Question Two
Gerald is opening a juice stand. He has up to $450.00 to spend on fruits and vegetables. The graph shows the amount that he can
spend on fruits and vegetables
Cost of Veg
500
450
400
350
300
250
200
150
100
50
0
Cost of Fruit
50 100 150 200 250 300 350 400 450 500
Which list contains only ordered pairs that will fit Gerald's budget?
O
C

Step-by-step explanation:

I think you have forgotten to attach the question.

Anyways....

In order to find the area of a circle use the formula:

π[tex]r^{2}[/tex]   Where r is the radius

For example the radius is 3cm. The area of the circle will be:

π × [tex]3^{2}[/tex]

Since you have taken pi as 3.142...

3.142 × [tex]3^{2}[/tex]

3.142  × 9

= 28.278

In order to find the answer to 1 decimal place, check the number next to the number right after the decimal. Is it a number greater than or equal to 5? then add +1 to the number.

= 28.3 [tex]cm^{2}[/tex]

Answer:

A (3 Oranges For $1.02)

Step-by-step explanation:

3 Oranges for $1.02 is $0.34 for each Orange

4 Oranges For $1.52 is $0.38 for each Orange

6 Oranges for $2.46 is $0.41 for each Orange

5 Oranges for $1.75 is $0.35 for each Orange

Which Makes The First One The Cheapest Out Of All

Answer:

s< -7/11

Step-by-step explanation:

Answer:

We are 95 percent confident that the mean word length for all papers submitted by students in humanities programs is between 20,995 words and 22,905 words

Step-by-step explanation:

The confidence interval is used to predict the mean for the entire humanities program, not just the sample.

Answer:

2x(2a + b)

Step-by-step explanation:

4ax+ 2bx

= 2x (2a + b)

Answer:

113.04 feet²

Step-by-step explanation:

Use the circle area formula, A = [tex]\pi[/tex]r²

Sine the diameter is 12 feet, the radius is 6 feet

Plug in 6 as r into the formula, and 3.14 as pi, then solve:

A = [tex]\pi[/tex]r²

A = (3.14)(6²)

A = (3.14)(36)

A = 113.04

So, the area of the circle is approximately 113.04 feet²

Answer:

113.04 feet²

Step-by-step explanation:

Hope this helps

Answer:

1. y = 32

2. x = 6

3. -33 = n

4. a = -15.6

Step-by-step explanation:

1.

y-23=55

 +23  +23          (23 cancels)

y = 32

2.

x - 14 = -8

 +14      +14           (-14 cancels)

   x = 6

3.

-15 = n + 18

    -18       -18          (18 cancels)

    -33 = n

4.

18.3 + a = 2.7

-18.3        -18.3        (18.3 cancels)

         a = -15.6

Answer:

1:2

Step-by-step explanation:

Answer:

x>16/5 or c<-1/12

Answer: x≥  

x≥16/5 or x≤-3/4

Step-by-step explanation: I think this is the answer but i´m not completely sure of it.

Answer:

0.82 = 82/100

simplified= 41/50

Step-by-step explanation:

Answer:

.8

Step-by-step explanation:

you can round, and since two is a number lower than five, the number stays the same so...

.8

Answer:

Step-by-step explanation:

21

Answer:

The second box is 1.125 pounds

Step-by-step explanation:

This is found by multiplying 1.5 by .75

Answer:

-2x-6

Step-by-step explanation:

Distribute -2x -2(3) = -2x-6

Answer:

Step-by-step explanation:

[tex] \frac{8}{32} = \frac{4}{16} = \frac{2}{8} = \frac{1}{4} [/tex]

[tex] \frac{27}{54} = \frac{9 }{18} = \frac{3}{6} = \frac{1}{2} [/tex]

[tex] \frac{36}{24} = \frac{18}{12} = \frac{9}{6} = \frac{3}{2} [/tex]

[tex] \frac{30}{60} = \frac{15}{30} = \frac{5}{10} = \frac{1}{2} [/tex]

Answer with explanation:

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. = 14

Median or second quartile i.e. = 18

Third quartile or upper quartile i.e. =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. = 26

Median or second quartile i.e. = 30

Third quartile or upper quartile i.e. = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

   The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.

   And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e.

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

Hence, the number is : 1.5

Answer:

ive seen this before

Step-by-step explanation:

Answer:

i don't know

Step-by-step explanation:

Answer:

14r+11

Step-by-step explanation:

3+5r+9r+8

=11+14r

Answer:

Let x = Kilometers  by bus  

then x + (x + 350) = 1100

2x = 750

x = 375 by bus

x - 350 + x = 1100

2x = 1450

x = 725 by train

i hope this helps a little bit

Answer:

for 3. the answer is 9

for 4. the answer is 12

Step-by-step explanation:

hope this helped!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

B

Step-by-step explanation:

5/1 is not equal to 6/2 or 7/3 or 8/4

Answer:

The answer would be B instead of D

Answer:

5.1

Step-by-step explanation:

hope it helps thank you

Answer:

x=25.45

Step-by-step explanation:

Step-by-step explanation:

3).20⁰

4).60⁰

180-70+70_180-140__20

Answer:

B

Step-by-step explanation:

Answer:

The possible coordinates of point A are (-8,-4) or (-8,6)

Step-by-step explanation:

The distance between two points is given by the formula

[tex]d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }[/tex]

For point A [tex](x_{1} , y_{1})[/tex]; [tex]x_{1}= -8[/tex] and [tex]y_{1}[/tex] is unknown

For point B [tex](x_{2} , y_{2})[/tex]; (4,1) i.e [tex]x_{2}=4[/tex] and [tex]y_{2}=1[/tex]

and d = 13

Putting the values into the equation,

[tex]13= \sqrt{[(4-(-8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{[(4+8)]^{2} + (1-y_{1})^{2} }\\13= \sqrt{12^{2} + (1-y_{1})^{2} }\\13^{2} = 12^{2} + (1-y_{1})^{2} \\169 = 144 +(1-y_{1})^{2}\\169-144 = (1-y_{1})^{2}\\25 = 1 -2y_{1} +y_{1}^{2} \\y_{1}^{2} -2y_{1}+1-25 =0\\y_{1}^{2} -2y_{1}-24 =0\\y_{1}^{2} -6y_{1} + 4y_{1} -24 =0 \\y_{1}(y_{1}-6) +4(y_{1} -6) = 0\\(y_{1}+4)(y_{1}-6) =0\\(y_{1}+4)=0 or (y_{1}-6) =0[/tex]

[tex]y_{1}+4= 0[/tex] or [tex]y_{1}-6 =0[/tex]

[tex]y_{1} =-4[/tex] or [tex]y_{1} = 6[/tex]

Hence, the possible coordinates of point A are (-8,-4) or (-8,6)

Answer:

SO THE EQUATION IS

2 + 2X = 11