How do I connect with my higher self?​

"V = IR" is the equation that relates current to voltage.

Relationship between current and voltage:

                                           V = IR or,

                                           I = V/R,

        the amount of current (I) flowing through a circuit is inversely    

        related to the amount of resistance (r) and directly proportional to  

        the voltage (v).

Therefore the correct answer is option C i.e., "V = IR".

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Endarterectomy is used to reduce the risk of stroke and correct the stenosis in the artery.

The primary blood vessels that supply the brain with blood and oxygen are the carotid arteries.

The narrowing of these arteries is referred to as carotid artery disease. Carotid artery stenosis is another name for it. The main factor causing constriction is atherosclerosis.

This fat deposit reduces the blood flow to the brain which cause a stroke.

Carotid endarterectomy is a surgical treatment to remove plaque, an accumulation of fatty deposits that causes a carotid artery to become narrowed.

Hence, an Endarterectomy is used to reduce the risk of stroke, it will correct stenosis in the artery.

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The two aircrafts are skidded for 14.9 s.

To find the answer, we need to know about the Newton's equation of motion.

As per Newton's equation of motion

=> a= -1000/224.2= -4.5 m/s²

=> t= 20/4.5 = 4.4 s

Thus, we can conclude that the two aircrafts are skidded for 4.4 s.

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DNA sequencing is the technique which allows multiple peoples DNA to be compared to look for similarities and differences in order to solve crime and is denoted as option C.

This is referred to as the deoxyribonucleic acid and contains the genetic components of organisms and is also located in the nucleus. On the other hand, DNA sequencing refers to the process of determining the nucleic acid sequence.

Each organisms has a unique DNA sequence which is why it is used to identify individuals through the use of bodily fluids such as saliva, blood etc.

It is used to compare the similarities and differences in order to solve crime thereby making it the most appropriate choice.

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The speed of the trimmer is not affected by the the distribution of trimmer line inside the spool. Option A

The weed trimmer is a device that is used to trim the grasses on a lawn or a field. This device has a rotating shaft that does the actual trimming of the grasses.

The speed of the trimmer is not affected by the the distribution of trimmer line inside the spool thus it does not affect the amount of time required to reach 9,000 rpm speed.

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The magnitude of the tension in the string marked A and B is mathematically given as

A = 52.5 N

Generally, the equation for is mathematically given as

tan=3/8

negative x

[tex]B= tan\phi \\tan \phi=5/4[/tex]

negative x

C= tan=1/6

Hence, considering the Horizontal components

74.9cos(9.46) = A*cos(20.6) + B*cos(51.3)

A = 78.9 - 0.668B

Vertical components

74.9*sin(9.46) + Asin(20.6) = Bsin(51.3)

40.07 = 1.015B

B = 39.5 N

In conclusion, Sub the value of B is the equation of A

A = 78.9 - 0.668B

Sub

A = 78.9 - 0.668( 39.5 N)

A = 52.5 N

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Answer:

Projectile motion formula or equations derived (In Tabular format)Motion Path equation:

y = (tanθ) x – (1/2) g . x2/(V0 cosθ)2

Explanation:

The speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

v = √GM/r

where;

v = √[(6.626 x 10⁻¹¹ x 5.97 x 10²⁴) / ((6371 + 4930) x 10³)]

v = 5,916.36 m/s

Thus, the speed of the satellite moving in a stable circular orbit about the Earth is 5,916.36 m/s.

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Answer:

1. 13..6 grams per centimeters cubed.

2. Mass = 400kg

3. Volume = 200cm = 2m

Explanation:

1. The conversion for kg/m^3 to g/cm^3 is divide by 1000.

2. [tex]density=\frac{mass}{volume}[/tex]

[tex]1000=\frac{mass}{2 * 1 * 0.2}[/tex]

[tex]1000*0.4=mass[/tex]

[tex]400kg = mass[/tex]

3. [tex]density=\frac{mass}{volume}[/tex]

[tex]0.6=\frac{120}{volume}[/tex]

[tex]volume=\frac{120}{0.6}[/tex]

[tex]volume= 200cm[/tex]

(a) The magnitude and direction of the net force on the crate while it is on the rough surface is 24.67 N, opposite as the motion of the crate.

(b) The net work done on the crate while it is on the rough surface is -16.04 J.

(c) The speed of the crate when it reaches the end of the rough surface is 0.65 m/s.

F(net) = F - μFf

F(net) = 299 - 0.351(92 x 9.8)

F(net) = -24.67 N

W = F(net) x L

W = -24.67 x 0.65

W = - 16.04 J

a = F(net)/m

a = -24.67/92

a = - 0.268 m/s²

v² = u² + 2as

v² = 0.88² + 2(-0.268)(0.65)

v² = 0.426

v = √0.426

v = 0.65 m/s

Thus, the magnitude and direction of the net force on the crate while it is on the rough surface is 24.67 N, opposite as the motion of the crate.

The net work done on the crate while it is on the rough surface is -16.04 J.

The speed of the crate when it reaches the end of the rough surface is 0.65 m/s.

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The upward force exerted on the board by the support is 530.8 N.

The upward force exerted on the board by the support is calculated as follows;

F(up) = 52.8 N  +  206.0 N  +  272.0 N

F(up) = 530.8 N

Thus, the upward force exerted on the board by the support is 530.8 N.

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The change in the gravitational potential energy of the pole vaulter is 2,156 J.

The change in the gravitational potential energy of the pole vaulter is calculated as follows;

ΔP.E = mg(Δh)

where;

ΔP.E = (55)(9.8)(4)

ΔP.E = 2,156 J

Thus, the change in the gravitational potential energy of the pole vaulter is 2,156 J.

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The magnitude of the acceleration of block m2  is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.

The acceleration of the blocks is calculated from the net force on the blocks.

∑F = ma

a = ∑F/m

a = (F) / (m₁ + m₂)

where;

a = (0.03)/(0.04 + 0.02)

a = 0.09 m/s²

T = m₂a

T = (0.02 x 0.09) = 1.8 x 10⁻³ N

Thus, the magnitude of the acceleration of block m2  is 0.09 m/s² and the tension in the cord is 1.8 x 10⁻³ N.

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The mechanical energy lost due to friction is 360 J.

The distance the runner slides is, s = 0.655 m

The mechanical energy lost due to friction acting on the runner is equal to the change in kinetic energy.

Change in Kinetic energy = 1/2m(v -u)²

Change in Kinetic energy = 80 * (0 - 3.0)²/2

Change in Kinetic energy = 360 J

Mechanical energy lost = 360 J

Distance he slide is determined using the formula below as follows:

Acceleration of runner = coefficient of friction * acceleration due to gravity

acceleration, a = 0.7 * 9.8 = 6.86

v² = u² - 2as

s = v² + u²/2a

s = 0 + 3³/2 * 6.86

s = 0.655 m

In conclusion, the mechanical energy lost due to friction is the loss in kinetic energy.

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The total resistance in the circuit, R is 4 Ω .

The meters connected to the 12 Ω resistance are:

If the switch is opened, only the 4 Ω and 2 Ω resistances will stop working.

The resistances in the circuit are connected both in series and in parallel

The resistances in series are the 4 Ω and the 2 Ω resistances.

Equivalent resistance = 4 + 2 = 6 Ω

The 4 Ω and the 2 Ω resistances are then connected in parallel with the 12 Ω resistance.

Total resistance, R is calculated as follows:

1/R = 1/12 + 1/6

1/R = 3/12

R = 12/3

R = 4Ω

The meters connected to the 12 Ω resistance are:

If the switch is opened, only the 4 Ω and 2 Ω resistances will stop working because the circuit connecting them to the cell is broken whereas the circuit to the 12 Ω resistance is continuous.

In conclusion, resistances can be connected in parallel or in series.

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The weight of the automobile is 17,533.6 N.

The weight of the automobile is calculated as follows;

P = F / A

F = (W/4)

P = (W/4) / A

P = W/4A

W = 4AP

where;

W = (4)(217 x 10⁻⁴ m²)(2.02 x 10⁵ Pa)

W = 17,533.6 N

Thus, the weight of the automobile is 17,533.6 N.

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The change in temperature is 20 kelvin


What is Temperature?


Temperature can simply be described as how hot or how cold an object is at a particular period in time. The unit of temperature is Kelvin.

The formula for calculating change in temperature is

Final temperature - Initial temperature

Final temperature = 300 kelvin
Initial temperature= 280 kelvin

Change in temperature= 300-280

= 20 kelvin

Thus the change in temperature for this process is 20 kelvin


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The range of horizontal projectile motion is 3737.5 m.

A projectile's horizontal velocity is constant (a never changing value), Gravity causes a downward vertical acceleration with a magnitude of 9.8 m/s/s. A projectile's vertical velocity fluctuates by 9.8 m/s per second, A projectile's vertical motion is unrelated to its horizontal motion.  we know that sinθ is maximum at 90°. Therefore horizontal range will maximum at 45°.

To calculate the range of horizontal projectile motion we use;

Δx = vₓ t

where , Δx = Range

             vₓ  = Velocity

              t   = Time

Initial horizontal velocity, vₓ = 650 m/s

Time = 5.75 sec

                Δx = 650 × 5.75

                     = 3737.5 m

Therefore, the range of horizontal projectile motion is 3737.5 m.

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according to definition of acceleration

a=v-u/t

t=v-u/a(equation 1)

according to the formula of average velocity

v+u/2*s/t

s=v+u/2*t(equation 2)

now putting the value of t in equation 2

s=v+u/2*v-u/a

s=v^2-u^2/2a

v^2=u^2+2as

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Answer:

overloading can be avoided if two many appliances are not connected to a single socket short circuiting is a name given to a situation in which they live and the natural voice accidentally coming contact

The magnitude of the tension in the string marked A is 52.5N

Generally, the equation for is mathematically given as

Let's take θ be an angle at A

So, tanθ = 3/8

Let's take α be an angle at B (Below X)

tanα = 5/4

Let's take β be an angle at C (Below x)

tanβ = 1/6

First we take the Horizontal Components

74.9cos(9.46°) = Acos(20.6°) + Bcos(51.3°)

By solving the equation, we get

A = 78.9 - 0.668B … (1)

Now, we take the vertical components

74.9sin(9.46°) + Asin(20.6°) = Bsin(51.3°)

By solving the equation, we get

40.07 = 1.015B

B = 39.5N

By substituting the value of B in equation (1)

A = 78.9 - 0.6668× 39.5

A = 52.5N

Hence, the magnitude of the tension in the string marked A is 52.5N

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Answer:

NE BİLİM

Explanation:

PUAN İÇİN YAZIYORUM SEN BENİ GÖRMEZDEN GEL ANLDIN MI DOSTUM bu arada Suriye >>>>>

The magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

The magnitude of e.m.f induced in the loop is calculated as follows;

emf = dФ/dt

Ф = 6t² + 7t

dФ/dt = 12t + 7

at t = 2 seconds

emf = dФ/dt = 12(2) + 7 = 31 V

Thus,  the magnitude of e.m.f induced in the loop when t = 2 s is 31 Volts.

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Answer:

Explanation:

An electric dipole is formed by two point charges +q and −q connected by a vector a. The electric dipole moment is defined as p = qa

The magnitude of the static friction force = 123 N

The coefficient of static friction = 0.31

Static friction is the frictional force that must be overcome in other for a body to that moving over another.

Since the crate does not move, the magnitude of the static frictional force is equal to the applied force.

The magnitude of the static frictional force = 123 N

The coefficient of static friction = frictional force/normal reaction

The coefficient of static friction = 123/(40* 9.8)

The coefficient of static friction = 0.31

In conclusion, the static frictional force on the on the crate is equal to the applied force on the crate.

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A wave is a phenomenon that does not cause a permanent displacement in the particles of the medium through which it passes. And it transfers energy from one end of the medium to the other. Examples of waves include light waves, sound waves, water waves, x-rays, radiowaves, etc. Thus the required answers for each part of the question are:

a. The angle that the light wave would have is [tex]7.5^{o}[/tex].

b. The type of mirror that can be used is a plane mirror.

c. The image distance is 146.3 cm.

ii. The image formed by the mirror is a real image.

a. When a ray of light passes from one medium to another, then refraction occurs. The refraction depends on the refractive index of the medium considered.

Thus from Snell's law, we have:

refractive index, n, = [tex]\frac{Sin i}{Sin r}[/tex]

where: i is the angle of incidence, and r is the refracted angle.

Now given that n = 1.5, and i = 15.

Then;

n = [tex]\frac{Sin i}{Sin r}[/tex]

1.5 = [tex]\frac{Sin 15}{Sin r}[/tex]

Sin r = [tex]\frac{0.2588}{1.5}[/tex]

        = 0.17253

r = [tex]Sin^{-1}[/tex] 0.17253

  = 9.936

r ≅ [tex]10^{o}[/tex]

Since the light wave now moves from the glass into water, the determined refracted angle now becomes its angle of incidence in water. So that;

n = [tex]\frac{Sin i}{Sin r}[/tex]

1.33 = [tex]\frac{Sin 10}{Sin r}[/tex]

Sin r = [tex]\frac{0.17365}{1.33}[/tex]

       = 0.1306

r = [tex]Sin^{-1}[/tex] 0.1306

 = 7.504

r = [tex]7.5^{o}[/tex]

Therefore, the angle that the light wave would have is [tex]7.5^{o}[/tex].

b. The image formed would be the same size as that of the object. And also the same distance as that of the object to the pole of the lens.

The type of mirror that can be used is a plane mirror.

The ray diagram is attached to this answer.

c. From the mirror formula;

[tex]\frac{1}{f}[/tex] = [tex]\frac{1}{u}[/tex] + [tex]\frac{1}{v}[/tex]

where; f is the focal length of the mirror, u is the object's distance to the mirror, and v is the image's distance to the mirror.

Given; u = 65 cm, and f = 45 cm, then:

[tex]\frac{1}{45}[/tex] = [tex]\frac{1}{65}[/tex] + [tex]\frac{1}{v}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{1}{45}[/tex] -  [tex]\frac{1}{65}[/tex]

[tex]\frac{1}{v}[/tex] = [tex]\frac{20}{2925}[/tex]

v = [tex]\frac{2925}{20}[/tex]

v  = 146.25 cm

The image distance is 146.3 cm.

ii. The image formed by the mirror is a real image.

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The Aster's final position from her initial position is 64 m

The angle is 300° and She has to head in West north direction to return to her initial position

The displacement is the distance travelled in a specific direction. Displacement is a vector quantity.

Given that Aster walks first 70 m in the direction 37° north of east, and then walks 82 m in the direction 20° south of east, and finally walks 28 m in the direction 30° west of north.

This can be solved by using bearing method. Cosine formula will be the best to solve for the distance D.

[tex]D^{2}[/tex] = [tex]70^{2}[/tex] + [tex]82^{2}[/tex] - 70 x 82 x Cos (37 + 20)

[tex]D^{2}[/tex] = 4900 + 6724 - 5740Cos57

[tex]D^{2}[/tex] = 11624 - 3126.23

[tex]D^{2}[/tex] = 8497.8

D = [tex]\sqrt{8497.8}[/tex]

D = 92.2 m

a) The Aster's final position from her initial position is 92.2 - 28 = 64 m

The angle = 270° + 30° = 300°

b) She has to head in West north direction to return to her initial position

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Answer:

11,890

Explanation:

First we need to know what is considered a significant figure.

A significant figure is a value that is not a zero at the start OR end of a value.

Which means, the 0 in the value of 90 or 0.363 are not considered a significant figure.

The 0 in the value of 3056 is considered a significant figure.

So from the table, we can deduce:

0.275 has 3 significant figures

750 has 2 significant figures

[tex]10.4 \times {10}^{5} = 1040000[/tex]

has 3 significant figures.

11,890 has 4 significant figures.

320,050 has 5 significant figures.

So from the above, we can already see the answer.

B. The normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

Fₙ = mg + mv²/r

where;

Fₙ = (2,000 x 9.8) + (2,000 x 18²)/24

Fₙ = 46,600 N

Fₙ =  4.7 x 10⁴ N

Thus, the normal force that is exerted on the coaster by the track at the lowest point is 4.7 x 10⁴ N.

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