in the following questions you will be asked to rank these rods. if multiple rods rank equallly use the same rank for each then exclude the intermediate ranking

The x-coordinate of the shell where it explodes, relative to its firing point, is approximately 7688.1 meters, and the y-coordinate is approximately 9507.8 meters.

If an automobile is at rest, its beginning velocity is 0.The starting velocity of an automobile that stops after using the brakes will be greater than zero, but the ultimate velocity will be zero.

The kinematic equations of motion can be used to resolve this issue.We can break down the initial velocity into its x- and y-components:

Vx = V0 cosθ = (300 m/s) cos(55.5°) ≈ 163.3 m/s

Vy = V0 sinθ = (300 m/s) sin(55.5°) ≈ 247.2 m/s

Next, we can use the equations of motion to find the shell's position after 47.0 seconds. The x-coordinate is given by:

x = Vx t = (163.3 m/s)(47.0 s) ≈ 7688.1 m

The y-coordinate is given by:

y = Vy t + (1/2)gt²= (247.2 m/s)(47.0 s) + (1/2)(9.81 m/s²)(47.0 s) ≈ 9507.8 m

where g is the acceleration due to gravity.

To know more about initial velocity visit:-

https://brainly.com/question/9163788

#SPJ1

A rock weighing 1 kilogramme is thrown from a distance of six metres.  height is the difference between the rock's kinetic and potential energy?

People have figured out how to transform energy from one type to another and use it to accomplish tasks, making modern civilization possible.

In a wide range of disciplines, including physics and the social sciences, the phrase is used to denote objects that are capable of changing

To know  more about energy visit :

https://brainly.com/question/1932868

#SPJ4

The dangling mass will not move and the puck will keep rotating in its orbit, Therefore, V = √(mgR/M)  will be an algebraic expression that includes the variables mentioned above.

A centripetal force that causes a body to travel along a curved path. The centripetal force always acts orthogonally to the motion of the body and towards the fixed point of the path's instantaneous centre of curvature. Isaac Newton described it as "a force by which bodies are drawn or impelled, or in any way tend, towards a point as to a centre". Gravity is the centripetal force that causes astronomical orbits, according to Newtonian mechanics theory.

A common example of centripetal force is when a body moves at a constant speed along a circular path. The centripetal force is directed at right angles to the motion as well as along the radius of the circular path towards the centre.

Fc = mg

Now, centripetal force on the puck is equal to the mass of the puck times the centripetal acceleration, or

Fc = Mac

centripetal acceleration is related to the tangential velocity of the puck as

ac = V²/R

where R is the radius of the orbit. Then we have

Fc = M ac =M ω² R = M V² / R

and, thus

M V² / R = mg

and, solving for V, we get

V = √(mgR/M)

Learn more about centripetal force

https://brainly.com/question/14249440

#SPJ1

The weight and normal force are the only two forces acting on the hockey puck vertically; however, because the puck is travelling at a constant speed, there are no forces acting on it horizontally.

A force known as the "normal force" is felt when an object is placed on a surface and pressed against it by that surface.

We come into contact with the usual force every day. When we place a book on a table, for instance, the usual reaction force stops it from falling through.

To know more about normal force visit:

https://brainly.com/question/13622356

#SPJ1

The resolving power of the microscope is approximately 0.196 μm when using the oil immersion lens.

What is Aperture?

In optics, the aperture refers to the opening or hole in an optical system through which light passes. It is typically a circular or rectangular opening that can be adjusted to control the amount of light that enters the system. The aperture size affects various properties of the optical system, such as the depth of field, the amount of light that reaches the sensor or film, and the resolving power or sharpness of the resulting image. The numerical aperture (N.A.) is a related term that describes the ability of an optical system to gather light, and it is determined by the size of the aperture and the refractive index of the medium through which light passes.

To calculate the resolving power (R.P.) of the microscope, we can use the formula:

R.P. = wavelength / (2 * N.A.)

where wavelength is the average wavelength of visible light, and N.A. is the numerical aperture of the objective lens.

Given that the average wavelength of visible light is 0.55 μm (micrometers), and assuming we are using an oil immersion lens, which typically has a numerical aperture of around 1.4, we can plug in these values and solve for R.P.:

R.P. = (0.55 μm) / (2 * 1.4)

R.P. = 0.196 μm

Therefore, the resolving power of the microscope is approximately 0.196 μm when using the oil immersion lens.

Learn more about Aperture from given link

https://brainly.com/question/1771913

#SPJ1

Two environmental changes that can cause the mantle at point X to begin partial melting are heat and pressure reduction.

Pressure reduction is a process that occurs when the pressure of an object or material is decreased. This can be done in a variety of ways, such as by using a pressure-reducing valve, increasing the area of a pipe, or using a compressor to reduce the pressure of a gas or liquid.

1. Low High Low

2. High Pinbr

3. Low High Low

4. High Low

5. The liquid/solid line would move to the right, indicating an increase in solidus temperature. This type of melting occurs at subduction zones.

6. No Melt

1. According to the continental geothermal gradient, rocks buried 80 km beneath a continent would normally be heated to about 1400 °C.

2. According to the oceanic geothermal gradient, rocks buried 80 km beneath an ocean basin would normally be heated to about 1000 °C.

3. The mantle rock at point X is a mass of solid, as indicated by the fact that it is below the solidus line.

4. If heated to 1750 °C, the mass of mantle at point X would remain a solid.

5. If heated to 2250 °C, the mass of mantle at point X would begin to partially melt.

6. a. At its current temperature, the mantle at point X will begin to melt at a depth of about 50 km and a pressure of about 10,000 atm.

b. The name applied to this kind of melting is decompression

To learn more about pressure reduction

https://brainly.com/question/28705060

#SPJ1

Always keep in mind that the problem will be divided into horizontal motion and vertical motion if a projectile is discharged at an angle.

A projectile is any object that is sent into orbit with only gravity acting upon that. The projectile is mostly affected by gravity. This doesn't mean that other forces don't have an impact; it just means that they have a much smaller one compared to gravity.

We can determine the duration of flight by solving the vertical motion equations. The range is then determined by applying the equations for horizontal motion. We must resolve the system of both equations in your inquiry.

I utilise the following three kinematic motion equations to address practically any projectile motion issue:

S=Vit+12at2

————--eqn 1

Vf=Vi+at

—————eqn 2

combine the equation 1 and 2 to eliminate “t” gives

V2f−V2i=2aS

—————eqn 3

Always watch your signs in these equations. Velocities are up = positive, down = negative and the acceleration due to gravity always points down so ay=−9.81ms2.

Moreover, S is negative if indeed the finishing position is lower than the initial position. S=0 in response to your query because it lands at the identical height.

Vertical Motion:

Let's use an equation without final velocity as we typically don't know it:

S=Vit+12at2

I’ll add subscripts to indicate vertical direction:

Sy=(Vi)yt+12ayt2

0=(Vsin40)t+12(−9.81)t2

cancel “t” in all terms gives

0=Vsin40+12(−9.81)t

or

2Vsin40=9.81t

—— equation 1

Horizontal Motion:

Sx=(Vi)xt+12axt2

but air resistance is negligible so ax=0

Sx=(Vi)xt

25=(Vcos40)t

or

t=25Vcos40

—— equation 2

Substitute equation 2 into equation 1:

2Vsin40=9.81(25Vcos40)

or

V2=(9.81)(25)2sin40cos40

V=15.8ms

Maximum Height:

At maximum height, velocity = 0

(Vf)2y−(Vi)2y=2aySy

0−(15.78sin40)2=2(−9.81)Sy

Sy=5.24m

To know more about Projectile visit:

https://brainly.com/question/11422992

#SPJ4

A) At the bottom, normal force is minimum so, Nbottom = mvb²/R - mg

B) At the top, normal force is maximum so, Ntop = mvt²/R + mg

A) When you are passing the bottom of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the bottom of the loop, the net force on you is equal to the force of gravity, and it acts towards the centre of the loop, providing the centripetal force required to keep you moving in a circular path.

The normal force, N, is the force exerted by the seat on you, perpendicular to the surface of the seat. Gravity's energy, mg, operates vertically downward. Therefore, we write,

Nbottom + mg = Fnet = mvb²/R  

where,

R is radius of the loop

vb is the speed at the bottom of the loop

Nbottom = mvb²/R - mg

B) When you are passing the top of the loop, the normal force that the seat exerts on you can be compared to the force that Earth exerts on you. At the top of the loop, the net force on you is again equal to the force of gravity, but it acts downwards, providing the centripetal force required to keep you moving in a circular path.

The normal force, N, is still perpendicular to the surface of the seat. Gravity's energy, mg, operates vertically downward. Therefore, we can write:

The normal force is at its lowest point at the bottom of the loop and is equivalent to,

Ntop + mg = Fnet = mvt²/R

where,

vt is the speed at the top of the loop

At the top of the loop, the normal force is at a maximum, and it is equal to,

Ntop = mvt²/R + mg

The question is incomplete. The complete question is 'You ride a roller coaster with a loop-the-loop.A) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the bottom of the loop. Express your answer in terms of R (radius of the loop), vb (speed at the bottom of the loop), and constant g.B) Compare the normal force that the seat exerts on you to the force that Earth exerts on you when you are passing the top of the loop. Express your answer in terms of R (radius of the loop), vt (speed at the top of the loop), and constant g.'

To know more about force:

https://brainly.com/question/20343879

#SPJ4

Answer:

1. Y = [tex]\frac{P*L}{Y}[/tex] = ((1.61 × 10⁸) × 0.47) ÷ 1.8 × 10¹⁰

   Y = 4.20Ε17 mm

2. P = F/A

   F = m×g = 68 ×9.8 = 666.4N

   A = (2 · (0.04)² = 0.0032²

   P = 666.4 ÷ 0.0032 = 208250 Pa

3. Psi = 208250 ÷ 6894.76

   Psi = 30.20 lb/in²

4. Δp = 2 × mass × velocity

   Δp = 2 × 0.005 × 11.7 × sin32 = 0.0620 kgm/s

   Δp = 578 × 0.0620 = 35.83 kgm/s

   F = Δp/Δt = 35.83 ÷ 84

   F = 0.4266N

5. P = F/A = 0.4266 ÷ 0.828

   P = 0.515244 N/m²

**(I'll add the last few later)**

The book will weigh 1 pound when it is twice as far from the center of the Earth as when it was on the surface.

The weight of an object depends on its mass and the gravitational force acting on it. Near the surface of the Earth, the gravitational acceleration is approximately 9.8 m/s^2. We can use the inverse square law to calculate the gravitational force on the book when it is twice as far from the center of the Earth than when it was on the surface:

F = G * (m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant, m1 is the mass of the Earth, m2 is the mass of the book, and r is the distance between the center of the Earth and the book.

Since the mass of the book remains the same, the weight of the book on the surface of the Earth is simply the force of gravity acting on it:

W = m * g

where W is the weight of the book, m is its mass, and g is the gravitational acceleration near the surface of the Earth.

When the book is twice as far from the center of the Earth, the gravitational force on it is:

F' = G * (m1 * m2) / (2r)^2 = F / 4

Therefore, the weight of the book when it is twice as far from the center of the Earth is:

W' = (m * g) * (F' / F) = (m * g) * (1/4) = 1 pound

So the book would weigh one pound when it is twice as far from the center of the Earth than when it was on the surface.

More on the weight of objects in space can be found here: https://brainly.com/question/12378369

#SPJ1

The spring, damper, and mass make up this system's model. The linear elasticity of the tow cable is represented by the spring.

The fishing boat's viscous drag and wave are represented by the damper. The fishing boat itself is represented by the mass.

b) The following expression can be used to represent the fishing boat's velocity over time:

                       V(t) = V₀ + [Ft - (10,000/m) ×Vt]/M,

where V₀ is the fishing boat's initial velocity, Ft is the cable force, and M is the boat's mass.

c) When the fishing boat's velocity equals the tow ship's velocity, the cable experiences its maximum force.

This occurs at t=0, and the force in the cable is 196,200 N.

d) The fishing boat's drag causes the tow cable to elongate by 0.03 m at t=0.

e) The stiffness of the cable should be 196,200 N/0.03 m to ensure that the fishing boat reaches the tow ship's velocity as quickly as possible without oscillating.

The rate of change in an object's position in a particular direction is measured by its velocity. Because it is a vector quantity, it has a magnitude (also known as speed) and a direction. Using the derivative of the object's position over time, velocity can be determined. The calculation of a particle's or object's motion over time frequently makes use of velocity.

Learn more about Velocity :

brainly.com/question/29523095

#SPJ1

Answer:

30.41 m/s

Explanation:

To solve this problem, we can use vector addition. We can represent the velocity of the plane as a vector pointing north with a magnitude of 30 m/s, and the velocity of the wind as a vector pointing east with a magnitude of 5 m/s.

The speed of the airplane is the magnitude of the resultant vector, which is the vector sum of the velocity of the plane and the velocity of the wind. To find the magnitude of the resultant vector, we can use the Pythagorean theorem:

magnitude of resultant vector = sqrt((30 m/s)^2 + (5 m/s)^2) = sqrt(900 m^2/s^2 + 25 m^2/s^2) = sqrt(925 m^2/s^2) = 30.41 m/s

Therefore, the speed of the airplane is approximately 30.41 m/s.

The more frictional force is acting on greater mass. Hence, less it will be accelerated to significant distance. So that in case 1 with small mass will slide farthest.

Friction is the resistive force that hinder the motion of an object. It just opposes the normal force of an object. Thus, frictional force will have a negative sign always.

The force of exerted on an object is directly proportional to its mass. Hence, the greater the mass of the object, greater force is needed to apply to accelerate the object.

Here, to slide the larger mass, the frictional force is greater than that for the first case. However, the small mass can be moved to slide the surface furthest. Hence case 1 is correct.

Find more on friction:

https://brainly.com/question/28356847

#SPJ1

Answer:

≈ 3 m/s

Explanation:

To express the speed which is given in km/h to m/s, we can simply individually change from km to m and h to s.

We know that 1 kilometer = 1000 meters and that 1 hour = 3600 seconds. Therefore:

[tex]\displaystyle{10 \cdot \dfrac{1000 \ \: \text{m} }{3600 \ \: \text{s}}}\\\\\displaystyle{=10 \cdot \dfrac{10 \ \: \text{m} }{36\ \: \text{s}}}\\\\\displaystyle{=\dfrac{100 \ \: \text{m} }{36 \ \: \text{s}}}\\\\\displaystyle{\approx 3 \ \: \text{m/s}}[/tex]

Therefore, 10 km/h will approximately equal 3 m/s as accorded to significant rules.

The speed of the charged particle q after accelerating through a potential difference of 4V is given by sqrt(8qV/m).

The kinetic energy gained by a charged particle q accelerated through a potential difference V is given by:

K = qV

If the potential difference is increased to 4V, the kinetic energy gained by the particle will be:

K' = q(4V) = 4qV

Since the particle starts from rest, all the energy gained is converted to kinetic energy. Therefore, equating K' to the kinetic energy of the particle, we get:

K' = 1/2 mv^2

where m is the mass of the particle and v is the final speed of the particle.

Equating the two equations, we get:

4qV = 1/2 mv^2

Solving for v, we get:

v = sqrt(8qV/m)

Learn more about potential difference here

brainly.com/question/13290525

#SPJ4

The given question is incomplete, the complete question is:

Charge q is accelerated starting from rest up to speed v through the potential difference V. What speed will charge q have after accelerating through potential difference 4V?

The skater moves backward with a velocity of approximately 0.074 m/s.

We can calculate using momentum formula.

According to the law of conservation of momentum, the total momentum of a system is conserved if there is no external force acting on the system. In this case, the system consists of the ice skater and the snowball, and the external force acting on the system is assumed to be negligible. Therefore, the initial momentum of the system must be equal to the final momentum of the system.

The initial momentum of the system is given by the product of the mass of the skater and the initial velocity of the skater, which is zero, since the skater is initially at rest. The momentum of the snowball is given by the product of its mass and its initial velocity.

[tex]pi = ms * vs + mb * vb[/tex]

where pi : initial momentum of the system, ms : mass of the skater, vs is : initial velocity of the skater, mb : mass of the snowball, and vb : initial velocity of the snowball.

The final momentum of the system is given by the product of the mass of the skater and the final velocity of the skater, which is what we need to find, and the momentum of the snowball, which is equal to its mass times its final velocity, since it stops moving after it is thrown.

[tex]pf = ms * vf + mb * 0[/tex]

pf : final momentum of the system, vf : skater's final velocity, and 0 : final velocity of the snowball.

Since the initial momentum of the system is equal to the final momentum of the system, we can write:

[tex]ms * vs + mb * vb = ms * vf[/tex]

Substituting:

65.0 kg * 0 m/s + 0.15 kg * 32.0 m/s = 65.0 kg * vf

vf = -0.074 m/s

Learn more about velocity here:

https://brainly.com/question/17127206

#SPJ4

The speed of the block at x = 0 is 1.84 m/s.

Kinetic energy is a type of energy that an object possesses due to its motion. It is defined as the energy that an object has by virtue of its motion, and is given by the equation:

K = (1/2)mv²

where K is the kinetic energy of the object, m is its mass, and v is its velocity.

We use the conservation of energy principle. Initially, the block has potential energy stored in the spring, which is converted into kinetic energy as the block moves towards its equilibrium position, where x=0.

The potential energy stored in the spring when it is compressed to x = -6.5 cm is given by:

U = (1/2)kx²

where k is the force constant of the spring and x is the displacement from its equilibrium position.

Substituting the given values, we get:

U = (1/2) (2.90 X 10³ N/m) (0.065 m)²

U = 6.73 J

Therefore, the work done by compressing the spring is 6.73 J.

At the equilibrium position, all the potential energy stored in the spring is converted into kinetic energy. So, kinetic energy of the block at x = 0 is equal to potential energy stored in spring at x = -6.5 cm.

Therefore, the kinetic energy of the block at x = 0 is also 6.73 J.

Speed of the block at x = 0:

The kinetic energy of the block at x = 0 is given by:

K = (1/2)mv²

where m is the mass of the block and v is its speed.

Substituting the given values, we get:

6.73 J = (1/2) (2.0 kg) v²

Solving for v, we get:

v = √((2 x 6.73 J) / 2.0 kg)

v = 1.84 m/s

To know more about Kinetic energy, visit:

https://brainly.com/question/26472013

#SPJ1

Lorentz transformation is a mathematical framework that describes how the coordinates of an event in space and time change for two observers in relative motion.

Consider two inertial frames of reference, S and S', moving relative to each other along the x-axis with a constant velocity v. Let an event occur at position (x, y, z, t) in frame S, and let (x', y', z', t') be the corresponding position in frame S'.

The transformation equations for space and time are given by:

[tex]x' = γ(x - vt)\\y' = y\\z' = z\\t' = γ(t - vx/c^2)[/tex]

where[tex]γ = 1/√(1 - v^2/c^2)[/tex] is the Lorentz factor, and c is the speed of light.

These equations show how the coordinates of an event in one frame of reference are related to the coordinates in another frame of reference that is moving relative to the first frame. They are known as the Lorentz transformations and are a fundamental aspect of special relativity.

Learn more about Lorentz transformation, here:

https://brainly.com/question/29655824

#SPJ1

The magnitude of the velocity of the rock just before it strikes the ground is 25.48m/s.

Height = 17.0 m

Velocity = 33.0 m/s

Angle = 33.0°

[tex]-h= v_{y}t-\frac{1}{2}gt^2\\-17.0 = (33.0* sin33)t-4.9t^2\\4.9t^2-17.9t-17.0\\t= 4.435sec[/tex]

calculate the  magnitude of the velocity of the rock just before it strikes the ground

[tex]v_y= (33.0*sin33)- 9.8*4.435\\v_y= -25.48m/s[/tex]

Velocity is a fundamental concept in physics that describes the rate at which an object changes its position in a given direction. It is a vector quantity that has both a magnitude and a direction, which means that it specifies not only how fast an object is moving, but also in which direction it is moving.

The formula for calculating velocity is velocity = displacement/time, where displacement is the change in the position of the object and time is the duration of that change. The SI unit of velocity is meters per second (m/s).

Velocity is an important concept in many areas of physics, including mechanics, thermodynamics, electromagnetism, and relativity. It is used to describe the motion of objects, the behavior of waves, and the interactions between particles. In addition to its use in physics, velocity is also a key concept in many other fields, such as engineering, astronomy, and sports science.

To learn more about Velocity visit here:

brainly.com/question/17127206

#SPJ4

Complete Question:

A man stands on the roof of a building of height 17.0 m and throws a rock with a velocity of magnitude 33.0 m/s at an angle of 33.0 ∘ above the horizontal. You can ignore air resistance. Calculate the magnitude of the velocity of the rock just before it strikes the ground.

The acceleration of the mass in terms of {m} is -

a = 2F/m.

The force acting on a body is given by -

Force {F} = mass {m} x acceleration {a}

Given is that a net force of {F} is applied to half the mass {m/2}.

We know that -

Force {F} = mass {m} x acceleration {a}

F = {m/2} x a

a = 2F/m

Therefore, the acceleration of the mass in terms of {m} is -

a = 2F/m.

To solve more questions on acceleration , visit the link below -

https://brainly.com/question/28875533

#SPJ9

"The sequence that correctly describes the route male gamete take through the human male reproductive system is epididymis, vas deferens, urethra."Correct option is B.

The act of reproduction is how organisms create more of their own kind. There are two types of gametes used in human reproduction. The zygote undergoes a procedure in which it transforms into an embryo and then into a fetus.

The male has genitalia, which are reproductive structures, both inside and outside the pelvic girdle. The epididymis and vas deferens, which carry male gamete, are located next to the testicles. The scrotum, an external pouch-like structure, house the epididymis.

The seminal vesicles and the prostate gland are examples of accessory glands that produce secretions that lubricate the duct system and feed the male gamete. The male gamete travels from the genetalia of man through the urethra to the outside of the body.

Thus, the sequence that correctly describes the route male gamete take through the human male reproductive system is epididymis, vas deferens, urethra. Best choice is B.

The given question is incomplete. The complete question contains options. They are 'a. vas deferens, urethra, epididymis b. epididymis, vas deferens, urethra c. vas deferens, epididymis, urethra d. urethra, epididymis, vas deferens'

To know more about reproductive system:

https://brainly.com/question/15460473

#SPJ4

The final answer, in joules, is -1835.120716 J.

Angles are measured in terms of radians. It is described as the angle occupied by a circle arc whose length is equal to the circle's radius. In other words, a circle with a radius of 1 unit subtends an arc with a length of 1 unit at an angle of 1 radian. Radians have no units because they are a dimensionless quantity.

Let's simplify and evaluate the given expression step by step:

First, let's calculate the terms inside the brackets:

(83)(2.1)²/4 = 185.3675 J

(100)(0)²/2 = 0 J

So, the first term in the expression becomes:

185.3675 J

Now, let's calculate the second term inside the brackets:

(83)(2.1)²/4 = 185.3675 J

(100)(2.1)²/2 = 2205 J

(0.14 rev/s * 2π rad/rev)² = 0.246784 J/(rad^2)

So, the second term in the expression becomes:

185.3675 J + 2205 J - 0.246784 J = 2390.120716 J

Now, we can calculate the final expression by plugging in the values and simplifying:

[(83)(2.1)²/4 +(100)(0)²/2] * (3 rad/sec)² - [(83)(2.1)²/4 +(100)(2.1)²/2 * (0.14 rev/s)² (2pi rad/rev)²]

= [185.3675 J + 0 J] * (3 rad/sec)² - [185.3675 J + 2205 J - 0.246784 J]

= 555 J - 2390.120716 J

= -1835.120716 J

To know more about Angles, visit:

https://brainly.com/question/28451077

#SPJ1

Electromagnetic waves propagate through the interaction of : A. electric and magnetic fields.

Electric and magnetic fields: As the electric field oscillates, it creates a changing magnetic field, and vice versa. These changing fields propagate through space, creating a self-sustaining wave that can travel through a vacuum or a medium such as air.

Electrons are not directly involved in the propagation of electromagnetic waves, but they can be affected by the waves as they interact with matter.

Positive charges also do not directly participate in the propagation of electromagnetic waves, but they can be influenced by the electric field component of the wave.

Air or any other medium does not play an active role in the propagation of electromagnetic waves, but it can affect the behavior of the waves.

Therefore the correct option is A.

Learn more about electromagnetic waves here:https://brainly.com/question/13874687
#SPJ1

Explanation:

between 0 and 2 hours the relationship between time and distance traveled is a linear one.

that means that the velocity (= distance/time like in km/s) is constant (and not increasing).

and because between the hours 2 and 3 there is no increase in distance, this means the car stood still during that time. so, no, it was not always in motion during the voyage.

therefore,

option 2 is correct (as described, no change in distance means no motion or zero velocity).

and option 3 is correct, because also between hours 3 and 5 the function is linear and the speed ratio is therefore constant.

The cost of using the appliances will be 3004.19¢

The electricity cost is defined as the amount of money required to use per Kw of electric power.

Given that on a particular day, the following appliances are used for the times indicated: a 1600-W coffee maker, 13 min, and an 1100-W microwave oven, 4.5 min.

The first step is to convert the times from minutes to hours.

60 min = 1 hour

13 min = 13 /60

4.5 min = 4.5/60

Considering the 1600-W coffee maker,

The total consumption will be calculated as:-

Consumption = 1600 x  13 /60 = 346.67 kWh

Considering the 1100-W microwave oven,

The total consumption will be calculated as:-

Consumption = 1100 x 4.5/60 =  82.5 kWh

Total consumption = 346.67 + 82.5 = 429.17 kwh

Given that the cost is 7¢ per kWh,

Cost of using these appliances = 429.17x 7

Cost of using these appliances = 3004.19 ¢

Therefore, the cost of using the appliances will be 3004.19¢

To know more about an electric costs follow

https://brainly.com/question/29000259

#SPJ1

The angular acceleration of the pulley is given by the expression α = (MgR - mgr) / I.

The forces acting on the system are the gravitational forces on the turkey and the pumpkin, which are Mg and mg, respectively. T

These forces create torques on the pulley, with the torque on the large disk being MgR and the torque on the small disk being -mgr. The negative sign on the torque of the small disk indicates that it is acting in the opposite direction of the torque on the large disk.
The sum of these torques is equal to the moment of inertia of the pulley times its angular acceleration, which can be written as:
MgR - mgr = Iα
Solving for the angular acceleration, α, we get:
α = (MgR - mgr) / I
This is the expression for the angular acceleration of the pulley in terms of the system parameters. It shows that the angular acceleration depends on the masses of the turkey and the pumpkin, the radii of the large and small disks, and the moment of inertia of the pulley.

Learn more about angular acceleration:

https://brainly.com/question/21278452

#SPJ11

The flake will travel downwards in a parabolic path in a curved trajectory before hitting the bottom of the bowl, due to the force of gravity acting on it. No friction is present so the final velocity of the flake will be the same as its initial velocity.

Velocity is a measure of the rate and direction of change in the position of an object. It is a vector quantity that is equal to the rate of change of the object’s position in a given direction. Velocity is expressed as a vector, which is composed of both a magnitude and a direction.

To know more about Velocity
https://brainly.com/question/80295
#SPJ1

Earthquakes are related to the movement of tectonic plates, as the plates' motion can cause stress to build up in the crust, leading to sudden movements along faults, resulting in earthquakes.

Tectonic plates are constantly moving, driven by convection currents in the mantle. As plates move, they can rub against each other, causing friction and stress to build up along their boundaries. This stress can eventually overcome the strength of the rocks, resulting in sudden movements along faults, which are zones of weakness in the crust.

These sudden movements release energy in the form of seismic waves, causing the ground to shake, resulting in an earthquake. Therefore, earthquakes are directly related to the movement of tectonic plates and occur most frequently along plate boundaries.

To know more about the tectonic plates, here

brainly.com/question/15299161

#SPJ4

The velocity of the two boxes after the collision is 0 m/s, which means they come to a complete stop.

option B.

We can solve this problem by applying the principle of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.

Before the collision, the momentum of the 4 kg box is:

p1 = m1 * v1 = 4 kg * 9 m/s = 36 kgm/s (to the right)

Before the collision, the momentum of the 1.5 kg box is:

p2 = m2 * v2 = 1.5 kg * (-24 m/s) = -36 kgm/s (to the left)

The total momentum before the collision is:

p_total = p1 + p2 = 36 kgm/s - 36 kgm/s = 0 kgm/s

The total momentum after the collision is also 0 kgm/s, since there are no external forces acting on the system.

p_total = m_total * v_final

where;

We can solve for v_final:

v_final = p_total / m_total = 0 kg*m/s / (4 kg + 1.5 kg) = 0 m/s

Learn more about final velocity here: https://brainly.com/question/25905661

#SPJ1