A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.80 m above. The second student catches the keys 1.80 s later.
a- With what initial velocity were the keys thrown?
magnitude:
direction: up / down
b- What was the velocity of the keys just before they were caught?
magnitude:
direction: up / down
please ,I need the answer very quickly

The right statement for electric field is The potential at points A and B are equal, and the potential at point C is lower than the potential at point A. The correct option to this question is C.

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The missing part of the question have been filled below on Continental drift

In the early part of the 20th century, a German scientist named Alfred Wegener, proposed the theory of continental drift which suggested the continents move and started out in different positions from what they are currently. In the 1960s, scientists discovered the spreading apart of areas of the sea floor. This in turn led to the theory of plate tectonics. The lithosphere is made of plates which float on a "plastic-like" undersurface called the mantle. Where these plates come together at boundaries, changes take place in the crust and its feature.

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The net electric potential at the origin due to the circular arc of charge Q1, and the two particles of charges Q2 and Q3 can be calculated by using the formula for electric potential due to a point charge:

V = (kQ)/r

Where V is the electric potential, k is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), Q is the charge, and r is the distance from the point of charge to the point where we want to calculate the electric potential.

For the circular arc of charge Q1, the electric potential at the origin is:

V1 = (kQ1)/R = (8.99 x 10^9 Nm^2/C^2)(7.21 x 10^-12 C)/(2.00 m) = 1.62 x 10^-2 V

For the particle of charge Q2, the electric potential at the origin is:

V2 = (kQ2)/R = (8.99 x 10^9 Nm^2/C^2)(4.00Q1)/(2.00 m) = 4.00V1 = 6.48 x 10^-2 V

For the particle of charge Q3, the electric potential at the origin is:

V3 = (kQ3)/R = (8.99 x 10^9 Nm^2/C^2)(-2.00Q1)/(2.00 m) = -2.00V1 = -3.24 x 10^-2 V

The net electric potential at the origin is the sum of the electric potentials due to each charge:

Vnet = V1 + V2 + V3 = 1.62 x 10^-2  V  + 6.48 x 10^-2  V  - 3.24 x 10^-2  V

Vnet = 4.86 x 10^-2 V

Therefore, the net electric potential at the origin due to the circular arc of charge Q1 and the two particles of charges Q2 and Q3 is 4.86 x 10^-2 V.

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Answer:

The change in momentum of an object is equal to the impulse applied to it. Impulse is the product of force and time, or J = FΔt.

In this case, the force acting on the rocket is 500 N, and the time it is applied is 600 s, so the impulse is:

J = FΔt = (500 N) * (600 s) = 300000 Ns

The impulse applied to the rocket causes a change in momentum, which is given by the formula:

Δp = J

So the change in momentum of the rocket is 300000 Ns.

Answer:

Explanation: Kinetic energy generated = work done by force = force x displacement

= 3 x 7 = 21 J

can i get brainlest pls (:

When Terry kicks a soccer ball that is sitting motionless on the field, the energy transfer that occurs is from Terry's foot to the soccer ball. The transfer of energy can be described as kinetic energy, which is the energy an object possesses due to its motion.

Kinetic energy is the energy that an object possesses due to its motion. It is defined as the energy an object has because of its mass and velocity.

Here,
With the ball being set in motion. This transfer of energy can be described as a transfer of kinetic energy. As the ball moves, it gains kinetic energy, which is the energy an object possesses by virtue of its motion. At the same time, Terry's foot loses kinetic energy. This is due to the conservation of energy, which states that energy can neither be created nor destroyed, only transferred or converted from one form to another. In this case, the energy that was initially in Terry's foot has been transferred to the ball in the form of kinetic energy, causing the ball to move.

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The amount of work required to stretch the spring from 1 m to 1.2 m is 40 J.

The work required to stretch the spring from 1 m to 1.1 m is 10 J.

The work required by spring is given by Hooke's Law,

W = ∫ Fdx

Here, F = kx , where k = spring constant.

W = ∫ kxdx

W = ∫ kxdx, where lower limit = 0 and upper limit = 0.1.

W = k×(x²)/2,

On evaluating the value of k,

k = 2W/0.01

k = 2000

For stretching the string from 1 m to 1.2 m,

W = ∫ kxdx

W = k∫x²/2

On substituting values of x,

W = {2000×[(0.2)² - (0)²]}/2

W = 40 J

Hence, The work required to stretch the spring from 1m to 1.2 m is 40 J.

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The answers to the questions are given in parts respectively.

Part A
The distance between nodes is given by the wavelength of the standing wave, which can be found using the equation:

λ = 2π/k

Where k is the wave number, given by:

k = 0.60

Plugging this into the equation for λ gives:

λ = 2π/0.60

λ = 10.47 cm

Therefore, the distance between nodes is 10.47 cm.

Part B
The amplitude of each of the component waves is given by the coefficient of the sine or cosine term in the equation for the displacement of the standing wave. In this case, the amplitude of each of the component waves is 3.6 cm.

Part C
The frequency of each of the component waves is given by the coefficient of the time term in the equation for the displacement of the standing wave. In this case, the frequency of each of the component waves is 48 Hz.

Part D
The speed of each of the component waves can be found using the equation:

v = λf

Where λ is the wavelength and f is the frequency. Plugging in the values for λ and f from Parts A and C gives:

v = (10.47 cm)(48 Hz)

v = 502.56 cm/s

Therefore, the speed of each of the component waves is 502.56 cm/s.

Part E
The speed of a particle of the string at a given position and time can be found by taking the derivative of the displacement equation with respect to time. This gives:

v = -3.6sin(0.60x)(48)sin(48t)

Plugging in the values for x and t gives:

v = -3.6sin(0.60(3.00 cm))(48)sin(48(2.2 s))

v = -3.6sin(1.8)(48)sin(105.6)

v = -164.81 cm/s

Therefore, the speed of a particle of the string at x=3.00 cm when t=2.2 s is -164.81 cm/s.

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Answer:

Below

Explanation:

Total mass = ( 50 + 7 + 4)  = 61 kg

    momentum = m * v

                        = 61 kg * 3 m/s = 183 kg m/s

The partial pressures of heptane is zero

The balanced chemical equation for the reaction between heptane and oxygen is:

C7H16 + 11O2 → 7CO2 + 8H2O

From the equation, we can see that for every mole of heptane that reacts, we need 11 moles of oxygen. Therefore, if we mix heptane and oxygen in the correct stoichiometric ratio, all the heptane will react, and none will be left over. This means that the partial pressure of heptane in the mixture will be zero.

The total pressure of the mixture is given as 300 mmHg. According to Dalton's law of partial pressures, the total pressure of a mixture of gases is equal to the sum of the partial pressures of the individual gases in the mixture. Therefore, if the partial pressure of heptane is zero

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The resultant force that water exerts on the overhang sea wall along abc is 179 kN.

Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.

Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.

(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.

Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,

Aabefa=1.5m(2.5m)=3.75m2and

2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,

Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N

Therefore,

Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN

FR²   =(Fbc)²H2+[Fab+(Fbc)v]²

==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]

=178.6(10³)N = 179 kN.

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I'm sorry, but I would need more information about the lab 3 part v requirement to provide an accurate answer to this question. Please provide more context or details about the lab and the requirements for part v.

The next most successful graft type and what is the source of killer t cells and macrophages energy. if Assuming that autografts and isografts are not possible.

CCR2− macrophages are largely derived from embryonic progenitors, including contributions from yolk sac macrophages, and are primarily autonomous from blood monocytes. energy, in physics, is the capacity to do work.  In contrast, resident cardiac CCR2+ macrophages are derived entirely from definitive HSCs and are replaced slowly by blood monocytes.

energy is the ability to do work. T cells and macrophages appear in the urine of patients with glomerulonephritis (GN), accompanied by active cellular infiltration such as cellular crescent formation and diffuse interstitial cell infiltration, but not in the urine of patients with GN without the active inflammatory lesions.

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At a height of 4.48 meters, a rock's kinetic energy is twice its potential energy.

Potential energy is the energy stored in any object or system due to the position or arrangement of its parts. It is, however, unaffected by factors outside of the object or system, such as air or height. Kinetic energy, on the other hand, is the energy of moving particles in an object or system.

Given that a 6.0-kg rock is dropped from a height of 9.0 m.

Calculate the total potential energy at the initial point,

PE = mgh

PE = 6 x 9.81 x 9

PE = 530.74 J

At the zero height, the kinetic energy will be maximum and is equal to the total energy,

KE = 530.75 J

1/2 mv² = 530.75

v² = 175.85

The height at which the kinetic energy is two times the potential energy is calculated as:-

1 /2 x mv² = 2 x mgh

h = ( 4 v²) / ( 4 x 9.81 )

h = 4 ( 175.82 ) / ( 4 x 9.81 )

h = 4.48 meters

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Studying physics can be challenging, but there are several strategies that can help you learn the subject more effectively. Here are some tips:

1. Review and understand the basics: Physics builds on foundational concepts, so it's essential to have a solid grasp of the basics before moving on to more complex material.

2. Practice problem-solving: Physics is all about solving problems, so practice is key. Work through as many problems as you can, and use a variety of resources such as textbooks, problem sets, and online resources.

Create study groups: Studying with others can be a great way to learn physics. Discussing concepts, working through problems, and teaching each other can help reinforce learning.

4. Seek help when needed: Physics can be challenging, and it's okay to ask for help. Seek assistance from your teacher, tutor, or study group when you are struggling with a concept or problem.

5. Use visual aids: Physics often deals with abstract concepts, so using visual aids such as diagrams, graphs, and videos can help to make the material more concrete and easier to understand.

6. Stay organized: Keep track of assignments, due dates, and notes in an organized way to avoid confusion and ensure that you don't fall behind.

7. Stay curious: Physics can be a fascinating subject, and cultivating a genuine interest in the subject can help motivate you to learn more and understand it better.

The parent should push vertically downward at a distance of 4.66 m from the pivot point in order to hold teeter-totter level.

Force can be a push or a pull that is always with magnitude and direction.

As, Fp × x - Mg × d - mc × (L - x) = 0

Fp is force applied by the parent, x is distance from the pivot point to the point where the parent applies force, Mg is weight of the teeter-totter, mc is the weight of the child, and L is length of the teeter-totter.

Fp × x - (38 kg × 9.81 m/s²) × 2.6 m - (19 kg × 9.81 m/s²) × (5.2 m - x) = 0

Fp × x - 976.68 N × m - 185.58 N × m + 183.39 N × m = 0

Fp × x = 978.87 N × m

x = 978.87 N × m / Fp

So, x = 978.87 N × m / 210 N = 4.66 m

Therefore, the parent should push vertically downward at a distance of 4.66 m from the pivot point in order to hold the teeter-totter level.

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Answer:When the speed of an object stays at the same speed

Explanation:

Answer:

•,¸,.·'｡◕ ᴗ ◕｡'·.,¸,•When the speed of an object remains the same - it does not increase or decrease - we say it is moving at a constant speed. constant speed.

The spaceship undergoes an instantaneous change in velocity at point A and then undergoes a continuous change in velocity at point B until it reaches point C. The trajectory of the spaceship is therefore curved and can be represented by one of the given options.

What is Instantaneous Velocity?

Instantaneous velocity is the velocity of an object at a specific moment in time or at a specific point in its motion. It is the limit of the average velocity as the time interval over which it is calculated approaches zero. In other words, it is the slope of the tangent to the position-time graph at a particular point.

To calculate the instantaneous velocity of an object, you need to determine the object's position at a specific moment in time and then take the derivative of the position function with respect to time. The resulting derivative gives you the object's instantaneous velocity at that specific moment in time.

Instantaneous velocity is important in physics and many other fields because it allows us to understand the behavior of objects in motion and to calculate important quantities such as acceleration, momentum, and energy.

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When light encounters an obstacle such as a wall, it can be either absorbed, transmitted, reflected, or refracted. The way in which light is blocked depends on the characteristics of the obstacle and the properties of the light.

For example, a solid object such as a wall absorbs light, meaning that the energy of the light is transferred to the object, causing the object to heat up. This can result in the object becoming warmer, such as a wall or floor in direct sunlight, or it can result in the object changing its chemical properties, such as with photosensitive materials like photographic film.

Reflection occurs when light bounces off an object, changing the direction of the light. This can result in a mirror image or a diffuse reflection, depending on the characteristics of the object.

Refraction occurs when light passes through an object, changing the direction of the light. This can occur when light passes through transparent materials such as water or glass.

Finally, light can also be blocked by scattering, which occurs when light is dispersed in many different directions as it encounters small particles in the atmosphere, such as dust or water droplets. This is why the sky appears blue during the day, as the shorter blue wavelengths of light are scattered more than the longer wavelengths of red and orange light.

The density of the object is:

rho object = m / V = 300 / 720 = [tex]0.4167 kg/m^3[/tex]

When an object is immersed in liquid, it appears to lose weight equal to the weight of the liquid displaced. Apparent weight loss is caused by an upwardly acting buoyant force that balances the weight of the object.

This problem can be solved using Archimedes' principle that the buoyant force on an object is equal to the weight of the liquid displaced by the object.

First, let's calculate the volume of the object. An object in air weighs 300 N. When immersed in water, the weight is reduced to 262 N. This means that the buoyant force acting on the object is 300 - 262 = 38 N.

Buoyancy is equal to the weight of water displaced by an object. Therefore, the volume of the object is:

[tex]V = m\ water / rho\ water = F\ buoyant / g / rho\ water[/tex]

where m water is the mass of water displaced by the object, rho water is the density of the water, F buoyancy is the buoyant force acting on the object, and g is the acceleration is respect of gravity.

Inserting the given value will result in:

[tex]V = 38 / 9.81 / 1000 = 0.00387 m^3[/tex]

Now let's calculate the density of an object when submerged in oil.

The object immersed in oil weighs 273 N. The buoyant force acting is:

F buoyancy = 300 - 273 = 27 N

The buoyant force is same to the weight of oil displaced by the object. So the volume of the object is:

V = m oil / rho oil = F buoyant / g / rho oil

where m oil is the mass of oil displaced by the object, rho oil is the density of the oil, F is the buoyant force acting on the object, and g is the acceleration due to gravity.

Inserting the given value will result in:

V = 27 / 9.81 / rho oil

We know that the volume of this object is 0.00387 [tex]m^3[/tex]. After inserting this value:

0.00387 = 27 / 9.81 / low oil

Solving Rho Oil gives:

Rho oil = 720 kg/

So the object density is:

Raw object = m / V = ​​300 / 720 =

0.4167/[tex]m^3[/tex]

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Answer:

None of the above.

Mass = Mass / Volume * Volume

W(eight) = Mass * 9.80 m/s^2 = Mass * Acceleration due to gravity

One needs to know specific values to make required comparisons.

None of the statements can be determined weighs as true without additional information.

The gravitational force pulls any two things in the cosmos, regardless of whether their masses are equal or not.

The weight of an object depends on its mass and the gravitational force acting on it. Therefore, if two objects have different weights, it does not necessarily mean that one object has a greater volume or weight density than the other.

For example, object A could be made of a denser material than object B, even though it weighs more, so it would occupy less volume. Similarly, object A could have a lower volume but a greater weight density than object B. Specific gravity also depends on the density of the object and the density of the reference material, so it cannot be determined without additional information.

Therefore, none of the statements can be determined as true without additional information.

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Answer:

1.73 x 10-7 N

Explanation:

3. What is the electrostatic force of attraction between a -5.8 x 10-7C charge and a 3.8 x 10-8C charge if they are separated by a distance of 4.4 meters?​

The electrostatic force of attraction between two charges can be calculated using Coulomb's law, which states that the force of attraction is inversely proportional to the square of the distance between them. In this case, the two charges are -5.8 x 10-7C and 3.8 x 10-8C and they are separated by a distance of 4.4 meters. Plugging these values into Coulomb's law, the electrostatic force of attraction is 1.73 x 10-7 N.

Answer:

Viscosity is the state of being thick, sticky, and semifluid, because of friction. A example is honey or syrup.

The turbine generates approximately 781.78 kW of power in a 14 m/s wind.

The power generated by a wind turbine is directly proportional to the cube of the wind speed. Therefore, we can write:

p ∝ [tex]v^3[/tex]

where "p" is the power generated in kilowatts (kW) and "v" is the wind speed in meters per second (m/s). We can also introduce a constant of proportionality "k" to get:

p = k [tex]v^3[/tex]

To find the value of "k", we can use the given information that the turbine generates 600 kW in a 13 m/s wind. Thus:

600 = k x [tex]13^3[/tex]

Solving for "k", we get:

k = 600 / [tex]13^3[/tex]

k = 0.270270...

Now we can use this value of "k" to find the power generated by the turbine in a 14 m/s wind. Thus:

p = 0.270270... x [tex]14^3[/tex]

p ≈ 781.78 kW

Therefore, the turbine generates approximately 781.78 kW of power in a 14 m/s wind.

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The required speed limit on a highway in lower slovakia is 20,000 furlongs per fortnight. And its value in miles per hour is 44.64 miles per hour.

The speed limit is given as 120000 furlongs per fortnight.

1 furlong is given as 1/8 miles.

120000 furlongs is equal to 120000/8 = 15000 miles per fortnight

Let us convert miles per fortnight to miles per hour.

1 fortnight is known to be 14 days

1 day = 24 hours

14 day = 24 × 14 = 336 hours

15000 miles per fortnight = 15000/336 = 44.64 miles per hour

Thus, 120,000 furlongs per fortnight is nothing but 44.64 miles per hour.

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The distance the block will move to have a kinetic energy of 57 J is 8.14 meters.

The work is defined as the amount of energy. The work in physics is the product of the force and the displacement.

Given that a 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. The total kinetic energy possessed by the block is 57 J.

The distance will be calculated as:-

W = F x D

W = 7 x 2

W = 14 J

The distance is,

W₁ / W₁ = D₂ / D₁

14 / 57 = 2 / D₂

D₂ = ( 57 x 2 ) / 14

D₂ = 8.14 meters

Therefore, the distance the block will move to have a kinetic energy of 57 J is 8.14 meters.

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The force is an external agent which is capable of changing a body's state of rest or motion. The acceleration due to gravity is 12.5 m/s².

The push or pull on an object with mass causes it to changes its velocity is defined as the force. The direction towards which the force is applied is called the direction of the force and the application of the force is the point where force is applied.

The SI unit of force is Newton. The equation which connects the force with mass and acceleration is given by:

F = ma

Total mass = 5 + 4 + 7 = 16

a = F / m

= 200 / 16

= 12.5 m/s²

Thus the acceleration of the system is 12.5 m/s².

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