Part a: is the probability of hitting the black circle inside the target closer to 0 or 1? explain your answer and show your work. (5 points) part b: is the probability of hitting the white portion of the target closer to 0 or 1? explain your answer and show your work. (5 points)

Answer:

125

Step-by-step explanation:

y = 1k/x^3  I am trying to find the constant k.  I will use the information that I have been given to find k

1 = k/5^3

1 = k/125  Multiply both sides by 125

125 = k

Now, we will find y when x = 1

y = 125/1^3

y = 125

The value of y is 125 when x is 1.

Write the function y as a function of x, i.e., y = f(x), and then solve for x as a function of y, to determine the inverse of a function.

y = 1k/x^3  I am trying to find the constant k.  I will use the information that I have been given to find k

1 = k/5^3

1 = k/125

Multiply both sides by 125

125 = k

Now, we will find y when x = 1

y = 125/1^3

y = 125

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If x - 4 is a factor then x = 4 is a root:

f(4) = 4^3 - 2 * 4^2 + 5 * 4 + 1

= 64 - 32 + 20 + 1

= 53

since f(4) is not zero then 4 is not a root of the f(x)

Also, x - 4 is not a factor

In algebra, the remainder theorem, or Bezout's small theorem, applies the principle of polynomial division. It states that the remainder of dividing the polynomial f (x) by the linear polynomial {\ display style x-r} is equal to {\ display style f (r). }

In algebra, a factor set is a set of factors and roots of. Polynomial. This is a special case of the remainder theorem. The factor theorem shows that the polynomial f (x) has a factor only if f = 0.

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The value of y from the given expression is 5

Given:

BD = 16

BC = 2y - 2

CD = y + 3

Since AC is a perpendicular bisector of BD:

BC  =  CD

2y - 2 = y + 3

2y - y = 3 + 2

y  =  5

Hence, the value of y from the given expression is 5

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The given triangle is a right triangle

The coordinates are given as:

D (0,n), E(m,n), F(m,0)

The length is calculated using:

[tex]l=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2[/tex]

So, we have:

[tex]DE=\sqrt{(0-m)^2 + (n-n)^2} = m[/tex]

[tex]DF=\sqrt{(0-m)^2 + (n-0)^2} = \sqrt{m^2 + n^2[/tex]

[tex]EF=\sqrt{(m-m)^2 + (n-0)^2} = n[/tex]

The slope is calculated using:

[tex]m = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

So, we have:

[tex]DE = \frac{n -n}{0- m} = 0[/tex]

[tex]DF = \frac{n -0}{0- m} = -\frac nm[/tex]

[tex]EF = \frac{n -0}{m- m} = \mathbf{unde fined}[/tex]

This is calculated using

[tex]m = 0.5 * (x_1 + x_2, y_1 + y_2)[/tex]

So, we have:

[tex]DE = 0.5 * (0 + m, n+ n)=(0.5m, n)[/tex]

[tex]DF = 0.5 * (0 + m, n+ 0)=(0.5m, 0.5n)[/tex]

[tex]EF = 0.5 * (m + m, n+ 0)=(m, 0.5n)[/tex]

In (a), we have:

Lengths

[tex]DE= m[/tex]

[tex]DF = \sqrt{m^2 + n^2[/tex]

[tex]EF= n[/tex]

Slope

[tex]DE = 0[/tex]

[tex]DF = -\frac nm[/tex]

[tex]EF = \mathbf{unde fined}[/tex]

The sides are not equal.

However, the 0 and the undefined slope implies that the triangle is a right triangle because the sides are perpendicular

It should be noted that the triangle cannot be graphed because the coordinates are not numeric

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Answer: Add 5 to the product of 3 and 6, then subtract 4

Step-by-step explanation:

     We will use the order of operations. Looking at 5 + (3 x 6) − 4, we would:

[1] Multiply 3 x 6

[2] Add 5 to that product

[3] Subtract 4 from that value

     This means the answer to your question is:

Add 5 to the product of 3 and 6, then subtract 4

Answer: B

i DiD tHe TeSt

Answer:

The slope is -2

Step-by-step explanation:

To find the slope, we can use the slope formula

m = ( y2-y1)/(x2-x1)

    = (-1 -3)/(-1 - -3)

   = ( -1-3)/(-1+3)

   = -4/2

   = -2

The slope is -2

The volume of the cylinder is approximately, 1,539.4 cubic meters.

Volume of a cylinder = πr²h

Given the following:

Diameter of cylinder = 14 m

Radius (r) = 14/2 = 7 m

Height of cylinder = 10 m

Volume of cylinder = πr²h = π(7²)(10)

Volume of cylinder ≈ 1,539.4 cubic meters.

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Answer:

The solution is 25, 36, 49

Step-by-step explanation:

a = 1

b = 3

c = 5-3

= 2

________________________________

Un = [tex]\sf a + (n-1) \times b + \frac{(n-1)(n-2)}{2} \times c[/tex]

Un = [tex]\sf 1 + (n-1) \times 3 + \frac{(n-1)(n-2)}{2} \times 2[/tex]

Un = [tex]\sf 1 + 3n-3 + (n-1)(n-2)[/tex]

Un = [tex]\sf 1 + 3n-3 + n^{2} - 2n - n + 2[/tex]

Un = [tex]\sf n^{2} + 3n - 2n - n + 2 + 1 - 3[/tex]

Un = [tex]\sf n^{2} + 0n + 0[/tex]

Un = [tex]\sf n^2[/tex]

________________________________

Un = n²

U5 = 5²

= 25

U6 = 6²

= 36

U7 = 7²

= 49

________________________________

So, the next three members are 25, 36, 49

The given radii of 4 and 6 and the sector angle of 112°, gives;

[tex] C.\: \frac{56 \cdot \pi}{9} [/tex]

The possible figure that relates to the question can be described as follows;

Two concentric circles having radii of AE = 4, and AB = 6, respectively.

Sector of the circles formed by lines AC and AB, with angle of sector = 112°

The shaded portion is described by arcs FE and CB

Therefore;

Area of the sectors are found as follows;

[tex]AFE = \frac{112 ^\circ}{360 ^\circ} \times \pi \times {4}^{2} = \frac{224 \cdot \pi}{45} [/tex]

[tex]ACB = \frac{112 ^\circ}{360 ^\circ} \times \pi \times {6}^{2} = \frac{56 \cdot \pi}{5} [/tex]

Area of the shaded portion, A is therefore;

[tex] A= \frac{56 \cdot \pi}{5} - \frac{224 \cdot \pi}{45} =\frac{56 \cdot \pi}{9} [/tex]

[tex] Shaded \: area, \: A= \frac{56 \cdot \pi}{9} [/tex]

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Answer:

x < 7

Step-by-step explanation:

The domain encompasses all the "x" values (or inputs) of a function.

The arrow on the left line symbolizes that the function continues into the negative region for infinity. As such, this eliminates option C.

Closed dots are points whose "x" values are included in the function. Open-dots are on points whose "x" values are not included in the function. Although the open-dot on the left line at x = -1 generally means it is not included in the function, the closed dot on the right line overrides this. Therefore, x = -1 is in the domain. The value x = 7 is not within the domain of the function due to the open-dot. This eliminates option B and option D.

With this said, the domain of the function is x < 7.

Given that price was $520 after a 30% increase,  the original price was $400.

Given that;

To determine the original price, we say;

x × ( 100% + 30% ) = $520

x × ( 130% ) = $520

x × (130/100) = $520

130x / 100 = $520

130x = $52000

x = $52000 / 130

x = $400

Given that price was $520 after a 30% increase,  the original price was $400.

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Answer:

I'm pretty sure it is √10, 3.12, 3.24, 31

Step-by-step explanation:

I don't know if you messed up but I got a question similar that is the length 31 in your quesion is actually 3 1/4 in my question. but i did the math and 31 is still the greatest number.

The percentage of the cost of the phones Annel earns in commission is 5%. If he sells $640 worth, the amount he earns as percentage will be $32.

The amount in commission Annel earns when he sells the phone worth $180 = $9

The percentage of the amount sold, Annel earns as commission is therefore;

[tex] \frac{9}{180} \times 100 = 5\%[/tex]

The amount earned as commission if he sells $640 worth of phones is found as follows;

Amount earned = 5% × 640 = 32

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The necessary solution that would be used to fill in the blanks would be

The way that Quintin would be able to do this would be the center of the circumferential triangle is equidistant from the vertices.

The center is going to be the intersection of the bisectors of the three sides of the given triangle.

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perpendicular bisectors, is the center of, circumscribed

Answer:

In the image

Hope this helps!

Step-by-step explanation:

1. perpendicular

2. is the center of

3. circumscribed

The volume of the cuboid is 132 cubic inches.

Given length of cuboid 7 1/3 inches, breadth being 6 2/3 inches , height being 2 7/10 inches.

Volume is amount of liquid a container can hold in its capacity. Cuboid is a 3 dimensional figure having length , breadth and height.Volume of cuboid is the product of length, breadth and height of cuboid.

We have to calculate volume of cuboid.

We have to make a simple fraction showing length , breadth and height.

Length=(3*7+1)/3=22/3

Breadth=(3*6+2)/3=20/3

Height=(10*2+7)/10=27/10

Volume=22/3*20/3*27/10

=11880/90

=132 cubic inches.

Hence the volume of cuboid having length of 22/3 inches, breadth of 20/3 inches and height of 27/10 is 132 cubic inches.

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Question is incomplete as it should include figure.

The probability of first rolling a 1, then a 5, will be [tex]\frac{1}{36}[/tex].

To find the probability of getting a 1 the first time and a 5 the second time:

Probability of getting 1 in 1st time = [tex]\frac{1}{6}[/tex]

Probability of getting 5 in 2nd time = [tex]\frac{1}{6}[/tex]

The probability of first rolling a 1, then a 5, will be = [tex]\frac{1}{6}[/tex] × [tex]\frac{1}{6}[/tex]

[tex]= \frac{1}{36}[/tex]

Therefore, the probability of first rolling a 1, then a 5, will be [tex]\frac{1}{36}[/tex].

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Answer:

144=12², so 144^3/2=(12²)^(3/2)=12³=1728.

this answer is not from the internet

go check yourselves

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El precio resultante con descuento de 12 % es igual a 342.32 pesos.

En este problema tenemos que determinar el precio resultante, el cual es igual al precio inicial menos el descuento. A continuación, se presenta la siguiente expresión:

x = 389 · (1 - 12/100)

x = 389 - 46.68

x = 342.32

El precio resultante con descuento de 12 % es igual a 342.32 pesos.

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(i) 57students liked at least one game.

(ii) 7 students who liked both the games.

(iii) 27 students liked football.

(iv) 37 students liked cricket.

(v) Below we represented the result in a Venn diagram.​

What is Venn diagram?

John Venn popularized the Venn diagram in the 1880s, which is a type of diagram that displays the logical relationship between sets. The illustrations are used in probability, logic, statistics, linguistics, and computer science to demonstrate basic set relationships and to teach rudimentary set theory.

Part (i)- We have to get number of people who like at least one game, there are total 75 students and only 18 did not like any of two games, so students who like at least one game are-

75-18 = 57

Part (ii)- There are 57 students who like at least one game, from the question statement we know that 20 students like football only and 30 liked cricket only, so student who like both games are-

57-20-30 = 7

Part (iii)- There are 7 students who liked both games and 20 who liked football only, so student who liked football are-

20+7 = 27

Part (iv)- There are 7 students who liked both games and 30 who liked cricket only, so student who liked cricket are-

30+7=37

Part (v)- Venn Diagram will look like-

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Complete Question- In a group of 75 students, 20 liked football only, 30 liked cricket only and 18 did not like any of two games? (i) How many of them liked at least one game? (ii) Find the number of students who liked both the games. (iii) How many of them liked football? (iv) How many of them liked cricket? (v) Represent the result in a Venn diagram.​

By applying the Theorem of Intersecting Secant to circle Q, an equation which is correct about the measure of ∠MNP is: A. m∠MNP = One-half(x – y).

The Theorem of Intersecting Secant states that when two (2) lines intersect outside a circle, the measure of the angle formed by these lines is equal to one-half (½) of the difference of the two (2) arcs it intercepts.

For this exercise, the following points should be noted:

By applying the Theorem of Intersecting Secant to circle Q shown in the image attached below, we can infer and logically deduce that angle MNP will be given by this formula:

m∠MNP = One-half(x – y).

m∠MNP = ½(x – y)

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The relationship that can be modeled by the function shown in the table is y = 4·√x

f(x) is defined as a product of 4 into √x

4 × √1 = 4

4 × √4 = 8

4 × √9 = 12

4 × √16 = 16

4 × √25= 20

Therefore, the relationship is defined as y is 4 times the square root of x that is, y = f(x) = 4√x

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The quadrants of the points that needs to be graphed  are:

Since the points that was given are:

A(2, 4)        B(0, -3)  

C(1, -1)       E(-4,1)    

G(-3,-2)      I(0, 2)

D(3, 3)        F(2,0)  

H(-2, 3)     J(-1,-4)

Then, we plot all the coordinate above on a graph (see image attached)

Hence, from the image attached graph, the categories that can be seen are:

Quadrant 1 is  Points A and D

Quadrant 2 is  Points E and H

Quadrant 3 is Points G and J

Quadrant 4 is Points C

x-axis-  Point F

y-axis- Point B and I

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Answer:

See below.

Step-by-step explanation:

Here is an example:-

Solve by elimination:

2x - 3y  =   0

3x + 2y =  13

To eliminate the y terms Multiply the first equation by 2 and the second by 3. This gives:

4x  - 6y = 0

9x + 6y = 39      Adding the 2 equations:

13x + 0 = 39

13x = 39

x = 39/13 = 3

Finally we find y by plugging x = 3 into the first equation:

2(3) - 3y = 0

3y = 2(3) = 6

y = 2.

The triangles are congruent by SAS congruence theorem

From the figure, we have the following congruent sides

Also, both triangles share a common vertex at B

This means that:

<B = <B

Two sides and one angle are congruent in the triangles

Hence, the triangles are congruent by SAS congruence theorem

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Answer:

x-intercept = 8

Step-by-step explanation:

Hello!

An x-intercept is when the y-value is 0, or when the graph intersects the x-axis.

We can replace p(x) with 0 and solve for x.

The x-intercept is 8.

Check the picture below, so the parabola looks more or less like so, with the vertex half-way from the focus point and the directrix.

Now, the distance from the directrix to the focus point is only 1 unit, so half that, or namely the "p" distance is 1/2 unit, and since the parabola is opening downwards, "p" is negative, so

[tex]\textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\begin{cases} h=0\\ k=-\frac{1}{2}\\[1em] p=-\frac{1}{2} \end{cases}\implies 4\left( -\frac{1}{2} \right)\left( ~~y-\left( -\frac{1}{2} \right) ~~ \right)~~ = ~~(x-0)^2 \\\\\\ -2\left( y+\frac{1}{2} \right)=x^2\implies y+\cfrac{1}{2} =\cfrac{x^2}{-2}\implies y = -\cfrac{1}{2}x^2-\cfrac{1}{2}[/tex]

now, we could also write that as either

[tex]y = -\cfrac{1}{2}(x^2+1)\qquad or\qquad y = \cfrac{1}{2}(-x^2-1)[/tex]

Shipping points are independent organizational entities within which processing and monitoring of the deliveries, as well as goods issue, is carried out. A delivery is processed by one shipping point only.

"FOB shipping point" or "FOB origin" means the buyer is at risk once the seller ships the product. The purchaser pays the shipping cost from the factory and is responsible if the goods are damaged while in transit. "FOB destination" means the seller retains the risk of loss until the goods reach the buyer.

Please check the attached file for a complete answer.

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the one you selected is correct

  [a] x = 175 - 7.5p

For a, we are isolating the x variable to one side of the equation.

        0.4x + 3p = 70

        0.4x = - 3p + 70

        x =  - 7.5p + 175

  [b] x = 115

For b, we are solving for x when p = 8.

        x =  - 7.5p + 175

        x =  - 7.5(8) + 175

        x = 115