The weight of the third heaviest among the four dogs is 2 kg.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
The 4 dogs weight is 60 kg with each dog weight been different. The second heaviest dog weighs 28 kg.
Let the heaviest dog be 29 kg, the third heaviest be 2 kg and the fourth be 1 kg.
29 + 28 + 2 + 1 = 60 kg
The weight of the third heaviest among the four dogs is 2 kg.
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The graph of a linear function is shown.
Which word describes the slope of the line?
positive
negative
zero
undefined
Answer:
zero
Step-by-step explanation:
because it's horizontal line
-2x+ 3y=-15 3x+2y = -23 solve by elimination
Answer:
x=237/7 and y=-199/7
Explanation:
Multiply the second equation by 2, then add the equations together.
(−2x+3y=−153)
2(x+2y=−23)
Becomes:
−2x+3y=−153
2x+4y=−46
Add these equations to eliminate x:
7y=−199
Then solve 7y=−199 for y:
7y=−199
(Divide both sides by 7)
y=−199/7
Now that we've found y let's plug it back in to solve for x.
Write down an original equation:
−2x+3y=−153
Substitute −199/7 for y in−2x+3y=−153:
Add 597/7 to both sides
Divide both sides by -2
You need to purchase supplies for the trip. You have
$1000 to spend.
Oxen: $40 each
Food: $0.20 per lb
Clothing: $10 per set.
Matt also charges 6% tax
Purchase at least 2 oxen,
500lbs of food,
and 5 sets of clothing.
You may want to purchase more.
Select the amount of items and find the total cost including tax.
Answer:
I'd say 955$ or so
Step-by-step explanation:
Noah walked a family’s dog 5 times this past month and earned the same amount each time. To thank him, the family gave him an extra $6 at the end of the month. Noah earned $106 from dog walking.
1- This situation IS represented by the tape diagram.
2- This situation IS NOT represented by the tape diagram.
The situation IS NOT represented by the tape diagram.
How to represent the situationNumber of times Noah walked the dog = 5Amount earned each time = sExtra amount earned = $6Total amount earned = $106The situation can be represented by the equation:
s + s + s + s + s + 6 = 106
5s + 6 = 106
5s = 106 - 6
5s = 100
s = 100/5
s = 20
Therefore, the amount Noah earned each time he walked the dog is $20
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what is m
ddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
Answer:
66 degrees
Step-by-step explanation:
All three angles on any given triangle have a sum of 180 degrees.
We know that the measure of angle B is the the same as angle C.
So 57 +57 = 114
180 - 114 = 66
Hope that helps!
What would be the corresponding angles ( similar figures ). Any help with this question will be gladly appreciated . Thank you
Answer:
x=4.8
I think ur supposed to solve for x. Since the rectangles are similar, we can set a proportion for the sides
5/3 = 8/x (then just solve for x)
24=5x
4.8=x
Write an essay comparing the two arguments made about whether dodgyball should be played in school. Use textual evidence from the article to support your answer. TITLE- A Dodgy call AUTHOR Tum Jones Introduction Hook- Bridge-
Answer:
(This is not math)
Step-by-step explanation:
I think that dodgeball should be allowed un our school because it gets our legs moving and lets us extrasice and practice our swiftness
What is the slope of the line that passes through the points (-10, 9) and (−10,18)?
Answer:
9
Step-by-step explanation:
the equation for the line should be:
y=9x-10
The slope of the line that passes through the point (−10,9) and (10,18) is undefined.
What is the Point-slope form?The equation of the straight line has its slope and given point.
If we have a non-vertical line that passes through any point(x1, y1) and has a gradient m. then general point (x, y) must satisfy the equation
y-y₁ = m(x-x₁)
We need to find the slope of the line that passes through the point (−10,9) and (10,18)
Where x₁ - x coordinate, y₁ - y coordinate, m - slope
Slope: (18 - 9) / ( -10 + 10)
m = 9/0
So, the slope is undefined.
Hence, the slope of the line that passes through the point (−10,9) and (10,18) is undefined.
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There is a red, orange, yellow, green, blue, and purple card placed in a box. (six total, one of each color). You are asked to randomly choose a card, replace it in the box, and choose another card.
Find P(Yellow, then Blue)
Answer:
Step-by-step explanation:
If you are doing probability with replacement they will all be 1/6 each time.
total there is 6/6. If you draw a yellow card first it's 1/6 then replace it and draw a blue it is still 1/6. so you take those two probabilities and multiply them (1/6)*(1/6)=1/36 1*1=1 and 6*6=36.
Your answer is 1/36
I need help, so this one question: 1/4 (4+x)=4/3
Is stopping me from being great
Answer:
if you are solving for x, x= 4/3
Step-by-step explanation:
How to solve your problem:
1. Rearrange terms
2. Combine multiplied terms into a single fraction
3. Multiply by 1
4. Multiply all terms by the same value to eliminate fraction denominators
5. Cancel multiplied terms that are in the denominator
6. Multiply the numbers
7. Subtract 4 from both sides
8.Simplify
Answer:
X= 4/3
Hopes this helps! ^^
If yesterday's day after tomorrow is Sunday, what day is tomorrow's day before
yesterday?
Answer:
friday
Step-by-step explanation:
Evaluate the expression 21 ÷ 3 + 8 − 4. 19 17 15 11
Answer:
Your answer is D, 11
Step-by-step explanation:
PEMDAS, first you divide, 21/3 is 7
7+8 is 15
15 - 4 is 11
Hope this helps! :)
Answer:
[tex]\boxed{\sf{11}}[/tex]
Step-by-step explanation:
Solving this problem requires an order of operations.
PEMDAS stands for:
ParenthesisExponentsMultiplyDivideAddSubtract21÷3+8-4First, divide.
[tex]\sf{21\div3+8-4}[/tex]
[tex]\sf{21\div3=7}[/tex]
Then rewrite the problem.
[tex]\sf{7+8-4}[/tex]
Add.
[tex]\sf{7+8=15}[/tex]
Subtract.
[tex]\sf{15-4=\boxed{\sf{11}}[/tex]
11
Therefore, the correct answer is 11.
I hope this helps you! Let me know if my answer is wrong or not.
The volumes of two similar solids are 1408 m3 and 594 m3. The surface are of the smaller solid is 549 m2. What is the surface area of the larger solid?
The surface area of the larger solid is approximately 971.13 m².
What is scale factor?
A scale factor is the ratio of the corresponding sides of two similar objects.
Let's find the scale factor as follows:
z = scale factor
x = the volume of the larger solid
y = the volume of the smaller solid
Therefore,
z³ = x / y
z³ = 1408 / 594
z = ∛1408 / 594
z = 11.2081573 / 8.40611799
z = 1.33
Therefore,
let's find the surface area of the larger solid.
The scale factor squared is equal to the surface area of the larger solid divided by the surface area of the smaller solid. Therefore,
z² = larger solid / 549
surface area of the larger solid = 1.33² × 549
surface area of the larger solid = 1.7689 × 549
surface area of the larger solid = 971.1261
surface area of the larger solid = 971.13 m²
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Need to see what the best result
Answer:
[tex]4 \sqrt{5} [/tex]
A safe has 10,000 possible lock combinations. If a thief tried 80 combinations the first hour, then 40 every hour after, how many hours would it take before trying them all?
It takes 249hrs before trying them all.
100 POINTS
Write the integral in one variable to find the volume of the solid obtained by rotating the first‐quadrant region bounded by y = 0.5x2 and y = x about the line x = 5.
Answer:
V = π ∫₀² (y² − 8y + 6√(2y)) dy
or
V = π ∫₀² (6x − 5x² + x³) dx
Step-by-step explanation:
y₁ = 0.5x²
y₂ = x
First, find the intersections of the curves.
0.5x² = x
x² = 2x
x² − 2x = 0
x (x − 2) = 0
x = 0 or x = 2
So the points of intersection are (0, 0) and (2, 2).
When we revolve this region about the line x = 3, we get a hollow shape that looks like an upside-down funnel, or a volcano.
One option is to use washer method to find the volume, by cutting a thin horizontal slice of thickness dy, inner radius 3−x₁ = 3−√(2y), and outer radius of 3−x₂ = 3−y.
V = ∫₀² π [(3−y)² − (3−√(2y))²] dy
V = ∫₀² π (9 − 6y + y² − 9 + 6√(2y) − 2y) dy
V = π ∫₀² (y² − 8y + 6√(2y)) dy
Another option is to use shell method to find the volume, by cutting a thin vertical slice of thickness dx, radius 3−x, and height y₂−y₁ = x−0.5x².
V = ∫₀² 2π (3 − x) (x − 0.5x²) dx
V = ∫₀² 2π (3x − 1.5x² − x² + 0.5x³) dx
V = ∫₀² 2π (3x − 2.5x² + 0.5x³) dx
V = π ∫₀² (6x − 5x² + x³) dx
The second option is arguably easier to evaluate, but either one will get you the same answer (V = 8π/3).
Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The Bombardier Dash 8 aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6200 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6200lb/37 = 167.6lb. What is the probability that the aircraft is overloaded? Should the pilot take any action to correct for an overloaded aircraft? Assume that weights of men are normally distributed with a mean of 185.47 lb and a standard deviation of 39 lb. make sure to include pdf
Using the normal probability distribution and the central limit theorem, it is found that the probability is of 0.9974 = 99.74%, which means that the pilot should take action.
Normal Probability DistributionIn a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].In this problem, for the population, the mean and the standard deviation are given by, respectively:
[tex]\mu = 185.47, \sigma = 39[/tex].
For a sample of 37 passengers, we have that:
[tex]n = 37, s = \frac{39}{\sqrt{37}} = 6.4116[/tex]
The probability that the aircraft is overloaded is one subtracted by the p-value of Z when X = 167.6, hence:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{167.6 - 185.47}{6.4116}[/tex]
[tex]Z = -2.79[/tex]
[tex]Z = -2.79[/tex] has a p-value of 0.0026.
1 - 0.0026 = 0.9974.
There is a 0.9974 = 99.74% probability that the aircraft is overloaded. Since this is a very high probability, the pilot should take action.
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May someone please help me with this?
Answer:
Step-by-step explanation:
First, calculate the angle of FDE (assume it as α) by:
[tex]EF=\frac{\alpha}{360}\times(2\pi)(DE) \rightarrow 2\pi = \frac{\alpha}{360}(2\pi)(6)[/tex]
[tex]\alpha=60^{0}[/tex]
So, use this angle to calculate the area of FDE (unshaded region):
[tex]A_{US}=\frac{\alpha}{360}\times(\pi)(DE)^{2}=\frac{60}{360}(\pi)(6^{2})=6\pi[/tex]
So, the shaded region can be determined by:
[tex]A_{S}=A-A_{US}=\pi(DE)^{2}-6\pi=36\pi-6\pi=30\pi=\frac{60}{2}\pi[/tex]
At his son's birth, a man invested $2,000 in savings at 6% for his son's college education.
Approximately how much, to the nearest dollar, will be available in 19 years? (Do not use comma placeholder in response.)
Rounded to the nearest year, approximately how long will it take for the man’s investment to double?
now, this is assuming the 6% is at simple interest rate.
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$2000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &19 \end{cases} \\\\\\ A=2000[1+(0.06)(19)]\implies A=2000(1.54)\implies A=3080 \\\\[-0.35em] ~\dotfill[/tex]
[tex]~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\dotfill & \$2000\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years \end{cases} \\\\\\ 4000=2000[1+(0.06)(t)]\implies \cfrac{4000}{2000}=1.06t \\\\\\ 2=1.06t\implies \cfrac{2}{1.06}=t\implies 1.89\approx t\implies \stackrel{\textit{rounded up}}{2\approx t}[/tex]
Answer:
value in 19 years: $6051
years to double: 12
Question
Which expression is equivalent to 5x2 – 18x + 9?
O (5x - 1)(x – 9)
O (5x – 9)(x + 1)
O (5x – 3)(x - 3)
O (5x + 3)(x - 3)
Answer:
(5x – 3)(x - 3)
Step-by-step explanation:
Break the expression into groups
[tex]=\left(5x^2-3x\right)+\left(-15x+9\right)[/tex]
Factor out
[tex]=x\left(5x-3\right)-3\left(5x-3\right)[/tex]
Factor out common terms
[tex]=\left(5x-3\right)\left(x-3\right)[/tex]
Hence, Answer is (5x-3)(x-3)
~Lenvy~
The expression which is equivalent to 5x² - 18x + 9 is (5x – 3)(x - 3).
What are Expressions?Expressions are mathematical statements which consist of two or more terms and terms are connected to each other using mathematical operators like addition, multiplication, subtraction and so on.
Given expression is,
5x² - 18x + 9
We have to find the equivalent expression of this.
We have to factor this.
Using quadratic formula,
x = -(-18) ± √[(-18)² - (4 × 5 × 9)] / (2 × 5)
= (18 ± √144) / 10
= (18 ± 12) / 10
x = 3 and x = 3/5
So the expression can be factored as
(x - 3)(x - 3/5) = 0
(x - 3)(5x - 3) = 0
Hence the correct option is (5x – 3)(x - 3).
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The number of men and women participating in the Winter Olympic Games has been steadily increasing in recent years. In the 19th Winter Olympics, 1389 men and 787 women participated. 1660 men and 1121 women participated in the 22nd Winter Olympics.
Part A
Which system describes the number of men and women participating if x represents the number of winter games after the 22nd Winter Olympics?
Multiple choice question.
A)
y=1389x+1660y=787x+1121
B)
y=2713x+1121y=3343x+1660
C)
y=2713x+1389y=3343x+787
D)
y=2713x+1660y=3343x+1121
Using a system of equations, it is found that the correct option is:
A) 1389x+1660y=787x+1121y.
What is a system of equations?A system of equations is when two or more variables are related, and equations are built to find the values of each variable.
In this problem, considering the amounts in each olympics(1389 men and 787 women participated on the 19th, 1660 men and 1121 women in the 22th), the system is:
A) 1389x+1660y=787x+1121y.
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23 10. Construct a quadratic equation whose roots are 1 and 2.A 3X-3x + 2-0 B. 3 + 3x - 2-0 C 22 + 3x - 2.0 D 2 - 3x +2=0 E.2x - 3x - 2 =0
Answer:
Step-by-step explanation:
Basic quadratic equation has this following form:
[tex](x-x_{1})(x-x_{2})=0[/tex]
where x1 and x2 are the roots.
For [tex]x_{1}=1[/tex] and [tex]x_{2}=2[/tex], we can find:
[tex](x-1)(x-2)=0 \rightarrow x^{2}-2x-x+2=0 \rightarrow x^{2}-3x+2=0[/tex]
There are six more necromancers than there are
wizards. Write a system of equations that deter-
mines the numbers of wizards and the number of
necromancers.
Answer:
Step-by-step explanation:
let x be necromancers and y be wizards
if you know the amount of wizards and want to find the amount of necromancers. you just use y + 6
but if you know the amount of necromancers and want to find out the amount of wizards you just do x - 6
When asked to factor the x^2 - 144, a student gives the answer (x - 12)(x - 12). What is wrong with this answer?
A. Both minus signs should be plus signs l
B. One of the minus signs should be a plus sign
C. There is nothing wrong with this answer
D. -1 is also a factor
Answer:
B
Step-by-step explanation:
because in general
(a + b)(a - b) = a² - b²
when the second term is negative, it has to be the product of a positive and a negative number.
positive × positive = positive
negative × negative = positive
Find the Perimeter of the Square with One side is 75cm
Answer:
P=300cm
Step-by-step explanation:
P=4a=4.75×4=300cm
[tex]\green{ \underline { \boxed{ \sf{Perimeter \: of \:Square = 4 \times side }}}}[/tex]
Putting Values -
[tex]\begin{gathered}\\\implies\quad \sf Perimeter \:of \:Square = 4 \times 75 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf Perimeter \: of \:Square = 300 sq. \:cm \\\end{gathered} [/tex]
>>Therefore, Perimeter of the Square is 300 sq. cm
-(4-x)=3/4(x-6) i need help pls
Solve for x by simplifying both sides of the equation, then isolating the variable.
x=−2
hope this is what your looking for
Answer:
x = -2
Step-by-step explanation:
[tex]-4+x=\frac{3}{4}x-\frac{9}{2}[/tex]
[tex]\mathrm{Add\:}4\mathrm{\:to\:both\:sides}[/tex]
[tex]-4+x+4=\frac{3}{4}x-\frac{9}{2}+4[/tex]
[tex]Simplify[/tex]
[tex]x=-\frac{1}{2}+\frac{3}{4}x[/tex]
[tex]\mathrm{Subtract\:}\frac{3}{4}x\mathrm{\:from\:both\:sides}[/tex]
[tex]x-\frac{3}{4}x=-\frac{1}{2}+\frac{3}{4}x-\frac{3}{4}x[/tex]
[tex]\frac{1}{4}x=-\frac{1}{2}[/tex]
[tex]\mathrm{Multiply\:both\:sides\:by\:}4[/tex]
[tex]4\cdot \frac{1}{4}x=4\left(-\frac{1}{2}\right)[/tex]
[tex]x=-2[/tex]
~lenvy~
Multiply
2n(-5n +2y-c)
2b² (3a – 5b +8c)
Answer:
thats the answer
Step-by-step explanation:
Answer:
1) = -10n^2 + 4ny -2nc
2) = 6b^2a-10b^3+16b^2c
Step-by-step explanation:
What is the slope-intercept equation for this line?
y = [?]x+ [?]
Answer:
y= -x-3
Step-by-step explanation:
Please helppppppp thank you so much
Answer:
7 1/8
Step-by-step explanation:
1 1/8 + 1 1/8 is 2 2/8
2 2/8 + 4 7/8 is 6 9/8 = 7 1/8
A sample of bacteria is decaying according to a half-life model. If the sample begins with 500 bacteria,
and after 17 minutes there are 150 bacteria, after how many minutes will there be 10 bacteria
remaining?
When solving this problem, round the value of k to four decimal places and round your final answer to
the nearest whole number.
contact +2348021312463, he can help you
after approximately 137 minutes, there will be 10 bacteria remaining.
To find the time at which there will be 10 bacteria remaining, we can use the half-life model for exponential decay, which is given by:
N(t) = N₀ * [tex](1/2)^{(t / t_{half})[/tex]
where:
N(t) = the number of bacteria at time t
N₀ = the initial number of bacteria
t = time (in minutes)
t_half = the half-life of the bacteria
We are given that the initial number of bacteria (N₀) is 500 and after 17 minutes there are 150 bacteria (N(17) = 150).
Let's use this information to find the value of k (the decay constant):
150 = 500 * [tex](1/2)^{(17 / t_{half})[/tex]
Divide both sides by 500:
[tex](1/2)^{(17 / t_{half})[/tex] = 150 / 500
[tex](1/2)^{(17 / t_{half})[/tex] = 0.3
Now, we can write the equation as an exponent:
17 / t_half = log base (1/2) of 0.3
Using logarithms:
t_half = 17 / log base (1/2) of 0.3
Now, calculate t_half:
t_half = 17 / log base 2 of 0.3 ≈ 38.555
Now, we can find the time at which there will be 10 bacteria remaining (N(t) = 10):
10 = 500 * [tex](1/2)^{(t / 38.555)[/tex]
Divide both sides by 500:
[tex](1/2)^{(t / 38.555)[/tex] = 10 / 500
[tex](1/2)^{(t / 38.555)[/tex] = 0.02
Write the equation as an exponent:
t / 38.555 = log base (1/2) of 0.02
Using logarithms:
t = 38.555 * log base 2 of 0.02 ≈ 137.08
Rounding to the nearest whole number:
t ≈ 137
So, after approximately 137 minutes, there will be 10 bacteria remaining.
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