Mathematics High School

I Need help on number 15 pls

Answers

Answer 1

Using the fact that the figures are similar, we will get z = 4.

How to find the value of z?

We know that the two figures are similar, then the correspondent quotients between sides must be equal.

That means that we can write the equation:

10/15 = z/6

And we can solve that equation for z, we will get:

z = 6*(10/15) = 4

That is the value of z.

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Related Questions

the usual price of a bag of oranges was $4. during a promotion, two bags of oranges were sold for $5.99. find the percentage decrease in the price of the two bags of oranges. give your answer correct to 1 decimal place.

Answers

The percentage decrease in the price of the two bags of oranges is 25.1 %.

We have been told that the usual price of a bag of oranges was $4 and during the promotion, it became $5.99 for two bags of oranges. We need to find the percentage decrease here.

We can calculate that two bags before the promotion cost = $4 × 2 = $8

As we already know, the two bags during the promotion cost = $5.99

The decrease in price can be calculated as well = $8 - $5.99 = $2.01

Percentage decrease = ($2.01 / $8) * 100 %

Percentage decrease = 25.1 %

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NEED HELP ASAP:In the year 2000, a person bought a new car for $15000. For each consecutive year
after that, the value of the car depreciated by 11%. How much would the car be worth
in the year 2004, to the nearest hundred dollars?

Answers

The car would be worth $9400 in the year 2004.

How to determine the worth of the car?

If the car depreciates by 11% each year, then its value at the end of each year will be 89% of its value at the beginning of the year (100% - 11% = 89%). Therefore, the value of the car after 1 year will be:

$15000 * 0.89 = $13350

The value of the car after 2 years will be:

$13350 * 0.89 = $11881.50

The value of the car after 3 years will be:

$11881.50 * 0.89 = $10576.77

The value of the car after 4 years (in the year 2004) will be:

$10576.77 * 0.89 = $9422.19

Therefore, the car would be worth $9400 in the year 2004.

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Toby goes on holiday to Geneva, Switzerland. In Geneva, Toby sees a watch costing 193. 75 CHF (Swiss Francs). In Manchester, an identical watch costs £145. Given that £1 = 1. 55 CHF
a) In which city is the watch cheaper?
b) By how much is it cheaper (in £)?

Answers

The watch is cheaper in Geneva. The watch is cheaper in Geneva by 20 pounds.

To answer this question, we will need to convert the price of the watch in Geneva to pounds and compare it to the price of the watch in Manchester.

First, let's convert the price of the watch in Geneva from CHF to pounds:

193.75 CHF ÷ 1.55 CHF/£ = 125 pounds

Now, we can compare the price of the watch in Geneva to the price of the watch in Manchester:

125 pounds (Geneva) < 145 pounds (Manchester)

Therefore, the watch is cheaper in Geneva.

To find out by how much it is cheaper, we can subtract the price of the watch in Geneva from the price of the watch in Manchester:

145 pounds - 125 pounds = 20 pounds

So, the watch is 20 pounds cheaper in Geneva.

In conclusion, the watch is cheaper in Geneva by 20 pounds.

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