Can someone answer this for me

The equation of the line in standard form is 6x - 7y = - 11

The standard form for linear equations in two variables is Ax + By = C.

Therefore, using (-3, -1)(1 / 2, 2)

y = mx + b

where

Hence,

m = 2 + 1 / 1  /2 + 3 = 6 / 7

Hence,

-1 = 6 / 7(-3) + b

- 1 = - 18 / 7 + b

-1 + 18 / 7 = b

b =  -7 + 18/ 7

b = 11 / 7

Therefore,

y = 6 / 7 x + 11 / 7

Using the standard form,

6 / 7 x - y = - 11 / 7

6x - 7y = - 11

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The linear equation in standard form is:

6x - 7y = -11

Which is the last option.

The line in slope-intercept form is written as:

y = a*x + b

We can see that the line passes through the points (-3, -1) and (1/2, 2), then the slope is:

[tex]a = \frac{2 - (-1)}{1/2 - (-3)} = \frac{3}{3.5} = \frac{6}{7}[/tex]

Then we can write:

y = (6/7)*x + b

To find the value of b, we use the first point. It means that when x = -3, the value of y is -1, then we get:

-1 = (6/7)*-3 + b

-1 + 18/7 = b

-7/7 + 18/7 = b

11/7 = b

Then the equation is:

y = (6/7)*x + 11/7

If we multiply both sides by 7 we get:

7y = 6x + 11

Now we move the term with "x" to the left:

7y - 6x = 11

That is the line in standard form.

If we multiply both sides by -1, we get the last option:

6x - 7y = -11

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