A tool box has the dimensions of 8 in by 5 in by 4 in. If Danny plans to double all three dimensions to build a larger tool box, he believes he would double the volume of the tool box. Is he correct? 1) Is Danny correct about doubling all three dimensions to build the larger tool box? Why or why not? :) Is Danny correct about doubling all three dimensions? If he doubles all three dimensions, the new volume will be the volume of the original tool box. Yes less than double exactly double No more than double​

a. The median is 70, the mode is 60, and the mean is 70.8.

b. Mean best captures the data.

c. When there are outliers, the mean might be a deceptive center measure.

Calculating the Mean, Median, and Mode

Mean: Total number of sunglasses / total quantity of pries

Mean = (20 + 20 + 50 + 50 + 50 + 60 + 60 + 60 + 60 + 60 + 60 + 70 + 70 + 70 + 80 + 80 + 80 + 80 + 90 + 90 + 90 + 90 + 100 + 100 + 130) / 25

Mean = 70.8

Median is equal to the (n/2 + 1)th term.

The number of sunglasses in this case is n.

(25/2 + 1)th term as the median

Median = 13th term

Median is 70

Mode is  the most frequent data

Therefore, mode = 70

Why is mean the most appropriate central measure ?

The mean is often the ideal measure of central tendency to use when your data distribution is continuous and symmetrical, such as when your data are normally distributed. So, mean here denotes the typical cost of the sunglasses.

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Answer:

Step-by-step explanation:

Answer:

Original equation:

y = a sin(b(θ -c)) + d

a = vertical dilation (stretch) of the amplitude

b = horizontal compression (shrink) of the period

c = horizontal shift (left/right)

d = vertical shift (up/down)

Your function is:

y = 3 sin(3θ + π) - 2

First, put it into the general from by factoring out the three in the argument of the sine:

y = 3 sin(3(θ + π/3)) - 2

a = vertical (amplitude) dilation = 3

b = horizontal (period) compression = 2π/period = 3

c = horizontal shift = π/3 to the left

d = vertical shift = -2

Collect data on a representative selection of patients for two weeks.

is the best data collection plan for this project.

According to the statement

we have a given that the surgical unit that receives 87 new patients per week.

and we have to tell the data plan to collect the baseline data before testing your change to control the pain across the unit.

And We know that the Data collection is A representative sample is one technique that can be used for obtaining insights and observations about a targeted population group

So,

Collecting data on a representative portion of your population — that is, sampling — allows you to collect baseline data and start making improvements faster, using fewer resources, than would be possible if you tried to look at every patient. Baseline data is important so that you can see if the changes you are testing are leading to improvement. Collecting data about a non representative sample of your population, such as by looking only at patients with the most severe pain, won't show the broad impact of your project on your unit.

So, Collect data on a representative selection of patients for two weeks.

is the best data collection plan for this project.

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Disclaimer: This question is incomplete. Please read the full content below.

Question:

You work on a surgical unit that receives 87 new patients per week. In your spare time, you are trying to improve pain control across the unit. As you prepare to collect your baseline data before testing your change, you consider your plan to gather this information. Which of the following would be the best data collection plan for this project, and why?

(A) Collect data on the pain level of every patient for at least a year.

(B) Collect data for at least a year, focusing only on patients who have undergone especially painful surgeries.

(C) Collect data on a representative selection of patients for two weeks.

(D) There is no reason to collect baseline data.

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Answer:

Step-by-step explanation:  use a square bracket [ when the set includes the endpoint and a parenthesis ( to indicate that the endpoint is either not included or the interval is unbounded.

Answer:

Step-by-step explanation:

Find the roots of x^2-25=0 by solving for x.

Add 25 to both sides

x^2=25

Square root both sides

x=-5

x=5

Answer:

x=5;x=-5

Step-by-step explanation:

It was right for me

Answer:

680

Step-by-step explanation:

Use elimination

(1)×5 and (2)×4

(3)-(4)

Putting in eq(1)

x + 4y = 16 __(1)

3x + 5y = 27 __(2)

Multiply the 1st equation by 3

3x + 12y = 48 __(3)

Solving (2) and (3)

3x + 12y = 48

3x + 5y = 27

__________

(-) (-) (-)

7y = 21

So, y = 3

By, putting the value of y = 3 in equation 1

x + 4(3) = 16

x + 12 = 16

x = 16 - 12

x = 4

The value of x = 4 and y = 3

Hope it helps you any confusions you may ask!

A random samples of ticket prices for concerts and the random samples of Coldplay ticket prices are independent . The answer is True.

According to the questions,

A random samples of ticket prices for concerts by the Rolling Stones was obtained. For comparison purposes another random samples of Coldplay ticket prices was obtained.

The two groups of data are independent samples.

Hence, a random samples of ticket prices for concerts and the random samples of Coldplay ticket prices are independent . The answer is True.

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The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

[tex]tan( \theta) = \frac{opposite}{adjacent} [/tex]

[tex]tan( 61 ^{ \circ}) = \frac{553.3}{ Vic' s\: distance \: to \: tower} [/tex]

[tex]distance = \frac{553.3}{tan ( {61}^{ \circ} )} = 306.7[/tex]

Similarly, we have;

[tex] Dan's distance = \frac{553.3}{tan ( {72}^{ \circ} )} = 179.8[/tex]

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan d is found as follows;

Therefore;

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A = 7M is the equation that might be used to find the unknown side length, M, of the rectangular logo.

We can determine the following details from the query:

Logo= rectangle with a

Length ,L= 7-foot

'A' stands for the logo's area, and 'M' for the side that isn't recognized.

The rectangle's area (A) is computed using:

A = L*W

⇒A = 7*M

(As per query, length, L=7 & W= M)

Consequently, the formula 'A = 7M' might be used to calculate the logo's undetermined side length, M.

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Answer:

Option A.

Step-by-step explanation:

Demonstration

[tex]y=\frac{7}{4} x+7[/tex]

for x = -4

[tex]y=\frac{7}{4} (-4)+7=-\frac{28}{4} +7=-7+7=0[/tex]

for x= 0

[tex]y=\frac{7}{4}(0) +7=0+7=7[/tex]

for x= 4

[tex]y=\frac{7}{4} (4)+7=\frac{28}{4} +7=7+7=14[/tex]

Hope this helps

See below for the solution of each question

The points are given as:

(3,60) and (5, 80)

The equation is calculated as:

[tex]C(n) = \frac{C_2 -C_1}{n_2 -n_1} * (n - n_1) + C_1[/tex]

This gives

[tex]C(n) = \frac{80- 60}{5-3} * (n - 3) + 60[/tex]

Evaluate the quotient

C(n) = 10 * (n - 3) + 60

Expand

C(n) = 10n - 30 + 60

Evaluate

C(n) = 10n + 30

Hence, the relation of total cost, C, and number of hours, n is C(n) = 10n + 30

The point (3, 60) means he paid $60 for 3 hours

Here, we have:
Fixed = $10

Hourly rate = $15

The equation is calculated as:

C(n) = Fixed + Rate * Number of hours

This gives

C(n) = 10 + 15n

Hence, the relation of total cost, C, and number of hours, n is C(n) = 10 + 15n

The equation is represented as:

C(n) = 10 + 15n

See attachment for the graph

This is the point where the two lines intersect.

From the graph, we have the point of intersection to be:

(n, C(n)) = (4, 70)

This means that the charges for Comput-Repair and Data-Fix are the same after 4 hours

Based on the point of intersection, it is best that Jargit uses Compu-Repair because they have a lesser hourly rate

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Find fog

For real range the domain

Domain is [5,oo)

The parameters of the sinusoidal function graphs can be found from the coordinates of the given locations.

First graph;

a. Amplitude = 0.5

b. The period = 2•π

c. The horizontal shift = 1

d. The vertical shift = π/4

Second graph;

a. Amplitude = 2

b. The period = π

c. The horizontal shift = -π/4

d. The vertical shift = -2

First graph;

a. The amplitude is half the distance between the y-value peak point and the y-value of a throw (lowest point) on the graph.

The coordinate of a peak point in the first graph is (0, -1.5)

The coordinate of a throw point is (π/2, -2.5)

Therefore;

Amplitude = (-1.5 - (-2.5)) ÷ 2 = 0.5

b. The period is the number of cycles per second, we have;

From the graph, we have;

Therefore;

The frequency = 1/π cycle per unit length

c. The horizontal shift is the distance from the closet intersection of the midline and the rising region of the graph and the y-axis.

Therefore;

The horizontal shift = (-π/2)/2 = -π/4

d. The vertical shift is the distance from the horizontal axis to the midline of the graph.

By observation, the midline is y = -2

Therefore;

Second Graph;

For the second graph, we have;

a. Amplitude = (3 - (-1))/2 = 2

b. Frequency = 1/(2×(5•π/4 - π/4)) = 1/(2•π)

Therefore;

c. Horizontal shift = Distance between x-coordinate of the intersection of the midline and the graph and the x-coordinate of the closest peak.

Therefore;

d. Vertical shift = (3 + (-1))/2 = 1

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Factorize the numerator and denominator. You'll see that they both have a factor of 4 that can be canceled. The introduce a factor of 3 to change the denominator to 36.

[tex]\dfrac{28}{48} = \dfrac{4\times7}{4\times12} = \dfrac7{12} = \dfrac{3\times7}{3\times12} = \boxed{\dfrac{21}{36}}[/tex]

P ( work/ senior ) = 0.14

The attached table

required

P ( work/ senior )

This is calculated using:

P ( work/ senior ) = n ( work/ senior )/ n ( senior ).

n ( work/ senior ) = 5

n ( senior ) = 25 + 5 + = 35

So:

P ( work/ senior ) = 5/35

P ( work/ senior ) = 0.14

Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

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The total number of students in the school is calculated as; 600 students

Usually, some figures are expressed as a fraction of a whole as depicted in this case. Thus, when we are given a fraction of a whole to be equal to a particular figure, we will just cross multiply to get the total number.

We are told that;

Number of students that play a team sport at Lincoln high school = 225

Now, we are told that the number above represents a fraction of 3/8 of the total students in that school.

Thus, if the total number of students in the school is x, then we can say that;

(3/8)x = 225

Multiply both sides by 8 to get;

3x = 1800

x = 1800/3

x = 600 students

Thus, we can conclude that if two hundred and twenty five students play a team sport at Lincoln high school and these students represent 3/8 of the total, then we can say that the total number of students in the school is 600 students.

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Mathew's speed of 100 m/min, and the distance of 10 m. east to which he is blown by the wind gives the angle in degrees Mathew is blown off his path as approximately 2.86°.

The given parameters are;

Speed at which Mathew is flying = 100 m/min

Distance and direction in which the strong wind blows him = 10 m. east

Time it takes the wind to deflect Mathew by 10 m. = 2 minutes

Therefore;

Speed and direction of the wind = 10/2 m/min east

Speed and direction of the wind = 5 m/min east

Mathew's flight path can be represented using a vector diagram (please see attached drawing)

Distance Mathew travels in 2 minutes = 100 m/min × 2 minutes = 200 m.

Tangent of the angle by which Mathew is off his flight path, A, can be found as follows;

tan(A) = 10/200 = 1/20

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Answer:

Step-by-step explanation:

hello :

P(E and F)=0.7×0.6 =0.42

The length of the measure of YZ is 80cm

Perpendicular lines are lines that are at angle 90 degrees to each other. From the given diagram;

WX = 82cm

Required

Length. of YZ

Using the pythagoras theorem

YV = VZ = √41²-9²

YV = VZ = √1600

YV = VZ = 40

Since YZ = YV + VZ

YZ = 40cm + 40cm

YZ= 80cm

Hence the length of the measure of YZ is 80cm

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Answer:

-3/2

Step-by-step explanation:

Slope=rise/run

Pick any 2 points and you can see that for every increase in 2 increases for x, there are 3 decreases for y.

The solution of the system of equations contains one point

The system is given as:

x + y = 6

x - y = 0

Add both equations

2x = 6

Divide by 2

x = 3

Substitute x = 3 in x - y = 0

3 - y = 0

Solve for y

y = 3

So, we have x =3 and y = 3

Hence, the solution of the system of equations contains one point

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Stronger evidence against the null hypothesis is indicated by: smaller p-values.

A statistical conjecture known as a null hypothesis asserts that certain features of a population or data-generating process are not different from one another.

A mechanism to reject the null hypothesis with a predetermined level of confidence is provided by hypothesis testing.

The alternative hypothesis is supported if the null hypothesis can be rejected.

The foundation of the scientific falsification principle is null hypothesis testing. The null hypothesis presupposes that any variation in the selected characteristics you observe in a set of data is the result of chance.

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One landscaper's hourly rate is $15 lower than the other landscaper's. Casey is deciding which of two landscapers to hire. Each landscaper charges an hourly rate plus a fee for each job.

What is system of linear equations?

A set of two linear equations with two variables is a system of linear equations. Casey is deciding between hiring one of two landscapers. Each landscaper bills a fee for each job in addition to an hourly rate. A set of linear equations was appropriately written and solved by Casey using substitution. He solved for the other variable and substituted an expression for one in his work. The intersection of the lines that represent the linear equations is where a system of linear equations finds its solution. Each landscaper bills a fee for each job in addition to an hourly cost. Casey produced a system of linear equations that was correctly written and solved. The hourly rates for both landscapers are the same, however their rates for individual jobs vary.

Casey is deciding between hiring one of two landscapers. Each landscaper bills a fee for each job in addition to an hourly cost. By using substitution, Casey created and properly figured out a set of linear equations. He solved for the other variable and replaced an expression for one in his work, producing the equation 5 = 20.

equation 5=20

20-5 = 15

Therefore, One landscaper's hourly rate is $15 lower than the other landscaper's.

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The true statements are :

the average monthly temperatures of New Orleans are not as varied as that of Indianapolis.

The median of the average monthly temperatures of New Orleans is equal to the upper quartile of the average monthly temperature of Indianapolis.

A box plot is used to study the distribution and level of a set of scores. The box plot consists whiskers. The whiskers represents the minimum and maximum scores.

On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median.  The third line on the box represents the upper (third) quartile.

Range for New Orleans = 85 - 50 = 35

Range for Indianapolis = 75 - 25 = 50

Median for New Orleans = 70

Upper quartile for  Indianapolis = 70

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Let [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex] be the nonzero rows of [tex]$R$[/tex] starting from the 1st row to the [tex]k[/tex]th row.

Step 1: We want to show that

R(R)= span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]

For any vector [tex]v $$\in \mathcal{R}(R)$$[/tex], We may write

v= [tex]$$c_{1} \boldsymbol{r}_{1}+c_{2} \boldsymbol{r}_{2}+\cdots+c_{k} \boldsymbol{r}_{k}+c_{k+1} \mathbf{0}+\cdots+c_{m} \mathbf{0}$$[/tex]

Then v= [tex]$$c_{1} r_{1}+c_{2} r_{2}+\cdots+c_{k} r_{k}$$[/tex]

So [tex]v[/tex] belongs to span{ [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]}

Thus R(R)[tex]\leq[/tex] Span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]

But trivially,

span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]≤ span{[tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex], 0, . . . , 0} = R(R),

span [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]=R(R)

Step 2: We want to show that  [tex]$\boldsymbol{r}_{1}, \ldots, \boldsymbol{r}_{k}$[/tex]are linearly independent. Suppose otherwise,

then we can write

[tex]$$c_{1} \boldsymbol{r}_{i_{1}}+\cdots+c_{\ell} \boldsymbol{r}_{i_{\ell}}=\mathbf{0}$$[/tex]

From Steps 1 and 2, we have proven that the nonzero rows of R form a basis for the row space.

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Answer:

B. (-6)(-6)

Step-by-step explanation:

-  X - = +

and 6 x 6 = 36.

Answer:

It is the first graph

Step-by-step explanation:

The line under the > and < sign means that it must include the 3 and the 0.  The closed circle is showing that the 3 and 0 or included.

Answer:

Rectangular Prism

Step-by-step explanation:

We usually see building shaped as a 3D rectangle. If this is the type of building you are talking about, we use a rectangular prism in order to build the building with correct measurements.