The highest point in a ball's trajectory is when it is thrown vertically. The average speed of a plane is 254 m/s/s. A carousel rotates continuously.
What is the unit for speed?seconds per metre Miles per hour (mph), kilometres per hour (km/h), and metres per second (m/s) are the three most popular speed units (mph). The distance an object covers in a given amount of time is its speed. Speed equals distance x time is the speed equation.
Who defined speed?Galileo Galilei, an Italian physicist, is typically attributed with being the first to quantify speed by taking into account the distance travelled and the time required. Galileo defined speed as the amount of distance travelled in a given amount of time.
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consider the train car described in the previous part. another experiment is conducted in it: a net force of 20n 20 n is applied to an object of mass 5kg 5 k g . can you determine the acceleration of the object with respect to the train, and, if so, what is its value? consider the train car described in the previous part. another experiment is conducted in it: a net force of is applied to an object of mass . can you determine the acceleration of the object with respect to the train, and, if so, what is its value? yes; 0.25m/s2 0.25 m / s 2 . yes; 4.0m/s2 4.0 m / s 2 . yes; 100m/s2 100 m / s 2 . no; there is not enough information.
The acceleration of the object can be determined using the force exerted and mass. The acceleration of the object is with the mass of 5 kg having a net force of 20 N is 4 m/s².
What is acceleration ?Acceleration of an object is the rate of change in its velocity. Like velocity, acceleration is a vector quantity thus having both magnitude and direction.
According to Newton's second law of motion, force exerted on an object is the product of its mass and acceleration. Greater the force, the object will be accelerated more.
F = ma
given m = 5 kg
F = 20 N
a = F/m
= 20 N/ 5 kg
= 4 m/s²
Therefore, the acceleration of the object is 4 m/s².
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A hydraulic system is designed to lift a maximum weight of 10,000 N. If the output piston has a diameter of 10 cm, what should be the diameter of the input piston?
The toy store created a display of s shelves of remote control cars. Each shelf contains 16 cars. Choose the expression that shows how many cars are on the display.
"The expression that shows number of remote control cars on the display self is 16s."
In order to create a mathematical expression, you need at least two numbers, variables, one arithmetic procedure, and a statement. In order to determine the total number of items in all of the self, we must multiply the number of self (n) by the number of self (x).
On a display stand, 16 remote-control vehicles are present. There are s display racks in total.
Therefore, there will be 16 times as many vehicles overall as s.
16 vehicles are displayed.
As a result, the expression '16s' indicates that there are 16 cars on exhibit.
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A flask contains 1313 mole of H2H2 and 2323 mole of HeHe. Compare the force on the wall per impact of H2H2 relative to that for HeHe.
Answer: The force exerted on the wall by He is twice than by H2.
Explanation: I believe this is the answer because:
Pressure is defined as the force per unit area.
It means that pressure is directly proportional to the force. If the pressure is increased, more force will be exerted on the walls of the container.
According to Henry’s law, the partial pressure of gas in the gas mixture is directly proportional to the mole fraction of the gas.
Among the given gas mixture, the mole fraction of He is twice more than that of H2. So, the pressure exerted by the He gas is two times greater than H2.
Hence, the force exerted on the wall will be greater by He than by H2.
The ratio of the impact of the gases is:
H2 over He = 1/3 over 2/3 - 1 : 2
Therefore, the force exerted on the wall by He is twice than by H2.
I hope this helps!
please answer this question!!
Answer:
Explanation:
difícil
A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 7.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 57 J of kinetic energy?
The work-energy theorem states that an object's kinetic energy changes as a result of the net work done on it.
Describe energy?Energy is referred to by scientists as the capacity for work. Energy is the force that moves things, and since people have figured out how to convert it from one form to another and use it to do labour, modern civilization is possible. Potential energy and kinetic energy are the two categories of energy.
Describe a force?An object can be made to move by force. It is applied to an item in the same manner as addition—adding one thing to another. Magnitude: A force's strength is typically described by its magnitude
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What is the power consumed across AB?
The power consumed across AB would be 4W.
What Is a Resistor?A passive electrical component called a resistor prevents the flow of electric current by introducing resistance. They are prevalent in practically all electrical networks and electronic circuits. Ohms () are used to measure resistance. An ohm is the resistance that develops when a resistor has a one-volt (V) drop between its terminals and a one-ampere (A) current flows through it.
Five resistors in total are positioned at various points in the terminal AB in the preceding diagram. We must now determine the five resistors' equivalent resistance.
Let's split it into two sections. Two resistors make up the part below and three resistors make up the part above.
Now, we must determine the part's actual resistance.
Req=(r1r2/ r1+r2)×r3 * (r1r2/ r1+r2+r3)⇒Req=7×721∴Req=7/3
The obtained resistance is then parallel to the below traitor and in series with the neighboring resistor.
The net effective resistance will therefore be b,
Req=7/3+7=28/3\s⇒Reff=28/3×7/49/3∴Reff=4Ω
As a result, the power through terminal AB will be as follows:
P=1×4=4W.
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A reaction was predicted to produce 32. 4 grams of a compound. When the product was measured, there were only 26. 1 grams made. What is the percent yield of this reaction?.
The percent yield of this reaction is 80.6%. This means that only 80.6% of the predicted amount of the compound was actually produced, while the remaining 19.4% was lost due to incomplete reactions or other factors.
The percent yield can be calculated as follows:
percent yield = (actual yield / theoretical yield) x 100%
Substituting the given values, we get:
percent yield = (26.1 / 32.4) x 100%
percent yield = 0.806 x 100%
percent yield = 80.6%
A compound is a substance made up of two or more different elements that are chemically bonded together in a fixed ratio. This means that compounds have a unique chemical formula, which describes the types and numbers of atoms that make up the compound.
The properties of a compound are different from those of the individual elements that make it up. For example, water (H2O) is a compound made up of hydrogen and oxygen. Although hydrogen is a gas and oxygen is a gas, water is a liquid at room temperature. This is because the properties of a compound are determined by the arrangement of the atoms and the type of chemical bonds between them.
Compounds are important in many areas of physics, including materials science, chemical engineering, and electronics. They are used to make a wide range of products, from plastics and medicines to electronic devices and batteries. Understanding the properties and behavior of compounds is therefore essential for many areas of research and development.
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the half life of plutonium is 24000 years. how long does it take for the activity of plutonimum waste to decrease from 20000 to 625?
It takes approximately 61,649 years for the activity of plutonium waste to decrease from 20,000 to 625.
How to find the time it takes for the activity of plutonium waste to decrease.We can use the radioactive decay formula to find the time it takes for the activity of plutonium waste to decrease from 20,000 to 625:
A = A₀(1/2)^(t/T)
where
A₀ = initial activity (20,000)A = final activity (625)t = timeT = half-life (24,000 years)We can solve for t by taking the logarithm of both sides:
log(A/A₀) = -t/T × log(1/2)t/T = -log(A/A₀) / log(1/2)t = -T × log(A/A₀) / log(1/2)Substituting the values:
t = -24,000 years × log(625/20,000) / log(1/2)
t = 61,649 years
Therefore, it takes approximately 61,649 years for the activity of plutonium waste to decrease from 20,000 to 625.
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An object is dropped from a height of 23 m. At what height will its kinetic energy and its potential energy be equal?
Answer:
Explanation:
We can use the conservation of energy to determine at what height the kinetic energy (KE) and potential energy (PE) of the object are equal. At any given point during the fall, the total mechanical energy of the object is equal to the sum of its kinetic energy and potential energy, and it remains constant throughout the fall.
Initially, when the object is dropped from a height of 23 m, it only has potential energy. At this point, the potential energy of the object is given by:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity (9.81 m/s^2), and h is the height of the object above some reference point. Plugging in the given values, we get:
PE = mgh = m × 9.81 m/s^2 × 23 m
Next, we need to determine the kinetic energy of the object when its potential energy is equal to the potential energy at some height h. At this point, the object has fallen a distance of (23 - h) meters, and its potential energy has been converted into kinetic energy. Therefore, we can write:
KE = 1/2 mv^2 = PE = mgh
where v is the velocity of the object at height h. Solving for v, we get:
v = sqrt(2gh)
Now we can calculate the kinetic energy of the object at height h:
KE = 1/2 mv^2 = 1/2 m (sqrt(2gh))^2 = mgh
We can see that the kinetic energy is equal to the potential energy at height h. So we can set the two equations for PE and KE equal to each other and solve for h:
mgh = 1/2 m (sqrt(2gh))^2
Simplifying this equation, we get:
h = 1/2 (sqrt(2gh))^2 / g
h = 1/2 (2gh) / g
h = h
Therefore, the height at which the kinetic energy and potential energy of the object are equal is h = 23 / 2 = 11.5 meters.
In Canadian football, after a touchdown the team has the opportunity to earn one more point by kicking the ball over the bar between the goal posts. The bar is 10.0 ft above the ground, and the ball is kicked from ground level, 36.0 ft horizontally from the bar in (Figure 1) . Football regulations are stated in English units, but convert to SI units for this problem.
A)There is a minimum angle above the ground such that if the ball is launched below this angle, it can never clear the bar, no matter how fast it is kicked. What is this angle? ===15.5
B) If the ball is kicked at 46.0 ∘ above the horizontal, what must its initial speed be if it is just to clear the bar? Express your answer in m/s.
I got part A but I can not figure out B
Therefore, the initial speed of the ball must be 27.8 m/s to just clear the bar when kicked at an angle of 46.0 degrees.
What is speed?Speed is a measure of how fast an object is moving, usually expressed as the distance traveled per unit of time. It is a scalar quantity, meaning that it has magnitude but no direction. The SI unit for speed is meters per second (m/s), although other units such as kilometers per hour (km/h) or miles per hour (mph) are also commonly used.
Here,
To solve part B, we can use the following kinematic equations:
y = yi + viyt - (1/2)gt² (vertical motion)
x = xi + vixt (horizontal motion)
where
y and x are the final vertical and horizontal displacements, respectively
yi and xi are the initial vertical and horizontal displacements, respectively (both are 0 in this case)
viy and vix are the initial vertical and horizontal velocities, respectively
g is the acceleration due to gravity (-9.81 m/s²)
t is the time of flight (the time it takes for the ball to reach the bar)
We want to find the initial velocity (v) that will allow the ball to just clear the bar, given an initial launch angle of 46.0 degrees above the horizontal. To do this, we can use the fact that the final vertical displacement (y) is equal to the height of the bar (10.0 ft = 3.05 m), and the final horizontal displacement (x) is equal to the distance from the ball to the bar (36.0 ft = 10.97 m).
y = 3.05 m
x = 10.97 m
θ = 46.0°
g = 9.81 m/s²
First, we can find the time of flight (t) by using the vertical motion equation:
y = yi + viyt - (1/2)gt²
3.05 m = 0 + visin(46.0°)*t - (1/2)(9.81 m/s²)*t²
Rearranging, we get a quadratic equation in t:
(1/2)(9.81 m/s²)t² - visin(46.0°)*t + 3.05 m = 0
Solving for t using the quadratic formula, we get:
t = [visin(46.0°) ± √((visin(46.0°))² - 4*(1/2)(9.81 m/s²)(3.05 m))]/(2(1/2)(9.81 m/s²))
We can ignore the negative solution, since time cannot be negative. Simplifying, we get:
t = [visin(46.0°) + √((visin(46.0°))² - 9.81 m/s²*3.05 m)]/4.905 m/s²
Now we can use the horizontal motion equation to find the initial velocity:
x = vixt
10.97 m = vicos(46.0°)*t
Substituting for t, we get:
10.97 m = vicos(46.0°)[visin(46.0°) + √((visin(46.0°))² - 9.81 m/s²*3.05 m)]/4.905 m/s²
Simplifying and solving for vi, we get:
vi = √(4.905 m/s² 10.97 m/[cos(46.0°)sin(46.0°) + √(sin²(46.0°) - 4(1/2)(9.81 m/s²)(3.05 m)/(vi²*cos²(46.0°)))])
= 27.8 m/s
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Fernando, who has a mass of 43.0 kg, slides down the banister at his grandparents’ house. If the banister makes an angle of 35.0° with the horizontal, what is the normal force between Fernando and the banister? FN = mg cos θ
Answer:
Below
Explanation:
Fn = mg cos(angle ) <======just plug in the values given
Fn = 43 * 9.81 * cos 35 = ~ 346 N
`A 860-kg Escalade traveling 40 m/s at 72 degrees has a perfect inelastic collision with a 220-kg mini-cooper traveling 22 m/s at 210 degrees. Find with what velocity the two cars continue moving after the collision.
The required two cars move together after the collision with a velocity of 15.13 m/s.
What is conservation of momentum?Conservation of momentum is a fundamental principle in physics that states that the total momentum of a closed system of objects is conserved, meaning that it does not change over time, as long as no external forces act on the system.
Here,
Momentum of the Escalade: p₁ = m₁ * v₁
= 860 kg * 40 m/s * cos(72)
= 26731.13 kg m/s
The momentum of the mini-cooper: p₂ = m₂ * v₂
= 220 kg * 22 m/s * cos(210)
= -10399.48 kg*m/s
(negative because it's traveling in the opposite direction)
The total momentum before the collision is the sum of these two momenta:
p₁ + p₂ = 26731.13 kgm/s - 10399.48 kgm/s = 16331.65 kg*m/s
After the collision, the two cars stick together and move with a common velocity v. We can use the conservation of momentum principle again to find this velocity,
Total mass after the collision: m₁ + m₂ = 860 kg + 220 kg = 1080 kg
Total momentum after the collision: (m1 + m2) * v
Setting these equal, we get:
p₁ + p₂ = (m₁ + m₂) * v
16331.65 kg*m/s = 1080 kg * v
v = 15.13 m/s
Therefore, the two cars move together after the collision with a velocity of 15.13 m/s.
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You throw a piece of chalk straight down in frustration at 2 m/s. How fast is it moving after 0.5 s?
The carnival ride from Prob 12.51 is modified so that the 80 kg riders can move up and down the inclined wall as the speed of the ride increases. Knowing that the coefficient of static friction between the wall and the platform is 0.2, determine the range of values of the constant speed v0 for which the platform will remain in the position shown.
The range of values of the constant speed v0 for which the platform will remain in the position shown is 0 < v0 < 3.2 m/s.
What is position?Position is the location of an object within a defined space. It is typically expressed as a set of coordinates, such as (3, 5), or as an angle, such as 30 degrees. Position can also refer to the occupation or job of a person, such as a CEO or engineer. In physics, position is the location of an object in relation to other objects or points of reference. In mathematics, position is an important concept in geometry, where shapes and angles are determined by their relative positions. In economics, position is a term used to describe a company's financial standing, such as its stocks, bonds, and other investments.
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A 6.0-kg rock is dropped from a height of 9.0 m. At what height is the rock's kinetic energy twice its potential energy?
The height at which the rock's kinetic energy is twice its potential energy is 4.5 meters above the ground.
What is Potential Energy ?
Potential energy is energy that is stored in an object or system as a result of its position or configuration. It is a form of energy that has the potential to do work, meaning that it can be converted into other forms of energy such as kinetic energy or thermal energy
At any point during the fall, the total energy of the rock (E) is equal to the sum of its potential energy (U) and its kinetic energy (K):
E = U + K
The potential energy of the rock is given by:
U = mgh
where m is the mass of the rock, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the rock above some reference point.
The kinetic energy of the rock is given by:
K = (1/2)mv^2
At some height h, the kinetic energy of the rock is twice its potential energy. We can express this mathematically as:
K = 2U
Substituting the expressions for U and K and solving for h, we get:
(1/2)mv^2 = 2mgh
Simplifying and solving for h, we get:
h = (v^2)/(4g)
To find v, we can use the fact that the initial potential energy of the rock is equal to its final kinetic energy (since the rock is dropped from rest):
U = K
mgh = (1/2)mv^2
Simplifying and solving for v, we get:
v = sqrt(2gh)
Substituting this expression for v into the equation for h, we get:
h = (2gh)/(4g)
Simplifying and canceling the factor of g, we get:
h = 0.5h
Therefore, the height at which the rock's kinetic energy is twice its potential energy is halfway between the initial height and the ground.
Plugging in the values given in the problem, we get:
h = (9.0 m)/2 = 4.5 m
Therefore, the height at which the rock's kinetic energy is twice its potential energy is 4.5 meters above the ground.
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PLEAS HELP
The picture is to answer the questions and here are the questions
The Death of Georgi Markov and the Attack on Vladimir Kostov (1978)
1. What was the delivery method of the ricin?
2. What are the symptoms of ricin poisoning?
3. How much ricin did they find in Markov?
Tylenol Tampering (1982)
1. How many people died?
2. What are the circumstances surrounding the deaths?
3. When/where did the tampering likely occur? How do they know?
4. What is the significance of this case?
A packing crate with mass 80. 0 kg is at rest on a horizontal frictionless surface at t 0 a net horizontal force in the x direction is applied to the crate the force has a constant value of 80. 0 n for 12. 0 s and then decreases linearly with time so it becomes zero after an additional 6. 00 s.
The required final speed of the crate after 18 seconds is calculated to be 15 m/s.
The mass of the packing crate is given as 80 kg.
The applied force is 80 N for 12 s.
So, the force is given as,
f = (mv₁ - mv₂)/t
where,
f is force
m is mass
t is time
v₁ is final velocity
v₂ is initial velocity
80 × 12 = 80 v₁ - 80 × 0
v₁ = 12 m/s
After 12 seconds, the crate's final velocity is 12 m/s.
The force drops to zero, linearly for the next 6 seconds. So,
F = 80 - (80/6)t
In the case of the force's magnitude linearly decreasing,
∫F dt = m v₁ - m v₂
∫(80 - (80/6)t)dt = 80 v₁ - 80 × 12
80 t - 80t²/(2×6) = 80 v₁ - 960
For the next coming 6 seconds, t = 6 then,
80 × 6 - (80/12) × 6² = 80 v₁ - 960
⇒ v₁ = 15 m/s
Thus, after 18s, we can conclude that the final speed of the crate is 15 m/s.
The question is incomplete. The complete question is 'What is the final speed of the crate, 18.0 s after the force was first applied?'
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Jaycie wants to increase her upper body strength by doing push-ups. She does one push-up by applying a force of 10 n to raise her center of gravity 2 m. How many push-ups must jaycie complete to do 200 j of work?.
Jaycie would need to complete 10 push-ups to do 200 J of work, assuming that the force and displacement are the same for each push-up.
The work done by Jaycie to do one push-up is equal to the product of the force applied and the displacement of her center of gravity:
Work = Force x Displacement x cos(theta)
where theta is the angle between the force vector and the displacement vector. In this case, we can assume that the angle is 0 degrees, since the force is applied vertically upward and the displacement is vertically upward as well.
So the work done by Jaycie to do one push-up is:
Work = Force x Displacement = 10 N x 2 m = 20 J
To do 200 J of work, Jaycie would need to do:
Number of push-ups = Total work ÷ Work per push-up = 200 J ÷ 20 J/push-up = 10 push-ups
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Describe the magnetic poles and magnetic field
The magnetic pole is referred to as the region at each end of a magnet where the external magnetic field is strongest while a magnetic field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.
What is a Magnetic field?This is referred to as a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials.
A bar magnet suspended in Earth's magnetic field orients itself in a north–south direction and is referred to as a magnetic pole which has magnetic field present in the region also.
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Please help (50 points)
The mass of the Salamander is 0.09 Kg
What is the momentum?Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum (p) can be expressed as:
p = mv
where m is the mass of the object and v is its velocity.
We know that;
Momentum before collision = Momentum after collision
(5 * 3.6) - (M * 2.2) = (5 + M) * 3.5
Let the mass of the Salamander
18 - 2.2M = 17.5 + 3.5 M
18 - 17.5 = 3.5 M + 2.2 M
M = 0.09 Kg
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Two masses of 1.8 kg and 1.2 kg are connected by an inextensible string, passing over a frictionless pulley. Calculate: (i) Acceleration of the system, when released from rest. (ii) Tension in the sting. Take mu = 0.2
The acceleration of the system is 1.96 m/s^2; The tension in the string is 8.16 N.
Define accelerationAcceleration is the rate of change of velocity with respect to time.
(i) The acceleration of the system can be found using the equation:
a = (m1 - m2)g / (m1 + m2)
where m1 and m2 are the masses, g is the acceleration due to gravity.
Substituting the given values, we get:
a = (1.8 kg - 1.2 kg) × 9.8 m/s^2 / (1.8 kg + 1.2 kg)
a = 1.96 m/s^2
(ii) The tension in the string can be found using the equation:
T = m2 × (g - a) + μm1g / (1 + μ)
where μ is the coefficient of friction.
Substituting the given values, we get:
T = 1.2 kg × (9.8 m/s^2 - 1.96 m/s^2) + 0.2 × 1.8 kg × 9.8 m/s^2 / (1 + 0.2)
T = 8.16 N
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A hippo is dozing under water with only its small nostrils sticking out. It has a mass of 1600 kg and a volume of about 1.57 m3 after exhaling. How much force does it exert on the ground of the pool (fresh water, density 1g/cm3)?
The concept Buoyant force is used here to determine the force which on the ground of the pool. The buoyant force is 15385.21 N.
What is Buoyant force?The Buoyant force is defined as the upward force exerted on an object which is fully or partially immersed in a liquid. This force is also called the Upthrust. Due to this force a body immersed in a fluid appears to lose its weight.
The Buoyant force is calculated as:
F = mg × ρ fluid / ρ hippo
Density of hippo = Mass/volume
= 1600/1.57 = 1019.10 kg/m³
Density of fluid = 1 g/cm³ = 1000 kg/m³
F = 1600 × 9.8 × 1000/1019.10 = 15385.21 N
Thus the Buoyant force is 15385.21 N.
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The mixing entropy formula derived in the previous problem actually applies to any ideal gas, and to some dense gases, liquids, and solids as well. For the denser systems, we have to assume that the two types of molecules are the same size and that molecules of different types interact with each other in the same way as molecules of the same type (same forces, etc.). Such a system is called an ideal mixture. Explain why, for an ideal mixture.
For an ideal mixture of two or more substances, the mixing entropy can be derived based on the same principles as for ideal gases. The reason is that ideal mixtures also have particles that are in constant random motion, and the entropy of mixing is still related to the number of possible ways the particles can be arranged.
Ideal mixture explained.
In an ideal mixture, the assumption is that the molecules of different substances are the same size and shape, and have the same intermolecular forces with each other as they do with their own kind. This means that there are no attractive or repulsive forces between particles of different types, which simplifies the calculation of the entropy of mixing.
The mixing entropy of an ideal mixture is determined by the number of possible ways the molecules of the two substances can be distributed among the available volume. Just as in the case of ideal gases, this leads to an increase in entropy when the two substances are mixed, as there are more ways to distribute the molecules than when they are separated.
Therefore, the concept of an ideal mixture allows us to apply the same principles of thermodynamics to denser systems as we do for ideal gases, which makes it a useful tool for studying a wide range of physical and chemical processes involving mixtures.
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The mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.
What is Ideal Mixing Entropy Formula?An ideal mixture is a hypothetical mixture of gases, liquids or solids where the components are assumed to behave as an ideal gas, and where the two types of molecules are the same size and interact with each other in the same way as molecules of the same type (same forces, etc.). In an ideal mixture, the mixing entropy formula applies due to the following reasons:
No intermolecular forces between different species: In an ideal mixture, the molecules of the different components do not attract or repel each other. This means that the interactions between the different species are negligible and the enthalpy of mixing is zero.No volume changes upon mixing: In an ideal mixture, the components have the same size and shape, and the volume of the mixture is equal to the sum of the volumes of the individual components. Therefore, there are no volume changes upon mixing, and the entropy of mixing is solely dependent on the number of ways of arranging the molecules.Random mixing: The assumption of ideal mixing also implies that the mixing is completely random, with no preferential interactions between the different species. This means that the entropy of mixing is solely dependent on the number of ways the molecules can be arranged, and this is given by the mixing entropy formula.Therefore, the mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.
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A basketball player makes 39% of her shots from the free throw line. Suppose that each of her shots can be considered independent and that she takes 5 shots. Let x = the number of shots that she makes. What is the mean for x?.
The mean of the number of shot that she makes is 1.95
The probability of making a free throw is 0.39, and the probability of missing a free throw is 0.61 (1 - 0.39). Since each shot is independent, we can use the binomial distribution to calculate the probability of making x shots out of 5.
Consider p is the probability of success in each trials
The equation to calculate the mean of a binomial distribution is:
mean = n × p
where n is the number of trials
In this case, n = 5 and p = 0.39, so:
mean = n × p = 5 × 0.39 = 1.95
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60. A friction block consists of a piece of wood with slotted masses on top of it. If you double the total mass of the block plus slotted masses, how does the coefficient of static friction between the friction block and concrete change?
The change in the coefficient of static friction between the friction block and concrete change would be Zero which means it will not change.
How does mass affect the coefficient of static friction?The coefficient of static friction between two surfaces does not depend on the mass of the object. Therefore, doubling the total mass of the friction block and slotted masses would not change the coefficient of static friction between the block and the concrete.
The coefficient of static friction is a property of the two surfaces in contact and is affected by factors such as the roughness of the surfaces, the materials they are made of, and the amount of force pressing the surfaces together.
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A 1. 50 kg book is sliding along a rough horizontal surface. At point a it is moving at 3. 21 m/s , and at point b it has slowed to 1. 25 m/s.
A) The work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.
B) The book is moving at 1.91 m/s at point C.
C) If +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.
(a) To find the work done on the book between points A and B, we need to use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy:
Net work done = change in kinetic energy
The change in kinetic energy can be found by subtracting the initial kinetic energy at point A from the final kinetic energy at point B:
change in kinetic energy = (1/2)mvB^2 - (1/2)mvA^2
where m is the mass of the book, vA is the velocity of the book at point A, and vB is the velocity of the book at point B.
Substituting the given values, we get:
change in kinetic energy = (1/2)(1.50 kg)(1.25 m/s)^2 - (1/2)(1.50 kg)(3.21 m/s)^2
= -5.32 J
Since the final velocity is less than the initial velocity, the change in kinetic energy is negative. Therefore, the net work done on the book between points A and B is also negative. The magnitude of the net work done is:
|net work done| = |-5.32 J| = 5.32 J
Therefore, the work done on the book between points A and B is 5.32 J in the direction opposite to the book's motion.
(b) Since -0.750 J of work is done on the book from point B to point C, we can use the work-energy principle again to find the final velocity at point C:
Net work done = change in kinetic energy
Substituting the given values, we get:
-0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)
Solving for vC, we get:
vC = 1.91 m/s
Therefore, the book is moving at 1.91 m/s at point C.
(c) If +0.750 J of work was done on the book from point B to point C, we would have:
0.750 J = (1/2)(1.50 kg)(vC^2 - 1.25^2 m/s^2)
Solving for vC, we get:
vC = 2.31 m/s
Therefore, if +0.750 J of work was done on the book from point B to point C, the book would be moving at 2.31 m/s at point C.
The given question is incomplete, the complete question is
A 1.50-kg book is sliding along a rough horizontal surface. at point a it is moving at 3.21 m>s, and at point b it has slowed to 1.25 m>s. (a) how much work was done on the book between a and b? (b) if -0.750 j of work is done on the book from b to c, how fast is it moving at point c? (c) how fast would it be moving at c if +0.750 j of work was done on it from b to c?
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A scientist has a sample of an unknown gas. In order to identify the gas, he looks at the spectrum of visible light emitted from it when it is heated. This is shown in the figure. Also shown in the figure are the emission spectra of five pure, gaseous elements. Which of the five elements is the unknown gas?
A. Xenon
B. Argon
C. Oxygen
D. Helium
E. Neon
In the scientist sample of unknown gas when he looks at the spectrum of visible light is xenon.
SpectrumThis spectrum appears to be much more promising. To begin with, we can observe that there are no absorption lines in this wavelength range in the spectra of xenon at these short wavelengths below around 470 nanometers where we have no absorption lines in the spectrum from the mystery gas. Similar to how there are numerous lines in the spectra of the unidentified gas at longer wavelengths starting at around 610 nanometers and upward, xenon's spectrum contains numerous lines as well. This similarity in absorption spectra identifies xenon as the unidentified gas.For more information on xenon kindly visit to
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kinetic energy of an object whose mass is 1Kg and it is moving at a velocity of 5m/s.
The kinetic energy of the object is: KE = 0.5 x 1 kg x (5 m/s)2
= 12.5 J
What is kinetic energy?Kinetic energy is the energy of motion. It is the energy an object has due to its motion. Kinetic energy can be defined as the energy an object has due to its mass and its velocity. Kinetic energy is measured in Joules (J). Kinetic energy increases with increasing mass and velocity of an object. When an object is at rest, it has zero kinetic energy. When an object is in motion, it has kinetic energy. Kinetic energy is a form of energy that is associated with the motion of an object. It is the energy that is stored in the movement of an object. Kinetic energy is one of the fundamental forms of energy, along with potential energy.
Kinetic energy is the energy possessed by an object due to its motion. It is a form of energy that can be calculated using the equation:
Kinetic energy (KE) = 0.5 x Mass (m) x Velocity (v)2
In this case, the mass of the object is 1 kg and its velocity is 5 m/s.
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A 11 N force moves an object 9 m. What is the work?
Answer :
99 JoulesStep-by-step explanation :
Given:
Force = 11 N Displacement = 9 mWork done = Force × Displacement
On substituting the values, we get :
Work done = 11 × 9
Work done = 99 joules