______________________________

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. Determine The Depth of The Water Well.

N.B. The Correct Answer Will Receive 30 Points & The Brainliest Title.
______________________________​

Answers

Answer 1

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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Related Questions

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Answers

Answer:

b

Explanation:

this because if force (f) are resultant cos then the point is proportional to the direction of c at greatest possible forces

how is work and energy inter-related?? (in simple words)​

Answers

Answer:

The work and energy is inter- related because if we are energetic then only we are able to work.

People who are weak and not energetic cannot work continuously.

Explanation:

hope this helps you....

Semiconductors can simplistically be thought of as an intermediate state between insulators and conductors. In a semiconductor, charges are normally bound in place (like in an insulator), but when injected with enough energy, the charges can move freely (like in a conductor). Given what we have observed about the behavior of conductors and insulators in this exploration, what would happen if we replaced the glass rod with a semiconductor material

Answers

Answer:

The semiconductor rod will conduct electricity

Explanation:

Glass rod does not conduct electricity. Glass is one of the best insulators of electricity. But when a glass rod is replace with a semi conductor, then the semi conductor rod starts conducting electricity as the electrons are free to move.

Semi conductors are special materials in which the energy band lies in between the conductor and the non conductor. The conductivity of a semi conductor increases with the increasing temperature.

In an semi conductor the electrons are free to move and as they starts moving they conduct electricity. Thus a semi conductor rod replacing a glass rod conducts electricity.

The "seeing" ability, or resolution, of radiation is determined by its wave length

The mass of an electrons is 9.10939 * 10^-31 kg and Planck's constant is 6.62607 * 10^-34 Js

If the size of an atom is an the order of 0.08 nm, how fast must an electron travel to have a wavelength small enough to "see" an atom? Answer in the units of m/s

Answers

ANSWER: 0.08nm !
Have a good night/day

Work is a measurement of the transfer of which of the following?
A. Impulse
B. Power
C. Energy

Answers

Answer:Enegry

Explanation:Energy transfer is used to do work

The low-frequency speaker of a stereo set has a surface area of and produces 1W of acoustical power. What is the intensity at the speaker

Answers

Answer:

      I =  [tex]\frac{1}{4\pi \ r^2}[/tex]

we see the intensity decreases with the inverse of the distance squared

Explanation:

Intensity is defined as power per unit area,

           I = P / A

in this case we have that the sound is emitted in a spherical form therefore the area is

           A = 4 pi r2

therefore the intensity is

          I =  [tex]\frac{1}{4\pi \ r^2}[/tex]

as we see the intensity decreases with the inverse of the distance squared

A 0.15 kg baseball is traveling at 40 meters per second (about 90 miles per hour) if the ball comes to a complete stop when it hits the catchers mitt, what is the change in velocity?

Answers

Answer:

Please find attached pdf

Explanation:

A Van de Graaff generator is one of the original particle accelerators and can be used to accelerate charged particles like protons or electrons. You may have seen it used to make human hair stand on end or produce large sparks. One application of the Van de Graaff generator is to create x-rays by bombarding a hard metal target with the beam. Consider a beam of protons at 1.10 keV and a current of 4.65 mA produced by the generator.
(a) What is the speed of the protons?
(b) How many protons are produced each second?

Answers

Solution :

Given that :

The energy of the protons, K.E. = 1.10 keV

                                                    [tex]$= 1.10 \times 10^3 \ eV $[/tex]

The current produced by the generator is I = 5 mA

                                                                        [tex]$= 5 \times 10^{-3} \ A$[/tex]

Now [tex]$1 \ eV = 1.6 \times 10^{-19 }\ J$[/tex]

Mass of the proton, m = [tex]$1.67 \times 10^_{-27} $[/tex] kg

Charge of the proton, [tex]$q_p = 1.6 \times 10^{-19} \ C$[/tex]

a). Therefore using the formula for K.E. we can find out the velocity of the proton.

[tex]$K.E. =\frac{1}{2}mv^2$[/tex]

[tex]$v=\sqrt{\frac{2K.E.}{m}}$[/tex]

[tex]$v=\sqrt{\frac{2\times 10^3 \times 1.6 \times 10^{-19}}{1.67 \times 10^{-27}}}$[/tex]

  [tex]$= 4.38 \times 10^5 \ m/s$[/tex]

b). We know that the current is :

 [tex]$I=\frac{\Delta Q}{\Delta t}$[/tex]

Therefore, the total charge in one second is given by :

[tex]$\Delta Q = I \times \Delta t$[/tex]

     [tex]$= 5 \times 10^{-3} \times 1$[/tex]

    [tex]$= 5 \times 10^{-3}\ C$[/tex]

So, the number of protons in this charge is given by :

[tex]$n = \frac{\Delta Q}{q_p}$[/tex]

  [tex]$=\frac{5 \times 10^{-3} }{1.6 \times 10^{-19}}$[/tex]

  [tex]$= 3.13 \times 10^{16}$[/tex] protons

a girl whose mass is 40kg walk up a flight of 20steps each 15mm hight in 10seconds.find power developed by the girl showing the solution

Answers

Answer: Approximately 11.76 joules per second

=========================================================

Work Shown:

Mass = 40 kg

Force pulling down = (mass)*(gravity) = 40*9.8 = 392 newtons

Roughly 392 newtons of force are pulling down on her.  

To climb the steps, she must apply 392 newtons of force upward.  

---------------

Displacement = 20*(15 mm) = 300 mm = 0.3 m

Work = Force*Displacement

Work = 392*0.3

Work = 117.6 joules of energy

---------------

Power = (Work)/(Time)

Power = (117.6 joules)/(10 seconds)

Power = (117.6/10) joules per second

Power = 11.76 joules per second, which is approximate

f body with a mass of 6kg. (Ans: When we throw a stone with 12 N force to produce an acceleration of m/s², what is the mass of 6 kg? (Ans: 1.5kg) Calculate the acceleration produced when a force of 48 N is What They m​

Answers

a. When the force = 12 N, mass = 6 kg, the acceleration is a = 2 m/s²

b. When the force = 48 N, mass = 6 kg, the acceleration is a = 8 m/s².

What is the acceleration of the body?

The acceleration of the body is calculated by applying Newton's second law of motion as follows;

F = ma

where;

F is the force applied to the objectm is the mass of the objecta is the acceleration of the object

a = F / m

when the force = 12 N, mass = 6 kg, the acceleration is calculated as;

a = 12 N / 6 kg

a = 2 m/s²

when the force = 48 N, mass = 6 kg, the acceleration is calculated as;

a = 48 N / 6 kg

a = 8 m/s²

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A transformer used on a 220V line deliver 1.5A at 1800V. what current is drawn from the line assuming the ideal Transformers

Answers

The current drawn from the line, assuming an ideal transformer, is approximately 12.27A.

In an ideal transformer, the power remains the same before and after transformation. Therefore, we can use the power equation to determine the current drawn from the line.

The power equation for a transformer is given by:

P1 = P2

where P1 is the input power, P2 is the output power.

Given that the input voltage (V1) is 220V, the input current (I1) is unknown, the output voltage (V2) is 1800V, and the output current (I2) is 1.5A, we can rewrite the equation as:

V1 * I1 = V2 * I2

Substituting the known values:

220V * I1 = 1800V * 1.5A

Simplifying:

I1 = (1800V * 1.5A) / 220V

I1 ≈ 12.27A

Therefore, the current drawn from the line, assuming an ideal transformer, is approximately 12.27A.

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two small identical conducting spheres have charges of 2.0x10-9C and - 0.5x109 C respectively when they are placed 4cm apart, what is the force between them? If they are brought into contact and then separated by 4cm, what is the force between them? ​

Answers

Answer:

6

Explanation:

nothingnsbejejjdbsbzbawkje

can you ans please ?????????????????????????????????????????

Answers

Answer:

ans a

Explanation:

as the circuit should not be completed until switch is closed

I love you


Please answer my question :-)

Answers

Answer:

A- Astronomical body

C- Galaxy

D- Comet

B- Moon

Hope this helps you! Have a great day!

Answer:

1. A

2. C

3. D

4. B

Explanation:

The blood pressure at your heart is approximately 100 mm Hg. As blood is pumped from the left ventricle of your heart, it flows through the aorta, a single large vessel with a diameter of about 2.5 cm. The speed of blood flow in the aorta is about 60 cm/s. Any change in pressure as blood flows in the aorta is due to the change in height: the vessel is large enough that viscous drag is not a major factor into successively smaller and smaller blood vessels until it reaches the capillaries. Blood flows in the capillaries at the much lower speed of approximately 0.7 mm/s. The diameter of capillaries and other small blood vessels is so small that viscous drag is a major factor..Because the flow speed in your capillaries is much less than in the aorta, the total cross-section area of the capillaries considered together must be much larger than that of the aorta. Given the flow speeds noted, the total area of the capillaries considered together is equivalent to the cross-section area of a single vessel of approximately what diameter?

a. 25 cm
b. 50 cm
c. 75 cm
d. 100 cm

Answers

Answer:

The correct option is c. 75 for this question

Explanation:

The correct option is c. 75 for this question:

Let's see how.

Continuity Equation is given as:

AcVc = AaVa

Where,

Aa = Area of Aorta

Ac = Area of the capillary

Va = Fluid speed in Aorta

Vc = Fluid speed in Capillary

So,

Assuming the fluid is the ideal one/

[tex]\pi[/tex]/4 [tex]Dc^{2}[/tex] Vc= [tex]\pi[/tex]/4 [tex]Da^{2}[/tex] Va

[tex]Dc^{2}[/tex] Vc= [tex]Da^{2}[/tex] Va

Dc = Da x [tex]\sqrt{\frac{Va}{Vc} }[/tex]

Dc = 2.5 cm x [tex]\sqrt{\frac{60 cm}{0.07 cm } }[/tex]

Dc = 73.192 cm

Dc = 75 approximately

Hence, the diameter of the capillary = 75 cm approximately  

In the human arm, the forearm and hand pivot about the elbow joint. Consider a simplified model in which the biceps muscle is attached to the forearm 3.80 cm from the elbow joint. Assume that the person's hand and forearm together weigh 15.0 N and that their center of gravity is 15.0 cm from the elbow (not quite halfway to the hand). The forearm is held horizontally at a right angle to the upper arm, with the biceps muscle exerting its force perpendicular to the forearm.
A. Find the force exerted by the biceps when the hand is empty.
B. Now the person holds a 80.0-N weight in his hand, with the forearm still horizontal. Assume that the center of gravity of this weight is 33.0 cm from the elbow. Find the force now exerted by the biceps.
C. Explain why the biceps muscle needs to be very strong.
D. Under the conditions of part B, find the magnitude of the force that the elbow joint exerts on the forearm.
E. Under the conditions of part B, find the direction of the force that the elbow joint exerts on the forearm.
F. While holding the 80.0-N weight, the person raises his forearm until it is at an angle of 53.0∘ above the horizontal. If the biceps muscle continues to exert its force perpendicular to the forearm, what is this force when the forearm is in this position?
G. Has the force increased or decreased from its value in part B? Explain why this is so, and test your answer by actually doing this with your own arm.

Answers

Answer:

Answer is explained in the explanation section below.

Explanation:

Part A)

From conserve moment of force, we have:

F1d1 = F2d2

F1 x (3.80 x [tex]10^{-2}[/tex] m) = 15N x (15 x [tex]10^{-2}[/tex] m)

F1 = [tex]\frac{15 . 15 . 10^{-2} }{3.80 . 10^{-2} }[/tex]

F1 = 59.2 N

Force exerted by the biceps when the hand is empty.

Part B)

The 80 N weight acts at 33 cm and 15 N at 15 cm, then the center of mass is:

x = [tex]\frac{m1x1 + m2x2}{m1+m2}[/tex]

x = [tex]\frac{\frac{80}{9.8} (33 .10^{-2}) + \frac{15}{9.8}(15.10^{-2} }{\frac{80}{9.8} + \frac{15}{9.8} }[/tex]

x = 30.16 x [tex]10^{-2}[/tex] m

Total Weight is:

F = 80N + 15N = 95N

From the conserve moment of force, we have:

F ( 3.8 x [tex]10^{-2}[/tex] ) = 95N (30.16 x [tex]10^{-2}[/tex])

F = 754 N

Part C:

From the above two examples solved, the force exerted by the biceps is higher than downward force, due to this muscle need to be very strong.

Part D)

The force exerted by elbow on the forearm is:

The force exerted by the elbow and biceps are in upward direction and total weight is in downward direction. So, the balancing force in vertical direction is:

F2 + 754N = 95N

F2 = 95N -754N

F2 = -659N

Negative sign shows the force is in downward direction.

Part E)

The bicep muscle acts perpendicular to the forearm, so it is lever arm stays the same. but those of the other two forces decreases as the arm is raised. There tension in the biceps muscle decreases.

Part F)

Angle = 53 degrees.

So,

Force = FcosФ

Force = 754 cos 53

Force = 453.76 N

Part G)

The value of force has gone downwards. It has decreased from that of part B.

Plzz answer correctly

Answers

“X”. Is the answer. Tell me if you got it correct

A steel cylinder of length 10 cm, mass 160 g and density 8 g/em. The radius of the cylinder is​

Answers

Answer:

0.8cm

Explanation:

Volume = mass/density = 160/8 = 20cm³

Volume = πr²h

r² = v/πh = 20/10π =0.64

r = √0.64 = 0.8

A motorcyclist is making an electric vest that, when connected to the motorcycle's 12 V battery, will warm her on cold rides. She is using 0.25-mm-diameter copper wire, and she wants a current of 4.2 A in the wire. Part A What length wire must she use

Answers

Answer:

L = 8.35 m

Explanation:

The lenght of a wire L can be calculated using the following expression:

L = R A/ρ  (1)

Where:

R: resistance of the wire

A: Cross section area of the wire

ρ: resistivity of the copper wire.

With this expression we realize that we do not have the area of the cross section, and the resistance of the wire either.

To calculate the area we can use the following expression:

A = πr²    (2)

If the diameter is 0.25 mm, then the radius is half, 0.125 mm. Converting this in meter it will have to be:

0.125 /1000 = 0.000125 m

Replacing we have:

A = π(0.000125)²

A = 4.91x10⁻⁸ m²

The reported resistivity of a copper wire is 1.68x10⁻⁸ Ω.m, so we just need to determine the resistance, which can be found using Ohm's law:

R = V/I  (3)

Replacing (3) into (1) we have:

L = (V * A) / (I * ρ) (4)

So finally, the length of the copper wire will be:

L = (12 * 4.91x10⁻⁸) / (4.2 * 1.68x10⁻⁸)

L = 8.35 m

Hope this helps

A car starts from rest at a stop sign. It accelerates at 2.0 m/s2 for 6.2 seconds, coasts for 2.5 s , and then slows down at a rate of 1.5m/s2 for the next stop sign. How far apart are the stop signs

Answers

Answer:

the distance between the stop signs is 120.7 m.

Explanation:

The car moved in three stages;

(1) It accelerates from rest at 2.0 m/s² for 6.2 seconds

(2) it moved at a constant speed for 2.5 s

(3) it finally decelerate at the rate of 1.5m/s²

(1) The distance moved by the car during the first stage;

s₁ = ut + ¹/₂at²

s₁ = 0 + ¹/₂ (2)(6.2)²

s₁ = 38.44 m

(2) The distance moved by the car during the second stage;

calculate the constant speed of the car,

v = u + at

v = 0 + 2 x 6.2

v = 12.4 m/s

The distance moved by the  car as it coasts for 2.5s: s₂ = vt

s₂ = 12.4 x 2.5

s₂ = 31 m

(3) The distance moved by the car during the third stage;

When the car stops, the final velocity is zero.

v² = u² + 2as₃

a = -1.5 m/s², since the car slowed down or decelerated.

0 = 12.4² + (2 x - 1.5)s₃

0 = 153.76 - 3s₃

3s₃ = 153.76

s₃ = 153.76 / 3

s₃ = 51.253 m

The total distance moved by the car from the start to stop = s₁ + s₂ + s₃

d = 38.44 m + 31 m + 51.253 m

d = 120.7 m

Therefore, the distance between the stop signs is 120.7 m.

How does altitude from the surface of earth affect the time period of a simple pendulum

Answers

Answer:

because the strength of Earth's gravitational field is not uniform everywhere, a given pendulum swings faster, and thus has a shorter period, at low altitudes and at Earth's poles than it does at high altitudes and at the Equator.

One species of eucalyptus tree, Eucalyptus regnans, grow to heights similar to those attained by California redwoods. Suppose a bird sitting on top of one specimen of eucalyptus tree drops a nut that is 1.7 ounces. If the speed of the falling nut at the moment it is 50.3 m above the ground is 42.7 m/s, how tall is the tree

Answers

Answer:

The tree is 143.325 meters tall

Explanation:

The given parameters of the eucalyptus tree are;

The mass of the eucalyptus tree nut = 1.7 ounces

The speed of the nut at 50.3 m above the ground, v = 42.7 m/s

The equation for free fall is given as follows;

v² = 2·g·h

Where;

v = The velocity after falling through a height, h

g = The acceleration due to gravity = 9.8 m/s²

h = The height through which the seed has already fallen

Therefore, we have;

h = v²/(2·g) = (42.7 m/s)²/(2 × 9.8 m/s²) = 93.025 m

The height through which the seed has already fallen, h = 93.025 m

The height of the tree = h + The height of the seed above ground at the moment it was falling at 42.7 m/s

The height of the tree = 93.025 m + 50.3 m = 143.325 m

The height of the tree = 143.325 m.

The height of the eucalyptus tree is approximately 111.9 meters.

To determine the height of the tree, we can use the equations of motion. The initial velocity of the nut, u, is 0 m/s (since it is dropped), the acceleration due to gravity, a, is approximately 9.8 m/s², and the final velocity, v, is 42.7 m/s. We need to find the height, h. Using the equation v² = u² + 2a(h - u), we can rearrange it to solve for h: h = (v² - u²) / (2a) Plugging in the values, we get: h = (42.7² - 0²) / (2 * 9.8) = 111.9 meters Therefore, the height of the eucalyptus tree is approximately 111.9 meters.

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Which of the following helps prevent and cope with heat-related conditions?

Drinking water


Wear proper clothing


Rest frequently


all of the above

Answers

drinking water is ur answer.

An action which would help in preventing and coping with heat-related conditions is: A. Drinking water.

What is heat?

Heat can be defined as a form of energy that is transferred from a physical object (body) to another, as a result of a difference in temperature. Also, heat is a condition of weather that is generally characterized by a high degree of temperature.

This ultimately implies that, heat is most likely to cause dehydration and high body temperature.

In order to prevent and cope with heat-related conditions, you should ensure that you drink water at regular intervals for hydration.

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What was the average speed in km/h of a car that travels 788 km in 7.1 h?

Answers

Answer:

Well the answer is 111 (rounded) km/h

Explanation:

788/7.1 is 110.9... so if you round it it would equal 111.

Q4. (a) An acre-foot is the volume of water that would cover 1 acre of flat land to a depth of 1
foot. How many gallons are in 1 acre-foot?

Answers

Answer:

326,000

Explanation:

One acre-foot equals about 326,000 gallons, or enough water to cover an acre of land, about the size of a football field, one foot deep. An average California household uses between one-half and one acre-foot of water per year for indoor and outdoor use.

What is the equivalent resistance of this network?

Answers

The equivalent resistance of the circuit network is determined as 1.6 ohms.

What is the equivalent resistance of the network?

The equivalent resistance of the circuit network is calculated as follows;

To determine the equivalent resistance of the circuit, we will decompose the circuit into series and parallel components.

The equivalent resistance at J₄ is calculated as follows;

The two 4 ohms are in series;

J₄ = 4Ω + 4 Ω = 8 Ω

The equivalent resistance at J₁ is calculated as follows;

The 4 ohms and 0 ohm are in series;

J₁ = 0 Ω + 4 Ω = 4 Ω

The equivalent resistance at J₂ and J₃ is calculated by applying the formula for parallel resistors;

1/Re = 1/J₁  + 1/J₄ + 1/J₂,₃

1/Re = 1/4 + 1/8 + 1/4

1/Re = 5/8

Re = 8/5

Re = 1.6 ohms

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Two students on ice skates stand one behind the other. Student 2 pushes student 1 in the back; student 1 has less mass than student 2; student 1 has a great acceleration than student 2. which law of motion is this (Newton's laws)

Answers

Answer:

law in acting

Explanation:

Stacy collected the data shown in the table.
Number of Washers Total Mass Total Force
0.6 kg 5.9 N
2
1.2 kg 11.8 N
3
1.8 kg 17.6N
4
2.5 kg 24.5 N
5
3.2 kg 31.4 N
What's the general relationship between mass and gravitational force?

Answers

Answer:

1.8 Kg 17.6N

Explanation:

I don't know the explanation hahaha

Answer:

The gravitational force on an object increases as the object’s mass increases.

Explanation:

This is the answer on Edmentum. :)

If a shopping cart is pushed by a person exerting 50 J of work on it, what is the energy transfer to the shopping cart if it has a mass of 2 kg?

A. 52 J
B. 50 J
C. 25 J

Answers

Answer:

B

Explanation:

A flower as an object in front of a convex mirror. A smaller upright flower closer to the mirror. A smaller upright flower close to the mirror on the other side of the mirror. An inverted smaller flower on the on the other side of the mirror just past the focal point. An inverted flower the same size as the object right below it.
Which flower would most likely represent the image formed by the mirror? Justify your answer.

Answers

Answer:

There are 13 a

Explanation:

That's the answer how many a r there

Answer:

the convex mirror will produce image 3. the image is virtual and is now behind the mirror and it becomes smaller but remains upright.

Explanation:

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The organizational department that is in charge of finding, screening, and negotiating prices with suppliers is typically called _______A) Reverse logisticsB) LogisticsC) WarehousingD) ProcurementE) Distribution publicity is considered to be integral to which part of the promotional mix? multiple choice question. A. personal selling B. direct marketingC. public relations D. advertising analyze the parts of the word intermolecular and define intermolecular forces of attraction. Calculate the pOH of a 7. 68x10-7 M HCl solution. pOH = (round to 3 sig figs) a smash and grab burglary is where the perpetrator throws a brick through the window of a business, seizes what can immediately be taken and leaves the scene. true or false? Do the follow reactions depict Heat of Formation Reactions? If so, mark the reaction as YES, if it is not a Heat of Formation Reaction, then choose NO.NoYes CO2(g) + C(gr) 2CO(g)NoYes 2Fe2O3(s) 4Fe(s) + 3O2(g)NoYes H2(g) + 1/2O2(g) H2O(g)NoYes HgS(s) + O2(g) Hg(l) + SO2(g)NoYes Ni(s) + 4CO(g) Ni(CO)4(g) when considering nested environments, one example of variables from the task (operational) environment Fe+ (aq) + SCN (aq) FeSCN+2 (aq) + heatcolorlesscolorlessred-brownWhich stress would result in the student observing a red-brown color in the reaction?A Remove FeSCN+2B Remove SCNC Add FeSCN+D Add heatSave2> Find the area of a regular hexagon with radius 12 in Which of the following is a database organization method commonly used for Big Data applications?Select one:a. Network-attached storage modelb. Temporary-network storage modelc. Directed application network storage modeld. Network-directed storage modele. Highly-structured storage model Nebula Corp's most recent earnings before interest and taxes (EBIT) was $29 million. They increased their net working capital by $4 million and invested $10 million in fixed assets. The firm had $7 million in depreciation expense. The firm's tax rate is 21%. The firm has 10 million shares outstanding and $57 million in long term debt. The firm has $18 million in cash and cash equivalents. What is Nebula's intrinsic value if we assume a weighted average cost of capital of 14%, a cos of equity of 16%, and their free cash flow to the firm grows at a constant rate of a 4%?A. $12.65B. $12.00C. $5.37 Consider the following data for a project to reorganize the office space at Platinum Financial Advisors: Immediate Predecessor(s) Activity A Expected Time (weeks) 5 3 B 2 4 B E 5 7 C, D D F a. Choose the correct network diagram for this project. O A. B. C A 5 Un A 5 E 5 Start Finish Start Finish B 3 D 4 B 3 4 O c. OD. C B 3 E 5 A 5 D 4 E 5 Start Finish Start Finish A 5 D 4 B 3 b. Identify the critical path and estimate the project's duration. The critical path is path and the project duration is weeks. (Enter your response as an integer.) c. Calculate the slack for each activity. (Enter your responses as integers.) Activity Slack (weeks) A B D Please copy and paste data from text area below. Selected delimiter: Comma (weeks), Immediate Predecessor(s) Activity, Expected Time A,5,- B,3,- C,2,A D, 4,B E, 5, "C, D" F,7,D which best describes the overall form of the aria "rejoice greatly" from handels messiah? a cost control method for examining project cost performance over time to determine whether performance is improving or deteriorating is FILL THE BLANK. according to the crowding-out effect, if the government sells bonds to finance spending, _____ can eventually fall. from chapter 14 of pursuing justice book: what is true about the worlds supply of available fresh water? .For each compound, write an equation showing how the compound dissolves in water and write an expression for KspMg(OH)2FeCO3PbS For the subspace below, (a) find a basis, and (b) state the dimension. 9a + 18b - 3c 3a-b-c a, b, c in R - 12a + 5b + 4c - 3a + b + c bc a. Find a basis for the subspace. A basis for the subspace is behavioral manifestations of personality traits are often exhibited with conscious thought rather than automatically.T/f radon-222 decays by a series of three emissions and two emissions. what is the final stable nuclide?