Frequency scaling was replaced by core scaling due to power density concerns.true/false

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Answer 1

True. Frequency scaling refers to increasing the clock speed of a processor to improve its performance.

However, as the frequency increases, the power consumption and heat generated by the processor also increase. This can lead to concerns about power density, which is the amount of power per unit area. To address these concerns, core scaling has become a more popular approach to improving processor performance. This involves adding more processor cores to a chip, rather than simply increasing the frequency of a single core. This allows for better performance while keeping power density under control.

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Related Questions

these columns go deep into the ground, connecting the earth to the sky, forming the axis of the universe. a. the wheel of the law b. columns of ashoka c. the cosmic mountain d. columns of kanishka

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The columns that go deep into the ground, connecting the earth to the sky and forming the axis of the universe are the cosmic mountain.

In Hindu mythology, the cosmic mountain, known as Mount Meru, is believed to be the center of the universe and is connected to the heavens and the earth. It is said to be so tall that its peak reaches the heavens, and so deep that its roots go all the way to the underworld. The cosmic mountain is often depicted in art and architecture, including the columns of ancient Indian emperors.

Therefore, the columns mentioned in the question, including the wheel of the law, columns of Ashoka, and columns of Kanishka, are not the columns that connect the earth to the sky and form the axis of the universe. Instead, it is the cosmic mountain that holds this significance in Hindu mythology.

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A force of 186 N acts on a 7.3 kg bowling ball for 0.40 s. What is the ball’s change in momentum

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A force of 186 N acts on a 7.3 kg bowling ball for 0.40 s. then the ball’s change in momentum is 74.4 Ns.

Momentum is defined as mass times velocity. it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum. its dimensions is [M¹ L¹ T⁻¹]. Momentum is conserved throughout the motion. According to conservation law of momentum initial momentum is equal to final momentum.

Change in momentum with respect to time is force,

F = Δp/Δt

Hence change in momentum is equal to,

Δp=F ×Δt

Δp= 186 × 0.40

Δp= 74.4 Ns

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if a 0.15- kg baseball with a radius of 3.7 cm is thrown with a linear speed of 48 m/s and an angular speed of 43 rad/s , how much of its kinetic energy is translational energy? assume the ball is a uniform, solid sphere.

Answers

The translational energy of the baseball is 151.88 J and the rotational energy is 0.033 J.

To calculate the translational energy of the baseball, we need to use the formula for kinetic energy:
K_trans = (1/2)mv^2
where m is the mass of the baseball and v is the linear speed. Plugging in the given values, we get:
K_trans = (1/2)(0.15 kg)(45 m/s)^2
K_trans = 151.88 J
To calculate the rotational energy of the baseball, we need to use the formula for rotational kinetic energy:
K_rot = (1/2)Iω^2
where I is the moment of inertia of the baseball and ω is the angular speed. For a uniform, solid sphere, the moment of inertia is given by:
I = (2/5)mr^2
Plugging in the given values, we get:
I = (2/5)(0.15 kg)(0.037 m)^2
I = 4.13 x 10^-5 kg*m^2
Now we can calculate the rotational energy:
K_rot = (1/2)(4.13 x 10^-5 kg*m^2)(40 rad/s)^2
K_rot = 0.033 J

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(240) What size overcurrent protection device is required for a 45 ampere continuous load? The circuit is in a raceway with 14 current carrying conductors.

Answers

For a 45A continuous load in a circuit with 14 current-carrying conductors, a 60A overcurrent protection device is required (NEC guidelines).

To decide the size of the overcurrent security gadget expected for a 45-ampere nonstop burden in a circuit with 14 current-conveying guides, you want to think about two factors: the consistent burden and the quantity of current-conveying guides.

According to NEC rules, for a nonstop burden, the overcurrent security gadget ought to be evaluated no less than 125% of the heap, which for this situation would be:

125% x 45 amps = 56.25 amps

Furthermore, for a circuit with multiple current-conveying guides, the ampacity of the guides should be changed by a derating factor. According to NEC Table 310.15(B)(3)(a), when there are 14 current-conveying guides in a raceway, the derating factor is 70%. Subsequently, the changed ampacity of the guides would be:

45 amps x 0.7 = 31.5 amps

Since the changed ampacity of the guides is not exactly the base required size of the overcurrent assurance gadget (56.25 amps), the base size overcurrent insurance gadget expected for this circuit would be 60 amps.

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2. Globalization implies all of the following except:
a. the world is free from national boundaries
b. a borderless world
c. competition between workers from other countries
d. an organization's nationality is held strongly in consciousness

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The correct answer is d. an organization's nationality is held strongly in consciousness. Globalization is the process of increasing interconnectedness and interdependence among individuals, businesses, and countries worldwide.

It involves the breaking down of national boundaries and creating a borderless world where goods, services, and people can move freely. As a result, there is increased competition between workers from different countries, but the emphasis on an organization's nationality is reduced in the face of globalization.
Globalization implies all of the following except

d. an organization's nationality is held strongly in consciousness

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A 5.00-kg sphere is moving at a speed of 4.00 m/s. An identical sphere is at rest. The two spheres collide. The first sphere moves off at a 60.0° angle to the left of its original path. The second sphere moves off in a direction 90.0° to the right of the first sphere’s final path. Assuming no friction, what are the speeds of the two spheres as they separate?

Answers

Answer:C

Explanation:

You should just have to do the math and will get you C

An electron moving along the +x-axis enters a magnetic field. Ifthe electron experiences a magnetic deflection in the -y direction, what is the direction of the magnetic field in this region?A) along the +z-axisB) along the -z-axisC) along the -x-axisD) along the +y-axisE) along the -y-axis

Answers

The direction of the magnetic field in this region is along the -z-axis (option B).

To determine the direction of the magnetic field when an electron moving along the +x-axis experiences a magnetic deflection in the -y direction, we can use the right-hand rule.

1: Point your thumb in the direction of the electron's motion, which is along the +x-axis.
2: Point your index finger in the direction of the magnetic force experienced by the electron, which is in the -y direction.
3: Your middle finger will point in the direction of the magnetic field.

Following these steps, your middle finger will point along the -z-axis.

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The head of a golf club moving at 45. 0 m/s strikes a golf ball (mass 46. 0 g) resting on a tee. The effective mass of the clubhead is 220 g. (a) with what speed does the ball leave the tee? (b) with what speed would it leave the tee if you doubled the mass of the clubhead? if you tripled it? what conclusions can you draw about the use of heavy clubs? assume that the collisions are perfectly elastic and that the golfer can bring the heavier clubs up to the same speed at impact. See question 13

Answers

Answer:

We can use the conservation of momentum and energy to solve this problem. Since the collision is perfectly elastic, both momentum and kinetic energy are conserved.

Let's first find the initial velocity of the combined club and ball system:

m_clubhead = 220 g = 0.22 kg  (effective mass of the clubhead)

m_ball = 46.0 g = 0.046 kg

v_clubhead = 45.0 m/s

The initial momentum of the system is:

p_i = m_clubhead * v_clubhead = 0.22 kg * 45.0 m/s = 9.90 kg·m/s

Since momentum is conserved, the final momentum of the system is also equal to 9.90 kg·m/s:

p_f = m_clubhead * v_clubhead' + m_ball * v_ball'

where v_clubhead' and v_ball' are the velocities of the clubhead and ball after the collision, respectively.

The initial kinetic energy of the system is:

KE_i = 1/2 * m_clubhead * v_clubhead^2 = 0.5 * 0.22 kg * (45.0 m/s)^2 = 222.75 J

Since kinetic energy is conserved, the final kinetic energy of the system is also equal to 222.75 J:

KE_f = 1/2 * m_clubhead * v_clubhead'^2 + 1/2 * m_ball * v_ball'^2

Now we can solve for v_ball':

p_f = m_clubhead * v_clubhead' + m_ball * v_ball'

9.90 kg·m/s = 0.22 kg * v_clubhead' + 0.046 kg * v_ball'

KE_f = 1/2 * m_clubhead * v_clubhead'^2 + 1/2 * m_ball * v_ball'^2

222.75 J = 0.5 * 0.22 kg * v_clubhead'^2 + 0.5 * 0.046 kg * v_ball'^2

We have two equations and two unknowns (v_clubhead' and v_ball'), so we can solve for v_ball':

v_ball' = (p_f - m_clubhead * v_clubhead') / m_ball

Substituting this expression into the energy conservation equation and solving for v_clubhead', we get:

v_clubhead' = sqrt(2/m_clubhead * (m_ball * v_ball'^2 + KE_i - KE_f))

Now we can use this equation to answer the questions:

(a) With the given data, we get:

v_ball' = (9.90 kg·m/s - 0.22 kg * 45.0 m/s) / 0.046 kg = 93.70 m/s

v_clubhead' = sqrt(2/0.22 * (0.046 kg * (93.70 m/s)^2 + 222.75 J - 222.75 J)) = 45.0 m/s

Therefore, the ball leaves the tee with a speed of 93.70 m/s.

(b) If we double the mass of the clubhead, the effective mass becomes 440 g = 0.44 kg, and the initial momentum of the system doubles to 19.80 kg·m/s. Using the same equations as before, we get:

v_ball' = (19.80 kg·m/s - 0.44 kg * 45.0 m/s) / 0.046 kg = 187.41 m

Explanation:

The fusible plug that is in all chlorine containers?
a. May be used as a tap for the chlorine source
b. Should be removed after the cylinders are empty
c. Should never be removed or tampered with
d. Should be removed prior to withdrawing chlorine from the container

Answers

d. Should be removed prior to withdrawing chlorine from the container. The fusible plug is designed to melt at a specific temperature in case of a fire, releasing the pressure inside the container and preventing an explosion.

However, if the plug is still in place when chlorine is being withdrawn, it can cause the chlorine to react with the metal plug and potentially create a dangerous situation. Therefore, it is important to remove the fusible plug before withdrawing chlorine from the container. Removing or tampering with the fusible plug could lead to hazardous situations when withdrawing chlorine. Always follow proper safety guidelines and procedures when handling chlorine containers.

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Question 20
Which one of the following is potentially the most important in terms of global warming?
a. carbon dioxide
b. nitrous oxide
c. methane
d. chlorofluorocarbons

Answers

The correct answer is c. methane. While carbon dioxide is the most abundant greenhouse gas, methane is much more potent, with a global warming potential 28 times greater than carbon dioxide over a 100-year period.

Methane is produced by a variety of sources, including natural wetlands, livestock, landfills, and fossil fuel production. Reducing methane emissions is a crucial step in mitigating the effects of global warming.


Potentially, methane (c) can be considered the most important in terms of global warming due to its high heat-trapping capacity, although carbon dioxide is the most abundant greenhouse gas.

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Answer:

chlorofluorocarbons (CFCs)

Explanation:

It has the highest GWP (Global Warming Potential). Got it right!

Have a good one!

A man drops a cup from cretain height which breaks in to pieces what's energy changes are involved?

Answers

There are various energy changes that occur when a guy drops a cup from a specific height. The cup's elevation above the ground gives it potential energy.

This potential energy is transformed into kinetic energy, the energy of motion, as it descends. The kinetic energy is transmitted to the cup as it falls to the ground, breaking it into pieces. This process involves the conversion of kinetic energy into thermal energy from the collision and friction of the shattered pieces with the ground as well as potential energy of the broken pieces. When a cup breaks, energy is released in the form of sound waves, which are then transmitted from the cup to the surrounding air.

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How would i solve this/Find the force applied

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(a). The skier slides approximately 9.89 meters along the hill before stopping.

(b). The magnitude of the force stopping the skier is approximately 12.53 N.

(a) Work done on an object is equal to the change in its kinetic energy:

[tex]W_{net} = \Delta K[/tex]

At the bottom of the hill, the skier has a kinetic energy of:

[tex]K_i = (1/2)mv^2 = (1/2)(73 kg)(4.2 m/s)^2 = 1326.18 J[/tex]

The skier has a gravitational potential energy of:

[tex]U_f = mgh = (73 kg)(9.8 m/s^2)[/tex](sin 9°)(x)

The net work done on the skier is equal to change in gravitational potential energy:

[tex]W_{net} = \Delta U = U_f - U_i[/tex]

Solving for x :

x = (K_i - U_f) / (mg sin 9°) = [tex](1326.18 J - (73 kg)(9.8 m/s^2)[/tex](sin 9°)(x)) / ([tex]73 kg[/tex])([tex]9.8 m/s^2[/tex])(sin 9°)

x = 9.89 m

(b)  Using trigonometry, we can calculate force:

F_parallel = mg sin 9° =[tex](73 kg)(9.8 m/s^2)[/tex](sin 9°) = 12.53 N

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a heat engine operates by group of answer choices usually having an efficiency equal to the maximum efficiency. transferring energy from a hot reservoir to a cold reservoir. always having an efficiency of 100% to conserve energy. usually having an efficiency less than the maximum efficiency. using a temperature difference between two thermal reservoirs.

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The heat engine operates by using a temperature difference between two thermal reservoirs and transferring energy from a hot reservoir to a cold reservoir. Usually, the efficiency of a heat engine is less than the maximum efficiency, which is the theoretical limit for the efficiency of the engine.

The important to keep the engine operating within a safe temperature range to prevent damage or failure.  A heat engine operates by using a temperature difference between two thermal reservoirs, transferring energy from a hot reservoir to a cold reservoir. In this process, it usually has an efficiency less than the maximum efficiency, as no engine can achieve 100% efficiency due to energy losses, primarily in the form of heat.

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Question 21
The major impact of global warning would most likely be in:
a. a general decrease in human skin cancer
b. an increase in human skin cancer
c. an alteration of world-wide rainfall
d. a melting in the polar cap

Answers

The correct answer is option c, an alteration of world-wide rainfall. Global warming can lead to changes in weather patterns and precipitation, causing alterations in rainfall levels and distribution.

It can also lead to melting of glaciers and ice caps, which can contribute to sea level rise and affect rainfall patterns. While skin cancer rates can potentially be impacted by global warming due to increased exposure to UV radiation, it is not the major impact that would be expected. Melting of the polar cap is a consequence of global warming.


The major impact of "global warming" (not "global warning") would most likely be in:
d. a melting of the polar ice caps.


While global warming can also have effects on skin cancer rates and rainfall patterns, the most significant and widely recognized impact is the melting point .

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c) What if nonconservative forces, such as friction, also act within the system? In that case, the total mechanical energy will change. The law of conservation of energy is then written as

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The law of conservation of energy is then written as the totals mechanical energy of a system, including any nonconservative forces, is conserved only if the work done by nonconservative forces is equal to the change in mechanical energy.

The law of conservation of energy states that the total energy in a system is constant, meaning that energy cannot be created or destroyed, only transferred or converted from one form to another.

However, in the presence of nonconservative forces like friction, the total mechanical energy of the system will change over time.

In such cases, the law of conservation of energy is modified to state that the total energy of the system, including both kinetic and potential energy, is conserved, but the sum of the kinetic and potential energy may decrease due to energy lost as heat or work done against nonconservative forces.

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How will the water affect the speed at which sounds reach his ears?
A. Water will not affect the speed of sound.
B. The sound will travel faster than in air. C. The sound will travel slower than in air.​

Answers

The answer is C, because water is denser, therefore it will take a longer time to reach the ears

31) Where does most star formation occur in the Milky Way today? A) in the halo B) in the bulge C) in the spiral arms D) in the Galactic center E) uniformly throughout the Galaxy

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Most star formation in the Milky Way Galaxy today occurs in the Galactic spiral arms. These arms are regions of high density and concentration of gas and dust, which are necessary for the formation of stars.

As the Milky Way rotates, the spiral arms move through the Galaxy, sweeping up gas and dust and triggering the formation of new stars. The Galactic center is also a region of active star formation, but the conditions there are much more extreme and only certain types of stars can form. In contrast, the spiral arms offer a more conducive environment for a wider range of stars to form. Overall, star formation in the Milky Way is a complex and ongoing process, influenced by a variety of factors such as density, temperature, and chemical composition of the interstellar medium. Studying the locations and characteristics of star formation in the Galaxy can provide valuable insights into the evolution of our Galactic neighborhood and the formation of our own Solar System.

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Question 33
The green pages of the emergency response guidebook lists a. EPA hazardous materials personnel
b. hazardous materials in alphabetical order
c. initial isolation and protective action distances
d. hazardous material by ID number

Answers

The green pages of the Emergency Response Guidebook list hazardous materials by ID number.

Therefore the answer is d) hazardous material by ID number.

The Emergency Response Guidebook (ERG) is a guidebook developed jointly by the US Department of Transportation (DOT), Transport Canada, and the Secretariat of Communications and Transportation of Mexico. The ERG provides guidance for first responders and emergency personnel who may be called upon to deal with hazardous materials incidents during transport.

The guidebook is divided into color-coded sections, with the green pages providing information on specific hazardous materials. These pages list the hazardous materials by their ID number, which is a unique four-digit number assigned by the DOT to each hazardous material.

The ID number provides information on the specific hazards posed by the material, as well as guidance on appropriate response actions, initial isolation and protective action distances, and other important information.

The green pages also provide information on the appropriate response actions for different situations, such as fire, spill, or leak, and provide guidance on protective clothing and equipment, evacuation, and decontamination.

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Final answer:

The green pages of the emergency response guidebook list initial isolation and protective action distances for hazardous materials. They don't list hazardous materials in alphabetical order, by ID number or EPA hazardous materials personnel.

Explanation:

The green pages of the emergency response guidebook provide detailed information about initial isolation and protective action distances. These pages are crucial in the event of a hazardous material incident, allowing responders to quickly determine the necessary steps to isolate the hazardous area and protect individuals in the vicinity. The green pages do not list hazardous materials in alphabetical order, by ID number, or EPA hazardous materials personnel. Instead, they focus solely on providing guidance for initial isolation and protective action distances.

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What type of electromagnetic radiation is light with a wavelength of 10 meters? Use the electromagnetic spectrum show.

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The type of electromagnetic radiation is Radiowaves which have a wavelength of 10 meters.

Since these waves have a longer wavelength, they are used for communication over long distances. Some examples of sources that emit these radiations - radiowaves - are TV and radio stations, cell phone towers, as well as satellites.

Radio waves are very beneficial as they can travel long distances without any power losses and getting absorbed or scattered by the atmosphere. Also, radio waves are non-ionizing and generally considered safe for human exposure. They are widely used in many applications, including broadcasting, navigation, remote sensing, and medical imaging.

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Due to the wave nature of light, light shined on a single slit will produce a diffraction pattern. Green light (570 nm) is shined on a slit with width 0.465 mm. (a) Find the width of the central maximum located 1.80 m from the slit. mm (b) What is the width of the first order fringe

Answers

(a) The width of the central maximum is 3.75 mm. (b) The width of the first order fringe is 1.87 mm.

(a) The width of the central maximum can be found using the formula:

w = (λL) / D

where w is the width of the central maximum, λ is the wavelength of light, L is the distance from the slit to the screen, and D is the width of the slit.

Substituting the given values, we get:

w = (570 × 10⁻⁹ m × 1.80 m) / 0.465 × 10⁻³ m = 3.75 mm

Therefore, the width of the central maximum is 3.75 mm.

(b) The width of the first order fringe can be found using the formula:

w = (λL) / d

where w is the width of the first order fringe, λ is the wavelength of light, L is the distance from the slit to the screen, and d is the distance from the central maximum to the first order fringe.

To find d, we can use the small angle approximation:

sinθ ≈ θ ≈ d/L

where θ is the angle between the central maximum and the first order fringe.

Substituting the given values, we get:

θ = d/L = 1.87 × 10⁻³ m / 1.80 m ≈ 0.00104 radians

Using the same formula as part (a), we can find the width of the first order fringe:

w = (570 × 10⁻⁹ m × 1.80 m) / 0.00104 = 1.87 mm

Therefore, the width of the first order fringe is 1.87 mm.

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The Ptolemaic model probably persisted for all these reasons EXCEPT:
A. It had the authority of aristotle behind it
B. It explain why stellar parallax was not observed by the greeks
C. It used perfect circles, which appealed to geometry.
D. It was consistent with the doctrines of the catholic church.
E. It accounted well for galileo's observations of the phase cycle of venus

Answers

E. It accounted well for Galileo's observations of the phase cycle of Venus. It accounted well for Galileo's observations of the phase cycle of Venus. The Ptolemaic model was an Earth-centered model of the universe that persisted for centuries despite its inaccuracies.

It was supported by Aristotle's authority and its use of perfect circles in its geometry. Additionally, it was consistent with the doctrines of the Catholic Church. However, it was unable to explain why stellar parallax was not observed by the Greeks. This fact was eventually used as evidence to support the heliocentric model of the universe proposed by Copernicus. Although Galileo's observations of the phase cycle of Venus were significant in advancing the heliocentric model, they were not a reason for the persistence of the Ptolemaic model.

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Question 3 Marks: 1 In practice, exposure to all ionizing radiation is controlled by the use of shields of lead.Choose one answer. a. True b. False

Answers

True, exposure to all ionizing radiation is controlled by the use of shields of lead.

Ionizing radiation is a form of energy that acts by removing electrons from atoms and molecules of materials that include air, water, and living tissue. Ionizing radiation can travel unseen and pass through these materials. Ionizing radiation, including nuclear radiation, consists of subatomic particles or electromagnetic waves that have sufficient energy to ionize atoms or molecules by detaching electrons from them.

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Which kind of transportation service provider provides convenient door-to-door service between two locations and is capable of carrying most any form of freight? a. Air carrierb. Pipeline carrierc. Truckload carrierd. Railroad carriere. Less-than-truckload carrier

Answers

Transportation service provider provides convenient door-to-door service between two locations and is capable of carrying most any form of freight is (c).Truckload carried is correct option.

A truckload carrier is a kind of transport company that provides door-to-door service between two sites and has the ability to transport almost any kind of freight. These transporters frequently make use of sizable trucks that can handle full truckload (FTL) or less-than-truckload (LTL) delivery of heavy items.

They have the ability to move a variety of commodities, such as bulky items, perishable goods, and other kinds of cargo. Truckload carriers are frequently employed for long-distance transportation and are renowned for their adaptability, convenience, and capacity to move freight directly between two locations without making any stops in between or requiring transfers.

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bob is pushing a box across the floor at a constant speed of 1.1m/s m / s , applying a horizontal force whose magnitude is 55n n . alice is pushing an identical box across the floor at a constant speed of 2.2m/s m / s , applying a horizontal force. a) what is the magnitude of the force that alice is applying to the box?

Answers

The boxes are identical and they have the same mass. Also, since both boxes are moving at a constant speed, their acceleration is zero. Therefore, the force that Alice is applying to the box is also 55 N.

To find the magnitude of the force that Alice is applying to the box, we need to use the equation: force = mass x acceleration

Since both boxes are identical, they have the same mass. Also, since both boxes are moving at a constant speed, their acceleration is zero. Therefore, the force that Alice is applying to the box is also 55 N.

To find the magnitude of the force Alice is applying, we should first understand that the force applied is proportional to the velocity when the boxes are moving at a constant speed. Since Alice's box moves at 2.2 m/s and Bob's box moves at 1.1 m/s, Alice's box is moving twice as fast as Bob's box.

To maintain this constant speed, the force applied must also be doubled. Since Bob is applying a force of 55 N, Alice must apply a force of 2 times 55 N, which is equal to 110 N. Therefore, the magnitude of the force Alice is applying to the box is 110 N.

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Question 38 Marks: 1 Water in wading pools should be completely recirculated everyChoose one answer. a. 1 to 2 hours b. 12 hours c. 6 hours d. 24 hours

Answers

The correct answer is c. 6 hours. Water in wading pools should be completely recirculated every 6 hours to maintain safe and clean water conditions for children. This helps to prevent the growth of harmful bacteria and other contaminants.

Wading pools are shallow pools typically used by children for play and recreation. Because the water in these pools is often not treated with chemicals like chlorine, it is important to ensure that the water is recirculated frequently to maintain its cleanliness and prevent the spread of waterborne illnesses. According to industry standards and guidelines, the water in wading pools should be completely recirculated every 6 hours. This helps to ensure that the water is adequately filtered and treated, and that any contaminants or bacteria are removed before they can cause harm to swimmers.

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Conductors in Parallel(310-10(H)(5): All parallel equipment grounding conductors are required to be a minimum No. 1/0.(True/False)

Answers

All parallel equipment grounding conductors must be a minimum No. 1/0 according to the code 310-10(H)(5). The answer is: False. The code 310-10(H)(5) does not specify a minimum No. 1/0 size for parallel equipment grounding conductors. It is important to follow the specific code requirements for conductor sizing in parallel installations.

According to NEC 310-10(H)(5), parallel equipment grounding conductors are not required to be larger than No. 1/0 unless they are part of a feeder or service entrance, in which case they must be at least the same size as the largest ungrounded conductor. However, it is recommended to use the same size equipment grounding conductors in parallel to simplify installation and minimize impedance differences between the conductors.

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Compression is to crest as rarefaction is to _________.


A. Peak

B. Trough

C. Amplitude

D. Wavelength

Answers

Compression is to crest as rarefaction is to Trough.

Hence, the correct option is B.

Because

In a longitudinal wave, compression refers to the region where the particles are closer together, while rarefaction refers to the region where the particles are farther apart.

The crest and trough, on the other hand, are terms used in transverse waves to describe the highest and lowest points of the wave, respectively. Therefore, in this analogy, rarefaction is equivalent to the trough.

Hence, the correct option is B.

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Given a parallel runtime of 20s on eight cores and a serial runtime of 80s, what is the runtime in seconds on 16 cores assuming the same efficiency (do not include any units in the answer)?

Answers

If we assume the same efficiency, then we can use Amdahl's Law to calculate the new runtime on 16 cores.

Amdahl's Law states that the speedup of a parallel program is limited by the portion of the program that must be executed sequentially. In this case, the portion that must be executed sequentially is (80-20)/80 = 0.75 or 75%. This means that only 25% of the program can be parallelized. Therefore, the speedup we can expect from doubling the number of cores is limited to 1/((1-0.25) + 0.25/8) = 1.85.
Using this speedup, we can calculate the new runtime on 16 cores as 20/1.85 = 10.81 seconds.

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950-kg satellite orbits the earth at a constant altitude of 90-km. (b) what is the change in the system's kinetic energy?

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The change in the system's kinetic energy of the 950-kg satellite orbiting the earth at a constant altitude of 90 km is zero.

This is because the satellite is orbiting at a constant altitude, meaning its distance from the Earth's center is constant, and therefore, its potential energy remains constant.  When the altitude is constant, there is no change in the system's kinetic energy, as the satellite maintains the same speed and distance from the Earth. Therefore, the change in kinetic energy is 0. Since the total energy of a satellite in orbit is constant, any change in potential energy is compensated by an equal and opposite change in kinetic energy. Therefore, since the potential energy is constant, the kinetic energy must also be constant.

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A ΔV = 2.7 V battery loses E = 6 J of energy each day (t = 24 hrs) powering a cell phone.
Part (a) Input an expression for the average current, I, supplied to the phone. Expression :
I = __________________________________________
Select from the variables below to write your expression. Note that all variables may not be required. α, β, ΔV, θ, a, d, E, g, h, j, k, m, P, S, t
Part (b) What is the current in Amperes?
Numeric : A numeric value is expected and not an expression. I =

Answers

The current supplied to the phone is 93.75 milliamperes (mA) or 0.09375 Amperes (A).

Part (a) Expression for the average current, I, supplied to the phone:

We can use the formula for electrical power:

Power = current x voltage

The energy lost by the battery each day is given by:

Energy = Power x time

E = P x t

Substituting Power = I x ΔV and time t = 24 hrs, we get:

E = I x ΔV x t

I = E / (ΔV x t)

Therefore, the expression for the average current supplied to the phone is:

I = E / (ΔV x t)

Part (b) Numeric value for the current in Amperes:

Substituting the given values, we get:

I = 6 J / (2.7 V x 24 hrs)

I = 0.09375 A or 93.75 mA

Therefore, the current supplied to the phone is 93.75 milliamperes (mA) or 0.09375 Amperes (A).

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