Assuming the resistance is constant, the current in the heating element if it is connected to 120 v is 4.247A
If the temperature and other physical parameters of the wire, such as stresses and strains, stay unchanged, the current flowing through the wire is precisely proportional to the potential difference applied across its ends.
To calculate the current in the heating element when connected to 120 V, we can use the Ohm's Law formula:
Power (P) = Voltage (V) x Current (I)
We know that the power rating of the heating element is 2,040 W when connected to 240 V. Therefore, we can find the resistance of the heating element using the formula:
Resistance (R) = (Voltage)² / Power
R = (240)² / 2040
R = 28.235 ohms
Now that we know the resistance of the heating element, we can use the formula for current:
I = V / R
When the heating element is connected to 120 V, the current can be calculated as:
I = 120 / 28.235
I = 4.247 A
Therefore, the current in the heating element when connected to 120 V is 4.247 A, assuming the resistance is constant.
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mc qu. 13 after using the barter system, it was... after using the barter system, it was decided that a simpler medium of exchange needed to take place, and the result was to
In the wake of taking on the trade framework, it was resolved that a less complex type of trade was required.
Prompting the decision of a solitary decent that could be openly traded for some other great with the assent of the gatherings.
What is a Barter system ?The term "barter," which comes from the Latin word "baretor," refers to a method of exchanging goods and services between two parties without the use of money.
The bartering system most likely originated with Mesopotamian tribes around 6000 BC. The Phoenicians saw how it was done and adopted it into their culture. These ancient people exchanged products for the food, instruments, and flavors they required.
Under this system, there is no imbalance in trade or a lack of foreign currency. A barter system does not produce the waste that occurs in a monetary economy. because there are neither too many nor too few products.
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monochromatic light shining on a metal is observed to cause it to emit electrons. which change below might cause the emission of electrons to stop?
If the frequency of the monochromatic light shining on the metal is decreased below the threshold frequency, the emission of electrons would stop.
This is because the energy of the photons in the light would not be sufficient to overcome the metal's work function and eject electrons from its surface.
If monochromatic light is causing a metal to emit electrons, this is known as the photoelectric effect. To stop the emission of electrons, you can either decrease the intensity of the light or choose a light source with a longer wavelength (lower frequency) so that the photons have insufficient energy to overcome the metal's work function.
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Can someone please help me understand these? (The box is sliding down the incline on #1). Preferably using free body diagrams :)
Question A.
i. the force you need to apply to the box to move it down the hill at a constant speed is 500 N.
ii. the acceleration of the piano down the ramp is 4.90 m/s^2.
Question b.
the acceleration of the car down the ramp is 5.42 m/s^2, and the velocity of the car at the top of the ramp is 23.7 m/s.
How do we calculate?We apply Newton's Second Law of Motion, which states that the net force acting on an object is equal to the product of its mass and acceleration:
F_net = m*a
v_f = v_i + at
d = v_it + 0.5at^2
Given values: :
Force F = 13000 N
Angle of incline θ = 30°
Mass of the car m = 1200 kg
we find the component of the force that is parallel to the incline, which will cause the car to move down the ramp:
F_parallel = Fsin(θ) = 13000sin(30°) = 6500 N
we then find acceleration of the car using Newton's Second Law:
F_net = m*a
a = F_net / m
a = F_parallel / m
a = 6500 N / 1200 kg
a = 5.42 m/s^2
we then the velocity of the car at the top of the ramp using the kinematic equations:
v_f^2 = v_i^2 + 2ad
d = 125 m
v_i = 0 (the car starts from rest)
v_f = sqrt(2ad)
v_f = sqrt(25.42 m/s^2125 m)
v_f = 23.7 m/s
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(300-19, Table 300-19(A)) A 100 foot vertical run of No. 4/0 copper requires the conductors to be supported at _____ locations.
According to Table 300-19(A) in the National Electrical Code (NEC), a 100 foot vertical run of No. 4/0 copper conductors requires the conductors to be supported at a minimum of 7 locations.
At least seven support locations are required for a 100 foot vertical run of No. 4/0 copper. The support locations should be spaced no more than 20 feet apart and should be supported with a combination of rigid metal conduit (RMC), intermediate metal conduit (IMC), conduit bodies, or cable trays. In addition, the support locations must be able to support the weight of the conductors as well as any environmental factors, such as wind loading, that could affect the support structure.
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in 2006, pluto was declared a dwarf planet. the three criteria for planethood are: 1.) it orbits the sun 2.) it must be gravitationally rounded 3.) it must have cleared the neighborhood around its orbit what of these criteria is pluto missing?
Pluto is missing the third criterion for planethood which states that 3, it must have cleared the neighborhood around its orbit.
What is the planet Pluto about?Pluto is a dwarf planet in our solar system, located in the Kuiper Belt beyond the orbit of Neptune. It was discovered in 1930 and was considered the ninth planet in our solar system until 2006, when it was reclassified as a dwarf planet due to its size and failure to meet the third criterion for planethood, which states that a planet must have cleared its orbit of other debris.
Pluto has five known moons and is primarily composed of rock and ice. It has a highly elliptical orbit that takes it closer to the sun than Neptune at certain points, but also farther away than any other planet in our solar system.
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a 1000 kg car experiences a net force of 8047 n while decelerating from 30.0 m/s to 23.4 m/s. how far does it travel while slowing down?
The car travels 26.7 meters while slowing down from 30.0 m/s to 23.4 m/s under the net force of 8047 N
We can solve this problem using the equation:
d = ((v_f + v_i)/2) * t
where d is the distance traveled, v_f is the final velocity, v_i is the initial velocity, and t is the time interval.
First, we can calculate the acceleration of the car using the formula:
a = F_net / m
where F_net is the net force acting on the car and m is the mass of the car. Substituting the given values, we get:
a = 8047 N / 1000 kg = 8.047 m/s^2
Next, we can use the formula:
v_f = v_i + a * t
to find the time interval t . Substituting the given values, we get:
23.4 m/s = 30.0 m/s + (-8.047 m/s^2) * t
Solving for t, we get:
t = (23.4 m/s - 30.0 m/s) / (-8.047 m/s^2) = 0.817 s
Finally, we can use the formula for distance to find the distance traveled:
d = ((23.4 m/s + 30.0 m/s) / 2) * 0.817 s = 26.7 m
Therefore, the car travels 26.7 meters while slowing down from 30.0 m/s to 23.4 m/s under the net force of 8047 N.
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To solve this problem, we can use the following equation:
Net force = mass x acceleration
We can rearrange this equation to solve for acceleration:
Acceleration = Net force / mass
Then, we can use the following equation to find the distance traveled:
Distance = (initial velocity + final velocity) / 2 x time
We can solve for time using the following equation:
Final velocity = Initial velocity + acceleration x time
Plugging in the given values, we get:
Acceleration = 8047 N / 1000 kg = 8.047 m/s^2
Final velocity = 23.4 m/s
Initial velocity = 30.0 m/s
Final velocity = Initial velocity + acceleration x time
23.4 m/s = 30.0 m/s + 8.047 m/s^2 x time
Time = (23.4 m/s - 30.0 m/s) / (8.047 m/s^2) = 0.812 s
Distance = (initial velocity + final velocity) / 2 x time
Distance = (30.0 m/s + 23.4 m/s) / 2 x 0.812 s = 21.6 m
Therefore, the car travels 21.6 meters while slowing down.
To find the distance the car travels while decelerating, we can use the work-energy principle. The work done by the net force equals the change in kinetic energy of the car.
First, let's calculate the change in kinetic energy:
ΔKE = 0.5 * m * (v_f² - v_i²)
where m is the mass of the car (1000 kg), v_i is the initial velocity (30.0 m/s), and v_f is the final velocity (23.4 m/s).
ΔKE = 0.5 * 1000 * (23.4² - 30.0²) = -214540 J
Since the car is decelerating, the net force (8047 N) is acting in the opposite direction of its motion. Therefore, the work done by the net force is negative:
W = -F * d
where F is the net force and d is the distance traveled.
Now, we can equate the work done by the net force to the change in kinetic energy and solve for d:
-8047 * d = -214540
d = 214540 / 8047 ≈ 26.66 meters
The car travels approximately 26.66 meters while slowing down.
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Question 44
A potential public health problem associated with reprocessing nuclear fission material is:
a. Volatile radioisotopes are released into the atmosphere
b. Reducing the concentration of U235
c. Converting gas into solid pellets
d. Leaching of wastes into the soil
The correct answer is a. Volatile radioisotopes are released into the atmosphere. Reprocessing nuclear fission material involves the extraction of usable materials, such as plutonium, from spent nuclear fuel.
This process can generate radioactive waste, which must be managed carefully to prevent exposure to humans and the environment.
One potential public health problem associated with reprocessing nuclear fission material is the release of volatile radioisotopes into the atmosphere. These isotopes can be carried by wind and air currents, and can be inhaled by humans or deposited on soil or water sources, causing potential health risks. The risks associated with these isotopes depend on their half-lives and how easily they can be absorbed into the body.
Reducing the concentration of U235, converting gas into solid pellets, and leaching of wastes into the soil are not directly associated with reprocessing nuclear fission material, but rather with other aspects of nuclear power generation and waste management. Therefore, options b, c, and d are incorrect.
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what is the difference between heat and temperature? multiple choice question. temperature is average internal potential energy and heat is the average internal kinetic energy. temperature is the term used in the united states and heat is used in most of the rest of the world; they both measure energy transfers. heat refers only to positive transfers of energy, whereas temperature refers to absolute transfers of energy. temperature is a measure of an object's internal kinetic energy and heat is the energy transferred from one object to another.
It is important to distinguish between the two concepts to understand how energy is transferred and how it affects the properties of different materials.
Heat and temperature are related concepts in thermodynamics. However, they have different meanings and measurements. Temperature refers to the average kinetic energy of molecules within an object or a substance. It is a measure of how hot or cold something is, and it is usually measured in Celsius or Fahrenheit units. Temperature is a property of a single object or substance.
On the other hand, heat refers to the transfer of energy from one object or substance to another. Heat is a form of energy that flows from a hotter object to a cooler one until they reach thermal equilibrium. Heat is measured in Joules or calories, and it is dependent on the temperature, mass, and specific heat capacity of the objects involved in the transfer.
In summary, temperature is a property of a single object or substance that measures the average kinetic energy of its molecules. Heat, on the other hand, is a form of energy that is transferred between objects or substances due to a temperature difference.
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Operators must have unobstructed access to a ladder for escape from a trench within what distance?
a) 15 feet
b) 20 feet
c) 25 feet
d) 30 feet
Operators must have unobstructed access to a ladder for escape from a trench within a distance of 25 feet.
According to OSHA regulations, operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet.
According to OSHA Occupational Safety and Health Administration, employers must provide ladders, steps, ramps, or other safe means of egress for workers working in trench excavations 4 feet 1.22 meters or deeper1. The means of egress must be located so as not to require workers to travel more than 25 feet 7.62 meters laterally within the trench1. Therefore, the answer is c 25 feet. Operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet
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You kick a can. Why does the can and your foot move if the forces are equal and opposite?
the chemical that makes up genetic material
The chemical that makes up genetic material is called nucleic acid. Specifically, DNA deoxyribonucleic acid and RNA ribonucleic acid are the two types of nucleic acids that store and transmit genetic information in living organisms.
What are acids ?Acids are substances that have a pH less than 7 and can donate a hydrogen ion (H+) to a solution. They are characterized by their sour taste and their ability to dissolve metals, react with bases, and change the color of indicators. Acids can be categorized as strong or weak based on their ability to ionize in water. Strong acids ionize completely in water, while weak acids only partially ionize.
What is an ionize ?Ionization refers to the process of converting a neutral atom or molecule into an ion by adding or removing one or more electrons. This can occur through a variety of methods, such as heating, chemical reactions, or exposure to radiation. When an atom loses one or more electrons, it becomes positively charged and is called a cation.
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It takes a physics student 3hrs to travel Toronto to Waterloo at the rate of 96 km/h then takes her 2 hrs to travel back what was the speed on her way back
Answer: 144 km/h
Explanation:
The distance between Toronto and Waterloo is 288 km. The student traveled from Toronto to Waterloo at a speed of 96 km/h, so the total distance traveled is 288 km (96 * 3). The student traveled back from Waterloo to Toronto in 2 hours, so the average speed on the way back is 144 km/h (288 / 2).
However, we cannot know the exact speed on the way back without knowing the student's exact route. If the student took the same route on the way back, then the average speed is 144 km/h. However, if the student took a different route on the way back, then the average speed could be different. For example, if the student took a more direct route on the way back, then the average speed could be higher. If the student took a more scenic route on the way back, then the average speed could be lower.
Therefore, the best answer to the question is that the average speed on the way back is 144 km/h assuming the student took the same route back.
(382-30(A)) Nonmetallic extensions shall be secured in place by approved means at intervals not exceeding _____ inches.
Nonmetallic extensions shall be secured in place by approved means at intervals not exceeding 54 inches.
The National Electrical Code (NEC) sets out guidelines and safety standards for electrical installations in the United States. Section 382-30(A) of the NEC specifies that nonmetallic extensions, which are used to extend electrical conduit or raceways, must be secured in place by approved means at intervals not exceeding 4.5 feet, that is 54 inches.
This means that the extensions must be firmly and securely attached to the wall or ceiling at regular intervals to prevent them from sagging or pulling away from the conduit or raceway. Failure to follow this code requirement can result in unsafe electrical installations that may pose a hazard to people and property.
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if neutrinos oscillated between five different types of neutrino during their transit from the sun to earth, then how many neutrinos would we have detected compared to what was emitted by the sun?
If neutrinos oscillated between five different types of neutrino during their transit from the sun to earth we would detect no neutrinos and would depend on the detection capabilities of our instruments and the specific types of neutrinos we are able to measure.
If neutrinos oscillated between five different types during their transit from the sun to earth, it means that the initial number of emitted neutrinos from the sun would have been spread out across these five different types. So, the number of neutrinos detected on earth would depend on how much oscillation occurred and how much of each type of neutrino was produced by the sun. However, it is estimated that about two-thirds of the emitted neutrinos from the sun are detected on earth, regardless of oscillation. It's important to note that neutrinos oscillate between three known types: electron, muon, and tau neutrinos. If they oscillated between five types, we would expect to detect a different proportion compared to what was emitted by the sun, but the exact number would depend on our ability to detect those specific types.
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Question 11
Perhaps our single most significant source of radiation exposure is:
a. Radon
b. Cosmic radiation
c. Alpha particles
d. Gamma rays
Perhaps our single most significant source of radiation exposure is, (B). Cosmic radiation is correct option.
High-energy particles that come from the universe and have the ability to enter the atmosphere of the Earth are referred to as cosmic radiation. Protons, gamma rays, and other radiation types fall within this category. For people who frequently fly, such as airline crew members and frequent travelers, as well as astronauts who spend a lot of time in space, cosmic radiation is a substantial source of radiation exposure. People who work in environments with greater elevations, such as mountain climbers and pilots, may potentially be exposed to cosmic radiation.
However, based on variables like height, latitude, and solar activity, the exposure to cosmic radiation can differ. Cosmic radiation is regarded as one of the most major sources of radiation exposure, along with radon, alpha particles, and gamma rays.
Therefore, the correct option is (b).
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A plane speeds up to 320m/s from 300m/s in 5 seconds. Assuming the plane was traveling in a straight line, what was it's average acceleration during those 5 seconds.
The calculate the plane's average acceleration, we need to use the formula. average acceleration = final velocity - initial velocity / time the plane's final velocity is 320m/s, its initial velocity is 300m/s, and the time it took to speed up is 5 seconds.
The plane's average acceleration during those 5 seconds was 4m/s^2.To find the average acceleration of the plane during the 5 seconds, you can use the formula. Average acceleration = Final velocity - Initial velocity / Time In this case, the final velocity plane speed is 320 m/s, the initial velocity is 300 m/s, and the time is 5 seconds. Average acceleration = 320 m/s - 300 m/s / 5 Average acceleration = 20 m/s / 5 s Average acceleration = 4 m/s² So, the plane's average acceleration during those 5 seconds was 4 meters per second squared 4 m/s² while traveling in a straight line.
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is the following statement true or false? a block completely submerged in water experiences greater buoyancy force on earth than on mars, because the gravitational acceleration g is greater on earth.
The statement is true because the buoyancy force is directly proportional to gravitational acceleration, and Earth's gravitational acceleration is greater than Mars'.
1. Buoyancy force is given by the formula: F_b = V * ρ * g, where F_b is the buoyancy force, V is the volume of the submerged object, ρ is the density of the fluid, and g is the gravitational acceleration.
2. The volume (V) and density (ρ) of the fluid remain constant for both Earth and Mars, as they are inherent properties of the fluid and object.
3. The gravitational acceleration (g) is greater on Earth than on Mars.
4. Therefore, the buoyancy force (F_b) experienced by a block submerged in water on Earth will be greater than that on Mars due to the greater gravitational acceleration on Earth.
A block submerged in water experiences greater buoyancy force on Earth compared to Mars due to Earth's higher gravitational acceleration.
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The ____ done by a constant force acting on an object is equal to the product of the magnitudes of the displacement and the component of the force parallel to that displacement
The work done by a constant force acting on an object is equal to the product of the magnitudes of the displacement and the component of the force parallel to that displacement.
Work is a measure of energy transfer, and it is calculated as the product of the force applied on an object and the distance over which the force is applied. However, when the force is not applied in the same direction as the object moves, only the component of the force parallel to the displacement of the object will contribute to the work done.
This principle is known as the work-energy theorem and is commonly used in physics to calculate the amount of work done on an object in a particular situation.
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the potential difference v(t) between the parallel plates of a capacitor is instantaneously increasing at a rate of 107 v/s. what is the displacement current (in ma) between the plates if the separation of the plates is 1.21 cm and they have an area of 0.202 m2?
The displacement current between the plates is approximately [tex]1.58557 * 10^{-5} mA[/tex].
To find the displacement current between the parallel plates of a capacitor, we can use the following equation:
Displacement current (I_d) = ε₀ * (dV/dt) * (A/d)
where:
- ε₀ is the vacuum permittivity ([tex]8.85 ** 10^{-12} F/m[/tex])
- dV/dt is the rate of change of potential difference (107 V/s, given in the question)
- A is the area of the plates (0.202 m², given in the question)
- d is the separation of the plates (1.21 cm = 0.0121 m, given in the question)
Now, plug in the values:
I_d = [tex](8.85 *10^{-12} F/m) * (107 V/s) * (0.202 m^2 / 0.0121 m)[/tex]
I_d = [tex]1.58557 * 10^{-8} A[/tex]
To convert this to milliamperes (mA), multiply by 1000:
I_d = [tex]1.58557 * 10^{-5} mA[/tex]
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chlorine disinfection is accomplished in a 1000 foot, 48 inch diameter pipeline at a 4.0 MGD water treatment facility. At the rated capacity of the plant how many minutes of disinfection are provided in this pipeline
At the rated capacity of the water treatment plant, 4.85 minutes of disinfection are provided in the 1000 foot, 48 inch diameter pipeline using chlorine at a dosage of 4 ppm.
To calculate the time of disinfection provided in the pipeline, we need to know the volume of the pipeline and the dosage of chlorine used for disinfection.
Assuming the pipeline is filled to capacity with water, the volume of the pipeline can be calculated using the formula:
Volume = pi x (diameter/2[tex])^2[/tex]x length
Where pi is the constant 3.14, diameter is 48 inches (converted to feet by dividing by 12), and length is 1000 feet.
So, Volume = 3.14 x (48/2)^2 x 1000 = 452,389 cubic feet
To determine the dosage of chlorine, we need to know the concentration of chlorine added to the water. Let's assume a concentration of 4 parts per million (ppm), which is a common dosage for disinfection.
The dosage of chlorine can be calculated using the formula:
Dosage = concentration x volume
Where concentration is 4 ppm (or 0.004 parts per million, since 1 ppm = 0.001 parts per million) and volume is 452,389 cubic feet (converted to gallons by multiplying by 7.48, the number of gallons in a cubic foot).
So, Dosage = 0.004 x 452,389 x 7.48 = 13,478.7 gallons
Now, we need to calculate the time it takes for the water to flow through the pipeline at a rate of 4.0 MGD (million gallons per day). To convert MGD to gallons per minute (GPM), we divide by 1440 (the number of minutes in a day).
So, Flow rate = 4.0 MGD / 1440 = 2,778 GPM
Finally, we can calculate the time of disinfection provided in the pipeline using the formula:
Time = Dosage / Flow rate
Time = 13,478.7 gallons / 2,778 GPM = 4.85 minutes (rounded to two decimal places)
Therefore, at the rated capacity of the water treatment plant, 4.85 minutes of disinfection are provided in the 1000 foot, 48 inch diameter pipeline using chlorine at a dosage of 4 ppm.
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greenhouse gases transmit visible light, allowing it to heat the surface, but then absorb infrared light from the earth's surface, trapping the heat near the surface. true or false
True. Greenhouse gases are gases that can trap heat within the Earth's atmosphere.
They allow visible light to pass through them and reach the Earth's surface.
Once this light reaches the surface, it is absorbed by the land, oceans, and vegetation, causing them to heat up.
However, once the surface has been heated, it begins to radiate heat back into the atmosphere in the form of infrared radiation.
Greenhouse gases such as carbon dioxide, methane, and water vapor are very effective at absorbing this infrared radiation, trapping the heat near the Earth's surface. This is known as the greenhouse effect, and it is the reason why the Earth's average temperature is approximately 15°C (59°F), making it hospitable to life.
However, human activities, particularly the burning of fossil fuels, have increased the levels of greenhouse gases in the atmosphere, which has led to an enhanced greenhouse effect.
This enhanced greenhouse effect has caused the Earth's average temperature to increase, leading to a range of impacts, including rising sea levels, more frequent and severe weather events, and changes in ecosystems.
To address this issue, it is crucial to reduce greenhouse gas emissions and transition towards cleaner, more sustainable energy systems.
This includes measures such as investing in renewable energy, improving energy efficiency, and transitioning away from fossil fuels.
By taking action to reduce greenhouse gas emissions, we can help to protect the planet and ensure a livable future for generations to come.
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3. What is the time constant Ï in s for a circuit with resistance R=1.0 kΩ in series with a capacitance C=1.0 μF?
The time constant (Ï) for a circuit with resistance R and capacitance C is given by the equation Ï = R*C. In this case, R=1.0 kΩ and C=1.0 μF.
Converting the units to SI units (ohms and farads), we get R=1000 ohms and C=1.0*10^-6 farads. Substituting these values into the equation, we get Ï = 1000 ohms * 1.0*10^-6 farads = 1.0 millisecond (ms) or 0.001 seconds (s). Therefore, the time constant for this circuit is 0.001 s.
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6.) A disk and a hoop of the same mass and radius are released at the same time at the top of an inclined plane. If both are uniform, which one reaches the bottom of the incline first if there is no slipping?
A.) The hoop
B.) The disk
C.) Both reach the bottom at the same time
The correct solution to this question here is option C.) Both reach the bottom at the same time.
This is because both the disk and hoop have the same mass and radius, and there is no slipping involved. Therefore, they will have the same acceleration down the inclined plane and will reach the bottom at the same time. B.) The disk
The disk reaches the bottom of the incline first because it has a smaller moment of inertia compared to the hoop. This results in the disk having a greater acceleration down the inclined plane, allowing it to reach the bottom faster than the hoop.
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Why does the quantity of the water in a beaker not matter but the quantity in a polystyrene cup does?
(PLS HELP ILL MARK U BRAINLIEST)
The quantity of water in a beaker or a polystyrene cup does matter, but the reason why it matters is different for each container.
Why does the quantity of water for each container matter?In a beaker, the quantity of water does not affect the temperature of the water significantly because glass is a good conductor of heat, meaning that the heat from the water is evenly distributed throughout the beaker. As a result, the temperature of the water remains relatively stable regardless of the quantity of water in the beaker.
On the other hand, in a polystyrene cup, the quantity of water does matter because polystyrene is a poor conductor of heat, meaning that the heat from the water is not evenly distributed throughout the cup. If there is a small quantity of water in the cup, the heat from the water is concentrated in a small area, causing the temperature to increase rapidly.
This can cause the cup to melt or deform. If there is a large quantity of water in the cup, the heat is distributed over a larger area, reducing the temperature increase.
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If the mass of dry air is 2 kg, the mass of water vapor is 10 g, and the volume of a parcel is 1 m^3, what is the mixing ratio of the parcel? What would the mixing ratio be if the volume were to double>
The mixing ratio of the parcel would remain unchanged at 0.005 even if the volume were to double.
The mixing ratio is defined as the ratio of the mass of water vapor to the mass of dry air in a parcel of air.
Given that the mass of dry air is 2 kg and the mass of water vapor is 10 g, we can convert the mass of water vapor to kilograms by dividing by 1000:
Mass of water vapor = 10 g ÷ 1000 = 0.01 kg
The mixing ratio is therefore:
Mixing ratio = Mass of water vapor ÷ Mass of dry air
Mixing ratio = 0.01 kg ÷ 2 kg
Mixing ratio = 0.005
So the mixing ratio of the parcel is 0.005.
If the volume were to double to 2 m^3, the mass of dry air and water vapor in the parcel would remain the same, but the mixing ratio would change because the mass of dry air per unit volume would decrease.
The new mixing ratio can be calculated as follows:
Mass of dry air per unit volume = Mass of dry air ÷ Volume
Mass of dry air per unit volume = 2 kg ÷ 1 m^3 = 2 kg/m^3
New mixing ratio = Mass of water vapor ÷ Mass of dry air per unit volume
New mixing ratio = 0.01 kg ÷ 2 kg/m^3
New mixing ratio = 0.005
So the mixing ratio of the parcel would remain unchanged at 0.005 even if the volume were to double.
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(382-56) Receptacle type tap connectors for nonmetallic extensions shall be of the _____.
Receptacle type tap connectors for nonmetallic extensions shall be of the twist-lock type.
The National Electrical Code (NEC) requires that receptacle-type tap connectors used with nonmetallic extensions, such as cords or cables, be of the twist-lock type. This is to ensure a secure connection between the plug and receptacle, as well as to prevent accidental disconnection. Twist-lock connectors have a locking mechanism that requires the plug to be twisted and locked into place before it can be energized.
This provides a more reliable and safe connection compared to standard plug connectors that can easily be pulled out or accidentally disconnected. The NEC provides guidelines and requirements for electrical installations to promote safety and minimize the risk of electrical hazards.
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Part awhat is the new orbital speed after friction from the earth's upper atmosphere has done −7. 5×109j of work on the satellite?
The new orbital speed after friction from the Earth's upper atmosphere has done -7.5x[tex]10^{9}[/tex] J of work on the satellite is approximately 7489 m/s.
We can use the work-energy principle to solve this problem. The work done by the atmosphere is equal to the change in kinetic energy of the satellite
W = ΔK
Where W is the work done by the atmosphere and ΔK is the change in kinetic energy. We can find the initial kinetic energy of the satellite using the formula
K = (1/2)m[tex]V^{2}[/tex]
Where m is the mass of the satellite and V is its initial velocity.
Since the problem does not provide the mass of the satellite, we can assume it is constant and cancel it out in the equations. Thus, we can write
W = ΔK = (1/2)m[tex]Vf^{2}[/tex] - (1/2) m[tex]Vi^{2}[/tex]
Where Vf is the final velocity of the satellite and Vi is its initial velocity.
Substituting the given values, we have
-7.5x[tex]10^{9}[/tex] J = (1/2)m[tex]Vf^{2}[/tex] - (1/2) m[tex]Vi^{2}[/tex]
We also know that the initial orbital speed of the satellite is equal to the velocity required for circular motion at its altitude, which can be calculated using the formula
V = √(GM/r)
Where G is the gravitational constant, M is the mass of the Earth, and r is the distance between the satellite and the center of the Earth.
Substituting the given values, we have
Vi = √[(6.67x[tex]10^{-11}[/tex]N[tex]m^{2[/tex]/[tex]Kg^{2}[/tex])(5.97x[tex]10^{24}[/tex] kg)/(6.67x[tex]10^{6}[/tex]m)] = 7646 m/s
Solving for the final velocity, we have
Vf = √[2(-7.5x[tex]10^{9}[/tex] J)/(m) + [tex]Vi^{2}[/tex]]
The mass of the satellite cancels out, and we get
Vf = √(2(-7.5x[tex]10^{9}[/tex] J)/([tex](7646m/s)^{2}[/tex] + [tex](7646m/s)^{2}[/tex] ) ≈ 7489 m/s
Therefore, the new orbital speed after friction from the Earth's upper atmosphere has done -7.5x[tex]10^{9}[/tex] J of work on the satellite is approximately 7489 m/s.
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a wave travels along a stretched horizontal rope. the vertical distance from crest to trough for this wave is 16 cm and the horizontal distance from crest to trough is 28 cm .what is the wavelength of this wave?
The wavelength of the wave can be calculated using the Pythagorean theorem, where the vertical distance from crest to trough represents the height (16 cm) and the horizontal distance from crest to trough represents the base (28 cm) of a right triangle.
Using the formula c² = a² + b², where c is the hypotenuse (or wavelength), a is the height, and b is the base, we can solve for the wavelength:
wavelength² = height² + base²
wavelength² = 16² + 28²
wavelength² = 256 + 784
wavelength² = 1040
Taking the square root of both sides, we get:
wavelength = √1040
wavelength ≈ 32.2 cm
Therefore, the wavelength of the wave traveling along the stretched horizontal rope is approximately 32.2 cm.
The wavelength of a wave traveling along a stretched horizontal rope can be determined using the horizontal distance between consecutive crests or troughs. In this case, the horizontal distance from crest to trough is 28 cm. However, the wavelength is the distance between two consecutive crests (or troughs), which is twice the distance from crest to trough. Therefore, the wavelength of this wave is 2 * 28 cm = 56 cm.
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a heater with a fixed heat flux heats 2 materials (of equal thickness). material a has a thermal conductivity k subscript a and material b has a thermal conductivity k subscript b. if k subscript a less than k subscript b and heat transfer through the wall is 1d conduction, how will the temperature difference across the two sides of each wall at steady state vary?
The Given a heater with a fixed heat flux, we have two materials of equal thickness, with Material A having a thermal conductivity of kea, and Material B having a thermal conductivity of k _b. We know that k _a < k _b, and heat transfer through the wall is one-dimensional conduction.
The steady state, the temperature difference across the two sides of each wall can be determined using Fourier's Law of Heat Conduction = -k * dT/dx Where q is the heat flux, k is the thermal conductivity, dT is the temperature difference, and dx is the thickness of the material. Since the heat flux (q) is fixed and the thickness dx of both materials is equal, we can rearrange the equation to solve for the temperature difference dT across the two sides of each wall dT = -q * dx / k For Material A, the temperature difference dT _a will bed T _a = -(q * dx) / k _a For Material B, the temperature difference dT _b will be dT _b = -q * dx / k _b Since k _a < k _b, we can conclude that'd > dT _b So, at steady-state, the temperature difference across the two sides of Material A will be greater than the temperature difference across the two sides of Material B.
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A ball is tossed with enough speed straight up so that it is in the air several seconds. Assume upward direction is positive and downward is negative.
What is the acceleration of the ball during any of these time intervals?
The acceleration of the ball is -9.8 m/s^2 (downward) during any of these time intervals. This is because the force of gravity is acting on the ball, causing it to accelerate downwards.
Even though the ball is moving upwards initially, its speed will eventually decrease to zero at the top of its trajectory, and then it will begin to fall back down with increasing speed. So, the direction of the acceleration is downwards, and its magnitude is constant at 9.8 m/s^2 (assuming no air resistance).
The acceleration of a ball tossed straight up, we need to consider the terms speed, direction, and acceleration.
The acceleration of the ball during any of these time intervals is determined by the force of gravity acting on it. In this scenario, the only force acting on the ball is gravity, which acts in the downward (negative) direction. The acceleration due to gravity is constant and approximately -9.81 m/s² (negative because it acts downward).
So, the acceleration of the ball during any of these time intervals is -9.81 m/s², acting in the downward (negative) direction.
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