Answer: they each carried 5 water bottles.
Step-by-step explanation: 8x5 equals 40
Answer: 5
Step-by-step explanation:
40 divided by 8
Which transformation(s) can be used to map one triangle onto the other? select two options. reflection only translation only dilation, then translation rotation, then translation rotation then dilation
Transformation which can be used for mapping of one triangle to another are;
Only translationRotation then dilation.What does mapping mean in geometry?
Any method that is outlined for assigning a specific object from one (or the same) set to each object in another is known as mapping. Any set, including all whole integers, all the points on a line, or all the objects inside a circle, can be mapped.We need to map one triangle to another ;
Hence, for mapping of one triangle to another,
The transformation which can be used from the given options are;
Only translationRotation then dilationLearn more about mapping
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Answer:
B. translation only
E. rotation then dilation
Step-by-step explanation:
B. translation only
E. rotation then dilation
Abc co issues a zero coupon bond with 5 years to maturity. investor's required rate of return is 3.25%, what is the price of the zero coupon bond issued?
Based on the number of years till maturity and the required rate of return, the price of the zero-coupon bond is $852.22.
what price is the zero coupon bond selling at?When a bond's par value is not given, assume it is $1,000.
the price of a zero coupon bond is:
= par value / (1 + rate) ^ number of years till maturity
solving gives:
= 1,000 / (1 + 3.25%)⁵
= 1,000 / 1.17341139582939453125
= $852.22
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Which system of inequalities is shown?
O A. y
y< 4
) B. y>x
y > 4
O C. y>x
y < 4
y > 4
Answer:
y < x
y < 4
Step-by-step explanation:
Dotted line means < or >, and since the shaded region is below the lines y = 4 and y = x, the answer is A.
I need help in this !! Thank you !!
(a) The median mark is 44
(b) The number of students who scored 54 marks or less is 120
(c) The number of students who scored 60 marks or more is 20
Cumulative frequency curve (OGIVE)From the question, we are to determine the median mark
The median mark for a cumulative frequency curve corresponds to the second quartile (Q₂)
Q₂ = 1/2(n+1)th mark
Where n is the total frequency
In the graph,
n = 160
∴ Q₂ = 1/2(160+1)th mark
Q₂ = 80.5th mark
The 80.5th mark is 44
∴ The median mark is 44
(b)
The number of students who scored 54 marks or less = 120 - 0
The number of students who scored 54 marks or less = 120
(c)
The number of students who scored 60 marks or more = 160 - 140
The number of students who scored 60 marks or more = 20
Hence, (a) The median mark is 44
(b) The number of students who scored 54 marks or less is 120
(c) The number of students who scored 60 marks or more is 20
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please help me im in a rush
Answer:
a. 25 seniors are randomly selected; 14 plan to go to a 4 year college
b. 420 students
Step-by-step explanation:
a. the less they have in common, the better
b. 14/25 is only between 25 students. make the denominator the same (750) and multiply the same to the numerator
750/25 = 30
14/25 x 30 = 420/750
A rectangle has a side length of two and seven eighths feet and a side width of 5 feet. What is the area of the rectangle?
A. six and five eighths ft2
B. nine and two eighths ft2
C. fourteen and one eighths ft2
D. fourteen and two eighths ft2
Answer:
14 3/8 ft^2
Step-by-step explanation:
Area = length * width
= 2 7/8 * 5
= 23/8 * 5
= 115/8
= 14 3/8 ft^2.
Divide. Reduce the answer to lowest terms.
Answer:
[tex]\frac{4}{15}[/tex]
Step-by-step explanation:
Given the following question:
[tex]\frac{1}{5} \div\frac{3}{4}[/tex]
To find the answer we will use KCF (Keep, Change, Flip) apply it to the following question and then complete by multiplying and reducing. If needed of course.
[tex]\frac{1}{5} \div\frac{3}{4}[/tex]
Apply KCF:
[tex]\frac{1}{5} \div\frac{3}{4}=\frac{1}{5} \times\frac{4}{3}[/tex]
[tex]\frac{1}{5} \times\frac{4}{3}[/tex]
Solve:
[tex]1\times4=4[/tex]
[tex]5\times3=15[/tex]
[tex]=\frac{4}{15}[/tex]
Answer is in simplest terms.
Which means your answer is the first option or "4/15."
Hope this helps.
What is the domain of f(x)=
F(X). 4)*
?
A. x>0
B. All real numbers
C. y> 0
D. x<0
Answer: All real numbers
Step-by-step explanation:
The domain is the set of inputs.
As an oak tree grows taller, it also grows wider. In other
words, the diameter of its trunk increases. Imagine that a
tree's height is about 8 times its diameter. Assume this
relationship will not change, and that the tree trunk is a
rather cylindrical shape. Write a function for the volume of
wood in the tree's trunk as it grows
The volume of wood in the tree's trunk as it grows is [tex]16\pi r^3[/tex]
The capacity of a cylinder, which determines how much material it can carry, is determined by the cylinder's volume. There is a formula for the volume of a cylinder that is used in geometry to determine how much of any quantity, whether liquid or solid, may be immersed in it uniformly. A cylinder is a three-dimensional structure having two parallel, identical bases that are congruent.
Thus, the volume (V) of a right circular cylinder, using the above formula, is, [tex]V = \pi r^2h[/tex] , where
'r' is the radius of the base (circle) of the cylinder
'h' is the height of the cylinder
Given:
Height(h) = 8 x diameter = 16 x radius (r) (diameter = 2 x radius )
∴ h = 16r.
V= [tex]\pi r^2h[/tex]
Substituting h = 16r in the volume formula we get
V = [tex]\pi r^2(16r)[/tex] = [tex]16\pi r^3[/tex]
Thus the volume of wood in the tree's trunk as it grows is [tex]16\pi r^3[/tex].
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The area of a rectangular cocktail table is x²-18x +32. If the width is x-16, what is it's length?
Answer:
x-2
Step-by-step explanation:
The formula for area of rectangle is length x width
And we know that width is x-16
And we know that the area is [tex]x^{2} -18x +32[/tex]
So we know that when x-2 is multiplied with x-16, it gives off [tex]x^{2} -18x +32[/tex]
The vertices of a rectangle are Q (2, -3), R (2,4), S (5,4), and T (5, -3).
4. Translate rectangle QRST 3 units left and 3 units down to produce rectangle Q'R'S'T'. Find the area of QRST and the area of rectangle Q'R'S'T'.
5. Compare the areas. Make a conjecture about the areas of a preimage and its image after a
translation.
6. The vector PQ=(4,1) describes the translation of A (-1, w) onto A' (2x+1, 4) and B (8y-1,
1) onto B' (3,32). Find the values of w, x, y, and z.
4) [tex]A_{QRST} = A_{Q'R'S'T'} = 9[/tex].
5) The areas of the rectangles QRST and Q'R'S'T' are the same since the translation of the geometric loci conserved the Euclidean distance.
6) x = 1, w = 3, y = - 1/4, z = 1/3
How to analyze and apply rigid transformations
Rigid transformations are transformations applied on geometric loci such that Euclidean distance is conserved. In this question we have applications of translations, a kind of rigid transformation.
Exercise 4
In this part we must determine the areas of rectangles QRST and Q'R'S'T':
Rectangle QRST
A = RS · QT
A = 3 · 3
A = 9
Rectangle Q'R'S'T'
Q'(x, y) = (2, - 3) + (- 3, - 3)
Q'(x, y) = (- 1, - 6)
R'(x, y) = (2, 4) + (- 3, - 3)
R'(x, y) = (- 1, 1)
S'(x, y) = (5, 4) + (- 3, - 3)
S'(x, y) = (2, 1)
T'(x, y) = (5, - 3) + (- 3, - 3)
T'(x, y) = (2, - 6)
A = R'S' · Q'T'
A = 3 · 3
A = 9
The rectangles QRST and Q'R'S'T' have both an area of 9 square units.
Exercise 5
The areas of the rectangles QRST and Q'R'S'T' are the same since the translation of the geometric loci conserved the Euclidean distance.
Exercise 6
In this case, we must solve the following equations:
PQ = A'(x, y) - A(x, y)
(4, 1) = (2 · x + 1, 4) - (- 1, w)
(4, 1) = (2 · x + 2, 4 - w)
(4, 1) = (2 · x, - w) + (2, 4)
(2, - 3) = (2 · x, - w)
(x, w) = (1, 3)
PQ = B'(x, y) - B(x, y)
(4, 1) = (3, 3 · z) - (8 · y - 1, 1)
(4, 1) = (2 - 8 · y, 3 · z)
(4, 1) = (- 8 · y, 3 · z) + (2, 0)
(2, 1) = (- 8 · y, 3 · z)
(y, z) = (- 1/4, 1/3)
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Which of these is the equation of a graph
in which the vertex is (4, 2) and
a=-2
HELPPPPPPPP
The equation of the graph in which the vertex (4,2) and a=-2 is
y=-2[tex](x-4)^{2}[/tex]+2.
Given that the point of the vertex is (4,2) and a=-2.
Equation is like a relationship between two or more variables expressed in equal to form. Equations of two variables look like ax+by=c. It may be a linear equation,quadratic equation, cubic equation or many more depending on the power of variable in the equation.
We know that point of vertex look like (h,k) in the equation and equation look like as under:
y=a[tex](x-h)^{2} +k[/tex].-----------1
So in order to find the equation we have to just put h=4 and k=2 and a=2 in equation 1.
y=-2[tex](x-4)^{2} +2[/tex]
Hence the equation of the graph in which the vertex (4,2) and a=-2 is
y=-2[tex](x-4)^{2}[/tex]+2.
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Which phrase describes an unknown or changeable quantity?
Answer:
That is a variable.
Step-by-step explanation:
- opposed to a constant which is known and does not change.
Can someone help me out on these geometry questions? ASAP!!!
Write formal proofs the HL Theorm.
Question 2
1) [tex]\overline{PR} \perp\overline{QS}, \overline{PQ} \cong \overline{PS}[/tex] (given)
2) [tex]\overline{PR} \cong \overline{PR}[/tex] (reflexive property)
3) [tex]\angle PRQ, \angle PRS[/tex] are right angles (perpendicular lines form right angles)
4) [tex]\triangle PRQ, \triangle PRS[/tex] are right triangles (a triangle with a right angle is a right triangle)
5) [tex]\triangle PRQ \cong \triangle PRS[/tex] (HL)
Question 3
1) [tex]\angle C[/tex] is a right angle, [tex]\overline{AC} \cong \overline{AE}, \overline{DE} \perp \overline{AB}[/tex] (given)
2) [tex]\angle DEA[/tex] is a right angle (perpendicular lines form right angles)
3) [tex]\triangle ACD, \triangle DAE[/tex] are right triangles (a triangle with a right triangle is a right angle)
4) [tex]\overline{AD} \cong \overline{AD}[/tex] (reflexive property)
5) [tex]\triangle ACD \cong \triangle AED[/tex] (HL)
6) [tex]\angle CAD \cong \angle DAE[/tex] (CPCTC)
7) [tex]\overline{AD}[/tex] bisects [tex]\angle BAC[/tex] (if a segment splits an angle into two congruent parts, it is an angle bisector)
what is the potential energy of a rock that weighs 100 newtons that sits on a hill 300 meters high
Answer:
30000J or 30 KJ
Step-by-step explanation:
Formula for finding Gravitiational Potential Energy or GPE = mgh (or Wh since W = mg)
Given
W = 100N
h = 300m,
GPE = Wh = 100 x 300 = 30000J or 30 KJ
pls help ILL MARK BRAINLIEST
Answer:
a) Height of the ledge is 1.6 m.
b) roots of the equation are: [tex]\bf d = 2[/tex] , [tex]\bf d = -1[/tex]
c) Maximum height reached = 1.8 m.
Step-by-step explanation:
a) The height of the ledge is the same as the height at which Jake is when he hasn't moved any horizontal distance from the ledge yet, that is, when d = 0:
[tex]h = -0.8(0)^2 + 0.8(0) + 1.6[/tex]
⇒ [tex]\bf h = 1.6 \space\ m[/tex]
∴ Height of the ledge is 1.6 m.
b) The x-intercepts occur where y = 0, that is when h = 0:
[tex]-0.8d^2 + 0.8d + 1.6 = 0[/tex]
Divide both sides of the equation by -0.8:
[tex]d^2 - d -2 = 0[/tex]
Factorizing:
⇒ [tex]d^2 -2d + d - 2 = 0[/tex]
⇒ [tex]d(d-2) +1 (d-2) = 0[/tex]
⇒ [tex](d-2)(d+1) = 0[/tex]
⇒ [tex]d - 2 = 0[/tex] or [tex]d + 1 = 0[/tex]
∴ roots are : [tex]\bf d = 2[/tex] , [tex]\bf d = -1[/tex]
c) To find the maximum value of a quadratic equation in the form
y = ax² + bx + c , use the formula:
max = c - (b² / 4a).
Using the formula for [tex]h = -0.8x^2 + 0.8x + 1.6[/tex] :
max h = [tex]1.6 - ( \frac{0.8^2}{4(-0.8)} )[/tex]
= 1.8
∴ Maximum height reached = 1.8 m.
Answer:
a) 1.6 m
b) -1, 2 meters
c) 1.8 m
Step-by-step explanation:
Apparently, technology tools are allowed when solving this problem. They readily show you the x- and y-intercepts and the vertex of the graph.
a) ledge heightThe height of the ledge is the value of h when d=0. It is the constant in the given equation, and the y-intercept of the graph.
The height of the ledge is 1.6 meters.
b) rootsThe x-intercepts are the values of d that make h equal to zero. The graph shows them to be ...
d = -1
d = 2 . . . . meters
c) maximum heightThe maximum height is the "h" coordinate of the vertex (d, h).
The maximum height is 1.8 meters.
__
Additional comment
"x" is the generic independent variable. The horizontal axis of a graph is often called the "x-axis" and places where the graph crosses that axis are called "x-intercepts" even when the independent variable is named something else. Here, the independent variable is "d", not "x".
Similarly, "y" is the generic dependent variable, and the vertical axis of a graph is often called the "y-axis" even when the dependent variable is something else. This is why we refer to h when d=0 as the "y-intercept". It is the point where the graph crosses the vertical axis.
The first three terms of a sequence are
given. Round to the nearest thousandth (if
necessary).
3, 6, 12, ...
Find the 9th term.
Answer: 768
Step-by-step explanation:
3, 6 ,12 ,24, 48, 96, 192, 384, 768
12 x 2 = 48
48 x 2 = 96
96 x 2 = 192
192 x 2 = 384
384 x 2 = 768
A basketball league’s average score is 58 points per game. Coach McGee tracks a team’s average for five weeks and compares it to the league’s average. The table shows the variances in scores for five weeks.
Points Above/Below Average
Week 1
Week 2
Week 3
Week 4
Week 5
2 and StartFraction 1 Over 8 EndFraction
1.6
Negative 2 and StartFraction 1 Over 8 EndFraction
–1.8
Negative 1 and StartFraction 4 Over 5 EndFraction
Which comparison is true? Use the number line to help you.
A number line going from negative 5 to positive 3 in increments of 1.
Week 1 = Week 3
Week 4 = Week 5
Week 2 < Week 4
Week 5 < Week 3
The correct option for the inequality is
Week 4 = Week 5. Option B. This is further explained below.
What is inequality?Generally, the relationship between two expressions that do not have the same value is denoted by a sign such as, which means "not equal to," >, which means "greater than," or, which means "less than."
In conclusion, When converted to decimal form, Week 5's score comes out to -1.8, which is the same as Week 4's score.
Week 4 = Week 5
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Answer:
The Answer Is B
Step-by-step explanation:
Week 4 = Week 5
A region in the first quadrant is bounded by the graph y equals two thirds times x, the y-axis, and the horizontal line y
By definite integrals and area formula of a rectangle, we find that the area of the region in the first quadrant is 147 / 4 square units.
How to calculate the area of the region by definite integrals
Integrals can be used to determine the area of regions bounded by curves set on Cartesian plane. The upper limit of the integral of the question is initially found:
(2 / 3) · x = 7
x = 21 / 2
The area can be defined as an rectangle in the first quadrant minus the area below the linear equation:
[tex]A = \left(\frac{21}{2} \right) \cdot (7) - \frac{2}{3} \int\limits^{\frac{21}{2} }_{0} {x} \, dx[/tex]
[tex]A = \frac{147}{2} - \frac{1}{3} \cdot \left[\left(\frac{21}{2} \right)^{2}-0^{2}\right][/tex]
A = 147/4
By definite integrals and area formula of a rectangle, we find that the area of the region in the first quadrant is 147 / 4 square units.
Remark
The statement is poorly formatted and incomplete. Correct form is shown below:
A region in the first quadrant is bounded by the line y = (2/3) · x, the y-axis and the horizontal line y = 7. Determine the area of the region.
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The line plot (shown in the attached image) shows the prices of sunglasses at a department store.
a. Find the mean, median, and mode.
b. Which measure best describes the data? Why?
c. Which measure might be misleading in describing the average price of sunglasses? Explain your reasoning.
Please help!! show all work and be sure to give final responses in complete sentence form in context of the problem, and explain your reasoning.
a. Mean is 70.8, median is 70, and mode is 60
b. Mean describes the data best
c. Mean can be a misleading central measure in case of outliers
Calculating Mean, Median and Mode
Mean = Total sum of pries / Total number of sunglasses
Mean = (20 + 20 + 50 + 50 + 50 + 60 + 60 + 60 + 60 + 60 + 60 + 70 + 70 + 70 + 80 + 80 + 80 + 80 + 90 + 90 + 90 + 90 + 100 + 100 + 130) / 25
Mean = 70.8
Median = (n/2 + 1)th term
Here, n is the number of sunglasses.
Median = (25/2 + 1)th term
Median =13th term
Median = 70
Mode = Most occurring data
Mode = 70
Why is mean the best central measure to describe the data?
When your data distribution is continuous and symmetrical, such as when your data are normally distributed, the mean is typically the best measure of central tendency to utilize. Thus, mean describes the average price of the sunglasses here
Mean Being Misleading
In case there are outliers, the mean of the data gets highly affected. Hence, it can be misleading for analyzing average price of the data.
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The lateral surface area of cone A is exactly 1/2 the lateral surface area of cylinder B. Cone A radius is r and height h - Cylinder B radius is r and height h. True or false?
The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to [tex]r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}[/tex]. (Correct choice: False)
What is the ratio of lateral area of cone to the lateral area of the cylinder?In accordance with space geometry, the lateral areas of the cone and cylinder are described by the following equations:
Cone
[tex]A_{l} = \pi \cdot r \cdot \sqrt{r^{2}+h^{2}}[/tex] (1)
Cylinder
[tex]A_{l} = 2\pi\cdot r\cdot h[/tex] (2)
If we divide (2) by (1), then we have the following ratio:
[tex]r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}[/tex]
The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to [tex]r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}[/tex]. (Correct choice: False)
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Shawna, Ryan, and Dominic ate a whole pizza. Shawna ate 1
3 of the pizza
and Ryan ate 1
2 of the pizza. Dominic ate the rest of the pizza. How much
pizza did Dominic eat?
Answer:
[tex]\frac{1}{6}[/tex]
Step-by-step explanation:
You need to add the amount Shawna & Ryan ate together, then subtract it from 1 to find the amount of pizza that was left for Dominic to eat.
[tex]\frac{1}{3}[/tex] + [tex]\frac{1}{2}[/tex] = ?
Make all the denominators the same to add fractions.
[tex]\frac{1}{3}[/tex] is [tex]\frac{2}{6}[/tex]
[tex]\frac{1}{2}[/tex] is [tex]\frac{3}{6}[/tex]
[tex]\frac{2}{6}[/tex] + [tex]\frac{3}{6}[/tex] = [tex]\frac{5}{6}[/tex]
1 - [tex]\frac{5}{6}[/tex] = [tex]\frac{1}{6}[/tex]
Evaluate the function when x=5
F(5)=?
Step-by-step explanation:
When evaluating piecewise function, make sure the x value satisfies the function we use.
since 5>3, we use the second equations
That function is a constant function, this means at any x>3, exclusive, we will have a y value of -1.
So
[tex]f(5) = - 1[/tex]
Can someone please tell me which one is correct??? The first screenshot is the question and the second screenshot is the options I have. I am in dire need of help
Answer:
43.5 unit^2.
Step-by-step explanation:
Area of the triangle
= 1/2 * base * height
= 1/2 * AB * AC.
AB = √ [(6-1)^2 + (6-8)^2] = √29
AC = √ [(8 - (-7))^2 + (1 - (-5)^2] = √261
So the area = 1/2 * √29 * √261
= 43.5
URGENT!!
Given the following table with selected values of f (x) and g(x), evaluate f (g(4)).
x –6 –4 1 3 4
f (x) 4 –1 –6 1 3
g(x) 1 4 3 –4 –6
–4
–1
1
4
Answer:
f[g(4)] = 4
Step-by-step explanation:
Given table:
[tex]\begin{array}{| c | c | c | c | c | c |}\cline{1-6} x & -6 & -4 & 1 & 3 & 4\\\cline{1-6} f(x) & 4 & -1 & -6 & 1 & 3 \\\cline{1-6} g(x) & 1 & 4 & 3 & -4 & -6 \\\cline{1-6}\end{array}[/tex]
f[g(4)] is a composite function.
When calculating composite functions, always work from inside the brackets out.
Begin with g(4): g(4) is the value of function g(x) when x = 4.
From inspection of the given table, g(4) = -6
Therefore, f[g(4)] = f(-6)
f(-6) is the value of function f(x) when x = -6.
From inspection of the given table, f(-6) = 4
Therefore, f[g(4)] = 4
As we can see
g(4)=-6So
f(g(4))f(-6)45.a.A tourist buys 5 pieces of Nepali cap at Rs 452 per piece including 13% VAT. How much will he recive while leaving Nepal?
Step-by-step explanation:
vat of a cap=13/100*452
=58.76
price after vat=58.76+452=510.76
price after vat of 5 cap = 510.76*5=2553.8
PLEASE HELP IM STUXK
On an exam you get two points for every question answered correctly, zero points for each question left blank and lose one-half point for each question answered incorrectly. what is your total score on the exam if you answered 13 questions correctly, leave 7 questions blank and answer 5 questions incorrectly?
Using multiplication, the total score on the exam if you answered 13 questions correctly, leave 7 questions blank and answer 5 questions incorrectly is 39 point.
According to the question,
For each correct question, you get 2 points, and there are 22 correct questions, so multiply 22 by 2
22 * 2 = 44 points.
For each question left blank, you get 0 points, and there are 7 questions left blank, so multiply 7 by 0
7 * 0 = 0 points
For each incorrect question, you get -1 point, and there are 5 incorrect questions, so multiply 5 by -1
5 * (-1) = -5 points.
The total number of score = 22*2 + 7*0 + 5*(-1) = 44 + 0 - 5 = 39 points.
Hence, using multiplication, the total score on the exam if you answered 13 questions correctly, leave 7 questions blank and answer 5 questions incorrectly is 39 point.
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Change the equation of the parent square root function to represent the equation of the graphed function. Enter the correct answer in the box.
The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2
According to the statement
we have to show the square root function as a equation in the graphical representation.
So,
we know that the definition of a
Graph a diagram showing the relation between variable quantities, typically of two variables and it also show the relation between more than two variables.
Now, we know that the definition of Equation is a mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
And the equation obtained from the graph is a y=√x-2 by a some calculations in the graph.
So, The equation of the parent square root function to represent the equation of the graphed function will be, y=√x-2
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Could y’all help me
Answer:
16. C
17. C
Step-by-step explanation:
16.
this is just a multiplication of the 2 functions.
that means we multiply the functional expressions, and the result is the new functional expression of the multiplied functions.
2(3x - 5) × (-2x + 1) = (6x - 10) × (-2x + 1) =
= 6x×-2x + 6x×1 + -10×-2x + -10×1 =
= -12x² + 6x + 20x - 10 = -12x² + 26x - 10
17.
the domain of a function is the interval or set of all valid x values (or input values).
the range is the interval or set of all valid y or functional result values.
so, for the domain we need to see what values x may have for a 4th root.
for this we can imagine that a 4th root is the square root of the square root of x.
this is directly related to x⁴ being the square of the square of x.
the valid input values for a square root are all positive numbers (incl. 0). the result will be again a positive number (incl. 0), which is again a valid input number for the second square root.
therefore, the valid values of x for a 4th root are also the valid values for a square root. and vice versa.
and that is
0 <= x < infinity
FYI : we can never say x = infinity, because infinity is not a number, just a generation concept. so, infinity can never be included in any interval, it can only be listed as an excluded limit concept.