A ball rolls 10.0 m [S] ina time of 60.0s, it hits a wall, and rolls back a distance of 15.0 m [N] in a time of 10.00s. Determine: ( /4)
The distance travelled by the ball.



The displacement of the ball.



The average speed of the ball.



The average velocity of the ball.

Answers

Answer 1

The distance travelled by the ball is 25 m.

The displacement of the ball is 5 m.

The average speed of the ball is 0.357 m/s.

The average velocity of the ball is 0.071 m/s.

What is the distance travelled by the ball?

The distance travelled by the ball is calculated as follows;

distance = 10 m + 15 m = 25 m

The displacement of the ball = Δx

where;

Δx is change in position

displacement = 15 m - 10 m = 5 m

The average speed of the ball is calculated as;

average speed = total distance / total time

average speed = (25 m ) / (60 s + 10 s ) = 0.357 m/s

The average velocity of the ball is calculated as;

average velocity = total displacement / total time

average velocity = (5 m ) / (60 s + 10 s ) = 0.071 m/s

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Related Questions

5. Find the resonance frequency Æ0 in Hz of a series LRC circuit with L=0.030H, C=1.0*10^-9, and R=1000 Ω.

Answers

The resonance frequency Æ0 is 318309.89 Hz. The resonance frequency of a series LRC circuit is given by the formula [tex]Æ0 = 1/(2π√(LC))[/tex].

Substituting the given values, we get [tex]Æ0 = 1/(2π√(0.030H x 1.0*10^-9F))[/tex] = [tex]318309.89 Hz[/tex]. This means that when an AC voltage is applied to the circuit at this frequency, the circuit will resonate and the current will be maximum. At frequencies higher or lower than the resonance frequency, the current will decrease. The resistor R in the circuit causes the current to decrease with time and thus limits the amplitude of the resonant current.

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