Question 24 Marks: 1 Resource recovery and reduction of solid wastes should startChoose one answer. a. at the point of generation b. at the sanitary landfill c. in the home d. at the transfer station

Answers

Answer 1

Resource recovery and reduction of solid wastes should start at the point of generation. So the correct option is a.

Resource recovery and reduction of solid wastes involve methods and practices aimed at minimizing the amount of waste generated, as well as recovering valuable resources from waste materials. The most effective and sustainable approach is to start the process of resource recovery and waste reduction at the point of generation, which is where waste is initially produced. This can include practices such as reducing waste generation through source reduction and waste prevention measures, reusing materials, recycling, and composting. By implementing waste reduction and resource recovery practices at the point of generation, such as in homes, businesses, and industries, we can minimize the environmental impact of waste disposal, conserve resources, and promote sustainability.

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Related Questions

compared with the frequency of illuminating light on a sheet of transparent plastic, the frequency of light that is transmitted

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The frequency of light that is transmitted through a sheet of transparent plastic is the same as the frequency of illuminating light. Transparent materials, like plastic, do not absorb light and therefore the frequency of light that passes through them remains unchanged.

What is transparent?

Transparency is a concept or value of being open and honest with others. It is the practice of being open, honest, and accountable with oneself and with others. Transparency involves communication between individuals and organizations in a way that is easily understood, accessible, and open to public scrutiny. Transparency is a key component of good governance, as it allows for public scrutiny and accountability, and encourages public participation in decision-making. Transparency also fosters trust in the government and promotes economic growth and development.

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the maximum output of the chlorinator at a well is 100 pounds per day. if this well requires a dosage of 3.75 mg/L. what is the maximum flow rate allowed for this well, expressed in MGD

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The maximum flow rate allowed for the well, expressed in MGD, is 3.01.

To calculate the maximum flow rate allowed for the well, we need to use the following formula:

Maximum Flow Rate = (Maximum Chlorine Output in Pounds per Day) / (Dosage in mg/L x 8.34)

Here, the maximum chlorine output is given as 100 pounds per day, and the dosage required is 3.75 mg/L. Plugging these values into the formula, we get:

Maximum Flow Rate = (100 pounds/day) / (3.75 mg/L x 8.34)

Maximum Flow Rate = 3.01 MGD (rounded to two decimal places)

Therefore, the maximum flow rate allowed for the well, expressed in MGD, is 3.01.

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Given that the planet orbiting the nearby star 51 Pegasi is about 20X larger than the Earth, but 400X more massive, on that world you would weigh: A. twice as much as you do here. B. 20X more that you do here. C. half as much as you do here. D. 400X more than you do here. E. the same as you do here.

Answers

The weight of me will be the same as I do here. So the correct option is E.

Your weight on a planet is determined by the gravitational force exerted on you, which depends on the planet's mass and its radius. In this case, the planet orbiting 51 Pegasi is 20 times larger (radius) and 400 times more massive than Earth. To calculate your weight on this planet, we'll use the formula:

Weight_on_Planet = (Weight_on_Earth × Mass_of_Planet) / (Radius_of_Planet^2)
Let's substitute the given values (20 times larger and 400 times more massive):
Weight_on_Planet = (Weight_on_Earth × 400) / ([tex]20^{2}[/tex])
Weight_on_Planet = (Weight_on_Earth × 400) / 400
Weight_on_Planet = Weight_on_Earth

So, on the planet orbiting 51 Pegasi, you would weigh the same as you do on Earth. Therefore, the answer is E. the same as you do here.

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A ball rolls 10.0 m [S] ina time of 60.0s, it hits a wall, and rolls back a distance of 15.0 m [N] in a time of 10.00s. Determine: ( /4)
The distance travelled by the ball.



The displacement of the ball.



The average speed of the ball.



The average velocity of the ball.

Answers

The distance travelled by the ball is 25 m.

The displacement of the ball is 5 m.

The average speed of the ball is 0.357 m/s.

The average velocity of the ball is 0.071 m/s.

What is the distance travelled by the ball?

The distance travelled by the ball is calculated as follows;

distance = 10 m + 15 m = 25 m

The displacement of the ball = Δx

where;

Δx is change in position

displacement = 15 m - 10 m = 5 m

The average speed of the ball is calculated as;

average speed = total distance / total time

average speed = (25 m ) / (60 s + 10 s ) = 0.357 m/s

The average velocity of the ball is calculated as;

average velocity = total displacement / total time

average velocity = (5 m ) / (60 s + 10 s ) = 0.071 m/s

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What is the frequency of light in a vacuum that has a wavelength of 70600 m?
(Choose from the following units: m, hz, m/s, s, degrees, dB)
Your Answer:

Answers

The frequency of light in a vacuum that has a wavelength of 70600 m is approximately 4.25 × 10⁻⁶ Hz.

The relationship between the frequency (f), wavelength (λ), and the speed of light (c) is given by the equation:

c = fλ

where c is approximately equal to 3 × 10⁸ meters per second in a vacuum.

Rearranging this equation, we can solve for the frequency:

f = c / λ

Plugging in the given wavelength of 70600 m, we get:

f = (3 × 10⁸ m/s) / (70600 m) ≈ 4.25 × 10⁻⁶ Hz

Therefore, the frequency of light in a vacuum that has a wavelength of 70600 m is approximately 4.25 × 10⁻⁶ Hz.

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the melting point and boiling point of steel pot

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Answer:

Explanation:

The melting point and boiling point of a steel pot can vary depending on the specific type of steel and its composition. However, the melting point of most common types of steel used in pots and pans ranges from 1370°C to 1530°C (2500°F to 2790°F).

It is important to note that the boiling point of steel is much higher than its melting point, and it is not practical to heat a steel pot to its boiling point as it would require extremely high temperatures and could result in damage or deformation of the pot.

4. A 50 mH inductor is placed in parallel with a 100.0Ω resistor. Ignoring any resistance in the inductor itself, what is the time constant in seconds of this RL circuit

Answers

5.0 ms (milliseconds) is the time constant in seconds of this RL circuit.

The time constant of an RL circuit is given by the product of the resistance and the inductance, or τ = L/R. In this case, the inductance is 50 mH (millihenries), or 0.050 H, and the resistance is 100.0 Ω (ohms).

Plugging these values into the equation, we get:

[tex]τ = L/R = (0.050 H)/(100.0 Ω) = 0.0005 s = 0.5 ms[/tex]

Therefore, the time constant of the RL circuit is 0.5 ms (milliseconds), or 5.0 × 10^-4 seconds. This represents the time it takes for the current in the circuit to reach approximately 63% of its maximum value, or for the voltage across the inductor to reach approximately 63% of its maximum value when a DC voltage is initially applied to the circuit. The time constant is an important parameter in analyzing the transient behavior of an RL circuit.

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If you go skiing on a 1200 m vertical mountain and your 2 MT car travels 50 km/hr up an average slope of 8 degrees. Find the horsepower output of your car.

Answers

The average acceleration during skiing is 0.4 [tex]m/s^2.[/tex]

To calculate the average acceleration, we can use the following equation:

average acceleration = (final velocity - initial velocity) / time

We can assume that the initial velocity is 0 m/s since we start from rest. We need to find the time it takes to travel the horizontal distance of 500 m.

To do this, we can use the following equation:

distance = average velocity x time

We can calculate the average velocity as:

[tex]average velocity = (0 m/s + 20 m/s) / 2 \\= 10 m/s[/tex]

Substituting this and the distance of 500 m into the equation above, we get:

[tex]500 m = 10 m/s * time[/tex]

Solving for time, we get:

[tex]time = 500 m / 10 m/s \\= 50 s[/tex]

Now we can calculate the average acceleration as:

average acceleration = (final velocity - initial velocity) / time

[tex]= (20 m/s - 0 m/s) / 50 s \\= 0.4 m/s^2[/tex]

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--The complete Question is, If you go skiing on a 1200 m vertical mountain and reach a final velocity of 20 m/s after traveling a horizontal distance of 500 m, what is your average acceleration? --

5. Find the resonance frequency Æ0 in Hz of a series LRC circuit with L=0.030H, C=1.0*10^-9, and R=1000 Ω.

Answers

The resonance frequency Æ0 is 318309.89 Hz. The resonance frequency of a series LRC circuit is given by the formula [tex]Æ0 = 1/(2π√(LC))[/tex].

Substituting the given values, we get [tex]Æ0 = 1/(2π√(0.030H x 1.0*10^-9F))[/tex] = [tex]318309.89 Hz[/tex]. This means that when an AC voltage is applied to the circuit at this frequency, the circuit will resonate and the current will be maximum. At frequencies higher or lower than the resonance frequency, the current will decrease. The resistor R in the circuit causes the current to decrease with time and thus limits the amplitude of the resonant current.

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Identifying Video Ports and Connectors
On the Ports and Connectors tab, select the connector names and video ports from the lists.

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By selecting the appropriate connector names and video ports from the lists, you'll be able to identify and understand the different types of video ports and connectors used in various devices.



Step 1: Open the Ports and Connectors tab, where you will find lists of connector names and video ports.

Step 2: Carefully review the lists and identify the most common video ports and connectors, such as HDMI, VGA, DVI, and DisplayPort.

Step 3: Select the appropriate connector names and video ports from the lists.

For example, some selections you might make include:
- HDMI: This connector is commonly used for high-definition video and audio, and can be found on many devices such as computers, TVs, and gaming consoles.
- VGA: This connector is an older analog video standard, commonly used for connecting monitors to computers. It is gradually being replaced by digital interfaces like HDMI and DisplayPort.
- DVI: This connector is used for digital video connections between computers and monitors. There are different types of DVI, such as DVI-A, DVI-D, and DVI-I.
- DisplayPort: This connector is a newer digital video and audio interface, used for connecting computers, monitors, and other devices. It supports high-resolution displays and multiple display setups.

By selecting the appropriate connector names and video ports from the lists, you'll be able to identify and understand the different types of video ports and connectors used in various devices.

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42. A car is moving along a horizontal road at a constant velocity that is directed 45° south of east. What is the direction of the angular velocity of the wheels of the car?
A) 45° south of west
B) 45° north of west
C) 45° south of east
D) 45° north of east
E) due east

Answers

The direction of the angular velocity of the wheels of the car is the same as the direction of the velocity of the car, which is 45° south of east. Therefore, the answer is C) 45° south of east.

The direction of the angular velocity of the wheels of the car is perpendicular to the plane of rotation. In this case, since the car is moving along a horizontal road, the wheels are rotating in a horizontal plane. Therefore, the angular velocity will have a direction perpendicular to this horizontal plane, which is vertically upwards or downwards. However, the given options do not include vertical directions, so we can assume that the question intends to ask for the direction of the linear velocity of a point on the rim of the wheel (the tangential velocity), which is parallel to the horizontal plane.

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Question 50 Marks: 1 The amount of heat required to lower one pound of a product one degree Fahrenheit isChoose one answer. a. exothermal extraction b. the specific heat c. the coolant factor d. important to know

Answers

The correct answer is Specific heat.

The amount of energy required to raise the temperature of one pound of water by one degree Fahrenheit at standard atmospheric pressure is called specific heat in BTU (British Thermal Unit) which is a unit of measurement for energy used as per the British system.

BTU is used for measuring the heating or cooling capacity of an appliance as per the FPS system. For example, the BTU rating of a furnace or air conditioner indicates how much heat or cooling it can produce in a given period of time.

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The most famous prehistoric astronomical observatory is:

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The most famous prehistoric astronomical observatory is likely Stonehenge in Wiltshire, England. Located in Wiltshire, England, Stonehenge is an iconic prehistoric monument that served as an astronomical observatory, allowing ancient people to track the movements of the sun, moon, and stars.

This ancient site, constructed over 4,000 years ago, features a circle of standing stones that align with astronomical events such as the solstices and equinoxes. Its purpose and exact use as an observatory is still a topic of debate among historians and archaeologists. Scientists can determine whether or whether the cosmos is expanding, contracting, or remaining static by examining extremely far-off objects. Redshift is the term used to describe this idea.

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which one of the statements below is correct? multiple choice an isentropic process is adiabatic reversible a carnot cycle has two isentropic processes and two isobaric reversible processes. a carnot cycle is not necessarily a reversible cycle. processes in a closed system that are in compliance with the second law of thermodynamics require that the change in entropy be equal or greater than zero. the entropy change for an isobaric process of air in a closed system at 800 kpa when modeled as ideal gas can be directly determined using table a-17 of your textbook.

Answers

The correct statement is: a carnot cycle has two isentropic processes and two isobaric reversible processes.

Any process that does not affect the system's entropy is called isentropic. It is reversible because it is a reversible of the cosmos. Real processes are irreversible because trying to turn them around would result in the cosmos becoming less entropic, which is not feasible.

There are 4 stages in the Carnot cycle:

-Gas expansion that is isothermal. It uses heat from a hot source in this procedure. It is not isentropic, but it is reversible.

– Diabatic growth. This one is isentropic, meaning that the entropy of the gas doesn't change over time and that it doesn't interact with its environment. The mechanism pulls on the gas to cause it to expand rather than the gas expanding on its own. The gas becomes cooler.

compression that is isothermal. adiabatic but not reversible. The gas's volume is decreased as a result of heat exchange with the cold source.

Diabatic compression. isentropic and adiabatic. The gas heats up as a result of the machine's compression of it.

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the energy requirements of waters latent heat of fusion are the same as waters latent heat of vaporization? true or false

Answers

Answer: The energy requirements of water's latent heat of fusion are the same as water's latent heat of vaporization.

Explanation:

False.

The energy requirements of water's latent heat of fusion and latent heat of vaporization are not the same.

Water's latent heat of fusion is the amount of energy required to change a unit mass of water from a solid (ice) to a liquid (water) at constant temperature and pressure.

The value of water's latent heat of fusion is approximately 334 J/g.

Water's latent heat of vaporization, on the other hand, is the amount of energy required to change a unit mass of water from a liquid state to a gaseous state (water vapor) at constant temperature and pressure.

The value of water's latent heat of vaporization is much higher than its latent heat of fusion, approximately 2260 J/g.

So, while both processes involve a change in the state of water and require energy, the energy requirements for the latent heat of vaporization are much higher than the energy requirements for the latent heat of fusion.

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A 110 kg football player runs at 8 m/s and plows into an 80 kg referee that is standing still on the football field. The referee moves forward at 5 m/s.

a. What is the momentum of the football player before the collision?

b. What is the momentum of the referee before the collision?

c. What is the total momentum before the collision? (Hint: add a and b)

d. What is the momentum of the referee after the collision?

e. What must be the momentum of the football player after the collision?

f. Find the football players speed after the collision.

Answers

Answer:

See below

Explanation:

(a) Momentum can be solved with the formula: p = mv, where m and v are mass and velocity, respectively. So, p = (110kg) * (8m/s) = 880 kg* m/s

(b) Since v = 0 m/s, p = 0 kg * m/s

(c) The total momentum is 880 + 0 = 880 kg * m/s

(d) pi = pf

880 = 190 *vf -----> vf = 4.631 m/s

p = mv = (80kg) * (4.631 m/s) = 370.53 kg * m/s

(e) p = mv = (110kg) * (4.631 m/s) = 509.47 kg * m/a

(e) 4.631 m/s (as solved in part (d) )

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