If 100.0 moles of H and 40.0 moles of O, react to produce water, which one is the limiting reactant in the
reaction below?
2 H, (g) + 02 (g) - > 2 H20(g)

Answer: the mass of 7.55 x 10^21 molecules of water is 0.226 g, which corresponds to option (c).

Explanation: The atomic weight of water (H2O) is:

2(1.008 g/mol) + 15.999 g/mol = 18.015 g/mol

Avogadro's number (NA) is:

6.022 x 10^23 molecules/mol

To calculate the mass of 7.55 x 10^21 particles of water, able to utilize the taking after equation:

mass = (number of atoms / Avogadro's number) x atomic weight

mass = (7.55 x 10^21 / 6.022 x 10^23) x 18.015 g/mol

mass = 0.226 g

The "Ring of Responsibility" requires a 15- to 25-foot untreated buffer zone next to water bodies.

A buffer zone is an area of land that separates two or more countries, states, or territories, and is often demilitarized. The purpose of a buffer zone is to provide a space for negotiations and to reduce the possibility of conflict and war. Buffer zones can also be used to protect sensitive natural resources or habitats, such as areas of wilderness or wildlife. Buffer zones can be permanent or temporary, and can range in size from a few miles to hundreds of miles. In addition to physical barriers, buffer zones can also include economic, political, and social measures to reduce tensions between two or more parties. Buffer zones are an important tool in international relations, as they can help to prevent armed conflict and promote peaceful resolution of disputes.

This buffer zone is intended to prevent pollutants from entering the water body and protect it from potential environmental damage.

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Answer:

20.44 grams of sodium nitrate can be formed

Explanation:

The balanced chemical equation for the reaction between lead (II) nitrate and sodium iodide is:

Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2

Moles of HCL present in the reaction is 0.899 moles

The mole is the unit of substance that is equal to the number of atoms in 0.012 kilogrammes of carbon 12 and is represented by the sign "mol".

chemical reaction, the transformation of one or more chemicals (the reactants) into one or more distinct compounds (the products). Chemical elements or chemical compounds make up substances. In a chemical reaction, the atoms that make up the reactants are rearranged to produce various products.

Use the following formula to calculate the moles of each reactant present at the start of the reaction:

Molar mass divided by mass equals a mole.

The molar mass of HCl is 36.461 g/mol (1.008 g/mol for H and 35.453 g/mol for Cl), while the molar mass of [tex]Ca(OH)_2[/tex] is 74.093 g/mol (40.078 g/mol for Ca, plus 215.999 g/mol for O and 21.008 g/mol for H).

Consequently, the amount of [tex]Ca(OH)_2[/tex] in the starting moles of the reaction is:

[tex]Ca(OH)_2[/tex] moles are equal to 48.5 g / 74.093 g/mol, or 0.654 moles.

At the start of the reaction, there are: moles of HCl present.

32.8 g of HCl divided by 36.461 g/mol yields 0.899 moles.

Since we have only 0.899 moles of HCl present, it is the limiting reactant. This means that all of the [tex]Ca(OH)_2[/tex] will react, and some of the HCl will be left over.

To convert this to grams, we use the formula:

mass = moles x molar mass

The molar mass of [tex]CaCl_2[/tex] is 110.984 g/mol (40.078 g/mol for Ca and 2*35.453 g/mol for Cl).

Therefore, the mass of [tex]CaCl_2[/tex] produced is:

mass of [tex]CaCl_2[/tex] = 0.654 moles x 110.984 g/mol = 72.6 g

So, 48.5 g of [tex]Ca(OH)_2[/tex] and 32.8 g of HCl will produce 72.6 g of [tex]CaCl_2[/tex] and 2 moles of [tex]H_2O[/tex].

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The mass (in grams) of CuO formed when 63.5 g of copper, Cu is heated strongly in air is 79.5 g

First, we shall write the balanced equation for the reaction, This is given below:

2Cu + O₂ -> 2CuO

Now, we shall determine the mass of CuO formed from the reaction. Details below:

From the balanced equation above,

127.1 g of Cu reacted to form 159.1 g of CuO

Therefore,

63.5 g of Cu will react to form = (63.5 × 159.1) / 127.1 = 79.5 g of CuO

Thus, the mass of CuO formed is 79.5 g

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The atoms of neon are [tex]27.099 *10^{23}[/tex], moles of silicon are 0.1199 , moles of [tex]CH_{4}[/tex] are 0.56, moles of gold are 8.64, atoms of cobalt are [tex]157.7764*10^{23}[/tex] and number of cookies are    [tex]7.2264*10^{23}[/tex].

Multiplying the number of moles with [tex]6.022*10^{23}[/tex] we will get number of atoms of neon.

Number of atoms= [tex]4.5* 6.022 *10^{23}[/tex]

Number of atoms of neon =  [tex]27.099 *10^{23}[/tex]

Number of atoms= moles * [tex]6.022*10^{23}[/tex]

Moles of silicon =  [tex]\frac{1.2*10^{23}}{6.022*10^{23} }[/tex]

Moles of silicon = 0.199 moles

Number of atoms= moles * [tex]6.022*10^{23}[/tex]

Moles of [tex]CH_{4}[/tex] = [tex]\frac{3.4*10^{23} }{6.022*10^{23} }[/tex]

Moles of [tex]CH_{4}[/tex]= 0.56 moles

Number of atoms= moles * [tex]6.022*10^{23}[/tex]

Moles of gold = [tex]\frac{5.2*10^{24} }{6.022*10^{23} }[/tex]

Moles of gold= 8.64 moles

Number of atoms= moles * [tex]6.022*10^{23}[/tex]

Number of atoms of cobalt = [tex]26.2*6.022*10^{23}[/tex]

Number of atoms of cobalt =  [tex]157.7764*10^{23}[/tex]

Number of atoms= moles * [tex]6.022*10^{23}[/tex]

Number of cookies= [tex]1.2*6.022*10^{23}[/tex]

Number of cookies= [tex]7.2264*10^{23}[/tex]

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Answer: , the work required to separate the two ions to an infinite distance is 4.63 x 10^-19 J.

Explanation: One can determine the potential energy of two point charges by utilizing the specified equation:

The value of U is directly proportional to the product of q1 and q2, and inversely proportional to the distance between them (r), where k is a constant factor.

The potential energy denoted by U is determined by the Coulomb constant, k, which has a value of 9 x 10^9 Nm^2/C^2. The calculation of U involves the charges of two particles, q1 and q2, as well as the distance between them, denoted by r.

We have an instance where a sodium ion (Na+) has a charge of 1.6x10^-19 C, and a chloride ion (Cl-) has a charge of -1.6x10^-19 C, positioned 4.95 Nm apart from each other.

Once we insert the given numbers, the result obtained is:

The expression for U can be obtained by utilizing the equation U = (kQq)/r, with k being the Coulomb's constant equal to 9 x 10^9 Nm^2/C^2, Q and q representing the electric charges of -1.6x10^-19 C and -1.6x10^-19 C, respectively, and r being the distance between the charges of 4.95 Nm.

The value of U is negative 4.63 times 10 to the power of negative 19 Joules.

It is important to observe that the negative symbol signifies the negativity of the potential energy, implying that effort must be exerted in order to disassociate the two ions.

We can start by using Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is equal to the sum of the partial pressures of each individual gas component.

Let PCO2 be the partial pressure of CO2 in the mixture after it is added. Then, we can set up the following equation:

PO2 + PN2 + PAr + PCO2 = Ptotal

Substituting in the given partial pressures and total pressure, we get:

100 torr + 150 torr + 200 torr + PCO2 = 575 torr

Simplifying the equation, we get:

PCO2 = 575 torr - 100 torr - 150 torr - 200 torr

PCO2 = 125 torr

Therefore, the partial pressure of CO2 in the gas mixture is 125 torr. Answer: B) 125 torr.

There are 6 atoms of oxygen present on the reactants side of the given reaction. Thus the correct answer is option B.

Firstly, let us write the accurate chemical equation and then subsequently we will balance it as and when needed.

4Fe+3O₂→2Fe₂O₃

This is the correct balanced chemical equation for the reaction. And as we can find that the amount of iron and oxygen atoms on the reactants side is equivalent to that of the products side. This corroborates that the given chemical equation is correctly balanced.

Now, the query is based on counting the total number of oxygen atoms present on the side of reactants. As we can clearly see on the reactant side  there are three Oxygen molecules that are present. That means that there are a total of six oxygen atoms, since 3*2 gives us a total of 6 oxygen atoms.

Hence, there are a sum total of six O₂ atoms that are present on the reactant side of the provided chemical equation.

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The full question is:

How many oxygen atoms are present on the reactant side of the chemical equation  4Fe+3O₂→2Fe₂O₃?

A. 3

B. 6

C. 7

D. 13

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The enthalpy for the following reaction Ca (s) + 2 H₂O → Ca(OH)₂(s) + H₂ (g) is -365kJ.

A thermodynamic system's enthalpy, which is one of its properties, is calculated by adding the system's internal energy to the product of its pressure and volume. It is a state function that is frequently employed in measurements of chemical, biological, and physical systems at constant pressure, which the sizable surrounding environment conveniently provides. The pressure-volume concept describes the effort needed to create space for the system by displacing its surrounds in order to determine its physical dimensions.For solids and liquids under typical conditions, the pressure-volume term is relatively tiny, whereas it is only somewhat small for gases. As a result, in chemical systems, enthalpy serves as a stand-in for energy; for example, in chemistry, "energies" like bond, lattice, and solvation are actually differences in enthalpy.

The enthalpy for the reaction Ca (s) + 2 H₂O (1) -> Ca(OH)₂ (s) + H₂ (g) is -365 kJ. This can be calculated by using the calculated enthalpy values of the three given reactions above and the law of Hess's.

First, let's look at the given reactions:

2 H₂ (g) + O₂ (g) → 2 H₂0

ΔH° = -572 kJ

Ca (s) + ½ O₂ (g) →CaO (s)

ΔH° = -635 kJ

CaO (s) + H2O → Ca(OH)₂ (s)

ΔH° = -64 kJ

Now let's calculate the enthalpy for the reaction Ca (s) + 2 H2O (1) -> Ca(OH)₂ (s) + H₂ (g):

ΔH° = [2(-64 kJ) + (-572 kJ) + (-635 kJ)] - (-572 kJ + (-64 kJ + (-635 kJ))

ΔH° = -365 kJ

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Answer: 0.313 mole of NH3

Explanation:

As a result, AgNO3 has a molar solubility of 0.0245 M.

A compound's capacity to dissolve in a particular substance known as a solvent is indicated by a property termed molar solubility (M). It is specifically the most moles of a solute that may dissolve in one liter of solvent.

The Ksp (solubility product constant) formula, which is the product of the ion concentrations elevated to their stoichiometric coefficients in a saturated solution4, can be used to determine the molar solubility of AgNO3.

The formula for AgNO3 is AgNO3 → Ag+ + NO3-.

Therefore, Ksp = [Ag+][NO3-] = 6.00 × 10⁻⁴

Since AgNO3 dissociates completely in water, [Ag+] = [NO3-] = S (molar solubility).

Thus, Ksp = S² = 6.00 × 10⁻⁴.

Solving for S gives us S = √(Ksp) =√(6.00 × 10⁻⁴) = 0.0245 M⁴

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Answer:

c. The recorded waves are mechanical waves.

e. The microphone does not change the wave type.

g. The frequency or amplitude of the waves will change in the microphone.

These statements are true. The microphone records the sound waves as mechanical waves, which require a medium to travel through, such as air or water. The microphone does not change the type of wave from mechanical to electromagnetic, or vice versa. The frequency and amplitude of the sound waves will change as they pass through the microphone, depending on the characteristics of the source producing the sound.

Answer:

Wave A (blue wave) has the highest volume because it has the highest amplitude.

Waves B and C have equal volumes because they have the equal amplitude.

Wave C (green wave) has the highest pitch because it has the highest frequency.

Waves A and B have equal pitch because they have the equal frequency.

At -79.6 °C, the standard free energy change for this reaction is -67.24 kJ/mol.

Use the following equation to calculate the standard free energy change at a different temperature:

ΔG = ΔH - TΔS

where ΔH = enthalpy change, ΔS = entropy change, and T = temperature in Kelvin.

Given:

ΔH = 53.29 kJ/mol

ΔS = 623.51 J/(mol⋅K)

T = -79.6 + 273.15 K = 193.55 K

First, convert ΔH from kJ/mol to J/mol:

ΔH = 53.29 × 10³ J/mol

Next, convert ΔS from J/(mol⋅K) to kJ/(mol⋅K):

ΔS = 623.51 J/(mol⋅K) ÷ 1000 = 0.62351 kJ/(mol⋅K)

Plug in the values:

ΔG = (53.29 × 10³ J/mol) - (193.55 K × 0.62351 kJ/(mol⋅K))

ΔG = 53.29 kJ/mol - 120.53 kJ/mol

ΔG = -67.24 kJ/mol

Therefore, the standard free energy change for this reaction at -79.6 °C is -67.24 kJ/mol.

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Answer:

c. The waves from the speaker are mechanical waves.

d. The frequency or amplitude of the waves could change.

g. The speaker does not change the wave type.

These statements are true. The waves that come out of the speaker are mechanical waves, meaning they require a medium to travel through, such as air or water. The frequency and amplitude of the waves could change, depending on the characteristics of the sound being played through the speaker. The speaker does not change the type of wave from mechanical to electromagnetic, or vice versa.

When 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.

The oxygen produced

The balanced chemical equation for the reaction:

2HgO(s) → 2Hg(l) + O2(g)

states that 2 moles of HgO will produce 1 mole of O2.

We can use the molar mass of HgO and the mole ratio of HgO to O2 to calculate the mass of O2 produced from a given mass of HgO.

The molar mass of HgO is 216.59 g/mol (200.59 g/mol for Hg + 16.00 g/mol for O).

So, 1 mole of HgO has a mass of 216.59 g.

According to the balanced equation, 2 moles of HgO produce 1 mole of O2.

Therefore, 1 mole of O2 has a mass of 32.00 g.

Using stoichiometry, we can calculate the mass of O2 produced when a certain mass of HgO reacts completely.

For example, if we start with 216.59 g of HgO (1 mole), then the amount of O2 produced will be 0.5 moles (1 mole of O2 for every 2 moles of HgO), which is equivalent to 16.00 g of O2 (0.5 moles of O2 x 32.00 g/mol).

So, when 216.59 g of HgO completely reacts, 16.00 g of O2 will be produced.

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Answer:

Please mark brainlist

Explanation:

The equilibrium expression for this reaction is Kw = [H₃O⁺][OH⁻], where Kw is the autoionization constant for water. At 25°C, the value of Kw is 1.0 x 10⁻¹⁴.

Answer: non-polar covalent

Explanation:

If two atoms have an electronegativity difference of 0.4 or less, they form a non-polar covalent bond.

B is 2.04 electronegativity

H is 2.20 electronegativity

the electronegativity difference is 0.16.

this is less than 0.4 so the bonds are non-polar covalent.

The expected result of the experiment is that the rate of precipitation of sulfur will be faster with hydrogen chloride than with acetic acid.

What is Precipitation?

Precipitation refers to the process in which a substance in a solution comes out of solution and forms a solid. This occurs when the concentration of the substance exceeds its solubility limit in the solution, resulting in the formation of solid particles that settle at the bottom of the solution.

Procedure:

Prepare a series of solutions with different monobasic acids. For example, you can prepare solutions of sodium thiosulphate (Na2S2O3) with different monobasic acids, such as hydrochloric acid (HCl), sulfuric acid (H2SO4), and nitric acid (HNO3), at a constant concentration and volume.

Place equal volumes of the thiosulphate solution and each monobasic acid solution in separate beakers or test tubes.

Start the timer or stopwatch as soon as the two solutions are mixed. The thiosulphate ions will react with the hydrogen ions from the monobasic acid, resulting in the formation of sulphur precipitate according to the following chemical equation:

S2O3^2- + 2H+ -> H2O + S + SO2

Observe the reaction and record the time taken for the formation of sulphur precipitate in each solution.

Compare the rates of precipitation of sulphur for each monobasic acid solution to study the dependence of the rate on the nature of the monobasic acid. Note any trends or differences in the rates of precipitation among the different acids used.

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If the density of antifreeze solution is 1.07 g/mL, then the molarity of the antifreeze solution is calculated as 8.66 M.

Number of moles of solute dissolved per liter of the solution is defined as molarity.

As we know, moles of EG = mass of EG / molar mass of EG

Mass of EG = 47.0 mL × 1.11 g/mL = 52.17 g

Moles of EG = 52.17 g / 62.07 g/mol = 0.840 mol

Total volume = 47.0 mL + 50.0 mL = 97.0 mL

So, mass of solution = volume of solution × density of solution

mass of solution = 97.0 mL × 1.07 g/mL = 103.79 g

As, molarity =moles of solute /volume of solution

Molarity = 0.840 mol / (97.0 mL / 1000 mL/L) = 8.66 M

Therefore, the molarity of the antifreeze solution is 8.66 M.

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Taking into account the reaction stoichiometry, 2.14 grams of H₂O are formed when 20.0 grams of NaHCO₃ decomposes.

In first place, the balanced reaction is:

2 NaHCO₃ → H₂O + CO₂ + Na₂CO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 168 grams of NaHCO₃ form 18 grams of H₂O, 20 grams of NaHCO₃ form how much mass of H₂O?

mass of H₂O= (20 grams of NaHCO₃× 18 grams of H₂O)÷168 grams of NaHCO₃

mass of H₂O= 2.14 grams

Finally, 2.14 grams of H₂O are formed.

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The percentage concentration of potassium sulfate in the solution is 20%.

What is Percentage Concentration?

Percentage concentration, also known as percent concentration or mass percent, is a measure of the amount of a solute present in a solution, expressed as a percentage of the total mass or volume of the solution. It is commonly used in chemistry and related fields to express the concentration of a solute in a solution.

To find the percentage concentration of potassium sulfate in the solution, we need to calculate the mass of potassium sulfate in the solution and express it as a percentage of the total mass of the solution.

Given:

Mass of potassium sulfate (K2SO4) = 80.0 g

Mass of water (H2O) = 320 g

Total mass of the solution = Mass of potassium sulfate + Mass of water

= 80.0 g + 320 g

= 400 g

Now, we can calculate the percentage concentration of potassium sulfate:

Percentage concentration = (Mass of potassium sulfate / Total mass of the solution) × 100

Percentage concentration = (80.0 g / 400 g) × 100

= 20%

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C is the correct option as it contains oxygen along with carbon and hydrogen. Aliphatic hydrocarbons that have had one or more hydrogen atoms .

Aliphatic hydrocarbons that have had one or more hydrogen atoms replaced by a halogen, such as those that have been fluorinated, chlorinated, brominated, or iodized, are known as halogenated aliphatic hydrocarbons.

The group of chemical molecules known as chlorinated aliphatic hydrocarbons is diverse and is characterised by an open-chain structure or a variable number of bonds, which can be single, double, or triple. C is the correct option as it contains oxygen along with carbon and hydrogen.

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The compound shown has the IUPAC name O Macmillan Learning. -3-ethyl-2,2-dimethyl-hexane Incorrect.

Explanation and response: Because it implies that there's methyl groups on carbons number one and sixth of the parent carbon chain, the name — appears-dimethylhexane is incorrect. Because the name "hexane" implies that a parent atom chain only has six molecules long, the methyl groups are located at the ends of every molecule.

Hexane, commonly referred to as sextane, is an organic compound that belongs to the alkane class. They are acyclic branched as well unbranched hydrocarbons with the standard structure CnH2n+2, and thus entirely composed of hydrogen and saturated oxygen atoms. Hexane is a colorless, clear liquid.

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The correct options that will result in mole are option B, C, and H

To know the options that will result in mole, do the following:

Ideal gas law states as follow:

PV = nRT

Where

PV = nRT

Make n the subject by dividing both sides by RT

n = PV / RT (option B)

Mole, mass and molar mass are related according to the following formula:

Mole = mass / molar mass (option C)

Molarity is defined as mole per unit volume as shown below:

Molarity = mole / volume

Make mole the subject by cross multiplying.

Mole = Molarity × volume (option H)

Thus, from the above illustrations, we can conclude that the correct options which will result in mole are option B, C, and H

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The mole fraction of the solute in the solution is calculated as 0.1406.

Non-volatile solute is a substance that does not readily evaporate at given temperature and pressure.

Raoult's law : P_total = P_solute + P_water

P_total is total vapor pressure of solution, P_solute is partial pressure of  solute, and P_water is partial pressure of water.

Since the solute is non-volatile, we can assume that its partial pressure is negligible compared to the pressure of water. Therefore: P_total ≈ P_water

P_total = X_water * P°_water

X_water is mole fraction of water and P°_water is vapor pressure of pure water at same temperature.

305 torr = X_water * 355.1 torr (since P_total ≈ P_water)

X_water = 305 torr / 355.1 torr = 0.8594

X_solute = 1 - X_water = 1 - 0.8594 = 0.1406

Therefore, the mole fraction of the solute in the solution is 0.1406.

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