PLEASE HELP ASAP
ANSWE

Correct answer is,

The mean is greater than the median, and the majority of the data points are to the left of the mean.

Since, The probability depicts the intended benefits of all possible values for just a specific data-generation procedure. This is a list of all of the possible values of random variables, along with the probability for each one of them.

We could see that the curve is tilted to the right by drawing a normal distribution bell curve.

This has a right tail, which implies it has a tail. This indicates that there are few points to the right of the mean.

A majority of the pieces of data are about the left of the mean, as stated.

The bulk of data are to the right, the median will be from the left of the mean, indicating that the median is less than the mean.

Hence, As just a result, the mean exceeds the median.

Therefore, the answer is "third choice".

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The way to transform A to B is (1,-1).

We are given that;

The coordinates (-1,1),(-3,1),(-1,3) and (1,-1),(3,-1),(1,-3).

Now,

To transform the coordinates (-1,1),(-3,1),(-1,3) to (1,-1),(3,-1),(1,-3), you can apply a reflection about the origin. This transformation can be represented by the matrix [-1 0; 0 -1]. When you multiply this matrix with the original coordinates, you will get the transformed coordinates.

First, represent the point (-1,1) as a column vector:

[-1]

[ 1]

Then, multiply this vector by the reflection matrix [-1 0; 0 -1]:

[-1 0; 0 -1] * [-1] = [ 1]

[ 1]   [-1]

Therefore, by transformation the answer will be (1,-1).

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Answer:

The algebraic expression for the phrase "the product of two numbers increased by 4" can be written as `xy + 4`, where `x` and `y` represent the two unknown numbers.

Answer:

Step-by-step explanation:

To translate the phrase “the product of two numbers increased by 4” into an algebraic expression, we can use the variables x and y to represent the two numbers.

The product of two numbers is xy, and if we increase this by 4, we get:

xy + 4

Therefore, the algebraic expression for “the product of two numbers increased by 4” is: xy + 4

I hope this helps! Let me know if you have any other questions.

[tex]|\Omega|=19+28+21+29=97\\|A|=19+28+21=68\\\\P(A)=\dfrac{68}{97}[/tex]

We are given two curves on a graph paper and we have to find the y values for the given x.

From the graph we can check for a value of x, what is the value of y from the curve.

x     -3     -2     -1    0      1         2        3

Exp  8      4      2    1      0.5  0.25  0.125

Lin.   7.5   6    4.5   3      1.5     0     -1.5

We find that the two have the same values where the two curves intersect.

From the graph we find that near to -3 and near to 2 both have the same values.

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The missing graph is attached below.

Answer: $4,998

Step-by-step explanation:

34000*1.147

38998-34000=4998

The value of variables in the figure is,

⇒ x = 80

⇒ y = 70

We have to given that;

By using given figure we have to find the value of each variable.

Now, We can formulate;

⇒ 55 = 1/2 (180 - y)

Solve for y;

⇒ 55 × 2 = 180 - y

⇒ 110 = 180 - y

⇒ y = 180 - 110

⇒ y = 70

And, The value of x is,

⇒ x = 180 - (60 + 40)

⇒ x = 180 - 100

⇒ x = 80

Thus, The value of variables in the figure is,

⇒ x = 80

⇒ y = 70

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The value of y is 10.8.

Here, we have,

given that,

The equation is: 5/3log_4(x)=9

or, 5 log₄x = 27

or, log₄x = 27/5

now, we have,

Using the property, x = loga, a = eˣ

we get,

x = 4²⁷/⁵

or, x = 4⁵°⁴

or, x = 2¹⁰°⁸

so, comparing with x=2^y , we get,

y = 10.8

Hence, The value of y is 10.8.

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The expanded logarithmic expression in the context of this problem is given as follows:

[tex]\log_7{(2 \times 11)^3} = 3\log_7{2} + 3\log_7{11}[/tex]

The logarithmic expression in the context of this problem is given as follows:

[tex]\log_7{(2 \times 11)^3}[/tex]

First we apply the power rule of logarithms, which states that the logarithm of a number applied to a power is equals to the power multiplying the logarithm of the number, hence:

[tex]\log_7{(2 \times 11)^3} = 3 \log_7{(2 \times 11)}[/tex]

Then we apply the product rule, which means that we can add the logarithms of base 7 of these two numbers, as follows:

[tex]\log_7{(2 \times 11)^3} = 3\log_7{2} + 3\log_7{11}[/tex]

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The value of x in the triangle is 28.3 degrees., y is 7.837 and z is 7.837.

We can find the value of x by using angle sum property.

It states that the sum of three angles in a triangle is 180 degrees.

61.7+90+x=180

151.7+x=180

Subtract 151.7 from both sides:

x=180-151.7

x=28.3 degrees.

Now let us find the value of y.

We know that tan function is a ratio of opposite side and adjacent side.

tanx=y/14.76

tan(28.3) = y/ 14.76

0.531 = y/14.76

Now apply cross multiplication:

y=0.531×14.76

y=7.837

Now let us find z:

sin 90=y/z

1=7.837/z

z=7.837

Hence, the value of x in the triangle is 28.3 degrees., y is 7.837 and z is 7.837.

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Option B has the highest overall cost by $64.50.

To determine the option that would result in the highest overall cost for the employee

we need to compare the costs of both options based on the estimated prescription drug expenses.

Option A:

Monthly premium: $94

Prescription coverage: 80%

Option B:

Monthly premium: $42

Prescription coverage: 75% for the first $500, 85% for costs over $500

Let's calculate the costs for each option:

Option A:

Total prescription drug cost: $1,250

Employee's share (20%): 20% × $1,250 = $250

Monthly premium: $94

Total cost for Option A: $250 + $94 = $344

Option B:

Total prescription drug cost: $1,250

Employee's share for the first $500 (25%): 25% × $500 = $125

Employee's share for costs over $500 (15%): 15% × ($1,250 - $500) = $112.50

Monthly premium: $42

Total cost for Option B: $125 + $112.50 + $42 = $279.50

Comparing the total costs for each option, we see that Option B has a lower overall cost for the employee.

Hence, Option B has the highest overall cost by $64.50.

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The expression that we need to solve is 4*45 + 2*123 , and that is equal to 426.

Here we want to calculate the quadruple of the decimal part by adding twice the integer part of the following decimal number: 123.45​

The decimal part of this number is 45

The integer part of this number is 123.

Then the expression that we need to solve is:

4*45 + 2*123 = 426

That is the value of the mathematical sentence.

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Answer:c

Step-by-step explanation:

To calculate the volume of a cylinder, we use the formula:

Volume = π * radius^2 * height

Given:

Radius = cm

Height = 4 cm

π (pi) = 3.14

Let's substitute these values into the formula and calculate the volume:

Volume = 3.14 * (cm)^2 * 4 cm

= 3.14 * (cm^2) * 4 cm

= 12.56 * cm^3

Rounding the answer to the nearest tenth, we get:

Volume ≈ 12.6 cm^3

Among the answer choices provided, the closest option to 12.6 cm^3 is:

B. 28.3 cm^3

Therefore, the correct answer is B. 28.3 cm^3.

Answer:

x=i[tex]\sqrt{2}[/tex], x=-i[tex]\sqrt{2}[/tex]

Step-by-step explanation:

This equation can be factored. In order to do so, we can split the expression into two parts: (x^3-3x^2) and (2x-6). The greatest common factor of the first group is x^2, factoring it out gives us x^2(x-3). The greatest common factor of the second group is 2, factoring it out gives us 2(x-3). Since both x^2 and 2 are being multiplied by x-3, we add them into a factored form of (x^2+2)(x-3)=0

x-3 provides us with one real root, so we can disregard it.
x^2+2=0 ---> x^2=-2--->x=±[tex]\sqrt{-2}[/tex]
Factoring out the imaginary number i (equals [tex]\sqrt{-1}[/tex]), we get x=±i[tex]\sqrt{2}[/tex]

Work Shown:

LCM = (product of two numbers)/(HCF of the two numbers)

LCM = 1536/16

LCM = 96

You have the derivative of a product:

first limit (7x+3)

second limit (4-3x)

The Rule for the derivative of a product is:

(first limit × derivative of second limit) + (second limit × derivative of first limit)

f(x) = (7x+3)(4-3x)

f'(x)=(7x+3)×-3 + (4-3x)×7 = -21x- 9 + 28-21x

f'(x) = -42x + 19

Answer:

D 0.89275

Step-by-step explanation:

The volume of the extra space in the box is 9.0 cubic inches.

To estimate the volume of the extra space in the box, we shall find the difference between the volume of the box and the volume of the cracker tower.

First, volume of the box:

The volume can be calculated as the product of the height, length, and width (we assume the width is the same as the side length since it is a square prism):

Box volume = height * length * width

Given:

height = 8 inches

side length = 2 inches

Box volume = 8 * 2  * 2

= 32  in³

Next, the volume of the cracker tower:

The tower of the cracker is cylindrical, so we shall use the formula for the volume of a cylinder to estimate the volume:

Tower volume = π * (radius²) * height

Given:

height = 7.9 inches

diameter = 1.9 inches

radius = diameter / 2 = 1.9  / 2 = 0.95

Tower volume = π * (0.95)² * 7.9

≈ 22.994 in³ (rounded to three decimal places)

Then, the volume of the extra space in the box:

Volume of the extra space = Tower volume - Box volume:

= 32 in³ - 22.994 in³

≈ 9.006 in³ (rounded to three decimal places)

Therefore, the volume of the extra space in the box = 9.0 in³.

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The class has collected a total of 74 pounds of food so far.

The class collected 33 pounds on the first day and 41 pounds on the second day.

To find the total pounds of food collected, we add these two amounts together:

33 pounds + 41 pounds = 74 pounds

On the first day, the students gathered 33 pounds, and on the second day, they collected 41 pounds.

We combine these two figures together to get the total number of pounds of food collected:

33 lbs. plus 41 lbs. equals 74 lbs.

On the first day, the class brought in 33 pounds, and on the second, 41 pounds.

We combine these two figures to get the total weight in pounds of food collected:

44 pounds plus 33 pounds equals 74 pounds.

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Answer:

x = 17

Step-by-step explanation:

KL + LM = KM

x+8+12 = 3x-14

or, x+20 = 3x-14

or, 3x-x=20+14

or, 2x = 34

x = 17

Answer:

Step-by-step explanation:

3x-14=x+8+12

3x-x=8+12+14

2x=34

x=17

then

KL=(17)+8=25

It is generally appropriate to calculate a probability about the difference in sample means when the sample sizes are large (typically n ≥ 30) and the populations are approximately normally distributed.

To determine if it is appropriate to calculate a probability about the difference in sample means, consider the assumptions and conditions for conducting a hypothesis test or constructing a confidence interval. The appropriateness of calculating a probability about the difference in sample means depends on the following factors:

1) Both population shapes are unknown. n1 = 50 and n2 = 100:

- It is generally appropriate to calculate a probability about the difference in sample means when the sample sizes are large (typically n ≥ 30) and the populations are approximately normally distributed. Since the population shapes are unknown in this case, it is difficult to assess this condition. However, the large sample sizes (n1 = 50 and n2 = 100) may suggest that it is reasonable to approximate the population distributions as normal. Therefore, calculating a probability about the difference in sample means could be considered.

2) Population 1 is skewed right and population 2 is approximately Normal. n1 = 50 and n2 = 10:

- In this case, the assumption of approximately normally distributed populations is violated for population 1, which is skewed right. When the population distributions are not approximately normal, it may not be appropriate to calculate a probability about the difference in sample means. The small sample size for population 2 (n2 = 10) may also limit the accuracy of any inference made based on this sample.

3) Both populations are skewed right. n1 = 5 and n2 = 10:

- Similar to the previous case, the assumption of approximately normally distributed populations is violated for both populations. Additionally, the small sample sizes (n1 = 5 and n2 = 10) may not provide sufficient information for reliable inferences. Therefore, it is generally not appropriate to calculate a probability about the difference in sample means in this situation.

4) Population 1 is skewed right and population 2 is approximately Normal. n1 = 10 and n2 = 50:

- Similar to case 2, the assumption of approximately normally distributed populations is violated for population 1, which is skewed right. In this case, the sample size for population 1 (n1 = 10) is also small, which may limit the accuracy of any inference made based on this sample. The larger sample size for population 2 (n2 = 50) might make it more reasonable to approximate the population distribution as normal. However, the violation of the assumption for population 1 suggests caution when interpreting the results. It is not generally appropriate to calculate a probability about the difference in sample means in this situation.

5) Both populations have unknown shapes. n1 = 50 and n2 = 100:

- Similar to case 1, the population shapes are unknown. However, the large sample sizes (n1 = 50 and n2 = 100) might suggest that it is reasonable to approximate the population distributions as normal. As mentioned before, calculating a probability about the difference in sample means could be considered in this case.

6) Both populations are skewed left. n1 = 5 and n2 = 40:

The assumption of approximately normally distributed populations is violated for both populations, as they are skewed left. Additionally, the small sample sizes (n1 = 5 and n2 = 40) may not provide sufficient information for reliable inferences. Therefore, it is generally not appropriate to calculate a probability about the difference in sample means in this situation.

Summarily, it is generally appropriate to calculate a probability about the difference in sample means when the sample sizes are large (typically n ≥ 30) and the populations are approximately normally distributed. However, when the population distributions are not approximately normal or when the sample sizes are small, it is generally not appropriate to calculate a probability about the difference in sample means.

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Answer:

119

Step-by-step explanation:

The 95% confidence interval for the mean number of delivery orders on a Friday night is 36 to 60 orders.

The confidence interval for the mean number of delivery orders on a Friday night is constructed assuming a 95% confidence level.

Given data:

Sample mean (x) = 48 orders

The margin of error (E) = 12 orders

To calculate the confidence interval, we'll use the formula:

Confidence Interval = x ± E

Substituting the values:

Confidence Interval = 48 ± 12

The lower limit of the confidence interval:

Lower Limit = 48 - 12 = 36

The upper limit of the confidence interval:

Upper Limit = 48 + 12 = 60

Therefore, the 95% confidence interval for the mean number of delivery orders on a Friday night is 36 to 60 orders.

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Complete question:

In Boston, A Popular Restaurant Recently Added A Delivery Option. In Reviewing The Sales For This New Delivery Service, The Restaurant Found The Mean Delivery Orders In A Random Sample Of Friday Nights Was X¯=48 Orders, With A Margin Of Error Of 12 Orders. Construct A Confidence Interval For The Mean Number Of Delivery Orders On A Friday Night.

All the slopes of tables are,

13) m = 2

14) m = - 1/1

15) m = 0

16) m = 3

17) m = infinite

18) m = - 1/3

We have to given that;

All the tables are shown.

And, To find the slope of all the table.

Since, We know that;

Slope passing through the points (x₁ , y₁) and (x₂, y₂) is defined as,

⇒ m = (y₂ - y₁) / (x₂ - x₁)

Hence, We get;

13) Two points are (- 2, - 3) and (- 1, - 1)

Hence, Slope is,

m = (- 1 + 3) / (- 1 + 2)

m = 2/1

m = 2

14) Two points are (- 4, 6) and (0, 4)

Hence, Slope is,

m = (4 - 6) / (0 + 4)

m = - 2/4

m = - 1/2

15) Two points are (6, 2) and (3, 2)

Hence, Slope is,

m = (2 - 2) / (3 - 6)

m = 0

16) Two points are (- 2, - 3) and (0, 3)

Hence, Slope is,

m = (3 + 3) / (0 + 2)

m = 6/2

m = 3

17) Two points are (3, 6) and (3, 4)

Hence, Slope is,

m = (4 - 6) / (3 - 3)

m = infinite

18) Two points are (- 4, 4) and (- 1, 3)

Hence, Slope is,

m = (3 - 4) / (- 1 + 4)

m = - 1/3

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The 95% confidence interval for the total percentage of national park visitors who support supporting endangered species is approximately 33.3% to 52.7%.

To calculate the 95% confidence interval for the percentage of national park visitors who support supporting endangered species, we can use the formula:

Confidence Interval = Sample proportion ± (Critical value * Standard error)

Given that 43% of a sample of 100 visitors believe that additional funds should be used to preserve endangered species, the sample proportion is 0.43.

To calculate the standard error, we use the formula:

Standard Error = sqrt((p * (1 - p)) / n)

where p is the sample proportion and n is the sample size. In this case, p = 0.43 and n = 100.

Standard Error = sqrt((0.43 * (1 - 0.43)) / 100) ≈ 0.0495

The critical value for a 95% confidence interval can be obtained from a standard normal distribution table. For a 95% confidence level, the critical value is approximately 1.96.

Now we can calculate the confidence interval:

Confidence Interval = 0.43 ± (1.96 * 0.0495)

Confidence Interval = 0.43 ± 0.097

The lower bound of the confidence interval is 0.43 - 0.097 = 0.333

The upper bound of the confidence interval is 0.43 + 0.097 = 0.527

Therefore, the 95% confidence interval for the total percentage of national park visitors who support supporting endangered species is approximately 33.3% to 52.7%.

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