answer the last one plss i give brain

The calculated area of the shaded region is 56 square cm

The shaded region is a triangle

The formula for the area of a triangle is:

A = 1/2 * base * height

where A is the area of the triangle, base is the length of the base of the triangle, and height is the height of the triangle perpendicular to the base.

Using the given values, we can substitute base = 8 and height = 14 into the formula to get:

A = 1/2 * 8 * 14 = 56

Therefore, the area of the triangle is 56 square units.

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The notation "||v||" typically refers to the Euclidean norm (also known as the magnitude or length) of a vector v in a Euclidean space. The Euclidean norm of a vector v in n-dimensional space is defined as the square root of the sum of the squares of its components:

||v|| = sqrt(v1^2 + v2^2 + ... + vn^2)

Given that ||v|| = 8, we can find the Euclidean norm of -7v as follows:

||-7v|| = 7 * ||-v|| = 7 * sqrt((-v1)^2 + (-v2)^2 + ... + (-vn)^2)

Since -v has the same magnitude as v but points in the opposite direction, we can replace each vi in the above expression with -vi:

||-7v|| = 7 * sqrt((-v1)^2 + (-v2)^2 + ... + (-vn)^2) = 7 * sqrt(v1^2 + v2^2 + ... + vn^2)

But we know that ||v|| = sqrt(v1^2 + v2^2 + ... + vn^2) = 8, so we can substitute:

||-7v|| = 7 * ||v|| = 7 * 8 = 56

Therefore, ||-7v|| is 56.

Answer: D

Step-by-step explanation:

The amount of gasoline used in the lawn mowers is 2/5 of the total amount of gasoline used. Therefore:

Gasoline used in lawn mowers = (2/5) x 81.5 gallons

Gasoline used in lawn mowers = 32.6 gallons

Therefore, the answer is D. 32.6 gal.

Required polynomial is (x+3) where x is amount of average snowfall.

Here given in January, the amount of snowfall was 3 inches above average.

1. The average snowfall for January was a certain amount (let's call this 'A' inches).

2. The actual snowfall for January was 3 inches more than the average.

3. To calculate the actual snowfall for January, we can use the equation: Actual Snowfall = Average Snowfall (A) + 3 inches.

So, if we knew the average snowfall (A), we could easily find the actual snowfall by adding 3 inches to it.

Let amount of average snowfall be x inches.

So, snowfall in January month = (x+3) inches .

Therefore, required polynomial is (x+3) where x is amount of average snowfall.

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Correct answer is " Find a polynomial of the statement For the month of January, the amount of snowfall was 3 inches above average"

Answer:

68 3/4 yds

Step-by-step explanation:

trust me :)

Answer:

see below

Step-by-step explanation:

area of triangle formula  = 1/2 base * height

so 1/2*6*22 =66

not sure why there's no choice of 66

Answer:

44

Step-by-step explanation:

there are 792 trees but one acre has 18,

so to find the number of acres divide 792 by 18,

which would give you 44.

According to the given condition, the answer is (b) 44. There are 44 acres in Orangeland.

Expressions can be simple or complex, and can be used in many different contexts depending on the specific programming language or mathematical system being used.

The problem asks us to find the number of acres in Orangeland given the population density of orange trees and the total number of trees. We can use the formula for population density, which relates the number of individuals (in this case, orange trees) to the area they occupy.

The formula for population density is:

Population density = number of individuals/area

We can rearrange this formula to solve for the area:

Area = number of individuals/population density

In this problem, we are given the population density of Orangeland, which is 18 orange trees per acre. We are also given the total number of orange trees, which is 792. To find the area of Orangeland, we can substitute these values into the formula:

Area = 792 / 18

Simplifying this expression, we get:

Area = 44

Therefore, According to the given condition, the answer is (b) 44. There are 44 acres in Orangeland.

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The angle -4 radians is equal to -229.0 degrees when rounded to the nearest 10th.

To convert from radians to degrees, we need to multiply the angle by 180/π. Therefore, to convert -4 radians to degrees, we have:

-4 radians x 180/π ≈ -229.2 degrees

Rounding this to the nearest 10th gives us:

-229.2 degrees ≈ -229.0 degrees

Therefore, the angle -4 radians is equal to -229.0 degrees when rounded to the nearest 10th.

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It will take Emma about 4.04 years for her balance to reach $450, assuming she doesn't make any payments and the interest rate remains constant.

The formula that models this situation is P(1 + r/n)ⁿˣ, where P is the principal (the initial amount borrowed or invested), r is the annual interest rate, n is the number of times the interest is compounded per year, and t is the time (in years) that the money is invested or borrowed.

In this case, the principal is $300, the annual interest rate is 15%, the interest is compounded monthly (so n = 12), and we want to find the time it takes for the balance to reach $450.

P = 300(1 + 0.15/12)¹²ˣ

To find out how long it will take for Emma's balance to reach $450, we need to solve for t in the equation above. We can do this by using logarithms to isolate the variable t:

=>  log(1.5) = 12t x log(1 + 0.15/12),

we can use the properties of logarithms. Specifically, we can use the property that log(a x b) = log(a) + log(b) to separate the logarithm on the right side of the equation:

log(1.5) = 12t x log(1 + 0.15/12)

log(1.5) = log[(1 + 0.15/12)¹²ˣ]   (using log(a x b) = log(a) + log(b))

Now we have two logarithms that are equal to each other. Therefore, we can take the exponential of both sides to eliminate the logarithms:

1.5 = (1 + 0.15/12)¹²ˣ

Simplifying this expression further, we get:

1.5 = (1.0125)¹²ˣ]

log(1.5) = log[(1.0125)¹²ˣ]]

log(1.5) = 12t x log(1.0125)

Finally, we can solve for t by dividing both sides by 12 x log(1.0125):

log(1.5) / [12 x log(1.0125)] = t

t ≈ 4.04

Therefore, the simplified expression is t ≈ 4.04.

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Answer:

[tex] {21}^{2} + {x}^{2} = {35}^{2} [/tex]

[tex] {x}^{2} =784[/tex]

[tex]x = 28[/tex]

[tex] {y}^{2} + {32}^{2} = {35}^{2} [/tex]

[tex] {y}^{2} = 201[/tex]

[tex]y = \sqrt{201} = 14.18[/tex]

The ladder will reach about 14.2 feet up the side of the house.

The equivalent expression is 2(y-4).

A statement with more than two variables or integers can be written as an expression using addition, subtraction, multiplication, and division operations.

Even though they have different looks, expressions that are equivalent do the same action. Two algebraic expressions that are equivalent have the same value when the variable is entered with the same value.

We have,

-2y - 8 + 4y

-2y and 4y are like terms.

So,

Add the like terms.

2y - 8

Taking out 2 commons.

2(y - 4)

Now,

We can not further simplify the expression.

Thus,

The equivalent expression is 2(y - 4).

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The statement "there is a 40% chance of rain today" means that there is a probability of 0.4 (or 40%) that it will rain today.

The statement "there is a 40% chance of rain today" means that there is a probability of 0.4 (or 40%) that it will rain today.

Probability is a measure of the likelihood or chance of an event occurring, and it ranges from 0 (impossible) to 1 (certain).

In this case, a probability of 0.4 means that out of 10 similar days with similar weather conditions, we would expect it to rain on 4 of those days.

However, if the weather conditions change or new information becomes available, the probability of rain may increase or decrease.

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Answer:

Step-by-step explanation:

B appears to be the only answer to this problem as the rest are perfect squares meaning their roots will terminate, while there is no guarantee for 8.

B is the correct answer

Answer:

The domain of h is

[tex] - 7 \leqslant x \leqslant 7[/tex]

Choice A is correct.

Answer:

c

Step-by-step explanation:

Answer:

1/2

Step-by-step explanation:

Since the events are independent, P(A and B) = P(A) * P(B)

P(X and Y) = P(X) * P(Y)

                  = 2/3 * 3/4

                  = 2/4

                   = 1/2

Answer: [tex]6.75\pi[/tex] inches^2

Step-by-step explanation:

If the diameter is 18 inches, the radius must be 18/2 = 9 inches.

Thus, we can calculate the area using the area of a circle = [tex]\pi r^{2}[/tex].

Plugging in the values, we get the area = [tex]81\pi[/tex] inches^2.

Since 30 degrees is 1/12 of 360 degrees, a 30-degree sector would be equal to 1/12 the area of the circle.

Therefore, we divide [tex]81\pi[/tex]/12 to get the area of the sector = [tex]6.75\pi[/tex] inches^2.

(a) The point estimate is 92/160 = 0.575 or 57.5%.

(b) Using the salt program, the 90% confidence interval is [0.502, 0.648].

(c) Using the salt program, the 95% confidence interval is [0.476, 0.674].

(d) The 95% confidence interval is wider than the 90% confidence interval.

(a) The point estimate for the above problem is the proportion of people who support new gun regulations, which is 92/160 = 0.575 or 57.5%.

(b) To find the 90% confidence interval, we can use the following formula:

[tex]CI = p ± z*(sqrt(p*(1-p)/n))[/tex]

where p is the point estimate, z is the z-score corresponding to the confidence level (90% in this case), and n is the sample size. Using a standard normal distribution table, we find that the z-score for a 90% confidence level is 1.645. Substituting the values, we get:

[tex]CI = 0.575 ± 1.645*(sqrt(0.575*(1-0.575)/160)) = (0.500, 0.650)[/tex]

Therefore, the 90% confidence interval for the proportion of people who support new gun regulations is (0.500, 0.650).

(c) To find the 95% confidence interval, we can use the same formula but with a different z-score. The z-score for a 95% confidence level is 1.96. Substituting the values, we get:

[tex]CI = 0.575 ± 1.96*(sqrt(0.575*(1-0.575)/160)) = (0.480, 0.670)[/tex]

Therefore, the 95% confidence interval for the proportion of people who support new gun regulations is (0.480, 0.670).

(d) The 95% confidence interval is wider than the 90% confidence interval, which is expected because a higher confidence level requires a wider interval to capture the true population proportion with higher probability.

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To decide which measurement has a reverse relationship with the number of wins, we ought to seek for a relationship coefficient with negative esteem. A negative correlation coefficient shows that as one variable increments, the other variable tends to diminish.

Without seeing the real relationship framework, we cannot point out the precise statistic that has a reverse relationship with the number of wins. In any case, ready to search for the relationship coefficient that features negative esteem.

For illustration, in the event that we have a relationship network like this:

markdown

| W | Period | WHIP | SO/9 | BB/9 |

----------------------------------------------

W | 1 | -0.7 | -0.6 | 0.5 | -0.3 |

----------------------------------------------

Period | -0.7| 1 | 0.9 | -0.8 | 0.5 |

----------------------------------------------

WHIP | -0.6| 0.9 | 1 | -0.7 | 0.4 |

----------------------------------------------

SO/9 | 0.5| -0.8 | -0.7 | 1 | -0.4 |

----------------------------------------------

BB/9 | -0.3| 0.5 | 0.4 | -0.4 | 1 |

----------------------------------------------

We are able to see that the relationship coefficient between the number of wins (W) and the earned run normal (Time) is -0.7, which indicates a strong negative relationship. This implies that as the Time increments (showing poorer pitching execution), the number of wins tends to diminish. Subsequently, Time has a reverse relationship with the number of wins.

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Answer: Its the last one

Step-by-step explanation:

It would take the bowling ball approximately 3.1 seconds to fall 150 feet.

What is distance?

Distance is the total movement of an object, regardless of direction. We can define distance as how much ground an object has covered, regardless of its starting or ending point.

Distance is defined as the size or amount of displacement between two positions. Note that the distance between two locations is not the same as the distance between them. The distance traveled is the total length of the path traveled between two positions.

Here given equation,

d = 16t², where t is the time in seconds and d is the distance in feet and distance is 150 feet.

We want to find the value of t.

Now,

[tex]d = 16 {t}^{2} \\ {t}^{2} = \frac{d}{16} \\ {t}^{2} = \frac{150}{16} \\ t = \sqrt{( \frac{150}{16}) } \\ t = \sqrt{9.375} \\ t = 3.0619[/tex]

So, t = 3.1 (rounded to one decimal place)

Therefore, it would take the bowling ball approximately 3.1 seconds to fall 150 feet.

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Correct question is "How long would it take the bowling ball to fall 150 feet where equation of distance is d = 16t² ?(Estimate your answer to one decimal place). "

The average rate of change of the function f(x) on the interval 1 ≤ x ≤ 8 is given as follows:

5.

The average rate of change of a function is given by the change in the output of the function divided by the change in the input of the function. Hence we must identify the change in the output, the change in the input, and then divide then to obtain the average rate of change.

The parameters for the function are given as follows:

Hence the average rate of change for the function is given as follows:

r = (25 - (-10))/(8 - 1) = 35/7 = 5.

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Answer:80

Step-by-step explanation:

The area of the given figure is 20cm².

What is a kite?

A quadrilateral called a kite has two pairs of sides that are each the same length and are next to one another.

What is area of a kite?

A kite's diagonals are perpendicular. The area of a kite is calculated as half of the diagonal product, which is the same as the area of a rhombus. The formula: can be used to express the area of a kite.

Area of Kite =1/2×D1×D2

D1 is the kite's long diagonal.

D2 is the kite's short diagonal.

when we draw the figure in coordinate system we find that it is shape of a kite,

so area of kite = 1/2*4*4+1/2*4*6

                         = 20 cm²

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l'exercice 3 est la boisson d'Andres. Je suis désolé si cela ne ressemble pas vraiment à un français parfait, je parle anglais et j'utilise Translate. passe une bonne journée!

Answer:

(0.5, -0.5)

Step-by-step explanation:

To find the midpoint of A and B, we can use the midpoint formula. The formula involves finding the average of the x-coordinates and the average of the y-coordinates.

Midpoint formula: ((x1 + x2) / 2 , (y1 + y2) / 2)

Using the coordinates of A (-3, -5) and B (4, 4), we can plug them into the formula:

(((-3) + 4) / 2 , ((-5) + 4) / 2)

Simplifying this gives us the midpoint of A and B: (0.5, -0.5).

Therefore, the midpoint of A and B is at coordinates (0.5, -0.5).

according to the question the actual distance between Chattanooga and Nashville is 133 miles.

Distance is an object's total, aimless movement. Without regard to whether anything has a beginning or an end, distance can be defined as the amount of space that something has traversed. Distance is referred to be the breadth or magnitude of the gap between two locations. It should be highlighted that the distance between two points and the length travelled between the two are not the same thing. The total length of a path connecting two locations counts as the distance travelled. Distance is the distance in reality that a body travels. It also goes by the name "path length." For instance, the length of a path for the thing passing via point O and arriving at position P would be OP = 360 m.

given,

If 1 inch on the map represents 38 miles in reality, then 3.5 inches on the map would represent:

3.5 inches * 38 miles/inch = 133 miles

Therefore, according to the scale on the map, the actual distance between Chattanooga and Nashville is 133 miles.

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From distance formula, the distance covered by a particle with position (x, y) as time, t is equals to the [tex] 18\sqrt{2}[/tex].

The distance d, traveled by the particle with position vector, r(t) = <x(t), y(t) > over the interval [a,b] is calculated by following

[tex]d = \int_{a}^{b} ( (\frac{dx}{dt})² +(\frac{dy}{dt})² )dt[/tex]. We have a particle with position value (x, y) as t varies in the time interval. The parametric equations are, x = 3 sin² (t), y = 3 cos²(t), on the

time interval [0,3π]. Now the derivative of above parametric equations with respect to time t are [tex]\frac{dx}{dt} = 6 sin(t)cos(t) [/tex] = 3 sin(2t)

[tex]\frac{dy}{dt} = -6 sin(t)cos(t) [/tex]

= - 3 sin(2t)

Therefore, the required distance travelled by particle in the interval [0,3π] is written as [tex]d = \int_{0}^{3π} \sqrt{( (3 sin(2t))² + (-3 sin(2t))²) dt} \\ [/tex]

[tex]= \int_{0}^{3π} \sqrt{ ( 9 sin²(2t) + 9sin²(2t))}dt \\ [/tex]

[tex]= \int_{0}^{3π} \sqrt{18sin²(2t)dt}[/tex]

[tex]= 3\sqrt{2}\int_{0}^{3π} |sin(2t)|dt[/tex]

[tex]= 3\sqrt{2}[ \int_{0}^{\frac{π}{2}} sin(2t)dt - \int_{\frac{π}{2}}^{π} sin(2t)dt + \int_{π}^{\frac{3π}{2}} sin(2t)dt - \int_{\frac{π}{2}}^{2π}sin(2t)dt + \int_{2π}^{\frac{5π}{2}}sin(2t)dt - \int_{\frac{5π}{2}}^{3π}sin(2t)dt \\ [/tex]

[tex]= 3\sqrt{2}([ \frac{cos(2t)}{2}]_{0}^{\frac{π}{2}} - [\frac{cos(2t)}{2}]_{\frac{π}{2}}^{π} + [\frac{cos(2t)}{2}]_{π}^{\frac{3π}{2}} - [\frac{cos(2t)}{2}]_{\frac{3π}{2}}^{2π} + [\frac{cos(2t)}{2}]_{2π}^{\frac{5π}{2} }- [ \frac{cos(2t)}{2}]_{\frac{5π}{2}}^{3π})\\ [/tex]

[tex]= 3\sqrt{2}([ \frac{1}{2} +{\frac{1}{2}] - [\frac{-1}{2}- \frac{1}{2}}] + [\frac{1}{2}+ \frac{1}{2}] - [\frac{-1}{2} - \frac{1}{2}] + [\frac{1}{2} + \frac{1}{2}]- [ \frac{-1}{2} - \frac{1}{2}])\\ [/tex]

[tex]= 3\sqrt{2}(6)[/tex] =[tex]= 18\sqrt{2}[/tex]

Hence, the required distance is [tex] 18\sqrt{2}[/tex].

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The z-score associated with an observed age at first marriage of 25.50 is 0.35.

To calculate the z-score associated with an observed age at first marriage of 25.50, we use the formula:

z = (x - μ) / σ

where:

x = the observed age at first marriage (25.50)

μ = the mean age at first marriage (23.33)

σ = the standard deviation of age at first marriage (6.13)

Substituting the given values, we get:

z = (25.50 - 23.33) / 6.13

z = 0.35

Therefore, the z-score associated with an observed age at first marriage of 25.50 is 0.35.

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Answer:

x =  ± [tex]\frac{4}{3}[/tex]

Step-by-step explanation:

9x² − 16 = 0

9x² = 16

x² = [tex]\frac{16}{9}[/tex]

x = ± √[tex]\frac{16}{9}[/tex]

x =  ± [tex]\frac{4}{3}[/tex]

So, the answer is:  x = [tex]\frac{4}{3}[/tex] , - [tex]\frac{4}{3}[/tex]

Farm Joe used [tex]7\frac{6}{15}[/tex] kg of soil in this month.

The total weight of soil that Farm Joe ordered was:

3 bags x 4 2/5 kg/bag = 12 6/15 kg = 12 2/5 kg

The weight of the first bag used was 4 2/5 kg.

The weight of the second bag remaining is 2 3/4 kg.

The weight of the third bag remaining is 7/8 kg.

The total weight of soil used in this month can be found by subtracting the weight of the second and third bags remaining from the total weight of soil ordered:

12 2/5 kg - 2 3/4 kg - 7/8 kg

Converting all fractions to fifteenths:

12 8/15 kg - 5 1/15 kg - 1/15 kg = 7 6/15 kg

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