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The man is 23 km west of his home after driving 169 km to the east and 192 km to the west.

To determine how far the man is from his home after driving 169 km to the east and 192 km to the west, we can think of his movements as a displacement vector.

The vector representing the man's movement to the east has a magnitude of 169 km and is directed towards the east. Similarly, the vector representing his movement to the west has a magnitude of 192 km and is directed towards the west.

Since these two vectors are in opposite directions, we can subtract them to find the net displacement vector.

Net displacement = 169 km east - 192 km west

= -23 km west

The negative sign indicates that the net displacement vector is directed towards the west, which means that the man is 23 km west of his home.

To determine the distance between the man and his home, we can use the Pythagorean theorem. Since the man moved only in the east-west direction, the distance between him and his home is the absolute value of the net displacement, which is 23 km.

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The approximate value of P(adult ∣ rode a ferris wheel) is 0.6364, which is approximately 63.64%.

To find the approximate value of P(adult|rode a ferris wheel), we can use the conditional probability formula:

[tex]\mathrm{P(adult | rode\ a\ ferris\ wheel) = \frac{P(adult \ and \ rode \ a \ ferris \ wheel)}{P(rode \ a \ ferris \ wheel)} }[/tex]

From the data given in the table, you can see that:

Total number of people who rode the ferris wheel: 198 (children + adults)

Number of adults who rode the ferris wheel: 126.

So, P(rode a ferris wheel) = 198/264

And, P(adult and rode a ferris wheel) = 126/264

Now plug these values into the conditional probability formula:

​[tex]\mathrm{P(adult | rode\ a\ ferris\ wheel) = \frac{P(adult \ and \ rode \ a \ ferris \ wheel)}{P(rode \ a \ ferris \ wheel)} } \\\\= \frac{126/264}{198/264}[/tex]

[tex]\mathrm{P(adult | rode\ a\ ferris\ wheel) } = \frac{126}{198} \\\\ \approx 0.6364[/tex]

Rounded to four decimal places, the approximate value of P(adult ∣ rode a ferris wheel) is 0.6364, which is approximately 63.64%.

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The 30th partial sum of the sequence 5x-12 = 1965

To derive the 30th partial sum of the sequence 5x -12, we need to add up to the first 30 terms of the sequence.

Th e nth term of the sequence will be:

5 -12

the first 30th terms are:

5(1) -12 = -7

5(2) -12 = -2

5(3) -12 = -3

5(4)  -12 = -8

and so on

So to get the 30th partial sum, we write:
-7 + (-2) = 3+ 8 ...... + (5(30)-12

If simplified, this expression will given us:

S = (n/2) (a+l)

In this case,

s is the sum of the n terms
A is the first term and
L is the last term.

In this ase, a = -7 (the first term) and L= 5(30) -12 = 138 (the 30th term) So  for the partial sum we say:

S30 = (30/2) (-7 + 138) = 30(131)/2
S30 = 1965

Thus, the partial sum of the sequence 5x-12) is 1965

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The graphical representation that will be most appreciated for the data would be box plot, because the median can easily be determined from the large set of data. That is option A.

The box plot is a type of graphical representation of data that gIves more than one detail about the data set such as;

Box plots allow you to compare multiple data sets better than others dues to the above listed features that it has.

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A Reflect triangle over the line x = -1 will take ABC to A"B"C".

What is triangle reflection theorem?

The outcome is the same as rotating the initial triangle 180 degrees around the origin, just as the theorem predicts, when we reflect the triangle over the y-axis and then cross the x and y axes while reflecting the outcome across the x axis.

The single transformation that takes ABC to A"B"C" is a reflection over the line x = -1.

The new triangle A'B'C' is formed by reflecting ABC across the line x = -2, where each point in A', B', and C' is the reflection of the corresponding point in ABC. As a result, A', B', and C''s x-coordinates are all 4 units to the left of A', B', and C''s x-coordinates.

The final triangle A"B"C is formed by reflecting A'B'C' over the line x = 0, where each point in A", B", and C" is a reflection of the corresponding point in A'B'C' over the line x = 0. Accordingly, the x-coordinates of A, B, and C" are all located two units to the right of the x-coordinates of A', B', and C'.

If we combine these two reflections into a single transformation, we can think of it as reflecting ABC over a line that is 2 units to the right of x = -2, which means it has an equation of x = -2 + 2 = -1. This line is the perpendicular bisector of the segment connecting the points (-2, 0) and (0, 0), which is the line that connects the two reflection lines x = -2 and x = 0.

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Answer:

5

Step-by-step explanation:

6.5 / x = 1.3

multiply by x on each side to cancel it out

6.5 = 1.3x

/1.3   /1.3

x = 5

1.3 x 5 = 6.5

Answer: True

Step-by-step explanation:

Answer:

Step-by-step explanation:

330/2 = 165

330/3 = 110

330/5 = 66

330/6 = 55

330/10 = 33

330/11 = 30

the answer is true

The length of the third side ​of a triangle cannot be 15 cm

The correct answer is an option (b)

We know that the triangle inequality theorem states that the sum of any two sides of a triangle is greater than or equal to the third side.

For example if a, b, c represents the side of a triangle then by above theorem a + b ≥ c

Here, the two sides of a triangle measure 4 cm and 8 cm.

Let a = 4 cm and b = 8 cm and c represents the third side of a triangle.

Using triangle inequality theorem,

a + b ≥ c

4 + 8 ≥ c

12 ≥ c

This means that the third side of the triangle must be less than or equal to 12 cm.

Thus, the correct answer is an option (b)

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The complete question is:

A triangle has two sides measuring 4 cm and 8 cm. Which lengths cannot be the length of the third side ​

a) 7 cm

b) 15 cm

c) 10 cm

d) 5 cm

The volume of the solid is (256π/15) - (128π/3) cubic units, which is formed by rotating the space bounded by y = 2x², y=0, and x = 2 around the line y = 8.

To find the volume of the solid formed by rotating the space bounded by y = 2x², y=0, and x = 2 around the line y = 8, we can use the disk method.

First, we need to find the bounds of integration. Since x = 2 is the right boundary, we can integrate from 0 to 2.

The distance between the line y=8 and the curve y=2x² is 8 - 2x². Therefore, the radius of the disk at a given x-value is 8 - 2x².

The area of each disk is given by π(radius)². Therefore, the volume of the solid is given by the integral of π(radius)² dx from 0 to 2;

V = ∫₀² π(8 - 2x²)² dx

This integral can be evaluated by expanding the square and using the power rule of integration. After simplification, we get;

V = (256π/15) - (128π/3)

Therefore, the volume of the solid is (256π/15) - (128π/3) cubic units.

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Answer: Let's call the time it takes for Mrs. Cunningham to overtake Mr. Cunningham "t".

In that time, Mr. Cunningham will have traveled for 4 more hours than Mrs. Cunningham, so he will have traveled 4 + t hours.

We can set up an equation to represent the distance each person traveled:

distance = rate x time

For Mr. Cunningham:

distance = 46 mph x (4 + t) hours

For Mrs. Cunningham:

distance = 62 mph x t hours

Since they end up at the same place, their distances must be equal:

46 mph x (4 + t) = 62 mph x t

Simplifying this equation:

184 + 46t = 62t

16t = 184

t = 11.5

Therefore, it will take Mrs. Cunningham 11.5 hours to overtake Mr. Cunningham.

Step-by-step explanation:

Using Ariana's method to  work out 135 ÷  12 1/2 without a calculator will gives us:  54/5 or 10.8.

Ariana's method for division involves breaking down the divisor into a more manageable fraction and adjusting the dividend accordingly. Here's how we can use this method to solve 135 ÷ 12 1/2 without a calculator:

Step 1: Rewrite the mixed number as an improper fraction:

12 1/2 = 25/2

Step 2: Determine the reciprocal of the fraction:

25/2 → 2/25 (reciprocal)

Step 3: Rewrite the division problem as multiplication by the reciprocal:

135 ÷ 12 1/2 = 135 x 2/25

Step 4: Simplify the expression:

135 x 2/25 = (27 x 5) x 2/25 = 54/5

Therefore, 135 ÷ 12 1/2 = 54/5 or 10.8 when rounded to one decimal place.

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To translate the function y = |x| one unit value downward, we need to subtract 1 from the function: y = |x| - 1.

The function y = |x| is a V-shaped graph that passes through the origin and has a slope of 1 on both sides. It represents the absolute value of x, which means that the function always returns a positive value regardless of whether x is positive or negative.

To translate the function one unit downward, we need to subtract 1 from the function. This means that for any given value of x, the function will return the absolute value of x minus 1. For example, if x = 2, then y = |2| - 1 = 1. If x = -2, then y = |-2| - 1 = 1.

The resulting graph of y = |x| - 1 is still a V-shaped graph, but it is shifted down by one unit compared to the graph of y = |x|.

Thus, the slope of the graph remains the same on both sides, but the minimum value of y is now -1 instead of 0.

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Answer:

Step-by-step explanation:

distance traveled by one revolution = circumference of the wheel

= 2πr = 2π(13 inches) = 26π inches

number of revolutions = distance traveled / distance traveled by one revolution

100 feet = 1200 inches

= 1200 inches / 26π inches

≈ 45.91 full revolutions

An equation in slope-intercept form for the line shown in the given graph is equal to y = -5x + 5.

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

First of all, we would determine the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (5 - 20)/(0 + 3)

Slope (m) = -15/3

Slope (m) = -5.

At data point (0, 5) and a slope of -5, a linear equation in slope-intercept form for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 5 = -5(x - 0)

y - 5 = -5x

y = -5x + 5

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The solution to the given problem of volume comes out to be the pyramid is 10 cm tall.

The volume of a three-dimensional item, which is measured in cubic units, describes how much room it occupies. Liter and in3 are the symbols for cubic measures.

Here,

The formula: gives the volume of a pyramid.

=> V = base_area * height * (1/3)

The area of the base (base_area) of a pyramid whose base is a rectangle with dimensions of 7.5 cm in length and 2 cm in width can be computed as follows:

base_area equals length * width,

=> 7.5 cm * 2 cm =15 cm².

Additionally, we are informed that the pyramid's (V) volume is 50 cm3.

=> (1/3) * 15 * height = 50

=> height =  (3 * V)/base_area.

When V and base_area's values are entered, we obtain:

=> height = (15/15) / (3*50) = 10 cm

Consequently, the pyramid is 10 cm tall.

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a) The exact solutions on [0, 2π) are t = π/3, π, and 5π/3. b) The exact solution on the interval [0, π) is t = 2π/3. c) The solutions are θ = π/3 and θ = 5π/3. d) The exact solutions on the interval [0, 2π) are: t = arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4] and t = 2π - arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4] using trigonometric identities.

a) We can rewrite the equation as:

2[tex]cos^{2}t[/tex] + cos(t) - 1 = 0

Using the quadratic formula, we get:

cos(t) = [-1 ± [tex]\sqrt{1-4(2)(-1)}[/tex] ] / (4)

cos(t) = [-1 ± [tex]\sqrt{9}[/tex]]/4

cos(t) = [-1 ± 3]/4

Thus, we have two solutions:

cos(t) = 1/2, which gives us t = π/3 and t = 5π/3

cos(t) = -1, which gives us t = π

Therefore, the exact solutions on [0, 2π) are t = π/3, π, and 5π/3.

b) We can use the identity [tex]tan^{2}t[/tex] + 1 = [tex]sec^{2}t[/tex] to rewrite the equation as:

[tex]tan^{2}t[/tex] = - [tex](3/2)^{2}[/tex]

Taking the square root of both sides and remembering that tan(t) is negative in the third quadrant, we get:

tan(t) = -3/2

Using the identity tan(t) = sin(t)/cos(t), we can rewrite this as:

sin(t)/cos(t) = -3/2

Multiplying both sides by cos(t) and rearranging, we get:

sin(t) = -3cos(t)/2

Squaring both sides and using the identity [tex]sin^{2}t[/tex] + [tex]cos^{2}t[/tex] = 1, we get:

9[tex]cos^{2}t[/tex]/4 + [tex]cos^{2}t[/tex] = 1

Expanding and simplifying, we get:

13 [tex]cos^{2}t[/tex] /4 = 1

[tex]cos^{2}t[/tex]  = 4/13

Taking the square root of both sides and remembering that cos(t) is negative in the third quadrant, we get:

cos(t) = -2[tex]\sqrt{13}[/tex] /13

Using the identity  [tex]sin^{2}t[/tex] +  [tex]cos^{2}t[/tex]  = 1, we can solve for sin(t) as:

sin(t) = -3/2 cos(t) = 3[tex]\sqrt{13}[/tex] /13

Therefore, the exact solution on the interval [0, π) is t = 2π/3.

c) We can use the identity sin(2θ) = 2sin(θ)cos(θ) to rewrite the equation as:

sin(θ) = 2sin(θ)cos(θ)

Dividing both sides by sin(θ) (assuming sin(θ) is non-zero), we get:

1 = 2cos(θ)

cos(θ) = 1/2

Therefore, the solutions are θ = π/3 and θ = 5π/3.

d) We can use the identity cos(2t) = 1 - 2 [tex]sin^{2}t[/tex]  and rearrange the equation as:

2 [tex]sin^{2}t[/tex]  + sin(t) - 5 = 0

Solving this quadratic equation using the quadratic formula, we get:

sin(t) = [-1 ± [tex]\sqrt{41}[/tex]]/4

Since the sine function has a range of [-1, 1], only the positive solution is possible, so we have:

sin(t) = (-1 + [tex]\sqrt{41}[/tex])/4

Using the identity [tex]cos^{2}t[/tex] = 1 -  [tex]sin^{2}t[/tex] , we can solve for cos(t) as:

cos(t) =[tex]\sqrt{1-sin^{2}t}[/tex] = [tex]\sqrt{17-\sqrt{41} }/4[/tex]

Therefore, the exact solutions on the interval [0, 2π) are:

t = arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4] and t = 2π - arcsin[(-1 +  [tex]\sqrt{41}[/tex])/4]

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The predicted length for a catfish with weight of 48 pounds is given as follows:

45 inches.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

Two points on the graph of the linear function are given as follows:

(20, 3) and (30, 21).

When x increases by 10, y increases by 18, hence the slope m is given as follows:

m = 18/10

m = 1.8.

Hence:

y = 1.8x + b.

When x = 20, y = 3, hence the intercept b is given as follows:

3 = 1.8(20) + b

b = 3 - 36

b = -33.

Hence the equation is:

y = 1.8x - 33.

The predicted length for a catfish with weight of 48 pounds is obtained as x when y = 48, hence:

48 = 1.8x - 33

x = 81/1.8

x = 45 inches.

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Supplementary angles are angles that add up to 180°. Angle 6 is a right angle, so it's worth 90°. This means that the other angle(s) have to be 90° as well.

As you can see, the other angle with 90° is angle 3, thus, making it the correct answer.

The function f has only one critical value on the open interval (0,10), and the answer is (a) one.

To find the critical values of the function f(x) on the open interval (0,10), we need to find the values of x where f'(x) is equal to zero or undefined.

First, we need to find the values of x where f'(x) is undefined. Since f'(x) contains a term of x in the denominator, it will be undefined at x = 0. However, since the interval we are interested in is (0,10), we can exclude this value.

Next, we need to find the values of x where f'(x) is equal to zero. We can set the numerator of f'(x) equal to zero and solve for x

cos(x²) = 1/5

Taking the inverse cosine of both sides, we get

x² = arccos(1/5)

x = ±√(arccos(1/5))

However, since we are only interested in the interval (0,10), we can discard the negative root. Using a calculator, we can find that

√(arccos(1/5)) ≈ 2.6779

Therefore, the correct option is (a) one

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For a 10,000 linear feet of fencing and wants to enclose a rectangular field, the maximum area of each pasture is equals to the 2,083,333.33 square feet .

A rancher wants to enclose about 10,000 linear feet of fencing in a rectangular field. There are two equal pastures. Let, W the Width and L the Length with 3 pieces. The total length will be equal to 2W + 3L. As we know, the Area of rectangle, A = L×W ---(1)

Perimeter of rectangle = 10,000 feet, so sum of all sides of rectangle, 2W + 3L = 10000

Solve for determining value of L, 3L

= 10000 - 2W

[tex]L = \frac{ 10000 - 2W }{3}[/tex]

Substitutes for L into the first equation, A = L×W

[tex]A = W(\frac{ 10000 - 2W }{3})[/tex]

For maximum area, set the 1st derivative = 0.

differentiating above Area equation w.r.t W,[tex] A = \frac{(10000 \: W - 2W^2)}{3}[/tex]

[tex] \frac{dA}{dW} = \frac{d(\frac{10000 \: W - 2W^2}{3})}{dW}[/tex]

=> [tex]\frac { 1}{3}(10000 - 4W) = 0 [/tex]

=> W = 2500 meters

Now, using above relation, 2W + 3L= 10000

=> 5000 + 3L = 10000

=> 3L = 5000

=> L = 1667 meters

Area = 2500× 5000/3 = 4,166,666.67 sq feet. Now, maximum area of each pasture

= 4,166,666.67/2 = 2,083,333.33333 sq. feet. Hence, required value is 2,083,333.33 sq. feet.

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The probability of selecting a J or an A on the second draw, given that an E was selected on the first draw is 0.101.

The number of tiles which have an E on them are shown to be 12 which means that if an E was selected on the first draw, there are now 99 tiles left.

The probability that an A or J will be selected in this second draw would be :

= ( Number of A tiles and J tiles ) / 99

Number of A tiles = 9

Number of J tiles = 1

The probability is then :

= ( 9 + 1 ) / 99

= 10 / 99

= 10.1%

= 0.101

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For a normally distribution of daily demand of fresh boston lettuce produce by skinner. the probability that skinner will have at least 20 units left over by the end of the day is equals the one.

Skinner produce buys fresh boston lettuce daily. There is daily demand is normally distributed,

Mean = 100 units

Standard deviations = 15 units

At beginning of the day skinner orders 140 units of lettuce. We have to determine the probability that skinner will have at least 20 units left over by the end of the day, P( X ≥ 20). Using the Z-Score for normal distribution is written as

[tex]z = \frac{ X - \mu}{\sigma} [/tex]

where, z --> z-score

X --> excepted value

--> standard deviations

--> population mean

Subsritute the known values in above formula, [tex]z = \frac{ 20 - 100}{15} [/tex]

= - 5.33

Now, probability value, P ( X < 20)

[tex]= P( \frac{X - \mu}{\sigma} < \frac{ 20 - 100}{15} )[/tex] = P( z < - 5.33 )

= 0.000

So, P( X < 20) = P( z< -5.33) = 0 . Also, required probability is P( X≥ 20) = 1 - 0

= 1

Hence, required value is one.

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The graph of a quadratic function in the form of y = ax² + bx + c, where "a" is not equal to zero, has a minimum value when "a" is positive.

what is quadratic function ?

A quadratic function is a second-degree polynomial function of the form f(x) = ax² + bx + c, where "a", "b", and "c" are constants, and "a" is not equal to zero. The graph of a quadratic function is a U-shaped curve called a parabola.

In the given question,

The graph of a quadratic function in the form of y = ax² + bx + c, where "a" is not equal to zero, has a minimum value when "a" is positive. This is because the parabola opens upward, and the vertex of the parabola, which represents the minimum point of the function, is located at the point (-b/2a, c - b²/4a).

On the other hand, if "a" is negative, the graph of the quadratic function will have a maximum value. This is because the parabola opens downward, and the vertex of the parabola represents the maximum point of the function.

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The complex number with the greatest modulus is given as follows:

z1.

A complex number is a number that is composed by a real part and an imaginary part, as follows:

z = a + bi.

In which:

The modulus of the complex number is obtained as follows:

|z| = sqrt(a² + b²).

On the coordinate plane, we have that:

In this problem, we have that the complex number z1 has both the highest absolute value in the x-coordinate and in the y-coordinate, thus it has the largest modulus.

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Answer:

hence the value of w is 12

Step-by-step explanation:

[tex]area = 2 {w}^{2} - 16w \\ by \: the \: question \: if \: area \: is \: equal \: to \: 8w \\ 8w = 2w {}^{2} - 16w \\ 8w + 16w = 2 {w}^{2} \\ 24w = 2 w {}^{2} \\ w = 12[/tex]

The volume of a stack of 9 books is 1368.75 cubic inches.

To find the volume of a stack of 9 books, we first need to find the height of the stack. Since each book is 3/4 inch thick, the height of the stack is 9 times 3/4 inch, which is 6 3/4 inches.

Now we need to find the area of the base of the rectangular prism formed by the stack of books. Since each book has an area of 22 1/2 square inches, the total area of the base of the stack is 9 times 22 1/2 square inches, which is 202 1/2 square inches.

Therefore, the volume of the stack of 9 books is:

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The coordinates of the point which is an outlier would be ( 14, 13).

The correlation between the 13 British towns is Linear.

The number of hours of sunshine for the British town with the maximum of 17.4 degrees Celsius is 13 hours of sunshine.

The coordinates of the outlier would be ( 14, 13). This is because, that point on the graph is far from the other points and does not follow their correlation.

The rest of the towns seem to be increasing in the same direction so they are linear.

The number of hours of sunshine in the British town with the maximum temperature of 17.4 degrees Celsius, based on the line of best fit drawn, would be 13 hours of sunshine.

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Full question is:

The scatter graph shows the maximum temperature and the numbers of hours of sunshine in 13 British towns in one day.

A line of best fit has also been drawn.

One of the points in an outliner.

a) Write down the coordinates of this point. (1)

b) For all the other points write down the type of correlation in just one word. (1)

On the same day, in another British town, the maximum temperature was 17.4C.

c) Estimate the number of hours of sunshine in this town on this day. (2)

Parker's standardized score (z-score) of +2.5 means that he is 2.5 standard deviations above the average score for the class. C

Normal distribution, the mean (average) is represented by the letter μ and the standard deviation by σ.

The z-score is a measure of how many standard deviations a data point is away from the mean.

A positive z-score indicates that the data point is above the mean, while a negative z-score indicates that it is below the mean.
Parker's z-score of +2.5 tells us that his score is 2.5 standard deviations above the class average.

We don't know the exact values of μ and σ, but we can use the properties of the Normal distribution to make some general statements about Parker's score.
99% of the data in a Normal distribution falls within 3 standard deviations of the mean.

Since Parker's z-score is 2.5, we can estimate that his score is higher than about 99% of the scores in the class.

Parker is performing very well in the history class compared to his peers.
z-score is a standardized measure, which means that it can be used to compare scores from different distributions.

If we wanted to compare Parker's score to the scores of students in another class, we could convert both sets of scores to z-scores and compare them directly.
Parker's z-score of +2.5 means that he is performing exceptionally well in the history class, with a score that is 2.5 standard deviations above the class average.

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The missing measures for the triangle are given as follows:

Suppose we have a triangle in which:

The lengths and the sine of the angles are related as follows:

[tex]\frac{\sin{A}}{a} = \frac{\sin{B}}{b} = \frac{\sin{C}}{c}[/tex]

The sum of the measures of the internal angles of a triangle is of 180º, hence the measure of angle B is obtained as follows:

m < B + 73 + 42 = 180

m < B = 180 - 115

m < B = 65º.

Then the relation is:

34/sin(73º) = a/sin(42º) = b/sin(65º).

Then the value of a is obtained as follows:

34/sin(73º) = a/sin(42º)

a = 34 x sine of 42 degrees/sine of 73 degrees

a = 23.8.

The value of b is obtained as follows:

34/sin(73º) = b/sin(65º)

b = 34 x sine of 65 degrees/sine of 73 degrees

b = 32.2.

More can be learned about the law of sines at https://brainly.com/question/4372174

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