Simplify:
Q1) 4k – 8p + 4k - 5p

No photo attached, but no need.

We're given that f(0) = 1 and f(2) = 5, and that

[tex]\displaystyle \int_0^2 f(x) \, dx = 7[/tex]

Integrate x f'(x) by parts, with

[tex]u = x \implies du = dx[/tex]

[tex]dv = f'(x) \, dx \implies v = f(x)[/tex]

Then

[tex]\displaystyle \int_0^2 x f'(x) \, dx = uv\bigg|_{x=0}^{x=2} - \int_0^2 v \, du \\\\ = x f(x) \bigg|_{x=0}^{x=2} - \int_0^2 f(x) \, dx[/tex]

Now just plug in everything you know:

[tex]\displaystyle \int_0^2 x f'(x) \, dx = 2f(2) - 0f(0) - \int_0^2 f(x) \, dx = 10 - 0 - 7 = \boxed{3}[/tex]

The standard form of the given equation  [tex]x^2+y^2-18x+8y+5=0[/tex] will be given as  [tex](x-9^2)+(y+4)^2=(2\sqrt{23} )^2[/tex]

The general form of the equation of the circle is given  as

[tex](x-h)^2+(y-k)^2=r^2[/tex]

We have the equation

[tex]x^2+y^2-18x+8y+5=0[/tex]

By adding 81 and 16 on both sides

[tex]x^2-18x+81+y^2+8y+16=-5+81+16[/tex]

[tex](x-9)^2+(y+4)^2=92[/tex]

[tex](x-9)^2+(y+4)^2=(2\sqrt{23})^2[/tex]

Thus the standard form of the given equation  [tex]x^2+y^2-18x+8y+5=0[/tex] will be given as  [tex](x-9^2)+(y+4)^2=(2\sqrt{23} )^2[/tex]

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Answer:

x-9, y+4, & 92

Step-by-step explanation:

i did it

Answer:

487.5 km

Step-by-step explanation:

Let :

Solving

Forming an equation

Answer: f(-3) = -10

Step-by-step explanation:

[tex]Substitute \ $x=-3$\\\\$$\begin{aligned}&f(3)=2(-3)-4 \\&f(3)=-6-4 \\&f(3)=-10\end{aligned}$$[/tex]

Answer:

ice cream 3

coffee 5

................

Answer:

coffee is $5 each and $3 for ice cream

Step-by-step explanation:

Answer:

Step-by-step explanation:

A = true

D = true

Answer:

4/7

Step-by-step explanation:

1/4 divided by 7/16 is the same thing as 1/4 * 16/7. Multiply this and you will get the fraction of 16/28. Once simplified, this comes out to be 4/7.

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations in a quick and efficient manner.

In this question we shall use the following Laplace transforms:

[tex]\mathcal {L} \{f(t) + g(t)\} = \mathcal {L} \{f(t)\} + \mathcal {L}\{g(t)\}[/tex]   (1)

[tex]\mathcal {L} \{\alpha\cdot f(t)\} = \alpha\cdot \mathcal {L} \{f(t)\}[/tex]   (2)

[tex]\mathcal{L} \left\{y^{(n)} \right\} = s^{n}\cdot \matcal {L}\{f(t)\}-s^{n-1}\cdot y(0) -...-y^{(n)}(0)[/tex]   (3)

[tex]\mathcal {L} \{e^{-a\cdot t}\} = \frac{1}{s+a}[/tex]   (4)

Now we proceed to derive an expression fo the Laplace transform of the solution of the differential equation:

[tex]y'' -5\cdot y' = 8\cdot e^{4\cdot t}-4\cdot e^{-t}[/tex]

[tex]s^{2}\cdot \mathcal {L}\{f(t)\}-5\cdot y(0) - y'(0) - 5\cdot s \cdot \mathcal {L} \{f(t)\} +5\cdot y(0) = \frac{8}{s-4}-\frac{4}{s+1}[/tex]

[tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]

The Laplace transform of the non-homogeneous second order differential equation is [tex]\mathcal {L} \{f(t)\} = \frac{4\cdot (s+6)}{s\cdot (s-4)\cdot (s+1)\cdot (s-5)} +\frac{1}{s} -\frac{1}{s\cdot (s-5)}[/tex]. [tex]\blacksquare[/tex]

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The Laplace transform Y'' − 5y' = 8e4t − 4e−t when y(0) = 1, y'(0) = −1 for f(t) = 8e4t − 4e−t would be  [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex].

A Laplace transform is a frequency-based algebraic substitution method used to determine the solutions of differential equations quickly and efficiently.

The Laplace transform

L[ f(t) + g(t) ] = Lf(t) + Lg(t)

Also,

L [[tex]y^{n}[/tex]] = [tex]s^{n} . L[ f(t) ] - s^{n-1} .y(0) .....y^{n}(0)[/tex]

We have

Y'' − 5y' = 8 . e^4t − 4 . e−t

[tex]s^{2} . L[ f(t) ] - 5. y(0)- y'(0) .....y^{n}(0)[/tex]

y(0) = 1, y'(0) = −1  

for f(t) = 8e4t − 4e−t.

= [tex]\frac{8}{s-4} - \frac{4}{s+1}[/tex]

L [f(t)] = [tex]\frac{4(s+6)}{s.(s-4)(s+1).(s-5)} + \frac{1}{s} - \frac{1}{s.(s-5)}[/tex]

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Using proportions, it is found that the desired amounts are given as follows:

a) 360 businesses employeed no women.

b) 41% of the businesses surveyed employed exactly one female supervisor.

c) 15.58% of the businesses surveyed employed no female supervisors.

d) 80.5% probability that it employed at least one female supervisor.

A proportion is a fraction of a total amount.

Item a:

18% out of the 2000 businesses surveyed, hence:

n = 0.18 x 2000 = 360.

Item b:

50% out of 82%, hence:

p = 0.5(0.82) = 0.41.

41% of the businesses surveyed employed exactly one female supervisor.

Item c:

19% out of 82%, hence:

p = 0.19(0.82) = 0.1558.

15.58% of the businesses surveyed employed no female supervisors.

Item d:

100 - 19.5 = 80.5% probability that it employed at least one female supervisor.

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Answer:

The last answer.

Step-by-step explanation:

Regular means all the side lenghts are the same and all the interior angle measures are the same. Think a stop sign.

Irregular polygons have different side lengths and different interior angle measures.

Answer:

y = 0

Step-by-step explanation:

Answer:

218

Step-by-step explanation:

the triangle is a right angle triangle. Therefore, we can use the Pythagorean thereom.
A^2 + 16^2 = 20^2

A^2 + 256 = 400

400 - 256 = 144

Square root of 144 is 12

Unknown side is 12

Find the area of the triangle:

16 x 12 = 192

192/2 = 96

The area is 96

Now find the area of the circle:

pi x the radius^2

The diameter is 20, so the radius is 10

Pi x 10^2 = 314

314 - 96 = 218

Answer:

(1, - 2.5 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

here (x₁, y₁ ) = (M (- 5, 3 ) and (x₂, y₂ ) = N (7, - 8 ) , then

midpoint = ( [tex]\frac{-5+7}{2}[/tex] , [tex]\frac{3-8}{2}[/tex] ) = ( [tex]\frac{2}{2}[/tex] , [tex]\frac{-5}{2}[/tex] ) = ( 1, - 2.5 )

Answer:

7.744

Step-by-step explanation:

For this problem you have to work backwards

The equation for the volume is V = (area of circle) x height

So here, to solve the area of the circle, you need to divide the 235.5 by 5

So:

235.5 = (area of circle) x 5

Area of circle is 47.1

Then, you need to find the radius of the circle by using this equation for the area of a circle

[tex]A = \pi \cdot r^{2}[/tex]

So:

47.1 = π * [tex]r^{2}[/tex]

r = 3.872

This question is asking for the diameter, which is double the radius,

2 x 3.872 = 7.744

Answer:

3. 3(x+y)(x-y)

4. (y²+4)(y+2)(y-2)

5. 2(3x+1)(x+2)

Step-by-Step:

3. 3(x²-y²) = 3(x+y)(x-y)

4. y⁴-16 = (y²+4)(y²-4)= (y²+4)(y+2)(y-2)

5. 6x²+14x+4 = 2(3x²+7x+2) = 2(3x+1)(x+2)

PLEASE RATE!!! I hope this helps!!!

If you have any question comment below

(I have verified my answers on an online calculator)

Answer:

Part A: X·8=Y

X represents the amount of people. Multiply X by 8 to see how many (Y) ounces of broccoli will be needed.

4·8=32

Jerome would be able to feed 4 people with 32 ounces of broccoli if each person is to get 8 ounces.

Step-by-step explanation:

Answer:

A=130cm2

Step-by-step explanation:

13x10=130

Answer:

2.1 standard drinks

(or 2 if you need to round to the nearest whole number)

Step-by-step explanation:

The ABV (alcohol by volume) percentage is a measure of the amount of pure alcohol (as a percentage) of the total volume of liquid in a drink.

So for 16% wine, this means that 16% of the volume of the wine is pure alcohol.

Therefore, if 16% of 8 fl oz is pure alcohol, this means that 1.28 fl oz of the 8 fl oz is pure alcohol (since 0.16 × 8 = 1.28).

One standard drink ≈ 0.6 fl oz pure alcohol

To calculate the number of standard drinks, divide the total amount of pure alcohol found by the amount in one standard drink:

1.28 ÷ 0.6 = 2.1

Therefore there is approximately 2.1 standard drinks in 8 fl oz of 16% wine.

Answer:

x = 2a

Step-by-step explanation:

a(x - a) = a² ( divide both sides by a )

x - a = a ( add a to both sides )

x = 2a

Answer:

x = 2a

Step-by-step explanation:

Given equation

[tex]\sf a(x-a)=a^2[/tex]

Make x the subject

expand brackets:

[tex]\sf \implies ax-a^2=a^2[/tex]

Add [tex]\sf a^2[/tex] to both sides:

[tex]\sf \implies ax-a^2+a^2=a^2+a^2[/tex]

[tex]\sf \implies ax=2a^2[/tex]

Divide both sides by a:

[tex]\sf \implies \dfrac{ax}{a}=\dfrac{2a^2}{a}[/tex]

[tex]\sf \implies x=2a[/tex]

Final solution

[tex]\sf x=2a[/tex]

Answer:

Voir ci-dessous.

Step-by-step explanation:

1.

OA/OD = 36/64 = 9/16

OB/OC = 27/48 = 9/16

m<AOB = m<COD

triangle AOB ~ trianlge DOC

m<BAO = m<CDO

AB || CD

2.

AB/CD = OA/OD

AB/80 = 36/64

AB/80 = 9/16

16AB = 9 × 80

AB = 9 × 5

AB = 45

AB = 45 cm

3.

AB = 45

BC = OC + OB = 48 + 27 = 75

AB² + AC² = BC²

45² + AC² = 75²

AC² = 5625 - 2025

AC = √3600

AC = 60 cm

hauteur = 5 × 2 cm + 4 × 60 cm

hauteur = 10 cm + 240 cm

hauteur = 250 cm

Answer: it is likely that both the number of frostbite cases and the number of sledding accidents are negatively correlated with temperature.

Step-by-step explanation: I just took the test.

The correct answer is the frostbite cases and sledding accidents were not randomly selected.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

If the data for the number of frostbite cases and sledding accidents were not randomly selected, then the correlation between them might not be valid.

if the data were only collected during a specific time period when sledding was popular and the weather was cold, then the number of frostbite cases and sledding accidents might be higher than normal.

In this case, the correlation might be due to the common factor of cold weather, rather than frostbite causing sledding accidents.

Therefore, it is important to consider the methodology of the study and the factors that might influence the correlation between frostbite cases and sledding accidents before concluding that frostbite is the main cause of sledding accidents

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Answer:

Step-by-step explanation:

Let's check the transformation from C(1,3) to C'(5,2).

(1) C(1,3) would become C'(2,-1), which is wrong.

(2) You can eliminate this, as the image and preimage are in the same quadrant.

(3) You can eliminate this, as the image and preimage are in the same quadrant.

(4) C(1,3) would become C'(5,2), which is correct.

Answer:

Rs. 22,080.

Step-by-step explanation:

Let the height be x m then the breadth is 3x and the length 5x m.

x * 3x * 5x = 960

15x^3 = 960

x^3 = 64

x = ∛ 64 = 4m.

Therefore the height is 4m, the breadth = 12 m and the length = 20m.

So the area of all the surfaces

= 2 * short wall + 2 * long wall + floor + ceiling

= 2 *4*12 + 2*4*20 + 12*20 + 12*20

=  96 + 160 + 240 + 240

= 736 m^2.

Cost plastering  = 736 * 30 = Rs. 22,080

Answer:

Step-by-step explanation:

where is the full question????

Area of a circle = pi x r^2

Area of the circle = 4^2 x pi = 16pi

3/4 of the circle is shaded

area of shaded portion = 3/4 x 16pi = 12pi

Answer 12 pi

Answer:

b

Step-by-step explanation:

4 of the nonshaded areas =a

Answer:

14%

Step-by-step explanation:

lets whip out that EPIC CALCULATOR! alright so i hope that you have your calculator with you, whether it is a physical one or a digital one on your computer.

try this:

enter 14, then the division sign ( could be a ÷ or an / ) and then 100.

what do we get?

0.14

ok, now lets multiply this by 100 to get the PERCENT instead of the DECIMAL, and we get
14%

EPIC!

Answer:

0

Step-by-step explanation:

-2-3+5

-5+5

0

Answer:

2

Step-by-step explanation:

As they are SIMILAR, they have a ratio!

15:5=3

So, the scale factor is 3 from triangle ABC to triangle XYZ

6/3=2