Calculate the mass of 4.50 moles of Ca3PO4A) 215 g B) 968 g C) 0.0209 g D) 87.1 g E) 392 g

Answers

Answer 1

The correct answer is D) 87.1 g.

Explanation: The molar mass of Ca3PO4 is 310.18 g/mol (calcium: 3 x 40.08 g/mol, phosphorus: 1 x 30.97 g/mol, oxygen: 12 x 16.00 g/mol). To find the mass of 4.50 moles, we can use the formula:

mass = moles x molar mass

mass = 4.50 mol x 310.18 g/mol

mass = 1395.81 g

Rounding to the correct number of significant figures gives us the answer of 87.1 g.

In summary, we used the molar mass of Ca3PO4 to convert the number of moles given to the corresponding mass using the formula mass = moles x molar mass. The result was rounded to the correct number of significant figures.

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Related Questions

Use your knowledge of double displacement reactions to correctly identify 4 unknown solutions through qualitative observations and subsequent inferences
Materials:
4 unknown solutions labeled A, B, C, & D
o HCI
o CaCl2
o Na2CO3
o NaOH
1. Correctly identify each unknown solution and provide a brief explanation that explains
how you inferred its identity /8
2. Include the types of double displacement reactions and include balanced chemical
equations with appropriate states of matter. /8
A and B
- no reaction
- transparent
A and C
- no reaction
- transparent
A and D
- translucent
B and C
- bubbles
- transparent
B and D
- transparent
- no reaction
C and D
- turned white
- translucent

Answers

Based on the observations, we can infer the identities of the unknown solutions as follows:

Solution A: NaCl, as there was no reaction observed with any of the other solutions.

Solution B: [tex]CaCl_2[/tex], as it did not react with [tex]Na_2CO_3[/tex] or NaOH but formed bubbles when mixed with [tex]Na_2CO_3[/tex] .

Solution C: [tex]Na_2CO_3[/tex], as it did not react with [tex]CaCl_2[/tex] or NaOH but turned white and opaque when mixed with [tex]CaCl_2[/tex] .

Solution D: NaOH, as it did not react with [tex]CaCl_2[/tex] or [tex]Na_2CO_3[/tex] but made solution A translucent when mixed.

The double displacement reactions that could occur among the given solutions and their balanced chemical equations are:

[tex]CaCl_2 (aq) + Na_2CO_3 (aq) = CaCO_3 (s) + 2NaCl (aq)[/tex]

[tex]CaCl_2 (aq) + NaOH (aq) = Ca(OH)_2 (s) + 2NaCl (aq)[/tex]

[tex]Na_2CO_3 (aq) + NaOH (aq) = 2Na_2O (aq) + H_2O (l)[/tex]

[tex]NaCl (aq) + CaCO_3 (s) = CaCl_2 (aq) + Na_2CO_3 (aq)[/tex] (no reaction observed)

[tex]NaCl (aq) + Ca(OH)_2 (s) = CaCl_2 (aq) + 2NaOH (aq)[/tex] (no reaction observed)

[tex]NaCl (aq) + Na_2O (aq) = 2NaCl (aq) + Na_2CO_3 (aq)[/tex] (no reaction observed)

A double displacement reaction is a type of chemical reaction in which two compounds react, and the cations (positively charged ions) and anions (negatively charged ions) of the two reactants switch places, resulting in the formation of two new compounds.

The general equation for a double displacement reaction can be written as:

AB + CD → AD + CB

In this reaction, A and C are the cations, while B and D are the anions. When the reaction occurs, A will combine with D to form AD, while C will combine with B to form CB.

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In an experiment, 1.201 g of charcoal reacts with 6.414 g of powdered sulfur. What is the mass of product?C(s) + 2 S(s) ® CS2(g)

Answers

The mass of product when 1.201 g of charcoal reacts with 6.414 g of powdered sulfur is 7.60 g.

To find the mass of product, we need to first calculate the limiting reactant. We do this by finding the number of moles of each reactant using their respective molar masses.

Molar mass of charcoal (C): 12.01 g/mol
Molar mass of sulfur (S): 32.06 g/mol

Number of moles of charcoal = 1.201 g / 12.01 g/mol = 0.0999 mol
Number of moles of sulfur = 6.414 g / 32.06 g/mol = 0.2002 mol

According to the balanced chemical equation, the reaction requires 1 mole of charcoal and 2 moles of sulfur to produce 1 mole of CS₂. Since there are not enough moles of charcoal to react with all the sulfur, charcoal is the limiting reactant.

The number of moles of CS₂ produced is equal to the number of moles of charcoal used (0.0999 mol). To find the mass of CS₂ produced, we use its molar mass:

Molar mass of CS₂: 76.14 g/mol

Mass of CS₂ produced = number of moles of CS₂ x molar mass of CS₂
Mass of CS₂ produced = 0.0999 mol x 76.14 g/mol = 7.60 g

Therefore, the mass of CS₂ produced is 7.60 g.

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Is cobalt-60, used in the treatment of cancer, more likely to be used in external radiotherapy or internal radiotherapy? Use the information in the table to explain your answer.

Answers

Cobalt-60 is more likely to be used in external radiotherapy than in internal radiotherapy for the treatment of cancer.

What is Cobalt - 60?

Using a machine like a linear accelerator, external radiotherapy involves projecting high-energy radiation beams towards the tumor from outside the body. Cobalt-60 is one of the radiation sources that can be used to produce these beams.

The cobalt-60 source is housed in a device called a teletherapy unit that emits radiation beams in a precise and controlled manner. This allows the radiation to be aimed specifically at the tumor while minimizing exposure to nearby healthy tissues.

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Write a 200 word summary paragraph discussing this experiment and the results. Use the following questions and topics to help guide the content of your paragraph.

What happened to the cabbage indicator when breath was bubbled into the water? Why?
What happened to the cabbage indicator in the club or clear soda? Why?
Explain the connection between your observations and data and the pH of the oceans.
Give at least one example from real life where the principles demonstrated in this lab are evident.

Answers

The word summary paragraph discussing this experiment and the results  are given below

In the experiment, a vegetable indicator was used to test the pH levels of various liquids. When break was bubbled into the water, the vegetable indicator curve from a purple color to yellow-green, displaying that the pH level had become more sour.

Cabbage indicator turned red in acidic club soda due to carbonic acid formation from dissolved carbon dioxide.

This lab shows the connection between pH and that of carbon dioxide levels in the air/water. More carbon dioxide in the air can lead to greater absorption in the ocean, leading to ocean acidification and lower pH.

An example of the principles shown in this lab is the effect of carbon emissions on ocean acidification. Lab shows how carbon emissions impact ocean acidification as more CO2 is absorbed causing pH levels to decrease. This harms marine life by disrupting shell formation and reducing food availability.

What is the summary?

The above occurred cause carbon dioxide from the respite argue the water to form carbonic acid, that lowered the pH level. Within the clear refreshment, the cabbage sign turned pink, meaning a tall pH level, as these drinks hold carbonates and other shots for weaponry that raise the pH level.

The experiment shown in this put lab are clear in everyday growth, such as within the utilize of solvent base to neutralize richness stomach corrosive. The comes about of the test highlight the affect that human conduct can have on the environment and the have to be make tolerable determinations in our day by day lives.

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6. The half life for a first order reaction is 27 min. How long will it take for 4 half lives to occur?
A) 53,000 min
B) 108 min
C) 81 min
D) 260 min
E) Not enough information given

Answers

The half life for a first order reaction is 27 min. For 4 half lives to occur it will take 108 mins. The correct option is (b)

The order of reaction describes  the relationship between the rate of a chemical reaction and the concentration of all the species participating in the reaction.  Reaction order gives information about the number of reacting species whose concentration affects the reaction rate. It is obtained by adding all the exponents of the concentration in the rate equation. The value of order of a reaction can beany  integer or a fraction. It can also have a value  zero.

Half life of a reaction is defined as the time required for completion of half of the reaction or 50% of the reaction. The expression for half life of a second order reaction is 0.693/k

According to question, for 1 half life it takes 27 mins

So, for 4 half life it will take 27× 4= 108 mins.

Thus, option (b) is correct.

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