Find the value of x and m

Answer:

C,D

Step-by-step explanation:

C: Range refers to the y axis and all values shown on this graph (and even beyond the graph) are greater than 0

D: The domain refers to the x-axis. The line goes on forever both to the right and the left therefore meaning all x values are used.

Answer:

A

Step-by-step explanation:

$30.00 ÷ 5 = $6.00

$6.00 × 3 = $18.00

Abiding by the two rules, the number of variable names we can have in Python are; 63

The rules for python are given as;

1) Variable names in Python can be any length and can consist of uppercase and lowercase letters ( A-Z, a-z ), digits ( 0-9 ), and the underscore character ( _ ).

1b) An additional restriction is that, although a variable name can contain digits, the first character of a variable name cannot be a digit.

2) We limit each line to 79 characters, so, to be extra careful, we will assume variables can be of at most 7 characters in length.

Now, abiding by the two rules above, the number of variable names we can have in Python are;

26( A-Z) + 26(a-z) + 10(0-9) + 1 ( _ ) = 63 variable names

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1598 cm square is the area of the container.

According to the statement

we have given that the container is rectangular prism

And Length of rectangular prism is 34cm

Width of rectangular prism is 17 cm

Height of rectangular prism is 20 cm

we use the below written formula to find the surface area

Surface area formula A=(wl+hl+hw)

To find the surface area of the container.

Substitute the values of Length, width and height in the formula then

A=(wl+hl+hw)

A=((17)(34)+(20)(34)+(20)(17))

After solving the values

A=(578+680+340)

A= 1598

So, 1598 cm square is the area of the container.

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The dimensions and volume of the largest box formed by the 18 in. by 35 in. cardboard are;

The given dimensions of the cardboard are;

Width = 18 inches

Length = 35 inches

Let x represent the side lengths of the cut squares, we have;

Width of the box formed = 18 - 2•x

Length of the box = 35 - 2•x

Height of the box = x

Volume, V, of the box is therefore;

V = (18 - 2•x) × (35 - 2•x) × x = 4•x³ - 106•x² + 630•x

By differentiation, at the extreme locations, we have;

[tex] \frac{d V }{dx} = \frac{d( 4 \cdot \: {x}^{3} - 106 \cdot \: {x}^{2} + 630\cdot \: {x} ) }{dx} = 0[/tex]

Which gives;

[tex] \frac{d V }{dx} =12\cdot \: {x}^{2} - 212\cdot \: {x} + 630 = 0[/tex]

6•x² - 106•x + 315 = 0

[tex]x = \frac{ - 6 \pm \sqrt{106 ^2 - 4 \times 6 \times 315} }{2 \times 6} [/tex]

Therefore;

x ≈ 4.55, or x ≈ -5.55

When x ≈ 4.55, we have;

V = 4•x³ - 106•x² + 630•x

Which gives;

V ≈ 1048.6

When x ≈ -5.55, we have;

V ≈ -7450.8

The dimensions of the box that gives the maximum volume are therefore;

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The percentage of students age 15 and above travel to school by bus is 47%

The table of values is given as:

                     Method of Travel to School

                            Walk/Bike    Bus    Car Row totals

Under age 15                            18                 165

Age 15 and above    65                                 195

Column totals          152          110        98      360

Using the column total of column 1, we have:

Under age 15 + 65 = 152

This gives

Under age 15 = 87

Using the column total of column 2, we have:

Age 15 and above + 18 = 110

This gives

Age 15 and above  = 92

Using the row total of row 1, we have:

Car + 87 + 18 = 165

This gives

Car = 60

Using the row total of row 2, we have:

Car + 65 + 92 = 195

This gives

Car = 38

So, the complete frequency table is

                     Method of Travel to School

                            Walk/Bike    Bus    Car Row totals

Under age 15           87              18      60        165

Age 15 and above    65          92        38        195

Column totals          152          110        98      360

The percentage of students age 15 and above travel to school by bus is:

Percentage = 92/195 * 100%

This gives

Percentage = 47%

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The general solution of the logistic equation is [tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex].

The particular solution of the logistic equation is [tex]y(t) = \frac{14}{1 + 0.4 \cdot e^{-\frac{14\cdot t}{3} }}[/tex].

In this question we are before a type of ordinary differential equation known as equation with separable variables, that is to say, that variables t and y can be separated at each side of the expression in order to find a solution:

dy / dt = 3 · y · (1 - y /14)

dy / [(- 3 / 14 ) · y · (y - 14)] = dt

Then, we simplify the expression by partial fractions and integrate the resulting expression:

- (1 / 14) ∫ dy / y + (1 / 14)∫ dy / (y - 14) = - (14 / 3)∫ dt

- (1 / 14) · ㏑ |y| + (1 / 14) · ㏑ |y - 14| = - (14 / 3) · t + C, where C is the integration constant.

㏑ |(y - 14) / y| = - (14 / 3) · t + C

[tex]1 - \frac{14}{y} = C\cdot e^{-\frac{14\cdot t}{3} }[/tex]

[tex]\frac{14}{y} = 1 - C \cdot e^{-\frac{14\cdot t}{3} }[/tex]

[tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex]

The general solution of the logistic equation is [tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex].

If y(0) = 10, then the particular solution of the differential equation is:

10 = 14 /(1 - C)

1 - C = 1.4

C = - 0.4

The particular solution of the logistic equation is [tex]y(t) = \frac{14}{1 + 0.4 \cdot e^{-\frac{14\cdot t}{3} }}[/tex].

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There are two real roots for the quadratic equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.

In this question we must apply algebraic handling to simplify a quadratic equation and find the roots that satisfy the expression. Completing the square consists in transforming part of the equation into a perfect square trinomial, and then we clear for x:

x² - 8 · x + 13 = 0

x² - 8 · x + 16 = 3

(x - 4)² = 3

x - 4 = ± √2

x = 4 ± √2

There are two real roots for the quadratic equation x² - 8 · x + 13 = 0, contained in the number x = 4 ± √2.

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110 postcards Xiulin had at first.

Algebric equation is a mathematical statement in which two equation set equal to each other.

Let the number of postcards belonging to Xiulin and Meifang be x.

Let the number of postcard Meifang gave to Xuilin be 'a'

Number of postcard left with meifang

=> x-a = 72                                                              

=> x = 72+a

Meifang had 76 fewer postcards than Xiulin.

so, (x+a)-72=76

   72+a+a-72=76

   2a = 76

   a = 38

meifang give 38 cards to xuilin

x = 72+38

 = 110

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Answer:

Step-by-step explanation:

hello : y = -2x - 5

          y = 2/3x + 3

means :  -2x-5 = 2/3 x+3

-6x-15 = 2x +9

-8x=24   so : x = -3

put the value for : x in the first equation :y = -2(-3)-5  =1

the  ordered pair (-3;1) is solution

The geometric center of the graph under the function is 5/3

The equation of the function is given as:

f(x) = 3 - |x - 2|

The interval is given as:

x ∈ [0, 3]

The geometric center (gc) of the graph under the function is calculated using

gc = ∫x f(x) dx/∫f(x) dx

Substitute the known values in the above equation

gc = ∫x * (3 - |x - 2|) dx/∫3 - |x - 2| dx

Integrate the numerator and the denominator of the above equation

gc = [-1/6(x - 2)((2|x -2| - 9)x + 2|x - 2| - 18)]/[3x - 1/2[|x - 2|(x - 2)]]

Recall that the interval is given as x ∈ [0, 3]

Substitute the interval values in the above equation.

The equation is then simplified using a graphing calculator.

So, we have

gc = (65/6)/(13/2)

Express the quotient expression as a product

gc = (65/6) * (2/13)

Divide 65 by 13

gc = 5/6 * 2

Divide 2 by 6

gc = 5/3

Hence, the geometric center of the graph under the function is 5/3

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Answer:

[tex]tan(30) = \frac{5}{b} [/tex]

Step-by-step explanation:

Trigonometric Ratios.

To solve for b, we check the parameters that are given in the triangle.

If we're considering 30°, we can see that the opposite is given as 5cm and the adjacent is b.

Applying:

[tex]tan \alpha = \frac{oppsite}{adjacent} \\ \\ tan \: (30) = \frac{5}{b} [/tex]

Answer:

a

Step-by-step explanation:

just did the quiz!!!!

The price the widgets should be sold for, to the nearest cent, for the company to make the maximum profit is 62.13

y = -14x² + 1035x - 10266

-14x² + 1035x - 10266 = 0

x = -b ± √b² - 4ac / 2a

= -1035 ± √1035² -4(-14)(-10266) / 2(-14)

= -1035 ± √1071225 - 574896 / -28

= -1035 ± √496329 / -28

x = 1035 / 28 ± √496329 / 28

x = 11.80 or 62.13

The maximum value of x is 62.13

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30 + 110 + 30 + 110 = 280

360-280 = 80

2y = 80

y = 40 degrees

If y is 40. Then the angle next to 30 is also y due to vertically opposite angles.

30 + 40 = 70

The line with 2 arrows is parallel to the line with x degrees. So, I use co-interior angles adds to 180.

In that c shaped, we got the bottom angle to be 70 & the top to be 110 because co-interior angles =180

Forget the c shape exists, and move onto the triangle that's visible. The top angle is 110 as found.

Angles in triangle add to 180.

180 - 110 - 30 = 40.

Thus, x = 40 degrees

There's a short cut I realise now because we can have alternate angles are equal; creating a z shape to find what x is equal to & that turns out to be the same value as y. ( due to vertically opposite angles)

Hope this helps!

The percentage of students age 15 and above travel to school by bus is 47%

The table of values is given as:

                     Method of Travel to School

                            Walk/Bike    Bus    Car Row totals

Under age 15                            18                 165

Age 15 and above    65                                 195

Column totals          152          110        98      360

Using the column total of column 1, we have:

Under age 15 + 65 = 152

This gives

Under age 15 = 87

Using the column total of column 2, we have:

Age 15 and above + 18 = 110

This gives

Age 15 and above  = 92

Using the row total of row 1, we have:

Car + 87 + 18 = 165

This gives

Car = 60

Using the row total of row 2, we have:

Car + 65 + 92 = 195

This gives

Car = 38

So, the complete frequency table is

                     Method of Travel to School

                            Walk/Bike    Bus    Car Row totals

Under age 15           87              18      60        165

Age 15 and above    65          92        38        195

Column totals          152          110        98      360

The percentage of students age 15 and above travel to school by bus is:

Percentage = 92/195 * 100%

This gives

Percentage = 47%

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We can simplify the inequality to:

y > (-1/5)*x - 2

From that, we conclude that the correct option is the last one.

Here we have the inequality:

5y + x > -10

If we isolate y, we get:

y > (-10 - x)/5

y > (-1/5)*x - 2

Then the inequality will be a dashed/dotted line with a negative slope, that passes through the point (0, -2), such that the region above and to the right of the line is shaded.

From that we conclude that the correct option is the last one:

"Number graph ranging from negative ten to ten on the x and y axes. A dotted line passes through (zero, negative two) and (five, negative three). The area above the line is shaded gray."

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It's very simple. Subract 554.26 from 866.32

then, we got the difference is

312.06

thank you

Brainlist please.

Answer:

$21200

Step-by-step explanation:

6% × 20000 = 1200.

20000 + 1200 = 21200

basically yout find 6% of 20000 then add it the original 20000

The amount of paint that would be contained in each of the can would be 8.

Using the information in the question we have the following

We have to solve the equation as

(2  1/2)   + 2(4)  + 1(5  1/2)  =

2.5 + 8 + 5.5

= 16

Each of these would have to hold 16/2 = 8 pints.

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Answer:

4 pints

Step-by-step explanation:

the expert is wrong

Answer:

hexagon and pentagon structure. also known as a truncated icosahedron

Step-by-step explanation:

hope that gives you a good enough description.

The computation illustrate that there'll be 13 cases and 2 additional units.

From the information given, it was stated that 80 units are needed, 6. units per case.

Therefore, the number of cases will be:

= 80/6

= 13 remainder 2.

Therefore, there'll be 13 cases and 2 additional units

Complete information

80 units are needed, 6. units per case. What is the number of cases and the number of additional units?

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The complete  table will be:

Fraction      Decimal       Percent

39/100            0.39           39%

82/100            0.82           82%

22/100           0.22          22%

3/4                   0.75          75%

80/100           0.8             80%

The percentage is the given definition for a fraction whose denominator is equal to 100. It is represented by %. See the following example:

[tex]\frac{25}{100} =0.25*100=25%[/tex]

The percentage is considered a math tool with several applications and areas, for example: medicine, engineering, investments, supermarkets, drugstores,banks  etc.

Fraction      Decimal       Percent

39/100            0.39           0.39*100=39%

Fraction      Decimal       Percent

82/100            0.82         0.82*100=82%

Fraction      Decimal       Percent

22/100           0.22        22%

Fraction      Decimal       Percent

3/4                 0.75        0.75*100=75%

Fraction      Decimal       Percent

80/100           0.8         0.80*100=80%

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Answer:

67 years old. (you only gave 4 people and missed out one person)

Step-by-step explanation:

take all the ages first and put the unknown (age of the person who entered the room) as x.

14, 16, 16, 13, x

all of these numbers added to together would be:

59 + x

Because the question is talking about the mean age, to find mean:

add all the values in the data (ages) and divide by the total number of values on the list. (in your case would be 6 people (following your question) but you gave only 5 people including the x).

then (59 + x) / 6 = 21

21 x 6 = 126

126 = 59 + x

x = 67

Answer:

13/8

Step-by-step explanation:

4 2/8 - 2 5/8

34/8 - 21/8 = 13/8

1 5/8 as a mixed fraction

Answer:

#3 5(2a+4)

#4 5(a+2+4)

#5 5a+5(2+4)

Step-by-step explanation:

I think so, I am probably wrong

Answer:

Answer:the answer is zero

Answer:the answer is zero Step-by-step explanation:

Answer:the answer is zero Step-by-step explanation:when we add -42 and -54 the answer we get is -96. -96and +96 cut each other and then the answer is zero

[tex] - 42 - 54 + 96 = 0[/tex]

We need 56 pints of the 55 % pure fruit juice and 84 pints of the 80 % pure fruit juice to prepare 140 pints of 70 % pure fruit juice.

In this problem we have to use two kinds of juice with different concentrations. To get a certain concentration, we must adjust quantities of each kind and weighted averages offers a method that is easy to apply:

70 · 140 = 55 · x + 80 · (140 - x)

70 · 140 = 80 · 140 - 25 · x

25 · x = 10 · 140

x = 56

We need 56 pints of the 55 % pure fruit juice and 84 pints of the 80 % pure fruit juice to prepare 140 pints of 70 % pure fruit juice.

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The inequalities that match the given expressions are

x ≤ 95

x > 100

5x ≤ 100

20 ≤ x ≤100

respectively

From the question, we are to match the statements with the corresponding inequalities

x ≤ 100 -5

x ≤ 95

x > 100

5x ≤ 100

x ≤ 100

and

x ≥ 1/5 × 100

x ≥ 20 ≡ 20 ≤ x

∴ 20 ≤ x ≤100

Hence, the inequalities that match the given expressions are

x ≤ 95

x > 100

5x ≤ 100

20 ≤ x ≤100

respectively

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Option 4,option 6, and option 2 is the respective contrapositive to the statements given. This can be obtained by understanding what contrapositive is and converting the statements.

Statement = If a figure is a square, then it is a quadrilateral.

Contrapositive = If a figure is not a quadrilateral, then it is not a square.

Here,

Contrapositive: If the corresponding sides of two figures aren't equal, then the two figures aren't congruent. (Option 4)

Contrapositive: If the product of two numbers isn't even, then the two numbers aren't even. (Option 6)

Contrapositive: If the sum of the interior angles of a figure isn't 540°, then the figure isn't a pentagon. (Option 2)    

Hence Option 4,option 6, and option 2 is the respective contrapositive to the statements given.

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[tex]B'=\{f,g,h,p,x\}\\B'\cup A=\{f,g,h,p,q,r,x\}\\(B'\cup A)\cap C=\{g,h,p,q\}[/tex]