x=5 is the value of the x that is the solution of the given inequality.
Define inequality.Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
What are types of inequality.>,< and not equal to are types of inequality.
x=5 is the value of the x that is the solution of the given inequality.
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Please help me find the circumference of the circle!
Answer:
[tex]C=59.6902604182[/tex]
Step-by-step explanation:
The formula to calculate the circumference of a circle given the diameter is:
[tex]C=\pi d[/tex]
Substitute and solve:
[tex]C=\pi \times19=59.6902604182[/tex]
[tex]C=59.6902604182[/tex]
Since the question doesn't say to round your answer is "59.6902604182."
Hope this helps.
As drug A gets absorbed into the body, less and less of it remains. A scatterplot of data showed a curved relationship between hours since drug A was administered (x) and the number of milligrams of drug A remaining in the body (y). Taking the logarithm of the milligrams of drug A remaining obtains a linear pattern on a scatterplot, and creates the following printout from a statistical software package:
Predictor Coef SE Coef t-ratio P
Constant 3. 00 0. 401 7. 481 0. 000
Time -0. 0737 0. 005 -14. 74 0. 000
s= 0. 014 R-sq= 98. 5% R-Sq(Adj)= 99. 0%
Required:
Write down the correct equation that follows from this output?
The equation is
log ( milligrams of drug A ) =3 - 0.0737 ( Time)
As per the details stated above,
Curved relationship between the number of milligrams of drug A is (x) still in the body and the number of hours since drug A was delivered (y)
The co-efficient of the constant is 3.00
the co-efficient of the time is -0.0737
the SE co-efficient of the constant is 0.4017
the SE co-efficient of the time is 0.005
the t-ratio of the constant is 7.481
the t-ratio of the time is -14.74
now the equation formed is
logarithm of drug A in milligrams is (The co-efficient of the constant - the co-efficient of the time )
that is log ( milligrams of drug A ) =3 - 0.0737 ( Time).
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PLEASE HELPPP
Given the diagram below, which statement is true?
∠1 and ∠3 are vertical angles and congruent.
What is congruence?
In geometry, two figures or objects are said to be congruent if their shapes and sizes match, or if one is the mirror image of the other.
What are vertical angles?
The opposing angles form when two lines cross. They are constantly on par. In this illustration, the angles a° and b° are vertical. The term "vertical" refers to the vertex, not up or down, where they cross.
Here,
we have given a diagram and we have to determine which statement is true that satisfies the true conditions.
By applying congruent property. we get
∠1 = ∠3 are vertivally opposite angle.
This is the only condition that satisfy the true condition from given statement.
Hence, ∠1 and ∠3 are vertical angles and congruent.
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Select the correct answer. what is the height, x, of the equilateral triangle? an equilateral triangle with the angles labeled as 60 degrees and a side length of 8 inches, the height labeled as x
a. in.
b. in.
c. in.
d. in.
The height of the equilateral triangle when its side length is given as 8 inches is calculated to be 6.93 inches.
The equilateral triangle has all sides and angles equal. The angles are always equal to 60 degrees.
Given that,
Side length of the equilateral triangle = 8 inches
Angles = 60 degrees
Height = ?
Therefore, let us find the height of the triangle using the Pythagoras theorem,
c² = a² + b²
8² - 4² = b²
b² = 64 - 16
b² = 48
b = 6.93 inches
Thus, the height of the equilateral triangle is calculated to be 6.93 inches.
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Person A buys 10 granola bars and 6 cups of yogurt for $18. Person B buys 5 granola bars and 4 cups of yogurt for $9.50. Find the cost of each item.
Answer:
granola bar: $1.50yogurt: $0.50Step-by-step explanation:
You want the cost of each item when person A buys 10 granola bars and 6 cups of yogurt for $18, and person B buys 5 granola bars and 4 cups of yogurt for $9.50.
EquationsThe equations describing the relations can be written ...
10g +6y = 18 . . . . . . . person A's purchase
5g +4y = 9.50 . . . . . . person B's purchase
SolutionSubtracting half of the first equation from the second, we find ...
(5g +4y) -1/2(10g +6y) = (9.50) -1/2(18)
y = 0.50 . . . . . . . . . . simplify
Substituting this into the first equation gives ...
10g +6(0.50) = 18
10g = 15 . . . . . . . . . . subtract 3
g = 1.50 . . . . . . . . . divide by 10
Each granola bar costs $1.50; each cup of yogurt costs $0.50.
__
Additional comment
The attachment shows the solution found using a calculator to find the reduced row-echelon form of the augmented coefficient matrix. The variable values are in the right column of the reduced matrix. This tells us granola bars are $1.50, and yogurt cups are $0.50, as we found above.
Arya has 5 cupcakes and wants to
share them with 8 friends equally.
How many cupcakes will each frien
receive?
Each friend of Arya will receive 0.625 cupcakes.
To divide 5 cupcakes equally among 8 friends, we can use simple division. We would divide the total number of cupcakes (5) by the total number of friends (8) to find the number of cupcakes each friend would receive. In this case, 5 divided by 8 is equal to 0.625. This means that each friend will receive 0.625 cupcakes. However, since cupcakes are not divisible it is not possible to divide 5 cupcakes equally among 8 friends. In this case, either Arya will have to make more cupcakes or they will have to decide on a different way to divide the cupcakes.
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What is the graph of the linear equation 2x +3y 6 that cuts the Y-axis at the point?
The graph of the linear equation 2x + 3y = 6 is a straight line that cuts the Y-axis at the point (0,2).
A linear equation is an equation in which the highest power of the variable is 1.
The general form of a linear equation is:ax + by = c where a, b and c are constants and x and y are variables. This equation represents a straight line when plotted on a graph.
The slope-intercept form of a linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept
To find the points at which the line will intersect y-axis,
take x=0 and substitute in the linear equation 2x+3y=6
2(0) + 3y = 6
3y = 6
y = 2
So the point where the line cuts the Y-axis is (0,2)
The straight line of the linear equation 2x+3y=6 intersects the y-axis at (0,2).
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an airplane is flying from new york city to los Angeles the distance it travels in miles, d, is related to the time in seconds, t, by the equation d=0.15t how long will it take to go 12.75 milles
Answer: 85 seconds
Step-by-step explanation: 12.75/0.15=85
Find a basis for the eigenspace corresponding to each listed eigenvalue of A below.
A = 4 0 -1 14 5 -10 2 0 1 λ=5,2,3
A basis for the eigenspace corresponding to λ = 5 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 2 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 3 is . { }. (Use a comma to separate answers as needed.)
The basis for the eigenspace corresponding to lambda=5,1,4 are None,[tex]\left[\begin{array}{c}-1 \\\frac{1}{2} \\0\end{array}\right][/tex] and [tex]$\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]$[/tex]
[tex]$$A=\left[\begin{array}{ccc}5 & -12 & 10 \\0 & 7 & -3 \\0 & 6 & -2\end{array}\right]$$[/tex]
Eigenspace corresponding to lambda=5,1,4
The eigenspace E_lambda corresponding to the eigenvalue lambda is the null space of the matrix a [tex]\mathrm{A}-(\lambda) \mathrm{I}"[/tex]
for lambda=5
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-5 \mathrm{I})$$[/tex]
Reducing the matrix A-5I by elementary row operations
[tex]$$\begin{aligned}A-5 I & =\left[\begin{array}{ccc}5-5 & -12 & 10 \\0 & 7-5 & -3 \\0 & 6 & -2-5\end{array}\right] \\& =\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 2 & -3 \\0 & 6 & -7\end{array}\right] \\& \sim\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_2 \rightarrow \frac{R_2}{2} \\& \sim\left[\begin{array}{ccc}1 & 0 & -8 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_1 \rightarrow R_1+2 R_2\end{aligned}$$[/tex]
[tex]\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 2\end{array}\right] R_3 \rightarrow R_3-6 R_2$$\\\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] R_3 \rightarrow \frac{\mathrm{R}_3}{2}$$\\\sim\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+8 \mathrm{R}_3$[/tex]
[tex]$\sim\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right] R_2 \rightarrow R_2+\frac{2 R_3}{2}$[/tex]
The solutions x of A-5I=0 satisfy x_1=x_2=x_3=0 that is, the null space solves the matrix
[tex]$$\left[\begin{array}{lll}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
Hence The null space is [tex]\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right] E_5[/tex] has no basis
[tex]$$\begin{aligned}& \text { case: } 2 \\& \text { for } \lambda=1 \\& \mathrm{E}_5=\mathrm{N}(\mathrm{A}-(1) \mathrm{I})\end{aligned}$$[/tex]
we reduce the matrix A-I by elementary row operations as follows.
[tex]$$\begin{aligned}A-1 & =\left[\begin{array}{ccc}5-1 & -12 & 10 \\0 & 7-1 & -3 \\0 & 6 & -2-1\end{array}\right] \\& =\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 6 & -3 \\0 & 6 & -3\end{array}\right] R_1 \rightarrow \frac{R_1}{4} \\& \sim\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 1 & -\frac{1}{2} \\0 & 6 & -3\end{array}\right] R_2 \rightarrow \frac{R_2}{6}\end{aligned}[/tex]
[tex]$$$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 6 & -3\end{array}\right] R_1 \rightarrow R_1+3 R_2$\\$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right] R_3 \rightarrow R_3-6 R_2$[/tex]
Thus, the solutions x of (A-I) X=0 satisfy
[tex]$\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]=\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right]$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=-\mathrm{t}, \mathrm{x}_2=\frac{\mathrm{t}}{2}$[/tex]
[tex]$\vec{x}=\left[\begin{array}{c}-t \\ \frac{t}{2} \\ t\end{array}\right]=\left[\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right] t$[/tex]
The Basis for the nullspace A-I will be: [tex]$\left.\left(\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right]\right)$[/tex]
case:3
lambda=4
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-(4) \mathrm{I})$$[/tex]
we reduce the matrix A-4I by elementary row operations as follows.
[tex]$\begin{aligned} A-4 \mid & =\left[\begin{array}{ccc}5-4 & -12 & 10 \\ 0 & 7-4 & -3 \\ 0 & 6 & -2-4\end{array}\right] \\ & =\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 3 & -3 \\ 0 & 6 & -6\end{array}\right] \\ & \sim\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] R_2 \rightarrow \frac{R_2}{3}\end{aligned}$[/tex]
[tex]$\begin{aligned} & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+12 \mathrm{R}_2 \\ & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 0 & 0\end{array}\right] \mathrm{R}_3 \rightarrow \mathrm{R}_3-6 \mathrm{R}_2\end{aligned}$[/tex]
Thus, the solutions x of (A-4IX)=0 satisfy
[tex]$$\left[\begin{array}{ccc}1 & 0 & -2 \\0 & 1 & -1 \\0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=2 \mathrm{t}, \mathrm{x}_2=\mathrm{t}$[/tex]
[tex]$$\vec{x}=\left[\begin{array}{c}2 t \\t \\t\end{array}\right]=\left[\begin{array}{l}2 \\1 \\1\end{array}\right] t$$[/tex]
The Basis for the nullspace A-4 I will be [tex]\left(\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]\right)[/tex]
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12 holes in 6 minutes. If the machine drills holes at a constant speed, it can drill ______ holes in 25 minutes.
Step-by-step explanation:
12 holes / 6 minutes = 2 holes / 1 minute
the simplified ratio is 2/1 = 2.
so, for 25 minutes we need to keep the same ratio :
x holes / 25 minutes = x/25 = 2
x = 2×25 = 50
it drills 50 holes in 25 minutes.
Of the 6,960 balloons thrown in a water-ballon fight, 870 were red. At this rate, how many balloons out of 48 would be red? WRITE JUST THE ANSWER WITHOUT UNITS
At this rate, the ratio or proportion of red balloons to the total balloons, the number of red balloons out of 48 is 6.
What is proportion?Proportion describes the two or more ratios equated to each other.
Proportions are depicted as fractional values in decimals, fractions, or percentages.
In this situation, we equate the ratio or proportion of red balloons to the sample to determine the number that will likely be red.
The total number of balloons thrown in a water balloon fight = 6,960
The number of the balloons that are red = 870
The proportion of the red balloons to the total = 0.125 or 12.5% (870/6,960)
In a sample of 48 balloons, the number of red balloons will be 6 (48 x 0.125)
Thus, out of 48 balloons, there are 6 red balloons at this constant rate.
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How do you solve 2 polynomial equations?
The steps to solve two polynomial equations are given below.
What is polynomial?
A polynomial is a mathematical expression made up of coefficients and indeterminates that uses only the operations addition, subtraction, multiplication, and powers of positive integers of the variables.
x^2 + 4x + 7 is an illustration of a polynomial with a single indeterminate x.
Apply the Zero Factor Property to an Equation Solving.
ZERO. FACTOR, write the equation with one side equal to zero. the expression by a factor.
PROPERTY. Solve the equation by setting each factor to zero.
Check by adding substitutes to the initial equation.
Write a polynomial equation in standard form before attempting to solve it. Factor it, then set each variable factor to zero once it has reached zero. The original equations' solutions are the solutions to the resulting equations. Factoring cannot always be used to solve polynomial equations.
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A baby manatee weighs 58 kilograms. At birth the manatee weighed 30 kilograms. What is the percent increase in the manatee's weight rounded to the nearest whole number?
Answer:
93.3% i hope this is right
Step-by-step explanation:
percentage increase= final-original/originalx100
58-30/30x100=93.3333%
hi can someone pls help me
:)
Need answer for b)iii)
Answer:
3.23, -1.23
Step-by-step explanation:
Draw the line y=1
See where it intersects x^2-2x-3
The x coordinates of the intersections are your answer
Joy is solving a quadratic equation of the form a2+bx+c=0 where b
and care integers.
She correctly solves the equation to get a = 3 ± √/13
Work out the values of b and c.
(3 marks)
b=
=
To find the values of b and c, we can use the quadratic formula:
[tex]x = (-b ± \sqrt{ (b^2 - 4ac)}) / 2a[/tex] which will give us the value B = -6 & C = -4
What is a quadratic equation.A quadratic equation is a second-order polynomial equation in one variable using the formula [tex]x = ax2 + bx + c = 0[/tex] and a 0. The fundamental theorem of algebra ensures that it has at least one solution because it is a second-order polynomial problem. Real or complex solutions are also possible.
So the equation that she get is [tex]x^{2} -6x-4[/tex]
this means that x=3+√13 or 3-√13
which also equals to x=3+√13 & x-3-√13=0 and
x=3-√13
x-3+√13=0
which if you try to find the quadratic equation for this. you need to do it by this
(x-3+√13)(x-3-√13)
which will get you
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Create a word problem for 4 x 8 = ?
and solve it using a bar model?
Answer:
Jackie has been assigned to hand out papers to all the students in her class. Each student gets 4 pieces of paper, and there are 8 total students. How many papers total does Jackie need to get?
(I cannot show a picture of a bar model, apologies)
Difference of functions
A pizza delivery driver must make three stops on her route. She will leave the restaurant and travel 4 miles north to the first house. The next house is 6 miles away in the direction of east. She delivers the last pizza to the third stop, which is 5 miles south of the restaurant before she returns to the restaurant to pick up more pizza. What is her displacment for the entire trip
The displacement of the pizza delivery driver for the full journey is therefore 6.08 miles.
The pizza delivery driver's displacement for the entire trip is the total distance and direction that she travels from the restaurant to her last delivery and back.
To find her displacement, we can use the Pythagorean theorem to find the total distance from the start to the endpoint.
The displacement is the distance between the start and end point and the direction of the trip. Here we can see that she traveled 4 miles north, 6 miles east, and 5 miles south,
To find the displacement we will use the Pythagorean theorem (ax2 + bx2 = cx2)
where c is the displacement and a and b are the east-west and north-south distances respectively.
so, a = 6 miles (east-west)
b = (4 miles - 5 miles) = -1 miles (north-south)
so, c = √(ax2 + bx2)
c = √(6x2 + (-1)x2)
c = √(36 + 1)
c = √(37)
c = 6.08 miles
So the pizza delivery driver's displacement for the entire trip is 6.08 miles.
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You are hired to work for a company at age 25 and the company has a retirement plan
where you can put up to 6% of your salary into the plan each month and they will match
that amount. Your starting monthly salary is $6,100, assume for simplicity sake you
never get a raise, and the retirement plan guarantees a 6.28% interest rate over the life of
the plan.
Scenario 1: You decide to start the retirement plan right away and you can afford
to put the full amount (6% of your salary) into the plan each month.
a) What is 6% of your salary? _______________
b) Since your company matches what you put into your retirement account, what is the
total amount put into your account each month?
_______________
c) How much money will you have in the retirement account when you reach full
retirement age, the time when you can start taking money out of the account, which is 62
years old? ________________
d) How much money did you put into the account? ________________
e) How much money did your employer put into your account? ________________
f) How much money did your account gain in interest over the years? _______________
Scenario 2: You decide to start the retirement plan right away, but you can only
afford to put 3% of your salary into the plan each month.
a) What is 3% of your salary? _______________
b) Since your company matches what you put into your retirement account, what is the
total amount put into your account each month?
_______________
c) How much money will you have in the retirement account when you reach full
retirement age, the time when you can start taking money out of the account, which is 62
years old? ________________
d) How much money did you put into the account? ________________
e) How much money did your employer put into your account? ________________
f) How much money did your account gain in interest over the years? _______________
What is the difference in the amount of money you will have at age 62 between scenarios
1 and 2? ________________
What is the difference in the amounts of money you put into retirement between
scenarios 1 and 2? _______________
How much more money did you get from your employer in scenario 1 than 2?
In scenerio 1, the money in the retirement account at 62 years old is $1,267,250.76
In scenerio 2, the money in the retirement account at 62 years old is $ 633,625.38.
How do we calculate future value of an ordinary annuity?Scenerio 1:
a) 6% of salary = Salary * 6% = $6,100 * 6% = $366
b) Total amount the company paid monthly = 6% of salary = Salary * 6% = $6,100 * 6% = $366
c) The money in the retirement account at 62 years old can be calculated using the formula for calculating the Future Value (FV) of an Ordinary Annuity given as follows:
FV = M * (((1 + r)^n - 1) / r) ................................. (1)
Where:
FV = Future value = Money in the retirement account at 62 years old = ?
M = Monthly payment = Contribution you + Contribution by the employer = $366 + $366 = $732
r = Monthly interest rate = Annual interest rate / 12 = 6.28% / 12 = 0.0628 / 12 = 0.0052
n = number of months = Number years * Number of months in a year = (Retirement age – Age when hired) * 12 = (62 - 25) * 12 = 37 * 12 = 444
Substituting all the values into equation (1), we have:
FV = $732 * (((1 + 0.0052)^444 - 1) / 0.0052)
FV = Money in the retirement account at 62 years old = $1,267,250.76
d) Amount of money you put into the account = 6% of salary * number of months = $366 * 444 = $162,504
e) Amount of money your employer put into your account = Amount of money you put into the account = $162,504
f) Amount your account gained in interest over the years = FV – (Amount of money you put into the account + Amount of money your employer put into your account) = $1,267,250.76 – ($162,504 + $162,504) = $942,242.76
Scenario 2:
a) 3% of salary = Salary * 3% = $6,100 * 3% = $183
b) Total amount the company paid monthly = 3% of salary = Salary * 3% = $6,100 * 3% = $183
c) Using equation (1), we have:
M = Monthly payment = Contribution you + Contribution by the employer = $183 + $183 = $366
Substituting all the values into equation (1), we have:
FV = $366 * (((1 + 0.0052)^444 - 1) / 0.0052)
FV = Money in the retirement account at 62 years old = $633,625.38
d) Amount of money you put into the account = 3% of salary * number of months = $183 * 444 = $81,252.00
e) Amount of money your employer put into your account = Amount of money you put into the account = $81,252
f) Amount your account gained in interest over the years = FV – (Amount of money you put into the account + Amount of money your employer put into your account) = $633,625.38 – ($81,252 + $81,252) = $471,121.38
The difference in the amount of money at age 62 between scenarios 1 and 2 = Money in the retirement account at 62 years old in scenarios 1 + Money in the retirement account at 62 years old in scenarios 2 = $1,267,250.76 - $633,625.38 = $633,625.38
Difference in the amounts of money you put into retirement between scenarios 1 and 2 = $366 - $183 = $183
Amount got from your employer in scenario 1 than 2 = $366 - $183 = $183
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A math club is having a bake sale. Find the area of the bake sale sign.
The Area of the sign is_ square feet
The bake sale sign has a 6 ft2 space.
What is area?
An object's area is how much space it takes up in two dimensions.
It is the measurement of the quantity of unit squares that completely cover the surface of a closed figure.
The word "area" refers to a free space.
A shape's length and width are used to compute its area. Unidimensional length is expressed in terms of feet (ft), yards (yd), inches (in), etc.
But a shape's area is a two-dimensional measurement. In order to measure something in a square, it is done so using measurements like square inches (in2), square feet (ft 2), square yards (yd2), etc.
The majority of forms and things have corners and edges.
According to our question-
The opposite sides of a rectangle's quadrilateral (it has four sides and four angles) are equal and parallel.
Area of a rectangle equals length times width.
The area of the bake sale sign = length * breadth
Hence, The bake sale sign has a 6 ft2 space.
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Write an equation of the perpendicular bisector of the segment with the endpoints (-8,-1) and (4,5).
y =
The equation of the perpendicular bisector of the segment with the endpoints (-8,-1) and (4,5) is 2x+y = -2.
The line between these locations' slopes must equal the negative reciprocal of the bisector's slope. It must go through the segment midway.
The slope of the line through the given points :
m = (y2 -y1)/(x2 -x1) = (5 -(-1))/(4 -(-8)) = 6/12 = 1/2
Then, The slope of the required bisector: m = -1/(1/2) = -2
The midpoint of the given segment:
((-8, -1) +(4, 5))/2 = (-8+4, -1+5)/2 = (-4, 4)/2 = (-2, 2)
Then the point-slope form of the equation of the bisector:
y -y1 = m(x -x1)
y -2 = -2(x -(-2))
y = -2x -4 +2
y = -2x -2 . . . . . . . slope-intercept form equation
2x +y = -2 . . . . . . .standard form equation
Thus, The equation of the perpendicular bisector of the segment with the endpoints (-8,-1) and (4,5) is 2x+y = -2.
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What is the value of DX for solving simultaneous equations 3x 2y =- 11 and 7x 4y 9 by Cramer's rule?
The value of DX for solving simultaneous equations 3x 2y =- 11 and 7x 4y 9 by Cramer's rule is -13/5.
The general formula for Cramer's rule is
DX = detX/detA
Where detX is the determinant of the matrix formed by replacing the x-column of the original matrix with the constant column vector, and detA is the determinant of the original matrix.
For the given equations,
A = [3, 2; 7, 4]
X = [-11; -9]
Therefore,
detA = 3*4 - 2*7 = -10
detX = 3*(-9) - 2*(-11) = 13
Hence, DX = detX/detA = 13/-10 = -13/5
The value of DX for solving simultaneous
3x 2y =- 11 and 7x 4y 9 by Cramer's rule equation is -13/5.
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find equation of the line passing through (4,8) and parallel to the line 3x+y=17( Please give workout)
Answer:
y = -3x +20
Step-by-step explanation:
Equation of line: y =mx + b
Where m is the slope and b is the y-intercept.
3x + y = 17
Write the above equation in y = mx +b form.
y = -3x + 17
m = -3
Parallel lines have same slope.
So, slope of the required line is (-3).
y = -3x + b
This line is passing through (4,8). Substitute in the above equation and find the value of 'b'.
8 = -3*4 + b
8 = -12 + b
8 + 12 = b
b = 20
Equation of the line:
[tex]\sf \boxed{ y = -3x + 20}[/tex]
Which act of congress set the line of latitude at 36 degrees 30 minutes north, as the northernmost limit for slavery? dred scott v. sandford missouri compromise compromise of 1850 kansas-nebraska act
Latitude 36°30′ was designated by the Missouri Compromise of 1820 as the northern limit for the legalization of slavery in the western territories.
What did the Missouri Compromise, the Compromise of 1850, and "Bleeding Kansas" have in common?By Stephen A. Douglas's Kansas-Nebraska Act of 1854, the Missouri Compromise's prohibition on slavery in the former Louisiana Territory north of the parallel 36°30′ north had been essentially removed. Latitude 36°30′ was designated by the Missouri Compromise of 1820 as the northern limit for the legalization of slavery in the western territories.
The expansion of slavery into the western lands was addressed by the Missouri Compromise, the Compromise of 1850, and "Bleeding Kansas." The balance between "free" and "slave" states in the Union was a factor in each of them.
Slavery was proposed to be outlawed in the remaining Louisiana Territory above the 36° 30' latitude line in the Missouri Compromise. The Kansas-Nebraska Act of 1854 abolished this clause after it had been in effect for 34 years.
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The Missouri Compromise of 1820 established latitude 36°30′ as the northern boundary for the legalisation of slavery in the western territories.
What were the similarities between the Missouri Compromise, the Compromise of 1850, and "Bleeding Kansas"?The Missouri Compromise's ban on slavery in the former Louisiana Territory north of the parallel 36°30′ north had been largely lifted by Stephen A. Douglas's Kansas-Nebraska Act of 1854. The Missouri Compromise of 1820 established latitude 36°30′ as the northern boundary for the legalisation of slavery in the western territories.The Missouri Compromise, the Compromise of 1850, and "Bleeding Kansas" all addressed the spread of slavery into the western areas. Each of them was influenced by the proportion of "free" and "slave" states in the Union.In the Missouri Compromise, slavery was suggested to be prohibited in the remaining Louisiana Territory above the 36° 30' latitude line. This provision was removed by the Kansas-Nebraska Act of 1854 after it had been in place for 34 years.To learn more about Bleeding Kansas, visit:
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The mean height of 15-year-old boys is 175 cm and the variance is 64. For girls, the mean is 165 and the variance is 64. If 8 boys and 8 girls were sampled, what is the probability that the mean height of the sample of boys would be at least 6 cm higher than the mean height of the sample of girls
The probability of the mean height of the sample of boys being at least 6 cm higher than the mean height of the sample of girls can be calculated using a two-sample t-test. The t-test compares the means of two samples and determines whether they are different from one another. The t-test requires the assumption of equal variances and normal distribution of the data.
What does the math term "probability" mean?
Simply put, probability is the likelihood that something will occur. When we don't know how an event will turn out, we can discuss the likelihood or likelihood of several outcomes. Statistics is the study of events that follow a probability distribution.
Given that the variances are equal, the t-test statistic can be calculated as:
t = (mean_boys - mean_girls - 6) / (sqrt(variance/n))
where n is the sample size of each group (8 in this case).
The probability of observing a t-value as extreme or more extreme than this value can be calculated using the cumulative distribution function (CDF) of a t-distribution with n1 + n2 - 2 degrees of freedom.
Because you are looking for the probability that the mean height of the sample of boys is at least 6cm higher than the mean height of the sample of girls, this is a one-tailed test. The probability of a one-tailed test can be calculated by subtracting the probability of a two-tailed test from 1.
The probability can be calculated using a t-distribution table with 14 d.f. or using software such as R or excel.
It is important to note that the sample size is very small, with 8 boys and 8 girls, which may not be representative of the population. As sample size increases the probability of getting a significant difference increases.
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Aquarium one contains 4. 6 gallons of water Luis Will begin filling aquarium one at a rate of 1. 2 gallons per minute aquarium to contains 54. 6 gallons of water Isaac will begin draining aquarium two at a rate of 0. 8 gallons per minute
The Filling time is After 25 minutes, both Aquariums will contain same amount of water.
What is filling time?you've fully prepared the aquarium, all you need to do is follow these quick and easy steps and safely fill your aquarium with water.
Calculate the Filling Time of the aquarium Explanation
Given,
Water in Aquarium A = 4.6 gallons
Water in Aquarium B = 54.6 gallons
Filling rate = 1.2 gallons per minute.
Draining rate = 0.8 gallons per minute.
Let,
x represents the minutes.
A(x) = 4.6 + 1.2x
(Because Luis is adding water in the tank.)
B(x) = 54.6 - 0.8x
(Isacc is draining water from the tank.)
For same amount of water;
A(x) = B(x)
4.6+1.2x=54.6-0.8x
1.2x+0.8x=54.6-4.6
2x=50
Dividing both sides by 2
2x/2=50/2
x=25
Therefore, After 25 minutes, both Aquariums will contain same amount of water.
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An office manager is planning to set up three computer workstations
and a file cabinet in a space that is 27 feet wide. The file cabinet takes up
3 feet. What is the width of the space available for each computer work
station?
PLEASE HELP
can someone please tell which congruency do you use and how?
To prove that ΔABC is isosceles.
Properties of an isosceles triangle.An isosceles triangle is a type of triangle in which the length of its two sides, and measure of its two internal angles are equal. When a bisector of an angle is drawn to one of the internal angles of the triangle, two congruent triangles of corresponding properties are produced.
To prove that ΔABC is isosceles, we have:
<CAD ≅ <BAD (definition of an angle bisector)
CD ≅ BD (definition of a midpoint)
AC ≅ AB (congruent sides of an isosceles)
<ACD ≅ <ABD (congruent internal angles of an isosceles)
<ADC ≅ <ADB (definition of right angle)
Therefore it can be concluded that;
ΔABC is an isosceles triangle (Angle-Side-Side theorem)
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6. Jenna wants to hang outdoor stringed lights on her house along the roof line
and horizontally across, connecting the ends of the roof line to create a triangle.
What is the approximate length, in feet, of lights that she needs to create one
triangle?
A. 48
B. 64
C. 80
D. 98
The approximate length, in feet, of lights that she needs to create one triangle is 64
This is an approximate estimate as the exact length would depend on the specific measurements of the roof line. However, if the roof line is a typical house roof and the string lights are hung horizontally across to connect the ends of the roof line, creating a triangle, the approximate length of lights needed would be the hypotenuse of the triangle (the longest side) which is equal to the square root of (leg 1^2 + leg 2^2).
A typical house roof is approximately 40 feet wide and 20 feet tall, which creates a right triangle with legs of 40 and 20. The hypotenuse of this triangle (the length of lights needed) would be approximately 64 feet (the square root of (40^2 + 20^2) = 64).
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