In an experiment 4.5kg of candle was completely burnt. Th e heat produced was measured to be 180.000kj. Calculate the calorific value of the candle.​

Answer:

if u are talking Abt H2O then the shape is vent shaped and angle between both oxygen atoms is 104.5°

Explanation:

I hope the image helps

The mass (in grams) of aluminum chloride that has the same number of aluminum atoms as 3.19 g of aluminum oxide is 8.36 g

First, we shall determine the mass of aluminum, Al present in 3.19 g of aluminum oxide, Al₂O₃. Details below:

102 g of Al₂O₃ contains 54 g of Al

Therefore,

3.19 g of Al₂O₃ will contain = (3.19 × 54) / 102 = 1.69 g of Al

Next, we shall determine the number of atoms in 1.69 g of Al. Details below:

From Avogadro's hypothesis,

1 mole of Al = 6.02×10²³ atoms

But

1 mole of Al = 27 g

Thus,

27 g of Al = 6.02×10²³ atoms

Therefore,

1.69 g of Al = (1.69 × 6.02×10²³) / 27

1.69 g of Al = 3.772×10²² atoms

Finally, we shall determine the mass of aluminum chloride, AlCl₃. Details below:

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of AlCl₃

But

1 mole of AlCl₃ = 133.5 g

Thus,

6.02×10²³ atoms = 133.5 g of AlCl₃

Therefore,

3.772×10²² atoms = (3.772×10²² × 133.5) / 6.02×10²³

3.772×10²² atoms = 8.36 g

Thus, the mass of aluminum chloride, AlCl₃, is 8.36 g

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Answer:

When a copper wire is heated in a Bunsen burner flame, the copper's color changes to become a glowing red. It won't be restored to its original appearance after cooling. Instead, it becomes a black material called copper (II) oxide, which is 79.9% copper and 20.1% oxygen (was 100% copper before it was burned). This chemical change occurred as the oxygen in the air combined with the copper during the heating process.

Explanation:

The evidence that indicates that both physical and chemical changes occur when a copper wire is heated in a Bunsen burner flame are:

The original appearance was not restored when the wire cooled, instead a new substance appears.

The wire changed color during the heating.

A physical change is a type of change in which the form, shape, size, or state of matter of a substance is altered, but the substance itself remains the same chemically. In other words, the composition of the substance does not change.

Examples of physical changes include changes of state (such as melting, freezing, or vaporization), changes in shape or size (such as crushing or cutting), and changes in appearance (such as changing color or texture).

A chemical change involves breaking or making of chemical bonds. This include formation of a new compounds and some color changes. Therefore,

The original appearance was not restored when the wire cooled, instead a new substance appears, states a physical change and

The wire changed color during the heating indicates a chemical change.

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The bird's potential energy is 2,802.8 J.

The potential energy of an object is the energy it has due to its position in a gravitational field. The formula for potential energy is as follows:

  PE = m × g × h

Where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.

In this case, the mass of the bird is 0.52 kg, the acceleration due to gravity is 9.8 m/s², and the height is 550 meters. Plugging these values into the formula, we get:

  PE = 0.52 kg × 9.8 m/s² × 550 m

  PE = 2,802.8 J

Therefore, the potential energy of the bird is 2,802.8 joules.

Your question seems incomplete. The completed version should be as follows:

A 0.52 kg bird flying at an altitude of 550 meters. What is the bird's potential energy?

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The molarity of both Li+ and SO42- ions in a 0.611 M solution of Li2SO4 is 1.22 M.

Lithium sulfate is a white inorganic salt with the formula Li₂SO₄.

When lithium sulfate (Li2SO4) dissolves in water, it dissociates into Li+ and SO42- ions:

Li2SO4(s) → 2 Li+(aq) + SO42-(aq)

If we assume that Li2SO4 dissociates completely in solution, then we can calculate the molarity of the Li+ and SO42- ions separately.

For Li+, we can use the stoichiometry of the dissociation reaction to see that the concentration of Li+ ions is twice the concentration of Li2SO4:

[L i⁺] = 2 × [Li₂SO4] = 2 × 0.611 M = 1.22 M

For SO42-, we also need to take into account that each formula unit of Li2SO4 produces two SO42- ions. Therefore, the concentration of SO42- ions is twice the concentration of Li2SO4:

[SO4²⁻] = 2 × [Li₂SO4] = 2 × 0.611 M = 1.22 M

So the molarity of both Li+ and SO42- ions in a 0.611 M solution of Li2SO4 (assuming complete dissociation) is 1.22 M.

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The volume of 0.800 M NaOH solution required to reach the third equivalence point is 67.5 mL

The volume of 0.333 M NaOH solution required to reach the second equivalence point is 156 mL

From the question, we are to determine the volume of NaOH required to reach third equivalence point

Question 1:

The third equivalence point is reached when all three hydrogen ions (H+) in phosphoric acid have reacted with hydroxide ions (OH-) from the sodium hydroxide solution.

From the given balanced equation,

Each molecule of phosphoric acid reacts with three molecules of sodium hydroxide, we can calculate the number of moles of sodium hydroxide required to reach the third equivalence point as follows:

Number of moles =Concentration × Volume

Number of moles of H3PO4 = 0.250 M x 0.0720 L = 0.0180 mol

Number of moles of NaOH required = 3 x 0.0180 mol = 0.0540 mol

Now, we can calculate the volume of the 0.800 M NaOH solution required to supply 0.0540 mol of NaOH:

Volume of NaOH = 0.0540 mol / 0.800 M = 0.0675 L = 67.5 mL

Hence, 67.5 mL of the 0.800 M NaOH solution is required.

Question 2:

The second equivalence point is reached when all the hydrogen ions (H+) in two molecules of oxalic acid dihydrate have reacted with two molecules of hydroxide ions (OH-) from the sodium hydroxide solution. Since each molecule of oxalic acid dihydrate reacts with two molecules of sodium hydroxide, we can calculate the number of moles of sodium hydroxide required to reach the second equivalence point as follows:

Number of moles of H2C2O4•2H2O = 0.400 M x 0.0650 L = 0.0260 mol

Number of moles of NaOH required = 2 x 0.0260 mol = 0.0520 mol

Now, we can calculate the volume of the 0.333 M NaOH solution required to supply 0.0520 mol of NaOH:

Volume of NaOH = 0.0520 mol / 0.333 M = 0.156 L = 156 mL

Hence, 156 mL of the 0.333 M NaOH solution is required

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Answer:

1.  It describes the number of atoms in 1 mole of an element.

2. 195.08 g Pt / 195.08 g/mol = 1 mol Pt

   1 mol Pt x 6.022 x 10^23 atoms/mol = 6.022 x 10^23 atoms

    The correct answer is: 6.022×10^23 atoms

3. Cu: 63.546 g/mol

  S: 32.065 g/mol

   O (4 atoms): 4 x 15.999 g/mol = 63.996 g/mol

   Molar mass of CuSO4 = 63.546 + 32.065 + 63.996 = 159.607 g/mol

    The correct answer is: 159.607 g/mol

Answer:

Filtration

Explanation:

FILTRATION = A technique that uses a porous barrier to separate a solid from a liquid.

The balanced equation for the given reaction is Cu[tex]_2[/tex]SO[tex]_4[/tex] + Ba(NO[tex]_3[/tex])[tex]_2[/tex] →2CuNO[tex]_3[/tex]+ BaSO[tex]_4[/tex]. The precipitates that result from it are these insoluble salts.

Chemical reactions known as precipitation reactions take place in aqueous solutions to produce precipitates. Moreover, chemical changes that occur inside the substances are a part of chemical processes. Hence, under some circumstances, it creates an entirely novel element.

It denotes a chemical process in which two ions combine to generate insoluble salts in aqueous solutions. The precipitates that result from it are these insoluble salts. Single displacement reactions and double displacement reactions are also possible.

a)The balanced equation for the given reaction is

Cu[tex]_2[/tex]SO[tex]_4[/tex] + Ba(NO[tex]_3[/tex])[tex]_2[/tex] →2CuNO[tex]_3[/tex]+ BaSO[tex]_4[/tex]

b) moles of Ba(NO[tex]_3[/tex])[tex]_2[/tex] = 0.02×0.2=0.04moles

The mole ratio between Ba(NO[tex]_3[/tex])[tex]_2[/tex] and BaSO[tex]_4[/tex] is 1:1

moles of BaSO[tex]_4[/tex]= 0.04moles

Therefore, the balanced equation for the given reaction is

Cu[tex]_2[/tex]SO[tex]_4[/tex] + Ba(NO[tex]_3[/tex])[tex]_2[/tex] →2CuNO[tex]_3[/tex]+ BaSO[tex]_4[/tex]

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Answer:

14

Explanation:

If a solution is able to conduct electricity,ionic compounds must be dissolved in it as it will generate ions.

An ion is defined as an atom or a molecule which has a net electrical charge. There are 2 types of ions :1) cation 2) anion . The cation is the positively charged ion and anion is the negatively charged ion . As they are oppositely charged they attract each resulting in the formation of ionic bond.

Ions consisting of single atom are mono-atomic ions while which consists of two or more ions are called as poly-atomic ions . They are created by chemical interactions . They are very reactive in their gaseous state and rapidly react with oppositely charged ions resulting in neutral molecules.

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The compound Li₂SO₄ on dissociation gives two moles of Li+ ions and one mole of SO₄ ²⁻ ions. Then the molarity of SO₄ ²⁻ is 0.611 M itself and the molarity of Li+ ions is 1.22 M.

Molarity of a solution is the ratio of  number of moles of solutes in that solution to the volume of solution in liters. It is a colligative property and depends on the amount of solute and solvent.

Molarity = n/V in L.

Given that, the molarity of Li₂SO₄ solution is 0.611 M. The complete dissociation of this compound is written as follows:

[tex]\rm Li_{2}SO_{4} \rightarrow 2 Li^{+} +SO_{4}^{2-}[/tex]

Here, the ionization of the compound produces 2 moles of Li+ and one mole of sulphate ions. Then, the molarity of the sulphate ions is the same as the whole solution that is 0.611 M.

Then molarity of the Li+ ions in the solution will be 1.22 M.

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The percent by mass of hydrogen in NH3 is 82.4%.

To find out the number of moles of hydrogen in 34 grams of NH3, first we need to find the number of moles of NH3 which can be calculated by dividing 34 grams by the molar mass of NH3 (17.0 grams/mol). Therefore, the number of moles of NH3 is 2 moles. As NH3 contains 3 moles of hydrogen per mole, the number of moles of hydrogen in 34 grams of NH3 is 2 x 3 = 6 moles.

Molecular mass of NH3 = 1 x atomic mass of N + 3 x atomic mass of H

= 1 x 14.01 + 3 x 1.01

= 17.03 g/mol

Mass percent of hydrogen in NH3 = (3 x atomic mass of H) / molecular mass of NH3 x 100%

= (3 x 1.01 g/mol) / 17.03 g/mol x 100%

= 82.4%

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Answer:

NaClO4

Explanation:

The empirical formula for a compound with 18.8% Na, 29.0% Cl, and 52.3% O is NaClO4. This means that the compound contains one atom of sodium, one atom of chlorine, and four atoms of oxygen.

The volume of 5.50 moles of CO2 at STP is 120.02 liters.

To calculate the volume of 5.50 moles of CO2 at standard temperature and pressure (STP), we need to use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (0 degrees Celsius). The gas constant is 0.08206 L•atm/mol•K.

So we can plug in the values and solve for V:

V = nRT/P = (5.50 mol)(0.08206 L•atm/mol•K)(273.15 K)/(1 atm) = 120.02 L

Therefore, the volume of 5.50 moles of CO2 at STP is 120.02 liters.

Standard temperature and pressure (STP) is a set of standard conditions used for measuring and comparing the properties of gases. STP is defined as a temperature of 273.15 Kelvin (0 degrees Celsius) and a pressure of 1 atmosphere (atm). These standard conditions allow scientists to compare the behavior of gases under the same set of conditions, making it easier to compare and contrast the properties of different gases.

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The number of moles is 123.2 moles

To find the volume of a substance from its number of moles, you will need to know its molar volume, which is the volume occupied by one mole of a substance. The molar volume can vary depending on the temperature and pressure, so you will need to specify these conditions.

The formula to calculate the volume of a substance from its number of moles is:

Volume = Number of moles x Molar volume

We know that;

1 mole occupies 22.4 L

5.5 moles occupies 5.5 moles  * 22.4 L/1 mole

= 123.2 moles

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The highest levels of atp are produced through the glycolysis Krebs (a) process.

By means of chemiosmosis, oxidative phosphorylation generates ATP using energy from the movement of electrons in an electron transport system. Only one proton (H+) and one electron are present in a hydrogen atom. Potential energy, or stored energy, is available to do work in electrons. A glucose molecule needs two ATP molecules to be completely phosphorylated. When glucose is phosphorylated to fructose 1,6-diphosphate in glycolysis, two molecules of ATP are used up.

A biological process called phosphorylation involves the addition of phosphate to an organic molecule. For two examples, adding phosphate to glucose will result in glucose monophosphate or adding it to adenosine diphosphate (ADP) will result in adenosine triphosphate (ATP).

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Answer:

a. The overall balanced chemical equation for the reaction is: 3O3 → 3O2 + O b. The intermediate in the mechanism is O3. c. The order of the reaction is first order with respect to O3 and second order with respect to O. d. The rate law for the overall reaction is rate = k[O3]^1[O]^2.

The density of the liquid is 0.87 g/mL. This liquid would be located in the "less dense than water" column since the density is less than 1 g/mL.

Density is a measure of mass per unit volume. It is used to measure the concentration of matter in a given space. The SI unit of density is kg/m3, although other units such as g/cm3 may also be used. The density of an object can be determined by dividing its mass by its volume. Density is an important physical property that affects how materials interact with each other, as well as how they interact with light and sound. For example, a denser material will be more likely to sink in a liquid. Additionally, higher density materials will generally be more durable than lower density materials. Density is also an important factor in understanding the behavior of fluids and gases.

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As the quantum numbers depend on the number of energy levels in an atom there are 2 quantum numbers for helium owing to it's 2 electrons.

Electrons present in an atom revolve in different orbits which are stationary states and are also called as energy levels. The energy levels are numbered as integers which are also called as principal quantum numbers.

Energy of the stationary state is given as E= -R

1/n² where R

is the Rydberg's constant. When an electron is excited, and it moves from lower to higher energy levels there is absorption of energy, while when it moves from higher energy level to lower energy level it radiates or gives out energy in the form of radiation.

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The mass of sliver deposited at the cathode during the electrolysis of Nitrate (AgNO₃) solution is 0.0011 gram.

The term electrolysis is defined as a chemical reaction that happens when an electric current is pass over through a substance. The substance gets or loses an electron during chemical reaction.

Given:

Current = 0.10 ampere

Tome = 10 second

Molar mass of Ag = 108 g mol−1

1 Faraday = 96500 C

Q = i × t

=0.1 × 10 × 60

= 60 Coulombs

Weight of the substance deposited = ZQ

Z=M/nF​

n-factor of AgNO3 ​= 1

Z = 108 / 1 × 96500

= 0.0011 gram

Thus, 0.0011 gram is the mass of Sliver deposited at the Cathode during the electrolysis of Nitrate (AgNO₃) Solution.

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Your question is incomplete, most probably your question was

Calculate the mass of Sliver deposited at the Cathode during the electrolysis of Nitrate (AgNO3) Solution,use a current of 0.10 ampere for 10 minutes.

The molar concentration of the solution prepared by diluting it from 10 ml to 50 ml is 0.0004000 mol/L.

In order to calculate the molar concentration of the diluted solution, firstly we need to know the molar concentration of the original solution and its dilution factor. The dilution factor is the ratio of the final volume to the initial volume. The dilution factor can be calculated here :

dilution factor = final volume / initial volume

dilution factor = 50.00 ml / 10.0 ml

dilution factor = 5.00

The molar concentration of the diluted solution can be calculated by using the formual  M1V1 = M2V2

Here M1 is the initial molar concentration, V1 is the initial volume of the solution, M2 is the final molar concentration, and V2 is the final volume.

Putting the values we have in the equation M1V1 = M2V2.

M1 = the molar concentration of the original solution is unknown.

V1 = 10.0 ml

M2 = the molar concentration of the diluted solution is unknown.

V2 = 50.00 ml

Using this formula and solving for M2, we get:

M2 = M1V1 / V2

Since, we do not know the initial molar concentration,  M2 can not be calculated directly. But, we do know that the number of moles of solute is the same before and after the dilution. Therefore, we can use the following equation:

n = M1V1 = M2V2, where n is the number of moles of solute.

n = M1V1

M1 = n / V1

after putting in the given values :

n = M1V1

M1 = n / V1 = (10.0 ml / 1000.0 ml/L) x (0.2000 mol/L)

M1 = 0.002000 mol

Since we know the initial molar concentration now, we can use the formula M2 = M1V1 / V2 to find the molar concentration of the diluted solution,

M2 = M1V1 / V2 = (0.002000 mol/L) x (10.0 ml / 50.00 ml)

M2 = 0.0004000 mol/L

Hence, the molar concentration of the solution diluted from 10 ml to 50 ml is calculated out to be 0.0004000 mol/L.      

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As the wind slows, silt is deposited because the wind has less energy.

Deposition in rivers and streams. A stream or river begins to deposit silt when it begins to slow down. In steep terrain, larger sediments fall, but smaller sediments can still be carried. As the slope gets less steep, smaller sediments are dropped.

Sediment that has been eroded is deposited in a new location when the speed of the wind or water slows. Fertile land is produced as a result of the sedimentation process.

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The concentration of carbonyl fluoride (COF2) remains at equilibrium is 0.33M if only COF2 is present initially at a concentration of 2.00 M.

The reaction given is an equilibrium reaction, and so the reaction can be expressed in terms of the equilibrium constant (Kc).

The equilibrium constant (Kc) for the reaction is given as = 5.10.

[tex]2COF2(g) ,--- > CO2(g)+CF4(g)[/tex]

For an equilibrium reaction, the equilibrium concentration of the reactants can be determined using the following equation:

[tex]Kc = [CO2][CF4]/[COF2]^2[/tex] Where [CO2], [CF4], and [COF2] are the equilibrium concentrations of the respective species.

Rearranging the equation gives us the following expression:

[tex][COF2]^2 = [CO2][CF4]/Kc[/tex]

ICE chart is :

         [tex]2COF2(g) < -- > CO2(g) + CF(g)[/tex]

I                2                           0           0

C              -2x                       +x         +x

----------------------------------------------------------

E              2-2x                       x            x

Plugging in the values given, we can calculate the equilibrium concentration of COF2:

[tex]Kc = (x)(x)/(2-2x)^2[/tex]

[tex]6.40 = x^2/(2-2x)^2[/tex]

Taking the square root of both sides, we can calculate the equilibrium concentration of COF2:

x = 0.835M

[COF2] = 2-2x =2 -2(0.835) = 0.33M

Therefore, if only COF2 is present initially at a concentration of 2.00 M, the concentration of COF2 at equilibrium will be 0.33 M.

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complete question: Carbonyl fluoride, COF2 , is an important intermediate used in the production of fluorine-containing compounds. For instance, it is used to make the refrigerant carbon tetrafluoride, CF4 via the reaction 2COF2(g)⇌CO2(g)+CF4(g), Kc = 6.40 . If only COF2 is present initially at a concentration of 2.00 M, what concentration of COF2 remains at equilibrium?

Taking into account the definition of Avogadro's Number, 1.38529×10²¹ molecules in 0.0023 mole of CO₂ .

Avogadro's number is defined as the number of particles (atoms, molecules, ions, electrons) in 12 grams of carbon-12, that is, in one mole of the substance or compound.

Its value is 6.023×10²³ particles per mole and it applies to any substance.

Considering the definition of Avogadro's number, you can apply the following rule of three: If 1 mole of CO₂ contains 6.023×10²³ molecules, 0.0023 mole of CO₂ contains how many molecules?

amount of molecules of CO₂= (0.0023 moles × 6.023×10²³ molecules)÷ 1 mole

amount of molecules of CO₂= 1.38529×10²¹ molecules

Finally, there are 1.38529×10²¹ molecules.

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A rock that begins with   4000 atoms of a radioactive isotope would have the following remain;

A. After one half-life, 2000 atoms would remain.

B. After two half-lives, 1000 atoms would remain.

C. After three half-lives, 500 atoms would remain.

D. After four half-lives, 250 atoms would remain.

If 25% of the isotope remains, that means 75% has decayed. Since each half-life represents 20 million years, two half-lives (40 million years) would result in 25% of the original isotope remaining, and therefore four half-lives (80 million years) would result in 6.25% of the original isotope remaining. Therefore, the rock must be older than 40 million years but younger than 80 million years. Since the answer choices only include 40 million years and 60 million years, the closest answer is C, 40 million years.

Each rock has decayed 50% of its radioactive element, which means they have all undergone the same amount of decay. However, since each isotope has a different half-life, the amount of time it takes to undergo 50% decay will be different. The rock dated with isotope C has the longest half-life, and therefore has undergone the least amount of decay and must be the oldest.

Carbon-14 dating is the best choice for dating organic materials, such as cotton cloth.

Using the half-life of Carbon-14 (5730 years), we can calculate the age of the burial site using the formula t = (ln(0.167) / ln(0.5)) x 5730. This results in an age of approximately 14,798 years.

The best way to obtain an absolute date for the sequence of rocks would be to date the volcanic ash layer using a radiometric dating method such as Uranium dating, which would provide an age for the time at which the ash was deposited. This age could then be used to bracket the ages of the sedimentary rocks above and below the ash layer.

Conclusively,  Using the half-life of the parent isotope, we can calculate the age of the sequence of rocks using the formula t = (ln(0.783) / ln(0.5)) x length of the half-life. Since we don't know the specific isotope being used, we can't calculate the exact age, but the closest answer choice is E, 1.588 billion years.

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The solutions for both are:

V_titanium = (1/4) V_total ≈ 0.188 cm³

And

V_iron = (3/4) V_total ≈ 0.565 cm³

We have a line in the V_titanium-V_iron plane with slope -4.5/7.87 and y-intercept 5/7.87. The two solutions above correspond to the points where this line intersects the line V_titanium = 0 and V_iron = 0, respectively.

The volume of titanium and iron in a bicycle can be related using the following constraint equation:

V_titanium * 4.5 + V_iron * 7.87 = M_total / 1000

where V_titanium and V_iron are the volumes of titanium and iron in cubic centimeters (cm³), M_total is the total mass of the bicycle in grams (g), and we divide by 1000 to convert the mass to kilograms.

We are given that the bicycle weighs 5 kg or 5000 g, so we can substitute M_total = 5000 into the equation:

V_titanium * 4.5 + V_iron * 7.87 = 5000 / 1000

4.5 V_titanium + 7.87 V_iron = 5

This is a linear equation in two variables, V_titanium and V_iron. To find two solutions, we need one additional equation that relates V_titanium and V_iron. One possibility is to assume that the bicycle contains a fixed ratio of titanium to iron, say 1:3. Then we can write:

V_titanium = (1/4) V_total

V_iron = (3/4) V_total

where V_total is the total volume of the bicycle, which is the sum of the volumes of titanium and iron:

V_total = V_titanium + V_iron

Substituting these expressions into the constraint equation and simplifying, we get:

(4.5/4) V_total + (7.87/4) V_total = 5/2

3.31 V_total = 5/2

V_total = (5/2) / 3.31

V_total ≈ 0.753 cm³

Using the ratios above, we can then calculate the volumes of titanium and iron:

V_titanium = (1/4) V_total ≈ 0.188 cm³

V_iron = (3/4) V_total ≈ 0.565 cm³

These are the two solutions for the volumes of titanium and iron in the bicycle, assuming a fixed ratio of 1:3.

To graph the constraint equation, we can solve for V_iron as a function of V_titanium:

V_iron = (5 - 4.5 V_titanium) / 7.87

This gives us a line in the V_titanium-V_iron plane with slope -4.5/7.87 and y-intercept 5/7.87. The two solutions above correspond to the points where this line intersects the line V_titanium = 0 and V_iron = 0, respectively.

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PV = nRT is the equation used in this experiment's calculations to find the molar volume of an ideal gas.

Ideal gas is a theoretical gas composed of a set of randomly-moving, non-interacting point particles that obey certain mathematical equations. It is assumed that the particles of an ideal gas have no volume, no inter-particle forces, and that the pressure, volume, and temperature are related by the ideal gas law. Ideal gas behaviour is an approximation of the behaviour of real gases under many conditions, and is widely used in the field of thermodynamics and statistical mechanics.

This equation states that the product of pressure and volume is equal to the number of moles of the gas multiplied by the gas constant and the temperature of the gas.

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Complete Question

which of the following equations is used in this experiment's calculations to find the molar volume of an ideal gas? group of answer choices
A) PV = nRT
B) V = nRT/P
C) Both A and B
D) None to these

Keep in mind that concentration (mol/L) = (# of moles) / (volume (L) )

Find the volume in litres is easy: 25.0mL + 55.5mL = 80.5 mL = 0.0805 L

Now we have to find the number of moles of Chlorine (Cl) moles of Cl in 25.0mL of NH4Cl = (25.0mL)(1 L/1000mL)(0.2450mol NH4Cl/1L)(1 mol Cl/1 mol NH4Cl) = 0.006125 mol

Cl moles of Cl in FeCl3= (55.5mL)(1 L/1000mL)(0.1655mol FeCl3/1 L)(3 mol Cl/ 1 mol FeCl3) = 0.02755575 mol Cl

Total moles Cl = 0.006125 + 0.02755575 = 0.03368075 mol Cl

Concentration = (0.03368075/0.0805) = 0.418 mol/L Cl

What is concentration of solutions?

The amount of solute that has been dissolved in a specific volume of solvent or solution is measured by the solution's concentration. A solution that contains a significant amount of dissolved solute is said to be concentrated. A solution is said to be dilute if it only contains a small amount of dissolved solute.

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