A ring-shaped region is shown below.
Its inner diameter is 14 ft. The width of the ring is 4 ft.
4 ft
14 ft
Find the area of the shaded region.
Use 3.14 for PI. Do not round your answer.
Answers
The area of the ring-shaped shaded region is found to be 650.46 square feet.
The area of the bigger ring minus the area of the smaller ring will give us the area of the shaded region. The radius of the outer circle is,
r = (14 + 4/2) ft = 16 ft
The area of the outer circle is,
A_outer = πr²
= 3.14 x 16²
= 804.32 ft²
The radius of the inner circle is,
r = 14/2 ft
r = 7 ft
The area of the inner circle is,
A_inner = πr²
= 3.14 x 7²
= 153.86 ft²
Therefore, the area of the shaded region is,
A_shaded = A_outer - A_inner
= 804.32 - 153.86
= 650.46 ft²
So the area of the shaded region is 650.46 square feet.
To know more about area of circle, visit,
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Complete question - A ring-shaped region is shown below. Its inner diameter is 14 ft. The width of the ring is 4 ft. Find the area of the shaded region. Use 3.14 for PI. Do not round your answer.
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Step-by-step explanation:
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Answer:
x= −5−11√13/2, −5+11√13/2Solve the equation for x by finding a, b, and c of the quadratic then applying the quadratic formula.
Exact Form:
x= −5−11√13/2, −5+11√13/2
Decimal Form:
x=17.33053201…,
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Step-by-step explanation:
x(x+5)=387
Simplify
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Subtract 387 from both sides of the equation.
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Simplify.
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The result can be shown in multiple forms.
Exact Form:
x=−5−11√13/2,−5+11√13/2
Decimal Form:
x=17.33053201…,
−22.33053201…
Hope it is helpful....Answer:
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General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Equality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityAlgebra I
Standard Form: ax² + bx + c = 0Quadratic Formula: [tex]\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]Step-by-step explanation:
Step 1: Define
x(x + 5) = 387
Step 2: Identify Variables
Rewrite
[Distributive Property] Distribute x: x² + 5x = 387[Subtraction Property of Equality] Subtract 387 on both sides: x² + 5x - 387 = 0Part: a = 1, b = 5, c = -387Step 3: Solve for x
Substitute in variables [Quadratic Formula]: [tex]\displaystyle x=\frac{-5\pm\sqrt{5^2-4(1)(-387)}}{2(1)}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle x=\frac{-5\pm\sqrt{25-4(1)(-387)}}{2(1)}[/tex][√Radical] Multiply: [tex]\displaystyle x=\frac{-5\pm\sqrt{25+1548}}{2(1)}[/tex][√Radical] Add: [tex]\displaystyle x=\frac{-5\pm\sqrt{1573}}{2(1)}[/tex][Fraction - Denominator] Multiply: [tex]\displaystyle x=\frac{-5\pm\sqrt{1573}}{2}[/tex][Fraction - √Radical] Simplify: [tex]\displaystyle x=\frac{-5\pm 11\sqrt{13}}{2}[/tex]what is the area of a square yards of a rectangle with a length of 9 yds and a width of 4 yds?
Answers
[tex]a = lw[/tex]
[tex]a = (9)(4)[/tex]
[tex]a = 36 \: {yds}^{2} [/tex]
Answer:
Here we can understand that the shape is a rectangle as length is not equal to width.
Area of the rectangle in square yards when length is 9 yds and width is 4 yds will be,
Area of Rectangle = LENGTH × WIDTH
⇒ 9*4
⇒ 36 sd yds
Thus the are will be 36 sd yds
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