if it took her 2.7 seconds to lift the lawnmower, how much power did she output

Answers

Answer 1

Answer:

N/A

Explanation:

The following formula can be used to compute the power output of a person lifting a lawnmower:

Work (W) / Time (t) = Power (P).

Where:

Work (W) is defined as the force used to lift the lawnmower multiplied by the distance traveled (i.e., work done against gravity).

Time (t) is the amount of time it takes to lift the lawnmower.

To determine the power output, however, we would need to know the force used to lift the lawnmower as well as the distance it was lifted. We won't be able to provide an accurate power output value without this information.


Related Questions

Increasing the number of loops in a solenoid will cause the strength of its magnetic field to

Answers

As long as the current is steady, a solenoid's magnetic field will become stronger as the number of loops increases.

Was the electromagnet made stronger or weaker by adding more loops?

An electromagnet's strength can be increased by increasing the current or voltage as well as the quantity of wire loops encircling the iron core.

What number of loops will result in the strongest magnetic field?

It follows that increasing the number of turns or the current flow (by raising the voltage because I = V/R) will produce a stronger magnetic field for a given coil length. Therefore, a coil with N of 1000 turns would generate a stronger magnetic field than one with N of only 100 turns.

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math
Determine if the function below is continuous.

graph of a piecewise function, with 2 pieces. The first piece is a line that starts at negative infinity and goes through point (-4,5) and ends with an open dot at (1,0). The second piece is a line that starts with a closed dot at (1,-1), goes through point (2,1) and continues to infinity.

A. not continuous at x = 1
B. not continuous at x = 0
C. not continuous at x = -1
D. continuous

Answers

The function is not continuous at x=1, so the answer is A.

At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.

Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.

similarities and differences between a lunar eclipse and the disappearing sun. HELP FAST

Answers

Answer: A solar eclipse results when the moon passes in between the earth and the sun hiding the sun fully or partly for some time. A lunar eclipse occurs when the earth passes in between the moon and the sun casting its shadow on the moon and thus hiding it fully or partly for some time.

A traditional (historical) windmill with the radius of its sails of 15 [m] subject to wind of 7 m/s pumps 3.4 [m³/s] of water over a height of 2.1 [m]. Estimate the actual efficiency of the windmill in [%]. Assume the Betz limit for wind power with Uout=Uin/3 (a=1/3), the air density of 1.225 kg/m³, and the water density of 1000 kg/m³.

O a. 70
O b. 40
O c. 50
Od. 80
O e. 60

Answers

According to the question the efficiency of the windmill is 60%.

What is efficiency?

Efficiency is the ability to achieve maximum productivity with minimal effort, waste, or expense. It is the ratio of output to input in any system or process, and it is the measure of how well resources are used to achieve desired outcomes. Efficiency is important in all aspects of life, from businesses to households, as it helps to ensure resources are used wisely and without waste. Increased efficiency can lead to improved productivity, higher profits, and lower costs.

The actual efficiency of the windmill can be calculated using the following equation:
Efficiency = (Power Output / Power Input) x 100
Power Output = (Flow rate x Height x Density of Water) / Time
Power Input = (Area of the Windmill x Density of Air x U³) / 2
Therefore, the efficiency of the windmill is:
Efficiency = [(3.4 m³/s x 2.1 m x 1000 kg/m³) / 1] / [(π x 152 m² x 1.225 kg/m³ x 7 m/s³) / 2] x 100
Efficiency = 60%.

Therefore, the correct option is E
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A bubble of air has a diameter of 1 mm when it is 0.5 m under the surface of water ( coefficient of surface tension 0.073 N/m). Find the gauge pressure inside the bubble.

Answers

The gauge pressure inside the bubble. is -101310.4 Pa.

The negative sign shows  that the pressure inside the bubble is lower than the atmospheric pressure. Hence, the bubble will rise to the surface of the water.

How do we calculate?

We apply Laplace's law to find the absolute pressure inside the bubble:

ΔP = 2γ/r

where ΔP is the pressure difference across the curved surface of the bubble, γ is the coefficient of surface tension of water, and r is the radius of curvature of the bubble.

r = 0.5 mm = 0.0005 m

Substituting the given values, we have:

ΔP = 2 × 0.073 N/m ÷ 0.0005 m

ΔP = 14.6 × 10^(-3) Pa

The atmospheric pressure at sea level is approximately 101325 Pa. Therefore, the gauge pressure inside the bubble is:

P_gauge = ΔP - P_atm

P_gauge = 14.6 × 10^(-3) Pa - 101325 Pa

P_gauge = -101310.4 Pa

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why does pure water increase in volume when heated​

Answers

Answer:

Pure water increases in volume when heated due to the phenomenon of thermal expansion. When water is heated, the kinetic energy of its molecules increases, causing them to move faster and spread out. This increased molecular movement leads to an increase in the average distance between water molecules, resulting in an expansion of the water.

Explanation:

.......

Need Help! The diagram shows a cross section of the Earth near its surface.

In the diagram, continental crust is labeled ___, and oceanic crust is labeled ____
A. 1; 2
B. 3; 1
C. 2; 1
D. 1; 3​

Answers

In the diagram, continental crust is labeled 1 and oceanic crust is labeled 2.

option A.

What are the characteristics of Continental and ocean crust?

Continental crust:

Generally thicker, averaging about 30-40 kilometers in depth.Composed mostly of granite, which is a type of igneous rock.Less dense compared to oceanic crust.Contains a wide range of rock types, including sedimentary, metamorphic, and igneous rocks.Forms the continents and the shallow shelves extending from the continents under the oceans.

Oceanic crust:

Generally thinner, averaging about 5-10 kilometers in depth.Composed mostly of basalt, which is a type of igneous rock.More dense compared to continental crust.Mostly consists of igneous rocks, specifically basaltic lava flows and volcanic rocks.Forms the ocean basins and the deep ocean floor.

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a bird flies 3km to the west and then 4km to the south. find the resultant displacement of the bird​

Answers

Answer:

We are asked to calculate for the resultant displacement.

We therefore conclude that the resultant displacement of the bird is 5 Km, 53o 5 K m , 53 o South of West.

Explanation:

have a nice day.

A uniform, aluminum beam 9.00 m
long, weighting 300 N
, rests symmetrically on two supports 5.00 m
apart. A boy weighing 600 N
starts at point A
and walks toward the right. (Figure 1) How far beyond the support can the boy walk without tipping?

Answers

The boy weighing 600 N can walk at most 4.1 m beyond point A without tipping the beam.

What is center of mass?

It is the weighted average position of all the system's or object's constituent pieces. It is the average position of all the parts of the system or object, weighted according to their mass. In other words, the center of mass is the point where an applied force will result in pure translation of the object, without any rotation.

To avoid tipping, the center of mass of the beam and the boy together must remain over the area between the two supports. Let's first find the center of mass of the beam.

The weight of the beam is 300 N and it is uniform, so its center of mass will be located at the midpoint, or 4.5 m from either support.

Next, we need to find the center of mass of the boy-beam system as the boy walks along the beam. Let's assume the boy moves a distance d to the right of point A before tipping occurs. The weight of the boy is 600 N and we can approximate his weight as acting at the center of his body, which we'll assume is 0.9 m from the left end of the beam. The combined center of mass of the boy-beam system will be at a distance (4.5 m + 0.9 m + d) from the left end of the beam.

For the system to remain stable, this combined center of mass must remain between the two supports, which are 5.00 m apart. Therefore, we can write:

4.5 m ≤ 4.5 m + 0.9 m + d ≤ 9.5 m

Solving for d, we get:

d ≤ 4.1 m

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The learner added some iodine solution to the water in the test tube. After 30 minutes at room temperature, the contents of the visking tubing bag were stained black, but the water in the test tube remained a yellow color.( I) explain this results

Answers

The Visking tubing is a selectively permeable membrane that allows small molecules like water to pass through, but restricts the movement of larger molecules such as iodine. When iodine solution was added to the water in the test tube, some of the iodine molecules diffused from the test tube into the Visking tubing bag, but the larger starch molecules in the bag could not diffuse out into the test tube due to their size.

Over time, the iodine molecules that diffused into the Visking tubing bag reacted with the starch molecules present in the bag, forming a blue-black complex. This complex is insoluble in water and therefore could not diffuse back out of the bag into the test tube.

As a result, the water in the test tube remained yellow in color, indicating that there was no iodine present in the water, while the contents of the Visking tubing bag were stained black due to the presence of the blue-black complex of iodine and starch. This demonstrates the process of diffusion and the selective permeability of the Visking tubing membrane.

With the solar photon flux of 3*10^21 m²s¹, how large area in [m²] covered by solar panels would be necessary to produce 150 kW of power? Assume yellow light (2.1 eV) and 15% power conversion efficiency.

O a. 100
O b. 50
O c. 25
O d. 10
O e. 1000

Answers

Answer: (D) 10

can't explain brainly keeps censoring the numbers out for some reason

As magma rises through the cracks of a spreading seafloor, it cools and adds new rock to the ocean floor.
The ribbon of magma causing the spreading is most similar to which structure?
A volcano
A sinkhole
A valley
A glacier

Answers

Answer:

zd its c

Explanation:

i know

when a pure water is heated , it increases in volume​

Answers

As water freezes below 4°C, the volume of the liquid shrinks and water molecule motion slows. When the temperature rises over 4 °C, the water molecules spread out and take up more space, increasing the volume.

How does cooling water from 4 C to 0 C affect its volume?

Due to the peculiar property of water known as "Anomalous Expansion of Water," when 1 liter of water is cooled from 4°C to 0°C, the volume of the water starts to grow. Between 4°C and 0°C, water expands abnormally.

What happens to water's specific volume when it is heated from 0 degrees Celsius?

Water volume reduces as it is heated from 0°C to 4°C because the water's density will be maximum

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On Earth the gravitational field strength is 10N/kg. What would be the weight of someone on Earth who had a mass of 75kg?


750N/kg

750N

75N

7500kg​

Answers

The weight of someone on Earth with a mass of 75kg is 750N.

option B.

What would be the weight of someone on Earth?

The weight of someone on Earth is calculated using Newton's second law of motion.

W = mg

where;

m is the massg is acceleration due to gravity

For the mass is 75kg and the gravitational field strength on Earth is 10N/kg.

W = 75 kg x 10 N/kg

W = 750 N

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A baseball player wants to hit a home run over the wall of a
stadium. The player swings the baseball bat so that it hits the
ball when it is at a height of 0.996 m above the ground. The
ball flies off at an angle of 30° above the horizontal and at a
speed of 36.2 m/s. What is the tallest wall that the player can
clear (i.e., get the ball over) if the wall is 99.1 m away
horizontally?

Answers

A wall less than or equal to 14.7 m in height is the highest the player can clear.

How to calculate height?

Use the kinematic equations of motion to solve the problem. First, we can find the time it takes for the ball to travel 99.1 m horizontally:

d = vt

t = d / v

t = 99.1 m / 36.2 m/s

t ≈ 2.74 s

Now, use the vertical motion equation to find the maximum height the ball reaches:

y = yo + vot + (1/2)at²

where:

yo = 0.996 m (initial height)

vo = v sinθ = 36.2 m/s x sin(30°) ≈ 18.1 m/s (initial vertical velocity)

a = -9.81 m/s² (acceleration due to gravity, pointing downward)

t = 2.74 s (time of flight)

y = 0.996 m + 18.1 m/s x 2.74 s + (1/2) x (-9.81 m/s²) x (2.74 s)²

y ≈ 14.7 m

Therefore, the tallest wall the player can clear is a wall with a height less than or equal to 14.7 m.

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what’s the answer for this

Answers

Answer is zero. Object is momentarily stationary meaning net force equals zero

Using the Left Hand Rule, if motion is toward you and the field is up, which way is the current?
A. Left
B. Right
C. Toward you
D. Away from you

Answers

Answer:
C
Explanation:
Just trust

A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final momentum of the green train?
A. 200 kgm/s
B. 90 kgm/s
C. 20 kgm/s
D. 110 kgm/s

Answers

a: 200 kgm/s final momentum

A laboratory measurement finds 200 μg of hemoglobin per μL of blood. Hemoglobin, the blood protein that transports oxygen, has a molecular weight of 64 kDa or 64,000 u , where 1 dalton ( Da ) = 1 atomic mass unit ( u ) = 1.66×10^−24g . Estimate the number of hemoglobin proteins in one red blood cell. Express your answer in hemoglobin per red blood cell.

Answers

One red blood cell contains an estimated 251 molecules of haemoglobin, according to our estimation.

What size does a red blood cell typically have?

The average red blood cell has a diameter of 6 to 8 micrometres, according to the American Society of Haematology, and a volume of 113-268 μm³ or 113-268x10⁻¹² L.

Let's first change the haemoglobin concentration from grammes per litre to grammes per litre so that it has the same units as the molecular weight:

200 μg/μL x 1 g/1000 μg x 10⁶ μL/L = 0.2 g/L

Next, let's translate hemoglobin's molecular weight from kDa to grammes per molecule:

64 kDa x 1000 Da/kDa x 1.66x10⁻²⁴ g/Da = 1.06x10⁻²⁰ g/molecule

Using Avogadro's number, we can now determine how many haemoglobin molecules are present in a single litre of blood ([tex]6.022*10^{23}[/tex] molecules/mol): 0.2 g/L x 1 mol/1.06x10⁻²⁰ g x [tex]6.022*10^{23}[/tex] molecules/mol = 1.13x10¹⁵ molecules/L.

Divide the total number of molecules in 1 litre of blood by the volume of red blood cells to get the amount of haemoglobin molecules per red blood cell. The typical red blood cell count range, according to the American Society of Haematology, is between 4.5-5.5 million cells/L, which translates to 4.5-5.5x10¹² cells/L.

When we divide the quantity of red blood cells in 1 L by the quantity of haemoglobin molecules, we get:

1.13x10¹⁵ molecules/L / 4.5x10¹² cells/L = 251 Red blood cell haemoglobin molecules, rounded to the closest integer.

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Fill in the blanks with GPE (Gravitational potential energy) or KE (Kinetic energy)

Consider the concepts of kinetic energy (KE) and gravitational potential energy (GPE) as you complete these questions. A ball is held 1.4 meters above the floor. Use the terms KE of GPE as your answers.

In fact, in the absence of air resistance, the amount of ____ energy when the ball is held motionless above the floor equals the amount of ____ energy at impact with the floor.

Answers

In fact, in the absence of air resistance, the amount of GPE (Gravitational potential energy) energy when the ball is held motionless above the floor equals the amount of KE (Kinetic energy) energy at impact with the floor.

33) If a speeding motorcycle is moving, it must also
have
a) potential energy.
b) kinetic energy.
c) chemical energy.
d) all of the above

Answers

D all of the above

If the motorcycle is in motion must have all those energies

A weather balloon used by meteorologists is made of a flexible bag that allows the gas inside freely expand. If a weather balloon containing 25.0 m^3 of helium gas  is released from sea level, what is the volume of gas when the balloon reaches a height of 2100 m, where the pressure is 0.82×10^5 PA? Assume the temperature is unchanged. 

Answers

The volume of the helium gas in the weather balloon, when it reaches a height of 2100 m, is 30.85 m^3.

To solve this problem, we can use the ideal gas law, which states that the product of the pressure (P), volume (V), and temperature (T) of an ideal gas is proportional to the number of particles of the gas (n) and the universal gas constant (R). Since the temperature is assumed to be constant, we can write:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume of the helium gas, and P2 and V2 are the pressure and volume at a height of 2100 m.

At sea level, the pressure is approximately 1.01×10^5 Pa, so we have:

P1 = 1.01×10^5 Pa

V1 = 25.0 m^3

At a height of 2100 m, the pressure is 0.82×10^5 Pa, so we can solve for V2:

P1V1 = P2V2

V2 = (P1*V1)/P2

V2 = (1.01×10^5 Pa * 25.0 m^3) / (0.82×10^5 Pa)

V2 = 30.85 m^3

Therefore, the volume of the helium gas in the weather balloon when it reaches a height of 2100 m is approximately 30.85 m^3.

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Which of the following can be formed by a convergent boundary?
A. Volcanic mountains B. All of these
C. Volcanic islands
D. Deep ocean trenches

Answers

Answer:

Volcanic mountains can be formed by a convergent boundary.

Help!! I need to get this done before 5pm!! I will give brainiest to whoever gets it done quickly!

Answers

Blood typing is a process that determines the type of antigens and antibodies present on the surface of red blood cells.

How to explain the blood

There are four major blood types: A, B, AB, and O. Each blood type is characterized by the presence or absence of certain antigens and antibodies. For example, type A blood has A antigens on the surface of red blood cells and B antibodies in the plasma, while type B blood has B antigens on the surface of red blood cells and A antibodies in the plasma.

Blood transfusions are medical procedures in which blood or blood products are transferred from one person to another. Blood transfusions can be life-saving in situations where a person has lost a significant amount of blood due to injury or surgery, or has a medical condition that affects the production or function of their own blood cells. It is important to match the blood type of the donor and the recipient to prevent adverse reactions, such as hemolysis (breakdown of red blood cells) or an immune response.

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A 0.120 kg, 90.0-cm-long uniform bar has a small 0.055 kg mass glued to its left end and a small 0.110 kg mass glued to the other end. The two small masses can each be treated as point masses. You want to balance this system horizontally on a fulcrum placed just under its center of gravity.
How far from the left end should the fulcrum be placed?

Answers

The fulcrum should be placed 0.120 m from the left end of the bar to balance the system horizontally.

What is balance?

To balance the system horizontally, the center of gravity (CG) of the bar and the attached masses should be placed directly above the fulcrum. We can find the location of the CG using the following formula:

CG = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)

where m1, m2, and m3 are the masses of the bar, the 0.055 kg mass, and the 0.110 kg mass, respectively, and x1, x2, and x3 are their respective distances from the left end of the bar.

We know that the total mass of the system is:

m = m1 + m2 + m3 = 0.120 kg + 0.055 kg + 0.110 kg = 0.285 kg

Let x be the distance from the left end of the bar to the fulcrum. Then, the distance from the fulcrum to the center of gravity is (L/2 - x), where L is the total length of the bar (90.0 cm). Therefore, we want to find x such that:

CG = (L/2 - x)

Substituting the expressions for the CG and the masses, we get:

(m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) = (L/2 - x)

Simplifying and rearranging, we get:

x = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) - L/2

We can choose any two points on the bar as reference points, and take their distances as x1 and x3. Let's choose the left end of the bar as x1 = 0, and the right end of the bar as x3 = L = 90.0 cm = 0.900 m. Then, we can find x2, the distance from the left end to the 0.110 kg mass, as:

x2 = L - x1 - x3 = 0.900 m - 0 m - 0.090 m = 0.810 m

Substituting the masses and distances, we get:

x = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) - L/2

x = (0 kg × 0 m + 0.055 kg × 0.810 m + 0.110 kg × 0.900 m) / (0.120 kg + 0.055 kg + 0.110 kg) - 0.450 m

x = 0.570 m - 0.450 m

x = 0.120 m

Therefore, the fulcrum should be placed 0.120 m from the left end of the bar to balance the system horizontally.

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The voltage of a DC supply always _____________.
A. Points in opposite directions
B. Does not point in any direction
C. Points in various directions
D. Points in the same direction

Answers

Answer: D

In direct current, the voltage is always constant, and the electricity flows in a certain direction.

The voltage of a DC supply always Points in the same direction. The correct answer is d.

A direct current (also known as DC) supply has voltage that always points in the same direction. A direct current (DC) is a form of electrical current in which the flow of electric charge is unidirectional. This means that it only moves in one direction through a circuit. DC is also known as a direct current. DC (Direct Current) keeps the flow of charge going in the same direction all the time, in contrast to AC (Alternating Current), which reverses its direction at regular intervals.

The voltage source in a DC circuit, which could be a battery or a DC power supply, is responsible for maintaining a consistent potential difference between the circuit's positive and negative terminals. The potential difference between the positive and negative terminals of the voltage source is greater at the positive terminal than it is at the negative terminal. As a direct consequence of this, electrons move from the negative terminal to the positive terminal, which results in the generation of an electric current that moves in the same direction consistently throughout the circuit.

When a load (such as a resistor, a light bulb, or any other type of electrical component) is connected to a DC voltage source, the DC voltage will drive the passage of electric charge through the load, which will either power the device or perform work that is of some benefit.

In a nutshell, the voltage coming from a DC supply always points in the same direction, which is from the negative terminal of the voltage source to the positive terminal of the voltage source. This results in a constant flow of electric current when the supply is connected to a DC circuit.

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A wave has a frequency of 50Hz and a wavelength of 20m.
Calculate the speed of the wave in m/s.

Answers

Explanation:

f= 50Hz

wavelength= 20m

Speed of wave (v) = frequency × wavelength

= 50×20

= 1000m/s

An airplane flies with a constant speed of 1624 miles per hour. How far can it travel in 30 minutes?

Answers

The distance the airplane will travel in 30 minutes, given that the airplane travels at 1624 miles per hour is 812 miles

How do i determine the distance travelled?

The following data were obtained from the question:

Speed of airplane = 1624 mile per hourTime taken = 30 minutes = 30 . 60 = 0.5 hourDistance travelled =?

Speed is defined as distance travelled per unit time.

Speed = Distance travelled / time

Inputting the various parameters, we can obtain the distance travelled as follow:

1624 = Distance travelled / 0.5

Cross multiply

Distance travelled = 1624 × 0.5

Distance travelled = 812 miles

Thus, we can conclude that the distance travelled by the airplane in 30 minutes is 812 miles

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Solve pls:
a) What are the maina dvantages of an epicyclicgearbox? b) Figure Q4 overleaf shows a diagram for an epicyclic gear train. Power is supplied to
wheel 3 and is delivered to a load attached to the epicyclic arm, body 2. Wheel 5 is fixed to the gear case, body 1.
i) Determine T4 if t3 = 30, t4 = 40 and t5 = 60.

Answers

a) The main advantages of an epicyclic gearbox are:

High gear ratios can be achieved in a small space, making it a compact design.It can provide a smooth and efficient transfer of power due to the multiple contact points between gears.It can be used for different applications, such as increasing torque or speed, reversing direction, and providing a neutral point.

How to solve a gearbox?

b) i) Using the formula for the gear ratio of an epicyclic gear train:

T4/T3 = (t2/t1) x (t5/t2) x (t4/t5)

T4/30 = (1/2) x (60/20) x (40/60)

T4 = 40 Nm

ii) From the law of gearing for an epicyclic gear train:

w21 = (t3/t2) x (t5/t4) x w31 - (t3/t2) x w2

Substituting the given values:

w21 = (30/20) x (60/40) x 200 - (30/20) x 100

w21 = 150 rad/s

iii) The fixing couple that must be applied to wheel 5 can be found from the power transmitted by the gear train:

P = w3 x T3 = w2 x T2 = w1 x T1

Substituting the given values:

9 kW = 200 rad/s x 30 Nm = w2 x T2 = w2 x 20 Nm

w2 = 450 rad/s

T2 = (9 kW) / (450 rad/s) = 20 Nm

The fixing couple that must be applied to wheel 5 is equal in magnitude and opposite in direction to T2, so it is -20 Nm.

iv) The tangential force at the pitch point between wheels 3 and 4 can be found from the formula:

Ft = (2 x Pd) / (m x z3)

where Pd is the diametral pitch, m is the module, and z3 is the number of teeth on wheel 3.

Substituting the given values:

Pd = 25.4 / 5 = 5.08 teeth/inch

z3 = t3 / m = 30 / 5 = 6 teeth

Ft = (2 x 5.08) / (5 x 6) = 0.846 N

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Starting with an initial speed of 6.00 m/s, a 62.0 kg skier skies down a slope. The speed of the skier at the bottom of the slope is 26.5 m/s. Neglecting friction, determine the height of the slope.

Answers

The height of the slope is 323.6 meters. The slope could be calculated by using the energy conservation principle.

What is friction?

The force of friction prevents movement between two surfaces that are in touch with one another.

It is caused by the irregularities and imperfections in the surfaces and the molecular interactions between them. Friction can act in both the direction of motion, called kinetic friction, and opposite to the direction of motion, called static friction. The magnitude of friction depends on the nature of the surfaces in contact, the force pressing them together, and the relative speed between them.

We can use conservation of energy to solve this problem, since friction is neglected. The total mechanical energy of the system (skier + Earth) is conserved:

KE_i + PE_i = KE_f + PE_f

where PE stands for potential energy and KE for kinetic energy.

At the top of the slope, the skier has only potential energy:

PE_i = mgh

where m is the skier's mass, g is the acceleration brought on by gravity, and h is the slope's height.

KE_f = (1/2)mv²

where v denotes the skier's speed at the slope's base.

Setting the initial and final energies equal to each other, we have:

mgh + 0 = (1/2)mv² + 0

Solving for h, we get:

h = (v²)/(2g) - (1/2)h

Plugging in the given values, we get:

h = (26.5²)/(2*9.81) - (1/2)h

Simplifying and solving for h, we get:

h = 323.6 m

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