Case A is 12 times heavy than Case B,Case B is 16 times heavy than case C. If case A is 8,640 g, what is the weight of case C

Answer: a=2 b= -2 c= -2

Step-by-step explanation: you replace y with a and you plug the x for them in so a= -1^2 -3 (-1) - 2 and you solve that to equal 2 then you solve for the others

There are two real solutions if the radicand is positive.

There is one real solution if the radicand is zero.

There are no real solutions if the radicand is negative.

In mathematics, the radicand refers to the value inside a square root (√) symbol. In the given equations and solutions, we can see that there are square root symbols involved, and we can determine the nature of the solutions based on the sign of the radicand.

For the first equation, y = -16x² + 32x - 10, the solutions for x are given as x = (-32 ± √384) / -32. The radicand in this case is 384. Since 384 is positive, greater than 0, there will be two real solutions for x.

For the second equation, y = 4x² + 12x + 9, the solutions for x are given as x = (-12 ± √0) / 8. The radicand in this case is 0. Since the square root of 0 is 0, there is only one real solution for x in this case.

Therefore, For the third equation, y = 3x² - 5x + 4, the solutions for x are given as x = (5 ± √(-23)) / 6. The radicand in this case is -23. Since the square root of a negative number is not a real number, there are no real solutions for x in this case.

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See full text below

Study the solutions of the three equations on the right. Then, complete the statements below. There are two real solutions if the radicand is There is one real solution if the radicand is There are no real solutions if the radicand is 1. y = negative 16 x squared + 32 x minus 10. x = StartFraction negative 32 plus-or-minus StartRoot 384 EndRoot Over negative 32 EndFraction. 2. y = 4 x squared + 12 x + 9. x = StartFraction negative 12 plus-or-minus StartRoot 0 EndRoot Over 8 EndFraction. 3. y = 3x squared minus 5 x + 4. x = StartFraction 5 plus-or-minus StartRoot negative 23 EndRoot Over 6 EndFraction.

Answer: The sequence modeling the amount of money in Samuel’s savings account is a recursive sequence. Each term in the sequence is determined by adding $75 to the previous term. The first term in the sequence is $100, representing Samuel’s initial deposit. After n months, the amount of money in Samuel’s savings account can be calculated using the formula An = An-1 + 75, where An represents the amount of money in his account after n months and An-1 represents the amount of money in his account after n-1 months.

For example, after 1 month, the amount of money in Samuel’s savings account will be A1 = A0 + 75 = 100 + 75 = $175. After 2 months, the amount of money in his account will be A2 = A1 + 75 = 175 + 75 = $250. And so on.

Answer:

D

Step-by-step explanation:

given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the turning point ( vertex ) is

[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]

y = 2x² + 4x - 3 ← is in standard form

with a = 2, b = 4 , then

[tex]x_{vertex}[/tex] = - [tex]\frac{4}{2(2)}[/tex] = - [tex]\frac{4}{4}[/tex] = - 1

substitute x = - 1 into the equation for corresponding y- coordinate

y = 2(- 1)² + 4(- 1) - 3 = 2(1) - 4 - 3 = 2 - 7 = - 5

turning point = (- 1, - 5 )

Answer:

The Correct answer is D

(-1,-5)

An iterated integral for the given function f and region d is  [tex]\int\limits^1_0 \int\limits^2_y {x+y} \, dx dy[/tex].

What is integral?

An integral is the continuous equivalent of a sum in mathematics, where sums are used to compute areas, volumes, and their generalizations. One of the two basic operations in calculus, along with differentiation, is integration, which is the process of computing an integral.

Here, we have

Given: Consider the following F(x, y) = x + y YA (1,1) D 0 2 x

Equation of line passes through (2,0),(1,1)

= (y - y₁)/(y₂ - y₁) =  (x - x₁)/(x₂ - x₁)

=  (y - 0)/(1 - 0) =  (x - 2)/(1 - 2)

= y/1 = (x-2)/(-1)

y = -x + 2

x = 2-y

∫∫F(x,y)dA = [tex]\int\limits^0_1 \int\limits^2_y {f(x,y)} \, dx dy[/tex]

∫∫F(x,y)dA = [tex]\int\limits^1_0 \int\limits^2_y {x+y} \, dx dy[/tex]

Hence,  an iterated integral for the given function f and region d is  [tex]\int\limits^1_0 \int\limits^2_y {x+y} \, dx dy[/tex].

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The turn the minute hand made is about 180 degrees when Mark finished his lunch.

To calculate time with angle, you need to know the angle between the hour hand and the minute hand. With that, you can use the formula

θ = 30H - 11/2M

where H is the current hour and M is the current minute.

Once you calculate the angle, you can use the formula

t = θ/30 to find the elapsed time in hours and decimal fractions of an hour.

The minute hand of a clock makes a full revolution (360 degrees) in 60 minutes (1 hour). Therefore, in 30 minutes, the minute hand will turn half the way around the clock face, which is 180 degrees.

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The complete question is: "Mark took 30minutes to finish lunch describe the turn the minute hand made when he finished his lunch".

The correct answer is D. Trapezoid EFGH is congruent to Trapezoid ABCD after undergoing transformation D.

Let's first define the transformations:

A. Translation down, followed by rotation of 90°, followed by dilation by a scale factor of 3.

B. Rotation of 45°, followed by a reflection, followed by a translation left.

C. Dilation by a scale factor of 12, followed by a translation up, followed by a reflection.

D. Reflection, followed by a dilation of a scale factor of 1, followed by a rotation of 180°.

To determine if Trapezoid EFGH is congruent to, an enlargement of, or a reduction of Trapezoid ABCD, we need to analyze the effects of each transformation on the trapezoid.

A. Translation down, followed by rotation of 90°, followed by dilation by a scale factor of 3.

This transformation involves moving the trapezoid down, rotating it 90 degrees clockwise, and then increasing its size by a scale factor of 3. This transformation does not preserve angles or side lengths, so Trapezoid EFGH is not congruent to Trapezoid ABCD.

B. Rotation of 45°, followed by a reflection, followed by a translation left.

This transformation involves rotating the trapezoid 45 degrees clockwise, reflecting it across a line of reflection, and then moving it left. This transformation does not preserve angles or side lengths, so Trapezoid EFGH is not congruent to Trapezoid ABCD.

C. Dilation by a scale factor of 12, followed by a translation up, followed by a reflection.

This transformation involves increasing the size of the trapezoid by a scale factor of 12, moving it up, and then reflecting it across a line of reflection. This transformation does not preserve angles or side lengths, so Trapezoid EFGH is not congruent to Trapezoid ABCD.

D. Reflection, followed by a dilation of a scale factor of 1, followed by a rotation of 180°.

This transformation involves reflecting the trapezoid across a line of reflection, then increasing its size by a scale factor of 1 (i.e., not changing its size), and then rotating it 180 degrees. This transformation preserves angles and side lengths, so Trapezoid EFGH is congruent to Trapezoid ABCD.

Therefore, the correct answer is D. Trapezoid EFGH is congruent to Trapezoid ABCD after undergoing transformation D.

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Answer:

Step-by-step explanation:

V=15

fraction of cylinder volume is=22

Answer:

Step-by-step explanation:

The solution to the given problem of the unitary method comes out to be Plan A and Plan B thus lasting for a total of 1.25 hours each.

Finish the project using the tried-and-true basic methodology, the actual variables, and any pertinent knowledge you gain from the broad and specific questions. In response, customers might be given another opportunity to sample the expression the products. We'll miss out on important breakthroughs in programming comprehension if these changes don't take place.

Here,

Let's say that Plan A's duration is "a" hours and Plan B's duration is "b" hours.

=> Equation 1: 6a + 2b = 10.

=>  Equation 2: 3a + 5b = 10.

To get rid of "a," multiply Equation 1 by 3 and Equation 2 by 6 and you get:

=> Equation 3: 18a + 6b = 30

=> Equation 4: 18a + 30b = 60

Equation 3 minus Equation 4 results in:

=>  24b = 30

When we multiply both sides by 24, we get:

=> b=30/24=5/4=1.25 hours.

The value of "b" can now be reinserted into Equation 3 to find "a":

=> 18a + 6(1.25) = 30

=> 18a + 7.5 = 30

=> 18a = 30 - 7.5

=> 18a = 22.5

When we multiply both sides by 18, we get:

=> if a = 22.5/18 then 1.25 hours.

Plan A and Plan B thus last for a total of 1.25 hours each.

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Therefore, we can say: limit sin(x) as x approaches pi/2 does not exist lim sin(x) as x approaches 0 = 0.

Although the function (sin x)/x is not defined at zero, it approaches 1 arbitrarily close as x approaches zero. In other words, when x gets closer to zero, the limit of (sin x)/x = 1.

We can put g(x) equal to -1/x and h(x) equal to 1/x because sin(x) is always between -1 and 1. As x approaches either positive or negative infinity, we know that the limit of both -1/x and 1/x is zero, and as a result, the limit of sin(x)/x is also zero.

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To sketch three solutions with initial values y(0) > 0, y(0) = 0, and y(0) < 0, we'll need to use a differential equation or system of differential equations. So, to sketch three solutions with initial values y(0) > 0, y(0) = 0, and y(0) < 0, we would first draw a slope or direction field for our differential equation. Then, we would start at the point (0, y(0)) and follow the direction of the slope or arrow to sketch the solution for each initial value.
To sketch three solutions with the given initial values, follow these steps:
1. Determine the differential equation you're working with. For example, let's consider the equation y'(t) = y(t). This is just an example, and the process will be similar for other differential equations.
2. Solve the differential equation to obtain a general solution. In our example, the general solution is y(t) = C * e^t, where C is an arbitrary constant.
3. Apply the initial values to find specific solutions:
  a. For y(0) > 0, choose a positive value for C, such as C = 1. The specific solution is y(t) = e^t.
  b. For y(0) = 0, choose C = 0. The specific solution is y(t) = 0.
  c. For y(0) < 0, choose a negative value for C, such as C = -1. The specific solution is y(t) = -e^t.
4. Sketch the three solutions on the same graph:
  a. For y(t) = e^t, draw a curve that starts at (0,1) and increases exponentially as t increases.
  b. For y(t) = 0, draw a horizontal line at y = 0.
  c. For y(t) = -e^t, draw a curve that starts at (0,-1) and decreases exponentially (toward 0) as t increases.
These three curves represent the solutions with the specified initial values. Note that this process assumes you have a specific differential equation in mind. If you have a different equation, just follow the same steps to find and sketch the solutions.

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Answer: Hi! Read the explanation below:

Brainliest?

Step-by-step explanation:

Let's use the variables x and y to represent the number of bags of soil and plants, respectively, that Katte will buy.

The cost of x bags of soil is $4x, and the cost of y plants is $10y. Therefore, the total cost of Katte's purchases is:

$4x + $10y

We want to make sure that she doesn't spend more than $100, so we can write:

$4x + $10y ≤ $100

We also want to make sure that she buys at least 5 plants, so we can write:

y ≥ 5

Finally, we want to make sure that both x and y are non-negative, since you can't buy negative bags of soil or plants. Therefore, we can write:

x ≥ 0

y ≥ 0

Putting it all together, the system of linear inequalities is:

4x + 10y ≤ 100

y ≥ 5

x ≥ 0

y ≥ 0

To graph this system, we can start by graphing the boundary lines for each inequality. The boundary for 4x + 10y ≤ 100 is the line 4x + 10y = 100, which we can graph by finding two points on the line:

When x = 0, we have 10y = 100, so y = 10. Therefore, one point on the line is (0, 10).

When y = 0, we have 4x = 100, so x = 25. Therefore, another point on the line is (25, 0).

Plotting these two points and connecting them with a line gives us the boundary for 4x + 10y ≤ 100:

       |

   11  |      o

       |

   10  |           o

       |

    9  |              o

       |

    8  |                 o

       |

    7  |                    o

       |

    6  |                       o

       |

    5  |                          o

       |

--------|-----------------------------    

       0    25

The boundary for y ≥ 5 is the horizontal line y = 5. We can graph this line by plotting two points on the line:

When x = 0, we have y = 5, so one point on the line is (0, 5).

When x = 100/4 = 25, we still have y = 5, so another point on the line is (25, 5).

Plotting these two points and connecting them with a line gives us the boundary for y ≥ 5:

lua

       |

       |    

       |

       |    

       |

       |    

    5  |-----------------------

       |

       |

       |

       |

       |

--------|-----------------------------    

       0    25

Finally, the boundaries x ≥ 0 and y ≥ 0 are simply the x and y axes, respectively. We can graph them as:

diff

       |

       |    

       |

       |    

       |

       |    

       |

       |

       |

--------|-----------------------------    

       0    25

Putting it all together, the graph of the system of linear inequalities looks like:

       |

   11  |      o

       |

   10  |           o

       |

    9  |              o

       |

    8  |                 o

       |

    7  |                    o

       |

    6  |                       o

       |

    5  | o----------------------

       |

       |    

       |

If cosA = 24/25 tanB = 4/3 and angles A and B are in Quadrant I. The value of tan(A-B) is -23/33.

We can start by using the identity: tan(A - B) = (tan A - tan B)/(1 + tan A tan B)

From the given information, we have:

cos A = 24/25, which means sin A = sqrt(1 - cos^2 A) = 7/25 (since A is in Quadrant I)

tan B = 4/3, which means sin B = 4/sqrt(4^2 + 3^2) = 4/5 and cos B = 3/sqrt(4^2 + 3^2) = 3/5

Now, we can use the definitions of sine and cosine to find tan A:

tan A = sin A / cos A = (7/25)/(24/25) = 7/24

Substituting the values we have found into the formula for tan(A - B), we get:

tan(A - B) = (tan A - tan B)/(1 + tan A tan B)

= [(7/24) - (4/3)]/[1 + (7/24)(4/3)]

= (-13/72)/(25/72)

= -13/25

Therefore, tan(A - B) = -13/25.

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Answer:

We can start by using the Pythagorean identity to simplify the expression for cos J:

cos^2(J) + sin^2(J) = 1

Since we are given the value of sin J, we can substitute and solve for cos J:

cos^2(J) + (4/√82)^2 = 1

cos^2(J) + 16/82 = 1

cos^2(J) = 66/82

cos(J) = ±√(66/82)

We want to express cos J in simplest radical form, so we can simplify the square root by factoring out the greatest perfect square factor of the numerator:

cos(J) = ±√[(2311)/(2*41)]

cos(J) = ±(√2/2) * (√33/√41)

Since J is in the first or second quadrant (based on the given value of sin J), we know that cos J is positive, so we can drop the negative sign:

cos(J) = (√2/2) * (√33/√41)

Therefore, the exact value of cos J in simplest radical form is (√2/2) * (√33/√41).

A rhombus is a quadrilateral with all four sides of equal length. When AB¯¯¯¯¯¯ || CD¯¯¯¯¯¯ and AB¯¯¯¯¯¯ ≅ CD¯¯¯¯¯¯, we know that ABCD is a parallelogram with opposite sides parallel and equal in length. The correct Answer is B.

To show that it is a rhombus, we need to prove that all four sides are equal.

Since the diagonals of a parallelogram bisect each other, we know that AP = CP and BP = DP.

If we can show that BC = AD, we can conclude that ABCD is a rhombus.

Using the fact that AB¯¯¯¯¯¯ || CD¯¯¯¯¯¯, we can show that ΔABP ≅ ΔCDP

Therefore, we have: BP/DP = AB/CD

Hence, the correct answer is B.

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The statement "When eliminating a loop-carried dependency that adds a constant, the closed-form direct solution will likely contain a multiplication" is true because eliminating a loop-carried dependency that adds a constant simplifies the equation, but to obtain a closed-form direct solution, we need to express the result as a function of the current iteration's variables only

When eliminating a loop-carried dependency that adds a constant, the closed-form direct solution will likely contain a multiplication. This is because the loop-carried dependency adds a constant to the result of the previous iteration, which means that the current iteration's result is a function of both the current iteration's variables and the previous iteration's result.

By eliminating this dependency, we remove the need to use the previous iteration's result, which simplifies the equation. However, to obtain a closed-form direct solution, we need to express the result as a function of the current iteration's variables only, which often involves a multiplication. This is because multiplication is a fundamental mathematical operation that allows us to combine variables in a way that preserves their individual values.

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True. When eliminating a loop-carried dependency that adds a constant, the closed-form direct solution will likely contain a multiplication. This is because the loop-carried dependency is typically expressed as an addition, and removing it would result in a product of the loop index and the constant.

when eliminating a loop-carried dependency that adds a constant, the closed-form direct solution will likely contain a multiplication. This is because the process often involves applying mathematical transformations that result in multiplications to simplify the loop and eliminate dependencies.

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The scale factor is one half

To find the scale factor, we can compare the side lengths of triangle D and triangle D′.

Let's compare the side lengths that are given for both triangles:

Triangle D has a side length of 4.2, and triangle D′ has a corresponding side length of 2.1.

Scale factor = (Side length of triangle D′) / (Side length of triangle D)

Scale factor = 2.1 / 4.2

Scale factor = 0.5

The scale factor used is 0.5, which corresponds to the first option, "one half".

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The values of x using the X method are x = -2 and x = 5/3, or in decimal form: x = -2, x = -1.33, and x = 0.83.

Using the X method:

x + 2 = 0 or 6x - 10 = 0

x = -2 or x = 10/6 = 5/3

Therefore, the solutions are x = -2 and x = 5/3, or in decimal form: x = -2, x = -1.33, and x = 0.83.

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Answer:

The analysis is given below :

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To find A's best response to B choosing L in normal form game, we can compare the payoffs for A choosing H and L when B chooses L.

If A chooses H and B chooses L, then A's payoff is 0 and B's payoff is 6.

If A chooses L and B chooses L, then A's payoff is 3 and B's payoff is 3.

Comparing the payoffs, we see that A gets a higher payoff if he chooses H when B chooses L. Therefore, A's best response to B choosing L is H.

To find B's best response to A choosing L, we can compare the payoffs for B choosing H and L when A chooses L.

If A chooses L and B chooses H, then A's payoff is 9 and B's payoff is 4.

If A chooses L and B chooses L, then A's payoff is 3 and B's payoff is 3.

Comparing the payoffs, we see that B gets a higher payoff if he chooses L when A chooses L. Therefore, B's best response to A choosing L is L.

So, the answer is (c) L;H. A's best response to B choosing L is H, and B's best response to A choosing L is L.

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The model of local restaurant which sends a 20% off coupon to its email subscribers, based on past data is an example of supervised model.

Supervised model is defined by its use of labeled datasets to train algorithms based on classification of data or predict outcomes accurately. While the accuracy of supervised learning models is more than unsupervised learning models. Supervised, as we are using past data. Classification, as we are trying to classify the customers into categories to study which ones will use the coupons. We have a local restaurant which send

a 20% off on a coupon to its email subscribers. It is based on past data. Using the above definition the predicted model for the provide example is supervised model.

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Answer:       This is called percent error this is how i solve.

                    8     20%

                    3     100%

          800. 60 =               48000          

The distance that the car travelled on 1 gallon of gasoline is 71 1/20. (option d).

Let's start by finding how far the car can travel on 1/3 gallon of gasoline. We can do this by dividing 50 3/4 by 1 2/3. To divide fractions, we invert the divisor and multiply. So we have:

50 3/4 ÷ 1 2/3 = 50 3/4 × 3/5 = 153/4

This means that the car can travel 153/4 miles on 1 2/3 gallons of gasoline.

Now, we can use the unitary method to find how far the car can travel on 1 gallon of gasoline. We know that the car can travel 153/4 miles on 1 2/3 gallons of gasoline, so we can set up a proportion:

1 2/3 gallons ÷ 153/4 miles = 1 gallon ÷ x miles

To solve for x, we can cross-multiply:

1 2/3 × x = 1 × 153/4

We can simplify the left side by converting 1 2/3 to an improper fraction:

5/3 × x = 153/4

To solve for x, we can cross-multiply again:

5/3x = 153/4 × 3/5

Simplifying both sides, we have:

x = 153/4 × 3/5 ÷ 5/3 = 229/20

So the car can travel 229/20 miles on 1 gallon of gasoline.

To check our answer, we can use the unitary method again to find how far the car can travel on 1 2/3 gallons of gasoline using our answer for how far the car can travel on 1 gallon of gasoline. We have:

1 gallon ÷ 229/20 miles = 1 2/3 gallons ÷ y miles

Simplifying both sides, we have:

20/229y = 3/5

Solving for y, we have:

y = 3/5 × 229/20 ÷ 20/229 = 71 1/20

Therefore, the answer to the question is (d) 71 1/20.

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We have to make a suspicion based on the given data. The standard deviations of the three bunches are not given within the address, so we cannot straightforwardly decide whether the condition of equal standard deviations is met. Be that as it may, ready to make a few taught surmises based on what we know almost each gather.

The primary gather, which did not think about, is likely to have a bigger change in scores than the other two bunches since understudies with shifting levels of arrangement and capacity took the test. Subsequently, we might anticipate the standard deviation of this group to be bigger than that of the other two bunches.

It is conceivable that the condition of rise to standard deviations isn't met. In case the condition of equal standard deviations isn't met, we may require to utilize an altered adaptation of ANOVA, such as Welch's ANOVA, which does not expect a rise in changes. 

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Answer:

The maximum number of data points that may not actually be on the line of best fit for 16 data points is 15 (Option A). This is because a line of best fit is an approximation of the relationship between the variables being studied, and it is unlikely that all data points will fall exactly on the line.

Step-by-step explanation:

To determine the line of best fit, a regression analysis can be performed. This involves finding the equation of the line that best represents the relationship between the variables. The line of best fit minimizes the distance between each data point and the line.

However, even with a perfect line of best fit, there may still be some data points that do not fall exactly on the line. This is due to natural variability in the data and measurement error.

Therefore, it is possible for all 16 data points to fall on the line of best fit, but it is more likely that some points will deviate slightly from the line. The maximum number of data points that may not actually be on the line is 15.

the value of f(6) is -972.To understand why f(6) is equal to -972, we can think of the recursive formula as a process that generates a sequence of numbers. Starting with f(1) = 4, we can apply the formula repeatedly to generate the sequence:

4, -12, 36, -108, 324, -972, ...

How to solve the question?

We can use the recursive formula given to find the value of f(6). Let's start by calculating f(2):

f(2) = -3f(1) = -3(4) = -12

Next, we can calculate f(3) using the same formula:

f(3) = -3f(2) = -3(-12) = 36

We can continue this process for f(4) and f(5):

f(4) = -3f(3) = -3(36) = -108

f(5) = -3f(4) = -3(-108) = 324

Finally, we can use the formula to find f(6):

f(6) = -3f(5) = -3(324) = -972

Therefore, the value of f(6) is -972.

To understand why f(6) is equal to -972, we can think of the recursive formula as a process that generates a sequence of numbers. Starting with f(1) = 4, we can apply the formula repeatedly to generate the sequence:

4, -12, 36, -108, 324, -972, ...

Each term in the sequence is obtained by multiplying the previous term by -3. We can see that the sequence alternates between positive and negative values, with the magnitude of each term growing rapidly. By the time we reach f(6), the magnitude has grown to 972, and the negative sign indicates that the term is negative. Thus, f(6) is equal to -972.

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Based on the function f(x) = 3 - x², the value of f(-2) include the following: f(-2) = -1.

In Mathematics and Geometry, a function can be defined as a mathematical expression which is typically used for defining and representing the relationship that exists between two or more variables such as an ordered pair in tables or relations.

In Mathematics and Geometry, a domain is sometimes referred to as input value and it can be defined as the set of all real numbers for which a particular function is defined.

When the domain (input value) of the given function f(x) is -2, the output value (range) is given by;

f(x) = 3 - x²

f(x) = 3 - (-2)²

f(x) = 3 - 4

f(x) = -1

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Andrew has $28, and Matthew has 5 times that amount, or $140.

The term "amount" typically refers to a quantity or sum of something. It can refer to a physical quantity of something, such as the amount of water in a glass, or an abstract quantity, such as the amount of time it takes to complete a task.

Let x be the amount of money that Andrew has.

Then, the amount of money that Matthew has is 5 times x, which is 5x.

Together, they have a total of $168, so we can write an equation:

x + 5x = 168

Simplifying, we get:

6x = 168

Dividing both sides by 6, we get:

x = 28

Therefore, Andrew has $28, and Matthew has 5 times that amount, or $140.

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