Hi! To calculate the frequency of a tsunami with a speed of 750 km/h and a wavelength of 500 km, you can use the formula:
Frequency (f) = Wave speed (v) / Wavelength (λ)
First, you need to convert the speed and wavelength to the same units. We'll convert them to meters and seconds:
Speed: 750 km/h * 1000 m/km * (1/3600) h/s = 208.33 m/s
Wavelength: 500 km * 1000 m/km = 500,000 m
Now, plug in the values into the formula:
Frequency (f) = 208.33 m/s / 500,000 m
Frequency (f) ≈ 0.00041667 Hz
The frequency of such a tsunami wave is approximately 0.00041667 Hz.
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The kinetic friction force that a horizontal surface exerts on a 60.0-kg object is 50.0 n. if the initial speed of the object is 25.0 m/s, what distance will it slide before coming to a stop?
Answer:
KE = 1/2 M v^2
KE = 60/2 * 25^2 = 18750 Joules initial Kinetic Energy
W = Fs * d distance thru which friction acts
d = W / Fs = 18750 J / 50 N = 375 m
A speed is a scalar physical quantity. Why?
Answer:
A speed is a scalar quantity because it only has magnitude.
Answer:
what is electronic configuration
A brick and a feather fall to the earth at their respective terminal velocities. Which objectexperiences the greater force of air friction?
Answer:
Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.
Explanation:
Objects at terminal velocity, only under the influence of gravity, have maximized their speed and have an acceleration of zero. Thus, neither object is accelerating.
Recall Newton's second law: [tex]\sum {\vec {F}}=m \vec {a}[/tex]
Since acceleration for each object is zero, the sum of the force acting on each of those objects must also be zero.
Since the only forces acting on the objects are gravity and the force of air friction, in order to zero out, the force of air friction must be equal in magnitude and opposite in direction to the force of gravity.
Recall that near the surface of the earth, [tex]F_{gravity}=mg[/tex], so the Force of Gravity acting on an object is directly proportional to the object's mass. (A similar argument could be made even if this were not taking place on the surface of the earth, so long as the objects were the same distance from the object providing gravitational influence).
If the masses of the objects are different, the object with the greater mass will experience a larger force of gravity, and hence a larger force of air friction at terminal velocity.
Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.
What occurs when a temperate glacier meets its pressure-melting point?
Answer:
a whole new glacier will start because the other one is melting
I need to know how to solve: finding magnitudes of forces related to a sum of three vectors
The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.
What are the magnitudes of two vectors to get the zero vector by vector sum?
According to the definition of vector sum and vectors in rectangular form, we must solve the following vector equation:
(0, 0) = 205 · (cos 23°, - sin 23°) + v · (- cos 75°, sin 75°) + u · (- cos 55°, - sin 55°)
(0, 0) = (188.703, 80.100) + v · (- 0.259, 0.966) + u · (- 0.574, 0.819)
(- 188.703, - 80.100) = v · (- 0.259, 0.966) + u · (- 0.574, 0.819)
Then, we must solve the following system of linear equations:
- 0.259 · v - 0.574 · u = - 188.703
0.966 · v + 0.819 · u = - 80.100
The solution is (v, u) = (- 585.709, 593,034). Please notice that the value of v only means that the direction of the real vector is antiparallel to the supposed one.
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A sound wave traveling through dry air has a frequency of 16 hz, a
wavelength of 22 m, and a speed of 350 m/s. when the sound wave passes
through a cloud of methane, its wavelength changes to 28 m, while its
frequency remains the same. what is its new speed? (the equation for the
speed of a wave is v= f * 1.)
Answer:
[tex]\huge\boxed{\sf v = 448\ m/s}[/tex]
Explanation:
Given data:Frequency = f = 16 Hz
Wavelength = λ = 28 m
Required:Speed = v = ?
Formula:v = fλ
Solution:Put the givens.
v = (16)(28)
v = 448 m/s
[tex]\rule[225]{225}{2}[/tex]
When the Sun runs out of hydrogen in its core, it will become larger and more luminous because Choose one: A. energy balance no longer holds, and the star just drifts apart. B. infalling material rebounds off the core and puffs up the star. C. it starts fusing hydrogen in a shell around a helium core. D. it starts fusing helium in a shell and hydrogen in the core.
It starts fusing hydrogen in a shell around a helium core
Eventually, a star will run out of hydrogen fuel in its core, nuclear fusion will stop, and the star will enter a new stage of its lifetime.
What happen to the Sun when it runs out of hydrogen ?Faster hydrogen burning means the star will grow larger and more luminous to allow the extra energy created to escape but since the temperature of the core remains constant the star's surface temperature will drop.
When our Sun runs out of hydrogen fuel in the core, it will contract and heat up to a sufficient degree that helium fusion can beginOnce that mass/temperature threshold is crossed, the star begins fusing hydrogen into helium, and will encounter one of three different fates.Learn more about Sun here:.
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Which statement about income is not true?
A. Income should increase over your career.
B. Income is part of a budget.
C. Income can come from multiple sources.
D. Income only includes salary.
Answer: d) income only includes salary
Explanation:
i just took a test for economics and personal finance and got it correct
The statement that "Income only includes salary " is not true.
Income is the money that an individual or organization receives in return for their services or goods.
Depending on the context—such as taxation, financial accounting, or economic analysis—income may have a variety of definitions.
For the majority of people, their total earnings include their wages and salaries, investment returns, pension payments, and other receipts.
For businesses, income refers to the money made from selling goods and services as well as any interest or dividends paid on the company's cash holdings and reserves.
So, the amount of money, property, and other value transfers received over a predetermined period in return for goods or services is often referred to as "income."
That's why income does not include only salary.
Hence Statement (D) about the income is not true.
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Assignment 1.4
VOLUME OF SPHERE
The radius of sphere 'r' is measured with vernier callipers as
(r+Ar)= (2.25 +0.01) cm. Calculate the volume of sphere. (47.7+0.6) cm³.
PHYSICS
you can use the graph to estimate the value of x when y is required to start a doubles match with the sun and the sky very well from her childhood and a kind young women who lives with her wearing a black and a veil and shows to be in that position or they have a bad past or bad life that they want to take revenge on every one by murder goes on by them in the streets of St and St Mary's Church and its followers are known as Sikhs and the other children claim she
The north-pole end of a bar magnet is held near a stationary positively charged piece of plastic. How is the plastic affected?.
When the north-pole end of a bar magnet is held near a stationary positively charged piece of plastic, it remains unaffected.
What is a bar magnet?
A bar magnet is made of ferromagnetic substance that produces
magnetic field.
What are the properties of a bar magnet?
Magnets attract ferromagnetic materials like iron, cobalt and nickel.Like poles repel each other and unlike poles attract each other.The strength of both poles is always the same.When a magnetic material is kept in contact with a bar magnet it acquires the magnetic property.Some materials like gold, silver and water get repelled by magnets.Since plastic is not a ferromagnetic material or any other material like gold and silver ,they remain unaffected in the presence of magnetic field.
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question is down below need rply fast
The X and Y components are as follows;
1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s
2. X = 12 * -cos 34 = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s
3. X = 8 * -cos 90 = 0 m/s; Y = 12 -sin 90 = -8 m/s
4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) = -19.3 m/s
What are the horizontal and vertical components of the vectors?The horizontal and vertical components of the velocities are given as follows:
Horizontal component, X = x cos θVertical component, Y = y sin θ1. 35 m/s at 57° from x-axis
X = 35 * cos 57 = 19. 1m/s
Y = 35 * sin 57 = 29.4 m/s
2. 12m/s at 34° S of W
X = 12 * -cos 34 = -10 m/s
Y = 12 * -sin 34 = -6.7 m/s
3. 8 m/s at South
X = 8 * -cos 90 = 0 m/s
Y = 12 -sin 90 = -8 m/s
4. 20 m/s at 275° from x-axis
X = 20 * cos 75 = 5. 2m/s
Y = 20 * (-sin 75) = -19.3 m/s
In conclusion, the X and Y components are found by taking cosines and sine of the angles.
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Find the work done when a constant force f = 13 lbs moves a chair from x = 2.4 to x = 4.1 ft. along the x -axis.
The work done in moving the chair from x = 2.4 to x = 4.1 ft using a force of F = 13 lbs is 29.98 J
What is work done?This is simply defined as the product of force and distance moved in the direction of the force. Mathematically, it can be expressed as
Workdone (Wd) = force (F) × distance (d)
Wd = Fd
How to convert lb to N1 lb = 4.45 N
Therefore,
13 lbs = 13 × 4.45
13 lbs = 57.85 N
How to determine the distance in mInitial distance = 2.4 ftFinal distance = 4.1 ftChange in distance = 4.1 -2.4 = 1.7 ft1 ft = 0.3048 m
Therefore,
1.7 ft = 1.7 × 0.3048
1.7 ft = 0.51816 m
How to determine the workdoneForce (F) = 57.85 NDistance (d) = 0.51816 mWorkdone (Wd) =?Wd = Fd
Wd = 57.85 × 0.51816
Workdone = 29.98 J
Thus, the workdone in moving the chair is 29.98 J
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A 1-oz bullet is traveling with a velocity of 1400 ft/s when it impacts and becomes embedded in a 5-lb wooden block. The block can move vertically without friction. Determine (a) the velocity of the bullet and block immediately after the impact, (b) the horizontal and vertical components of the impulse exerted by the block on the bullet.
After impact velocity = 14.968 ft/s
Weight and mass of Bullet and wooden block:
Bullet: w = 1oz = 1/16 lb m = 0.001941 lb
wooden block : W = 5lb M = 0.15528 lb
velocity of block and bullet immediately after impact:
Σmv1 + ΣImp = mv2
Resolving vertical component
( m× v₀cos30⁰) + 0 = ( m+M) v'
v' = ( m× v₀cos30⁰)/ (m+M)
v' = 14.968 ft/s
Horizontal and vertical component of the impulse exerted by block on the bullet:
Here we will apply the principle of impulse and momentum.
Horizontal component:
-mv₀ cos30⁰ + RxΔt =0
RxΔt = mv₀sin30⁰
= 0.001941 × 1400sin30⁰
RxΔt = 1.3587 lb.s
Vertical component:
-mv₀cos30⁰ + RyΔt = -mv'
RyΔt = m( v₀cos30⁰-v')
RyΔt = 0.001941(1400cos30⁰ - 14.968)
= 2.32 lb.s
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How do astronomers explain the energetic jets that come out of quasars and active galactic nuclei in opposite directions
Astronomers explain the energetic jets that come out of quasars and active galactic nuclei(AGN) in opposite directions in a way that the supermassive black holes' chaotic accretion discs "spit out" jets in directions perpendicular to the disc.
Quasar : A supermassive black hole with a mass between millions and tens of billions of solar masses that is fueled by an extraordinarily bright active galactic nucleus (AGN) and encircled by a gaseous accretion disc is known as a quasar.
An active galactic nucleus (AGN) is a compact area at the Centre of a galaxy that exhibits features that indicate the luminosity is not coming from stars and is substantially brighter than usual over at least some of the electromagnetic spectrum.
Hence, astronomers propose that the chaotic accretion discs of supermassive black holes "spit out" jets in directions perpendicular to the disc, explaining the intense jets that emerge from quasars and active galactic nuclei in different directions.
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Which types of decay will cause the mass number a of a nucleus to change?.
Nuclear decay results in the change in the mass number of a nucleus. In precise it is alpha decay.
What is nuclear decay?The process through which an unstable atomic nucleus loses energy through radiation is known as radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or nuclear disintegration.
What is alpha decay?A nuclear process known as "alpha decay" releases a particle made up of two protons and two neutrons when an unstable nucleus transforms to another element. The helium nucleus that is being ejected is known as an alpha particle. Positive charge and a sizable mass characterize alpha particles.How is mass number of nucleus is changed by alpha decay?
When a nucleus emits an alpha particle, these changes happen:
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Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through what angle should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of:
Answer: Plane-polarized light is incident on a single polarizing disk with the direction of E0 parallel to the direction of the transmission axis. Through angle [tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] should the disk be rotated so that the intensity in the transmitted beam is reduced by a factor of n .
Explanation: To find the correct answer, we need more clarifications about the Malu's law.
What is Malu's law?When a beam of plane polarized light is passed through an analyzer, the intensity I of the transmitted light varies directly as the square of the angle between the direction of polarizer and the analyzer.[tex]I=I_0cos^2\alpha[/tex]
where, [tex]I_0[/tex] is the maximum intensity of transmitted light.
Intensity of the light transmitted through the polarizer is half of the incident intensity.How to solve the problem?Here in the question ,let's take the factor at which the intensity of transmitted light is reduced by as n.we have the expression[tex]I=I_0cos^2\alpha[/tex]
we have to find the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n.[tex]\alpha =cos^-1\sqrt{(\frac{I}{I_0}} )=cos^-1\sqrt{\frac{I}{nI} } \\\alpha =cos^-1\sqrt{\frac{1}{n} }[/tex]
If we know the value of n, then we can easily find the angle.Thus, we can conclude that, the value of angle alpha, so that the intensity in the transmitted beam is reduced by a factor of n will be,
[tex]\alpha=cos^-1(\sqrt{\frac{1}{n} })[/tex] .
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What is the total energy that the ball has when the launcher is in the ""ready to launch"" position with the spring fully compressed?
An 80-N crate is pushed a distance of 5.0 m upward along a smooth incline that makes an angle of 30o with the horizontal. The force pushing the crate is parallel to the slope. If the speed of the crate increases at a rate of 1.5 m/s2, find the work done by the force. Group of answer choices 260 J 200 J 1 J 200 kJ 140 J
The work done by the force is 140 J.
Calculation:
It is given that, an 80-N crate is pushed a distance of 5.0 m upward along a smooth incline that makes an angle of [tex]30^\circ[/tex] with the horizontal. The force pushing the crate is parallel to the slope and the acceleration is 1.5 [tex]\text{ m/s}^2[/tex].
It is required to find the work done by the force.
The free-body diagram is shown below,
Here, W=80 N, a=-1.5 [tex]\text{ m/s}^2[/tex]
We can write the net force equation as,
[tex]\begin{gathered}F-W \sin 30^{\circ}=m a \\F-m g \sin 30^{\circ}=\left(\frac{W}{g}\right) a\end{gathered}[/tex]
Here W is the weight of the object, m is the mass of the body, and F is the applied force.
Thus,
[tex]\begin{aligned}F-(80 \mathrm{~N}) \sin 30^{\circ} &=\left(\frac{80 \mathrm{~N}}{9.8 \mathrm{~m} / \mathrm{s}^{2}}\right)\left(-1.5 \mathrm{~m} / \mathrm{s}^{2}\right) \\F &=27.755 \mathrm{~N}\end{aligned}[/tex]
It is known that the work done by the force is calculated as the multiplication of the applied force and the displacement.
Thus the work one is,
[tex]\begin{aligned}W &=(27.755 \mathrm{~N})(5 \mathrm{~m}) \\& \approx 140 \mathrm{~J}\end{aligned}[/tex]
Thus the last option is the correct one.
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Compared with a car moving at some original speed, how much work must the brakes of a car supply to stop a car that is moving twice as fast? how will the stopping distances compare?.
It takes four times the work and four times the stopping distance.
Given:
original speed of car = x
brakes applied so final speed = 0
moving speed of another car = 2x
To Find:
work done to stop the car
Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
Work done is given by
W = KE(final) - KE(initial)
W = 1/2m(v)^2 - 1/2m(u)^2
W = 1/2m(0 - (x)^2)
W = 1/2m(4x^2)
W = 4(1/2mx^2)
W = 4W
So, work done will be 4 times initial work
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If there is no change in the velocity of the object then it is known to be in ______
a) constant speed
b) uniform acceleration
c) uniform motion
d) non-uniform motion
OPTION (C) IS CORRECT
ANSWER - UNIFORM MOTION
If there is no change in the velocity of the object then it is known to be in UNIFORM MOTION.
EXPLORE MORE:-
EXAMPLE - A CAR COVERS A DISTANCE OF 15 KM WE'D EVERY 2 HOURS
FOR AN UNIFORM MOTION, ACCELERATION IS ZERO , AS THERE IS NO CHANGE IN VELOCITY....
-THANKS.!!
The light ray is now incident on a glass-air interface, with an angle of incidence in the glass of 45 degrees. What is the angle of light ray emerging from the glass into air
The ray will not emerge into the air medium from glass medium.
To find the answer, we need to know about the critical angle.
What's critical angle of glass?Critical angle of a medium can be determined from the relation as sinФ = 1/n, n = refractive index of that medium.As glass has refractive index of 1.5, so Critical angle = sin⁻¹(1/1.5) = 42 °Why does the light incident at 45° inside a glass not emerge to the air medium?As we got the critical angle of glass is 42°, so the light incident at 45° which is greater than 42° will reflect back into the glass medium instead of emergence into the air medium.Thus, we can conclude that the light will not emerge into air medium.
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How many watts of power are needed to exert a force of 30 n over a distance of 100 m for 1 minute?
Power require in Watts is 50 watts
Given:
Force = 30 N
Distance = 100m
Time for which force applied = 1 min = 60 sec
To Find:
Power
Solution: A watt is a unit of power. It is the amount of energy an item needs to function; the rate at which energy is consumed. One watt is equivalent to electricity flowing at a rate of one joule (unit of energy) per second
P = W/t
where W is work done by force and t is the time for which force is applied
W = F x d
W = 30 x 100 = 3000
P = 3000/60 = 50 watts
So Power require in Watts is 50 watts
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A piece of copper of mass 150g at temperature of mass 70g containing 60g of water at temperature of 20°C. Ignoring heat losses, what would be the final steady temperature of the mixture? [Specific of heat capacity of copper = 4.0× 10²J/kg-1/K ^-1. Please any Physics student can help or if you have any idea, you can help me out. Thanks.✨✨
Answer:
The final temperature is [tex]29.6^oC[/tex].
Explanation:
When the two masses come in contact, one releases heat and the other absorbs it. The former can be modelled with the equation [tex]HeatLost = (Mass1 (kg))(c1)(T1-T)[/tex], and the latter by [tex]HeatGained=(Mass2(kg))(c2)(T-T2)[/tex]
m1=0.15 kg
m2=0.06 kg
T1 = 70 degrees Celsius = 343 K
T2 = 20 degrees Celsius = 293 K
T= Final temperature
c1 = Specific heat capacity of copper
c2 = Specific heat capacity of water
Because there is no heat lost into the surroundings, the heat removed from one substance is the same as the heat gained in the other. Therefore:
[tex](Mass1)(c1)(T1-T)=(Mass2)(c2)(T-T2)[/tex]
[tex](0.150)(400)(343-T)=(0.06)(4184)(T-293)[/tex]
[tex](60)(343-T)=(251.04)(T-293)[/tex]
[tex]20580-60T=251.04T-73554.72[/tex]
[tex]-311.04T=-94134.72[/tex]
[tex]T=302.6 K[/tex]
[tex]T=29.6^oC[/tex]
Hope this helps! (My apologies if the answer is wrong, it has been a while since I've done this)
An airplane traveling at speed, 180 m/s, emits sound at a frequency of 2 000 Hz. What is the change in frequency (in Hz) heard by a stationary listener as the plane approaching and passing by
Answer:
As the plane moves toward the listener, the apparent frequency of the plane would be [tex]4250\; {\rm Hz}[/tex] ([tex]2250\; {\rm Hz}[/tex] higher than the frequency at the source.)
As the plane moves away from the listener, the apparent frequency of the plane would be approximately [tex]1308\; {\rm Hz}[/tex] (approximately [tex]692\; {\rm Hz}[/tex] lower than the frequency at the source.)
Assumption: the speed of sound in the air is [tex]340\; {\rm m\cdot s^{-1}}[/tex].
Explanation:
Crests of this sound wave travel toward the listener at a constant [tex]v = 340\; {\rm m\cdot s^{-1}}[/tex]. Since there is a pause of [tex]t = 1 / f = (1/2000)\; {\rm s}[/tex] between every two consecutive crests of this sound wave, the distance between each pair of consecutive crests would be:
[tex]\begin{aligned}\lambda &= \frac{v}{f} \\ &= \frac{340\; {\rm m \cdot s^{-1}}}{2000\; {\rm s^{-1}}} \\ &= 0.17\; {\rm m} \end{aligned}[/tex].
Hence, if the aircraft wasn't moving, the first crest would have a head start of [tex]\lambda = 0.17\; {\rm m}[/tex] relative to the second one. This head start would ensure that the first crest arrive [tex]t = \lambda / v = 0.17\; {\rm m} / (340\; {\rm m \cdot s^{-1}}) = (1/2000)\; {\rm s}[/tex] earlier than the second crest.
However, at a speed of [tex]v_{\text{s}} = 180\; {\rm m\cdot s^{-1}}[/tex], the aircraft would have travelled an additional [tex]v_\text{s}\, t = 180\; {\rm m\cdot s^{-1}} \times (1/2000)\; {\rm s} = 0.09\; {\rm m}[/tex] within that [tex]t = (1 / 2000)\; {\rm s}[/tex].
If the aircraft was travelling towards the listener, the head start of the first crest over the next one would be reduced to [tex]\lambda - v_\text{s}\, t =[/tex][tex]0.17\; {\rm m} - 0.09\; {\rm m} = 0.08\; {\rm m}[/tex]. The first crest would arrive earlier than the second one by [tex](\lambda - v_{\text{s}}\, t) / (v) = (0.08\; {\rm m}) / (340\; {\rm m\cdot s^{-1}}) \approx 0.000235\; {\rm s}[/tex].In contrast, if the aircraft was travelling away from the listener, the head start of the first crest over the next one would be increased to [tex]\lambda + v_\text{s}\, t = 0.17\; {\rm m} + 0.09\; {\rm m} = 0.26\; {\rm m}[/tex]. The first crest would arrive earlier than the second one by [tex](\lambda + v_{\text{s}}\, t) / (v) = (0.26\; {\rm m}) / (340\; {\rm m\cdot s^{-1}}) \approx 0.000765\; {\rm s}[/tex].In other words, if the aircraft was moving towards the listener, the period of the sound would appear to the listener to be approximately [tex]0.000235\; {\rm s}[/tex]. in contrast, if the aircraft was moving away from the listener, the period of the sound would appear to the listener as approximately [tex]0.000765\; {\rm s}[/tex].
Therefore:
When the aircraft moves toward the listener, the listener would hear a frequency of [tex]f = 1 / t \approx 1 / 0.000235\; {\rm s} = 4250\; {\rm Hz}[/tex].When the aircraft moves away from the listener, the listener would hear a frequency of approximately [tex]f = 1 / t \approx 1 / 0.000765\; {\rm s} \approx 1307\; {\rm Hz}[/tex].
An object falls from the top of a building that is 25 m high. Air resistance is negligible.
What is the speed of the object when it hits the ground?
The velocity of the object s calculated as 22.1 m/s.
What is the speed of the object?Given that we can write that;
v^2 = u^2 + 2gh
Now u = 0 m/s because the object was dropped from a height
v^2 = 2gh
v = √2 * 9.8 * 25
v = 22.1 m/s
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the question is down below
The speed of the airplane, v is 144.2 m/s
The height, H of the roof above the head of the man is 66.4 m.
What is the speed of the airplane?The speed of the airplane is determined using the Pythagoras theorem.
The speed of the airplane, v is calculated as follows:
v = √(80² + 120²0
v = 144.2 m/s
The height, H of the roof above the head of the man is calculated as follows:
tan 38° = H/85
H = tan 38° * 85 m
H = 66.4 m
In conclusion, the tangent ratio is used to find the height of the roof above the head of the man.
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In the NEC Code, what does 210.8 indicate
A. Article 210, Section 8
B. Chapter 210, Paragraph 8
C. Page 210, Chapter 8
D. That Article 210 contains 8 paragraphs
In the NEC Code, 210.8 indicates article 210, section 8 and is denoted as option A.
What is NEC code?This is referred to the standards which are required for the safe installation of electric wires and equipment in USA.
This comprises of several articles covering different topics and sections which gives it a more elaborate meaning and understanding.
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Noah drops a rock with a density of 1.73 g/cm° into a
pond. Will the rock float or sink? Explain your answer.
Answer:
the rock will probably sink in water because density of rock heavier than the density of water.
Density of water=1g/cm
density of rock=1.73g/cm
1g/cm< 1.73g/cm
5.1 What is the nucleus composed of ?
Answer:
5.1 The DNA double helix is the most recognizable nucleic acid structure, but these are ribozymes.
Upon inspiration, what is the name of the air in the conducting zone that is not available for gas exchange?.
Dead space is the name of the air in the conducting zone that is not available for gas exchange.
What is conducting zone?
The conducting zone consists of all of the structures that provide passageways for air to travel into and out of the lungs.
The conducting zone is part of the respiratory system. It serves as a route for incoming and outgoing air and filtering debris and pathogens from the incoming air.In order to compensate for the reduction in gas exchange in the respiratory system, ventilation will increaseThe volume of air that is inhaled that does not take part in the gas exchange is dead space. Because it either remains in the conducting airways or reaches alveoli that are not perfused or poorly perfused.
Dead space volume is air in the conducting airways that does not participate in gas exchange between the alveoli and blood.
Hence,
Dead space is the name of the air in the conducting zone that is not available for gas exchange.
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