I really need help on this!

Therefore , we may now say that the requisite unequal declaration is 4.50x+1.75y 50 if the expression problem is resolved.

In mathematics, an expression is made up of a claim, two or more integers or variables, and one or more arithmetic operations. This mathematical operation can multiply, divide, add, or remove numbers. The following is how an expression is put together: Expression: A variable or a number, a math operator, and a math operator.

Here,

$4.50 is the price per assignment.

The assignment cost "x" is equivalent to 4.50x as a result.

$1.75 for each task.

Therefore, the cost of assignment "Y" is 1.75Y.

Because of this, 4.50x+1.75y should be $50 maybe less.

As a result, the inequality declaration required is 4.50x+1.75y ≤50.

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Answer:

the missing side is 29 so point D or bubble 2

Step-by-step explanation:

use the formula a^2 + b^2 = c^2

20^2 + 21^2 = ?^2 find the answer for the squared values

400 + 441 = ?^2 Add the values

841 = ?^2 in order to get rid of the power square root on both sides

_/- 841 = ? solve

29 = ?

The range of y=2x^(2)+12x-13 is all real number Option C

Generally, A quadratic function is a type of polynomial function that has the form

f(x) = ax^2 + bx + c,

where

a, b, and c are constants and x is the variable.

The graph of a quadratic function is a parabola that opens either upward or downward, depending on the value of a. The vertex of the parabola is the point (h, k), where h = -b/2a and k = f(h). The roots of the quadratic function, or the x-coordinates of the points where the parabola crosses the x-axis, can be found using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a.

The range of a quadratic function in the form of y = ax^(2) + bx + c is all real numbers for a ≠ 0, and for a = 0,

the range is {c}. In this case, a = 2, so the range of y = 2x^(2) + 12x - 13 is all real numbers.

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The range of the given quadratic equation is y ≤ 5.

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function, the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

For solving a quadratic function you should find the discriminant: Δ=b²-4ac . And after that, you should apply the discriminant in the formula:[tex]x=\frac{-b\pm\sqrt{\Delta} }{2a}[/tex] .

The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.  While the domain is related to the values ​​of x, the range is related to the possible values ​​of y that the function can have.

For a quadratic function,  the range is defined from the y-coordinate of the vertex  ( [tex]y_v=\frac{-\Delta}{4a}[/tex]).

If a<0, the range is y≤ yv

If a>0, the range is y≥ yv

The question gives the following quadratic equation: -2x²+12x-13, then:

a=-2

b=12

c=-13

Δ= b²-4ac=12²-4*(-2)*(-13)=144-104=40

Therefore,

[tex]y_v=\frac{-\Delta}{4a}=\frac{-40}{4*(-2)}=\frac{-40}{-8}=5[/tex]

Thus, yv=5 and the range is ≤ 5.

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Sophie plotted the point in the coordinate plane: (1, 1), (–5, 1), (–3, 5),      (–1, 5) so, when the vertices are connected the shape formed is a rectangle.

The internal angles of a rectangle, which has four sides, are all exactly 90 degrees. At each corner or vertex, the two sides come together at a straight angle. The rectangle differs from a square because its two opposite sides are of equal length.

A rectangle is a type of quadrilateral that has its parallel sides equal to each other and all four vertices are equal to 90 degrees. Hence, it is also called an equiangular quadrilateral.

Thus, when Sophie plotted the point in the coordinate plane: (1, 1), (–5, 1),  (–3, 5), (–1, 5), the vertices connected form the shape of a rectangle.

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The numbers in the ascending order is given by A , where

-73 < -21 < -6 1/2 < -4.7 < 0 < 8 8/9 < 11 < 13 < 38

When numbers are arranged in ascending order, they are done so from least to largest. We must first compare the numbers before we may arrange them in any order. Compare first, then order. Numbers arranged in ascending order: Determine how many digits each number has.

Given data ,

Let the set of numbers be represented as set P

The value of set P is P = { -4.7 , 11 , 13 , -21 , 8 8/9 , 0 , -6 1/2 , 38 , -73 }

On simplifying the equation , we get

The larger the negative number , the lesser is its value

And , larger the positive number , the greater is its value

So ,

The ascending order of the numbers are

-73 < -21 < -6 1/2 < -4.7 < 0 < 8 8/9 < 11 < 13 < 38

Hence ,

The ascending order is -73 < -21 < -6 1/2 < -4.7 < 0 < 8 8/9 < 11 < 13 < 38

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To obtain the equation 2x² + 3xy from x² xy y², you would need to add 1x² and 2xy to the original equation.

In order to obtain the equation 2x² + 3xy from x² xy y², you must add some terms to the original equation. The equation 2x² + 3xy represents a polynomial of degree 2, with x² and xy as the leading terms.

The original equation, x² xy y², is also a polynomial of degree 2, but it does not have the same leading terms as the desired equation.

By adding terms to the original equation, we can change the coefficients of the leading terms to match those of the desired equation. In this case, we need to add 1x² and 2xy to the original equation.

This can be simplified as x² + xy + y² + x² + 2xy = 2x² + 3xy. The polynomial x² and 2xy should be added to x² xy y² to get 2x² + 3xy.

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In some fields, a good R-Squared reading could be required to meet criteria of 0.9 or above. An R-Squared value above 0.7 is typically regarded as indicating a high level of correlation in the financial industry, whilst a value below 0.4 would indicate a low level of correlation.

What Exactly Is Residual Value?

The estimated value of an asset that is fixed at the end of its useful life or lease term is its residual value, which is often referred to as salvage value. In lease agreements, the residual value is one of the lessor's main methodologies for calculating the lessee's periodic lease payments.

A good residual value is what?

Check out the Car Lease Ratings section of our Lease Kit for a complete list of high-residual vehicle brands and models.

                  A car is probably not a good lease deal if the lease-end residual value is less than 50% of the MSRP (for a 36-month lease). 55% to 65% of MSRP would be a nice residual.

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Answer:

Volume: 197.92

Formula: π r² h

Step-by-step explanation:

Using synthetic division, the value of the remainder comes out to be -9.

What is synthetic division?

When the divisor is a linear factor, synthetic division is a technique used to carry out the division operation on polynomials. The ability to compute without writing variables when doing polynomial division with the synthetic division makes it an easier technique than the classic lengthy method, which is one of its advantages over the latter.

Two polynomials can be divided using the formula:

p(x)/q(x) = Q(x) + R/(q(x))

where,

The dividend is p(x).

The linear divisor is q(x).

The quotient is Q(x).

The remainder is R

Given expression is [tex]4x^{4} -3x^{3} +6x-10[/tex]

We have to divide this expression by (x + 1) by using synthetic division.

Expression given above can be written as,

4x⁴ - 3x³ + 6x - 10 = 4x⁴ - 3.x³ - 0.x² + 6x - 10

Now on dividing by x = -1 by synthetic division method, we get

-1 |  4     -3     0      6     -10

      -    -4      7     -7       1    

     4    -7      7     -1      -9    

Remainder of the synthetic division will be -9.

Hence, we rewrite the given expression as, [tex]4x^{3} -7x^{2} +7x+1 -\frac{9}{x-9}[/tex]

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A perpendicular bisector is a line that intersects a segment of a line at its midpoint, forming two equal segments.

To construct a perpendicular bisector of a line segment in class 9, the following steps should be followed:

1. Draw the line segment and mark the midpoint of the segment.

2. Take a compass and place the point at the midpoint of the line segment.

3. Adjust the width of the compass such that it is slightly greater than half the length of the line segment.

4. Make an arc above and below the line segment.

5. Draw a line through the two points of intersection of the arc and the line segment. This line is the perpendicular bisector of the line segment.

The formula for the perpendicular bisector is (x - x1) / (x2 - x1) = (y - y1) / (y2 - y1), where (x1, y1) and (x2, y2) are the coordinates of points on the line segment.

To calculate the perpendicular bisector of the line segment:

1. Calculate the midpoint of the line segment using the midpoint formula (x1 + x2) / 2 and (y1 + y2) / 2.

2. Substitute the coordinates of the midpoint and the endpoints into the perpendicular bisector formula.

3. Solve the equation to find the equation of the perpendicular bisector.

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An equation that represents the line is Y is (-4/3)x+2 is the solution.

Y = mx+b, where m is the slope and b is the y-intercept, is the formula for a line's slope-intercept (the point on the y-axis where the line crosses it). Replace m with the value you determined for your slope. In our case, the formula might be written as y = 1x+b or y = x+b if the slope value were substituted.

y=(-4/3)

We have two points since x+2 = -1.33x+2:

(3) and (2) are calculated from the graph.

We are aware that the line's equation is

y=mx+b

m=slope

m=(y2-y1)/(x2-x1)

m=(2-(-2))/(0-3)

therefore the slope is what we have

m=4/-3

m=-4/3

-4/3=-1.3333

We must track down "b"

using the example (0,2)

There are

2=m*0+b

2=b

Finally, here is

Y=(-4/3)x+2 is the solution.

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Writing 5/x + 1 + 2/3x as a single fraction will result to (17 + 3x)/3x

The expression is written with parameters having unlike terns. The terms consist of the constant term and the variable parameters.

The constant terms are 1

terms with variables are 5/x and 2/3x

adding like terms gives

= 5/x + 2/3x

the LCM of x and 3x is 3x and this will be the common denominator

= (15 + 2) / 3x

= 17/3x

adding both together

= 17/3x + 1

the LCM of 1 and 3x is 3x and this will be the common denominator

= (17 + 3x) / 3x

The single fraction is (17 + 3x) / 3x

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the perimeter of the sector is not greater than 47.5.

The perimeter of a form is the space surrounding its edge. Find the perimeter of various forms by summing the lengths of their sides.

Given,  a sector of a circle radius of 11 cm angle of sector 135 degrees

From the general formula of the Perimeter of the circle:

perimeter = 2 * pi * radius

In our case radius = 11 cm

Thus,

Perimeter = 2 * pi * 11

Primetime = 69.14

Since the arc is 135 degrees

Perimeter of arc = 135/360 * perimeter of whole circle

Perimeter of arc = 135/360 * 69.14

The perimeter of the arc = 25.925cm

Therefore,  the perimeter of the sector is not greater than 47.5.

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Any equation in the variable x that contains a logarithm is called a logarithmic equation.

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To calculate the sale price, we need to find out how much the TV is discounted by, which we can do by multiplying the original price by the percentage discount (expressed as a decimal).

35% of the original price can be expressed as 0.35.

so,

Discount = 540 omr * 0.35 = 189 omr

To find the sale price, we can subtract the discount from the original price:

Sale price = Original price - Discount

Sale price = 540 omr - 189 omr

So the sale price is 351 omr.

Answer: e, a, f, c

Step-by-step explanation:

v evenly cuts through line tv and line VS. you can tell because the single line on each side....... rest should be correct

An example of dilation math is a square of side 5 units can be dilated to a square of side 15 units, but the shape of the square remains the same.

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Answer:

Step-by-step explanation:

[tex]\mathrm{\cfrac{3^5\times\:10^5\times\:25}{5^7\times\:6^5}}[/tex]

Factor:

6^5= 2^5*3^5

10^5= 2^5*5^5

25 = 5^2

[tex]\mathrm{\cfrac{3^5\times\:2^5\times\:5^5\times\:5^2}{5^7\times\:2^5\times\:3^5}}[/tex]

3^5*2^5*5^5*5^2 = 3^5*2^5*5^7

[tex]\mathrm{\cfrac{5^7\times\:3^5\times\:2^5}{5^7\times\:2^5\times\:3^5}}[/tex]

Now, cancel common factor:-

[tex]\mathrm{3^5\times\:2^5\times\:5^7}[/tex]

[tex]\mathrm{1}[/tex]

-Hope this helps!

Applying the relation between the force and the distance between the two objects , the force between the objects when the distance between the objects is 7 meters is 0.21 N.

Force is a physical quantity that describes the interaction between two objects. It is the push or pull exerted on an object that changes or tends to change its motion. Force is measured in units of Newtons (N) and it can be a vector quantity, meaning that it has both magnitude and direction.

The unit of measurement for force is the Newton (N). It is important in physics because it is one of the fundamental quantities used to describe the motion and interactions of objects. Forces are responsible for changes in an object's motion, such as acceleration or deceleration, and they play a key role in many physical phenomena, including gravity, friction, and tension.

As given in the question , the force is 0.65 Newtons when the distance between the objects is 4 meters.

Let the force when the distance is 7 meters be F2.

So using the relation between the force and the distance , i.e Force is inversely proportional to the square of distance between the objects.

[tex]\frac{F2}{0.65} =\frac{4^{2} }{7^{2} }[/tex]

Therefore, F2 = 0.21 Newtons

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Answer:

Step-by-step explanation:

So we know what a gradient is = y=mx+c So you have to make a triangle with the 2 numbers touching a line and make a triangle the conects to both of them. and then you will get the answer

Answer:

-72

Step-by-step explanation:

-0.125x=16-7

-0.125x=

x=-72

Answer:

x = -72

Step-by-step explanation:

Given equation,

→ -0.125x + 7 = 16

Now we have to,

→ Find the required value of x.

Then the value of x will be,

→ -0.125x + 7 = 16

Subtract RHS with the number 7:

→ -0.125x = 16 - 7

→ -0.125x = 9

Divide RHS with the number -0.125:

→ x = 9 ÷ (-0.125)

→ [ x = -72 ]

Hence, the value of x is -72.

Triangulation is the method of finding the location of an object based on the measurements made from the two other locations. The above statement is true statement.

Triangulation is the division of a face or plane polygon into a series of triangles, usually with the limitation that each side of a triangle is fully shared by two adjacent triangles. In geometry, triangulation is the division of planar objects into triangles, or more broadly, the division of high-dimensional geometric objects into simplifications. Triangulation of a 3D volume involves subdivision into packed tetrahedra that directly measure distances to points. It is a method for finding the location of the object.

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Answer:

The measure of each exterior angle of a regular dodecagon will be =360∘12=30∘

a) The reason for which r > 3 is because a side length in a figure cannot assume a negative value.

b) The double inequality for r is given as follows: 3 < r < 8.

The perimeter of a rectangle of base b and height h is given by the equation presented as follows:

P = 2(b + h).

The dimensions for this problem are given as follows:

The perimeter of the rectangle is smaller than 26 cm, hence the inequality is defined as follows:

P < 26.

2(b + h) < 26

b + h < 13 (simplifying by 3 both sides of the inequality).

r + r - 3 < 13

2r < 16

r < 8.

Hence the double inequality is defined as follows:

3 < r < 8.

As a side length cannot be negative nor zero, hence it is also needed that r - 3 > 3 -> r > 3.

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Answer:

A)57   film a music video

Step-by-step explanation:

Let x represent measure of angle 1.

We have been given that measure of angle 3 is six more than twice the measure of angle 1. So measure of angle 3 would be .

We are also told that measure of angle 2 is 27 less than measure of angle 3, so measure of angle 2 would be .

We have been given that angle 1, angle 2 and angle 3 form a straight line, so the sum of angles 1, 2 and 3 would be 180 degrees.

Upon substituting the expressions for measure of angles, we will get:

Now, we will combine like terms.

The measure of angle 2 would be .

Therefore, the measure of angle 2 is 57 degrees.  

Quadrant Class 9 is a level of mathematics taught in secondary school in the United Kingdom. It is the equivalent of Algebra 1 and Geometry combined in the United States.

This class teaches students how to graph equations, solve equations, and use the properties of shapes to solve problems. Quadrant Class 9 also covers the basics of calculus, such as derivatives, integrals, and limits.

The main focus of Quadrant Class 9 is on graphing equations. Students learn how to plot points on a graph, connect the points to make a line or curve, and solve equations by finding the intersection of two lines. They also learn how to graph the solutions of inequalities and identify the domain and range of a function.

In addition to graphing, students learn how to solve equations using basic algebraic principles, such as the order of operations and the distributive property. They also learn how to solve systems of equations, manipulate polynomials, and find the roots of a quadratic equation.

Quadrant Class 9 also covers the basics of geometry, such as the Pythagorean Theorem, the properties of triangles, and the area and perimeter of shapes. Students learn how to use these skills to solve problems involving angles, area, and volume.

Overall, Quadrant Class 9 is a challenging and rewarding mathematics class that prepares students for higher-level math classes in the future.

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Answer:

A) 0

Step-by-step explanation:

h/4+(12-y)/3

-12/4+(12-3)/3

-3+(9)/3

-3+9/3

-3+3

0