A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves. What is the solute in this scenario?

A. Sodium
B. Sodium Chloride
C. Water

Answer:

solid

Explanation:

chlorine is liquid

Answer:

100.09 amu is the answer.

Answer:

45g

Explanation:

first we will find out which is the limiting reactant (hope you know how to find it)

Cao is the limiting reactant

so

we will find the number of moles of cao which is 0.45 mol

as according to the equation cao and caco3 have ratios 1:1 so both will have the same no. of moles

then by multiplying 0.45mol by 100 (mr of caco3) we will get the mass of caco3 which is 45g

After subtracting the volume needed from the volume dispensed, we got a remainder of 35ml

Given Data

Let us compute the amount of excess hexane/ the volume that will remain

Remainder = The difference in volume dispensed and the volume needed

Remainder = 40-5

Remainder = 35 ml

The remainder is 35ml

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If you dispense 40 ml of hexane, but it turns out you only need 5 ml, then we should have 35 mL of remained hexane.

Remaining volume of any liquid will be calucted as:

Remaining Volume = Total volume - Used volume

Given that, total volume of hexane = 40 mL

Used volume of hexane = 5 mL

On putting values in above equation, we get

Remaining volume = 40 - 5 = 35 mL

Hence required value of remaining volume is 3 mL.

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A map that shows the location of volcanoes is called a Geologic Map. This kind of map contains information about the geological history and condition of volcanic sites.

Geologic maps indicate the following:

Note that the map specific to the question is unavailable hence the general response.

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When a solution of MgCl₂ and a solution of AgNO₃ are mixed, the net ionic equation obtained is:

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.

The reactants are located on the left side while the products are located on the right side.

Reactants —> Products

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

In solution

MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)

AgNO₃(aq) —> Ag⁺(aq) + NO₃¯(aq)

The reaction proceeds as follow

MgCl₂(aq) + AgNO₃(aq) —>

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) —> 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Cancel out the spectator ions (i.e Mg²⁺ and NO₃¯) to obtain the net ionic equation

2Cl¯(aq) + 2Ag⁺(aq)  —> 2AgCl(s)

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When a solution of MgCl₂ and one of AgNO₃ are mixed, the net ionic equation is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

Net ionic reactions are those reactions in which each species are written in their respective ions form except the spectator ions.

Given chemical reaction is:

MgCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Mg(NO₃)₂(aq)

Ionic form of the given reaction will be written as

Mg²⁺(aq) + 2Cl¯(aq) + 2Ag⁺(aq) + 2NO₃¯(aq) → 2AgCl(s) + Mg²⁺(aq) + NO₃¯(aq)

Spectator ions are those which are commonly present on both side of the reaction and for this reaction they are Mg²⁺ and NO₃¯. So the net ionic reaction will be:

2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s)

Hence required net ionic reaction is 2Cl¯(aq) + 2Ag⁺(aq) → 2AgCl(s).

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Aldol condensation involves the reaction of an acid or base with a carbonyl group producing a nucleophile that attacks another carbonyl compound  to yield a β-hydroxyaldehyde or β-hydroxyketone compound.

The aldol condensation is a reaction in organic chemistry in which there is a reaction between an acid or base and a carbonyl group which then serves as the nucleophile that attcks a second carbonyl to yield a β-hydroxyaldehyde or β-hydroxyketone compound.

The aldol condensation may be acid catalysed or base catlysed. The question is incomplete hence the complete mechanimsms can not be decuced.

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Decomposition reaction results in the formation of the products by splitting the reactants. Moles of mercury(ii) oxide needed are 15.63 moles.

Moles are the ratio of mass and the molar mass of the compound or the molecule.

Moles of oxygen are calculated as:

[tex]\begin{aligned}\rm n &= \rm \dfrac {mass}{molar\; mass}\\\\&= \dfrac{250}{32}\\\\&= 7.8125 \;\rm moles\end{aligned}[/tex]

The balanced chemical reaction can be shown as,

[tex]\rm 2HgO \rightarrow 2Hg + O_{2}[/tex]

From the reaction, it can be said that 1 mole of oxygen requires 2 moles of mercury oxide.

Moles of mercury oxide are calculated as:

[tex]\begin{aligned} \rm n HgO& = (7.8125 \;\rm moles \; O_{2}) \times (\dfrac{2 \;\rm moles\; HgO}{1 \;\rm mole \; O_{2}})\\\\\rm n HgO &= 15.625 \;\rm moles \end{aligned}[/tex]

Therefore, option C. 15.63 moles of mercury (II) oxide is needed.

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The molecular formula of the compound which has a molecular weight of 112.124 atomic mass units is C₆H₈O₂.

Molecular formula of any compound tells about the composition and numbers of each entities present in that molecule.

Steps involved in the prediction of molecular formula:

      Molar mass of C₃H₄O = 3(12) + 4(1) + 16 = 56

        112.124/56 = 2

        Molecular formula = (C₃H₄O)₂ = C₆H₈O₂

Hence correct option is (E).

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Answer:

The answer is Ka1

▬▬▬▬▬▬▬▬

When it comes to dissociation, Ka1 is fairly the most even-out level, classifying it as a Weak Acid.

They must be fully separable into ions. If that's the case, you are dealing with a Strong acid.

If this is not the case, that would make the acid Weak.

▬▬▬▬▬▬▬▬

In conclusion, I hope this helps you and I hope you have a great day!

Answer:

Fiddlehead

Explanation:

Young fronds are called Fiddleheads

because of how they are coiled

Answer:

Fiddleheads or koru

Explanation:

The coiled, immature leaves are called fiddleheads. Young fronds, called fiddleheads because of their striking resemblance to the head of a violin, start out tightly curled at the base of the root. New, or young fronds are produced from the rhizome. They are tightly coiled into a spiral (called a fiddlehead or koru), and these slowly uncoil as they mature.

Answer:

The air resistance is a special type of frictional force that acts upon objects as they travel through the air. The force of air resistance is often observed to oppose the motion of an object. This force will frequently be neglected due to its negligible magnitude (and due to the fact that it is mathematically difficult to predict its value). It is most noticeable for objects that travel at high speeds (e.g., a skydiver or a downhill skier) or for objects with large surface areas. Air resistance is a contact force.

The force of gravity is the force with which the earth, moon, or other massively large object attracts another object towards itself. By definition, this is the weight of the object. All objects upon earth experience a force of gravity that is directed "downward" towards the center of the earth. Gravitational force is considered to be a non-contact force because it is an attracting force which does not include contact between the objects to exert force

Answer:

D

Explanation:

because if a flea is on a dog that is a parisite to host relashionship

Answer:

for number 3 is D

Explanation:

but i am not 100% sure of that

Explanation:

which one of the following a correct way of finding current?

Answer:

acquired traits are traits that organisms develops over a lifetime. adaptation are trait that enhances an organism's ability to survive and reproduce in its environment.

It is not possible for the structure to be an isomer of butanoic acid because it consists of 5 carbon atoms.

An isomer of butanoic acid is a chemical compound with the same molecular formula but a different structural arrangement of its atoms.

Butanoic acid, also known as butyric acid, has the molecular formula C₄H₈O₂. It is a carboxylic acid with a straight-chain arrangement of four carbon atoms.

One isomer of butanoic acid is called isobutyric acid (2-methylpropanoic acid). Isobutyric acid has the same molecular formula C₄H₈O₂, but its carbon atoms are arranged in a branched structure.

So from the given structural formula, it is not possible for the structure to be an isomer of butanoic acid because it consists of 5 carbon atoms.

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Answer:

When it decays, a radionuclide transforms into a different atom - a decay product. The atoms keep transforming to new decay products until they reach a stable state and are no longer radioactive. The majority of radionuclides only decay once before becoming stable.

The negative ion in aqueous sodium hydroxide, NaOH(aq) is hydroxide ion, OH-.

A neutralization reaction is a reaction between an acid and a base to form salt and water only.

The reaction between vinegar and NaOH is a neutralization reaction which produces a salt and water only.

NaOH is composed of a positive sodium ion, Na+ and a negative hydroxide ion, OH-

Therefore, the negative ion in the NaOH(aq) used in this titration is hydroxide ion, OH-.

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The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = Molarity × Volume

Mole of NiCl₂•6HO₂ = 0.035 × 0.5

Mole of NiCl₂•6HO₂ = 0.0175 mole

Mass = mole × molar mass

Mass of NiCl₂•6HO₂ = 0.0175 × 238

Mass of NiCl₂•6HO₂ = 4.165 g

Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution

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The grams of NiCl₂.6H₂O will be used to prepare a 0.0350M, 500ml of NiCl₂ solution is 2.268 grams.

Mass in grams of any substance will be calculated by using moles as:

n = W/M, where

W = given mass

M = molar mass

Moles from molarity will be calculated by using the below formula:

M = n/V, where

M = molarity of NiCl₂ solution = 0.0350M

V = volume of solution = 500mL = 0.5L

On putting values, we get

n = (0.035)(0.5) = 0.0175 mol

Now we convert these moles into grams by using the first formula as:
W = (0.0175mol)(129.6g/mol) = 2.268g

Hence required mass of NiCl₂.6H₂O is 2.268g.

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The volume of NaOH required to titrate 50 mL of 0.0998 M butanoic acid to the equivalence point is 41.58 mL

C₄H₈O₂ + NaOH —> C₄H₇O₂Na + H₂O

From the balanced equation above,

From the question given above, the following data were obtained:

CaVa / CbVb = nA / nB

(0.0998 × 50) / (0.12 × Vb) = 1

4.99 / (0.12 × Vb)  = 1

Cross multiply

0.12 × Vb = 4.99

Divide both side by 0.12

Vb = 4.99 / 0.12

Vb = 41.58 mL

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Answer:

0.258 moles of Oxygen.

Explanation:

Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

Addition of sodium carbonate is a way to soften water by removing calcium ions

Water can be softened by the addition of lime to precipitate the calcium as carbonate. Sodium carbonate is also added to remove the remaining calcium salts and to make the water soft.

So we can conclude that addition of lime or sodium carbonate is a way to soften water by removing calcium ions.

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A process based on ksp experiment to soften the water by removing calcium ions is by ion exchange resin process in which the calcium ion is substituted by a sodium ion.

The water containing a large number of calcium ions is called hard water.

Hard water is not suitable to use.

To remove calcium ion or soften the water, there are various methods are used.

They are ion exchange resin, distillation, and sodium hydroxide.

Thus, a process based on ksp experiment to soften the water by removing calcium ions is by ion exchange resin process in which the calcium ion is substituted by a sodium ion.

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Answer:

Cycle

Explanation:

Water on the earth is constantly on the move, it recycles over and over again. This movement is called the water cycle. Precipitation occurs when there is so much water in the air it cannot hold onto it anymore. It will rain, snow, sleet or hail. It fills up our lakes, streams and oceans on the surface of the earth.

Answer:

At the equivalence point, equal amounts of H+ and OH– ions will combine to form H2O, resulting in a pH of 7.0 (neutral). The pH at the equivalence point for this titration will always be 7.0, note that this is true only for titrations of strong acid with strong base.

Explanation:

Answer:

1.312788 atm

Explanation:

Answer:

should be 2M

Explanation:

:)

Answer:

Acrylonitrile Styrene Acrylate

Answer: 139.2 g

Explanation:

2.9 mol KClO3 (3 mol O2 / 2 mol KClO3) (32 g / 1 mol O2) = 139.2 grams :)

Answer:

This is a pretty straightforward example of how an ideal gas law problem looks like.

Your strategy here will be to use the ideal gas law to find the pressure of the gas, but not before making sure that the units given to you match those used by the universal gas constant.

So, the ideal gas law equation looks like this

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

P

V

=

n

R

T

a

a

∣

∣

−−−−−−−−−−−−−−−

Here you have

P

- the pressure of the gas

V

- the volume it occupies

n

- the number of moles of gas

R

- the universal gas constant, usually given as

0.0821

atm

⋅

L

mol

⋅

K

T

- the absolute temperature of the gas

Take a look at the units given to you for the volume and temperature of the gas and compare them with the ones used in the expression of

R

.

a

a

a

a

a

a

a

a

a

a

a

Need

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

Have

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

a

Liters, L

a

a

a

a

a

a

a

a

a

a

a

a

a

Liters, L

a

a

a

a

a

a

a

a

a

a

a

√

a

a

a

a

a

a

a

Kelvin, K

a

a

a

a

a

a

a

a

a

a

a

a

Celsius,

∘

C

a

a

a

a

a

a

a

a

a

×

Notice that the temperature of the gas must be expressed in Kelvin in order to work, so make sure that you convert it before plugging it into the ideal gas law equation

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

T

[

K

]

=

t

[

∘

C

]

+

273.15

a

a

∣

∣

−−−−−−−−−−−−−−−−−−−−−−−−

Rearrange the ideal gas law equation to solve for

P

P

V

=

n

R

T

⇒

P

=

n

R

T

V

Plug in your values to find

P

=

0.325

moles

⋅

0.0821

atm

⋅

L

mol

⋅

K

⋅

(

35

+

273.15

)

K

4.08

L

P

=

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

2.0 atm

a

a

∣

∣

−−−−−−−−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the temperature of the gas.

Answer:

[tex]\huge\boxed{\sf P = 1.68 \ atm}[/tex]

Explanation:

Given:

Moles = n = 0.6 mol

Volume = v = 9.13 L

Temperature = T = 38 °C + 273 = 311 K

Gas constant = R = 0.08206 L atm K⁻¹ mol⁻¹

Required:

Pressure = P = ?

Formula:

Pv = nRT

Solution:

Rearranging formula

[tex]\displaystyle P = \frac{nRT}{v} \\\\P = \frac{(0.6)(0.08206)(311)}{9.13} \\\\P = \frac{15.3}{9.13} \\\\P = 1.68 \ atm\\\\\rule[225]{225}{2}[/tex]

Answer:

...

Explanation:

Explanation:

BECAUSE I DONT KNOW AS WELL CAN SOME ONE HELP.