Hello I’m having a hard time with question

Hello Im Having A Hard Time With Question

Answers

Answer 1

[-1.5, 3.5] and [-2, infty) are the range and domain of the equation.

Determining the domain and range of a quadratic function

Quadratic function are functions that have a leading degree of 2.

The domain of the function are values that lies along the x-axis of the graph. Hence the domain of the curve will be [-1.5, 3.5]

The range of the function are values that lies along the y-axis of the graph. Hence the domain of the curve will be [-2, infty)

Hence the range and domain of the graph are [-1.5, 3.5] and [-2, infty)

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Related Questions

Cual de estas condiciones es menos probable que exista en una recesión o una depresión

Answers

Answer:you did not give us anyting for us to answer

Step-by-step explanation:

X divided by 5 multiply by 12

Answers

Answer:

Step-by-step explanation:

The expression "X divided by 5 multiplied by 12" can be written as:

( X / 5 ) * 12

To simplify this expression, we can first multiply 12 by X/5, which gives:

( X / 5 ) * 12 = X * (12/5)

So the simplified expression is:

X * (12/5)

or

(12/5)X

which is equivalent to "12/5 times X".

What is the median of these numbers 17 12 54 36 71 28 31 55

Answers

53.5
Ok so since there are 8 numbers it is gonna be in the middle of two numbers.. so you would take 36 and 71 and add them and since there are two numbers you will divide by 2 after you add them.. 36+71 is 107 , 107/2 is 53.5.. ANSWER IS 53.5!! The dude on top of me is wrong…

Ms. Wong sold 28 cars. She sold 8 fewer cars than 34 as many cars as Mr. Diaz. Which equation can be used to find the number of cars that Mr. Diaz sold, c?
Responses

Answers

So the equation that can be used to find the number of cars that Mr. Diaz sold, c, is:

34c - 8 = 28

Which kinds of equations are feasible?

In algebra, a statement of mathematics that proves the equality of two mathematical expressions is known as an equation. Consider the equation 3x + 5 = 14, where the word "equal" is used to denote the relationship between the terms 3x + 5 and 14.

Let c be the number of cars that Mr. Diaz sold.

According to the problem statement, Ms. Wong sold 8 fewer cars than 34 times the number of cars Mr. Diaz sold, which can be written as:

Ms. Wong's cars sold = 34c - 8

We also know that Ms. Wong sold 28 cars, so we can set this expression equal to 28 to get:

34c - 8 = 28

To solve for c, we can add 8 to both sides and then divide both sides by 34:

34c - 8 + 8 = 28 + 8

34c = 36

c = 36/34

So the equation that can be used to find the number of cars that Mr. Diaz sold, c, is:

34c - 8 = 28

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Could someone help me with part A, please, thanks! :)

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Answer:

a. The amount borrowed is $95,000. The annual interest rate is 5%. The number of payments per year is 12 (monthly payments). The loan term in years is 25, and the payment amount is $450.


b. The loan requires a total of 25 x 12 = 300 payments over the full term.


To calculate the total amount paid over the full term of the loan, we can use the formula for the present value of an annuity:


PV = PMT x [(1 - (1 + r)^-n) / r]


Where PV is the present value (the amount borrowed), PMT is the payment amount, r is the monthly interest rate (5% / 12 = 0.004167), and n is the total number of payments (300).


Plugging in the values, we get:PV = $95,000

PMT = $450

r = 0.004167

n = 300PV = $450 x [(1 - (1 + 0.004167)^-300) / 0.004167] = $144,781.92


Therefore, the total amount paid over the full term of the loan is $144,781.92.

" The expressions Q(t)=t+12
Q
(
t
)
=
t
+
12
and P(t)=t2+9t+36
P
(
t
)
=
t
2
+
9
t
+
36
models the unit price ′P(t)′

P
(
t
)

and quantity of goods ′Q(t)′

Q
(
t
)

sold from a shop in a given ′t′

t

month. Using this model, Calulate the total revenue of the shop for a year.

Answers

By integration of monthly revenue we will get total revenue of the shop for a year is $51,600.

What is integration ?

Integration is a fundamental operation in calculus that involves finding the area under a curve, or the antiderivative of a function. It is the reverse operation of differentiation, which is used to find the rate of change of a function.

Integration is represented by the symbol ∫ (the integral sign), and the result of the operation is called the indefinite integral or antiderivative of the function. The antiderivative is a family of functions that differ only by a constant, known as the constant of integration.

Given by the question:

The monthly revenue can be calculated by multiplying the unit price and the quantity of goods sold in a given month. Therefore, the monthly revenue function is:

[tex]R(t) = P(t) * Q(t) = (t^2 + 9t + 36) * (t + 12)[/tex]

To find the total revenue over a year, we need to integrate the monthly revenue function over the interval [0,12] (since we are considering a year):

[tex]Total revenue = \int\limits^a_0 {R(t)} \, dt[/tex]

= [tex]\int\limits^a_b (t^2 + 9t + 36) * (t + 12) } \, dt[/tex]

= [tex]\int\limits^a_b {(t^3 + 21t^2 + 132t + 432) } \, dt[/tex]

=[tex][t^4/4 + 7t^3/3 + 66t^2 + 432t][/tex]evaluated from 0 to 12

=[tex](20736/4 + 12096 + 9504 + 5184) - (0 + 0 + 0 + 0)[/tex]

= [tex]51600[/tex]

Therefore, the total revenue of the shop for a year is $51,600.

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Can someone help me with this problems with an explanation please? Thank you.

Answers

The values and heights obtained using the trigonometric ratios are as follows;

4. The six trigonometric ratios are;

cos(θ) = 15/17sec(θ) = [tex]1\frac{2}{15}[/tex]sin(θ) = 8/17csc(θ) = [tex]2\frac{1}{8}[/tex]tan(θ) = 8/15cot(θ) = [tex]1\frac{7}{8}[/tex]

5. The two other ways to write cot(θ) are;

cot(θ) = 1/tan(θ)cot(θ) = cos(θ)/sin(θ)

6. The six trigonometric function values are;

cos(x) = -3/5sec(x) = [tex]-1\frac{2}{3}[/tex]sin(x) = -4/5csc(x) = [tex]-1\frac{1}{4}[/tex]tan(x) = [tex]1\frac{1}{3}[/tex]cot(x) = 3/4

7. The function for the height of the tree is; H = 100·tan(θ)

The completed table is presented as follows;

θ   [tex]{}[/tex]               10°                 15°              20°                 25°

H[tex]{}[/tex]               17.63             26.79          36.4               46.63

What are trigonometric ratios?

Trigonometric ratios are functions that relate the ratio of two of the sides of a right triangle to an interior angle of the right triangle.

4. The length of the adjacent side to the angle θ according to the Pythagorean Theorem is; Adjacent = √(17² - 8²) = 15

The six trigonometric ratios are;

cos(θ) = 15/17, sec(θ) = 17/15 = 1 2/15

sin(θ) = 8/17, csc(θ) = 17/8 = 2 1/8

tan(θ) = 8/15, cot(θ) = 15/8 = 1 7/8

5. The 2 other ways to write cot(θ) are;

cot(θ) = 1/(tan(θ))

cot(θ) = cos(θ)/sin(θ)

6. The location of the point on the terminal side of the angle is; (-3, -4)

Length of the hypotenuse side = √((-3)² + (-4)²) = 5

Let x represent the angle, we get;

The six trig functions of the angle are;

cos(x) = -3/5sec(x) = -5/3 = -1 2/3sin(x) = -4/5csc(x) = -5/4 = -1 1/4tan(x) = -4/(-3) = 4/3 = 1 1/3cot(x) = 3/4

7. The length of the shadow of the tree = 100 m

Angle of elevation of the Sun = θ

Let h represent the height of the tree, we get;

tan(θ) = h/100

Therefore, the height of the tree, h = 100·tan(θ)

The values of the height of the tree at the different angle of elevation in the table are;

θ = 10°, h = 100 feet × tan(10°) ≈ 17.63 feet

θ = 15°, h = 100 feet × tan(15°) ≈ 26.79 feet

θ = 20°, h = 100 feet × tan(20°) ≈ 36.4 feet

θ = 25°, h = 100 feet × tan(25°) ≈ 46.63 feet

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Identify a sequence of transformations that maps triangle ABC onto triangle A”B”C” in the image below

Answers

The sequence of transformations that maps triangle ABC onto triangle A”B”C” is: First the triangle is rotated by 90 degrees thus following the transformation rule (x, y) → (y, -x) and then dilation.

What is dilation?

The scale factor is defined as the difference in size between the new and old images. An established location in the plane is the centre of dilatation. The dilation transformation is determined by the scale factor and the centre of dilation.

The image stretches when the scaling factor exceeds 1.

When the scale factor is between 0 and 1, the image gets smaller.

The resulting image and the original image are identical if the scale factor is 1.

The coordinates of the triangle ABC are:

A(0, -1)

B (0, 1)

C (0, 1.8)

First the triangle is rotated by 90 degrees thus following the transformation rule:

(x, y) → (y, -x)

The new coordinates are:

A(0, -1) → A (1, 0)

B (0, 1) → B (-1, 0)

C (0, 1.8) → C (1.8, 0)

Then, the rotated figure is dilated using a scale factor of:

SF = 6/2 = 3

Hence, the sequence of transformations that maps triangle ABC onto triangle A”B”C” is: First the triangle is rotated by 90 degrees thus following the transformation rule (x, y) → (y, -x) and then dilation.

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write the size of amoeba proteus in meters

Answers

Answer:

Step-by-step explanation:

up to beyond hald a milimeter in length

2mm

3. Which of the following are true? The universe for each statement is given in parentheses.
a) (Vx) (x+xzx). (R)
b) (3x) (2x+3=6x+7). (N)
c) (3x) (3*=x²). (R)
d) (3) (3x). (R)
e) (3x) (3(2-x)=5+8(1-x)). (R)
f) (Vx)(Vy) [x

Answers

The statement that are true are:

a) (Vx) (x+xzx). (R)

c) (3x) (3*=x²). (R)

d) (3) (3x). (R)

f) (Vx)(Vy) [x<y -> (3x<3y)]. (R)

What are the statement that are true?

a) (Vx) (x+xzx). (R) - This statement is true. It is a vacuously true statement, meaning it is true because the predicate (x+xzx) is never satisfied for any element x in the universe (R).

b) (3x) (2x+3=6x+7). (N) - This statement is false. There is no value of x in the universe (N) that satisfies the equation 2x+3=6x+7.

c) (3x) (3*=x²). (R) - This statement is true. For every value of x in the universe (R), 3 times x is equal to x squared.

d) (3) (3x). (R) - This statement is true. For any value of x in the universe (R), multiplying x by 3 will always result in a real number, which means 3x is also in the universe (R).

e) (3x) (3(2-x)=5+8(1-x)). (R) - This statement is false. There is no value of x in the universe (R) that satisfies the equation 3(2-x)=5+8(1-x).

f) (Vx)(Vy) [x<y -> (3x<3y)]. (R) - This statement is true. For any two elements x and y in the universe (R) where x<y, 3x is always less than 3y, so the implication (3x<3y) is true. Since this is true for all x and y, the universal quantifiers (Vx)(Vy) make the statement true.

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Referring to the figure, find an expression for the area.

Answers

The area of the figure can be expressed using the formula A = (x + 1)2.

What is area?

Area is a quantity that measures the size of a two-dimensional surface or shape. It is expressed in square units such as square centimetres (cm2), square metres (m2) or square kilometres (km2). Area is used to describe the size of a garden, a house, a room, a city and much more. It can also be used to calculate the amount of material required for a project, such as paint, carpet or tiles. Knowing the area of a shape can help to calculate costs, and to make sure that enough materials are ordered.

This formula is derived from the fact that the figure is a square with sides of length x + 1. Since a square is a special type of rectangle, the area of a square is simply equal to the product of its two sides, or (x + 1)2.

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Which value of x makes the following equation true?

2(x+8)=x+21

OA. -3
OB. 21
OC. 13
OD. 5

Answers

im pretty positive ur answer is 5

In the given figure, XYis a tangent to the circle with centre
Oat A. If LCAX= LBAY= 600, then OD equals

Answers

The measure of the segment OD is same as OE. Hence , OD = DE.

Tangent to A Circle :

A straight line that only touches a circle once is said to be tangent to it. The term "point of tangency" refers to this point. At the point of tangency, the tangent to a circle is perpendicular to the radius.

Given: XY is the tangent to the circle with centre O at A and

∠CAX=∠BAY=60°

By Alternate Segment Theorem

∠BCA=∠BAY=60°

Similarly,

∠ABC=∠CAX=60°

Therefore, ΔABC is an equilateral triangle circumscribing the circle with centre O.

Thus, centre O is also the centroid.

⇒OA:OD=2:1

Also,

OA=OE            (Radii)

∴ OD=DE

Hence , OD = DE

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A flagpole casts a 5 foot shadow while a nearby sign cast of 1 1/4 foot shadow. Find the height of the flag pole if the sign is 4 feet high.

Answers

Answer:

16Ft

Step-by-step explanation:

We can use proportions to solve this problem.

Let's let "x" be the height of the flagpole. We know that the sign is 4 feet high, and it casts a shadow of 1 1/4 feet. So we can set up the proportion:

4/1.25 = x/5

Simplifying the left side of the equation, we get:

4/1.25 = 16/5

Substituting into the original equation, we have:

16/5 = x/5

Multiplying both sides by 5, we get:

16 = x

Therefore, the height of the flagpole is 16 feet.

The perimeter of a rectangular parking lot is 274m. If the width of the parking lot is 62 m, what is its length?

Answers

The required length of the parking lot is 75 meters.

What is the perimeter?

Perimeter is the measure of the figure on its circumference.

Here,
Let's call the length of the parking lot "L". The perimeter of a rectangle is given by the formula:

Perimeter = 2 × (length + width)

We know that the width is 62 m and the perimeter is 274 m, so we can plug these values into the formula and solve for the length:

274 = 2 × (L + 62)

Dividing both sides by 2, we get:

137 = L + 62

Subtracting 62 from both sides, we get:

L = 137 - 62

L = 75

Therefore, the length of the parking lot is 75 meters.

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Use the graphs of f and g to find (f+g)(3).

Answers

Answer:

- 4

Step-by-step explanation:

(f + g)(3) = f(3) + g(3)

f(3) = - 5

g(3) = 1

f(3) + g(3) = - 5 + 1 = -4

please help me with this

here is the picture is just one question

Answers

Note that the equation for the parent function y=x² stretched horizontally by a factor of 4 and shifted down 5 units is given as follows: y = (1/16)x² - 5

What is the rationale for the above response?

Note that a parent function is a simple, basic function from which other more complex functions can be derived by applying transformations.

To stretch the graph horizontally by a factor of 4, we divide x by 4, which gives:

y = (1/16)x²

To shift the graph down 5 units, we subtract 5 from the whole function, which gives:

y = (1/16)x² - 5

Therefore, the equation for the parent function y=x^2 stretched horizontally by a factor of 4 and shifted down 5 units is:

y = (1/16)x² - 5

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Find the measure of angle 1
Find the measure of angle 2

Answers

The measure of angle 1 and the measure of angle 2 are 45° and 90°.

What is square?

A square is a two-dimensional closed shape with 4 equal sides and 4 vertices. Its opposite sides are parallel to each other.

Given is a square,

We are asked to find the missing angles,

We know that, The diagonals of the square bisect each other at 90°,

The diagonal of a square bisects its internal angle,

Therefore, the measure of angle 1 = 45°

And,

The measure of angle 2 = 90°

Hence, the measure of angle 1 and the measure of angle 2 are 45° and 90°.

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I can’t get this right!!!!

Answers

Answer:

[tex]\csc \theta=\dfrac{\sqrt{61}}{6}[/tex]

[tex]\sin \theta=\dfrac{6}{\sqrt{61}}=\dfrac{6\sqrt{61}}{61}[/tex]

[tex]\cot \theta=\dfrac{5}{6}[/tex]

Step-by-step explanation:

Use Pythagoras Theorem to calculate the length of the hypotenuse of the given right triangle:

[tex]\implies a^2+b^2=c^2[/tex]

[tex]\implies 5^2+6^2=c^2[/tex]

[tex]\implies 25+36=c^2[/tex]

[tex]\implies c^2=61[/tex]

[tex]\implies c=\sqrt{61}[/tex]

Therefore:

The side opposite angle θ is 6 units.The side adjacent angle θ is 5 units.The hypotenuse is √(61) units.

[tex]\boxed{\begin{minipage}{8cm}\underline{Trigonometric ratios}\\\\$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$\\\\\\$\sf\csc(\theta)=\dfrac{H}{O}\quad\sec(\theta)=\dfrac{H}{A}\quad\cot(\theta)=\dfrac{A}{O}$\\\\where:\\\phantom{ww}$\bullet$ $\theta$ is the angle.\\\phantom{ww}$\bullet$ $\sf O$ is the side opposite the angle.\\\phantom{ww}$\bullet$ $\sf A$ is the side adjacent the angle.\\\phantom{ww}$\bullet$ $\sf H$ is the hypotenuse.\\\end{minipage}}[/tex]

Substitute the given values into each ratio:

[tex]\csc \theta=\dfrac{\sqrt{61}}{6}[/tex]

[tex]\sin \theta=\dfrac{6}{\sqrt{61}}[/tex]

[tex]\cot \theta=\dfrac{5}{6}[/tex]

Note: The sin θ ratio can also be written as:

[tex]\implies \sin \theta=\dfrac{6}{\sqrt{61}}\cdot \dfrac{\sqrt{61}}{\sqrt{61}}[/tex]

[tex]\implies \sin \theta=\dfrac{6\sqrt{61}}{61}[/tex]

In what ratio must water be mixed with milk to gain 25% on selling the mixture at cost price?

Answers

we need to mix milk and water in the ratio of 1:5 to gain a profit of 25% when selling the mixture at cost price.

What is ratio ?

Ratio can be defined as given value divided by total value.

Let's assume that we have x liters of milk and y liters of water. We want to find the ratio in which water must be mixed with milk to gain 25% on selling the mixture at cost price.

If we sell the mixture at cost price, we will not make any profit or loss. So, let's first calculate the cost price of the mixture.

Assuming that the cost price of milk is the same as the cost price of water, the cost price of x liters of milk and y liters of water is:

Cost price = Cost price of milk + Cost price of water

= x * cost price of milk + y * cost price of water

Since we are not making any profit or loss, the selling price of the mixture will be the same as the cost price.

Now, to gain a profit of 25%, the selling price must be 125% of the cost price. So, we have:

Selling price = 125% of cost price

= 1.25 * (x * cost price of milk + y * cost price of water)

We know that the mixture contains only milk and water, so the total volume of the mixture is x + y liters.

Now, we can set up an equation to find the ratio of water to milk:

y/x = (1 - 1.25) / (1.25 - 0)

y/x = -0.2

Simplifying this equation, we get:

y = -0.2x

This means that for every 1 liter of milk, we need to mix it with 0.2 liters of water in order to gain a 25% profit when selling the mixture at cost price.

In terms of ratio, the ratio of water to milk is:

0.2 : 1

or

1 : 5 (by simplifying the ratio by multiplying both sides by 5)

Hence, we need to mix milk and water in the ratio of 1:5 to gain a profit of 25% when selling the mixture at cost price.

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In square ABCD, points E and F are midpoints of sides BC and CD, respectively. Line segments AE and BF intersect each other at point K. Which is greater: the area of triangle AKF or the area of quadrilateral KECF?

Answers

The area of quadrilateral KECF is greater than area of triangle.

What is Triangle?

A triangle is a three-sided polygon that consists of three edges and three vertices.

Given that ABCD is a square.

points E and F are midpoints of sides BC and CD, respectively

Line segments AE and BF intersect each other at point K

k is the midpoint of the square.

We need to find whether the area of triangle AKF or the area of quadrilateral KECF is greater.

then the area of quadrilateral will be greater.

Hence, the area of quadrilateral KECF is greater than area of triangle.

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he model below measures the proportion of the normal level of oxygen in a pond, where t is the time in weeks after organic waste is dumped into the pond. (Round your answers to two decimal places as needed) o(t)=0.6t2-t+2/( t^2 +2 )
(a) What will be the percentage of the normal oxygen level after 4 weeks? (b) How quickly (in percent per week) is the percentage of the normal oxygen level changing after 4 weeks? % per week What does this mean? At weeks, the percent of the Select- in a pond is increasing at a rate of 96 per week. (c) What will be the percentage of the normal oxygen level after 5 weeks? (d) Find o'(5) (5)- Interpret o'(5). At weeks, the percent of the -Select in a pond is increasing at a rate of 96 per week.

Answers

The percentage of the normal oxygen level after 4 weeks is 52.2%

At week 4, the percentage of the normal oxygen level in the pond is increasing at a rate of 96% per week.

The percentage of the normal oxygen level after 5 weeks is 41.9%

At week 5, the percentage of the normal oxygen level in the pond is increasing at a rate of 60% per week.

What is the increasing rate of a function?

The increasing rate of a function is the rate at which the function is increasing at a specific point in its domain. It tells us how fast the function is increasing, or how quickly its output values are getting larger, at that particular point.

The increasing rate can be determined using the derivative of the function. Specifically, if the derivative of a function is positive at a certain point, then the function is increasing at that point, and the magnitude of the derivative gives us the rate of increase. If the derivative is negative at a point, then the function is decreasing at that point, and the magnitude of the derivative gives us the rate of decrease.

In general, the sign of the derivative indicates the direction of change of the function, while the magnitude of the derivative indicates the rate of change. So, when we take the derivative of a function, we can use it to analyse how the function is changing and how quickly it is changing at each point in its domain.

The given model is:

o(t) = [0.6t² - t + 2] / [t² + 2]

(a) To find the percentage of the normal oxygen level after 4 weeks, we need to evaluate o(4) and multiply it by 100:

o(4) = [0.6(4²) - 4 + 2] / [4² + 2] = 9.4 / 18 = 0.522

So the percentage of the normal oxygen level after 4 weeks is:

0.522 * 100% = 52.2%

(b) To find how quickly the percentage of the normal oxygen level is changing after 4 weeks, we need to find the derivative of o(t) with respect to t and evaluate it at t = 4:

o'(t) = [1.2t(t²+ 2) - (2t)(0.6t² - t + 2)] / (t² + 2)²

o'(4) = [1.2(4)(4² + 2) - (2)(4)(0.6(4²) - 4 + 2)] / (4² + 2)² = 0.96

So the rate of change of the percentage of the normal oxygen level after 4 weeks is:

0.96 * 100% per week = 96% per week

This means that at week 4, the percentage of the normal oxygen level in the pond is increasing at a rate of 96% per week.

(c) To find the percentage of the normal oxygen level after 5 weeks, we need to evaluate o(5) and multiply it by 100:

o(5) = [0.6(5²) - 5 + 2] / [5² + 2] = 11.3 / 27 = 0.419

So the percentage of the normal oxygen level after 5 weeks is:

0.419 * 100% = 41.9%

(d) To find o'(5), we can use the same formula for the derivative of o(t) that we found in part (b), but evaluate it at t = 5:

o'(5) = [1.2(5)(5² + 2) - (2)(5)(0.6(5²) - 5 + 2)] / (5² + 2)² = 0.60

So at week 5, the percentage of the normal oxygen level in the pond is increasing at a rate of 0.60 * 100% per week, which is approximately 60% per week.

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Can you pls tell which one is a function and which one is not?

Answers

Answer:

Graph                 Function?

Graph 1                 No

Graph 2                No

Graph 3                Yes

Graph 4                Yes

Graph 5                No

Graph 6                No

Step-by-step explanation:

For a graph to represent a function, for a single value of x there can be one and only one value of y

When examining the graph of a function, use the vertical line test to see if the graph represents a function.

Vertical Line Test

The vertical line test is helpful to find if the given equation represents a function or not. The vertical line test states that a vertical line needs to cuts the graph of a function(equation) at only one point, for it to represent a function. If the graph of the equation represented in the coordinate axis, is cut by the vertical line at more than one point, then the graph is not a function.

Determine whether a curve in the plane represents the graph of a function by visually examining the number of intersections of the curve with vertical lines. and, as a result, any vertical line in the plane can intersect the graph of a function at most once.

For the given graphs, here are the results of the vertical line test

Graph #                      Vertical Line Test Result
Graph 1                        Fails
Graph 2                       Fails
Graph 3                       Succeeds
Graph 4                       Succeeds (vertical line intersects only one point)
Graph 5                       Fails
Graph 6                       Fails (vertical line through x =1 intersects 2 points)



Can you help me find the point of intersection for the question in the attached picture?

Answers

Answer:

y = x + 3 --- 1

y = 4x + 9 --- 2

By combining 1 and 2, we have

x + 3 = 4x + 9

3-9 = 4x-x

-6 = 3x

x = -2

Sub x = -2 into 1

y = (-2) + 3 = 1

Intersection = (-2,1)

In a school, 60% of the students are senior.
45% of the seniors have school meals.
75% of the juniors have school meals.
What percentage of the students (seniors and juniors) have school meals?

Answers

Answer:

57%

Step-by-step explanation:

Let's consider the total number of students as 100%.

60% of all students are senior, which means that the rest (40%) are juniors.

Out of all senior students, 45% have school meals.

To find the percentage of senior students who have school meals, we should do the following:

[tex]\ \frac{45\% \times60\%}{100\%} = 27\%[/tex]

This is the percentage of students who are senior and have school meals.

We need to repeat the same procedure with junior students.

To do that, we need to find the 75% of 40% out of total, which is 100%.

[tex] \frac{75\% \times 40\% }{100\%} = 30\%[/tex]

This is the percentage of junior students who have school meals.

Finally we need to add up the percentages to find the total percentage of students who have school meals.

[tex]27\% + 30\% = 57\%[/tex]

A line that makes up the boundary of an inequality (including the line itself) has points (4, 5),(1, −1) sitting on
it, find the inequality (and graph it) given that the point (−3, −5) makes the inequality false.

Answers

Using the graph of the line, we can see that the inequality, including the line which is the boundary of inequality, is:

 y + 2x ≥ -3

What is meant by inequality?

An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way. The majority of the time, size comparisons between two numbers on the number line are made. An inequality symbol has non-equal expressions on both sides. It indicates that the phrase on the left should be bigger or smaller than the expression on the right, or vice versa. Literal inequalities are relationships between two algebraic expressions that are expressed using inequality symbols.

Given that the boundary line of equality has points (4,5) and (1,-1) on it.

So we can write the equation of the line.

Slope m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] = -1-5 / 1-4 = 2

Equation of the line:

y - y1 = m (x-x1)

y - 5 = 2(x - 4)

y - 5 = 2x - 8

y = 2x - 3

y + 2x = -3

Point (−3, −5) makes the inequality false.

Substituting,

-5 + 2 * -3 = -5 - 6 = -11

y + 2x should not be -11

When graphing the line it should not include the point (−3, −5).

This point is present on the lower portion of the line.

So the upper portion of the line should be the inequality including the line itself.

Therefore using the graph of line, we can see that the inequality, including the line which is the boundary of inequality, is:

 y + 2x ≥ -3

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A triangle has side lengths of (6.2v+5.4w) centimeters, (5.2v - 6.7x) centimeters, and (2.1x - 5.3w) centimeters. Which expression represents the perimeter, in centimeters, of the triangle?​

Answers

Answer:

The answer to this question would be A

Step-by-step explanation:

I took the test one time before .

A music industry researcher wants to estimate, with a 95% confidence level, the proportion of young urban people (ages 21 to 35 years) who go to at least 3 concerts a year. Previous studies show that 42% of those people (21 to 35 year olds) interviewed go to at least 3 concerts a year. The researcher wants to be accurate within 1% of the true proportion. Find the minimum sample size necessary.

Answers

The researcher needs a minimum sample size of 1093 young urban people (ages 21 to 35 years) to estimate the proportion of those who go to at least 3 concerts a year with a 95% confidence level and an accuracy of within 1%.

To find the minimum sample size necessary to estimate the proportion of young urban people who go to at least 3 concerts a year with a 95% confidence level and an accuracy of within 1%, we can use the formula:

n = (z^2 * p * q) / E^2

where:

n is the minimum sample size
z is the z-score for the confidence level (in this case, 1.96 for a 95% confidence level)
p is the estimated proportion from previous studies (42% or 0.42)
q is 1 - p (the complement of p)
E is the maximum error or accuracy (1% or 0.01)
Plugging in the values, we get:

n = (1.96^2 * 0.42 * 0.58) / 0.01^2

n = 1.96^2 * 0.42 * 0.58 * 10000

n = 1092.33

Rounding up to the nearest whole number, the minimum sample size necessary is 1093.

Therefore, the researcher needs a minimum sample size of 1093 young urban people (ages 21 to 35 years) to estimate the proportion of those who go to at least 3 concerts a year with a 95% confidence level and an accuracy of within 1%.

a marketing manager tells her assistant that she wants to use only primary data in her market research. which of the following data would be most applicable for this research?

Answers

Primary data is usually designed to collect original data which is required for a specific kind of research. This data is tailored according to what is the focus of the research and what outcome are the people looking for.

Interviews: This is type of primary data in which we conduct interview of our target segment. The information exchange is mostly based out of questions and answers, and in-depth information regarding customer experience or product feedback could be easily done. This is collection of qualitative data instead of quantitative one. Only con is its high costs.Surveys and Questionnaire: This is the most common form of primary data collection, the main reason being this is not cost intensive and helps with getting large quantitative data for the research. Observation. This is most less likely to be used as primary data, as this mostly relates to behaver sciences. Thus, this is least conducted form of data collection. In products this would be used to observe the customer reaction to product packaging or their prices.Focus groups. Focus groups is collection of target segment and allowing them exchange of their thoughts. This helps with understanding customer behaver or understanding any pain-point that customer has. Experiment. This is the most basic form of primary data collection, here a controlled environment is designed and a determined process is followed in order to understand the causality of process with outcome.

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Complete Question:

A marketing manager tells her assistant that she wants to use only primary data in her market research. Which of the following data would be most applicable for this research?

Interviews

Observation

Focus groups

Experiment

Surveys and Questionnaire

qualitative research

market research

To indirectly measure the distance across a lake, Mia makes use of a couple
landmarks at points Vand W. She measures UX, XV, and XY as marked. Find
the distance across the lake (VW), rounding your answer to the nearest hundredth
of a meter.
W
70 m
120.25 m
130 m
U

Answers

The distance across the lake VW is 185m.

Define the term similar triangle?

Triangles that are similar but not necessarily the same size are called similar triangles. This indicates that their sides are proportional and that their angles are the same.

We can see there are two similar triangles with interior parallel line.

So, apply the Side Angle Side (SAS) rule for ΔUVW ≈ ΔUXY;

⇒   [tex]\frac{VW}{XY} = \frac{UV}{UX}[/tex]

⇒   [tex]\frac{VW}{120.25}=\frac{(130+70)}{130}[/tex]

Cross multiply both sides,

⇒   VW  =  [tex]\frac{200}{130}*120.25[/tex]

⇒    VW = 185 m

Therefore, the value of VW is 185m.

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