The enthalpy change for combustion of 15.0 g of ethanol in the chemical reaction is -180.93 kJ.
The enthalpy change for combustion of 15.0 g of ethanol can be calculated using the equation:
ΔH = (ΔH°/mol) × (mol/mass) × mass
Where ΔH° is the standard enthalpy change for the reaction, mol is the number of moles of ethanol, and mass is the mass of ethanol in grams.
Given that the standard enthalpy change for the combustion of ethanol is -555 kJ, the molecular weight of ethanol is 46.0 g/mol, and the mass of ethanol is 15.0 g, we can plug these values into the equation:
ΔH = (-555 kJ/mol) × (1 mol/46.0 g) × (15.0 g)
Simplifying the equation gives:
ΔH = (-555 kJ/mol) × (0.326 mol)
ΔH = -180.93 kJ
Therefore, the enthalpy change for combustion of 15.0 g of ethanol is -180.93 kJ.
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The photograph below shows a carved limestone head. The surface of this
limestone has changed over many years.
Which process made the surface of the limestone change over many years?
carving
polishing
melting
weathering
Name a substance in the air that made the surface of the limestone
change.
ASAP
Answer:
Weathering (I think)
Explanation:
don't know what else to add because you need a minimum of twenty words to answer
For those reactions that are not redox, indicate whether they are precipitation or neutralization reactions. Zncl2(aq)+2naoh(aq)→zn(oh)2(s)+2nacl(aq).
The reaction ZnCl2(aq)+2NaOH(aq)→Zn(OH)2(s)+2NaCl(aq) is a precipitation reaction.
In this reaction, Zn(OH)2(s) is the precipitate that forms when ZnCl2(aq) and NaOH(aq) are mixed. The other product, NaCl(aq), remains dissolved in the solution.
A precipitation reaction is a type of chemical reaction in which two soluble salts in aqueous solution combine to form an insoluble solid, called a precipitate. In this case, the precipitate is Zn(OH)2(s).
A neutralization reaction, on the other hand, is a type of chemical reaction in which an acid and a base react to form water and a salt. This reaction does not involve the formation of a precipitate.
Therefore, the reaction ZnCl2(aq)+2NaOH(aq)→Zn(OH)2(s)+2NaCl(aq) is a precipitation reaction, not a neutralization reaction.
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The reaction ZnCl2(aq)+2NaOH(aq)→Zn(OH)2(s)+2NaCl(aq) is a precipitation reaction.
In this reaction, Zn(OH)2(s) is the precipitate that forms when ZnCl2(aq) and NaOH(aq) are mixed. The other product, NaCl(aq), remains dissolved in the solution.
A precipitation reaction is a type of chemical reaction in which two soluble salts in aqueous solution combine to form an insoluble solid, called a precipitate. In this case, the precipitate is Zn(OH)2(s).
A neutralization reaction, on the other hand, is a type of chemical reaction in which an acid and a base react to form water and a salt. This reaction does not involve the formation of a precipitate.
Therefore, the reaction ZnCl2(aq)+2NaOH(aq)→Zn(OH)2(s)+2NaCl(aq) is a precipitation reaction, not a neutralization reaction.
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In passage 2, president Obama begins with a reminder to the audience of important laws former president Lyndon b Johnson signed into effect in 1965 what impact does this have on the development of president Obama claim
Answer:
A
Explanation:
just do it
Vildl
JES !
Pido prestado dinero de mi madre cuando voy de compras.
O I lend
O lowe
O I borrow
O pay
Answer:
C- I borrow
Explanation:
Simulate an environment with equal amounts of insects and seeds, but no fruit. Which flock will be able to eat the most? The least? Why?
In an environment with equal amounts of insects and seeds, but no fruit, the flock that will be able to eat the most will be the one that has a diet consisting mainly of insects and seeds.
The advantage of the abundanceThis is because they will be able to take advantage of the abundance of these two types of food sources and consume them at a higher rate than flocks that have a diet consisting mainly of fruit.
On the other hand, the flock that will be able to eat the least will be the one that has a diet consisting mainly of fruit. This is because there are no fruit available in this environment, and they will have to rely on the limited amount of insects and seeds available to them. This will result in them consuming less food overall and potentially struggling to find enough food to sustain themselves.
Overall, the ability of a flock to consume the most food in this environment will depend on their dietary preferences and the availability of different types of food sources. Flocks that have a diet consisting mainly of insects and seeds will be able to consume the most food, while flocks that have a diet consisting mainly of fruit will be able to consume the least.
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Answer:
Flock Y will eat the most and Flock X will eat the least.
Explanation:
look INT0J3SUS and whoever there was i didn’t mean anything by what i said i’m just gonna leave and if you want to believe the moderator is a racist fine, but i’m not.
Answer:
oop what happened. spill the tea
A 21. 8 g sample of ethanol (c2h5oh) is burned in a bomb calorimeter, according to the following reaction. If the temperature rises from 25. 0 to 62. 3°c, determine the heat capacity of the calorimeter. The molar mass of ethanol is 46. 07 g/mol. C2h5oh(l) + 3 o2(g) → 2 co2(g) + 3 h2o(g) δh°rxn = -1235 kj.
The heat capacity of the calorimeter in the sample of ethanol is -15.65 kJ/°C.
To determine the heat capacity of the calorimeter, we need to use the formula:
Q = C x ΔT
Where Q is the heat released or absorbed, C is the heat capacity of the calorimeter, and ΔT is the change in temperature. We can rearrange this formula to solve for C:
C = Q / ΔT
We are given the change in temperature (ΔT = 62.3 - 25.0 = 37.3°C) and the molar enthalpy of the reaction (δH°rxn = -1235 kJ). We can use the molar enthalpy to calculate the heat released (Q) by the reaction:
Q = (21.8 g / 46.07 g/mol) x (-1235 kJ/mol) = -583.7 kJ
Now we can plug in the values of Q and ΔT into the formula to find the heat capacity of the calorimeter:
C = (-583.7 kJ) / (37.3°C) = -15.65 kJ /°C
Therefore, the heat capacity of the calorimeter is -15.65 kJ/°C.
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The web development team is having difficulty connecting by ssh.
There could be a variety of reasons why the web development team is having difficulty connecting by ssh. Some common issues include incorrect login credentials, network issues firewall blocking the connection, or server configuration problems.
First, make sure that the login credentials are correct and that the correct port is being used. If that is not the issue, check for any network issues that may be preventing the connection. If there are no network issues, check the firewall settings to ensure that the connection is not being blocked. Lastly, make sure that the server configuration is correct and that there are no issues with the ssh daemon.
If none of these solutions work, it may be best to contact the network or server administrator for assistance.
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A 2-column table with 9 rows titled December Temperatures. Column 1 is labeled Day with entries 1, 2, 3, 4, 5, 6, 7, 8, 9. Column 2 is labeled Temperature (degrees Fahrenheit) with entries 33, 34, 42, 36, 39, 36, 39, 40, 44. Based on the sample standard deviation value, the temperature each day during this time period varied by about
from the
of 38. 11°F. If the next recorded temperature is 56°F, the standard deviation would
The new standard deviation would be 6.41°F, which is larger than the original standard deviation of 3.67°F.
This means that the data is more spread out with the new temperature included.
The standard deviation is a measure of how spread out the data is from the mean. To calculate the standard deviation, we first need to find the mean of the data set. The mean is the sum of all the data points divided by the number of data points.
Mean = (33 + 34 + 42 + 36 + 39 + 36 + 39 + 40 + 44) / 9 = 38.11
Next, we need to find the difference between each data point and the mean, square each difference, and find the sum of the squared differences.
Sum of squared differences = [tex](33 - 38.11)^2 + (34 - 38.11)^2 + (42 - 38.11)^2 + (36 - 38.11)^2 + (39 - 38.11)^2 + (36 - 38.11)^2 + (39 - 38.11)^2 + (40 - 38.11)^2 + (44 - 38.11)^2[/tex] = 107.88
Finally, we divide the sum of the squared differences by the number of data points minus 1, and take the square root of the result to get the standard deviation.
Standard deviation = √(107.88 / (9 - 1)) = √13.48 = 3.67
The standard deviation for this data set is 3.67°F. This means that the temperature each day during this time period varied by about 3.67°F from the mean of 38.11°F.
If the next recorded temperature is 56°F, we would need to recalculate the standard deviation with the new data point included. The new mean would be (33 + 34 + 42 + 36 + 39 + 36 + 39 + 40 + 44 + 56) / 10 = 39.9, and the new standard deviation would be
√[tex]((33 - 39.9)^2 + (34 - 39.9)^2 + (42 - 39.9)^2 + (36 - 39.9)^2 + (39 - 39.9)^2 + (36 - 39.9)^2 + (39 - 39.9)^2 + (40 - 39.9)^2 + (44 - 39.9)^2 + (56 - 39.9)^2) / (10 - 1))[/tex] = √[tex](366.9 / 9)[/tex]= 6.41.
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Answer:
3.66
mean
increase
Explanation:
How can you ensure that messages from a trusted email address will not be identified as spam or junk email?
Answer:
Add the massage to the Safe Sender's list
A table with a list price of x dollars is discounted by 15% and then discounted an additional 12%. What is the final sale price of the tablet, in terms of x?
The final sale price of the tablet is 0.748x
What is discount?Discount results in the reduction of the selling price of the product, which makes it more attractive for the customer.
Reduction in price makes a psychological impact on the customer which results in the purchase. The two types of discount offered are trade discount and cash discount.
x is discounted by 15%
= x × 15/100
= 15x /100
The new price = x -15x/100
= 85x/100
It is discounted again by 12%
85 x/100 × 12/100
= 1020x/10000
= 102x/100
The final sale price
= 85x /100 - 102 x/1000
= (850x-102 x)/1000
= 748x/1000
= 0.748x
Therefore the final sale price is 0.748x
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In the autumn season, leaves become brown-orange in color
and fall down off trees. Indicate which change these leaves undergo, and give
evidence