I NEED HELP ON THIS ASAP!!!

We can use a normal probability model to represent the distribution of sample means when the sample size is large enough to ensure that sample means will be normally distributed, option (C) is correct.

The central limit theorem (CLT) states that when sample sizes are sufficiently large (typically, n > 30), the distribution of sample means will be approximately normal, regardless of the distribution of the variable in the population.

This is because as the probability of sample size increases, the sample mean becomes a more reliable estimate of the population mean, and the variability in the sample means decreases. This results in a distribution that is bell-shaped and symmetric, similar to a normal distribution, option (C) is correct.

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– The question is inappropriate, The correct question is:

We can use a normal probability model to represent the distribution of sample means for which of the following reasons? check all that apply.

A) the sample is randomly selected

B) the distribution of the variable in the population is normally distributed

C) the sample size is large enough to ensure that sample means will be normally distributed flag –

Answer:

s=3

Step-by-step explanation:

Equation: s=(50-44)/2

First, do the operation(s) in parenthesis:

s=(50-44)/2

s=(6)/2

Next, do the division, since it's the last operation:

s=6/2

s=3

So, your answer is s=3

From the given dimensions, area of the figure is approximately equal to 75.8 cm².

A regular polygon is a closed shape with straight sides and equal-length edges, as well as equal angles between those sides. Examples of regular polygons include equilateral triangles, squares, and hexagons. The number of sides a regular polygon has is referred to as its order, while the measure of each interior angle of a regular polygon can be calculated using the formula (n-2) x 180/n, where n represents the number of sides.

From the image we can see that, ABHI is a square with sides 6 cm, BCDGH is a regular pentagon with sides 6 cm (BH = AI = 6 cm) and DEFG is a rectangle with length 11 cm and breadth 6 cm ( DG = AI = 6 cm).

To find the area of the figure we have to find the area of each shape and add it together.

Area of square = side × side = 6 × 6 = 36 cm²

Area of regular pentagon = [tex]\frac{1}{4} \sqrt{5(5+25)a^{2} }[/tex]

= [tex]\frac{1}{4} \sqrt{5(5+25)6^{2} }[/tex]

= [tex]\frac{1}{4} \sqrt{25 + 10*1.41*36}[/tex]

= [tex]\frac{1}{4} \sqrt{532.6 }[/tex]

≈ 5.77 cm²

Area of rectangle = 2(l + b) = 2(11 + 6) = 34 cm²

Therefore area of the figure = 36 cm² + 5.77 cm² + 34 cm² ≈ 75.8 cm².

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Answer:

y = [tex]\frac{1}{3}[/tex]x

Step-by-step explanation:

As y increases by 1, x increases by 3.

Helping in the name of Jesus.

The series can be represented in summation notation as follows: ∑(n = 7 to 207) (4n - 1)

In this notation, the Greek letter sigma (∑) represents the summation symbol, and n represents the index of summation. The series starts from n = 7 and goes up to n = 207, with each term being (4n - 1). The notation "n = 7 to 207" indicates the range of values that n takes on in the summation. The expression (4n - 1) represents the general term in the series, which changes as n varies from 7 to 207.

Summation notation, denoted by the Greek letter sigma (∑), is a shorthand way to represent the sum of a sequence of numbers. In this case, the series you provided is:

7 + 11 + 15 + … + 203 + 207

The general term of the series, which changes as "n" varies, is (4n - 1). This means that for each value of "n", we substitute it into the expression (4n - 1) to get the corresponding term in the series. For example, when "n" is 7, the corresponding term is (4 * 7 - 1) = 27. When "n" is 11, the corresponding term is (4 * 11 - 1) = 43, and so on, up to "n" = 207.

The summation notation "∑(n = 7 to 207) (4n - 1)" represents the sum of all the terms in the series, where "n" takes on values from 7 to 207, and the term for each "n" is (4n - 1). This notation allows us to compactly represent the entire series in a concise mathematical form.

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a.

the value of s that yields the coordinate (2, 0) is 2.

b.

the value of s that yields the coordinate (9, 1) is estimated 9.055.

we  use the distance formula between the origin and point P on the path:

d(P) = √ (x^2 + y^2) = s

For the coordinate (2, 0), we have x = 2 and y = 0. So, we can plug these values into the distance formula and solve for s:

d(P) = √(x^2 + y^2)

= √t(2^2 + 0^2) = 2

For the coordinate (9, 1), we have x = 9 and y = 1. So, we can plug these values into the distance formula and solve for s:

d(P) = √t(x^2 + y^2)

= √t(9^2 + 1^2)

= √(82)

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a) Given statement: skipped : I'm not sure what statement you're referring to, as there is no statement labeled "a" in  question.

Hence answer provided.

b) As the degrees of freedom increase, the t distribution curve does become more similar to the standard normal curve.

True. Because the t distribution resembles the normal distribution when the degrees of freedom are high.

c) The two mean non-pooled test is used for 2 independent populations under the assumption that the two populations have different standard deviations.

False - Because the non-pooled t-test can be used to compare the means of the two populations when the assumption of equal variances is true.

d) The standard error is the standard deviation of the sampling distribution and is calculated by dividing the sample standard deviation by the square root of the sample size.

False - Because the standard error, which is determined as the sample standard deviation divided by the square root of the sample size, is a measure of the variability of the sample mean.

a)  Given statement: skipped : I'm not sure what statement you're referring to, as there is no statement labeled "a" in  question.
b) Given statement : As the degrees of freedom increase, the t distribution curve does become more similar to the standard normal curve.

The given statement is true.

Because, When the degrees of freedom are large, the t distribution approaches the standard normal distribution.
c) Given statement: The two mean non-pooled test is used for 2 independent populations under the assumption that the two populations share the same standard deviation.

The given statement is true.

Because, When the assumption of equal variances is met, the non-pooled t-test can be used to compare the means of the two populations.
d)  Given statement: The standard error is not always equal to the sample standard deviation.  

The given statement false.

Because, The standard error is a measure of the variability of the sample mean, and it is calculated as the sample standard deviation divided by the square root of the sample size.

The sample standard deviation is a measure of the variability within the sample itself.

The standard error tends to be smaller than the sample standard deviation because it accounts for the effect of the sample size on the variability of the sample mean.

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The femur length for someone with a height of 187 cm is; 55 cm

The formula for the equation of a line formed by 2 coordinates is;

(y2 - y1)/(x2 - x1) = (y - y1)/(x - x1)

Using the coordinates (30, 127) and (35, 139), we have;

(139 - 127)/(35 - 30) = (y - 127)/(x - 30)

12/5 = (y - 127)/(x - 30)

12(x - 30) = 5(y - 127)

12x - 360 = 5y - 635

5y = 12x + 275

Thus, when the height is y = 187 cm, we have;

5(187) = 12x + 275

935 = 12x + 275

12x = 935 - 275

12x = 660

x = 660/12

x = 55 cm

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The domain and the range of the function are given as follows:

The values of x of the function are from an open circle at x = -6 to a closed circle at x = 1, hence the domain is given as follows:

(-6, 1].

The minimum value of the function is y = -2, while the maximum value is an open circle at y = 4, hence the range of the function is given as follows:

[-2, 4).

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The inequality to represent the possible number of hours Kat can afford to book the DJ is 80x + 225 ≤ 970 and one possible length Kat can afford to book the DJ is 9 hours.

(a) Let x be the number of hours that Kat can book the DJ. Then, the total cost of the DJ is 80x, and the total cost of the party is 80x + 225.

Since Kat has $410 saved and will earn another $560, the total amount she can spend on the party is $410 + $560 = $970.

Therefore, we can write the following inequality to represent the possible number of hours Kat can afford to book the DJ:

80x + 225 ≤ 970

b) To solve for x, we can start by subtracting 225 from both sides of the inequality:

80x ≤ 745

Then, we can divide both sides by 80:

x ≤ 9.3125

Since Kat can only book the DJ in whole hours, the largest integer less than or equal to 9.3125 is 9. Therefore, one possible length Kat can afford to book the DJ is 9 hours.

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According to the concept of inequality, the maximum value of A is obtained when a = 2 and c = 28.

Let's assume that each minute of advertising attracts 40,000 viewers and each minute of comedy attracts 45,000 viewers. Therefore, the total audience (in thousands) that can be reached is given by:

A = 40a + 45c

Firstly, we know that the total time allotted for advertising and comedy cannot exceed 30 minutes. Therefore, we can rewrite the inequality as:

a + c ≤ 30

Solving for c, we get:

c ≤ 30 - a

Now, we can substitute this expression for c in the equation for A:

A = 40a + 45c

A = 40a + 45(30 - a)

A = 1350 - 5a

To maximize A, we need to find the value of a that will result in the maximum value of A. Taking the derivative of A with respect to a and setting it equal to zero, we get:

dA/da = -5 = 0

a = 0

This does not make sense, as a cannot be zero. Therefore, we need to check the endpoints of the interval [2,4] to see if they give a maximum value for A.

When a = 2, we get:

A = 40(2) + 45c

A = 80 + 45c

Substituting c = 30 - a, we get:

A = 80 + 45(30 - 2)

A = 80 + 1350

A = 1430

When a = 4, we get:

A = 40(4) + 45c

A = 160 + 45c

Substituting c = 30 - a, we get:

A = 160 + 45(30 - 4)

A = 160 + 1215

A = 1375

This means that the producer should allocate 2 minutes for advertising and 28 minutes for the comedy program in order to maximize the number of viewers.

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The absolute maximum value of g(x) on the interval [-4,1] is approximately 4.4817, which occurs at x = 1.

To find the absolute maximum value of g(x) on the interval [-4,1], we need to evaluate the function at both the endpoints and at any critical points inside the interval, and then compare the values to determine the maximum.

First, let's evaluate g(x) at the endpoints of the interval

g(-4) = (-4² + 4 + 1)e^(-4) ≈ 0.00064

g(1) = (1² - 1 + 1)e^1 ≈ 4.4817

Next, we need to find any critical points of g(x) inside the interval. To do this, we take the derivative of g(x) and set it equal to zero

g'(x) = (2x - 1 + (x² - x + 1))e^x = (x² + x - 1)e^x

Setting g'(x) = 0, we get

x² + x - 1 = 0

Using the quadratic formula, we get

x = (-1 ± sqrt(5))/2

Both of these critical points, approximately -1.618 and 0.618, are inside the interval [-4,1], so we need to evaluate g(x) at these points as well:

g(-1.618) ≈ 0.4963

g(0.618) ≈ 2.5305

Now we can compare the values of g(x) at the endpoints and critical points to determine the absolute maximum

g(-4) ≈ 0.00064

g(-1.618) ≈ 0.4963

g(0.618) ≈ 2.5305

g(1) ≈ 4.4817

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The given question is incomplete, the complete question is:

Let g be the function defined by g(x)=(x²- x+1)e^x. What is the absolute maximum value of g on the interval [-4,1] ?

Answer: (a) Let the circle roll along the x-axis with the center at the origin. Then, the parametric equations of the cycloid are given by:

x = t - sin(t)

y = 1 - cos(t)

where t is the angle in radians that the circle has rotated from its initial position.

(b) The arclength of one period of the cycloid is given by the integral:

L = ∫(0,2π) √[dx/dt]^2 + [dy/dt]^2 dt

Substituting the parametric equations from part (a), we get:

dx/dt = 1 - cos(t)

dy/dt = sin(t)

Therefore,

[dx/dt]^2 + [dy/dt]^2 = 2 - 2cos(t)

Substituting back into the arclength integral, we get:

L = ∫(0,2π) √(2 - 2cos(t)) dt

This integral can be evaluated using the half-angle formula:

cos(t) = 1 - 2sin^2(t/2)

Substituting this into the integral and simplifying, we get:

L = 8∫(0,π/2) √(sin^3(t/2)) dt

This integral can be evaluated using a substitution u = cos(t/2), du = -sin(t/2)dt:

L = 16∫(0,1) √[(1-u^2)^3] du

This integral can be further simplified by making the substitution u = sin(θ):

L = 16∫(0,π/2) cos^4(θ) dθ

This integral can be evaluated using integration by parts and trigonometric identities. After some algebraic manipulations, we get:

L = 8π

Step-by-step explanation:

a) The conjugate of the denominator is given as follows: 2 - 14i.

b) The division has the result given as follows: 0.375 - 1.15i.

A complex number is a number that is composed by a real part and an imaginary part, as follows:

z = a + bi.

In which:

The division for this problem is given as follows:

(16 - 3i)/(2 + 14i).

For the conjugate of the denominator, we keep the real part, changing the sign of the imaginary part, hence it is given as follows:

2 - 14i.

Hence we can solve the division multiplying by the conjugate, considering that i² = -1, as follows:

(16 - 3i)/(2 + 14i) x (2 - 14i)/(2 - 14i) = (32 - 224i - 6i + 42)/(4 + 196)

(16 - 3i)/(2 + 14i) x (2 - 14i)/(2 - 14i) = (74 - 230i)/200

(16 - 3i)/(2 + 14i) x (2 - 14i)/(2 - 14i) = 0.375 - 1.15i.

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The values of a, h, and k are 5, -6 and -2, respectively

In the given function:

y = 5/(x+6) - 2

The function is in the form of a rational function, f(x) = a/(x-h) + k, where a = 5, h = -6, and k = -2.

Therefore, the values of a, h, and k are:

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By simplifying the given square root , we get Simplified Root : 6 xz • [tex]\sqrt{(2xz) }[/tex]

Factor 72 into its prime factors

          72 = 23 • 32

To simplify a square root, we extract factors which are squares, i.e., factors that are raised to an even exponent.

Factors which will be extracted are :

          36 = 22 • 32

Factors which will remain inside the root are :

          2 = 2

To complete this part of the simplification we take the square root of the factors which are to be extracted. We do this by dividing their exponents by 2 :

          6 = 2 • 3

At the end of this step the partly simplified square root looks like this:

        6 • [tex]\sqrt{ (2x3z3) }[/tex]

Simplify the Variable part of the square root

Rules for simplifing variables which may be raised to a power:

  (1) variables with no exponent stay inside the radical

  (2) variables raised to power 1 or (-1) stay inside the radical

  (3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples:

   [tex]\sqrt{(x8)}[/tex]=x4

 [tex]\sqrt{ (x^6)}[/tex]=x-3

   (4) variables raised to an odd exponent which is  >2  or  <(-2) , examples:

   [tex]\sqrt{ (x5)}[/tex]=x2•[tex]\sqrt{x}[/tex]

  [tex]\sqrt{ (x^7)}[/tex]=x-3•[tex]\sqrt{x}[/tex]

Applying these rules to our case we find out that

[tex]\sqrt{ (x3z3)}[/tex] = xz • [tex]\sqrt{(xz) }[/tex]

Combine both simplifications

      [tex]\sqrt{ (72x3z3)}[/tex] = 6 xz •[tex]\sqrt{(2xz) }[/tex]

Simplified Root :

6 xz • [tex]\sqrt{(2xz) }[/tex]

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The area of the parallelogram is 30 square inch.

A parallelogram is simply a quadrilateral with two pairs of parallel sides.

The area of parallelogram is expressed as:

A = base × height

From the diagram:

Plug the given values into the above equation and solve for area.

Area = base × height

Area = 10 in × 3 in

Area = 30 in²

Therefore, the area is 30 in².

Option D) 30 in² is the correct answer.

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The expected return on the market portfolio is 15.46.

To calculate the expected return on the market portfolio, we can use the Capital Asset Pricing Model (CAPM) formula, which is: Expected Return = Risk-free rate + Beta * (Market return - Risk-free rate)

In this case, the risk-free rate is given as 7% (treasury bills yield), and the beta of the stock is 1.3. We are also given the expected return on the stock as 18%.

Substituting these values into the CAPM formula, we get:

18% = 7% + 1.3 * (Market return - 7%)

Simplifying the equation, we get:

Market return - 7% = (18% - 7%) / 1.3

Market return - 7% = 8.46%

Market return = 7% + 8.46%

Market return = 15.46%

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The center of mass of the thin plate  of density delta = 6 bounded by the lines y = x and x = 0 and the parabola  is located at (x, y) = (4/15, 1/15).

To find the center of mass of a thin plate,

Calculate the moments and products of inertia with respect to the x and y axes,

And then use them to find the coordinates of the center of mass.

First, determine the limits of integration.

Since the plate is bounded by the lines y=x and x=0 and the parabola y=20-x² in the first quadrant,

Integrate over the following limits.

0 ≤ x ≤ 4, and

x ≤ y ≤ 20 - x²

The mass of the plate can be found by integrating the density delta = 6 over the plate.

m = ∫∫over R δ dA

   = ∫∫over R 6 dA

where R is the region bounded by the given curves.

m =[tex]\int_{0}^{4}[/tex] ∫x²⁰⁻ˣ² 6 dy dx

Simplifying the limits, we get,

m = ∫0⁴ 6x(20-x²) dx

Evaluating this integral gives,

m = 960

Next, find the moments and products of inertia.

The moments of inertia are given by,

Ix = ∫∫over R y² δ dA, and

Iy = ∫∫over R x² δ dA

The product of inertia is given by,

Ixy = ∫∫ over R xy δ dA

Substituting the given density delta = 6 and integrating over the region R, we get,

Ix = [tex]\int_{0}^{4}[/tex] ∫x²⁰⁻ˣ² y² 6 dy dx

  = 64/3

Iy = [tex]\int_{0}^{4}[/tex] ∫x²⁰⁻ˣ² x² 6 dy dx

  = 512/15

Ixy = [tex]\int_{0}^{4}[/tex] ∫x²⁰⁻ˣ²  xy 6 dy dx

    = 64/3

Using these moments and products of inertia,

The coordinates of the center of mass (X, Y) can be found using the following formulas.

X = Iy / m, and

Y= Iy / m

Substituting the values we have calculated, we get,

X = (512/15) / 960

  = 4/15

Y = (64/3) / 960

   = 1/15

Therefore, the center of mass of the thin plate is located at (x, y) = (4/15, 1/15).

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The retailer would pay $1,339.20 for 30 dozen work gloves.

One dozen is equal to 12, so 30 dozen would be equal to 360 gloves.

The wholesaler's list price for one dozen gloves is $62.

The discount given by the wholesaler is 28%

The retailer pays 100% - 28% = 72% of the list price.

The price the retailer pays for one dozen gloves is:

$62 x 0.72 = $44.64

Therefore, the price the retailer pays for 30 dozen gloves is:

$44.64 x 30 = $1,339.20

So the retailer would pay $1,339.20 for 30 dozen work gloves.

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Answer:

Usemos la variable s para representar la cantidad de CD que tiene Sonya.

Luego, dado que Dana tiene 1/5 de la cantidad que tiene Sonya, podemos escribir la siguiente ecuación y resolverla para s:

1 s = 9

5

Multiplica ambos lados de la ecuación por 5 para resolver:

5 * 1 s = 9 * 5

    5

s = 45

Sonya tiene 45 CD.

The probability of exactly 2 defective bulbs in a sample of 3 bulbs chosen with replacement from the bin is 0.288 or approximately 28.8%.

To solve this problem, we can use the binomial probability distribution formula:

P(X=k) = (n choose k) * p^k * (1-p)^(n-k)

Where P(X=k) is the probability of getting exactly k successes, n is the total number of trials, p is the probability of success in each trial, and (n choose k) is the binomial coefficient, which represents the number of ways to choose k items from a set of n items.

In this case, n = 3 (because we are choosing 3 bulbs), p = 4/10 = 0.4 (because the probability of choosing a defective bulb is 4 out of 10), and we want to find P(X=2) (the probability of getting exactly 2 defective bulbs).

Substituting these values into the formula gives:\

P(X=2) = (3 choose 2) * 0.4^2 * (1-0.4)^(3-2)

= 3 * 0.16 * 0.6

= 0.288

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Answer:

$2,611.9.

Step-by-step explanation:

To find the operating cost for the lowest 2% of the airplanes, we need to find the corresponding z-score from the standard normal distribution using a z-table.

Using the formula:

z = (x - μ) / σ

where x is the cost we are interested in, μ is the mean cost, and σ is the standard deviation.

For the lowest 2% of airplanes, the z-score can be found by looking up the area to the left of z in the z-table. This area is 0.02.

Looking up 0.02 in the z-table gives a z-score of approximately -2.05.

So we have:

-2.05 = (x - 3403) / 398

Solving for x, we get:

x = -2.05 * 398 + 3403 = $2,611.9

Therefore, the operating cost for the lowest 2% of the airplanes is approximately $2,611.9.

The value of x is given as follows:

x = 12.25

Similar triangles are triangles that share these two features listed as follows:

The proportional relationship for the side lengths in this problem is given as follows:

x/7 = 3.5/2

Applying cross multiplication, the value of x is obtained as follows:

2x = 7 x 3.5

x = 7 x 3.5/2

x = 12.25.

The triangle is given by the image presented at the end of the answer.

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Applying the inscribed angle theorem, the value of x is calculated as: 47 degrees.

If an inscribed angle intercepts an arc in a circle, according to the inscribed angle theorem, we have:

measure of inscribed angle = 1/2(measure of intercepted arc) or 1/2(measure of central angle)

x is an inscribed angle, while 94 degrees is a central angle. Therefore, we have:

x = 1/2(94)

x = 47 degrees.

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Using trigonometric functions, we can find the value of w to be = 9.688cm.

The right triangle's angle serves as the domain input value for the six fundamental trigonometric operations, which return a range of numbers as their output. The angle, expressed in degrees or radians, is the domain of the trigonometric function of f(x) = sin, also referred to as the "trig function," and its range is [-1, 1]. In terms of their domain and scope, the other functions are comparable. Algebra, geometry, and calculus all make extensive use of trigonometric functions.

Here in the question,

We have a right-angled triangle.

Basse of the triangle = 8√3cm.

It's an isosceles triangle.

So, cos45° = w/8√3

⇒ 0.70 = w/8√3

Cross multiplying:

⇒ w = 0.70 × 8√3

⇒ w = 9.688 cm.

Therefore, the measure of the length of the side w = 9.688cm.

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The total area of the rectangle and the two right-angled triangles is 50 square units.

What is meant by area?

Area refers to the measurement of the size or extent of a two-dimensional surface or shape. It is usually expressed in square units, such as square meters or square feet.

What is meant by a rectangle?

A rectangle is a four-sided polygon with two pairs of parallel sides and four right angles. The opposite sides of a rectangle are equal in length, and the area can be calculated as length x width.

According to the given information

Area of rectangle = h * x

Area of one right-angled triangle = (1/2) * h * y

Total area of two right-angled triangles = 2 * (1/2) * h * y = h * y

Adding the area of the rectangle and the area of the triangles, we get the total area:

Total area = Area of rectangle + Total area of two right-angled triangles

Substituting the given values, we get:

Total area = (5 * 4) + (5 * 6)

Total area = 20 + 30

Total area = 50 square units

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the values of $a$ and $b$,is So, $b - a = 6$.using the smallest and largest integers within this interval. Since "integer" refers to whole numbers (both positive and negative), we can identify $a$ and $b$

let's first solve the given inequality $x^2 - 15 < 2x$. We can rewrite this inequality by moving all terms to one side:

$x^2 - 2x - 15 < 0$

Now, we want to factor the quadratic:

$(x - 5)(x + 3) < 0$

From this factored form, we can see that the quadratic changes sign at x = -3 and x = 5. This means the inequality holds between these values:

-3 < x < 5

Now, we want to find the smallest and largest integers within this interval. Since "integer" refers to whole numbers (both positive and negative), we can identify $a$ and $b$ as follows:

$a = -2$ (the smallest integer greater than -3)
$b = 4$ (the largest integer less than 5)

Finally, we need to find the difference $b - a$:

$b - a = 4 - (-2) = 4 + 2 = 6$

So, $b - a = 6$.

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Answer:

100

Step-by-step explanation:

2 x [(7)^2+1]

2x(49+1)

2x(50)

100