please help quickly
The polygons are similar. x = ___ Write your answer as a decimal

The inverse of the function is {(5, 3), (8, 2), (5, 1), (3, 0)} and it is not a function

From the question, we have the following parameters that can be used in our computation:

((3,5), (2,8), (1.5), (0.3))

The above ordered pairs can be represented a

(x, y)

This means that the inverse function is

(y, x)

So, we have the following expression

(y, x) = {(5, 3), (8, 2), (5, 1), (3, 0)}

Also, the inverse is not a function

This is so because the x value 5 has different y values 3 and 1

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The value u > -16 that makes the inequality 5u > -80 is true.

In mathematics, "inequality" refers to a relationship between two expressions or values that are not equal to each other. To solve the inequality, you may multiply or divide each side by the same positive number, add the same amount to each side, take the same amount away from each side, and more. You must flip the inequality sign if you multiply or divide either side by a negative number.

Given:

We have the inequality,

5u > -80

To find the solution set of the inequality;

Divide by 5 to both sides,

5u/5 > -80/5

u > -16.

That means, the inequality is true for u > -16.

Therefore, the inequality is true for u > -16.

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In the quadrilateral, ∠GEF will be same as angle ∠EDF=42°°

A polygon with four sides, four angles, and four vertices is called a quadrilateral. The Latin words quadri, which means four, and latus, which means side, were combined to create the English word quadrilateral. A quadrilateral is shown in the above image as an example.

A parallelogram has two pairs of parallel sides, whereas a trapezoid only has one pair. Consequently, a parallelogram is a trapezoid.

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Answer:

EGF

Step-by-step explanation:

Got it right on plato.

Considering that the quadrilateral EFGH is similar to quadrilateral IJKL the side LI is calculated to be

The side LI is calculated using the concept of similar polygons. This concept allows for the sides to be proportionally equal to each other.

This implies that the factor used for any side will produce same result

let the factor be r and using side HG and JK to solve for the factor r

HG * r = JK

where

HG = 16

JK = 51

substituting the values and solving for r

HG * r = JK

16 * r = 51

r = 51/16

and HE * r = LI

where HE = 9.6

LI = 9.6 * 51/16

LI = 30.6

hence side LI = 30.6

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Answer:

55.2049%

Step-by-step explanation:

R², the coefficient of determination, is the proportion of the variation in the dependent variable that is predictable from the independent variable.

In this case, if we square our correlation coefficent r=0.743, we get R²=0.552049, which means that 55.2049% of the variation in the number of yearly boaters can be explained by differences in lake sizes

If the freight elevator lifts goods the same height in 2 minutes and 30 seconds, it will travel at a pace of 6.4 feet per second.

Speed is the pace at which an item moves along a route in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar number. The sign for speed is v (italic), whereas the symbol for velocity is v. (boldface). A bar is placed over the symbol to represent average values. Speed is defined as the rate at which distance changes over time. It has a distance by time dimension. Thus, the SI unit of speed is defined as a combination of the fundamental units of distance and time. As a result, the SI unit of speed is the metre per second.

Here,

Given that a passenger elevator in the sears tower in Chicago can lift people 960 feet in 1 minute and 30 seconds (1.5 minutes). This means that the lift is travelling with a speed of:

=960/1.5

=640 ft/min

If the elevator lifts cargo through the same height in 2 minutes and 30 seconds (2.5 minutes), then the speed is given by:

=640/2.5

=384 ft/min

=384/60

=6.4 ft/second

The freight elevator be traveling at the speed of 6.4 ft/second if it lifts cargo the same height but in 2 minutes and 30 seconds.

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the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

or in this case, hourly wage :)

to get the slope of any straight line, we simply need two points off of it, let's use those in the picture below.

[tex](\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{200}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{200}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{10}-\underset{x_1}{0}}} \implies \cfrac{ 200 }{ 10 } \implies \cfrac{20}{1}\cfrac{dollars}{hour}\qquad \textit{\$20 per hour}[/tex]

Answer:

x = 8

Step-by-step explanation:

572 - 500 = 72

72 / 8 = 9.

But in order to spend less than 572, he has to buy 8 cases. If he buys 9 cases he will be exactly 572.

Answer:

9 or fewer cases

Step-by-step explanation:

Solving a two step equation:

First, determine how much he has left to spend

572 - 500 = 72

He has 72 dollars left to spend on soda

Each case is 8 dollars.

Divide how much he has to spend by the cost of each case

72/8 = 9

He can buy up to 9 cases and stay under budget.

Area of the region enclosed by one loop of the curve is pi/288.

To find the area of the region enclosed by one loop of the curve, we can use the formula for the area of a polar region:

A = 1/2 * ∫(r^2)dθ

We can use this formula with the equation for r given:

A = 1/2 * ∫(sin^2(6θ))dθ

This integral can be simplified by noting that sin^2(x) = (1/2)(1 - cos(2x))

Thus,

A = 1/2 * ∫(1/2)(1 - cos(12θ))dθ

This integral can be solved by noting that the antiderivative of (1/2)(1 - cos(12θ)) is (1/24)(sin(12θ) + θ).

Therefore, the area enclosed by one loop of the curve is

A = 1/2 * ((1/24)(sin(12θ) + θ)) evaluated from 0 to pi/6

A = (1/48)(sin(2pi) + pi/6)

   = (1/48)(0 + pi/6)

   = pi/288

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The value for the blanks after calculating the as per the given data is found to be as 4 and 9 respectively.

On solving the question we will get the answer of the final blank as 0.

The question can be rephrased as ,

__x 9 - __ x 4 = ___ - ___ = ___.

Now if we will place 4 in first blank and 9 in second blank we will get the result as follows,

4 x 9 - 9 x 4 = 36 - 36 = 0

Therefore , we will get our desired answer.

A relationship between two quantities or, more broadly, two mathematical expressions that asserts that the quantities have the same value or that the expressions reflect the same mathematical object is referred to as equality.

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The monthly payment for this difference would be $1,361.21. An Adjustable Rate Mortgage (ARM) is a type of mortgage in which the interest rate on the loan changes over time.

An Adjustable Rate Mortgage (ARM) payment is based on various factors such as the loan amount, interest rate, and the terms of the ARM. The interest rate is usually tied to a specific financial index, such as the U.S.

Here is the calculation format for the difference in payments between year 2 and year 3 for Bart and April's mortgage:

Total amount to be paid for the mortgage: $315,000

Rate of interest: 5.85% (Depreciating rate)

Time = 2 years:

a. Remaining amount to be paid after 2 years:

Principal × (1 - Rate/100)^time

= $315,000 × (1 - 5.85/100)²

= $315,000 × (1 - 0.0585)²

= $279,223.01

Time = 3 years:

a. Remaining amount to be paid after 3 years:

Principal × (1 - Rate/100)^time

= $315,000 × (1 - 5.85/100)³

= $315,000 × (1 - 0.0585)³

= $262,888.46

Difference in payments from year 2 to year 3:

= Remaining amount after 2 years - Remaining amount after 3 years

= $279,223.01 - $262,888.46

= $16,334.55

The monthly payment for this difference would be $1,361.21, which is calculated by dividing the difference in payments by 12:

$16334.546/12 = $1361.21

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A 45°-45°-90° triangle looks like Right Angle Triangle.

A 45°−45°−90° triangle is a commonly encountered right triangle whose sides are in the proportion 1:1:√2.

45°−45°−90° triangle is a commonly encountered right triangle whose sides are in the proportion 1:1:√2 . The measures of the sides are x, x, and x√2.

In a 45°−45°−90° triangle, the length of the hypotenuse is √2 times the length of a leg, and the Opposite side to 45 = 1/√2 * Hypotenuse.

The 45-45-90 triangle has three unique properties that make it very special and unlike all the other triangles.

Hence, a 45°−45°−90° triangle is a commonly encountered right triangle whose sides are in the proportion 1:1:√2.

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Answer: 125

Step-by-step explanation:

The first term is 1³. The second term is 2³. The third term is 3³. And the Fourth term is 4³.

So the pattern is n term = n³

plug in 5

= 5³

= 125

The required point that satisfies each system of equation is (12, -1). Option B is correct.

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

To equations are given as,
y = -1/3x + 3 - - - - (1)
y = -3/4x + 8 -- - - - (2)

From equation 1 and 2
-1/3x + 3 = -3/4x + 8
3/4x - 1/3x = 8 - 3
9x - 4x / 12 = 5
5x = 60
x = 12

Now, to evaluate the y ordinate put the above x in equation 1
y = -1/3(12) + 3
y = -4 + 3
y = -1

Thus, the required point that satisfies each system of equation is (12, -1). Option B is correct.

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Answer:

f(x + 2) = - 3x - 1

Step-by-step explanation:

substitute x = x + 2 into f(x) , that is

f(x + 2)

= 5 - 3(x + 2)

= 5 - 3x - 6

= - 3x - 1

The number of hours that the team trains per week is 17 hours.

A fraction simply means a piece of a whole. In this situation, the number is represented as a quotient such that the numerator and denominator are split. In this situation, in a simple fraction, the numerator as well as the denominator are both integers.

Since the swim tea spends 1/2h in the gym followed by 1 1/4 in the pool. On Saturday there is no gym work but double the swim team time. The number of hours will be:

( 1 1/4 + 1/2 + 2 1/2) × 4

= 4.25 × 4

= 17 hours.

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The function graph is Linear Constant. Option C

We know that when we plot a graph, there would be the vertical and the horizontal axis. We can be able to deduce the nature of the graph when we look at how the graph is going.

In this case, we can see that the graph is flat. The flatness of the graph would show us that there is neither an increase nor a decrease in the function that we have in view. The increase or the decrease can be seen from the direction of the line that is drawn across the graph.

Hence, the fact that the line is flat on the graph shows that it is linear constant.

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The actual length of the car based on the model will be 350 inches.

Ratio in Mathematics simply demonstrates how many times one number can be able to fit into another number. It should be noted that ratios contrast two numbers by dividing them. In this case, A/B will be the formula if one is comparing one variable (A) to another variable (B).

Since the ratio of the model car was 2:35. If the model is 20 inches long, the actual length of the car will be:

= 20 ÷ 2/35

= 20 × 35/2

= 350 inches.

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Complete question

The ratio of the model car was 2:35. If the model is 20 inches long. then what would be the actual length of the car??

The value of x that will make aob a straight line equation is x = -6.

To make aob a straight line, we need to make the gradients of both lines equal.

The gradient of the first line is 3x20 = 60.

The gradient of the second line is 4x-36 = 4x-36.

To make the gradients equal, we need to solve the equation 4x - 36 = 60.

Subtracting 36 from both sides gives us: 4x = 96.

Dividing both sides by 4 gives us x = -6.

Therefore, the value of x that will make aob a straight line is x = -6

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Answer:

β, α, γ

Step-by-step explanation:

The figure only shows us the side lengths of the triangle, but is asking for the angles.

Thus, we have to use the angle relationships of a triangle to answer the question.

⭐What are the angle relationships of a triangle?

α° is opposite of the side length with 9 cm.

β° is opposite of the side length with 12 cm.

γ° is opposite of the side length with 5 cm.

∴ The angles from highest to the least are β, α, γ

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Answer:

Step-by-step explanation:

The answer should be BAY but if i check it don't work

The data which is given by the historian is used to find the population, variable, parameter, sample, data, and statistic. He estimated the mean number of children per household in New York City in 1900.

Population - all of the households in New York City in 1900.

Variable - a quantity equivalent to the number of children in a randomly selected household

Parameter -  the mean number of children per household in New York City in 1900

Sample - the 200 households selected by the historian

Data - the 200 records collected by the historian

Statistic -  the mean number of children per household in the historian's sample.

Complete question:

Suppose a historian wants to estimate the true mean number of children per household in New York City in 1900. The historian randomly selects 200 household census records from New York City. She records the number of children residing in each household. The historian then computes the mean number of children per household among these 200 households. Classify each description as one of a parameter, variable, population, sample, data, or statistic.

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The equation of a line is given by y = mx + b, where m is the slope and b is the y-intercept. Given that the slope is 3 and the y-intercept is 5, the equation of the line is y = 3x + 5.

The equation of a line is a mathematical expression of the form y = mx + b, where m is the slope and b is the y-intercept. This equation can be used to describe the relationship between the x-coordinate and y-coordinate of points on a line. In this specific equation, the slope is 3 and the y-intercept is 5, which means that the line passes through the point (0, 5) and has a slope of 3. Substituting 3 for m and 5 for b in the equation, we get y = 3x + 5, which is the equation of the line with a slope of 3 and a y-intercept of 5. We can use this equation to determine the y-coordinate of any given point on the line, provided we know the x-coordinate of the point. It is important to note that this equation is only applicable to straight lines, and not curves.

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Answer: Spent $120 originally, profited by $36

Step-by-step explanation:

The total cost Stefan earned from selling the helmet and the bicycle is $139 + $17 = $156.

130% can be rewritten as [tex]\frac{130}{100}[/tex] which is simplified to 1.3.

Set up and this equation to find 130% of this price.

[tex]1.3x = 156\\x = 120[/tex]

Stefan spent $120 on these items.

Subtract this value from the selling price and solve.

[tex]156-120 = 36[/tex]

Stefan made $36 from selling the helmet and bicycle.

Between the 100th and 400th kilometers, the average fuel consumption rate is 5/6 liters per kilometer.

A consequence of dividing the variation in a variable's function by the variation in the variable. For example The rate at which a distance changes in relation to time is known as velocity.

Given, Devin drove her truck. The fuel remaining in the truck's tank (in liters) as a function of distance (in kilometers) is graphed.

Since in the domain [100, 400] graph shows somewhat linear properties.

from the graph Fuel consumption at 100 = 375 liters

Fuel consumption at 400 = 125 liters

rate in a linear function between two points = (y₂ - y₁)/ (x₂ - x₁)

thus rate between [100, 400] = (375-125)/400-100

rate between [100, 400]  = 250/300

rate between [100, 400] = 5/6litere per kilometer

therefore, the average fuel consumption rate, between the 100th kilometer and 400th kilometer is 5/6 liters per kilometer.

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34.7 is the monthly phone use will Plan A cost no more than Plan B and 2.1 is the value of m in the inequality.

a relationship between two expressions or values that are not equal to each other is called 'inequality.

In Plan A, the customer pays a monthly fee of $20 and then an additional 7 cents per minute of use

20+7m

In Plan B, the customer pays a monthly fee of $26.30 and then an additional 4 cents per minute of use

26.3+4m

We need to find the amounts of monthly phone use will Plan A cost no more than Plan B

20+7m<26.3+4m

7m-4m<26.3-20

3m<6.3

m<2.1

Hence, 34.7 is the monthly phone use will Plan A cost no more than Plan B and 2.1 is the value of m in the inequality.

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The general solution is [tex]$$y=c_3 e^x+c_4 e^{-x}+\frac{1}{2} x \sinh x \text {. }$$[/tex]

Consider the following differential equation: y'' − y = cosh x

The given differential equation in the operator form will be: (D^2-1)y=coshx

The auxiliary equation of the corresponding homogeneous equation will be:

m^2-1 = 0

=>m^2=1

=>m=+1,-1

So, the complementary function will be [tex]y_c=c_1 e^x+c_2 e^{-x}.\alpha[/tex]

Now, let [tex]y_1=e^x, y_2=e^{-x}.[/tex]

Compute the Wronskian determinant:

[tex]$$\begin{aligned}W\left(y_1, y_2\right) & =\left|\begin{array}{ll}y_1 & y_2 \\y_1^{\prime} & y_2^{\prime}\end{array}\right| \\& =\left|\begin{array}{ll}e^x & e^{-x} \\e^x & -e^{-x}\end{array}\right| \\& =-e^x e^{-x}-e^x e^{-x} \\& =-2\end{aligned}$$[/tex]

Since the given differential equation is already in the form [tex]$y^{\prime \prime}+P(x) y^{\prime}+Q(x) y=f(x)$[/tex] (that is, the coefficient of y'' is 1 ),

So identify:

f(x)=cosh x

Then, calculate the values of u_1' and u_2', using formulas as follows:

[tex]$$\begin{aligned}u_1^{\prime} & =-\frac{y_2 f(x)}{W} & u_2^{\prime} & =\frac{y_1 f(x)}{W} \\& =-\frac{e^{-x} \cdot \cosh x}{-2} & & =\frac{e^x \cdot \cosh x}{-2} \\& =\frac{e^{-x} \cdot\left(\frac{e^x+e^{-x}}{2}\right)}{2} & \text { and } & =-\frac{e^x \cdot\left(\frac{e^x+e^{-x}}{2}\right)}{2} \\& =\frac{1}{4}\left(1+e^{-2 x}\right) & & =-\frac{1}{4}\left(e^{2 x}+1\right)\end{aligned}$$[/tex]

Integrate on both sides of u_1' and u_2' with respect to ' x', to get:

[tex]$$u_1=\frac{x}{4}-\frac{e^{-2 x}}{8} \text { and } u_2=-\frac{x}{4}-\frac{e^{2 x}}{8} .$$[/tex]

So, the particular solution is,

[tex]$$\begin{aligned}y_p & =u_1 y_1+u_2 y_2 \\& =\left(\frac{x}{4}-\frac{e^{-2 x}}{8}\right) e^x+\left(-\frac{x}{4}-\frac{e^{2 x}}{8}\right) e^{-x} \\& =\frac{1}{4} x\left(e^x-e^{-x}\right)-\frac{1}{8}\left(e^{-x}+e^x\right) \\& =\frac{1}{2} x \sinh x-\frac{1}{8}\left(e^{-x}+e^x\right)\end{aligned}$$[/tex]

Thus, the general solution of the given differential equation is,

[tex]$$\begin{aligned}y & =y_c+y_p \\& =c_1 e^x+c_2 e^{-x}+\frac{1}{2} x \sinh x-\frac{1}{8} e^{-x}-\frac{1}{8} e^x \\& =\left(c_1-\frac{1}{8}\right) e^x+\left(c_2-\frac{1}{8}\right) e^{-x}+\frac{1}{2} x \sinh x \\& =c_3 e^x+c_4 e^{-x}+\frac{1}{2} x \sinh x\end{aligned}$$[/tex]

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Answer:

Step-by-step explanation:

The answer I got was y= -3/2x+3

Answer:

[tex]b = 90[/tex]

[tex]d = 100[/tex]

[tex]c = 80[/tex]

Step-by-step explanation:

The problem is asking for the values of the variables [tex]b[/tex], [tex]c[/tex], and [tex]d[/tex] in the given parallelogram with angles [tex]d\textdegree[/tex], [tex]c\textdegree[/tex], [tex](b-10)\textdegree[/tex], and [tex](b+10)\textdegree[/tex].

To solve for these variables, we can construct three equations using the knowledge that any two adjacent angles of a parallelogram are supplementary (their measures add to 180º).

The first equation shows that the top two angles are supplementary:

[tex]d\textdegree + c\textdegree = 180\textdegree[/tex]

The second equation shows that the bottom two angles are supplementary:

[tex](b-10)\textdegree + (b+10)\textdegree = 180\textdegree[/tex]

The third equations shows that the left two angles are supplementary:

[tex]d\textdegree + (b-10)\textdegree = 180\textdegree[/tex]

First, we can solve for [tex]b[/tex] in the second equation using simple algebraic manipulation.

[tex](b-10)\textdegree + (b+10)\textdegree = 180\textdegree[/tex]

[tex](b+b)\textdegree + (10-10)\textdegree = 180\textdegree[/tex]

[tex]2b\textdegree = 180\textdegree[/tex]

[tex]b\textdegree = 90\textdegree[/tex]

[tex]b = 90[/tex]

Using this [tex]b[/tex]-value, we can solve for [tex]d[/tex] by rewriting the third equation, plugging [tex]90[/tex] in for [tex]b[/tex]:

[tex]d\textdegree + (b-10)\textdegree = 180\textdegree[/tex]

[tex]d\textdegree + (90-10)\textdegree = 180\textdegree[/tex]

[tex]d\textdegree + 80\textdegree = 180\textdegree[/tex]

[tex]d\textdegree = 100\textdegree[/tex]

[tex]d = 100[/tex]

Finally, we can solve for [tex]c[/tex] in the first equation by plugging [tex]100[/tex] in for [tex]d[/tex]:

[tex]d\textdegree + c\textdegree = 180\textdegree[/tex]

[tex]100\textdegree + c\textdegree = 180\textdegree[/tex]

[tex]c\textdegree = 80\textdegree[/tex]

[tex]c = 80[/tex]

Answer:

#1 multiply

#2 divide

#3 subtract

#4 subtract

#5 divide