Chemistry High School

P5-F2 + Ar --> ArF3
P5a- How many moles of F2 (Fluorine) are needed to produce 9 mole of ArF3 (Argon trifluoride)?
P5b- How many moles of Argon (Ar) are consumed in a reaction that consumes 5 moles of F2 (fluorine)?


I need the answers for the p5 part please help

P5-F2 + Ar --> ArF3P5a- How Many Moles Of F2 (Fluorine) Are Needed To Produce 9 Mole Of ArF3 (Argon

Answers

Answer 1

Answer:

5a. 13.5 moles of F₂

5b. 3.33 moles of Ar.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

3F₂ + 2Ar —> 2ArF₃

From the balanced equation above,

3 moles of F₂ reacted with 2 moles of Ar to produce 2 moles of ArF₃.

5a. Determination of the number of mole of fluorine, F₂, needed to produce 9 moles of ArF₃.

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of ArF₃.

Therefore, Xmol of F₂ will react to produce 9 moles of ArF₃ i.e

Xmol of F₂ = (3 × 9)/2

Xmol of F₂ = 13.5 moles

Thus, 13.5 moles of F₂ is needed.

5b. Determination of the number of mole of Ar needed to react with 5 moles F₂.

From the balanced equation above,

3 moles of F₂ reacted with 2 moles of Ar.

Therefore, 5 moles of F₂ will react with = (5 × 2)/3 = 3.33 moles of Ar.

Thus, 3.33 moles of Ar was consumed.

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Answers

Answer:

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https://brainly.com/question/11940982

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Answers

Answer:

Explanation:

The correct answer is

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hope it helps :)

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Answers

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1. What is WRONG with the setup used by the student to solve this
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10 points
If 53.8 grams of Aluminum Carbide is treated with Sodium Oxide, how many moles of Aluminum Oxide is
produced?
AlqC3 +6 Na2O + 2 Al2O3 + 3 Nand
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Ο Ο Ο
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INITI

Answers

Answer:

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Answers

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Answers

Answer:

It would react better than what with dilute and will furnish more hydrogen gas.

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Answers

Answer:

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Answer:

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C.......................

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I dont know i just want help thats why im answering to get 1 help as i have to help to get help

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Answers

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Answers

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Explanation:

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Answers

Answer:thanks for the points

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Answers

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Answers

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Answers

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Answers

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Hope this helps

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i am way to much of an idiot for this (hope i made you laugh (and mad cuz i did not answer) :3)

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