Find the equation of the line passing through the given point and
PARALLEL to the given equation. Write your answer in slope intercep
form. (xX_PARALLEL_Xx) *
(5,3) and y = x + 4

[tex]3\frac{1}{4}[/tex]  cups of chocolate chips is 19.5 ounces.

If one cup of chocolate chips weighs about 6 ounces

we can find out the weight of [tex]3\frac{1}{4}[/tex] cups by multiplying it by the weight of one cup.

[tex]3\frac{1}{4}[/tex] cups = 3 cups + 1/4 cup

= 3 + 0.25

= 3.25 cups

Weight of 3.25 cups = 3.25 cups × 6 ounces/cup

Weight of 3.25 cups = 19.5 ounces

Therefore, [tex]3\frac{1}{4}[/tex]  cups of chocolate chips is 19.5 ounces.

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Answer:

87% of all the packets of biscuits Jemima displayed on the shelves.

Step-by-step explanation:

400-52=348

so, 348*25%

348*25/100

87

Answer:

33.33 megabytes per day on average.

Step-by-step explanation:

You forgot to include your slope but it should just follow the form y= mx+ b. where m is your slope and b is your y-intercept.

Answer:

35

Step-by-step explanation:

well, you know the angles of a triangle add up to 180 degrees, and you have the other 2 degrees right there, so all you have to do is add both of the other angles 111+34= 145 and then subtract by 180, 180-145=35 so your answer is 35

Answer:

hmm i think its

1/2(x + y)

Step-by-step explanation:

because well... this would be eaiser for me if it said "of the" because "of the" is mostly used for multiply, but since it just said "the..." i can only guess. I think this may be the answer tho?

Answer:

k

[tex]2xyy15 { { \div - \\ \sqrt[ {x. - - {?}^{?} }^{2} ]{?} }^{2} }^{2} [/tex]

Answer:

On the day the link was emailed, trailer

A

had the most views.

Two days after the link was emailed, trailer

A

had the most views.

Four days after the link was emailed, trailer

B

had the most views.

Step-by-step explanation:

The total number of views on the day the email was sent, two days later, and four days later are represented by the values of the functions when x = 0, 2, and 4.

Substitute these values into the equation:

Find these values in the table:

Apply the described rule:

So, on the day the link was emailed, trailer A had the most views.

Two days after the link was emailed, trailer A had the most views.

Four days after the link was emailed, trailer B had the most views.

Answer:

The farmer can predict that 55 cows in the entire population have no spots.

Step-by-step explanation:

The farmer can predict that 40 cows in the entire population have no spots, the correct option is C.

Suppose we're given that:

Favourable Cases X (in count, in sample)

Sample Size N

Level of significance =[tex]\alpha[/tex]

Then, the sample proportion of favorable cases is:

[tex]\hat{p} = \dfrac{X}{N}[/tex]

The critical value at the level of significance[tex]\alpha is Z_{1- \alpha/2}[/tex]

The corresponding confidence interval is:

[tex]CI = & \displaystyle \left( \hat p - z_c \sqrt{\frac{\hat p (1-\hat p)}{n}}, \hat p + z_c \sqrt{\frac{\hat p (1-\hat p)}{n}} \right)[/tex]

The given information;

The farmer took a random sample of 40 cows out of 200 total cows and found that 11 of those cows have no spots. We can use this sample data to make a prediction about the entire population using statistical inference.

Now,

Plugging in the values, we get:

CI = 0.275 ± 1.96sqrt((0.275(1-0.275))/40)

CI = 0.275 ± 0.139

CI = (0.136, 0.414)

This means that we can be 95% confident that the true proportion of cows with no spots in the entire population lies between 0.136 and 0.414.

the farmer can predict that between 13.6% and 41.4%

Therefore, by confidence interval the answer will be  farmer can predict that 40 cows in the entire population have no spots

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Answer:

I can help you what you need help with

Step-by-step explanation:

The largest number of relief supplies that can be put in each box is 75 bottles and 8 cans of food respectively.

The factors of:

1350 = 1, 2, 3, 5, 6, 9, 10, 15, 18, 25, 27, 30, 45, 50, 54, 75, 90, 135, 150, 225, 270, 450, 675 and 1350.

144 = 1, 2, 3, 4, 6, 8, 9, 12, 16, 18, 24, 36, 48, 72, and 144.

1350 bottles / 18

= 75 bottles per box

144 cans of food / 18

= 8 cans of food per box

So, there 18 boxes of items, each containing 75 bottles and 8 cans of food respectively.

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Answer:

the answer would be 12-19+23=18 so you need a new calculator

Step-by-step explanation:

yes

The range of a dataset is the distance between the maximum value and the minimum value. The range is found by subtracting the minimum value from the maximum value: maximum - minimum = range.

Maximum value of this dataset = 20.4

Minimum value of this dataset = 10.1

20.4 - 10.1 = 10.3

Range = 10.3

Hope this helps!

Answer:

10.3

Step-by-step explanation:

Given set of values

Maximum value

Minimum value

Range

Answer:

D. 30

Step-by-step explanation:

Notice how $2 buys 6 packets. This means that if Sandra had $1, she could buy 3 packets.

If she had $10, you must multiply 3 (packets) by 10. Sandra can buy 30 packets with $10.

Answer:

The answer is 20 (I think)

Step-by-step explanation:

The question says 6 tomato seeds at $2

So, 10*2=20

hence proved

Answer:

$149 - price of the skateboard

$52 - Carly's money

$20 × 5 cars = $100

$100 + $52 = $152

$152 - $ 149 = $3

money left is $3

Answer: 24

Answer:

117

Step-by-step explanation:

we should subtract 63 from 180

so 180 - 63 = 117°

Check the picture below.

[tex]\stackrel{\textit{\Large Areas}}{\stackrel{\textit{front and back}}{2(5\cdot 3)}~~ + ~~\stackrel{\textit{left and right}}{2(3\cdot 4)}~~ + ~~\stackrel{\textit{top and bottom}}{2(5\cdot 4)}}\implies 30+24+40\implies 94[/tex]

The area of the entire surface of the solid given is 94 units².

The area of a three dimensional object on it's outer surface is called the surface area of the object.

Given a rectangular prism.

It consists of 3 pairs of identical rectangular sides.

Area of a rectangle = length × width

Find the area of each rectangular sides to find the total area.

Total area = (5 × 3) + (5 × 3) + (5 × 4) + (5 × 4) + (4 × 3) + (4 × 3)

                 = 15 + 15 + 20 + 20 + 12 + 12

                 = 94 units²

Hence the area of the prism given is 94 units².

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Answer:

x=6?

Step-by-step explanation:

I think it's this answer im not sure

Step-by-step explanation:

please mark me as brainlest

Answer:

[tex]\sf -\dfrac{1}{36}[/tex]

Explanation:

[tex]\rightarrow \sf -\dfrac{7}{9} -(-\dfrac{5}{12} )+\dfrac{1}{3}[/tex]

remove parenthesis

[tex]\rightarrow \sf -\dfrac{7}{9} +\dfrac{5}{12} +\dfrac{1}{3}[/tex]

all the denominators has a common multiple of 108

[tex]\rightarrow \sf -\dfrac{7(12)}{108} +\dfrac{5(9)}{108} +\dfrac{1(36)}{108}[/tex]

simplify

[tex]\rightarrow \sf \dfrac{-84}{108} +\dfrac{45}{108} +\dfrac{36}{108}[/tex]

join the fractions

[tex]\rightarrow \sf \dfrac{-84+45+36}{108}[/tex]

simplify

[tex]\rightarrow \sf \dfrac{-3}{108}[/tex]

simplify

[tex]\rightarrow \sf -\dfrac{1}{108}[/tex]

Recall the geometric sum,

[tex]\displaystyle \sum_{k=0}^{n-1} x^k = \frac{1-x^k}{1-x}[/tex]

It follows that

[tex]1 - x + x^2 - x^3 + \cdots + x^{2020} = \dfrac{1 + x^{2021}}{1 + x}[/tex]

So, we can rewrite the integral as

[tex]\displaystyle \int_0^\infty \frac{x^2 + 1}{x^4 + x^2 + 1} \frac{\ln(1 + x^{2021}) - \ln(1 + x)}{\ln(x)} \, dx[/tex]

Split up the integral at x = 1, and consider the latter integral,

[tex]\displaystyle \int_1^\infty \frac{x^2 + 1}{x^4 + x^2 + 1} \frac{\ln(1 + x^{2021}) - \ln(1 + x)}{\ln(x)} \, dx[/tex]

Substitute [tex]x\to\frac1x[/tex] to get

[tex]\displaystyle \int_0^1 \frac{\frac1{x^2} + 1}{\frac1{x^4} + \frac1{x^2} + 1} \frac{\ln\left(1 + \frac1{x^{2021}}\right) - \ln\left(1 + \frac1x\right)}{\ln\left(\frac1x\right)} \, \frac{dx}{x^2}[/tex]

Rewrite the logarithms to expand the integral as

[tex]\displaystyle - \int_0^1 \frac{1+x^2}{1+x^2+x^4} \frac{\ln(x^{2021}+1) - \ln(x^{2021}) - \ln(x+1) + \ln(x)}{\ln(x)} \, dx[/tex]

Grouping together terms in the numerator, we can write

[tex]\displaystyle -\int_0^1 \frac{1+x^2}{1+x^2+x^4} \frac{\ln(x^{2020}+1)-\ln(x+1)}{\ln(x)} \, dx + 2020 \int_0^1 \frac{1+x^2}{1+x^2+x^4} \, dx[/tex]

and the first term here will vanish with the other integral from the earlier split. So the original integral reduces to

[tex]\displaystyle \int_0^\infty \frac{1+x^2}{1+x^2+x^4} \frac{\ln(1-x+\cdots+x^{2020})}{\ln(x)} \, dx = 2020 \int_0^1 \frac{1+x^2}{1+x^2+x^4} \, dx[/tex]

Substituting [tex]x\to\frac1x[/tex] again shows this integral is the same over (0, 1) as it is over (1, ∞), and since the integrand is even, we ultimately have

[tex]\displaystyle \int_0^\infty \frac{1+x^2}{1+x^2+x^4} \frac{\ln(1-x+\cdots+x^{2020})}{\ln(x)} \, dx = 2020 \int_0^1 \frac{1+x^2}{1+x^2+x^4} \, dx \\\\ = 1010 \int_0^\infty \frac{1+x^2}{1+x^2+x^4} \, dx \\\\ = 505 \int_{-\infty}^\infty \frac{1+x^2}{1+x^2+x^4} \, dx[/tex]

We can neatly handle the remaining integral with complex residues. Consider the contour integral

[tex]\displaystyle \int_\gamma \frac{1+z^2}{1+z^2+z^4} \, dz[/tex]

where γ is a semicircle with radius R centered at the origin, such that Im(z) ≥ 0, and the diameter corresponds to the interval [-R, R]. It's easy to show the integral over the semicircular arc vanishes as R → ∞. By the residue theorem,

[tex]\displaystyle \int_{-\infty}^\infty \frac{1+x^2}{1+x^2+x^4}\, dx = 2\pi i \sum_\zeta \mathrm{Res}\left(\frac{1+z^2}{1+z^2+z^4}, z=\zeta\right)[/tex]

where [tex]\zeta[/tex] denotes the roots of [tex]1+z^2+z^4[/tex] that lie in the interior of γ; these are [tex]\zeta=\pm\frac12+\frac{i\sqrt3}2[/tex]. Compute the residues there, and we find

[tex]\displaystyle \int_{-\infty}^\infty \frac{1+x^2}{1+x^2+x^4} \, dx = \frac{2\pi}{\sqrt3}[/tex]

and so the original integral's value is

[tex]505 \times \dfrac{2\pi}{\sqrt3} = \boxed{\dfrac{1010\pi}{\sqrt3}}[/tex]

Answer:

B) B

Step-by-step explanation:

       In this case, the first partial product will be 2 * 5 which is 10. The only option that shows this is option B, so this is our answer.

       We can also check the answers as a whole,

2 * 5 = 10

80 * 5= 400

400 + 1 = 410

       Again, only option B gives us this. This is means that option B is our answer.

Answer:

B

Step-by-step explanation:

82

5

--

5 x 2 = 0 (carry 1)

5 x 8 + 1 = 1 (carry 4 to bottom)

Answer:

Angle CBD is 65°

Step-by-step explanation:

All of these angles add up to 180:

So, we can make this equation: (x is CBD)

46 + 21 + 48 + x = 180

115 + x = 180

-115         -115

x = 65

Hope this helps

Answer:

∠CBD = 65 degrees

Step-by-step explanation:

Please open the attached image!!

Answer:

Step-by-step explanation:

Given that, The length of a rectangle is 3 m more than twice the width, and the area of the rectangle is 54 m²

Let's assume width of rectangle be x m and length be 3 + 2x m respectively. To find the dimensions of the rectangle we will use the formula of Perimeter of rectangle

[tex] \\ { \underline{ \boxed{ \pmb{ \sf{ \purple{Area _{(rectangle)} = Length × width}}}}}} \\ \\ [/tex]

Substituting values in above formula:

[tex] \\ \dashrightarrow \sf \: \: (3 + 2x)(x) = 54 \\[/tex]

[tex]\dashrightarrow \sf \: \: 3x + 2x^2 = 54 \\ [/tex]

[tex]\dashrightarrow \sf \: \: - 54 + 3x + 2x^2 = 0 \\ [/tex]

[tex]\dashrightarrow \sf \: \: 2x^2 + 3x - 54 = 0\\ [/tex]

[tex]\dashrightarrow \sf \: \: 2x^2 + 12x - 9x - 54 = 0\: [/tex]

[tex]\dashrightarrow \sf \: \: 2x(x + 6) -9(x + 6) = 0\\ [/tex]

[tex]\dashrightarrow \sf \: \: (2x -9)(x+6) = 0 \\ [/tex]

[tex]\sf{x=}{\sf{\dfrac{9}{2}}}{\sf{\: or\: -6}} [/tex]

[tex]\dashrightarrow \: \: { \underline{ \boxed{ \pmb{ \sf{\purple{ x = 4.5 }}}}}}[/tex]

Hence,

[tex] \\ { \underline{ \pmb{ \frak{ \therefore Length \: and \: width \: of \: the \: rectangle \: is \:12 \: m \: and \: 4.5 \: m}}}} \\ [/tex]

Answer:

Step-by-step explanation:

Given :-

To find :-

Solution:-

According to the question ,

Let the width of rectangle be x and length of rectangle be 2x+3 m

Area of rectangle :- L×B

L×B = 54m²

(2x+3) * x = 54m²

x = 4.5 m

By putting the value of x , we get

Length :- 2x+3 = 12 m

Width :- 4.5 m

Answer:

82 ft²

Step-by-step explanation:

Area of the patio:

5 x 9 =45

Area of the walkway:

2 x 8 =16

Area of the garden:

3 x 7 =21

Total:

45+16+21 = 82

Answer:

[tex] \sqrt{41} [/tex]

Step-by-step explanation:

[tex]let \: the \: hypothenuse =\: x \\ by \: pythagoras \: theorem \\ x {}^{2} = 4 {}^{2} + 5 {}^{2} \\ x {}^{2} = 16 + 25 \\ x {}^{2} = 41 \\ sqare \: root \: bothsides \\( \sqrt{x}) {}^{2} = \sqrt{41} \\ x = \sqrt{41} \\ lenght \: of \: the \: hypothenus = \sqrt{41} [/tex]

Answer:

r = 8.12

Step-by-step explanation:

The volume for a cylinder is V=πr^2h therefore,

v = 2279.64

h = 11ft

r = ?

2279.64 = πr^2 * 11

[tex]\frac{2279.64}{11}= {\pi r^2} \\[/tex]

207.24 = πr^2

[tex]\frac{207.24}{\pi} =r^2\\\\66 = r^2\\\\\sqrt{66} = r\\\\\\8.12 = r[/tex]

Answer:

23 gallons

Step-by-step explanation:

Given:

A barn is shaped like a rectangular prism with a triangular prism on top as shown.

The exterior four walls and two triangular faces need to be repainted.

To Find:

If one gallon of paint covers 232 square feet, how many gallons will it take to repaint the barn?

Solve:

[tex]12\cdot38\div2\cdot2+84\cdot20+38\cdot20\cdot2[/tex]

= [tex]5336\;square\;feet[/tex]

[tex]\frac{5336}{232}=23[/tex]

Hence 23 gallons to repaint the barn

~lenvy~