Answer: Therefore, the concentration of hydroxide ions [OH-] in the given solution is 4.0 x 10⁻¹⁹M.
We know that In an aqueous solution Kw is the ionization constant of water.
Kw = [H3O⁺][OH⁻]
[OH⁻] = [tex]\frac{Kw}{[H3O^+]}[/tex]--------------------------------------(a)
Kw = ionization constant of water
[H3O⁺]= the concentration of hydronium ions
[OH⁻] = the concentration of hydroxide ions
Kw = 1x10⁻¹⁴M²-------------------(i)
[H3O⁺]= 2.5 x 10⁴M------------------(ii)
[OH⁻] = ?
NOW Putting values in (i) and (ii) in equation (a)
[OH⁻] = [tex]\frac{1 X 10^-^1^4}{2.5 X 10^4}[/tex]
[OH⁻] = 4.0 x 10⁻¹⁹M
The OH concentration in an aqueous solution at 25 °C is 3.3 x 10³.
What is [H*]?
The concentration of hydroxide ions ([OH-]) and the concentration of hydronium ions ([H+]) are related in an aqueous solution by the equation [H+][OH-] = 1.0 x 10^-14 at 25 °C .The concentration of hydronium ions ([H+]) in the aqueous solution at 25 °C is approximately 3.03 x 10^-18.
Given that [OH-] is 3.3 x 10^3, we can substitute this value into the equation as follows:
[H+][3.3 x 10^3] = 1.0 x 10^-14
Dividing both sides of the equation by 3.3 x 10^3, we get:
[H+] = (1.0 x 10^-14) / (3.3 x 10^3)
Simplifying the expression, we have:
[H+] ≈ 3.03 x 10^-18
In summary, at 25 °C, an aqueous solution with an OH- concentration of 3.3 x 10^3 has a hydronium ion concentration of approximately 3.03 x 10^-18. The hydronium ion concentration is determined by the equilibrium constant for water dissociation and is inversely proportional to the hydroxide ion concentration. The two concentrations are related through the equation [H+][OH-] = 1.0 x 10^-14.
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The number of transition elements in the 1, 2" and 3rd transition series... a) 9 b) 30 c) 10 d) 27
Answer: There are
30 elements for the 1st transition series, 10 elements for the 2nd transition series, 3rd transition series is not listed as one of the given options, but it consists of 14 elements.Explanation:
1st transition series: The 1st transition series spans the elements from Scandium (Sc) to Zinc (Zn) in the periodic table.These elements fill the 3d orbitals. Since there are 10 elements in each period of the d-block, the 1st transition series consists of 10 elements. 2nd transition series: The 2nd transition series includes the elements from Yttrium (Y) to Cadmium (Cd) in the periodic table. These elements fill the 4d orbitals. Similar to the 1st transition series, there are 10 elements in each period of the d-block, so the 2nd transition series also consists of 10 elements.3rd transition series: The 3rd transition series includes the elements from Lanthanum (La) to Mercury (Hg) in the periodic table. These elements fill the 5d orbitals. In the 5d orbital, there are a total of 10 elements in each period of the d-block. However, the 3rd transition series does not include all 10 elements of the 5d block. It includes 14 elements from Lanthanum (La) to Lutetium (Lu). Therefore, the 3rd transition series consists of 14 elements.The pH of an acidic solution is 2.83. What is [H*]?
Answer:
0.001464 M, or 1.464 × 10^(-3) M.
Explanation:
[H+] = 10^(-pH)
In this case, the pH of the acidic solution is 2.83. Plugging this value into the equation, we get:
[H+] = 10^(-2.83)
Using a calculator, we can find that 10^(-2.83) is approximately 0.001464.
Therefore, the concentration of hydrogen ions in the acidic solution is approximately 0.001464 M, or 1.464 × 10^(-3) M.
can you explian me about the oxidixer
Explanation:
An oxidizer is a substance that facilitates oxidation, a chemical reaction where a substance loses electrons. It is also called an oxidizing agent or oxidant. Oxidizers are commonly used in combustion reactions, supporting the burning of fuels by providing oxygen. Examples of oxidizers include oxygen, chlorine, hydrogen peroxide, and potassium permanganate. They have applications in combustion, chemical synthesis, bleaching, rocket propellants, and cleaning. Oxidizers can be highly reactive and require proper handling and safety precautions.
The following reactions (note that the arrows are pointing only one direction) can be used to prepare an activity series for the halogens:
Br2(aq)+2NaI(aq)⟶2NaBr(aq)+I2(aq)
Cl2(aq)+2NaBr(aq)⟶2NaCl(aq)+Br2(aq)
A) Predict whether a reaction will occur when elemental chlorine and potassium bromide are mixed.
Express your answer as a chemical equation.
B)Predict whether a reaction will occur when elemental iodine and lithium chloride are mixed.
Express your answer as a chemical equation.
A) The chemical equation for the reaction is [tex]Cl_2(aq) + 2KBr(aq)[/tex] ⟶ [tex]2KCl(aq) + Br_2(aq)[/tex]
B)No reaction occurs when elemental iodine is mixed with lithium chloride. [tex]I_2(aq) + 2LiCl(aq)[/tex]⟶ No Reaction
A) To predict whether a reaction will occur when elemental chlorine ([tex]Cl_2[/tex]) and potassium bromide (KBr) are mixed, we can refer to the activity series for the halogens. According to the activity series, chlorine is more reactive than bromine. Therefore, chlorine can displace bromine from its compounds.
The chemical equation for the reaction between chlorine and potassium bromide can be written as:
[tex]Cl_2(aq) + 2KBr(aq)[/tex] ⟶ [tex]2KCl(aq) + Br_2(aq)[/tex]
In this reaction, chlorine displaces bromine from potassium bromide, resulting in the formation of potassium chloride and elemental bromine.
B) Similarly, to predict whether a reaction will occur when elemental iodine ([tex]l_2[/tex]) and lithium chloride (LiCl) are mixed, we can refer to the activity series. In the halogen activity series, iodine is less reactive than chlorine and bromine. Therefore, it is less likely for iodine to displace chlorine or bromine from their compounds.
The chemical equation for the reaction between iodine and lithium chloride can be written as:
[tex]I_2(aq) + 2LiCl(aq)[/tex]⟶ No Reaction
No reaction occurs because iodine is less reactive than chlorine, and lithium chloride does not react with iodine under these conditions.
Therefore, when elemental chlorine is mixed with potassium bromide, a reaction occurs and chlorine displaces bromine. On the other hand, no reaction occurs when elemental iodine is mixed with lithium chloride.
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