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Answer:

I hope this will help you

Explanation:

The air that is inside a ship is much less dense than water. That's what keeps it floating! The average density of the total volume of the ship and everything inside of it (including the air) must be less than the same volume of water.

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Answer:

60 Liters

Explanation:

The equation for this reaction is given as;

N2 + 3H2 → 2NH3  

From the reaction;

3 mol of H2 produces 2 mol of NH3

At STP;

1 mol = 22.4 L

This means

67.2 L ( 3 * 22.4) of H2 produces 44.8 L ( 2 * 22.4) of NH3

How many L of H2 would produce 40 L of NH3

67.2 = 44.8

x = 40

Solving for x;

x = 40 * 67.2 / 44.8

x = 60 L

Answer:

The formation of a gas is a clue to chemical changes. The bubbles of gas that you observed form when an antacid is dropped into water is an example of change. Another clue that a chemical change has occurred is the formation of a solid.

Explanation:

Explanation:

It to be fossilized, the remains usually to be covered by sediment soon after death. sediment can include the sandy seafloor,lava,and even sticky tar. Over time, minerals in the sediment seep in to remains. The remains become fossilized.

Answer:

Silicon tetrachloride

Explanation:

In science, literature, and everything, equilibrium has the same meaning. The meaning simply put, is balance. If you wanted a sentence example, it could be something like:

'He sat down to try and recover his equilibrium.'

Or

'They can't maintain enough equilibrium to ride a bike.'

I hope you understand the meaning now?

Answer:

Turgor pressure in plants. Turgor pressure within cells is regulated by osmosis and this also causes the cell wall to expand during growth.

Explanation:

I hope that helps

Answer:

2. for number two I asks what the experiment is showing, I need the picture of the experiment.

3.  As temperature increases, the particles will gain kinetic energy causing it to move more rapidly and randomly. However, this causes the gas to expand as the particles will have more energy to roam freely. as temperature increases, Volume increases.

4.  Im not sure D:

Answer:

0.017 moles of ammonia remains after the reaction is stopped.

Explanation:

The reaction is:

4NH₃  +  5O₂  →  4NO  +  6H₂O

The first step is to convert the mass to moles, of each reactant:

2 g .  1mol/ 17g = 0.117 moles of NH₃

4 g . 1mol /32g = 0.125 moles of O₂

Ammonia, states the question, is the excess reactant so we can confirm it,

5 moles of oxygen need 4 moles of ammonia to react (by stoichiometry)

Then, 0.125 moles of oxygen may react to (0.125 . 4) / 5 = 0.1 moles

As we have 0.117 moles of ammonia and we need 0.1 moles.

(0.117 - 0.1) = 0.017 moles remains after the reaction is completed.

If we convert the moles to mass we have:

0.017 mol . 17 g /1mol = 0.289 g

Answer:

True

Explanation:

The reason why is because frost is a result of a chemical reaction

the empirical chemical formula of X is CH4

Explanation:Step 1: Imagine you have a sample of compound weighing exactly . Multiply the mass of this sample by the mass percents to find the mass of each element in the sample

Step 2: Divide the mass of each element by the element's molar mass to find the moles of each element in the sample. Remember to round your answers to the correct number of significant digits.  

Step 3: Divide the moles of each element by the the smallest number of moles of any element to find the mole ratio of elements in the sample.  

Step 4: Multiply the mole ratio by the smallest whole number that changes it into a whole number ratio to find the atom ratio of elements in the sample.

Note that the result of each multiplication must equal a whole number only within measurement uncertainty.  

The measurement uncertainty in this calculation comes from the measurement uncertainty of the mass percents given in the question. The mass percents each have significant digits. That means each mass percent has some measurement uncertainty in the third significant digit, and only the first two significant digits can be considered completely reliable.  

In Step 1 you multiplied each mass percent by something with zero uncertainty (the exactly you assumed your sample weighed), in Step 2 you divided by a measurement with more than significant digits (the molar mass of the elements), and in Step 3 you divided by a measurement with the same number of significant digits (the least number of moles of any element in the compound). None of these steps added to the measurement uncertainty of your calculation.  

Therefore, the measurement uncertainty in the final result of all your calculations is determined by the measurement uncertainty in the original mass percents and will be in the third significant digit. That means the result of each of the final multiplication steps must equal a whole number only to within the first two significant digits.  

The whole numbers in the last column of the table are and .  

Explanation:

➢number of moles. Moles and Chemical Reactions. Chapter 4. 3 H2. + N2. →. 2 NH3 ... How many grams of NH3 would form if 2.11 moles of N2 reacted with ...

Answer:

143.9946 g

Explanation:

Answer: because its more scientific and "formal"? I guess.

Explanation:

Answer:

a)82.5 g

Explanation:

To solve this problem we will use Avogadro's number, which states the number of formula units per mole.

Then we convert 1.41 moles of NaCl to grams, using its molar mass:

The closest answer is option a).

Answer:

15.69 dozen

Explanation:

Mass of penny = 5 g

Dozens of penny =..?

Next, we shall convert 5 g to gross. This can be obtained as follow:

3824 g = 1000 gross

Therefore,

5 g = 5 g × 1000 gross / 3824 g

5 g = 1.3075 gross

Thus, 5 g is equivalent to 1.3075 gross.

Finally, we convert 1.3075 gross to dozen. This can be obtained as follow:

1 gross = 12 dozen

Therefore,

1.3075 gross = 1.3075 gross × 12 dozen / 1 gross

1.3075 gross = 15.69 dozen

Thus, 5 g of penny is equivalent to 15.69 dozen

Answer:chemical markers

Explanation:

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Answer:

hydrochloric acid

Explanation:

Answer:

For example, when water solutions of calcium nitrate and sodium carbonate are mixed, calcium carbonate precipitates from the solution while the other product, sodium nitrate, remains dissolved. It is a precipitate.

Explanation:

The concept of significant figures are mainly used by scientist and engineer to know the significance of digits in a measurement. Therefore, 3,545,530 upto 3 significant figures is 3.54 x 10³.

Significant figures are the figures that indicate the degree of accuracy of a value. It tells about the precision of a value. It gives an idea about the digits that are necessary to indicate the experimental value.

Rules for counting significant figures are:

Number between 1 to 9 is always significant

Zeroes after a number has got no significance

Zeroes before a number has got no significance

Zeroes between number has got significance

3,545,530 upto 3 significant figures is 3.54 x 10³.

Therefore, 3,545,530 upto 3 significant figures is 3.54 x 10³.

To learn more about Significant figures, here:

https://brainly.com/question/12656148?

#SPJ1

Answer:

85.6

Explanation:

(72 x 85) + (28 x 87)

-----------------------------

        100

= 85.56

= 85.6 (3 s.f.)

Answer  :32,5 g NaCl equal 0,556 moles.

Explanation:

Answer:

true

Explanation:

Answer:

Limiting reactant: O2

grams NO2 produced = 230.276 g NO2

grams of NO unused = 26.67 gNO

Explanation:

2NO + O2 --> 2NO2

Step 1: Determine the molar ratio NO:O2

molar ratio NO:O2 = 5.895: 2.503 = 2.35

stoichiometric molar ratio NO:O2 = 2:1

So, O2 is the limiting reactant.

Step2: Determine the grams of NO2:

?g NO2 = moles O2 x (2moles NO2/1 mol O2) x (MM NO2/ 1 mol NO2) = 2.503 x 2 x 46 = 230.276 g NO2

Step 3: Determine the amount of excess reagent unreacted

moles excess NO reacted = moles O2 x (2 moles NO/1 mol O2) = 2.503 x 2 = 5.006 moles NO reacted

moles NO unreacted = total moles NO - moles NO reacted = 5.895-5.006 =0.889 moles NO unreacted

mass NO unreacted = moles NO unreacted x MM NO = 0.889 x 30 =26.67 g NO unreacted

Answer:

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Explanation:

Answer:

sorry if this is wrong but B

Explanation:

ITS C

Oxygen, APT, and Glucose