PLEASE HELP!!!!!!! MT TIME FOR MY TEST IS ALMOST OVER!!!

An ideal spring, with a pointer attached to its end, hangs next to a scale. With a 100-N weight attached, the pointer indicates "40" on the scale as shown. Using a 200-N weight instead results in "60" on the scale. Using an unknown weight X instead results in "30" on the scale. The weight of X is:

From Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.

This law states that action and reaction are equal and opposite. That is the force applied to an object is equal to the reaction received by the object.

F₁₂ = -F₂₁

m₁a₁ = -m₂a₂

m₁v₁/t = -m₂v₂/t

m₁v₁ = -m₂v₂

m₁v₁ + m₂v₂ = 0

The sum of the initial momentum must be equal to sum of final momentum.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

Thus, from Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.

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Answer:

As the cars ascend the next hill, some kinetic energy is transformed back into potential energy. Then, when the cars descend this hill, potential energy is again changed to kinetic energy. This conversion between potential and kinetic energy continues throughout the ride.

Explanation:

hope it helps U

Answer:

A) nucleus, ribosomes, and chloroplasts

B) mitochondria, cell wall, chloroplasts

D) cell membrane, ribosomes, small vacuoles

E) cell wall, central vacuole, and cell membrane

Explanation:

It cannot be C as the list features centrioles, which is an animal-cell only structure.

[tex]1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\[/tex]

[tex]4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J[/tex]

The initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.

The initial velocity of a moving body can be calculated using the following formula:

a = v - u/t

Where;

According to this question, a car accelerates to a speed of 55 m/s within the span of 8 seconds. If its acceleration was 4 m/s², the initial velocity is calculated as follows:

4 = 55 - u/8

32 = 55 - u

u = 55 - 32

u = 23m/s

Therefore, the initial velocity of a car that accelerates to a speed of 55 m/s within the span of 8 seconds is 23m/s.

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Answer:

The reflection and rectilinear propagation of light helps in the formation of shadows and also tells light doesn't penetrate opaque materials.

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For a twin mass of 30.9 kg, sitting at a distance of 1.85 m, with a horizontal force of 59.0 N  the ratio of Serena's speed to Sallie's speed  is mathematically given as

V= 2.06:1

Generally, the equation for the velocity   is mathematically given as

v = w r

Therefore

[tex]\frac{v serena}{vsallie} = \frac{r serena}{r sallie}[/tex]

V= 3.63/1.76

V= 2.06

In conclusion,  the ratio is

V= 2.06:1

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Answer:

0.035

Explanation:

7÷1000

=0.007m

0.007/0.2

=0.035

Mechanical strain of an elastic substance is the ratio of its change in length to the original length. The strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.

Strain is a physical quantity used to express the change in dimension of an elastic material. It is the ratio of change in length to the original length. Stress is the force that causing the deformation.

According to Hook's law of elasticity, the strain is directly proportional to the strain. They show a linear relation. Let L be the original length of a string and its change in length be ΔL.

Thus, strain = ΔL / L

Given that, the change in length = 7 mm = 0.7 cm

original length of the string = 20 cm

strain = 0.7 cm/ 20 cm

         = 0.035

Therefore, the strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.

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Answer:

2.4*10^-17 J

Explanation:

E = V/d = 300 V / 3*10^-3 m = 1.0*10^5 V/m

Voltage at midpoint = E*d = 1.0*10^5 V/m * 1.5*10^-3 m = 150 V

ΔV = 300 V - 150 V = 150 V

Charge of a proton = 1.6*10^-16 C

U = qΔV = (1.6*10^-16 C)(150V) = 2.4*10^-17 J

The electric field strength inside the capacitor is 100,000 V/m, the Potential difference at the midpoint is 150V, and the potential energy of a proton at the midpoint of the capacitor is  2.403 x 10⁻¹⁷J.

A capacitor is an electronic device that stores electrical energy in an electric field between two conducting plates separated by a dielectric material. When a voltage difference is applied across the plates, a charge is stored on each plate, creating an electric field between the plates. The capacitor can then release this stored electrical energy when needed.

The energy stored in a capacitor is given by the formula:

U = [tex]\frac{1}{2}[/tex]CV²

Where

U =the energy stored in the capacitor,

C = the capacitance of the capacitor,

V =the voltage difference across the plates.

Capacitance is a measure of the ability of a capacitor to store charge and is given by the formula:

C = εA/d

Where C = the capacitance,

ε = the permittivity of the dielectric material between the plates,

A = the area of the plates,

d =the distance between the plates.

Here in the question

To calculate the electric field strength inside the capacitor, we can use the formula:

E = V/d

Where E = the electric field strength,

V =the voltage difference between the plates,

d =the distance between the plates.

In this case, the distance between the plates is d=3mm =0.003m,

the voltage difference is between 0V to 300V.

Now, the electric field strength inside the capacitor is:

E = V/d = 300V/0.003m = 100,000 V/m

To calculate the potential energy of a proton at the midpoint of the capacitor, we can use the formula:

U = qV

Where U = the potential energy,

q =the charge of the particle,

V =the voltage difference between the plates.

In this case, we need to know the charge of the proton.

The charge of a proton = +1.602 x 10⁻¹⁹ C.

At the midpoint of the capacitor, the proton will experience a potential difference of 150V (half of the 300V voltage difference).

Now, the potential energy of the proton at the midpoint of the capacitor is:

U = qV = (1.602 x 10⁻¹⁹ C) x (150V) = 2.403 x 10⁻¹⁷J

Therefore, the electric field strength is 100,000 V/m and the potential energy of a proton at the midpoint of the capacitor is 2.403 x 10⁻¹⁷J.

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Answer:

1/R = 1/R1 + 1/R2 + 1/R3

1/1 + 1/2 + 1/4 = 1 + .5 + .25 = 1.75

1/1.75 = .572

multiplying this by 100 gives us

R = 57.2 ohms

The smallest resistor (100 ohms) will draw the most current

(One can also use R = R1 R2 R3 / (R1 R2 + R1 R3 + R2 R3)

Hi there!

We can use the following equation to solve for equivalent resistance:

[tex]\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + ... + \frac{1}{R_n}[/tex]

We can plug in the givens and solve.

[tex]\frac{1}{R_T} = \frac{1}{100} + \frac{1}{200} + \frac{1}{400} \\\\\frac{1}{R_T} = 0.175\\\\R_T = \frac{1}{0.175} = \boxed{57.143 \Omega}[/tex]

The resistor that would draw the most current is the 100 Ohm resistor because current chooses the path of LEAST RESISTANCE. This can also be proved mathematically with the following:

For resistors in parallel, the POTENTIAL DIFFERENCE (VOLTAGE) is the same.

Since I = V/R, a smaller 'R' means a larger 'I'. Thus, the smallest resistor would have the greatest current through it.

We need evidence to be able to continually test theories about the composition and origin of our solar system and galaxies in order to verify the theories and to make laws.

A theory is an explanation for observations of the natural world that has been carried by using the scientific method, and which brings together many facts.

So we can conclude that we need evidence to test theories about the composition and origin of our solar system in order to verify the theories and to make laws.

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As it mentioned

So

power is 100W

Now

Current be I

[tex]\\ \rm\rightarrowtail I=\dfrac{P}{V}=\dfrac{100}{120}=\dfrac{5}{6}=0.8A[/tex]

Answer:

Blue supergiants represent a slower burning phase in the death of a massive star. Due to core nuclear reactions being slightly slower, the star contracts and since very similar energy is coming from a much smaller area (photosphere) then the star's surface becomes much hotter.

Explanation:

I know this may not be the answer youre looking for, but hopefully this can help somehow!

Answer:

let alpha be y,

1/2=y(x-6)^(-b)

1/2=y(1/x-6)

1/2=y/x-6

x-6=2y

x-6/2=y

(1/2)x-(6/2)=y

y=(1/2)x-3

#1

Yes gravity is acting downwards

#2

#3

#4

$5

No Applied force

Answer:

R1 + R2 = R = 12 for resistors in series - so R1 = R2 if they are identical

2 R1 = 12         and R1 = R2 = 6 ohms

1 / R = 1 / R1 + 1 / R2     for resistors in parallel

R = R1 * R2 / (R1 + R2) = 6 * 6 / (6 + 6) = 3

The equivalent resistance would be 3 ohms if connected in parallel

Answer:

load

a generator, a light bulb (load) and a closed switch

Explanation:

as explained in the other question, the fan is using generated electric energy to create mechanical movement. as such it is a load on the grid or circuit or net.

and electric power can only flow, if there is a closed (uninterupted) circuit from the power source to a load and back.

any open switch is an interruption of the circuit.

a buzzer is a kind of switch. it closes the circuit (and puts a load on) only when somebody presses it.

by the way, a closed circuit without a load will "destroy" (short circuit) the power source or at least the wires (burn through).

The electric field is all around the balloon and paper including between them, where, depending on their charge, there would be a force of either attraction or repulsion.

An electric field is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.

Thus, for the charged balloon and a charged piece of paper 0.04 m away, we can conclude that, the electric field is all around the balloon and paper including between them, where, depending on their charge, there would be a force of either attraction or repulsion.

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Answer:

292.31 m/s

Explanation:

If Distance (d) = 190m

Time (t) = 1.3s

Speed of sound in air (v) =?

then

2d=vt

v=2d/t

v= 2×190/1.3

v=292.31 m/s

Answer:

0.175 second

Explanation:

i hope it helps

The volume that the gas will occupy based on the temperature given will be 0.80 liters.

From the information, it was stated that the figure shows a pV diagram for 4.00×10−3 mole of ideal H2 gas and that the temperature of the gas does not change during segment bc.

Therefore, the volume will be:

= (0.20) × (2.0/0.50)

= 0.20 × 4

= 0.80

In conclusion, the volume is 0.80 liters.

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Answer:                                                                                    

Explanation:

Muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.

The quadriceps, hamstrings, the calf muscles and the hip adductors are the muscles which get stronger by doing walking because impact is produced on these muscles while walking. Walking is a good exercise which have many health benefits.

So we can conclude that muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.

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Answer:

introversion is the correct answer

Explanation:

God bless! Have a great day!

The total change in velocity of the satellite is 23 m/s

In Physics, Impulse is the product of mass and change in velocity

Given:

mass = 46 kg

Impulse = 1035 kg•m/s

change in velocity = ?

impulse = mass * velocity

change in velocity = Impulse / mass

change in velocity = 1035 / 45

change in velocity =  23 m/s

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Answer:

wood lighters gasoline hope it helps

Explanation:

Based on the data provided, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s.

The terminal velocity of a body is the velocity at which the body falls at constant velocity through a fluid.

For the falling raindrop, let positive direction be downwards and negative direction upwards,

The raindrop experiences a downward gravitational force mg, and an upward drag force -bv.

The total force at a time t is given as

a)

Terminal velocity is achieved then the total force is 0,

0 = mg - bv0

Therefore

b = mg/v0

Substitutingthe values:

b = (3 × 10^-5 × 9.8)/9

b = 3.27 × 10^-5 kg/s

b) Applying Newton's Second Law

F = ma

where

Therefore,

mg = mv/t t = v/g

however, t is at 63% velocity

thus:

t = 0.63v/g

t = 0.63 × 9 /9.8

t = 0.58 s

Therefore, the value of the constant b is 3.27 × 10^-5 kg/s and the time required to reach 63% of terminal velocity is 0.58 s

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The electric potential V(z) on the z-axis is :  V = [tex](\frac{Q}{a^2} ) [ (a^2 + z^2)^{\frac{1}{2} } -z[/tex]

The magnitude of the electric field on the z axis is : E = kб 2[tex]\pi[/tex]( 1 - [z / √(z² + a² ) ] )

Given data :

V(z) =2kQ / a²(v(a² + z²) ) -z  

Considering a disk with radius R

Charge = dq

Also the distance from the edge to the point on the z-axis = √ [R² + z²].

The surface charge density of the disk ( б ) = dq / dA

Small element charge dq =  б( 2πR ) dr

dV  [tex]\frac{k.dq}{\sqrt{R^2+z^2} } \\\\= \frac{k(\alpha (2\pi R)dR}{\sqrt{R^2+z^2} }[/tex]  ----- ( 1 )

Integrating equation ( 1 ) over for full radius of a

∫dv = [tex]\int\limits^a_o {\frac{k(\alpha (2\pi R)dR)}{\sqrt{R^2+z^2} } } \,[/tex]

 V = [tex]\pi k\alpha [ (a^2+z^2)^\frac{1}{2} -z ][/tex]

     = [tex]\pi k (\frac{Q}{\pi \alpha ^2})[(a^2 +z^2)^{\frac{1}{2} } -z ][/tex]

Therefore the electric potential V(z) = [tex](\frac{Q}{a^2} ) [ (a^2 + z^2)^{\frac{1}{2} } -z[/tex]

Also

The magnitude of the electric field on the z axis is : E = kб 2[tex]\pi[/tex]( 1 - [z / √(z² + a² ) ] )

Hence we can conclude that the answers to your question are as listed above.

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