Figure 1) is a snapshot graph at t = 0 s of two waves on a string approaching each other at 1 m/s.
1. List the values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s.

Figure 1) Is A Snapshot Graph At T = 0 S Of Two Waves On A String Approaching Each Other At 1 M/s.1.

Answers

Answer 1

To solve this we must be knowing each and every concept related to interval. Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as below.

What is interval?

An interval is any set of numbers that fall between two distinct integers. This range includes all real values that fall between those two. All real numbers that lie in any 2 of a set's numbers are collectively referred to as an interval within mathematics.

For instance, the set of integers x fulfilling 0 x 1 is the interval consisting of 0, 1, and all numbers in between. a snapshot graph of wave on a string moving toward one another at 1 m/s at time t = 0 s.

At time t = 0,Y₀= 0 cm

At At time t =1, Y₁= 0 cm

At time t = 2, Y₂= 0 cm

At time t =3, Y₃= 0 cm

At time t =4, Y₄= 0 cm

At time t = 5 ,Y₅=0 cm

At time t = 6, Y₆= 0 cm

Therefore, values of the displacement of the string at x = 5.0 m at 1 s intervals from t = 0 s to t = 6 s can be listed as above.

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Related Questions

need help with Kirchhoff's rules

Answers

The nodal voltage is V and the currents are as defined in the diagram.

At the upper node, Kirchhoff's current law equation is  I1+I5=I2+I3

What is  Kirchhoff's rules?The voltage around a loop equals the sum of every voltage drop in the same loop for any closed network and equals zero. Put differently, the algebraic sum of every voltage in the loop has to be equal to zero and this property of Kirchhoff's law is called conservation of energy.Kirchhoff's circuit laws are two equalities that deal with the current and potential difference in the lumped element model of electrical circuits. They were first described in 1845 by German physicist Gustav Kirchhoff. This generalized the work of Georg Ohm and preceded the work of James Clerk Maxwell.Kirchhoff's first rule—the junction rule. The sum of all currents entering a junction must equal the sum of all currents leaving the junction. Kirchhoff's second rule—the loop rule. The algebraic sum of changes in potential around any closed circuit path (loop) must be zero

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Can you help me with this question

Answers

A bar magnet's magnetic field lines flow from its north pole toward its south pole, just like they do in all magnets. Field lines that begin close to a pole's edges stay nearby the bar magnet longer than those that begin closer to the pole's centre.

What produces a magnetic field in a bar magnet?

Because the molecules in magnets are arranged so that their electrons spin in the same direction, magnets are unique. This configuration and motion produces a magnetic force that emanates from a north- and south-seeking pole, respectively.

Where does a bar magnet's magnetic field are strongest?

At the poles, it is strongest.

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Write two or three sentences to describe the conductivity of a conductor. Explain its conductivity in terms of the electrons in it.

Answers

The conductivity of a conductor refers to its ability to conduct electrical current.

A material that has high conductivity allows electrical charges to flow through it easily and with little resistance, while a material with low conductivity does not allow electrical charges to flow as easily and has more resistance.

The conductivity of a conductor is determined by the number of free electrons in the material, as well as how easily these electrons can move through the material.

In a conductor, the atoms are closely packed together and the electrons are not tightly bound to the atoms, allowing them to move freely through the material and carry an electrical charge. This facilitates the flow of electrical current through the material, resulting in high conductivity.

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A model rocket flies horizontally off the edge of a cliff at a velocity of 50.0 m/s. If the canyon below is 100.0 m deep, how far from the edge of the cliff does the model rocket land?

My teacher provided the equations:
x= vt and y = (Vi * t)1/2* a * t^2

Answers

Yes! The second one is one of the constant acceleration equations. We know that our X and Y values are independent of each other, which is why Y doesn't matter here. We only care about the X position value since X and Y are independent! (This is an extremely important rule, trust me)

Therefore, we don't need to calculate a Y velocity or anything like that. We only need Y because we need to find time t. We can use Y to calculate time because although X and Y are independent of each other, they do share the same time traveled!

We know that [tex]V_{0,y}[/tex] = 0, since the car wasn't moving vertically initially. We also know Y initial is 100 and Y final is 0 when it hits the ground! The last thing we know is that the acceleration of any item in free fall is (usually) -9.81. Therefore, using the original Y equation that your teacher gave, we can plug things in and solve for time!

[tex]y_f=y_i+v_it+\frac{1}{2}at^2\\0=100+(0)t+\frac{1}{2}(-9.81)t^2\\-100=-4.905t^2\\t^2=20.39\\t=4.52[/tex]t = 4.52s

(Your teacher simplified the Y equation a little, so it may look slightly different from mine. I started at the original Y equation)

Now we have time! So now we can use the other equation your teacher provided. Again, remember, even though the car is now traveling through the air vertically, that does not affect its x velocity! The car is still traveling at 50m/s!

Therefore, we can just plug and chug!:

x = vt

x = (50)(4.52)

x = 226m

I hope this helps!

While skiing in Jackson, Wyoming, your friend Ben (of mass 63.2 kg) started his de- scent down the bunny run. 11.5 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben's kinetic energy at the bottom of the bunny run? Use g = 9.8 m/s Answer in units of J.​

Answers

Answer:

Approximately [tex]7.1 \times 10^{3}\; {\rm J}[/tex] (given: [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].)

Explanation:

To find the change in the gravitational potential energy ([tex]\text{GPE}[/tex]), use the formula:

[tex]\begin{aligned}& (\text{change in GPE}) \\ &= (\text{mass})\, (g)\, (\text{change in height})\end{aligned}[/tex].

Assume that gravitational field strength [tex]g[/tex] is constant (e.g., [tex]g = 9.8\; {\rm m\cdot s^{-2}}[/tex].) For an object of mass [tex]m[/tex], if the altitude of the object changes by [tex]\Delta h[/tex], the [tex]\text{GPE}[/tex] of that object would change by [tex]m\, g\, \Delta h[/tex].

In this question, the mass of Ben is [tex]m = 63.2\; {\rm kg}[/tex]. It is given that [tex]g = 9.8\; {\rm m\cdot s^{-2}} = 9.8\; {\rm N\cdot kg^{-1}}[/tex] and is constant. Since change in the altitude of Ben is [tex]\Delta h = 11.5\; {\rm m}[/tex], the change in the ([tex]\text{GPE}[/tex]) of Ben would be:

[tex]\begin{aligned} m\, g\, \Delta h &= (63.2\; {\rm kg}) \, (9.8\; {\rm N\cdot kg^{-1}})\, (11.5\; {\rm m}) \\ &\approx 7.1\times 10^{3}\; {\rm N\cdot m} = 7.1\times 10^{3}\; {\rm J} \end{aligned}[/tex].

A ruler partially hangs over the end of a bench. It is supported at one end and made to vibrate at the other end in an attempt to display simple harmonic motion. If the ruler has an amplitude of 0.22 cm and makes twelve complete vibrations in 0.12 seconds, how far does the end of the ruler travel in 4.7 seconds?

Answers

Answer:

The Distance travelled is 410 cm

I would like to ask for help in understanding on what basis the universe is considered to be expanding? As far as I understand, it is only an idea (hypothesis, theory) and not a scientific fact as the media presents it. Given that we on Earth receive evidence of various radiations from the past, we cannot say with certainty that the Universe is still expanding. Let's say the Universe stopped expanding 4 billion years ago and started contracting, would the results of all our observations be the same as they are or not?

Answers

Expansion of universe is not a hypothetical one but the universe is expanding in the sense increase distance over the space and dark matter.

What is universal expansion?

The increase in distance over time between any two particular gravitationally unbound regions of the observable universe is known as the universe's expansion

As a result, the size of space itself expands intrinsically. It is not necessary for space to exist outside of the cosmos or for it to extend into anything.

The metric changes in scale rather than space or the things in space moving in the conventional sense. Objects move farther apart from one another at ever-increasing speeds as the spatial component of the universe's spacetime metric scales up.

Any viewer in the cosmos would see that all of space appears to be expanding, except for the galaxies receding with a speed proportional to the distance from the observer.

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8. Jane rides a sled down a slope of angle θ at constant speed v. Determine the coefficient of kinetic friction between the sled and the slope. Neglect air resistance.
(A) μ=gsinθ (B) μ=mgcosθ (C) μ=tanθ (D) μ=gcosθ

Answers

Answer:ssssw

Explanation:

19. A pitcher throws a baseball toward a batter at 30m/s. The batter swings his
bat and hits the baseball. The baseball flies away in the opposite direction at a
speed of 35m/s. Is there a transfer of energy in this situation? (SC.7.P.11.4)
a) Yes, because both the bat and the ball are moving after the collision.
b) No, because the ball and the bat only touched for a short time.
c) Yes, because the force from the bat changes the motion of the ball

Answers

A pitcher throws a baseball towards a batter at 30m/s. The batter swings his bat and hits the baseball, then there is a transfer of energy in this situation : c) Yes, because the force from the bat changes the motion of the ball.

How is energy transferred from baseball bat to a baseball?

Although baseball may appear hard and solid, it actually behaves much like a rubber ball. In the fraction of a second that ball collides with the swinging bat, ball compresses as the energy of motion goes into deforming the ball and transforms it into an elastic potential energy.

The collision of baseball with bat is elastic and the collision between baseball and glove is nearly inelastic.

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calculate the maximum capillary rise of water to be expected a, in a vertical glass tube 1mm in diameter b, in between tow concentric glass tubes of radii 4 and 5 mm. take 6=0.0733n c, in between two vertical parallel.clean glass plates spaced a distance of 2mm apart.

Answers

The maximum capillary rise of water to be expected  in the vertical glass tube is 15 mm.

What is capillary rise?

The process of a liquid flowing in a small area without the aid of, or even in opposition to, any outside forces like gravity is known as capillary rise.

The effect can be observed in a biological cell, in a thin tube, in porous materials like paper and plaster, in some non-porous materials like sand, liquid carbon fiber, and some other porous materials.

The maximum capillary rise of water = 4σcosθ/ρgd

= ( 4 × 0.0733 × cos0°)/(10³ × 9.81 × 2 × 10⁻³) meter

= 0.015 meter

= 15 mm.

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A box with a weight of 25N sits on the floor. What is the maximum force that could be applied horizontally on the box before it would start to accelerate if the coefficient of friction is 0.40?

Answers

So, we know that The box isn't moving at all. I'm assuming the coefficient they gave you is for static friction. We know that with static friction, the value that we calculate is a maximum value that represents the force we'd have to apply before an object starts moving!

We also know that the box isn't moving vertically. That means that its Y forces must be cancelling out, which means its weight force and its normal force must be equal to each other!

Now we can plug in these values into our static friction equation!

[tex]F_s[/tex] ≤ [tex]F_N[/tex] * μ[tex]_s[/tex]

[tex]F_s[/tex] ≤ (25N) (0.40)

[tex]F_s = 10[/tex]

Therefore your force that you'd need to apply is 10N!

Which of the following is the only group in mission control that gets to communicate with the astronauts in space?


Flight Director


CAPCOM


Senior Flight Controller


Lead Ground Astronaut

Answers

Capsule communicator or Capcom  is the only group in mission control that gets to communicate with the astronauts in space. Hence, option (B) is correct.

What is capsule communicator or Capcom?

The capsule communicator, or Capcom, was the only voice that spoke to the astronauts during their trip to avoid any mistake. To ensure that the men in the capsule always had a familiar individual who understood their situation and could provide the information they required, Capcom was always manned by astronauts.

Both the technical control team on the ground and the astronauts in space are represented by Capcom.

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1- A ball, M = 4 kg is released from rest (vi =0) at a height, h = 2 m above the ground. (a)
What is the kinetic energy of the ball just before it hits the ground? What is the change in the
potential energy, ΔU during this motion? (b) Find the kinetic energy of the ball at a height, y
= 1.2 m above the ground. (Take g = 10 m/s2
).

Answers

(a) The kinetic energy of the ball just before it hits the ground is 78.4 J.

(b) The kinetic energy of the ball at a height of 1.2 m is 31.36 J.

What is the kinetic energy of the ball?

The kinetic energy of the ball just before it hits the ground is calculated as follows;

K.E ( bottom) = P.E (top)

P.E (top) = mgh

where;

m is the mass of the objecth is the height of the objectg is acceleration due to gravity

P.E (top) = 4 x 9.8 x 2

P.E (top) = 78.4 J

The change in the potential energy of the ball during its motion is calculated as follows;

ΔU = P.Ef - P.E i

where;

P.Ef is the final potential energy at ground levelP.Ei is the initial potential energy at maximum height

ΔU = 0 J - 78.4 J

ΔU = -78.4 J

The kinetic energy of the ball at a height of 1.2 m is the change in the potential energy of the ball and it is calculated as follows;

K.E = -ΔU

K.E = -mg (hf - hi)

K.E = (4 x 9.8)(2m - 1.2 m)

K.E = 31.36 J

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A particle which is moving in a straight line with a velocity of 15m/s accelerates uniformly for 3.0s, increasing its velocity to 45m/s. What distance does it travel while accelerating

Answers

The distance travel while accelerating is 90m

The initial velocity of the particle is 15m/s and the final velocity is 45m/s, so the change in velocity is 45m/s - 15m/s = 30m/s. The particle accelerates uniformly for 3.0s, so the acceleration is 30m/s / 3.0s >>30/3=10 that is 10m/s^2.

The distance traveled during the acceleration is equal to the average velocity times the time elapsed, so the distance traveled is (15m/s + 45m/s)/2 * 3.0s = (15+45)/2*3= 90m .

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The largest flowers in the world are the Rafflesia Arnoldii, found in Malaysia. A single flower is almost a meter across and has a mass up to 11.0 kg. Suppose you cut off a single flower and drag it along the flat ground. If the coefficient of kinetic friction between the flower and the ground is 0.39, what is the magnitude of the frictional force that must be overcome?

Answers

The magnitude of the frictional force that must be overcome is 42.04 N.

What is the magnitude of the frictional force?

The magnitude of the frictional force that must be overcome is calculated by applying Newton's second law of motion as follows;

Mathematically, the formula for the frictional force is given as;

F = μmg

where;

μ is the coefficient of frictionm is the mass of the flowerg is acceleration due to gravity

The magnitude of the frictional force that must be overcome is calculated as;

F = 0.39 x 11 kg  x  9.8 m/s²

F = 42.04 N

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how is the energy of boiling water in an electric kettle a different energy from electric fan changing to kinetic energy

Answers

The energy of boiling water in an electric kettle is thermal energy, which is created by a transfer of electrical energy from the kettle to the water.

What is Energy?

Energy is a fundamental physical quantity that is a property of objects and their environment. It is the ability to do work and is often associated with the motion of objects. In physics, energy is defined as the capacity to do work and is measured in joules. It can take many forms such as thermal, kinetic, electrical, mechanical, and chemical.

Electric fan changing to kinetic energy is the conversion of electrical energy from the fan motor into kinetic energy, which is the energy of motion.

Kinetic energy is basically the energy of motion. It is the energy an object has due to its motion. It is defined as the work which is needed to accelerate a body of a given mass from rest to its current velocity.

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Part A
What is the radius of the hydrogen-atom Bohr orbit shown in the figure? (Figure 1)
r = ____ nm

Answers

The radius of the hydrogen-atom Bohr orbit shown in the figure is 5.3 nm.

What is  Bohr orbit?

The path that hypothetical electrons take around the nucleus is known as Bohr's orbit.

These orbits are described by Bohr in his hypothesis of the structure of an atom as energy levels or shells where electrons move in a fixed circle around the nucleus.

These orbits resemble solar system orbits, with the exception that they are attracted by electrical forces rather than gravity. The term "ground state" refers to the amount of energy that an electron typically occupies.

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A sample of copper (specific heat capacity of copper is 0.386J/g*C) absorbs 1200 J of heat and
the temperature of the water it is being heated in increases from 27*C to 95*C, what mass of
copper was heated?

Answers

The mass of copper heated from a temperature of 27°C to 95°C is 45.72 g.

What is mass?

Mass is the quantity of matter contained in a body, The units of mass are

Kilogram (kg)Gram (g)Milligram (mg) etc.

To calculate the mass of the copper, we use the formula below.

Formula:

m = Q/cΔt.................. Equation 1

From the question,

Given:

m = MassQ = Amount of heatc = Specific heat capacity of copperΔt = Change in temperature

From the question,

Given:

Q = 1200 Jc = 0.386 J/g°CΔt = 95-27 = 68°

Substitute these values into equation 1

m = 1200/(0.386×68)m = 45.72 g

Hence, the mass of copper is 45.72 g.

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If a Current Current of strength 3A flows through aresistance of 20 om for 10 minutes,then calculate the amount of heat produced in the resistance. ​

Answers

Answer:

1.08 x 10^5 J

Explanation:

First, apply the formula V = IR , where V is the voltage, I is the current and R is the resistance.

R -> 20 ohm (Given)

I -> 3A (Given)

Hence, V = 3 x 20 = 60V (60 volts)

Next, apply the formula E = Pt , where E is the energy produced, P is the power and t is the time in seconds

Furthermore, since P = IV (power = current x voltage)

The formula can be re-expressed as E = VIt

t -> 10 minutes = 600 seconds (don't forget to convert time to seconds!)

Therefore, energy = (60 x 3 x 600) J

                              = 108000 J

                               = 1.08 x 10^5 J (in scientific notation)

Hea produced in the resistance = energy produced in the resistor

                                                      = 1.08 x 10^5 J

Directions: Unscramble each word. Then write each term on the line before its definition.
1. antstonc
2. desep
3. ticlovey
4. onlacietrace
5. emincedsplat
6. tomoni
7. cenferree nitop
8. spooniti


9. measure of change in velocity
10. distance an object moves in a unit of time
11. change of position
12. distance and direction from a reference point
13. not changing
14. speed of an object in a given direction
15. distance between the initial and final position
16. starting point used to describe the location of an object

Answers

Answer:

constantspeedvelocityaccelerationdisplacementmotionreference pointposition

Explanation:

Above is the unscrambled words. Hope this helps!

POSSIBLE POINTS: 1
This is another example of a lever.



Identify each part, A, B and C, and then classify the lever as 1st, 2nd, or 3rd class.

Responses

A. fulcrum, B. load, C. effort. 2nd class
A. fulcrum, B. load, C. effort. 2nd class

A. load, B. fulcrum, C. effort. 1st class
A. load, B. fulcrum, C. effort. 1st class

A. load, B. fulcrum, C. effort. 3rd class
A. load, B. fulcrum, C. effort. 3rd class

A. effort, B. fulcrum, C. load. 1st class

Answers

In the given image A. load, B. fulcrum, C. effort. 1st class. The correct option is B.

What is fulcrum?

The pivotal point of the beam is known as the fulcrum. A load is applied at the other end of a lever when an effort is exerted to one end of the lever. A mass will be raised as a result.

The fulcrum of first-class levers is in the centre. Levers of the second class have the load in the centre.

This indicates that a heavy load can be moved with only moderate effort. - Levers of the third class exert middle-of-the-road force.

The illustration shows a class 1 lever with a fulcrum in the middle and load and effort located at the other two ends.

Thus, the correct option is B.

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Please help!
Two pieces of clay, one white and one gray, are thrown through the air. The white clay has a
momentum of 25 kg. M/s and the gray clay has momentum of -30 kg m/s immediately
before they collide.

What is the magnitude and direction of their final momentum immediately after the collision?


Answers

When two objects collide in two dimensions (for example, x and y), the momentum will be conserved separately in each direction (as long as there isn't an external impulse in that direction).

One white and one gray piece of clay are flung through the air. The 25-kilogram mass of the white clay?

The momentum before and after a direct impact between two pieces of clay is maintained. The amount of initial kinetic energy lost during the impact as a fraction is 0.961.

What is the difference between the total momentum of two objects before and after a collision?

The total momentum of the two objects prior to the collision equals the total momentum of the two following the collision when object 1 and object 2 collide in an isolated system. The momentum obtained by object 2 equals the momentum lost by object 1, and vice versa.

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A 9.5 kg test rocket is fired vertically from Cape Canaveral. Its fuel gives it a kinetic energy of 2390 J by the time the rocket motor burns all of the fuel. The acceleration of gravity is 9.8 m/s². What additional height will the rocket rise? Answer in units of m.​

Answers

Answer:

4.95 m

Explanation:

The rocket's initial kinetic energy is equal to the final gravitational potential energy, so we can set these equal to each other and solve for the additional height the rocket will rise:

KEinitial = KEfinal

1/2 * m * v^2 = m * g * h

Substituting the given values, we have:

1/2 * 9.5 kg * v^2 = 9.5 kg * 9.8 m/s^2 * h

Solving for h, we find that the additional height the rocket will rise is h = 2390 J / (9.5 kg * 9.8 m/s^2) = 4.95 m.

How long would you have to film something in HD to collect 1 PB of data?


all day for 2 consecutive weeks


all day for 365 days (or 364 days in a leap year)


all day for about 3.5 years


all day for one light year

Answers

Time required to film something in HD to collect 1 PB of data is all day for about 3.5 years.

What is Petabyte?

A petabyte, or 2 to the 50th power of a byte, is a unit of measurement for memory or data storage. One exabyte is equal to about 1,024 petabytes (PB), or 1,024 terabytes (TB).

Although traditional network-attached storage (NAS) can handle petabytes of data and is expandable, it might be resource-intensive to traverse the system's ordered storage index.

A common laptop or desktop computer has 16 GB of random access memory for storage (RAM).

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Two carts of equal mass are on a horizontal surface with negligible friction. Cart A is approaching cart B, which is at rest, as shown in Figure 1 above. Attached to cart B is a spring that is initially compressed. At the moment cart A collides with cart B, the spring is released and pushes on cart A, as shown in Figure 2 above. Which of the following correctly states what happens to the kinetic energy and the momentum of the two-cart system as a result of the collision compared to those quantities before the collision?
(A) Kinetic energy: Increases; Magnitude of Momentum: Decreases
(B) Kinetic energy: Increases; Magnitude of Momentum: Stays the same
(C) Kinetic energy: Increases; Magnitude of Momentum: Increases
(D) Kinetic energy: Stays the same; Magnitude of Momentum: Decreases
(E) Kinetic energy: Stays the same; Magnitude of Momentum: Stays the same

Answers

The option that correctly states what happen to the kinetic energy and the momentum of the two-cart system as a result of the collision compared to those quantities before the collision is

B) Kinetic energy: Increases; Magnitude of Momentum: Stays the same

What is kinetic energy?

The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force.

Since the elastic potential energy that was initially stored in the compressed spring has now been converted into kinetic energy, the system's total energy should be conserved. As a result, the system's kinetic energy increases. As a result, the system's kinetic energy rises.

The magnitude of the two-cart system's net momentum remains constant because there is no outside force acting on it, which implies that the system's overall momentum should be conserved.

Therefore, the correct option is B.

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A frog jumps as is moves. what is the relation between its maximum height and maximum range​

Answers

The relation between a frog's maximum height and maximum range is that when the frog jumps at an angle of 45°, its maximum height is half of the horizontal range.

What are the maximum height and maximum range​?

The maximum height refers to the maximum vertical distance that an object can travel.

The maximum range is the maximum horizontal distance that an object can travel.

The maximum height, H that the projectile reaches when the range, R, is at its greatest is H = Rmax /4.

R = 4Hcot is the relationship between the horizontal range and maximum height.

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The uniform beam has a weight W and length L and is supported by a pin at A and cable BC ( figure 1)
Part A
Determine the horizontal and vertical components of reaction at A
Express your answers in terms of some or all of the variables W, R. Φ and θ). Enter your answers separated by a comma.
View Available Hint's)
Aa + Ay = ____
Parts B
Determine the one cable car necessary to hold the beans position shown
Express your answers in terms of some or all of the variables W, R. Φ and θ).

Answers

The reaction is in A in vertical direction is W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ).

What is Normal Stress and Strain?

In terms of psychology, "stress" and "strain" are sometimes used interchangeably in popular culture, as in the expressions "I'm feeling stressed" or "I'm under a lot of pressure."

In engineering, these phrases have specific, technical meanings. If a hook in the steel wire is attached,

If you hang the wire from the ceiling while placing a weight on the lower end, it will sag. By dividing the length change by the starting length, the strain in the wire may be computed.

Thus, as per the given scenario, W(2cosϕsinθ−sinϕcosθ)/2sin(θ−ϕ) will be the equation.

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The system in the figure below, If atmospheric pressure is 101.3 KPa and the absolute pressure at the bottom of the tank is 231.3 KPa, what is the specific gravity of the olive oil?

Answers

If atmospheric pressure is 101.3 KPa and the absolute pressure at the bottom of the tank is 231.3 KPa, the specific gravity of the olive oil is 1.30

How do you calculate the gravity?

To calculate the specific gravity, deduct the absolute pressure at the bottom of the tank (231.3 KPa) from the atmospheric pressure (101.3 KPa). This will give you a ratio of 130KPa, then divide it by the atmospheric pressure which is the specific gravity of olive oil.

Use the formula below:

specific gravity = absolute pressure - atmospheric pressure / atmospheric pressure

Specific gravity = (231.3 KPa - 101.3 KPa) / (101.3 KPa) = 1.30

Therefore, the specific gravity of the olive oil is 1.30.

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What does newton first law states ​

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Answer:

Newton's first law, also known as the law of inertia, states that an object will remain at rest or in motion at a constant velocity unless acted upon by an external force. In other words, an object will not change its velocity on its own, it will only do so if something else pushes or pulls on it. This law is a fundamental principle of classical mechanics, and it helps to explain the behavior of objects under various conditions.

Explanation:

Answer: Newton first law states that an object at rest tends to stay at rest. an object in motion tends to stay in motion in a straight line at a constant speed until another force acts on the object.  It is also called the law of inertia

Explanation: Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

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On what basis is it considered that the universe is expanding?

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UNIVERSE

There is strong evidence to support the idea that the universe is expanding. One of the main pieces of evidence for this is the observation of the cosmic microwave background radiation, which is a faint glow of microwave radiation that permeates the entire universe. This radiation is thought to be a residual heat left over from the Big Bang, the event that is believed to have marked the beginning of the universe.

The cosmic microwave background radiation has a very even temperature throughout the universe, but if the universe were not expanding, we would expect to see some regions that are slightly hotter or cooler than others due to differences in density. However, measurements of the cosmic microwave background radiation show that it has a very uniform temperature, which suggests that the universe must be expanding in order to even out any temperature differences that may have existed in the past.

Other evidence for the expansion of the universe includes the observation of supernovae in distant galaxies, which are explosions of massive stars that can be used to measure the distances to those galaxies. These measurements have shown that the most distant galaxies are moving away from us at a speed that is proportional to their distance, which is consistent with the expansion of the universe.

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