The mass in grams of 7.55 × 10²¹ molecules of water H₂O is 1.25 × 10⁻² g.
This is using mole concept.
What is mole?The International System of Units (SI) uses the mole (symbol mol) as the unit of material amount. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that material.
Exact 6.02214076 × 10²³ basic entities make up the mole. An elementary entity can be an atom, a molecule, an ion, an ion pair, or a subatomic particle like a proton depending on the makeup of the substance. For instance, although having differing volumes and masses, 10 moles of water (a chemical compound) and 10 moles of mercury (a chemical element) both have the same quantity of substance, and the mercury has exactly one atom for each molecule of the water.
The mass in grams of 7.55 x 10²¹ molecules of water H₂O can be calculated using Avogadro's number. Avogadro's number is 6.02 x 10²³molecules/gram-mole.
Mass (grams) = (7.55 x 10²¹ molecules) (1 Gram/6.02 x 10²³ molecules)
Mass (grams) = 1.25 x 10⁻² grams
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Why C is the correct answer? (the question is:Which of the following compounds are NOT aliphatic hydrocarbons?)
C is the correct option as it contains oxygen along with carbon and hydrogen. Aliphatic hydrocarbons that have had one or more hydrogen atoms .
Aliphatic hydrocarbons that have had one or more hydrogen atoms replaced by a halogen, such as those that have been fluorinated, chlorinated, brominated, or iodized, are known as halogenated aliphatic hydrocarbons.
The group of chemical molecules known as chlorinated aliphatic hydrocarbons is diverse and is characterised by an open-chain structure or a variable number of bonds, which can be single, double, or triple. C is the correct option as it contains oxygen along with carbon and hydrogen.
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Nitric acid is commercially available at a concentration of 15.9 M. What volume of this solution must be diluted to a final volume of 1.00 L to prepare a 4.00 M solution?
The "Ring of Responsibility" requires a next to water bodies. O 50-foot 43 3-foot O 5-foot O 15- to 25-foot untreated buffer zone
The "Ring of Responsibility" requires a 15- to 25-foot untreated buffer zone next to water bodies.
What is buffer zone?A buffer zone is an area of land that separates two or more countries, states, or territories, and is often demilitarized. The purpose of a buffer zone is to provide a space for negotiations and to reduce the possibility of conflict and war. Buffer zones can also be used to protect sensitive natural resources or habitats, such as areas of wilderness or wildlife. Buffer zones can be permanent or temporary, and can range in size from a few miles to hundreds of miles. In addition to physical barriers, buffer zones can also include economic, political, and social measures to reduce tensions between two or more parties. Buffer zones are an important tool in international relations, as they can help to prevent armed conflict and promote peaceful resolution of disputes.
This buffer zone is intended to prevent pollutants from entering the water body and protect it from potential environmental damage.
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When lead (II) nitrate reacts with sodium iodide, sodium
nitrate and lead (II) iodide are formed. If you start with 25.0
grams of lead (II) nitrate and 15.0 grams of sodium iodide, how
many grams of sodium nitrate can be formed?
Answer:
20.44 grams of sodium nitrate can be formed
Explanation:
The balanced chemical equation for the reaction between lead (II) nitrate and sodium iodide is:
Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2
What would be the bond type (covalent, polar covalent, ionic) for both B-H bonds in BH2? Explain in a short sentence.
Answer: non-polar covalent
Explanation:
If two atoms have an electronegativity difference of 0.4 or less, they form a non-polar covalent bond.
B is 2.04 electronegativity
H is 2.20 electronegativity
the electronegativity difference is 0.16.
this is less than 0.4 so the bonds are non-polar covalent.
An solution of antifreeze is prepared by mixing 47.0mL of ethylene glycol (d = 1.11 g/mL; molar mass = 62.07 g/mol) with 50.0 mL H2O (d = 1.00 g/mL) at 25°C. If the density of the antifreeze solution is 1.07 g/mL, what is its molarity?
If the density of antifreeze solution is 1.07 g/mL, then the molarity of the antifreeze solution is calculated as 8.66 M.
What is meant by molarity?Number of moles of solute dissolved per liter of the solution is defined as molarity.
As we know, moles of EG = mass of EG / molar mass of EG
Mass of EG = 47.0 mL × 1.11 g/mL = 52.17 g
Moles of EG = 52.17 g / 62.07 g/mol = 0.840 mol
Total volume = 47.0 mL + 50.0 mL = 97.0 mL
So, mass of solution = volume of solution × density of solution
mass of solution = 97.0 mL × 1.07 g/mL = 103.79 g
As, molarity =moles of solute /volume of solution
Molarity = 0.840 mol / (97.0 mL / 1000 mL/L) = 8.66 M
Therefore, the molarity of the antifreeze solution is 8.66 M.
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Listen A gas mixture contains O2. N₂, and Ar at partial pressures of 100, 150, and 200 torr, respectively. If CO2 gas is added to the mixture until the total pressure reaches 575 torr, what is the partial pressure of the CO₂? 575 torr 125 torr 450 torr 0.50 M E
We can start by using Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas component.
Let PCO2 be the partial pressure of CO2 in the mixture after it is added. Then, we can set up the following equation:
PO2 + PN2 + PAr + PCO2 = Ptotal
Substituting in the given partial pressures and total pressure, we get:
100 torr + 150 torr + 200 torr + PCO2 = 575 torr
Simplifying the equation, we get:
PCO2 = 575 torr - 100 torr - 150 torr - 200 torr
PCO2 = 125 torr
Therefore, the partial pressure of CO2 in the gas mixture is 125 torr. Answer: B) 125 torr.
A sodium ion Na+ with a charge of 1.6x10^-19 and a chloride ion Cl- with a charge of -1.6x10^-19 are separated by a distance of 4.95 Nm . How much work would be required to increase the separation of the two ions to an infinite distance?
Answer: , the work required to separate the two ions to an infinite distance is 4.63 x 10^-19 J.
Explanation: One can determine the potential energy of two point charges by utilizing the specified equation:
The value of U is directly proportional to the product of q1 and q2, and inversely proportional to the distance between them (r), where k is a constant factor.
The potential energy denoted by U is determined by the Coulomb constant, k, which has a value of 9 x 10^9 Nm^2/C^2. The calculation of U involves the charges of two particles, q1 and q2, as well as the distance between them, denoted by r.
We have an instance where a sodium ion (Na+) has a charge of 1.6x10^-19 C, and a chloride ion (Cl-) has a charge of -1.6x10^-19 C, positioned 4.95 Nm apart from each other.
Once we insert the given numbers, the result obtained is:
The expression for U can be obtained by utilizing the equation U = (kQq)/r, with k being the Coulomb's constant equal to 9 x 10^9 Nm^2/C^2, Q and q representing the electric charges of -1.6x10^-19 C and -1.6x10^-19 C, respectively, and r being the distance between the charges of 4.95 Nm.
The value of U is negative 4.63 times 10 to the power of negative 19 Joules.
It is important to observe that the negative symbol signifies the negativity of the potential energy, implying that effort must be exerted in order to disassociate the two ions.
Which term is best used to classify sodium chloride mixed in water (salt water) at room temperature?
The term that best classifies sodium chloride mixed in water at room temperature is a homogeneous mixture or solution.
~~~Harsha~~~
Answer:
It is homogeneous
Explanation:
A new band sensation is playing a concert and recording it for a live album to be released this summer. Select all the statements that are true for when the microphone records the sound.
a. The microphone changes the wave from an electromagnetic wave to a mechanical wave.
b. The recorded waves are electromagnetic waves.
c. The recorded waves are mechanical waves.
d. The microphone changes the wave from mechanical wave to an electromagnetic wave.
e. The microphone does not change the wave type.
f. The frequency or amplitude of the waves will not change in the microphone.
g. The frequency or amplitude of the waves will change in the microphone.
Answer:
c. The recorded waves are mechanical waves.
e. The microphone does not change the wave type.
g. The frequency or amplitude of the waves will change in the microphone.
These statements are true. The microphone records the sound waves as mechanical waves, which require a medium to travel through, such as air or water. The microphone does not change the type of wave from mechanical to electromagnetic, or vice versa. The frequency and amplitude of the sound waves will change as they pass through the microphone, depending on the characteristics of the source producing the sound.
A new band sensation is playing a concert and recording it for a live album to be released this summer. Sound waves from singers in the band are displayed in the diagram below.
Answer:
Wave A (blue wave) has the highest volume because it has the highest amplitude.
Waves B and C have equal volumes because they have the equal amplitude.
Wave C (green wave) has the highest pitch because it has the highest frequency.
Waves A and B have equal pitch because they have the equal frequency.
Complete the w expression for the autoionization of water at 25 °C.
Answer:
Please mark brainlist
Explanation:
The equilibrium expression for this reaction is Kw = [H₃O⁺][OH⁻], where Kw is the autoionization constant for water. At 25°C, the value of Kw is 1.0 x 10⁻¹⁴.
How many moles of ammonia would be required to react exactly with 0.470 moles of copper(I) oxide in the
following chemical reaction?
2 NH, (g) + 3 CuO (s) -> 3 Cu(s) + Na (8) + 3 H20 (g)
Answer: 0.313 mole of NH3
Explanation:
I NEED HELP WITH THIS QUESTION THANK YOU
The mole fraction of the solute in the solution is calculated as 0.1406.
What is non volatile solute?Non-volatile solute is a substance that does not readily evaporate at given temperature and pressure.
Raoult's law : P_total = P_solute + P_water
P_total is total vapor pressure of solution, P_solute is partial pressure of solute, and P_water is partial pressure of water.
Since the solute is non-volatile, we can assume that its partial pressure is negligible compared to the pressure of water. Therefore: P_total ≈ P_water
P_total = X_water * P°_water
X_water is mole fraction of water and P°_water is vapor pressure of pure water at same temperature.
305 torr = X_water * 355.1 torr (since P_total ≈ P_water)
X_water = 305 torr / 355.1 torr = 0.8594
X_solute = 1 - X_water = 1 - 0.8594 = 0.1406
Therefore, the mole fraction of the solute in the solution is 0.1406.
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A sealed container holds 12.0 L of gas
at 2.5 atm pressure. A valve is opened
any some gas escapes. What happens
to the pressure in the container?
A. The pressure remains the same.
B. The pressure increases.
C. The pressure decreases.
A sealed container holds 12.0 L of gas at 2.5 atm pressure. A valve is opened and some gas escapes. The pressure decreases. Option C is correct.
When a valve is opened in a sealed container of gas, some of the gas molecules inside the container escape.
This means that the total number of gas molecules inside the container decreases, which in turn causes the pressure to decrease. This can be explained by the ideal gas law.
If some gas escapes from the sealed container, the number of gas molecules inside the container decreases.
As a result, the pressure inside the container decreases as well.
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Determine the mass in grams of 7.55 × 1021 molecules of water H2O.
a.
7.14 × 10-4 g
d.
22.6 g
b.
2.59 x 102 g
e.
2.59 g
C.
0.226 g
Answer: the mass of 7.55 x 10^21 molecules of water is 0.226 g, which corresponds to option (c).
Explanation: The atomic weight of water (H2O) is:
2(1.008 g/mol) + 15.999 g/mol = 18.015 g/mol
Avogadro's number (NA) is:
6.022 x 10^23 molecules/mol
To calculate the mass of 7.55 x 10^21 particles of water, able to utilize the taking after equation:
mass = (number of atoms / Avogadro's number) x atomic weight
mass = (7.55 x 10^21 / 6.022 x 10^23) x 18.015 g/mol
mass = 0.226 g
Device an experiment to study the dependence of rate ov precipitation of sulphur upon the nature of monobasic acid for the reaction between thiosulphate ion and hydrogen ion
The expected result of the experiment is that the rate of precipitation of sulfur will be faster with hydrogen chloride than with acetic acid.
What is Precipitation?
Precipitation refers to the process in which a substance in a solution comes out of solution and forms a solid. This occurs when the concentration of the substance exceeds its solubility limit in the solution, resulting in the formation of solid particles that settle at the bottom of the solution.
Procedure:
Prepare a series of solutions with different monobasic acids. For example, you can prepare solutions of sodium thiosulphate (Na2S2O3) with different monobasic acids, such as hydrochloric acid (HCl), sulfuric acid (H2SO4), and nitric acid (HNO3), at a constant concentration and volume.
Place equal volumes of the thiosulphate solution and each monobasic acid solution in separate beakers or test tubes.
Start the timer or stopwatch as soon as the two solutions are mixed. The thiosulphate ions will react with the hydrogen ions from the monobasic acid, resulting in the formation of sulphur precipitate according to the following chemical equation:
S2O3^2- + 2H+ -> H2O + S + SO2
Observe the reaction and record the time taken for the formation of sulphur precipitate in each solution.
Compare the rates of precipitation of sulphur for each monobasic acid solution to study the dependence of the rate on the nature of the monobasic acid. Note any trends or differences in the rates of precipitation among the different acids used.
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A new band sensation is playing a concert and recording it for a live album to be released this summer. Select all the statements that are true for when the recorded sound moves through the speaker.
a. The frequency or amplitude of the waves will not change.
b. The speaker changes the wave from an electromagnetic wave to a mechanical wave.
c. The waves from the speaker are mechanical waves.
d. The frequency or amplitude of the waves could change.
e. The speaker changes the wave from mechanical wave to an electromagnetic wave.
f. The waves from the speaker are electromagnetic waves.
g. The speaker does not change the wave type.
Answer:
c. The waves from the speaker are mechanical waves.
d. The frequency or amplitude of the waves could change.
g. The speaker does not change the wave type.
These statements are true. The waves that come out of the speaker are mechanical waves, meaning they require a medium to travel through, such as air or water. The frequency and amplitude of the waves could change, depending on the characteristics of the sound being played through the speaker. The speaker does not change the type of wave from mechanical to electromagnetic, or vice versa.
Ca(OH)2 + 2HCl = CaCl2 + 2H2O
Go out to 3 decimal places for all values except 0.
In this reaction, 48.5 g of Ca(OH)2 and 32.8 g of HCl:
1) Determine how many moles of each reactant are present at the beginning of the reaction.
2) Convert one of the reactants into moles of the other reactant to determine whether or not it is the limiting reactant.
3) Convert moles of the excess reactant into moles of the product.
Moles of HCL present in the reaction is 0.899 moles
What is moles?The mole is the unit of substance that is equal to the number of atoms in 0.012 kilogrammes of carbon 12 and is represented by the sign "mol".
What is reaction?chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.
Use the following formula to calculate the moles of each reactant present at the start of the reaction:
Molar mass divided by mass equals a mole.
The molar mass of HCl is 36.461 g/mol (1.008 g/mol for H and 35.453 g/mol for Cl), while the molar mass of [tex]Ca(OH)_2[/tex] is 74.093 g/mol (40.078 g/mol for Ca, plus 215.999 g/mol for O and 21.008 g/mol for H).
Consequently, the amount of [tex]Ca(OH)_2[/tex] in the starting moles of the reaction is:
[tex]Ca(OH)_2[/tex] moles are equal to 48.5 g / 74.093 g/mol, or 0.654 moles.
At the start of the reaction, there are: moles of HCl present.
32.8 g of HCl divided by 36.461 g/mol yields 0.899 moles.
Since we have only 0.899 moles of HCl present, it is the limiting reactant. This means that all of the [tex]Ca(OH)_2[/tex] will react, and some of the HCl will be left over.
To convert this to grams, we use the formula:
mass = moles x molar mass
The molar mass of [tex]CaCl_2[/tex] is 110.984 g/mol (40.078 g/mol for Ca and 2*35.453 g/mol for Cl).
Therefore, the mass of [tex]CaCl_2[/tex] produced is:
mass of [tex]CaCl_2[/tex] = 0.654 moles x 110.984 g/mol = 72.6 g
So, 48.5 g of [tex]Ca(OH)_2[/tex] and 32.8 g of HCl will produce 72.6 g of [tex]CaCl_2[/tex] and 2 moles of [tex]H_2O[/tex].
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Why will the results be slow for test on the possible solutions for decreasing the impact of human activities on the ocean shores zones?
A. It will be slow because you will have to wait for control
B. It will be slow because you will have to wait for natural processes to affect each area
C. It will be slow because you will have to wait for more human activity within the area
D.It will be slow because you will have to wait to build sand dunes
B. It will be slow because you will have to wait for natural processes to affect each area.
What is Ocean?
An ocean is a vast body of saltwater that covers more than 70% of the Earth's surface. Oceans are the largest bodies of water on our planet and are essential for supporting life on Earth. Oceans play a crucial role in regulating the Earth's climate, absorbing heat and carbon dioxide, and generating oxygen.
The impact of human activities on ocean shores zones, such as coastal development, pollution, and overfishing, can have long-lasting and sometimes irreversible effects on these ecosystems. Restoring or mitigating the impacts of human activities on ocean shores zones requires time and effort, as natural processes need to take place to restore the affected areas.
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7. How many total atoms are present on the reactant side of the equation?
A. 3
B. 6
C. 7
D. 13
There are 6 atoms of oxygen present on the reactants side of the given reaction. Thus the correct answer is option B.
How do you calculate the total atoms present on the reactant side?Firstly, let us write the accurate chemical equation and then subsequently we will balance it as and when needed.
4Fe+3O₂→2Fe₂O₃
This is the correct balanced chemical equation for the reaction. And as we can find that the amount of iron and oxygen atoms on the reactants side is equivalent to that of the products side. This corroborates that the given chemical equation is correctly balanced.
Now, the query is based on counting the total number of oxygen atoms present on the side of reactants. As we can clearly see on the reactant side there are three Oxygen molecules that are present. That means that there are a total of six oxygen atoms, since 3*2 gives us a total of 6 oxygen atoms.
Hence, there are a sum total of six O₂ atoms that are present on the reactant side of the provided chemical equation.
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The full question is:
How many oxygen atoms are present on the reactant side of the chemical equation 4Fe+3O₂→2Fe₂O₃?
A. 3
B. 6
C. 7
D. 13
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How many atoms are in 4.5 moles of neon?
How many miles are in 1.2x1023 atoms of silicon?
How many moles are in 3.4x1023 molecules of CH4?
How many moles are in 5.2x1024 atoms of gold?
How many atoms are in 26.2 moles of cobalt?
How many cookies are in 1.2 mole of cookies?
The atoms of neon are [tex]27.099 *10^{23}[/tex], moles of silicon are 0.1199 , moles of [tex]CH_{4}[/tex] are 0.56, moles of gold are 8.64, atoms of cobalt are [tex]157.7764*10^{23}[/tex] and number of cookies are [tex]7.2264*10^{23}[/tex].
How to calculate atoms?Multiplying the number of moles with [tex]6.022*10^{23}[/tex] we will get number of atoms of neon.
Number of atoms= [tex]4.5* 6.022 *10^{23}[/tex]
Number of atoms of neon = [tex]27.099 *10^{23}[/tex]
Moles of silicon?Number of atoms= moles * [tex]6.022*10^{23}[/tex]
Moles of silicon = [tex]\frac{1.2*10^{23}}{6.022*10^{23} }[/tex]
Moles of silicon = 0.199 moles
Moles of [tex]CH_{4}[/tex] ?Number of atoms= moles * [tex]6.022*10^{23}[/tex]
Moles of [tex]CH_{4}[/tex] = [tex]\frac{3.4*10^{23} }{6.022*10^{23} }[/tex]
Moles of [tex]CH_{4}[/tex]= 0.56 moles
Moles of gold?Number of atoms= moles * [tex]6.022*10^{23}[/tex]
Moles of gold = [tex]\frac{5.2*10^{24} }{6.022*10^{23} }[/tex]
Moles of gold= 8.64 moles
Number of atoms of cobalt?Number of atoms= moles * [tex]6.022*10^{23}[/tex]
Number of atoms of cobalt = [tex]26.2*6.022*10^{23}[/tex]
Number of atoms of cobalt = [tex]157.7764*10^{23}[/tex]
Number of cookies ?Number of atoms= moles * [tex]6.022*10^{23}[/tex]
Number of cookies= [tex]1.2*6.022*10^{23}[/tex]
Number of cookies= [tex]7.2264*10^{23}[/tex]
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If you have 155 mL solution of a 0.762 mL solution of a 0.762 M FeCl3 solution, how many grams of FeCl3 are contained in this sample?
Select all answer choices that would result in units of moles.
a) RT/PV
b) PV/RT
c) mass ÷ molar mass
d) molar mass ÷ mass
e) molar mass × mass
f) molarity ÷ volume
g) volume ÷ molarity
h) molarity × volume
The correct options that will result in mole are option B, C, and H
How do i know which options will result in mole?To know the options that will result in mole, do the following:
Ideal gas law states as follow:
PV = nRT
Where
P is the pressure V is the volumen is the number of moleR is the gas constantT is the temperaturePV = nRT
Make n the subject by dividing both sides by RT
n = PV / RT (option B)
Mole, mass and molar mass are related according to the following formula:
Mole = mass / molar mass (option C)
Molarity is defined as mole per unit volume as shown below:
Molarity = mole / volume
Make mole the subject by cross multiplying.
Mole = Molarity × volume (option H)
Thus, from the above illustrations, we can conclude that the correct options which will result in mole are option B, C, and H
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3. 20.0 grams of NaHCO3 decomposes following the balanced reaction below. How many grams of H2O will you form? Show all work. 2 NaHCO3 → H2O + CO2 + Na2CO3
Taking into account the reaction stoichiometry, 2.14 grams of H₂O are formed when 20.0 grams of NaHCO₃ decomposes.
Reaction stoichiometryIn first place, the balanced reaction is:
2 NaHCO₃ → H₂O + CO₂ + Na₂CO₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
NaHCO₃: 2 moleH₂O: 1 moleCO₂: 1 moleNa₂CO₃: 1 moleThe molar mass of the compounds is:
NaHCO₃: 84 g/moleH₂O: 18 g/moleCO₂: 44 g/moleNa₂CO₃: 106 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
NaHCO₃: 2 moles ×84 g/mole= 168 gramsH₂O: 1 mole ×18 g/mole= 18 gramsCO₂: 1 mole ×44 g/mole= 44 gramsNa₂CO₃: 1 mole ×106 g/mole= 106 gramsMass of H₂O formedThe following rule of three can be applied: if by reaction stoichiometry 168 grams of NaHCO₃ form 18 grams of H₂O, 20 grams of NaHCO₃ form how much mass of H₂O?
mass of H₂O= (20 grams of NaHCO₃× 18 grams of H₂O)÷168 grams of NaHCO₃
mass of H₂O= 2.14 grams
Finally, 2.14 grams of H₂O are formed.
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For a particular reaction at 121.3 °C, Δ=53.29 kJ/mol , and Δ=623.51 J/(mol⋅K) . Calculate ΔG for this reaction at −79.6 °C.
At -79.6 °C, the standard free energy change for this reaction is -67.24 kJ/mol.
How to determine standard free energy change?Use the following equation to calculate the standard free energy change at a different temperature:
ΔG = ΔH - TΔS
where ΔH = enthalpy change, ΔS = entropy change, and T = temperature in Kelvin.
Given:
ΔH = 53.29 kJ/mol
ΔS = 623.51 J/(mol⋅K)
T = -79.6 + 273.15 K = 193.55 K
First, convert ΔH from kJ/mol to J/mol:
ΔH = 53.29 × 10³ J/mol
Next, convert ΔS from J/(mol⋅K) to kJ/(mol⋅K):
ΔS = 623.51 J/(mol⋅K) ÷ 1000 = 0.62351 kJ/(mol⋅K)
Plug in the values:
ΔG = (53.29 × 10³ J/mol) - (193.55 K × 0.62351 kJ/(mol⋅K))
ΔG = 53.29 kJ/mol - 120.53 kJ/mol
ΔG = -67.24 kJ/mol
Therefore, the standard free energy change for this reaction at -79.6 °C is -67.24 kJ/mol.
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What is the molar solubility, S, of AgNO, if Ksp , = 6.00 × 10-4?
As a result, AgNO3 has a molar solubility of 0.0245 M.
what does molar solubility mean?A compound's capacity to dissolve in a particular substance known as a solvent is indicated by a property termed molar solubility (M). It is specifically the most moles of a solute that may dissolve in one liter of solvent.
The Ksp (solubility product constant) formula, which is the product of the ion concentrations elevated to their stoichiometric coefficients in a saturated solution4, can be used to determine the molar solubility of AgNO3.
The formula for AgNO3 is AgNO3 → Ag+ + NO3-.
Therefore, Ksp = [Ag+][NO3-] = 6.00 × 10⁻⁴
Since AgNO3 dissociates completely in water, [Ag+] = [NO3-] = S (molar solubility).
Thus, Ksp = S² = 6.00 × 10⁻⁴.
Solving for S gives us S = √(Ksp) =√(6.00 × 10⁻⁴) = 0.0245 M⁴
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80.0 grams of potassium sulfate is dissolved in 320 grams of water. Find the percentage concentration
The percentage concentration of potassium sulfate in the solution is 20%.
What is Percentage Concentration?
Percentage concentration, also known as percent concentration or mass percent, is a measure of the amount of a solute present in a solution, expressed as a percentage of the total mass or volume of the solution. It is commonly used in chemistry and related fields to express the concentration of a solute in a solution.
To find the percentage concentration of potassium sulfate in the solution, we need to calculate the mass of potassium sulfate in the solution and express it as a percentage of the total mass of the solution.
Given:
Mass of potassium sulfate (K2SO4) = 80.0 g
Mass of water (H2O) = 320 g
Total mass of the solution = Mass of potassium sulfate + Mass of water
= 80.0 g + 320 g
= 400 g
Now, we can calculate the percentage concentration of potassium sulfate:
Percentage concentration = (Mass of potassium sulfate / Total mass of the solution) × 100
Percentage concentration = (80.0 g / 400 g) × 100
= 20%
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How many grams of oxygen form when each quantity of reactant completely reacts?
2HgO(s)→2Hg(l)+O2(g)
When 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.
The oxygen produced
The balanced chemical equation for the reaction:
2HgO(s) → 2Hg(l) + O2(g)
states that 2 moles of HgO will produce 1 mole of O2.
We can use the molar mass of HgO and the mole ratio of HgO to O2 to calculate the mass of O2 produced from a given mass of HgO.
The molar mass of HgO is 216.59 g/mol (200.59 g/mol for Hg + 16.00 g/mol for O).
So, 1 mole of HgO has a mass of 216.59 g.
According to the balanced equation, 2 moles of HgO produce 1 mole of O2.
Therefore, 1 mole of O2 has a mass of 32.00 g.
Using stoichiometry, we can calculate the mass of O2 produced when a certain mass of HgO reacts completely.
For example, if we start with 216.59 g of HgO (1 mole), then the amount of O2 produced will be 0.5 moles (1 mole of O2 for every 2 moles of HgO), which is equivalent to 16.00 g of O2 (0.5 moles of O2 x 32.00 g/mol).
So, when 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.
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O Macmillan Learning
What is the IUPAC name for the compound shown?
IUPAC name:
The compound shown has the IUPAC name O Macmillan Learning. -3-ethyl-2,2-dimethyl-hexane Incorrect.
Why was 1 6 dimethylhexane wrong?Explanation and response: Because it implies that there's methyl groups on carbons number one and sixth of the parent carbon chain, the name — appears-dimethylhexane is incorrect. Because the name "hexane" implies that a parent atom chain only has six molecules long, the methyl groups are located at the ends of every molecule.
Is hexane considered an organic chemical?Hexane, commonly referred to as sextane, is an organic compound that belongs to the alkane class. They are acyclic branched as well unbranched hydrocarbons with the standard structure CnH2n+2, and thus entirely composed of hydrogen and saturated oxygen atoms. Hexane is a colorless, clear liquid.
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