyst used in this process is iron which increases the rate of reaction.Learn more about Haber process on
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Regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called:_______
Regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism
What are nucleotides?Nucleotide can simply be defined as the basic building block of nucleic acids either RNA and DNA
Generally, nucleotides consists of a sugar molecule (either ribose in RNA or deoxyribose in DNA) attached to a phosphate group and a nitrogen-containing base.
A region is any considerable and connected part of a space or surface; specifically, a tract of land or sea of considerable but indefinite extent, a country, a district, in a broad sense, a place without special reference to location or extent but viewed as an entity for geographical, social or cultural reasons.
So therefore, regions in the human genome where one nucleotide has been substituted for another in at least 1% of the population are called single nucleotide polymorphism.
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In texas, special elections are used to:
In Texas, special elections are used to ratify amendments to the Texas Constitution.
What is Election?This is referred to a formal way of people voting for someone or for a type of cause.
Special elections which are held in Texas is done to ratify amendments to the constitution and is usually done by the legislature thereby making it the most appropriate choice.
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The equilibrium concentration of sulfide ion in a saturated lead sulfide solution is M. (Assume that .)
What type of polymer is alginic acid? Which two modified carbohydrate units make up the basic building block of this polymer?
An alginic acid is bio polymer. The two modified carbohydrate units make up the basic building block of this polymer are guluronic acid ( G) and mannuronic acid (M).
Alginic acid is a biopolymer formed from chain of polyuronic acid. Alginic acid is polysaccharide found in brown algae. Alginic acid is also known as Algin. it is linear co-polymer.
Polysaccharides are found in the food and it is most abundant carbohydrates. It is long chains of monosachharides. Polysaccharides is formed by glycosidic linkage or bonds .
Example of polysaccharides are cellulose , starch , glucogen.
lern about polysaccharide
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Which is more precise
164 or 165 if the true value is 167
A Carnot cycle operates between the temperatures limits of 400 K and 1600 K, and produces 3600 kW of net power. The rate of entropy change of the working fluid during the heat addition process is
The rate of entropy change:
The rate of entropy change of the working fluid during the heat addition process is 3 kW/K
What is the Carnot cycle?
The Carnot Cycle is a thermodynamic cycle made up of reversible isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression processes in succession. The ratio of the heat absorbed to the temperature at which the heat was absorbed determines the change in entropy.The entropy of a system:
The rate of heat addition is expressed as,
Q = [tex]\frac{WT_{H}}{T_{H}- T_{L}}[/tex]
The entropy of a system is a measure of how disorderly a system is getting. The rate of entropy generation during heat addition is,
[tex]S_{gen} = \frac{Q}{T_{H}} = \frac{W}{T_{H} - T_{L}}[/tex]
Calculation:
Given:
[tex]T_{L}[/tex] = 400K
[tex]T_{H}[/tex] = 1600K
W = 3600 kW
Put all the values in the above equation, and we get,
[tex]S_{gen} = \frac{W}{T_{H} - T_{L}}[/tex] = [tex]\frac{3600}{1600-400}[/tex] = 3 kW/K
The rate of entropy change is 3 kW/K
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Help me pls!!!!!!!!!!!!!!!!!!!!!
The liberated electron will have 10.28 eV kinetic energy.
Given that light of frequency 3.62 × [tex]10^{15}[/tex] Hz strikes a surface of copper metal with work function([tex]W_{0}[/tex] = 4.70 eV).
The incident (photon) energy given as hf (Planck's Constant time's frequency) minus the energy that "binds" the electron to the metal (the work function) will equal the maximum kinetic energy of the emitted electron.
K.E. = hf − ϕ
Where K = Kinetic energy
h = Planck's constant = 6.62607015 × [tex]10^{-34}[/tex] J s
f = frequency = 3.62 × [tex]10^{15}[/tex] Hz
ϕ = 4.70 eV = 4.7 × 1.6 × [tex]10^{-19}[/tex] = 7.52 × [tex]10^{-19}[/tex]
K.E. = 6.62607015 × [tex]10^{-34}[/tex] × 3.62 × [tex]10^{15}[/tex] - 7.52 × [tex]10^{-19}[/tex]
= 6.62607015 × 3.62 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]
= 23.98 × [tex]10^{-19}[/tex] - 7.52 × [tex]10^{-19}[/tex]
K.E. = 16.46 × [tex]10^{-19}[/tex] J = 10.28 eV
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QUICK CHECK
Select the structure corresponding to methylpropylether.
O
Distinguishing Alcohols and Ethers
DONE
The structure that corresponds to methylpropylether is the structure CH3 - O - C3H7 in option C.
What is structure?The structure of a compound is defined as the way in which the atoms in the compound are arranged. We know that a compound is composed of atoms and these atoms are arranged in particular patterns in space. This is the stereochemistry of the molecule.
Now we know that methylpropylether is a compound that contains the methyl group and the propyl group separated by a oxygen atom as is typical of all ethers.
As such, the structure that corresponds to methylpropylether is the structure CH3 - O - C3H7 in option C.
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A sample of air at room temperature in a 4.00 L container holds approximately 0.562 moles of O2and 2.11 moles of N2 along with other trace elements to total 2.67 moles. What is the mole fraction of N2 in the mixture
Taking into account the definition of mole or molar fraction, the mole fraction of N₂ in the mixture is 0.79.
Molar fractionThe molar fraction is used to express the concentration of a solute in a solution and expresses the proportion in which a substance is found with respect to the total moles of the solution, which are calculated by adding the moles of solute(s) and solvent.
The mole fraction "x" of the elements in a compound is defined as a ratio between the number of moles of each of the different elements present in the compound and the total number of moles of them:
x=number of moles of the solute÷ total number of moles
Mole fraction of N₂ in the mixtureIn this case, you know that:
number of moles of N₂: 2.11 molestotal number of moles: 2.67 molesReplacing in the definition of mole fraction:
x=2.11 moles÷ 2.67 moles
Solving:
x= 0.79
Finally, the mole fraction of N₂ in the mixture is 0.79.
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what is the formula n²o
Answer:
Nitrous oxide
Explanation:
Nitrous+ Oxygen (ygen becomes -ide when it is combined) = Nitrous oxide
just learnt these in school, hope this is correct
hii kiran hru my darling
In your reaction you started with a solution that was approximately 8 M acetic acid and 4 M isopentyl alcohol. Use the equilibrium expression for this reaction to calculate the final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid (you'll need to use the quadratic equation to solve this expression) assuming that the equilibrium constant is 4.2. Calculate the percent yield of isopentyl acetate to which this value would correspond.
The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M
Using ICE table:-
Acetic acid + Isopentyl alcohol ------> Isopentyl acetate + water
I 8M 4M 0 0
C 8-x 4-x +x +x
E 8-x 4-x +x +x
Equilibrium constant (Keq) = 4.2
On using the equilibrium expression -
Keq = [Product] / [Reactant]
Keq = x^2 / (8-x) (4-x )
4.2 = x^2 / 32 - 8x - 4x + x^2
x = 3.4
Concentration of acetic acid = 8-x = 8-3.4 = 4.6M
Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M
Concentration of isopentyl acetate = x = 3.4M
Concentration of water = x = 3.4M
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How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __ H2
Answer:
0.6258 g
Explanation:
To determine the number grams of aluminum in the above reaction;
determine the number of moles of HCldetermine the mole ratio,use the mole ratio to calculate the number of moles of aluminum.use RFM of Aluminum to determine the grams required.Moles of HCl
35 mL of 2.0 M HCl
2 moles of HCl is contained in 1000 mL
x moles of HCl is contained in 35 mL
[tex]x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \: [/tex]
We have 0.07 moles of HCl.
Mole ratio
Balanced equation6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)
Hence mole ratio = 6 : 2 (HCl : Al
but moles of HCl is 0.07, therefore the moles of Al;[tex] = \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles[/tex]
Therefore we have 0.0233333 moles of aluminum.
Grams of Aluminum
We use the formula;
[tex]grams \: = moles \: \times \: rfm[/tex]
The RFM (Relative formula mass) of aluminum is 26.982g/mol.
Substitute values into the formula;
[tex] = 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams[/tex]
The number of grams of aluminum required to react with HCl is 0.6258 g.