Expand the polynomial: (2x+3)^2

The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

The interval is given as:

x = 2 to x = 5

The slope is calculated as:

[tex]m = \frac{y_2 -y_1}{x_2-x_1}[/tex]

16. y = 3x - 4

Substitute 2 and 5 for x

y = 3*2 - 4 = 2

y = 3*5 - 4 = 11

So, we have:

[tex]m = \frac{11 - 2}{5 - 2}[/tex]

[tex]m = \frac{9}{3}[/tex]

Divide

m = 3

Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3

17. y = 2x^2-4x - 2

Substitute 2 and 5 for x

y = 2 * 2^2 - 4 * 2 - 2 = -2

y = 2 * 5^2 - 4 * 5 - 2 = 28

So, we have:

[tex]m = \frac{28 + 2}{5 - 2}[/tex]

[tex]m = \frac{30}{3}[/tex]

Divide

m = 10

Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10

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The equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4

From the question, we are to determine the equation of the line that has a slope of 3 and that passes through the point (5,19)

Using the point-slope form of an equation of a line

y - y₁ = m(x - x₁)

Where m is the slope

and (x₁, y₁) is a point on the line

From the given information

m = 3

x₁ = 5

y₁ = 19

Putting the parameters into the equation, we get

y - 19 = 3(x - 5)

y - 19 = 3x - 15

y = 3x -15 + 19

y = 3x +4

Hence, the equation of the line that has a slope of 3 and that passes through the point (5,19) is y = 3x + 4

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a) The linear function that models the population in t years after 2004 is: P(t) = -200t + 29600.

b) Using the function, the estimate for the population in 2020 is of 26,400.

A linear function is modeled by:

y = mx + b

In which:

The initial population in 2004, of 29600, is the y-intercept. In 12 years, the population decayed 2400, hence the slope is:

m = -2400/12 = -200.

Hence the equation is:

P(t) = -200t + 29600.

2020 is 16 years after 2004, hence the estimate is:

P(16) = -200(16) + 29600 = 26,400.

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Answer:

-3

Step-by-step explanation:

Answer: 3/4

Step-by-step explanation:

Parallel lines have the same slope.

Answer:

only (0,5)

Step-by-step explanation:

(0,5) is in the shaded region on the graph, so it is a solution.

One other point is in the unshaded region so it is NOT a solution. The other two points are on the dashed line, so they are NOT solutions. If the line was solid (not dashed) they would work, but since the line is dashed they are NOT solutions.

Answer:

A. (0,5)

Step-by-step explanation:

Answer:

98

Step-by-step explanation:

Solution 1, (quick)

When enlarging by a scale factor, the shape's area is multiplied by the scale factor squared.

3.5*7*2^2=98

This works because for a rectangle width x and length y, width 2x and length is 2y, area is 4xy compared to area xy originally.

Solution 2, (technical)

Scale factor of 2 means multiplying by 2

3.5^2=7

7*2=14

7*14=98

she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

According to the statement

Janice bought total items = 30

Price of items are 30 cents, 2 dollars, or 3 dollars.

Total purchase price of Janice = 30$

If we let she bought 10 items at price of 3$, Then it is not possible

So, Number of items which are bought by her at price of $3 is less than 10. Similarly Number of items which are bought by her at price of $2 is less than 10.

we know that 1 CENT = 0.01 $

We also know that 10 30-cents will worth 3 dollars, so the number of cents which are bought by her at price of $0.01 is greater than 10.

Now, Let she bought 20 items at price of 0.01$

Then 20*0.3 = 6$

It means 30$-6$ = 24$

24$ are left to purchase the things which are at price of 2$ and 3$.

If we let she purchase 4 items at cost $3 then

Then 4*$3 = 12$

It means 24$-12$ = 12$

Now, with remaining money she bought 6 items at cost $2.

So, she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

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she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

According to the statement

Janice bought total items = 30

Price of items are 30 cents, 2 dollars, or 3 dollars.

Total purchase price of Janice = 30$

If we let she bought 10 items at price of 3$, Then it is not possible

So, Number of items which are bought by her at price of $3 is less than 10. Similarly Number of items which are bought by her at price of $2 is less than 10.

we know that 1 CENT = 0.01 $

We also know that 10 30-cents will worth 3 dollars, so the number of cents which are bought by her at price of $0.01 is greater than 10.

Now, Let she bought 20 items at price of 0.01$

Then 20*0.3 = 6$

It means 30$-6$ = 24$

24$ are left to purchase the things which are at price of 2$ and 3$.

If we let she purchase 4 items at cost $3 then

Then 4*$3 = 12$

It means 24$-12$ = 12$

Now, with remaining money she bought 6 items at cost $2.

So, she bought 20 items at price of 0.01$, 6 items at cost $2, 4 items at cost $3.

Answer:

28.26658805 (I included every digit in case your teacher needs you to round)

Step-by-step explanation:

In order to find x, we need to isolate x by subtracting 15^2 and taking the square root of both sides.

Thus, we have:

[tex]15^2+x^2=32^2\\x^2=32^2-15^2\\\sqrt{x^2} =\sqrt{(32^2-15^2)} \\\sqrt{x^2}=\sqrt{799} \\x=28.26658805[/tex]

Answer: 225

Step-by-step explanation:

What is a square number?

A square number is a product of a number times itself

So, the 12th square number would be 12 * 12, or 12²

The 9th square number would be 9 * 9, or 9²

The equation would be 12² + 9²

So:

12² + 9²

= 144 + 81

= 225

So, the answer is 225

Answer:

[tex]\huge\boxed{\sf DE = 9}[/tex]

Step-by-step explanation:

From the figure,

AB = 2

BC = 3

AD = 6

Substitute in the given formula

[tex]\displaystyle \frac{AB}{BC} =\frac{AD}{DE} \\\\\frac{2}{3} = \frac{6}{DE} \\\\Cross \ Multiply \\\\2 \times DE = 6 \times 3\\\\2DE = 18\\\\Divide \ 2 \ to \ both \ sides\\\\DE = 18/2\\\\DE = 9\\\\\rule[225]{225}{2}[/tex]

Answer:

A. y= cos x - 1

Step-by-step explanation:

short answer: this is basically the parent graph cos(x), just vertically shifted down 1 unit.

longer answer:

standard form is y = a cos(bx-c) +d

a = amplitude

b = 2pi/period

c = horizontal shift

d = vertical shift (also equal to midline)

for this graph

a=1

period is 2pi, so b=1

there is no horizontal shift so c=0

d= -1 because it is shifted down one unit from axis (midline is at -1)

[tex]a(0) = 1 \: \: \: \: \: \: b(0) = 2 \: \: \: \: \: c(0) = 3 \\ a(1) = b(0) + c(0) = 2 + 3 = 5 \\ b(1) = a(0) + c(0) = 1 + 3 = 4 \\ c(1) = a(0) + b(0) = 1 + 2 = 3 \\ \\ a(2) = b(1) + c(1) = 4 + 3 = 7 \\ b(2) = a(1) + c(1) = 5 + 3 = 8 \\ c(2) = a(1) + b(1) = 5 + 4 = 9[/tex]

[tex]a(3) = b(2) + c(2) = 8 + 9 = 17\\ b(3) = a(2) + c(2) =7 + 9 = 16 \\ c(3) = a(2) + b(2) = 7 + 8 = 15 \\ \\ a(4) = b(3) + c(3) = 16 + 15 = 31 \\ b(4) = a(3) + c(3) = 17 + 15 = 32 \\ c(4) = a(3) + b(3) = 17 + 16 = 33[/tex]

[tex]a(5) = 32 + 33 = 65 \\ b(5) = 31 + 33 = 64 \\ c(5) =31 + 32 = 63 \\ \\ a(6) = 64 + 63 = 127 \\ b(6) = 65 + 63 = 128 \\ c(6) = 65 + 64 = 129 \\ [/tex]

[tex]a(7) = 128 + 129 = 257 \\ b(7) = 127 + 129 = 256 \\c (7) = 127 + 128 = 255 \\ \\ a(8) = 256 + 255 = 511 \\ b(8) = 257 + 255 = 512 \\ c(8) = 257 + 256 = 513[/tex]

[tex]a(9) = 512 + 513 = 1025 \\ b(9) = 511 + 513 = 1024 \\ c(9) = 511 + 512 = 1023 \\ \\ a(10) = 1024 + 1023 = 2047 \\ b(10) = 1025 + 1023 = 2048 \\ c(10) = 1025 + 1024 = 2049[/tex]

[tex]a(n) + b(n) + c(n) = \\ 2(a(n - 1) + b(n - 1) + c(n - 1)) \\ 6 \times 2 {}^{n } [/tex]

[tex]6 \times 2 {}^{n} > 100 \: 000 \\ 2 {}^{n} > \frac{100 \: 000}{6} \\ n > log {}^{2} ( \frac{100 \: 000}{6} ) \\ n > 14.02468 \\ n = 15[/tex]

The value of k is 1/4.

According to the statement

we have given

The equation of parabola is y=k−x2

And tangent to the line of equation is y = x

and we have to find the value of K.

So, let y=k−x2  -(1)

and let  y = x  -(2)

(2) is the tangent to the (1) then

therefore they cut at

y=k−x2  -(1)

y = x  -(2)

so, put (2) in the (1) then

x = k- (x)^2

(x)^2 + x = k

The above written equation has one real number then for this D =0

so, (x)^2 + x - k = 0

-1 -1*4*k = 0

-1 - 4k = 0

-4k = 1

The value of k is -1/4.

So, The value of k is 1/4.

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Step-by-step explanation:

Part A: [tex]u^6[/tex] can be written as the square of u³, or [tex](u^3)^2[/tex]. Similarly, [tex]v^6=(v^3)^2[/tex]. Hence, we can write this as a difference of two squares by writing it as

[tex](u^3)^2-(v^3)^2[/tex]

Part B:

We can first factor a difference of two squares a² - b² into (a+b)(a-b). Here, a would be u³ and b would be v³.

[tex](u^3+v^3)(u^3-v^3)[/tex]

We can factor this further by the use of two special formulas to factor a sum of two cubes and a difference of two cubes. These formulas are as follows:

[tex]a^3+b^3=(a+b)(a^2-ab+b^2)\\a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]

Since u³ + v³ is a sum of two cubes, let's rewrite it.

[tex]u^3+v^3=(u+v)(u^2-uv+v^2)[/tex]

Since u³ - v³ is a difference of two cubes, we can rewrite it as well.

[tex]u^3-v^3=(u-v)(u^2+uv+v^2)[/tex]

Now, let's multiply them together again to get the final factored form.

[tex]u^6-v^6=(u+v)(u^2-uv+v^2)(u-v)(u^2+uv+v^2)[/tex]

Part C:

If we want to factor [tex]x^6-1[/tex] completely, we can just see that x to the sixth power is just [tex]x^6[/tex] and 1 to the sixth power is just 1. Hence, x can substitute for u and 1 can substitute for v.

[tex]x^6-1=(x+1)(x^2-x(1)+1^2)(x-1)(x^2+x(1)+1^2)\\x^6-1=(x+1)(x^2-x+1)(x-1)(x^2+x+1)[/tex]

We can repeat this for [tex]x^6-64[/tex], as 64 is just 2 to the sixth power.

[tex]x^6-64=(x+2)(x^2-x(2)+2^2)(x-2)(x^2+x(2)+2^2)\\x^6-64=(x+2)(x^2-2x+4)(x-2)(x^2+2x+4)[/tex]

The remaining two angles of the given isosceles triangle is Option(C) 40°,70° .

For an isosceles triangle, the two sides of the triangle are congruent and equal in length . Also the angles subtending the adjacent equal sides of the isosceles triangle are of same measure.  

We also know that the sum of the three interior angles of any triangle is always equal to 180° .

In the options given, in Option(C) the angles measure 40° and 70° .

Thus as one angle of the isosceles triangle is given to be 70°, the other angle of its adjacent side is also 70° .

The sum of the interior angles of the triangle is equal to -

70° + 40° + 70° = 180° which satisfies the property.

Therefore, the remaining two angles of the given isosceles triangle is Option(C) 40°,70° .

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The area of the given figure is 38 square units

The area of the given trapezoid is expressed as:

A = 0.5(a+b)h

where

a and b are the sides

h is the height

Substitute

A = 0.5(9+10) * 4

A = 19 * 2

A = 38 square units

Hence the area of the given figure is 38 square units

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There is enough evidence to conclude that taking aspirin cannot  reduces the chance of cancer.

Given sample size of patients take aspirin 11037, sample size of patients who have assigned placebo group be 11034. 104 doctors who take aspirin had a heart attack, 189 doctors had placebo had heart attacks.

First we have to form hypothesis.

[tex]H_{0} :p{1} -p_{2} =0[/tex]

[tex]H_{1}:p_{1} -p_{2} < 0[/tex]

We have to find the respective probabilities.

[tex]p_{1}[/tex]=104/11037

=0.0094

[tex]p_{2}[/tex]=189/11034

=0.0171

Now their respective margin of errors.

[tex]s_{1}[/tex]=[tex]\sqrt{ {(0.0094*0.9906)/11037}[/tex]

=0.0009

[tex]s_{2}[/tex]=[tex]\sqrt{0.0171*0.9829}[/tex]

=0.0011

Hence the distribution of the differences,they are given by:

p=[tex]p_{1} -p_{2}[/tex]

=0.0094-0.0171

=-0.0077

S=[tex]\sqrt{s_{1} ^{2}+s_{2} ^{2} }[/tex]

=[tex]\sqrt{(0.0009)^{2} +(0.0011)^{2} }[/tex]

=0.00305

z=(p -f)/S (In which f=0 is the value tested at the null hypothesis)

=(-0.0077-0)/0.00305

=-2.52

p value will be 0.005.

p value of 0.05 significance level.

z=1.96.

1.96>0.005

So we will reject the null hypothesis which means it cannot reduce the whole chance of becomming a heart attack.

Hence there is enough evidence to conclude that taking aspirin cannot  reduces the chance of cancer.

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The odds in simplest form against getting two numbers greater than 4 is 1 : 4.

Probability determines the odds that a random event would happen. The odds  the event occurs is 1 and the probability that the event does not occur is 0.

The odds of getting two numbers greater than 4 = 2 x (numbers greater than 3 in a cube / total number of sides in a cube)

2(3/6)

2 x 1/2 = 1 : 4

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Answer:

Step-by-step explanation:

two

The two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

Given the equation; 6x² - 35 = -11x

The quadratic formula is expressed as;

x = [ -b±√( b² - 4(ac)  ]/2a

First, we re-arrange our equation in the form of ax² + bx + c = 0

6x² + 11x - 35 = 0

We substitute into the formula.

x = [ -b±√( b² - 4(ac)  ]/2a

x = [ -11±√( 11² - 4( 6 × -35 )  ]/2×6

x = [ -11±√( 121 + 840 ]/12

x = [ -11±√961 ]/12

x = [ -11 ± 31 ]/12

x = (-11 + 31)/12,  (-11 + 31 )/12

x = 20/12,  -42/12

x = 5/3, -7/2

Therefore, the two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2

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The statement which identifies Melissa’s error and the correct answer is; Melissa added incorrectly. The correct answer is 4.5°F

New temperature = Initial temperature + (Change in temperature per × Number of hours)

= -20.5°F + (5°F × 5)

= -20.5°F + (25°F)

= 4.5°F

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Answer:

C

Step-by-step explanation:

The distance of the car to the base of the building is 23 metres.

The situation will form a right angle triangle.

Therefore, the distance of the car to the base of the building is the adjacent side of the right angle triangle formed.

Therefore,

tan 35 = opposite / adjacent

tan 35 = 16 / x

x tan 35 = 16

x = 16 / tan 35

Therefore,

x = 16 / 0.70020753821

x = 22.8506141103

x = 23 meters

Therefore, the distance of the car to the base of the building is 23 metres.

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The probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.

To find the probability that a part was manufactured on machine A, given that the part is defective:

The probability that a part was manufactured on machine A given that part is defective:

P ( A | D )

P ( A | D ) = [P (A) * P ( D | A )]/ P ( D )

Where: P (A) is the probability that the part is manufactured in machine A which is 0.2 (half of the parts are manufactured in machine A)

P (D/A) is the probability of a defective part given that the part was manufactured in machine A which is 2% or 0.02

And finally, the probability of defective part in the production is 8% or 0.08 hence :

P ( A | D ) = [ ( 0.2 ) * 0.02 ] / 0.08

P ( A | D ) = 0.024

Therefore, the probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.

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Answer:

70

Step-by-step explanation:

the 30/100 of 100 is 30

So 100-30=70

Answer:

70kg

Step-by-step explanation:

30% of 100kg is

--> 100 x 30/100 which is 30kg.

If you want to decrease 100kg by 30%, you can take away 30kg from 100kg.

--> 100 - 30 = 70

So 70kg is the remainder.

The growth factor as a decimal is 1.026 and the number of students enrolled 10 years from now is 1939

The given parameters are

Initial value of enrollment, a = 1500

Rate, r = 2.6%

The growth factor is then calculated as:

Growth factor = 1 + Rate

This gives

Growth factor = 1 + 2.6%

Evaluate the sum

Growth factor = 1.026

Hence, the growth factor as a decimal is 1.026

As a general rule, the number of students enrolled t years from now is

Students = Initial value * Growth factor^Number of years

This is represented as

Students = 1500(1.026)^t

10 years from now means t = 10

So, we have

Students = 1500(1.026)^10

Evaluate

Students = 1939

Hence, the number of students enrolled 10 years from now is 1939

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Answer:

first option x = 7

Step-by-step explanation:

"x" is the cathetus opposite the angle of 30°

14 is the hypotenuse

use the sine function

[tex]sin30^{0} =\frac{x}{14}[/tex]

[tex]x=14sen30^{0} =14(0.5)=7[/tex]

Hope this helps

Probability of people needing corrective shoes or dental work is 0.36.

The proportion of favorable cases to all possible cases used to determine how likely an event is to occur.

A statistical term used to describe events that cannot occur concurrently is "mutually exclusive".

Here, the two events getting corrective shoes and getting dental work are not mutually exclusive events.

P(corrective shoes or dental work) = P(corrective shoes) + P(dental work) - P(corrective shoes and dental work)

P(corrective shoes or dental work)  = 0.16 + 0.23 - 0.03

P(corrective shoes or dental work)  = 0.36

Hence, the probability of people needing corrective shoes or dental work is 0.36.

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The wide-area search method employs the use of markers such as knots at regular intervals along the search line.

Given the method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line.

In order to locate, relieve distress, and preserve the life of a person who has been reported missing or is believed to be lost, stranded, or is considered a high-risk missing person, wide area search and rescue refers to activities occurring within large geographic areas. It also refers to the removal of any survivors to a safe location.

Hence, the wide-area search method employs the use of markers such as knots at regular intervals along the search line to indicate distance from the beginning of the search line

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The midpoint of co-ordinate is (5, 6)

Add both "x" coordinates, and divide by 2.

Add both "y" coordinates, and divide by 2.

Given that;

Coordinates of A = (2,3)

Coordinates of B = (8,9)

Find:

Midpoint of co-ordinate

Computation:

Midpoint of co-ordinate = [(x1 + x2) / 2], [(y1 + y2) / 2]

Midpoint of co-ordinate = [(2 + 8) / 2], [(3 + 9) / 2]

Midpoint of co-ordinate = [10 / 2], [12 / 2]

Midpoint of co-ordinate = (5, 6)

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