Answer:
[tex]\sf \theta=\dfrac34 \ radians=42.97 \textdegree \ (nearest \ hundredth)[/tex]
Step-by-step explanation:
Formulae
[tex]\sf radius (r)=\dfrac12 d[/tex]
(where d is the diameter of a circle)
[tex]\sf arc \ length =r\theta[/tex]
(where r is the radius and [tex]\theta[/tex] is measured in radians)
Calculation
Given:
[tex]\sf radius (r)=\dfrac12 \cdot 8=4 \ mi[/tex]arc length = 3 miSubstituting these values into the formula for arc length:
[tex]\implies \sf 3 =4\theta[/tex]
[tex]\implies \sf \theta=\dfrac34 \ radians[/tex]
To convert radians to degrees use
[tex]\sf 1 \ rad \cdot \dfrac{180\texrdegree}{\pi}[/tex]
[tex]\implies \sf \dfrac34 \cdot \dfrac{180\texrdegree}{\pi}=42.97183463...\textdegree[/tex]
Now
[tex]\\ \rm\rightarrowtail \theta=\dfrac{l}{r}[/tex]
[tex]\\ \rm\rightarrowtail l=r\theta[/tex]
[tex]\\ \rm\rightarrowtail 3=4\theta[/tex]
[tex]\\ \rm\rightarrowtail \theta=\dfrac{3}{4}^c[/tex]
At the store grapes are on sale. You can buy 3 pounds for
$2 dollars. At that rate, how many pounds can you buy
for $8? Show how you know.
Answer:
If you buy 3 pounds for $2, and have 8 dollars to spend, then multiply 2x4 to get $8. Since we multiplied by 4 for the money, we do the same thing for the pounds of grapes. So, we multiply 3x4 to get 12 pounds. So, you can buy 12 pounds of grapes for $8.
Step-by-step explanation:
Hope this helps! :)
PLEASE MARK ME AS BRAINLIEST I REALLY WANT TO LEVEL UP.
What is the value of x?
13 m
15 m
Answer:
which one?
Step-by-step explanation:
Write the recursive formula for the following sequence 2, 8, 32, 128
Answer:
an+1 = 4an
Step-by-step explanation:
an+1 = 4an commonratio: r=4
2
2x4=8
8x4=32
32x4=128
A teacher teaches 8 students how to fold an origami model. Each of these students goes on to teach 8
students of their own how to fold the same model. If this teaching process goes on for 6 generations,
how many people total will know how to fold the origami model
Answer:
8x8= 64
64x6= 384
384 is the answer
Let me know if i helped!
ans this sum plsss .
Answer:
See below ↓
Step-by-step explanation:
3.
2/512/253/73/83/104.
Draw a number of spacing 0.25 eachStart from -1 to 1-2/8 = -0.25 [mark on line]3/6 = 0.5 [mark on line]5.
Midpoint of -2/5 and 1/2M = [-2/5 + 1/2] / 2M = [1/10] / 2M = 1/20Find the slope of the line passing through the points(-9,-6) and (-4,5)
Hey there!
We're given 2 points that the line intersects, so we can easily determine the line's slope.
This is the formula:
[tex]\bold{\displaystyle\frac{y2-y1}{x2-x1} }[/tex]
[tex]\bold{\displaystyle\frac{5-(-6)}{-4-(-9)}}[/tex]
[tex]\bold{\displaystyle\frac{5+6}{-4+9}}[/tex]
[tex]\bold{\displaystyle\frac{11}{5}}[/tex]
Hence, the answer is
[tex]\boxed{\boxed{\bold{\frac{11}{5} }}}[/tex]
Hope everything is clear.
Let me know if you have any other questions!
#LearningDoesn'tEnd
:-)
[tex]\rule{200}{2}[/tex]
solve following problem
Answer:
p²=h²-b²
p² =10²-6²
p² =100-36
p²=64
p=( √8)²
p=8
Let [tex]x[/tex] and [tex]y[/tex] be the length and height, respectively, of the rectangle.
Let the bottom left vertex be the origin (0, 0), and position the triangle so that the bottom leg lies on the horizontal axis in the [tex]x,y[/tex]-plane. The hypotenuse of the triangle then lies on the line through (0, 0) and (6, 8), with slope 8/6 = 4/3. Then for some [tex]x[/tex] between 0 and 6, we have [tex]y = \frac43x[/tex].
This means for some fixed distance [tex]x[/tex] from the origin, the rectangle has length [tex]6-x[/tex] and height [tex]\frac43x[/tex]. Thus the area of the rectangle can be expressed completely in terms of [tex]x[/tex] as
[tex]A(x) = (6-x) \times \dfrac43x = 8x - \dfrac43 x^2[/tex]
Non-calculus method:
Complete the square to get
[tex]8x - \dfrac43 x^2 = -\dfrac43 (-6x + x^2) = 12 - \dfrac43 (9 - 6x + x^2) = 12 - \dfrac43 (x-3)^2[/tex]
which is maximized when the quadratic term vanishes at [tex]x=3[/tex], giving a maximum volume of [tex]\boxed{12\,\mathrm{in}^2}[/tex].
Calculus method:
Differentiate [tex]A(x)[/tex] and find the critical points.
[tex]A'(x) = 8 - \dfrac83 x = 0 \implies x = 3[/tex]
Differentiate again to check the sign of the second derivative at the critical point.
[tex]A''(x) = -\dfrac83 \implies A''(3) = -\dfrac83 < 0[/tex]
which indicates a local maximum at [tex]x=3[/tex]. Hence the maximum area is [tex]A(3) = 12[/tex], as before.
Find the value of x. 1222° 0 111 O 55 O 42 O 138
Based on the outside angles theorem, the value of x is: 42°
What is the Outrside Angles Theorem?The outside angles theorem states that the measure of the angle that is formed outside a circle when two tangents or secants intersect is half the measure of the diffrence of the intercepted arcs.
Given the following:
One arc measure = 222°The second arc measure = 360 - 222 = 138°Therefore, based on the outside angles theorem, we would have the following:
x = 1/2(222 - 138)
x = 42°
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FIRST CORRECT GETS BRAINLIEST
Answer:
First choice.
Step-by-step explanation:
cos 11π/6 = cos π/6 = √3/2
So cos 11π/12 = √(1 + cos 11π/6) / √2
= √(1 + √3/2) / √2
= √(2 + √3) / 2.
Find the rule from the given table
A.Divide by 2
B.Divide by 3
C.Divide by 5
D.Divide by 6
Answer:
the answer b
Step-by-step explanation:
te answer b because I guessed
9
These lists show the ages of attendees in a yoga class and a dance dass
Yoga: 18, 31, 17, 14, 20, 33, 36
Dance: 20, 47, 23, 38, 26, 42, 30
Select from the drop-down menus to correctly complete each statement about the attendees in the two cases
The median age of the attendees in the yoga class is
the median age of the attendees in the dance
The range of ages of the attendees in the yoga class is
the range of ages of the attendees in the conce
Answer:
median is 20
Step-by-step explanation:
due to both of them having it in there 1 time
Answer:
The Median Age: Yoga Class (31) Dance Class (30)
The Range: Yoga Class (17-44) Dance Class (20-47)
Step-by-step explanation:
WILL MARK BRAINLIEST
Rewrite the equation in Ax+By=C form.
Use integers for A, B, and C.
y-6= -5(x-3)
y - 6 = - 5 * x - 5 * (-3)
y - 6 = -5x + 15
y + 5x = 15 + 6
5x + y = 21
Answer:
5x + y = 21.
Step-by-step explanation:
y - 6 = -5(x - 3)
y - 6 = -5x + 15
5x + y - 6 = 15
5x + y = 15 + 6
5x + y = 21.
CAN SOMEBODY HELP ME SOLVE THIS EQUATION
Pam kicked a soccer ball down the field. Part of the ball's path, including its highest
point, is described by the function below, where f(x) is the height of the ball in feet.
According to the function, what is the ball's maximum height, in feet? (Use only the
digits 0-9 to enter the height.)
f(x) =
12x2+2x
Answer:
maximum height is 45/4 in feet
The maximum height of the ball is 45/4 in feet
What is the unitary method?The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.
Given tha Pam kicked a soccer ball down the field. Part of the ball's path, including its highest point, is described by the function below, where f(x) is the height of the ball in feet.
F(x)= 12x^2+2x
Thus for this quadratic , the max value will occur at x= -b/2a
= - 2 / (2 x 1/12) = -12
Plug in -12 to find the max height
= (-12)^2 + 2 x-12
= 45/4 in feet
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Betsy, a recent retiree, requires $5,000 per year in extra income. She has $70,000 to invest and can invest in B-rated bonds paying 13% per year or in a certificate of deposit (CD) paying 5% per year. How much money should be invested in each to realize exactly $5,000 in interest per year?
A. The amount of money invested at 13% = ___
B. The amount of money invested at 5% = ___
A. The amount of money that Betsy should invest n B-rated bonds at 13% is $20,000.
B. The amount of money that Betsy should invest in a certificate of deposit (CD) at 5% is $50,000.
How are CDs different from Bonds?Certificates of deposit (CDs) are short-term investments in financial institutions (money market) while Bonds are long-term investments in the stock exchange (capital market).
CDs pay reduced interest rates when compared to bonds'.
Data and Calculations:The amount required per year in interest = $5,000
Total investible funds = $70,000
Interest rate of B-rated bonds = 13%
Interest rate in CD = 5%
Since Betsy is not interested in realizing more than $5,000 in interest per year, she should invest $50,000 in the CD and $20,000 in the B-rated bonds.
The interest in CD = $2,500 ($50,000 x 5%)
The interest in bonds = $2,600 ($20,000 x 13%)
Total interest in CD and bonds = $5,100 ($2,500 + $2,600)
Thus, Betsy should invest $50,000 in the CD and $20,000 in the B-rated bonds.
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the length of a rectagle is 6 ft longer than its width. if the perimeter of the rectangle is 64 ft, find its length and width
Answer:
19 and 13
Step-by-step explanation:
width = x
length = x + 6
2x + 2(x + 6) = 64
2x + 2x + 12 = 64
4x = 64 - 12
4x = 52
x = 13
x + 6 = 19
Answer:
19 and 13
Step-by-step explanation:
Lori puts up a sign for her business 500 meters from the main entrance. She once read that it takes the average adult 6 minutes to walk 500 meters. She decides to test this by having 200 adults walk the 500 meters from her sign to her store. Which of the following is the sample in Lori's experiment?
Step-by-step explanation:
She decided to test this by 200 adults, so. Divide 6 by 500 = 0.012 (200)=2.4mins.
Answer: The 200 adults
Step-by-step explanation:
At the beginning of the summer,
Shay had $27 in her savings
account. Shay worked as a
lifeguard and by the end of the
summer had a total of $575 in
her savings account. How much
did Shay save over the summer?
The giraffes at the Liberia zoo eat 75 pounds of food per day, and 52.5 pounds per day comes from acacia leaves. How much of their diet comes from other types of leaves?
Julia, the zookeeper, used the equation 52.5 + x = 75 to find the answer. Which equation is an equivalent equation that can be used to solve the problem?
Answer:
Step-by-step explanation:
75-52.5=x
Evan owns a small business selling ice-cream. He knows that in the last week 83
customers paid cash, 8 customers used a debit card, and 2 customers used a credit
card.
Based on these results, express the probability that the next customer will pay with a
debit card or a credit card as a percent to the nearest whole number.
The probability that the next customer will pay with a debit card or a credit card is 12%.
What is the probability that the next customer would pay with a debit card or a credit card?
Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
The probability that the next customer would pay with a debit card or a credit card = (number of customers that paid with a debit card + number of customers that paid with a credit card) / total number of customers
(8 + 2)/ 83 = 0.12 = 12%
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What is 1 * 2 = + * 1 = + + 2 2 + 1 8 5 / 9
Whoever answers it gets grevious
Answer:
Can you use a specific question please
Step-by-step explanation:
Answer: = 17 7/
Step-by-step explanation:
8 1/5 + 9 1/2 = 177/
10
= 17 7/
The regular price of a color TV is $539.22. During a sale, Hill TV is selling the TV for $456.56. Determine the percent decrease in the price of the TV
Hey there!
Answer: = 15.3296% decrease
How to Calculate Percentage Decrease
Subtract starting value minus final value=> 539.22 - 456.56
=> 79.66
Divide that amount by the absolute value of the starting value=> 79.66 ÷ 539.22
=> 0.153296
Multiply by 100 to get percent decrease=> 0.153296 × 100
=> 15.3296%
If the percentage is negative, it means there was an increase and not an decrease.
Therefore, percentage decrease is 15.3%
need help with geometry question
Which values from the set {-8, -6, -2, 0, 2, 4, 8} satisfy the following inequality?
he was never late negative to affirmative
[tex] \\ { \rm{If \: }{\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}}, { \rm{shown \: that \: AB = A \: and \: BA = B}}[/tex]
[tex] \: [/tex]
Don't Spam
Explain well
Answer:
Given:
[tex] \\ {\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}[/tex]
Matrix A is of order 3 × 3 and Matrix B is of order 3 × 3
To Show:
Matrix AB = A , BA = BFormula Used:
[tex]\\ { \rm{ \left[ \begin{array}{c c c} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33}\end{array} \right] \times \left[ \begin{array}{c c c} b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23} \\ b_{31} & b_{32} & b_{33} \end{array} \right] = \: \left[ \begin{array}{c c c} \: \: a_{11}b_{11} + a_{12}b_{21} + a_{13}b_{31} & a_{11}b_{12} + a_{12}b_{22} + a_{13}b_{32} & a_{11}b_{13} + a_{12}b_{23} + a_{13}b_{33} \\ \: \: a_{21}b_{11} + a_{22}b_{21} + a_{23}b_{31} & a_{21}b_{12} + a_{22}b_{22} + a_{23}b_{32}&a_{21}b_{13} + a_{22}b_{23} + a_{23}b_{33} \\ \: \: a_{31}b_{11} + a_{32}b_{21} + a_{33}b_{31}&a_{31}b_{12} + a_{32}b_{22} + a_{33}b_{32} & a_{31}b_{13} + a_{32}b_{23} + a_{33}b_{33}\end{array} \right]}}[/tex]
If A is a matrix of order a×b and B is a matrix of order c×d , then matrix AB exits and is of order a×d , if and only if b = c.
[tex] \: \: [/tex]
If A is a matrix of order a×b and B is a matrix of order c×d , then matrix BA exits and is of order c×b , if and only if d = a.
[tex] \: \: [/tex]
____________________________________________________________________For Matrix AB, a = 3, b = c = 3, d = 3 , thus Matrix AB is of order 3×3
[tex]\\ { \rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = \left[\begin{array}{c c c} \: \: \: \: 2(2)-3(-1)-5(1) & \: \: \: \: 2(-2)-3(3)-5(-2) & \: \: \: \: 2(-4)-3(4)-5(-3) \\ -1(2)+4(-1)+5(1) & -1(-2)+4(3)+5(-2) & -1(-4)+4(4)+5(-3)\\ \: \: \: \: 1(2)-3(-1)-4(1) & \: \: \: \: 1(-2)-3(3)-4(-2) & \: \: \: \: 1(-4)-3(4)-4(-3) \end{array} \right]}}[/tex]
[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 4 + 3 - 5 & \: \: \: -4 -9 + 10 & \: \: -8 - 12 + 15 \\ -2 - 4 + 5 & \: \: \: \: \: \: + 2 + 12 - 10 & \: \: \: \: \: 4 + 16 - 15 \\ \: \: \: \: \: 2 + 3 - 4 & \: \: -2 - 9 + 8 & -4 - 12 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right]}}[/tex]
[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] = Matrix \: A}}[/tex]
Matrix AB = Matrix A____________________________________________________________________For Matrix BA, a = 3, b = c = 3, d = 3 , thus Matrix BA is of order 3 × 3
[tex]\\ {\rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: \: 1 & -3 & -4 \end{array} \right]}}= \left[ \begin{array}{c c c} \: \: \: \: \: 2(2) -2(-1) -4(1) & \: \: \: \: 2(-3) -2(4) -4(-3) & \: \: \: \: 2(-5) -2(5) -4(-4) \\ \: -1(2) + 3(-1) + 4(1) & -1(-3) + 3(4) +4(-3) & -1(-5) + 3(5) + 4(-4) \\ \: \: \: \: \: 1(2) -2(-1) -3(1) & \: \: \: \: 1(-3) -2(4) -3(-3) & \: \: \: \: 1(-5) -2(5) -3(-4) \end{array} \right][/tex]
[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 4 + 2 - 4 & \: \: \: -6 -8 + 12 & \: \: -10 - 10 + 16 \\ -2 - 3 + 4 & \: \: \: \: \: \: +3 + 12 - 12 & \: \: \: \: \: + 5 + 15 - 16 \\ \: \: \: \: \: 2 + 2 - 3 & \: -3 -8 +9 & \: \: \: \: \: -5 -10 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right]}}[/tex]
[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = Matrix \: B}}[/tex]
Matrix BA = Matrix B____________________________________________________________________find the value of x in the diagram
Answer: there is something off screen i cant see so i cant help you 183- what?
Step-by-step explanation:
I need lateral surface
Answer:
un rhgdb tennis felicidades ID remix estoy do do ID do ID Rockband do ID do TX
What is the coefficient of x in 4+[tex]3y^{2}[/tex]+x?
ASAP PLS ANSWER
Hello!
Please remember that
The coefficient is the number before a variable.Example:
4T+5H
In this example, the coefficient of T is 4, and the coefficient of H is 5.
So let's identify the coefficient of x.
It seems like x doesn't have a coefficient, but it does.
It's equal to 1.
Hope everything is clear.
Let me know if you have any questions!
#KeepLearning
:-)
Find the mean of the data.
55,64,58,43,49,67
Answer:
56
Step-by-step explanation:
Step 1: Order the data
43,49,55,58,64,67
Step 2: Count all numbers and add them up
43+49+55+58+64+67=336 and we have 6 numbers in total so... 336 ÷ 6
Step 3: Divide!
336 ÷ 6 = 56
Hope this helps you!
What expression is equivalent to 12x^4/4x^16 helpppp
Answer: 48x/64
Work (assuming ^ is multiplication):
12x^4/4x^16
12x ^ 4x = 48x
4 ^ 16 = 64