How many lone pairs of electrons are in the ion OH⁻?

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Answers

Answer 1

There are 1 lone pairs of electrons are in the ion OH⁻

An OH ion has how many lone pairs?

Since oxygen creates two bonds, we know that two electrons are required to create those two bonds. There are now just two electron pairs remaining that are not involved in bonding. Oxygen thus contains two lone pairs.

Is there a single pair of electrons in OH?

The O and H atoms are connected by a solitary covalent link. The oxygen atom has a net -1 charge, which normally manifests as the whole charge on the OH- ion. On the O atom in the OH- Lewis structure, there exist lone electron pairs.

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Related Questions

Ca(OH)2 + 2HCl = CaCl2 + 2H2O

Go out to 3 decimal places for all values except 0.
In this reaction, 48.5 g of Ca(OH)2 and 32.8 g of HCl:
1) Determine how many moles of each reactant are present at the beginning of the reaction.
2) Convert one of the reactants into moles of the other reactant to determine whether or not it is the limiting reactant.
3) Convert moles of the excess reactant into moles of the product.

Answers

Moles of HCL present in the reaction is 0.899 moles

What is moles?

The mole is the unit of substance that is equal to the number of atoms in 0.012 kilogrammes of carbon 12 and is represented by the sign "mol".

What is reaction?

chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

Use the following formula to calculate the moles of each reactant present at the start of the reaction:

Molar mass divided by mass equals a mole.

The molar mass of HCl is 36.461 g/mol (1.008 g/mol for H and 35.453 g/mol for Cl), while the molar mass of [tex]Ca(OH)_2[/tex] is 74.093 g/mol (40.078 g/mol for Ca, plus 215.999 g/mol for O and 21.008 g/mol for H).

Consequently, the amount of [tex]Ca(OH)_2[/tex] in the starting moles of the reaction is:

[tex]Ca(OH)_2[/tex] moles are equal to 48.5 g / 74.093 g/mol, or 0.654 moles.

At the start of the reaction, there are: moles of HCl present.

32.8 g of HCl divided by 36.461 g/mol yields 0.899 moles.

Since we have only 0.899 moles of HCl present, it is the limiting reactant. This means that all of the [tex]Ca(OH)_2[/tex] will react, and some of the HCl will be left over.

To convert this to grams, we use the formula:

mass = moles x molar mass

The molar mass of [tex]CaCl_2[/tex] is 110.984 g/mol (40.078 g/mol for Ca and 2*35.453 g/mol for Cl).

Therefore, the mass of [tex]CaCl_2[/tex] produced is:

mass of [tex]CaCl_2[/tex] = 0.654 moles x 110.984 g/mol = 72.6 g

So, 48.5 g of [tex]Ca(OH)_2[/tex] and 32.8 g of HCl will produce 72.6 g of [tex]CaCl_2[/tex] and 2 moles of [tex]H_2O[/tex].

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If you have 155 mL solution of a 0.762 mL solution of a 0.762 M FeCl3 solution, how many grams of FeCl3 are contained in this sample?

Answers

Therefore, 19.1558g of FeCl3 F e C l 3 is present in this sample.

Determine the boiling point of a solution prepared by dissolving 119 g ethanol (CH3CH2OH) in 425 g water.

Answers

Answer:

Boiling point of the solution = 103.11 °C.

Explanation:

To determine the boiling point of a solution, we need to use the equation:

ΔTb = Kb · m

where ΔTb is the boiling point elevation, Kb is the boiling point elevation constant for water (0.512 °C/m), and m is the molal concentration of the solute (in mol/kg).

First, we need to calculate the molality of the solution, which is the number of moles of solute per kilogram of solvent. We can use the formula:

molality (m) = moles of solute / mass of solvent in kg

The mass of water is 425 g, which is 0.425 kg. To find the moles of ethanol, we can use the formula:

moles of solute = mass of solute / molar mass of solute

The molar mass of ethanol is 46.07 g/mol, so the moles of ethanol are:

moles of ethanol = 119 g / 46.07 g/mol = 2.58 mol

Therefore, the molality of the solution is:

m = 2.58 mol / 0.425 kg = 6.07 mol/kg

Now we can use the boiling point elevation equation to find ΔTb:

ΔTb = Kb · m
ΔTb = 0.512 °C/m · 6.07 mol/kg
ΔTb = 3.11 °C

The boiling point elevation is 3.11 °C, which means that the boiling point of the solution is higher than the boiling point of pure water. To find the boiling point of the solution, we need to add the boiling point elevation to the boiling point of water at standard pressure (1 atm), which is 100.00 °C. Therefore:

boiling point of solution = 100.00 °C + 3.11 °C = 103.11 °C

So the boiling point of the solution prepared by dissolving 119 g ethanol in 425 g water is 103.11 °C.

Nitric acid is commercially available at a concentration of 15.9 M. What volume of this solution must be diluted to a final volume of 1.00 L to prepare a 4.00 M solution?

Answers

Answer:

V1= 0.252 L

Explanation:

Let V be the volume of the 15.9 M nitric acid solution that needs to be diluted.

According to the dilution formula, the moles of solute before and after dilution are equal. Therefore, we can write:

M1V1 = M2V2

where M1 is the initial concentration (15.9 M), V1 is the initial volume (unknown), M2 is the final concentration (4.00 M), and V2 is the final volume (1.00 L).

Solving for V1, we get:

V1 = (M2V2)/M1
= (4.00 M)(1.00 L)/(15.9 M)
= 0.252 L or 252 mL (rounded to three significant figures)

Therefore, 252 mL of the 15.9 M nitric acid solution must be diluted to a final volume of 1.00 L to prepare a 4.00 M solution.

Device an experiment to study the dependence of rate ov precipitation of sulphur upon the nature of monobasic acid for the reaction between thiosulphate ion and hydrogen ion

Answers

The expected result of the experiment is that the rate of precipitation of sulfur will be faster with hydrogen chloride than with acetic acid.

What is Precipitation?

Precipitation refers to the process in which a substance in a solution comes out of solution and forms a solid. This occurs when the concentration of the substance exceeds its solubility limit in the solution, resulting in the formation of solid particles that settle at the bottom of the solution.

Procedure:

Prepare a series of solutions with different monobasic acids. For example, you can prepare solutions of sodium thiosulphate (Na2S2O3) with different monobasic acids, such as hydrochloric acid (HCl), sulfuric acid (H2SO4), and nitric acid (HNO3), at a constant concentration and volume.

Place equal volumes of the thiosulphate solution and each monobasic acid solution in separate beakers or test tubes.

Start the timer or stopwatch as soon as the two solutions are mixed. The thiosulphate ions will react with the hydrogen ions from the monobasic acid, resulting in the formation of sulphur precipitate according to the following chemical equation:

S2O3^2- + 2H+ -> H2O + S + SO2

Observe the reaction and record the time taken for the formation of sulphur precipitate in each solution.

Compare the rates of precipitation of sulphur for each monobasic acid solution to study the dependence of the rate on the nature of the monobasic acid. Note any trends or differences in the rates of precipitation among the different acids used.

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80.0 grams of potassium sulfate is dissolved in 320 grams of water. Find the percentage concentration

Answers

The percentage concentration of potassium sulfate in the solution is 20%.

What is Percentage Concentration?

Percentage concentration, also known as percent concentration or mass percent, is a measure of the amount of a solute present in a solution, expressed as a percentage of the total mass or volume of the solution. It is commonly used in chemistry and related fields to express the concentration of a solute in a solution.

To find the percentage concentration of potassium sulfate in the solution, we need to calculate the mass of potassium sulfate in the solution and express it as a percentage of the total mass of the solution.

Given:

Mass of potassium sulfate (K2SO4) = 80.0 g

Mass of water (H2O) = 320 g

Total mass of the solution = Mass of potassium sulfate + Mass of water

= 80.0 g + 320 g

= 400 g

Now, we can calculate the percentage concentration of potassium sulfate:

Percentage concentration = (Mass of potassium sulfate / Total mass of the solution) × 100

Percentage concentration = (80.0 g / 400 g) × 100

= 20%

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1. Using a graduated cylinder, measure out 50 mL water (H2O) and pour it in a 100 mL beaker 2. Using a balance, measure out 5 g of glucose (C6H12O6) 3. Pour the 5 g of glucose into the 50 mL of water 4. Stir the contents of the beaker using a glass rod 5. Using tweezers, count out 15 pieces of iron (Fe) filings 6. Add the iron filings to the beaker 7. Stir the contents of the beaker using a glass rod During which step(s) was the student handling a pure substance? Responses A Steps 1 and 3Steps 1 and 3 B Step 4 onlyStep 4 only C Steps 1, 2, and 5Steps 1, 2, and 5 D Steps 6 and 7Steps 6 and 7

Answers

The step during which the student handling pure substance is : B.) Step 4 only.

During which step was the student handling pure substance?

In step 4, student added 5 grams of glucose to 50 mL of water, which is a pure substance. Glucose is a compound with the chemical formula C₆H₁₂O₆, and it is a pure substance because it consists of only one type of molecule.

In steps 1, 2, and 5, student was handling water, glucose, and iron filings respectively, but these are not pure substances in those steps because they are mixed with other substances or impurities.

In steps 6 and 7, the student added iron filings to beaker and stirred the mixture, but iron filings are not pure substance either because they may contain impurities or other metals in addition to iron.

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How many oxygen atoms are in 225 g 02?

Answers

A 225-gram a sample of oxygen contains 84.684375 X 1023 atoms of oxygen.

What do you mean by oxygen, O2?

One oxygen atom, designated O. Two molecules of oxygen combine to form the molecule O2. Our bodies have developed to breathe O2, which is the main component of our atmosphere.

Why is oxygen abbreviated O2?

Because each molecule is made up of two atoms of oxygen fused together, its formula is written as O2.

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Select all answer choices that would result in units of moles.

a) RT/PV
b) PV/RT
c) mass ÷ molar mass
d) molar mass ÷ mass
e) molar mass × mass
f) molarity ÷ volume
g) volume ÷ molarity
h) molarity × volume

Answers

The correct options that will result in mole are option B, C, and H

How do i know which options will result in mole?

To know the options that will result in mole, do the following:

Ideal gas law states as follow:

PV = nRT

Where

P is the pressure V is the volumen is the number of moleR is the gas constantT is the temperature

PV = nRT

Make n the subject by dividing both sides by RT

n = PV / RT (option B)

Mole, mass and molar mass are related according to the following formula:

Mole = mass / molar mass (option C)

Molarity is defined as mole per unit volume as shown below:

Molarity = mole / volume

Make mole the subject by cross multiplying.

Mole = Molarity × volume (option H)

Thus, from the above illustrations, we can conclude that the correct options which will result in mole are option B, C, and H

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A new band sensation is playing a concert and recording it for a live album to be released this summer. Sound waves from singers in the band are displayed in the diagram below.

Answers

Answer:

Wave A (blue wave) has the highest volume because it has the highest amplitude.

Waves B and C have equal volumes because they have the equal amplitude.

Wave C (green wave) has the highest pitch because it has the highest frequency.

Waves A and B have equal pitch because they have the equal frequency.

Which term is best used to classify sodium chloride mixed in water (salt water) at room temperature?

Answers

The term that best classifies sodium chloride mixed in water at room temperature is a homogeneous mixture or solution.

~~~Harsha~~~

Answer:

It is homogeneous

Explanation:

Why C is the correct answer? (the question is:Which of the following compounds are NOT aliphatic hydrocarbons?)

Answers

C is the correct option as it contains oxygen along with carbon and hydrogen. Aliphatic hydrocarbons that have had one or more hydrogen atoms .

Aliphatic hydrocarbons that have had one or more hydrogen atoms replaced by a halogen, such as those that have been fluorinated, chlorinated, brominated, or iodized, are known as halogenated aliphatic hydrocarbons.

The group of chemical molecules known as chlorinated aliphatic hydrocarbons is diverse and is characterised by an open-chain structure or a variable number of bonds, which can be single, double, or triple. C is the correct option as it contains oxygen along with carbon and hydrogen.

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How many moles exist in 6.035 x 10^25 atoms of boron?

Please help

Answers

To determine the number of moles of boron in 6.035 x 10^25 atoms of boron, we need to use Avogadro's number, which is 6.022 x 10^23 particles per mole. We can set up a proportion to solve for the number of moles:

(6.035 x 10^25 atoms) / (6.022 x 10^23 atoms/mol) = x moles

Simplifying the expression on the left side, we get:

x = (6.035 / 6.022) x (10^25 / 10^23) moles

x = 1.002 moles

Therefore, there are 1.002 moles of boron in 6.035 x 10^25 atoms of boron.

The "Ring of Responsibility" requires a next to water bodies. O 50-foot 43 3-foot O 5-foot O 15- to 25-foot untreated buffer zone

Answers

The "Ring of Responsibility" requires a 15- to 25-foot untreated buffer zone next to water bodies.

What is buffer zone?

A buffer zone is an area of land that separates two or more countries, states, or territories, and is often demilitarized. The purpose of a buffer zone is to provide a space for negotiations and to reduce the possibility of conflict and war. Buffer zones can also be used to protect sensitive natural resources or habitats, such as areas of wilderness or wildlife. Buffer zones can be permanent or temporary, and can range in size from a few miles to hundreds of miles. In addition to physical barriers, buffer zones can also include economic, political, and social measures to reduce tensions between two or more parties. Buffer zones are an important tool in international relations, as they can help to prevent armed conflict and promote peaceful resolution of disputes.

This buffer zone is intended to prevent pollutants from entering the water body and protect it from potential environmental damage.

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How many atoms are in 4.5 moles of neon?

How many miles are in 1.2x1023 atoms of silicon?

How many moles are in 3.4x1023 molecules of CH4?

How many moles are in 5.2x1024 atoms of gold?

How many atoms are in 26.2 moles of cobalt?

How many cookies are in 1.2 mole of cookies?

Answers

The atoms of neon are [tex]27.099 *10^{23}[/tex], moles of silicon are 0.1199 , moles of [tex]CH_{4}[/tex] are 0.56, moles of gold are 8.64, atoms of cobalt are [tex]157.7764*10^{23}[/tex] and number of cookies are [tex]7.2264*10^{23}[/tex].

How to calculate atoms?

Multiplying the number of moles with [tex]6.022*10^{23}[/tex] we will get number of atoms of neon.

Number of atoms= [tex]4.5* 6.022 *10^{23}[/tex]

Number of atoms of neon = [tex]27.099 *10^{23}[/tex]

Moles of silicon?